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The positive-type Gaussian on the real line and its cyclic model

Example

Assume the Axiom of Choice. Let G=(R,+) with its usual topology and put w(s):=e−s2/42π,ξ(s):=w(s)=e−s2/82π,φ(t):=e−t2. On complex L2(R,ds) define (π(t)f)(s):=eitsf(s),H0:=span⁡C{π(t)ξ:t∈R}‾. Then ξ∈H0 has norm one, H0 is a cyclic invariant Hilbert subspace, and π∣H0 is a strongly continuous unitary representation with φ(t)=⟨π(t)ξ,ξ⟩(t∈R). Consequently φ is normalized positive type and this pointed cyclic representation is unitarily equivalent to its canonical GNS representation.

Facts & Assumptions

Given: AC, the additive real group with its usual topology, and the functions w,ξ,φ displayed above.

[A2]

The Gaussian improper integral is π; substitution applies to monotone differentiable maps on improper intervals; a mixed improper integral splits at its finite interior point (The Gaussian integral ∫−∞∞e−x2 dx=π, Change of variable in an improper integral, Improper integrals with several singular ends).

[A6]

Differentiation under the integral sign applies under a measurable integrable majorant, and dominated convergence applies to complex-valued integrands; the complex L2 pairing uses the first-variable-linear convention (Differentiation under the integral sign, Dominated convergence, The Lebesgue integral is linear on L1(μ), Integrable real and complex functions, and their integrals, Complex Lp classes and Euclidean test-function conventions).

[A7]

The complex exponential satisfies its addition law, Euler's identity and ∣eiu∣=1 for real u; its real-parameter phase is continuous. Continuous real and complex functions are Borel measurable, and Borel sets are Lebesgue measurable under Countable Choice (exp⁡(z+w)=exp⁡z exp⁡w, and the complex exponential extends the real exponential, exp⁡(x+iy)=ex(cos⁡y+isin⁡y), ∣exp⁡(x+iy)∣=ex, and eiπ+1=0, A function differentiable at c is continuous at c, Sums, scalar multiples, products, absolute values, maxima, minima and quotients with nonvanishing denominator of continuous functions are continuous, as are constants, the identity and every polynomial function, A composite of continuous functions is continuous, with no side hypothesis of the kind the composition of limits needs, Sums, products, absolute values, finite maxima and minima, and quotients of continuous real-valued maps on a topological space are continuous where defined, The absolute value makes R a metric space: d(x,y)=∣x−y∣ is a metric, its open balls are the intervals (x−r,x+r), and it is unbounded, The product set ∏i∈IXi of functions choosing a point in each factor, the projections, the box topology, and the product topology as the initial topology of the projections; the empty product is a one-point space, Group and abelian group, The reals form a field, Topological group: multiplication and inversion are continuous, Continuous functions on Euclidean spaces are Borel measurable, Assuming countable choice, every Borel subset of Rn is Lebesgue measurable, Arithmetic and lattice operations preserve measurability whenever they are defined).

[A8]

For a strongly continuous unitary representation, each diagonal coefficient is continuous positive type; a cyclic pointed representation with that coefficient is uniquely unitarily equivalent to the canonical GNS representation (Continuous positive-type functions and normalization, Cyclic vector and cyclic unitary representation, Topological group: multiplication and inversion are continuous, GNS construction for a continuous positive-type function, Uniqueness of the pointed cyclic GNS representation, Diagonal unitary coefficients have positive type).

Proof

technique · direct
1.1A7

The additive real field gives the group laws for (R,+), and addition and negation are continuous by the algebra of continuous real maps on a metric space, so G is a topological group.

1.2A2

Let h0(s)=e−s2/4; evenness, reflection of the negative improper tail, and the mixed-integral convention give ∫0∞e−x2 dx=π/2, so the substitution s=2x yields ∫0∞h0(s) ds=π.

1.3A5

For R>0, FTC gives ∫0Rse−s2/4 ds=2(1−e−R2/4), whose limit is 2; both h0 and h1(s):=∣s∣e−s2/4 are continuous and nonnegative on [0,∞), and their half-line improper integrals are respectively π and 2.

1.4A5A7

For fixed t, qt(s):=e−s2/4eits has derivative qt′(s)=(−s/2+it)qt(s) by Euler's identity and the real product and chain rules; its continuous components are integrable on [−n,n], and their Riemann and Lebesgue integrals agree, so componentwise FTC gives qt(n)−qt(−n)=∫−nn(−s/2+it)qt(s) ds.

1.5A4A7

The formula ∣eits∣=1 makes multiplication by eits a well-defined complex-linear isometry on L2(R); the exponential addition law gives π(t+u)=π(t)π(u) and π(−t) is its inverse, so π is a unitary representation.

1.6A4A6A7

For f∈L2 and tn→t, the squared orbit difference has integrand ∣eitns−eits∣2∣f(s)∣2, which converges pointwise to zero and is bounded by 4∣f(s)∣2; dominated convergence gives ∥π(tn)f−π(t)f∥2→0, hence π is strongly continuous because R is metrizable.

1.7A4A8

The algebraic orbit span is linear, and its norm closure H0 is a closed linear subspace: for x,y in the closure, the metric-closure criterion approximates them by span elements within ε/3, whose sum is within 2ε/3 of x+y; scalar multiples follow from norm homogeneity. Thus [A4] and the closed-subspace completeness theorem make H0 a Hilbert space. The group law sends each orbit vector to another orbit vector, and continuity of π(u) and its inverse shows π(u)H0=H0; by construction ξ∈H0 is cyclic.

2.1A1A3step 1.2step 1.3

The half-line comparison turns the values in steps 1.2 and 1.3 into Lebesgue integrals; for either even function h∈{h0,h1}, splitting into positive and negative open half-lines and the null singleton gives ∫Rh=2∫(0,∞)h by reflection invariance and integral additivity. Thus ∫Rw=1 and ∫R∣s∣w(s) ds=2/π<∞.

3.1A5A6A7step 2.1

The functions s↦eitsw(s) are measurable and have modulus w(s), so they are integrable; for each fixed s, differentiation in t gives ∂t(eitsw(s))=iseitsw(s), whose modulus is bounded by the integrable majorant ∣s∣w(s). Hence differentiation under the integral sign gives F′(t)=i∫Rseitsw(s) ds for F(t):=∫Reitsw(s) ds.

3.2A6A7step 2.1step 1.4

The boundary terms in step 1.4 tend to zero, and dominated convergence passes the truncated integrals to their full-line integrals because ∣qt∣=e−s2/4 and ∣sqt∣=∣s∣e−s2/4 are integrable by step 2.1; therefore ∫sqt(s) ds=2it∫qt(s) ds, or ∫seitsw(s) ds=2itF(t).

4.1A5step 2.1step 3.1step 3.2

Steps 3.1 and 3.2 give F′(t)=−2tF(t), while step 2.1 gives F(0)=1; the product and chain rules show (et2F(t))′=0, so applying the real FTC to each component on every compact interval yields F(t)=e−t2 for all t∈R.

5.1A4A8step 2.1step 4.1step 1.5step 1.6step 1.7

The norm identity ∥ξ∥22=∫w=1 holds, and the first-linear L2 pairing gives ⟨π(t)ξ,ξ⟩=∫eitsw(s) ds=F(t)=e−t2 by step 4.1; [A8] now gives normalized positive type and identifies (π∣H0,H0,ξ) with the canonical GNS triple.

6.1A1A3A8∎

AC is propagated through Countable Choice exactly for the L² and measure-theoretic suppliers in [A1] and [A3], and is used directly by the canonical GNS construction and pointed uniqueness in [A8]; the Gaussian integral calculation and the phase representation use no further choice.

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