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TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-09-04
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Time-dependent vector fields have local smooth evolution operators

Statement

Let IR be an open interval, and let Xt be a smooth time-dependent vector field on M over I. For every (s,p)I×M there exist an open interval JI containing s, open neighbourhoods Ur of the evolving points, and a smooth map

Ψ:{(t,s,q):t,sJ, qUs}M

such that tΨt,s(q) is the unique solution of γ˙(t)=Xt(γ(t)) with Ψs,s(q)=q.

Facts & Assumptions

Given: An open interval IR, a smooth time-dependent vector field Xt over I, and a base point (s,p)I×M.

[L1]

Chart maps identify manifold neighbourhoods with Euclidean open sets (Chart maps are diffeomorphisms onto Euclidean open sets).

[L2]

Smooth nonautonomous ODEs on Euclidean open sets have unique local smooth evolution operators (The fundamental theorem for nonautonomous smooth ODEs).

Proof

technique · direct
1.1

Choose a chart (U,x) around p. By [L1], the chart identifies U with an open subset of Rn, and the field Xt becomes a smooth time-dependent Euclidean vector field X~t there.

L1given
2.1

Apply [L2] to X~t at (s,x(p)). Because I is open, the Euclidean field is defined on the open set I×x(U). The theorem therefore yields an open interval JI containing s, an open set Wx(U) around x(p), and a smooth Euclidean evolution map Ψ~t,s(y).

L2step 1.1choose
3.1

Transport back by the chart: Ψt,s(q):=x1(Ψ~t,s(x(q))). This map is smooth and its time slices solve the manifold differential equation because the chart intertwines derivatives with the coordinate vector field.

L1step 2.1construct
4.1

Any other local manifold solution would push forward under x to a Euclidean solution of the same nonautonomous ODE with the same initial data, so [L2] gives uniqueness.

L2step 3.1
5.1

Therefore smooth time-dependent vector fields have unique local smooth evolution operators.

step 3.1step 4.1

Depends on

Used by

Dependency tree · two levels

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Sources