Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-adaptedPipeline-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Coulomb Jost Volterra solution

Statement

Assume the Axiom of Countable Choice and the Axiom of Choice (The Axiom of Countable Choice (ACω), The Axiom of Choice). Let γ≥0, l≥0, and let Al be the radial operator of Transported radial endpoint realization with form domain Vl. Let D:={k∈C:Re⁡k>0, Im⁡k≥0} be the parameter domain for the Jost solution. For each kmin⁡>0 also write K:={k∈D:Re⁡k≥kmin⁡} for its restriction. Then:

(a) regular solution. With c0:=1, c−1:=0 and cn:=−γcn−1+k2cn−2n(n+2l+1)(n≥1), the series φl(k,r):=rl+1∑n≥0cnrn converges for every r>0 and every k∈C, the function (k,r)↦φl(k,r) is holomorphic in k and C∞ in r>0, and φl solves −u′′+(l(l+1)/r2−γ/r)u=k2u with φl(k,r)/rl+1→1 as r↓0;

(b) Jost-type solution. Put a:=γ/(2k), θ(r):=kr+alog⁡r, w(r):=eiθ(r), b:=a2+l(l+1)+ia and consider the integral equation v(r)=1+∫r∞bs2 w(s)2(∫rsw(y)−2dy)v(s) ds. For every k∈D the equation has exactly one bounded solution v(⋅;k) on [r0,∞) for some r0>0 depending on k; extend fl uniquely by its regular initial data to every r>0 and put v=fl/w there. Constructions with different admissible tails agree by bounded-solution and initial-value uniqueness, so these functions are independent of the tail and of kmin⁡. One has v(r)=1+O(1/r), v′(r)=O(1/r); the functions fl(k,r):=w(r)v(r) and v are jointly continuous on D×(0,∞), holomorphic in k on {Re⁡k>0,Im⁡k>0}, satisfy the radial equation −∂r2fl+(l(l+1)/r2−γ/r)fl=k2fl exactly, and obey the asymptotics fl=ei(kr+alog⁡r)(1+O(1/r)),fl′=ei(kr+alog⁡r)[ik+O(1/r)](r→∞);

(c) Wronskians. For real k>0 one has W(fl‾,fl)=2ik and Wl(k):=W(φl,fl)≠0; consequently every solution of the radial equation on (0,∞) is Afl+Bfl‾ with A,B∈C, and φl is a nonzero complex multiple combination of fl,fl‾;

(d) no positive eigenvalue. For real k>0 and A,B∈C, if g=Afl+Bfl‾ then ∫RL∣g(r)∣2dr=(∣A∣2+∣B∣2)[L−R−γlog⁡(L/R)/(2k2)]+O(1) as L→∞ with R>r0 fixed; hence g∈L2(r0,∞) if and only if A=B=0, and k2>0 is not an eigenvalue of Al.

All assertions concern the ordinary differential equation and the operator Al; no scattering amplitude, cross-section or physical interpretation is asserted or computed.

Facts & Assumptions

Given: γ≥0, l≥0, kmin⁡>0, K as above, and for k∈D the quantities a,θ,w,b; the radial equation Llu=k2u with Llu:=−u′′+(l(l+1)/r2−γ/r)u.

[F1]

On any compact interval [a,b]⊂(0,∞) the radial equation has a two-dimensional space of C2 solutions, and for real k complex conjugation preserves the solution space because both the potential and k2 are real (Regular interval IVP: existence, a priori bound and entire spectral-parameter dependence, Continuity of f:A→R at a point of A and on A: the ε-δ condition, its agreement with lim⁡x→cf(x)=f(c) at a limit point, and continuity at an isolated point).

[F2]

The Wronskian W(u,v)=uv′−u′v of two solutions of −(u′′)+qu=0 with q continuous is constant (Regular interval IVP: existence, a priori bound and entire spectral-parameter dependence).

[F4]

Banach fixed point and Gronwall: the standard existence-uniqueness and a priori bound arguments for Volterra integral equations; integrals of continuous functions against continuous kernels may be interchanged (A contraction of a nonempty complete metric space into itself has exactly one fixed point, the limit of the iterates from any starting point, Gronwall's integral inequality with variable and constant coefficients, Tonelli and Fubini for the completed product, with only almost-everywhere section measurability).

[F6]

Every eigenfunction u∈D(Al) of Al with Alu=Eu, E constant, is a C2 solution of the radial equation on (0,∞) (Transported radial endpoint realization (c)).

[F7]

A continuous function with zero contour integral on every triangle is holomorphic, and a locally uniformly convergent series of holomorphic functions is holomorphic with termwise derivatives (Morera's theorem: vanishing triangle integrals characterize holomorphy among continuous functions, A locally uniformly convergent series of holomorphic functions may be differentiated term by term).

Proof

1.1F7givenalgebra

[Regular solution] On a compact k-set choose C≥max⁡(1,γ,sup⁡∣k∣). Induction gives ∣cn∣≤Cn/n!, since the recurrence majorant divided by Cn/n! is [γ/C+∣k∣2(n−1)/C2]/(n+2l+1)≤1; at n=1 the second term is absent. Each cn is a polynomial in k2. The exponential majorant also bounds every fixed r-derivative on compact subintervals of (0,∞), so the series is entire in k, smooth in r>0, and termwise substitution gives the stated radial equation. Its leading coefficient is one, and the remaining series tends to zero as r↓0, uniformly on compact k-sets. For real k all coefficients and φl are real.

1.2F3givenalgebra

[A common tail and the correct complex-power modulus] Perform the construction on D:={Re⁡k>0,Im⁡k≥0}, then restrict to K. Fix a compact Q⊂D, and put m:=min⁡Q∣k∣>0, A:=max⁡Q∣a∣, B:=max⁡Q∣b∣, H:=2/m+2A/m2, and D:=BH. Choose r0≥max⁡(1,γ/(2m2),2A/m,2D). For s≥y≥r0, the exact modulus is ∣w(s)2w(y)−2∣=exp⁡[−2Im⁡k(s−y)](s/y)−2Im⁡a. Here −2Im⁡a=γIm⁡k/∣k∣2, and log⁡(s/y)≤(s−y)/y makes this modulus at most one. Write p(y)=k+a/y and d(y)=1/(−2ip(y)). Then ∣p∣≥m/2, ∣d∣≤1/m and ∣d′∣≤2A/(m2y2). Integration by parts on the finite interval gives w(s)2∫rsw(y)−2dy=d(s)−d(r)w(s)2w(r)−2−∫rsd′(y)w(s)2w(y)−2dy, whose modulus is at most H. Thus the actual kernel R(k;r,s):=bs−2w(s)2∫rsw(y)−2dy satisfies ∣R∣≤D/s2, uniformly for k∈Q and s≥r≥r0.

2.1step 1.2F4algebra

[Contraction and bounded-solution uniqueness] On the complete space Cb([r0,∞);C) define (Vkh)(r)=∫r∞R(k;r,s)h(s)ds. The kernel estimate gives ∥Vk∥≤D/r0≤1/2; continuity follows by splitting the integral at a finite upper limit and using the uniformly small s−2 tail. Therefore v=∑n≥0Vkn1 is the unique fixed point of h↦1+Vkh, and ∥v∥∞≤2, ∣v(r)−1∣≤2D/r. Any bounded function for which the integral equation holds is continuous by the same kernel estimate and hence equals this fixed point. Constructions on different common tails agree on their overlap by uniqueness. This proves bounded-solution uniqueness on the chosen tail and the uniform O(r−1) estimate.

3.1step 1.2step 2.1F3algebra

[Differentiate the genuine double integral] In the integral equation the lower-limit term vanishes because R(k;r,r)=0, whereas ∂rR=−bs−2w(s)2w(r)−2. The ratio bound in step 1.2 dominates this derivative times v(s) by 2B/s2 on each compact r-interval in the tail. Truncated-integral differentiation followed by uniform convergence therefore gives v′(r)=−bw(r)−2I(r), where I(r):=∫r∞w(s)2v(s)s−2ds; this is a derivative identity, not a replacement of the original fixed-point equation by v=1+bI. The integral for I is absolutely convergent: for real k, ∣w∣=1, and for Im⁡k>0, ∣w(s)∣=e−Im⁡kss−Im⁡a decays exponentially times a power. Hence I′=−w(r)2v(r)/r2 and v′′=−2i(k+a/r)v′+bv/r2. The ratio estimate gives ∣v′∣≤2B/r, uniformly on Q. Using w′′=−[(k+a/r)2+ia/r2]w and 2ka=γ, the product rule for f=wv gives f′′=[−k2−γ/r+l(l+1)/r2]f. Consequently f=w[1+O(r−1)] and f′=w[ik+O(r−1)], with the factor w retained and all errors uniform on Q.

4.1step 1.2step 2.1step 3.1F3F4F7algebra

[Continuity and holomorphy on the common tail] Each Picard iterate is jointly continuous in (k,r) on Q×[r0,∞): on compact r-intervals the finite-integral kernel is continuous, and the D/s2 majorant makes the improper tail uniformly small. Induction on iterates followed by the uniform geometric bound ∥Vkn1∥∞≤2−n proves joint continuity of v; the derivative formula, dominated by 2B/s2, also proves joint continuity of v′. On each triangle in {Re⁡k>0,Im⁡k>0} with a compact neighborhood, the finite-integral kernel is holomorphic because 1/k and the complex exponential are holomorphic. If an iterate is holomorphic, interchange its s-integral with the triangle contour integral using the uniform s−2 bound; the contour integral vanishes, so Morera proves that the next iterate is holomorphic. Uniform convergence and [F7] prove holomorphy of v. Apply the same contour argument to v′=−∫r∞bs−2w(s)2w(r)−2v(s)ds to prove holomorphy of its initial data. Thus f,f′ are continuous to real k and holomorphic in the open first quadrant. The construction on D also supplies an open complex neighborhood for points with Re⁡k=kmin⁡ and Im⁡k>0, which makes the asserted holomorphy at that boundary precise.

4.2step 2.1step 3.1F3algebra

[First integration by parts improves the derivative] Fix real k>0 and write Q(r)=2iθ′(r)=2i(k+a/r) and h(r)=v(r)/r2. Since θ′≥k, Q−1 is bounded and its first two derivatives are O(r−2) and O(r−3). Initially v=O(1) and v′=O(r−1), so h=O(r−2), h′=O(r−3) and (h/Q)′=O(r−3). Integration by parts, whose boundary term vanishes at infinity, gives I(r)=−e2iθ(r)h(r)/Q(r)−∫r∞e2iθ(s)(h/Q)′(s)ds=O(r−2). The exact derivative identity then gives v′=O(r−2); the ODE from step 3.1 gives v′′=O(r−2).

5.1step 3.1step 4.1F1F3F7algebra

[Extend to every positive radius] Fix ε>0 smaller than the common r0. The regular-IVP result gives a unique extension of f from (f(r0),f′(r0)) across [ε,r0]. To establish complex parameter dependence rather than invoking that supplier's real-parameter differentiability clause, write Y=(f,f′)T and Y′=M(k,r)Y, with M=(01l(l+1)/r2−γ/r−k20). Its initial-value integral series on [ε,r0] has nth term bounded by C0[CM(r0−ε)]n/n!, uniformly on compact k-sets, since the nfold ordered integration simplex has volume at most (r0−ε)n/n!. Each term is continuous to real k and holomorphic in the open first quadrant by finite contour integration. Thus the sum has both properties by [F7], agrees with the unique IVP solution, and supplies the asserted parameter properties for every r>0. Set v=f/w on the extension; w never vanishes, so the same properties hold for v. Patching overlapping tails and intervals is unambiguous by IVP uniqueness. For fixed nonreal k∈D, f,f′ have the stated exponential-times-power decay.

5.2step 4.2step 2.1step 3.1F3algebra

[Second integration gives the amplitude coefficient] Now h′′=v′′/r2−4v′/r3+6v/r4=O(r−4). Put j=(h/Q)′. Then j=O(r−3), j′=O(r−4) and (j/Q)′=O(r−4). A second integration by parts gives ∫r∞e2iθj=−e2iθ(r)j(r)/Q(r)−∫r∞e2iθ(j/Q)′=O(r−3). Therefore I(r)=−e2iθ(r)v(r)/(2iθ′(r)r2)+O(r−3), v′=bv/(2iθ′r2)+O(r−3)=b/(2ikr2)+O(r−3), and integration to the known limit v(∞)=1 gives v=1−b/(2ikr)+O(r−2). Since −b/(2ik)=−a/(2k)+i[a2+l(l+1)]/(2k) and ∣w∣=1, the coefficient is ∣f∣2=∣v∣2=1−a/(kr)+O(r−2). These estimates are uniform when real k is restricted to a compact subset of (0,∞), because all preceding constants and the lower bound for θ′ can be chosen uniformly.

6.1step 1.1step 3.1step 5.1F1F2algebra

[Real-energy Wronskians] Any real k>0 belongs to the public domain D of the single patched family fl. By the asymptotic formulas, W(f‾,f)=2i(k+a/r)∣v∣2+2iIm⁡(v‾v′)=2ik+O(r−1). It is constant by [F2], hence equals 2ik. The pair f,f‾ is therefore a basis of the two-dimensional solution space. If W(φl,f)=0, their initial data are proportional at any positive radius, hence IVP uniqueness implies f=cφl; neither solution is identically zero, by their normalizations. Since φl is real, proportionality forces W(f‾,f)=0, a contradiction. Thus Wl(k)≠0, every solution is Af+Bf‾, and the nonzero φl has such a representation with coefficients not both zero.

7.1step 6.1step 5.2F3F6algebra

[The mixed term has a bounded integral] For fixed R>r0, integration by parts gives ∫RLf2=[e2iθv2/Q]RL−∫RLe2iθ(v2/Q)′. The endpoint term is uniformly bounded and (v2/Q)′=2vv′/Q+v2(Q−1)′=O(r−2) is integrable, hence the whole integral is bounded independently of L. Expanding ∣Af+Bf‾∣2=(∣A∣2+∣B∣2)∣f∣2+2Re⁡(AB‾f2) and integrating step 5.2 yields ∫RL∣Af+Bf‾∣2=(∣A∣2+∣B∣2)[L−R−(a/k)log⁡(L/R)]+O(1), with a/k=γ/(2k2). If at least one coefficient is nonzero the integral diverges, since its linear term dominates the logarithm; if both vanish it is zero. Every positive-energy eigenfunction in D(Al) is an L2 classical solution by [F6], hence step 6.1 and this divergence exclude such an eigenfunction.

8.1step 1.1step 1.2step 2.1step 3.1step 4.1step 5.1step 6.1step 4.2step 5.2step 7.1given∎

[Conclusion and choice accounting] Steps 1.1; 1.2, 2.1, 3.1, 4.1 and 5.1; 6.1; and 4.2, 5.2 and 7.1 prove (a), (b), (c), and (d), respectively, for precisely the stated radial operator and parameter range. The explicit regular series, prescribed Picard iteration and unique IVP patching require no new arbitrary choice of solutions. The public Countable Choice assumption is retained for the invoked IVP and Hilbert-space suppliers; the public Axiom of Choice assumption is retained for the existing transported radial-operator supplier contract. No reduction of that supplier's choice hypothesis is inferred from this local argument.

Remarks

Cauchy-Schwarz in the forms ∣∫fg‾∣≤∥f∥2∥g∥2 and the finite-dimensional estimate on C2 (Cauchy-Schwarz inequality for L2, Cauchy–Schwarz: ∣⟨u,v⟩∣≤∥u∥∥v∥, with equality exactly for linearly dependent vectors, The space Lp(μ) as the quotient by null functions).

Depends on

Dependency tree · 2 levels

Sources