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Weak Harnack inequality for nonnegative supersolutions

Statement

Assume Countable Choice and the Axiom of Choice. Let n≥2, let Ω⊆Rn be open, let A and L0 be as in De Giorgi local boundedness of homogeneous subsolutions, and let F∈Llocq(Ω) with q>n/2. Let u∈H1(Ω;R) satisfy u≥0 a.e. and a0(u,φ)≥−∫ΩF φ dxfor every nonnegative φ∈Cc∞(Ω;R), i.e. u is a nonnegative weak supersolution of L0u=−F. Then for every ball BR(x0) with B2R(x0)⋐Ω and every 0<p<n/(n−2), R−n/p∥u∥Lp(BR(x0))≤C(ess inf⁡BR/2(x0)u+R 2−n/q∥F∥Lq(B2R(x0))), with C=C(n,q,θ,Ma,p) independent of R and x0. For n=2 every finite p is allowed, with the critical Sobolev embedding in place of the 2∗ embedding. The forcing term enters additively and cannot be dropped: the exponent range 0<p<n/(n−2) and the threshold q>n/2 are the ones the iteration actually produces.

Facts & Assumptions

Given: Countable Choice and the Axiom of Choice; an open set Ω⊆Rn, n≥2; measurable symmetric uniformly elliptic coefficients A with constants θ,Ma; the principal operator L0u=−Di(aijDju) with form a0; a source F∈Llocq(Ω), q>n/2; a nonnegative u∈H1(Ω;R) with a0(u,φ)≥−∫ΩFφ dx for all nonnegative φ∈Cc∞(Ω;R); a ball BR(x0) with B2R(x0)⋐Ω and 0<p<n/(n−2) when n≥3, or any finite p>0 when n=2.

[F1]

Assume the Axiom of Choice. Moser chains for positive supersolutions: if w∈H1(BS;R) satisfies w>0 a.e. and a0(w,v)≥0 for every nonnegative v∈H01(BS), then for every 0<ρ<1 and every p>0, (1∣BS∣∫BSw−pdx)−1/p≤C1ess inf⁡BρSw, and for some p0=p0(n,θ,Ma)>0 one has (1∣B3S/4∣∫B3S/4wp0dx)1/p0≤C1(1∣B3S/4∣∫B3S/4w−p0dx)−1/p0; the constants depend only on their listed arguments (Moser iteration for positive supersolutions: negative-power and logarithmic comparison, The average of a locally integrable function over a Euclidean ball).

[F2]

Assume the Axiom of Choice. Logarithmic estimate: for every positive supersolution w as in [F1] on a ball, every η∈Cc∞ and every ε>0, ∫η2∣Dlog⁡(w+ε)∣2dx≤4Ma2θ∫∣Dη∣2dx (Logarithmic Caccioppoli estimate for positive supersolutions).

[F3]

Assume the Axiom of Choice. On the reference ball B2, the weak maximum principle for a zero-trace solution of L0h=g gives h≥0 when g≥0 and ess sup⁡B2h≤C∥g+∥Lq(B2) for q>n/2 (and q>1 in dimension two). The constant is fixed for this ball, and the estimate applies after scaling B2R to B2 (Weak maximum principle for coercive divergence-form equations, The Lp trace operator on a bounded C1 domain, The kernel of the trace is the closure of the test functions, Bounded C^k domains and boundary charts).

[F4]

Assume the Axiom of Choice. Lax-Milgram and coercivity on H01(B2): H1(B2) is Hilbert by Hk is a Hilbert space under the derivative-sum inner product. The closure definition makes H01(B2) a closed linear subspace; a Cauchy sequence converges in H1(B2) and its limit remains in that closure, so the inherited inner product makes it Hilbert. The form a0 is a bounded coercive form there, and every bounded conjugate-linear functional on H01(B2) is represented by a unique weak Dirichlet solution (The Lax--Milgram theorem, Coercivity of the principal Dirichlet form, The elliptic form is well defined and bounded on H1, The negative Sobolev space H−1(Ω), Weak Dirichlet solutions for a divergence-form operator, Zero-boundary Sobolev space as a norm closure, The Poincare inequality for zero-boundary Sobolev closures on domains bounded in one direction).

[F5]

Assume the Axiom of Choice. Embedding and Holder input: for n≥3 and 1≤r<2∗ there is Cr with ∥v∥Lr(B1)≤Cr∥v∥H01(B1); in dimension two the same holds for every finite r. By dilation this makes φ↦∫B2F+φ bounded on H01(B2) when q>n/2 (and q>1 for n=2), since the conjugate exponent q′ lies in the available Sobolev range. Also, if z∈H1(B2), multiplying by a smooth cutoff supported in B2 and equal to one on B3/2 gives z∈Lr(B3/2) for every 1≤r<2∗ when n≥3 and every finite r when n=2. The Sobolev norms scale as ∥v∥Lr(BR)≤CrR1+n/r−n/2∥Dv∥L2(BR) for v∈H01(BR), with the corresponding inhomogeneous local estimate after cutoff; Holder's inequality gives ∥g∥Lr(E)≤∣E∣1/r−1/s∥g∥Ls(E) for 1≤r<s≤∞ (The Sobolev inequality for zero-boundary Sobolev closures on open sets, The critical Sobolev embedding into every finite Lq, Holder's inequality for integrals, including the endpoint cases, The space Lp(μ) as the quotient by null functions).

[F6]

Assume the Axiom of Choice. For U=u+ε≥ε>0 and 0<s<1, both scalar maps t↦(max⁡{t,0}+ε)s−1 and t↦(max⁡{t,0}+ε)s/2 are globally Lipschitz. Their compositions with u lie in Hloc1; the first, multiplied by a compactly supported smooth cutoff squared, gives an H01 test by the product rule, zero extension and smooth density. The second gives V=Us/2∈Hloc1 with DV=(s/2)Us/2−1Du (Chain rule for globally Lipschitz scalar maps of Sobolev functions, Weak Leibniz rule with a smooth factor, Compactly supported Sobolev functions extend by zero in every integer order, Compactly supported smooth functions are dense in W^{k,p}(R^n), Zero-boundary Sobolev space as a norm closure, Integer-order Sobolev spaces and their norms).

[F7]

Assume the Axiom of Choice. Dominated convergence passes integrals with an integrable majorant (Dominated convergence). Scaling invariance on doubled balls: with v(y):=u(x0+Ry) and G(y):=R2F(x0+Ry), the weak supersolution inequality scales to B2, ∥G∥Lq(B2)=R2−n/q∥F∥Lq(B2R(x0)), and R−n/p∥u∥Lp(BR(x0))=∣B1∣1/p(1∣B1∣∫B1∣v∣p)1/p (Uniformly elliptic divergence-form operators and their sesquilinear forms, The average of a locally integrable function over a Euclidean ball, The Poincare inequality for zero-boundary Sobolev closures on domains bounded in one direction).

Proof

technique · direct; scale the doubled ball to $B_2$, add a Lax-Milgram barrier there to make the solution a homogeneous supersolution on the full region required by Moser's comparison, derive the positive-integrability transitions using only negative-power tests with exponent $s-1<0$, then undo the scaling
1.1givenF3F4F5F7

Removing the source by a barrier on the doubled ball. After the rescaling of [F7] it suffices to treat R=1, B2(x0)⋐Ω, and source norm ∥F∥Lq(B2). Since F∈Lq(B2) and q>n/2, the local supersolution inequality extends by density from nonnegative smooth tests to all nonnegative H01(B2) tests: the embedding in [F5] puts H01(B2) in Lq′(B2). The functional φ↦∫B2F+φ dx is therefore bounded on H01(B2), so [F4] gives a unique h∈H01(B2) with a0(h,φ)=∫B2F+φ dx for all φ∈H01(B2). Since F+≥0, [F3] gives h≥0; its radius-two estimate gives ess sup⁡B2h≤C∥F+∥Lq(B2)≤C∥F∥Lq(B2), where the fixed scaling factor 22−n/q is absorbed into C. With w:=u+h one has w≥0 and a0(w,φ)≥−∫B2Fφ+∫B2F+φ≥0 for every nonnegative φ∈H01(B2), so w is a nonnegative homogeneous weak supersolution on the full doubled ball. Also ∥u∥Lp(B1)≤∥w∥Lp(B1) and ess inf⁡B1/2w≤ess inf⁡B1/2u+ess sup⁡B2h.

1.2F1F2F5algebra

The seed exponent on a compactly contained ball. Let w≥0 be a homogeneous weak supersolution on B2 and set U:=w+ε. The outer ball B7/4 is compactly contained in B2, so the comparison clause of [F1], supplied by the logarithmic estimate [F2], gives (1∣B21/16∣∫B21/16Up0)1/p0≤C1(1∣B21/16∣∫B21/16U−p0)−1/p0 for some p0=p0(n,θ,Ma)>0. Apply the negative-power chain of [F1] with outer ball B21/16⋐B2 and ratio ρ=8/21; it bounds the reciprocal negative moment on B21/16 by C2ess inf⁡B1/2U. Decrease the seed to s0:=min⁡{p0,1/2}<1; Jensen's inequality on the normalized ball mean gives (1∣B21/16∣∫B21/16Us0)1/s0≤C3ess inf⁡B1/2U.

1.3givenF3F5F6algebra

The positive-integrability transition for input exponents below one. Fix 0<s<1 and a cutoff η∈Cc∞(BR) with η=1 on Br, 0<r<R≤2. For U=w+ε, the admissible test η2Us−1 of [F6] and the homogeneous supersolution inequality give (1−s)∫η2Us−2⟨ADw,Dw⟩≤2∫∣η∣Us−1∣⟨ADw,Dη⟩∣. Cauchy--Schwarz in the A-energy bounds the right side by 2Ma(∫η2Us−2⟨ADw,Dw⟩)1/2(∫Us∣Dη∣2)1/2. Absorbing this energy square root and using ellipticity gives ∫η2Us−2∣Dw∣2≤4Ma2(1−s)2θ∫Us∣Dη∣2. With V:=Us/2 this becomes ∫η2∣DV∣2≤Ma2s2(1−s)2θ∫V2∣Dη∣2. Applying Sobolev to ηV and the product rule therefore gives, for n≥3 and every 1<λ≤κ∗:=n/(n−2), or for n=2 and every finite λ>1, ∥U∥Lsλ(Br)≤(C(s,λ,n,θ,Ma)R−r)2/s∥U∥Ls(BR). The truncation and density in [F6] justify the test; no estimate for an untruncated positive power is assumed.

2.1step 1.2step 1.3F5algebra

Reaching every exponent in the claimed range. Work on concentric balls between B21/16 and B1, using equal positive radius gaps for the finitely many transitions below. If 0<p≤s0, Jensen on B1⊂B21/16 and step 1.2 give (1∣B1∣∫B1Up)1/p≤Cess inf⁡B1/2U. For s0<p≤κ∗s0 when n≥3, use step 1.3 once with s=s0 and λ=p/s0≤κ∗. If κ∗s0<p<κ∗, choose an integer m≥1 so large that a:=(p/(κ∗s0))1/m<κ∗. Apply step 1.3 m times with exponent multiplier a, reaching input exponent sm=s0am=p/κ∗<1, then once with multiplier κ∗. Every input exponent is below one, so all tests in step 1.3 are admissible. The constants are finite and depend only on n,θ,Ma,p. In dimension two, for any finite p>s0, a single use of step 1.3 with s=s0 and finite λ=p/s0 suffices. In every case this proves (1∣B1∣∫B1Up)1/p≤Cess inf⁡B1/2U for the stated range.

3.1step 2.1F5F7

Removing regularization in the homogeneous case. Let ε↓0 in step 2.1. The right side tends to Cess inf⁡B1/2w, while Up↓wp and is dominated by (w+1)p, integrable on B3/2 by the cutoff-local Sobolev consequence in [F5] because p<n/(n−2)<2∗ for n≥3 and p is finite for n=2 (for p<1, use (w+1)p≤1+w). Dominated convergence passes the positive-power mean and yields the homogeneous weak Harnack estimate.

4.1step 1.1step 3.1F5F7algebra∎

Conclusion with the source and the radius rescaling. For the barrier supersolution w=u+h of step 1.1, step 3.1 gives ∥w∥Lp(B1)≤Cess inf⁡B1/2w. Since u≤w and ess inf⁡B1/2w≤ess inf⁡B1/2u+ess sup⁡B2h, step 1.1 gives ∥u∥Lp(B1)≤C(ess inf⁡B1/2u+∥F∥Lq(B2)). Scaling back by [F7] gives the estimate with additive term R2−n/q∥F∥Lq(B2R); the doubled-ball hypothesis supplies the full region used in the barrier and in steps 1.2--2.1. The n=2 argument allows every finite p, and all constants are independent of R,x0.

Remarks

  • Radius convention. The quantitative interior form of the weak Harnack inequality controls the mean over BR by the essential infimum over BR/2 and requires the supersolution inequality on the doubled ball B2R, exactly as in Theorem 2 of [K1] and Theorem 2 of [K2]; the statement records this explicitly rather than silently enlarging the class of admissible balls.

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