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Boundary values and zeros of a Blaschke product
Statement
Let be a Blaschke sequence with Blaschke product and partial products . Then:
(i) for every , and the zeros of are exactly the points , with multiplicity;
(ii) for every , is the Blaschke product of the tail ; it is holomorphic on , satisfies , and , a product that is eventually positive and tends to as ;
(iii) has finite nontangential limits for -almost every , and for -almost every . In particular .
Facts & Assumptions
Given: Countable choice and a Blaschke sequence with , its Blaschke product , and the partial products .
The product converges normally: is holomorphic on with zeros exactly the counted with multiplicity, and ; for each the quotient is the Blaschke product of the tail and is holomorphic with , while is holomorphic on a neighbourhood of the closed disc with for every ; also and for every (Blaschke factors and Blaschke products, Normally convergent products define holomorphic functions with the expected zeros).
Radii and moduli: for the tail products, ; since we have , so all but finitely many have , and for those ; hence is eventually positive and tends to as (The zero set of a Hardy function satisfies the Blaschke condition, Blaschke factors and Blaschke products).
If is holomorphic on a neighbourhood of the closed disc of radius , then : is subharmonic by Positive powers of the modulus of a holomorphic function are subharmonic with , its Poisson modification on majorizes it and has the mean value of on the circle at its centre, and for this is the mean inequality for holomorphic functions of Radial p-means of a holomorphic function are nondecreasing (Poisson modification on a compactly contained disc, Poisson modification is subharmonic and majorizes the original function, Radial p-means of a holomorphic function are nondecreasing).
Under countable choice every bounded holomorphic disc function has finite nontangential limits almost everywhere. (Bounded holomorphic disc functions have Poisson boundary data and Fatou limits under countable choice, The Axiom of Countable Choice ())
Domination and convergence: if for all and -almost everywhere as , then ; the kernel has unit mass in the torus normalization and is a probability measure (Dominated convergence, The Poisson kernel is positive, has total mass one, and concentrates at a boundary point, The one-dimensional torus and its normalized Haar integral).
Proof
Items (i) and (ii). [L1] gives with the stated zeros and the holomorphy and bound for . For each the value at the origin is , whose factors are all nonzero once exceeds the largest index with . The tail need not be empty. By [L2] its product is eventually positive and tends to ; for a finite sequence the empty tail equals .
Nontangential limits exist and are bounded. Since and B is holomorphic, [L4] gives finite nontangential limits almost everywhere; hence exists and satisfies for -almost every .
The mean inequality for each tail. Fix and . The function is holomorphic on a neighbourhood of the closed disc of radius by [L1], so [L3] gives
Letting the radius tend to the boundary. For -almost every one has as , and extends continuously to with on by [L1], so along these radii, a limit of modulus . Since , [L5] applies and gives
Conclusion. Letting in step 3.1 and using that by [L2] gives , so ; since -almost everywhere, the nonnegative function has integral , hence vanishes -almost everywhere by A nonnegative measurable function has integral exactly when it vanishes almost everywhere, that is, -almost everywhere. In particular the boundary function is not identically zero, so .
Depends on
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
- Blaschke factors and Blaschke products
- Normally convergent products define holomorphic functions with the expected zeros
- The zero set of a Hardy function satisfies the Blaschke condition
- Radial p-means of a holomorphic function are nondecreasing
- Bounded holomorphic disc functions have Poisson boundary data and Fatou limits under countable choice
- The $C^2$ real and imaginary parts of a holomorphic function satisfy Laplace's equation and form a harmonic-conjugate pair
- Plane harmonic functions
- Positive powers of the modulus of a holomorphic function are subharmonic
- Poisson modification on a compactly contained disc
- Poisson modification is subharmonic and majorizes the original function
- Dominated convergence
- The Poisson kernel is positive, has total mass one, and concentrates at a boundary point
- The one-dimensional torus and its normalized Haar integral
- A nonnegative measurable function has integral $0$ exactly when it vanishes almost everywhere
Used by
- A divergent Blaschke sum: no nonzero Hardy function has these zeros Counterexample
- Inner, singular inner and outer functions Definition
- An infinite Blaschke product whose zeros accumulate at the boundary Example
- Finite Blaschke products Example
- Inner-outer factorization of a rational function with one interior zero Example
- Blaschke factorization of a Nevanlinna-class function Lemma
- F. Riesz factorization of a Hardy-space function Theorem
- Inner-outer factorisation of a Hardy-space function Theorem
- Zero-free inner functions are unimodular multiples of singular inner functions Theorem
Cited to discharge well-definedness by Blaschke factors and Blaschke products.
Dependency tree · two levels
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Sources
- J. B. Garnett, Bounded Analytic Functions, revised first edition, Chapter II §2 (standard reference, not scraped)
- R. K. Srivastava, Lecture Notes on Hardy Spaces (MA650, IIT Guwahati), §5.8 (standard reference, not scraped)