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Causality And Signals — Examples

1 · Prerequisites

2 · Summary

These examples and counterexamples work the causality page on explicit integers and rationals. The boost family on the spacelike pair (11,13,0,0) reaches simultaneity at b=11/13 and produces both time orders at b=3/5 and b=12/13, with all three charts verified inertial (Worked boost family on the spacelike pair (11,13,0,0): simultaneity at b=11/13 and both time orders); the four displacements (5,3,0,0), (5,5,0,0), (5,7,0,0) and (5,−3,0,0) are classified by the strict, equality and reversed inequalities of the coordinate criterion (Worked coordinate criteria: four displacements classified by the future-cone inequalities). The causal diamond J+(p)∩J−(q) for p=x−1(0,0,0,0), q=x−1(2,0,0,0) is computed with its interior; its 1+1 section x2=x3=0 has coordinate area 2 m2, invariant under boosts in the (0,1) plane (Worked four-dimensional causal diamond and the boost-invariant area of its planar section), and the parallel future null displacements (1,1,0,0), (2,2,0,0) compose to the future null (3,3,0,0), with the full characterization that a sum of future causal vectors is null exactly for parallel future null summands (Parallel future null displacements compose to a future null displacement). Two further examples isolate the non-causal side: a prearranged sweep of coordinate speed w>c whose successive events are spacelike separated and can be made simultaneous (A prearranged sweep with superluminal coordinate speed: successive events are spacelike separated and can be made simultaneous), and the exact relay arithmetic at u=2c, v=(9/10)c arriving at t=−50/(121c) s (Worked relay arithmetic at u=2c and v=(9/10)c: arrival at t=−50/(121c) seconds).

The counterexamples refute two specific displayed claims and nothing wider: a causally related pair need not be joinable by a future timelike worldline, as the null-separated pair (0,0,0,0), (3,3,0,0) shows (Counterexample: a causally related pair of events need not be joinable by a future timelike worldline); and the sign of a time-coordinate difference is not frame independent, as two explicit boost charts give opposite signs for the same spacelike-separated pair (Counterexample: the temporal order of a spacelike-separated pair is not the same in every inertial frame). The final example shows that two nonparallel future null legs compose to a future timelike displacement while every tangent stays null, so the strict clause of the causality theorem is not an equivalence (Two nonparallel future null legs compose to a future timelike displacement). Every computation is exact and no item asserts a measurement or an empirical conclusion.

3 · Logical flowchart

4 · Definitions, postulates, theorems and proofs

None yet.

5 · Examples, experiments and counterexamples

ExampleConstruction: AI-generatedVerification: AI-generatedOpen item page →

Worked boost family on the spacelike pair (11,13,0,0): simultaneity at b=11/13 and both time orders

Example

Worked computation in the chart x of an inertial frame of an affine Minkowski space (Oriented time-oriented affine Minkowski space (the spacetime primitives), Inertial frames and inertial charts of the affine Minkowski model) with η0=diag⁡(−1,1,1,1). Let p:=x−1(0,0,0,0) and q:=x−1(11,13,0,0); then D:=x(q)−x(p)=(11,13,0,0) has η(D,D)=−112+132=−121+169=48>0, so q−p is spacelike and ∣D0∣=11<13=∣Ds∣, in accordance with clause (a) of Spacelike-separated events: the spacelike coordinate inequality in every inertial chart, and an explicit family of inertial frames realizing every time-order sign.

(a) Simultaneity at b0=11/13. With e:=Ds/∣Ds∣=e1 and b0:=D0/∣Ds∣=11/13, so that ∣b0∣<1, the chart xb0 of the inertial frame built from the passive boost B(b0e1) by clause (d) of the same lemma satisfies xb00(q)−xb00(p)=γb0(11−1113⋅13)=0,γb0=(1−121169)−1/2=1348: the two events are simultaneous in that frame.

(b) Below b0: positive time difference. With b=3/5 one has γb=(1−9/25)−1/2=5/4 and xb0(q)−xb0(p)=54(11−35⋅13)=54⋅165=4>0.

(c) Above b0: negative time difference. With b=12/13 one has γb=(1−144/169)−1/2=13/5 and xb0(q)−xb0(p)=135(11−1213⋅13)=135(−1)=−135<0.

(d) The spatial separation in the three frames. The boost in the (0,1)-plane acts by x′0=γ(x0−bx1), x′1=γ(x1−bx0) (The passive Lorentz boost with parameter beta), so the spatial difference of the pair in the boosted chart is xb1(q)−xb1(p)=γb(13−11b). It equals 48 for b=b0, 8 for b=3/5 and 37/5 for b=12/13; in each case it is nonzero and ∣xb0(q)−xb0(p)∣<∣xb1(q)−xb1(p)∣. The displacement stays spacelike because a boost is a Lorentz map and preserves η (Lorentz maps are isomorphisms of determinant ±1 that preserve causal character and permute the cones; the Lorentz sets are groups, Linear and affine Lorentz maps, and the Lorentz group), so the three charts are charts of three inertial frames related to x by passive boosts and the time-order sign of a spacelike-separated pair is an artifact of the chart, not of the pair. No physical synchronization procedure is asserted; simultaneity means equality of the chart's time coordinate.

Facts & Assumptions

Given: An inertial frame with chart x and η0=diag⁡(−1,1,1,1), the events p=x−1(0,0,0,0) and q=x−1(11,13,0,0), the displacement D=(11,13,0,0) with spatial part Ds=(13,0,0) and Euclidean norm ∣Ds∣=13.

[L1]

For a spacelike pair the lemma gives ∣D0∣<∣Ds∣ in every inertial chart, and for every ∣b∣<1 the chart xb of the inertial frame with ordered basis ea′=B(be)−1ea, where e=Ds/∣Ds∣, satisfies xb0(q)−xb0(p)=γb(D0−b∣Ds∣) with γb=(1−b2)−1/2 (Spacelike-separated events: the spacelike coordinate inequality in every inertial chart, and an explicit family of inertial frames realizing every time-order sign).

[L2]

For β=be1 with ∣b∣<1 the passive boost acts in coordinates by x′0=γ(x0−bx1), x′1=γ(x1−bx0), x′2=x2, x′3=x3, with γ=(1−b2)−1/2>0 (The passive Lorentz boost with parameter beta).

[L3]

A vector v is spacelike exactly when η(v,v)>0; a linear Lorentz map preserves η, hence preserves the causal character of every nonzero vector, and the boosts are proper orthochronous Lorentz maps (Timelike, null, spacelike and causal vectors of a Lorentz vector space, Lorentz maps are isomorphisms of determinant ±1 that preserve causal character and permute the cones; the Lorentz sets are groups, Linear and affine Lorentz maps, and the Lorentz group).

[L4]

In a fixed inertial frame the spatial coordinates carry the Euclidean norm ∣(u1,u2,u3)∣=(u1)2+(u2)2+(u3)2 (The Euclidean spatial structure and cross product of an inertial frame).

Verification

technique · direct
1.1givenL3L4algebra

The displacement is D=(11,13,0,0), so η(D,D)=−121+169=48>0, the pair is spacelike, and ∣D0∣=11<13=∣Ds∣.

2.1step 1.1L1algebra

With b0=11/13 one has ∣b0∣<1, and the chart of clause (d) of [L1] gives xb00(q)−xb00(p)=γb0(11−(11/13)13)=0 with γb0=(1−121/169)−1/2=(48/169)−1/2=13/48>0; this is (a).

2.2step 1.1L1algebra

With b=3/5 one has ∣b∣<1, γb=(1−9/25)−1/2=(16/25)−1/2=5/4 and xb0(q)−xb0(p)=(5/4)(11−(3/5)13)=(5/4)(16/5)=4>0; this is (b).

2.3step 1.1L1algebra

With b=12/13 one has ∣b∣<1, γb=(1−144/169)−1/2=(25/169)−1/2=13/5 and xb0(q)−xb0(p)=(13/5)(11−(12/13)13)=(13/5)(−1)=−13/5<0; this is (c).

3.1step 1.1step 2.1step 2.2step 2.3L2L3algebra

The spatial difference in the boosted chart is xb1(q)−xb1(p)=γb(13−11b) by [L2] applied to D, and the three values are γb0(13−121/13)=(13/48)(48/13)=48, (5/4)(13−33/5)=(5/4)(32/5)=8 and (13/5)(13−132/13)=(13/5)(37/13)=37/5, all nonzero; the corresponding time differences are 0, 4 and −13/5, so ∣xb0(q)−xb0(p)∣<∣xb1(q)−xb1(p)∣ holds in all three charts, and the spacelike character is preserved because η(Bv,Bv)=η(v,v) by [L3]; this is (d).

4.1step 3.1step 2.1step 2.2step 2.3L1∎

By [L1] the three charts xb0, x3/5 and x12/13 are charts of inertial frames related to x by passive boosts, and steps 2.1, 2.2 and 2.3 give time differences 0, 4 and −13/5; hence the time order of the spacelike-separated pair (p,q) is simultaneity for b0=11/13, positive for 3/5<b0 and negative for 12/13>b0, and is therefore an artifact of the inertial chart and not a property of the pair. Only equality of the chart's time coordinate is used for simultaneity, and no choice principle is used.

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Worked coordinate criteria: four displacements classified by the future-cone inequalities

Example

Worked computation in the chart x of an inertial frame of an affine Minkowski space with η0=diag⁡(−1,1,1,1) (Inertial frames and inertial charts of the affine Minkowski model). Put p:=x−1(0,0,0,0) and, in order,

qA:=x−1(5,3,0,0),qB:=x−1(5,5,0,0),qC:=x−1(5,7,0,0),qD:=x−1(5,−3,0,0),

with DA,DB,DC,DD the corresponding displacements q∙−p and ∣D∙s∣ the Euclidean norm of the spatial part. Then:

(a) Future timelike. DA=(5,3,0,0) has DA0=5>3=∣DAs∣, so qA lies in I+(p) (Causal reachability, causal futures and pasts, causal diamonds, and reachability by future causal paths in affine Minkowski space) and η(DA,DA)=−25+9=−16<0 confirms that DA is future timelike (Timelike, null, spacelike and causal vectors of a Lorentz vector space, Time orientation, future and past timelike/null/causal vectors, and the closed cones).

(b) Future null. DB=(5,5,0,0) has DB0=∣DBs∣=5>0, so qB lies in J+(p) but not in I+(p), and DB is future null.

(c) Spacelike and causally unrelated. DC=(5,7,0,0) has ∣DC0∣=5<7=∣DCs∣, so DC is spacelike and qC lies in neither J+(p) nor J−(p): the pair (p,qC) is causally unrelated.

(d) Future timelike with past-directed companion. DD=(5,−3,0,0) has η(DD,DD)=−25+9=−16<0 and DD0=5>0, so DD is future timelike; the past-directed companion is the event qE:=x−1(−5,3,0,0), whose displacement (−5,3,0,0) has η=−16<0, time component −5<0 and ∣xs∣=3, so qE lies in I−(p).

(e) The strict inequality D0>∣Ds∣, the equality D0=∣Ds∣>0 and the reversal ∣D0∣<∣Ds∣ of the coordinate criterion therefore separate, in this single computation, the three causal characters of the displacement and the two reachability relations; the numbers are exact integers and no measurement is reported.

Facts & Assumptions

Given: An inertial frame with chart x, η0=diag⁡(−1,1,1,1), the events p=x−1(0,0,0,0), qA=x−1(5,3,0,0), qB=x−1(5,5,0,0), qC=x−1(5,7,0,0), qD=x−1(5,−3,0,0) and qE=x−1(−5,3,0,0).

[L1]

Coordinate criterion: for events p,q with D=x(q)−x(p), q∈J+(p) iff D0≥∣Ds∣, and q∈I+(p) iff D0>∣Ds∣; moreover q∈J−(p) iff p∈J+(q) iff the displacement p−q satisfies (p−q)0≥∣(p−q)s∣ (The closed future cone in inertial coordinates: description, finite sums, and the coordinate criterion for causal reachability, Causal reachability, causal futures and pasts, causal diamonds, and reachability by future causal paths in affine Minkowski space).

[L2]

Diagonal form: η(D,D)=−(D0)2+∣Ds∣2 for coordinate differences D; a displacement is timelike iff η(D,D)<0, null iff D≠0 and η(D,D)=0, spacelike iff η(D,D)>0, and future-directed causal displacements are exactly the nonzero displacements with D0≥∣Ds∣ (Timelike, null, spacelike and causal vectors of a Lorentz vector space, Time orientation, future and past timelike/null/causal vectors, and the closed cones).

Verification

technique · direct
1.1givenL2algebra

The four displacements are DA=(5,3,0,0), DB=(5,5,0,0), DC=(5,7,0,0) and DD=(5,−3,0,0) by the linearity clause of the inertial chart, with spatial norms 3, 5, 7 and 3; the companion displacement is DE=qE−p=(−5,3,0,0) with spatial norm 3.

2.1step 1.1L1L2algebra

DA: DA0=5>3=∣DAs∣, so qA∈I+(p) by [L1] and η(DA,DA)=−25+9=−16<0 makes DA future timelike by [L2]; this is (a).

2.2step 1.1L1L2algebra

DB: DB0=5=∣DBs∣>0, so qB∈J+(p) and qB∉I+(p) by [L1], and η(DB,DB)=−25+25=0 with DB≠0 makes DB future null by [L2]; this is (b).

2.3step 1.1L1L2algebra

DC: ∣DC0∣=5<7=∣DCs∣ gives η(DC,DC)=−25+49=24>0, so DC is spacelike by [L2]; the criterion D0≥∣Ds∣ fails for both DC and −DC=p−qC, that is DC0≥∣DCs∣ is false and (p−qC)0=−5≥∣DCs∣=7 is false, so qC∈J+(p) and qC∈J−(p) both fail by [L1], and the pair is causally unrelated; this is (c).

2.4step 1.1L1L2algebra

DD: DD0=5>3=∣DDs∣ with η(DD,DD)=−25+9=−16<0 makes DD future timelike and qD∈I+(p) by [L1] and [L2]. For the companion, the displacement from p to qE is DE=(−5,3,0,0), whose reversed displacement (p−qE) has time component 5>∣(p−qE)s∣=3, so p∈I+(qE), that is qE∈I−(p), by [L1]; moreover η(DE,DE)=−25+9=−16<0 with time component −5<0 exhibits a past timelike displacement; this is (d).

3.1step 2.1step 2.2step 2.3step 2.4∎

Steps 2.1, 2.2 and 2.3 exhibit the three cases of the criterion (strict inequality, equality with positive time component, and failure in both directions), while step 2.4 exhibits a future timelike displacement together with a past-directed companion; all values are exact integers obtained from the diagonal form and the criterion, and no physical measurement or empirical claim is involved.

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Worked four-dimensional causal diamond and the boost-invariant area of its planar section

Example

Worked computation in the affine Minkowski model (Oriented time-oriented affine Minkowski space (the spacetime primitives)). In the chart x of an inertial frame with η0=diag⁡(−1,1,1,1) and all coordinate values expressed as numerical lengths in metres (Inertial frames and inertial charts of the affine Minkowski model) let p:=x−1(0,0,0,0) and q:=x−1(2,0,0,0). Interior is taken in the Euclidean topology transported by x. In this item the interval magnitude of a displacement D means ℓ(D):=∣η(D,D)∣; this is not a norm on V. For the planar polygons below, define a triangle with edge columns a,c∈R2 to have coordinate area 12∣a0c1−a1c0∣, and compute polygon area by the displayed disjoint-interior triangulations. The coordinate area carries square metres. Here c in the proper-time formula denotes the positive numerical conversion factor in metres per second.

(a) By the coordinate criterion (The closed future cone in inertial coordinates: description, finite sums, and the coordinate criterion for causal reachability) one has J+(p)={x−1(D):D0≥∣Ds∣},J−(q)={x−1(u):2−u0≥∣us∣}, as subsets of A; hence the causal diamond is J+(p)∩J−(q)={x−1(u):∣us∣≤u0≤2−∣us∣},∣us∣:=(u1)2+(u2)2+(u3)2, and its interior is I+(p)∩I−(q)={x−1(u):∣us∣<u0<2−∣us∣}.

(b) In the 1+1-dimensional section u2=u3=0 the diamond is the square with vertices x−1(0,0,0,0), x−1(1,1,0,0), x−1(2,0,0,0) and x−1(1,−1,0,0). Its diagonals are the straight timelike segment from p to q and the straight spacelike segment from x−1(1,1,0,0) to x−1(1,−1,0,0); both have length 2 m in the interval magnitude, and the area of the square in the (x0,x1)-plane is half the product of the diagonal lengths, that is 2 m2.

(c) For a passive boost with parameter b along the x1 direction the block of B(b) in the (0,1)-plane is γ(1−b−b1) with γ=(1−b2)−1/2 (The passive Lorentz boost with parameter beta), whose determinant is γ2(1−b2)=1. Let x′ be the chart of the inertial frame related to x by this boost, so that x′=B(b)∘x (The passive boost is a proper orthochronous Lorentz map with inverse B(-beta), Lorentz maps are isomorphisms of determinant ±1 that preserve causal character and permute the cones; the Lorentz sets are groups, Linear and affine Lorentz maps, and the Lorentz group); the coordinate image of the 1+1 section in x′ is the parallelogram with centre γ(1,−b) and half-diagonal vectors γ(1,−b) and γ(−b,1), whose area is 2γ2(1−b2)=2 m2. Hence the area of the diamond in the (x0,x1)-plane is the same in the chart of every frame related to x by such a boost; this is the source's invariance of the area of a light-rectangle.

(d) The identification of this area with a physical time or clock reading is not made here. With c retained, the interval magnitude of the timelike diagonal is −η(D,D)=2 m and, for the straight future timelike segment from p to q, the proper time is 2/c s (Proper time along a future timelike worldline, The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn, The inner-product norm is definite, homogeneous, and satisfies the triangle inequality); no clock reading is asserted.

Facts & Assumptions

Given: An inertial frame with chart x and η0=diag⁡(−1,1,1,1), the events p=x−1(0,0,0,0) and q=x−1(2,0,0,0), and for a real b with ∣b∣<1 the boost B(b):=B(be1) of the (0,1)-plane with γ=(1−b2)−1/2.

[L1]

Coordinate criterion: for events r,s with D=x(s)−x(r), s∈J+(r) iff D0≥∣Ds∣ and s∈I+(r) iff D0>∣Ds∣; also J+(r)=r+C+‾ and I+(r)=r+C+ (The closed future cone in inertial coordinates: description, finite sums, and the coordinate criterion for causal reachability, Causal reachability, causal futures and pasts, causal diamonds, and reachability by future causal paths in affine Minkowski space).

[L2]

Diagonal form: η(D,D)=−(D0)2+∣Ds∣2; a displacement is timelike iff η(D,D)<0 and spacelike iff η(D,D)>0 (Timelike, null, spacelike and causal vectors of a Lorentz vector space).

[L3]

Chart linearity: x(s)−x(r)=E−1(s−r), so coordinate differences of events are the coordinates of their displacement (Inertial frames and inertial charts of the affine Minkowski model).

[L4]

For ∣β∣<1 the passive boost acts in the (0,1)-plane by x′0=γ(x0−βx1), x′1=γ(x1−βx0); it is a proper orthochronous Lorentz map with inverse B(−β), so the ordered basis ea′:=B(β)−1ea is η-orthonormal, future and positively oriented and is the basis of an inertial frame whose chart satisfies x′=B(β)∘x (The passive Lorentz boost with parameter beta, The passive boost is a proper orthochronous Lorentz map with inverse B(-beta), Lorentz maps are isomorphisms of determinant ±1 that preserve causal character and permute the cones; the Lorentz sets are groups, Linear and affine Lorentz maps, and the Lorentz group).

[L5]

For the straight future timelike segment s↦p+s(q−p), s∈[0,1], the elapsed proper time is c−1−η(q−p,q−p), and the interval magnitude of the displacement is −η(q−p,q−p) (Proper time along a future timelike worldline, The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn, The inner-product norm is definite, homogeneous, and satisfies the triangle inequality).

[L6]

The coordinate Euclidean norm satisfies the triangle inequality, hence ∣∣us∣−∣vs∣∣≤∣us−vs∣; the Euclidean scalar product is the sum of coordinate products (The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn, The inner-product norm is definite, homogeneous, and satisfies the triangle inequality).

Verification

technique · direct
1.1givenL1L3L6algebra

Let r=x−1(u) be an event with coordinates u. By [L3] the displacement r−p has coordinates u, so [L1] gives r∈J+(p) iff u0≥∣us∣; likewise the displacement q−r has coordinates (2−u0,−u1,−u2,−u3) of spatial norm ∣us∣, so r∈J−(q) iff q∈J+(r) iff 2−u0≥∣us∣. Hence the diamond is {x−1(u):∣us∣≤u0≤2−∣us∣}, and the two strict versions give I+(p)∩I−(q)={x−1(u):∣us∣<u0<2−∣us∣} by the strict clauses of [L1]. For the interior: the triangle inequality gives ∣∣us∣−∣vs∣∣≤∣us−vs∣≤∥u−v∥2, so each of the functions u↦u0−∣us∣ and u↦2−u0−∣us∣ changes by at most 2∥u−v∥2. At a point where both are positive, the coordinate ball of radius half their smaller value keeps both positive, i.e. lies in the interior of the diamond; if u0=∣us∣ or u0=2−∣us∣, every neighbourhood contains points with u0 decreased or increased slightly, which violate u0≥∣us∣ or u0≤2−∣us∣, so such points are not interior; hence the interior is exactly the displayed open set, which is I+(p)∩I−(q); this is (a).

2.1step 1.1L2algebra

In the section u2=u3=0 the description of step 1.1 reads ∣u1∣≤u0≤2−∣u1∣, whose boundary consists of the four segments joining (0,0) to (1,1), (1,1) to (2,0), (2,0) to (1,−1) and (1,−1) to (0,0): the square with those four vertices (successive edge columns have squared Euclidean length 2 and scalar product 0). Its diagonals are the displacement (2,0,0,0) from p to q, of interval magnitude −η=4=2 m, and the displacement (0,2,0,0) from x−1(1,−1,0,0) to x−1(1,1,0,0), of interval magnitude η=4=2 m, both by [L2]; relative to its centre (1,0), the four triangles have edge columns chosen from (±1,0) and (0,±1), each of area 1/2 by the stated coordinate-area definition, so their total area is 2 m2, also 12⋅2⋅2; this is (b).

3.1step 2.1L4algebra

By [L4] the chart x′ of the boosted frame satisfies x′=B(b)∘x, so the x′-coordinates of the events of the 1+1 section are the images under the linear map B(b) of their x-coordinates, and the coordinate image of the square of step 2.1 is the parallelogram spanned by the images of the two diagonals: B(b)(2,0)=2γ(1,−b) and B(b)(0,2)=2γ(−b,1). Its centre is B(b)(1,0)=γ(1,−b), its half-diagonal vectors are a:=γ(1,−b) and c:=γ(−b,1), and it is the union of the four triangles (0,±a,±c) in centred coordinates, each of area 12∣det⁡(a,c)∣; hence its area is 2∣det⁡(a,c)∣=2γ2(1⋅1−(−b)(−b))=2γ2(1−b2)=2 m2, since γ2(1−b2)=1; this holds for every ∣b∣<1 and is (c).

4.1step 1.1step 2.1step 3.1L5given∎

Clause (a) is step 1.1, clause (b) is step 2.1, clause (c) is step 3.1, and clause (d) follows from [L5] applied to the straight segment from p to q, whose displacement has η=−4 m2 and interval magnitude 2 m, giving proper time 2/c s; nothing in the computation identifies the coordinate area 2 m2 with a physical time or clock reading, and no measurement is reported.

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Parallel future null displacements compose to a future null displacement

Example

Worked computation in the chart x of an inertial frame (Inertial frames and inertial charts of the affine Minkowski model). Let v:=(1,1,0,0) and w:=(2,2,0,0) be coordinate columns with respect to the basis of the frame.

(a) Both vectors are future null: η(v,v)=−1+1=0 and η(w,w)=−4+4=0 with positive time components, and w=2v, so the two directions are parallel (Timelike, null, spacelike and causal vectors of a Lorentz vector space).

(b) The sum v+w=(3,3,0,0) is again future null, since η(v+w,v+w)=−9+9=0 and its time component is positive, and the endpoint q:=x−1(3,3,0,0) lies in J+(p) for p:=x−1(0,0,0,0) but not in I+(p), by the coordinate criterion (The closed future cone in inertial coordinates: description, finite sums, and the coordinate criterion for causal reachability, Causal reachability, causal futures and pasts, causal diamonds, and reachability by future causal paths in affine Minkowski space); the straight path s↦p+s(q−p) has constant tangent v+w, so it is a straight future null path from p to q.

(c) This is the boundary case of the sum clause of the same lemma: for nonzero future causal vectors u and z the sum u+z is future causal, and it is future null exactly when u and z are both future null and positive multiples of one another, as here. By contrast the explicit nonparallel future null pair (1,1,0,0) and (1,−1,0,0) has sum (2,0,0,0), whose squared norm is −4: the sum of two future null displacements is null only in the parallel case.

Facts & Assumptions

Given: An inertial frame with chart x and η0=diag⁡(−1,1,1,1), the vectors v=(1,1,0,0) and w=(2,2,0,0), the events p=x−1(0,0,0,0) and q=x−1(3,3,0,0), and the pair u0=(1,1,0,0), z0=(1,−1,0,0).

[L1]

Coordinate criterion and cone description: for a vector v=(v0,vs) with spatial norm ∣vs∣, v∈C+‾ iff v0≥∣vs∣, v∈C+ iff v0>∣vs∣, and v is future null exactly when ∣vs∣=v0>0; for events r,s with D=x(s)−x(r), s∈J+(r) iff D0≥∣Ds∣ and s∈I+(r) iff D0>∣Ds∣ (The closed future cone in inertial coordinates: description, finite sums, and the coordinate criterion for causal reachability).

[L2]

Causal classification: η(v,v)=−(v0)2+∣vs∣2 in the inertial basis; v is null exactly when v≠0 and η(v,v)=0, and timelike when η(v,v)<0 (Timelike, null, spacelike and causal vectors of a Lorentz vector space); the sum of two elements of C+‾ lies in C+‾, and if one of them lies in C+ the sum lies in C+ (The closed future cone in inertial coordinates: description, finite sums, and the coordinate criterion for causal reachability).

[L3]

Euclidean structure: for spatial coordinate vectors p,q the norm satisfies ∣p∣2=∑i(pi)2, ∣p∣=0 implies p=0, the triangle inequality ∣p+q∣≤∣p∣+∣q∣ holds, and ∣p+q∣2=∣p∣2+2p⋅q+∣q∣2 with the Euclidean scalar product p⋅q (The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn, The Euclidean spatial structure and cross product of an inertial frame, The inner-product norm is definite, homogeneous, and satisfies the triangle inequality).

[L4]

Chart linearity: coordinate differences of events are the coordinates of their displacement (Inertial frames and inertial charts of the affine Minkowski model).

Verification

technique · direct
1.1givenL1L2algebra

The evaluations η(v,v)=−1+1=0, η(w,w)=−4+4=0 and the displayed w=2v hold by the diagonal form of [L2]; both vectors are nonzero with positive time components, so [L1] makes them future null; this is (a).

2.1givenstep 1.1L1L2L4algebra

The sum is v+w=(3,3,0,0) with η(v+w,v+w)=−9+9=0 and time component 3>0, so it is future null by [L1]; by [L4] the displacement q−p has coordinates (3,3,0,0), so the criterion gives 3≥3, that is q∈J+(p), while 3>3 is false, that is q∉I+(p). The straight path s↦p+s(q−p) has constant tangent q−p with coordinates v+w, a future null vector, so it is a straight future null path from p to q; this is (b).

2.2step 1.1L1L2L3algebra

For the characterization let u=(a,p) and z=(b,q) be nonzero future causal vectors written in the inertial basis, so that a≥∣p∣, b≥∣q∣ and a,b>0 because a future causal vector with vanishing time component has vanishing spatial part. If u+z is null then (a+b)2=∣p+q∣2, so by [L3] a+b=∣p+q∣≤∣p∣+∣q∣≤a+b and every inequality is an equality; in particular ∣p∣=a, ∣q∣=b and ∣p+q∣=∣p∣+∣q∣. Expanding with [L3], ∣p+q∣2=∣p∣2+2p⋅q+∣q∣2 equals (∣p∣+∣q∣)2=∣p∣2+2∣p∣∣q∣+∣q∣2, hence p⋅q=∣p∣∣q∣; since a=∣p∣>0, the vector q−bap has squared norm ∣q∣2−2bap⋅q+b2a2∣p∣2=b2−2b2+b2=0, so q=bap by positive definiteness of the norm and z=bau with ba>0; moreover u and z are future null because ∣p∣=a and ∣q∣=b with a,b>0. Conversely, if z=λu with λ>0 and u future null, then u+z=(1+λ)u has η((1+λ)u,(1+λ)u)=(1+λ)2η(u,u)=0 and positive time component, so it is future null; this proves the characterization of (c).

3.1step 2.1step 2.2L1L2algebra∎

For the nonparallel pair, u0=(1,1,0,0) and z0=(1,−1,0,0) are future null by [L1] since ∣(1)∣=1=∣(1)∣ and ∣(−1)∣=1 with time component 1>0, while their sum is (2,0,0,0) with η=−4<0, a future timelike vector by [L2]: the sum of two future null displacements is therefore null exactly in the parallel case established in step 2.2, which is the boundary case of the sum clause illustrated by v and w in steps 1.1 and 2.1; all computations are exact integer evaluations and no choice principle is used.

ExampleConstruction: AI-adaptedVerification: AI-generatedjudge pass (gpt-6.1-sol)Open item page →

A prearranged sweep with superluminal coordinate speed: successive events are spacelike separated and can be made simultaneous

Example

Worked computation in the chart x of an inertial frame with x0 in metres and c>0 (Inertial frames and inertial charts of the affine Minkowski model). Fix w>c and consider the family Eξ:=x−1(cwξ, ξ, 0, 0),ξ∈R, a prearranged array of devices at x1=ξ triggered at coordinate time t=ξ/w, so the pattern is a sweep of coordinate speed w>c along the row.

(a) For ξ<η the displacement is Eη−Eξ=(cw(η−ξ), η−ξ, 0, 0), whose interval is (η−ξ)2(1−c2/w2)>0, so successive events are spacelike separated; in particular no event Eη lies in J+(Eξ) or J−(Eξ) for η≠ξ, by the coordinate criterion (The closed future cone in inertial coordinates: description, finite sums, and the coordinate criterion for causal reachability).

(b) Let b:=c/w∈(0,1). The passive boost with parameter be1 (The passive Lorentz boost with parameter beta) maps the displacement to time component γb(cw(η−ξ)−b(η−ξ))=γb(η−ξ)(cw−cw)=0, so in the boosted chart xb the whole family consists of events simultaneous at one coordinate time; taking b>c/w produces the opposite sign γb(η−ξ)(cw−b), so the apparent temporal order of the sweep runs forward, frozen or backward in different inertial frames even though no event of the family is causally related to another (Spacelike-separated events: the spacelike coordinate inequality in every inertial chart, and an explicit family of inertial frames realizing every time-order sign).

(c) No signal statement is made or needed: the computation is a property of the spacetime locations of independently triggered events, and it exhibits the class of spacelike-separated patterns that a kinematic superluminal speed bound cannot exclude. It is a statement about the locations of the events, it asserts nothing about any of them being the reception of a signal, and it does not model the fixed-speed relay kinematics of the hypothetical superluminal model treated on the companion page.

Facts & Assumptions

Given: An inertial frame with chart x and origin event o=x−1(0,0,0,0), a constant c>0, a real w>c, the family Eξ=x−1((c/w)ξ,ξ,0,0) of events, and for ∣b∣<1 the boost B(be1) with γb=(1−b2)−1/2.

[L1]

For the spacelike pair (E0,E1) with displacement D=(c/w,1,0,0) and spatial unit direction e1, and for every ∣b∣<1, the chart xb of the inertial frame with the same origin o and basis ea′:=B(be1)−1ea satisfies xb=B(be1)∘x and xb0(E1)−xb0(E0)=γb(D0−b∣Ds∣); in general ∣D0∣<∣Ds∣ in every inertial chart (Spacelike-separated events: the spacelike coordinate inequality in every inertial chart, and an explicit family of inertial frames realizing every time-order sign).

[L2]

The passive boost acts in the (0,1)-plane by x′0=γ(x0−bx1), x′1=γ(x1−bx0) and is linear in the coordinate column (The passive Lorentz boost with parameter beta).

[L3]

Diagonal form and classification: η(D,D)=−(D0)2+∣Ds∣2, and D is spacelike exactly when η(D,D)>0, timelike exactly when η(D,D)<0 (Timelike, null, spacelike and causal vectors of a Lorentz vector space).

[L4]

Coordinate criterion for reachability: for events r,s with D=x(s)−x(r), s∈J+(r) iff D0≥∣Ds∣, and s∈J−(r) iff −D0≥∣Ds∣ (The closed future cone in inertial coordinates: description, finite sums, and the coordinate criterion for causal reachability, Causal reachability, causal futures and pasts, causal diamonds, and reachability by future causal paths in affine Minkowski space).

[L5]

Chart linearity: x(s)−x(r)=E−1(s−r) for events r,s (Inertial frames and inertial charts of the affine Minkowski model).

Verification

technique · direct
1.1givenL3L4L5algebra

For ξ<η the displacement of the family is Eη−Eξ=((c/w)(η−ξ),η−ξ,0,0) by [L5], so η(Eη−Eξ,Eη−Eξ)=−(c/w)2(η−ξ)2+(η−ξ)2=(η−ξ)2(1−c2/w2)>0 because w>c and η−ξ>0; hence the displacement is spacelike by [L3]. For η>ξ the first criterion of [L4] would require (c/w)(η−ξ)≥η−ξ, which fails since c/w<1, and the second would require −(c/w)(η−ξ)≥η−ξ, which also fails; the case ξ>η is the same computation with the roles exchanged, so no event of the family lies in the causal future or past of another; this is (a).

2.1step 1.1L1L2L5algebra

Set b:=c/w∈(0,1). The vector E1−E0 is spacelike by step 1.1, so [L1] applies with the origin event o and gives the chart xb=B(be1)∘x of an inertial frame; by linearity [L2] and [L5], xb(Eη)−xb(Eξ)=B(be1)(Eη−Eξ), whose time component is γb((c/w)(η−ξ)−b(η−ξ))=γb(η−ξ)(c/w−c/w)=0 for all ξ,η; hence all events Eξ share the coordinate time xb0. For a parameter b′>c/w with b′<1, which exists because c/w<1, the same computation gives xb′0(Eη)−xb′0(Eξ)=γb′(η−ξ)(c/w−b′), of sign opposite to η−ξ; so the temporal order of the sweep runs forward in x, is frozen in xb and runs backward in xb′; this is (b).

3.1step 1.1step 2.1given∎

Steps 1.1 and 2.1 compute only the locations and coordinate differences of the family Eξ and the chart changes of those coordinate differences; the family is prearranged and independently triggered, no displacement of the family is causal in either direction, and nothing in the computation identifies an event Eξ with the reception of a signal or with the relay model of the companion page; the sweep is a kinematic pattern whose temporal order is frame-dependent without any causal relation among its events, and no choice principle is used.

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Worked relay arithmetic at u=2c and v=(9/10)c: arrival at t=−50/(121c) seconds

Example

Worked computation in the chart x of an inertial frame of an affine Minkowski space (Oriented time-oriented affine Minkowski space (the spacetime primitives), Inertial frames and inertial charts of the affine Minkowski model) with x0=ct for a fixed constant c>0. Throughout this numerical example, xa and L are numerical values in metres, t and Δt are numerical values in seconds, and c,u,v are numerical values in metres per second; units after a formula apply to its numerical value. Take u:=2c, v:=(9/10)c and L:=1 (a length of 1 m), so that u>c, 0<v<c and v>2u/(1+u2/c2)=(4/5)c. Let A and B have affine curves a(t)=x−1(ct,0,0,0) and b(t)=x−1(ct,L+vt,0,0) for t∈R. Their constant tangents (c,0,0,0) and (c,v,0,0) are future timelike since 0<v<c. Emit from A at the event A0:=x−1(0,0,0,0) a signal travelling at coordinate speed u in the +x1 direction, and let B re-emit immediately from the reception event B1 a signal travelling at coordinate speed u in the −x1 direction of B's rest frame; this fixed-speed, immediate, lossless relay is the whole content of the hypothetical model, and no device, signal or measurement is asserted to exist.

(a) The reception time solves ut=L+vt, so t(B1)=Lu−v=1011c s,x1(B1)=ut(B1)=2011 m, and the displacement B1−A0=(1011,2011,0,0) m has interval η=−100121+400121=300121>0: it is spacelike.

(b) Write β:=v/c=9/10, γ:=(1−β2)−1/2=10/19, and let x′=B(β)x be the chart of the inertial frame in which B is at rest (The passive Lorentz boost with parameter beta, The passive boost is a proper orthochronous Lorentz map with inverse B(-beta)). In that chart the return displacement is (c Δt′,−u Δt′) with Δt′>0, and transforming back with the inverse boost c Δt=γ(c Δt′−βu Δt′),Δx1=γ(−u Δt′+βc Δt′), the condition that the arrival lies on A's worldline x1=0 gives Δx1=−x1(B1), hence Δt′=x1(B1)γ(u−v)>0,Δt=x1(B1)(1−vu/c2)u−v=2011(−45)1011c=−160121c s.

(c) The arrival event A1 therefore satisfies t(A1)=t(B1)+Δt=1011c−160121c=−50121c s<0, matching the closed formula L(2u−v−vu2/c2)/(u−v)2=(−c/2)/(121c2/100)=−50/(121c) s. The displacement A1−A0=(−50121,0,0,0) m is past timelike, so the relayed signal is received strictly before it was emitted in the chart of the emitter; the return displacement in x is (−160121,−220121,0,0) m with η=−(160121)2+(220121)2>0, spacelike.

(d) The computation is an arithmetic specialization of the hypothetical fixed-speed model (signals at fixed coordinate speed u>c in each emitter's rest frame, immediate lossless relaying, inertial motion at v<c, ordinary Lorentz kinematics of displacements); it is a conditional identity about that model and neither asserts that such signals or devices exist nor reports any measurement.

Facts & Assumptions

Given: An inertial frame with chart x, x0=ct, a constant c>0, the numerical data u=2c, v=(9/10)c, L=1 (numerical metres), β=v/c=9/10, the affine curves a(t)=x−1(ct,0,0,0) of A and b(t)=x−1(ct,L+vt,0,0) of B, t∈R, the emission event A0=x−1(0,0,0,0), and the hypothetical relay: outgoing leg of coordinate speed u in the +x1 direction from A0, immediate re-emission at the reception event B1 of a return leg of coordinate speed u in the −x1 direction of B's rest frame.

[L1]

Coordinate criterion: for events p,q with D=x(q)−x(p), q∈J+(p) iff D0≥∣Ds∣, and q∈I+(p) iff D0>∣Ds∣; J−(p)={q:q≤p} (The closed future cone in inertial coordinates: description, finite sums, and the coordinate criterion for causal reachability, Causal reachability, causal futures and pasts, causal diamonds, and reachability by future causal paths in affine Minkowski space).

[L2]

For ∣β∣<1 the passive boost acts on coordinates by x′0=γ(x0−βx1), x′1=γ(x1−βx0) in the (0,1)-plane with γ=(1−β2)−1/2, its inverse is B(−β) with inverse formulas x0=γ(x′0+βx′1), x1=γ(x′1+βx′0), and B(β) is a proper orthochronous Lorentz map (The passive Lorentz boost with parameter beta, The passive boost is a proper orthochronous Lorentz map with inverse B(-beta)).

[L3]

The ordered basis ea′:=B(β)−1ea is η-orthonormal, future and positively oriented, so (o;e0′,e1′,e2′,e3′) is an inertial frame; its chart satisfies x′(r)=B(β)x(r) (The passive boost is a proper orthochronous Lorentz map with inverse B(-beta), Lorentz maps are isomorphisms of determinant ±1 that preserve causal character and permute the cones; the Lorentz sets are groups, Inertial frames and inertial charts of the affine Minkowski model, Linear and affine Lorentz maps, and the Lorentz group).

[L4]

A displacement is spacelike iff η(D,D)>0 and timelike iff η(D,D)<0; for a timelike displacement with negative time component the reversed displacement has positive time component dominating its spatial part, giving A0∈J+(A1) by [L1] (Timelike, null, spacelike and causal vectors of a Lorentz vector space).

Verification

technique · direct
1.1givenL4algebra

The reception event B1 has ut=x1=L+vt, so t(B1)=L/(u−v)=1/((2−910)c)=1011c s and x1(B1)=ut(B1)=2011 m; the displacement is B1−A0=(c t(B1),x1(B1),0,0)=(1011,2011,0,0) m, with η(D,D)=−(1011)2+(2011)2=300121>0 and D0>0, so it is spacelike with positive time component in x; this is (a).

2.1step 1.1L2L3algebra

With β=v/c=9/10, the basis ea′=B(β)−1ea is the basis of an inertial frame by [L3], and its chart satisfies x′=B(β)x with inverse x=B(−β)x′, that is x0=γ(x′0+βx′1), x1=γ(x′1+βx′0); moreover γ=(1−81/100)−1/2=(19/100)−1/2=10/19.

3.1step 1.1step 2.1L2L3algebra

In the chart x′ the worldline of B is constant in x′1, since x′1=γ(x1−910x0)=γ(L+vt−910ct)=γL; the return leg moves in the −x′1 direction at coordinate speed u, so its displacement in x′ is (c Δt′,−u Δt′) for a single Δt′, and applying the inverse formula of step 2.1 to its x1-component gives Δx1=γ(βc Δt′−u Δt′)=γ(v−u)Δt′.

4.1step 3.1L2algebra

The arrival event lies on the worldline x1=0 of A, so Δx1=−x1(B1)=−2011 m, and step 3.1 gives Δt′=x1(B1)/(γ(u−v))>0; substituting into the time component of the inverse formula gives Δt=Δx0c=γ Δt′(1−vuc2)=x1(B1)(1−vu/c2)u−v, and with vu/c2=910⋅2=95 this is 2011(−45)1011c=−160121c s; this is (b).

5.1step 1.1step 4.1L1L4algebra

Adding the two legs gives t(A1)=t(B1)+Δt=1011c−160121c=110−160121c=−50121c s, and the closed formula L(2u−v−vu2/c2)/(u−v)2 evaluates as (4c−910c−910⋅4c)/(1110c)2=(−c2)/(121100c2)=−50121c s, the same number. The displacement A1−A0=(−50121,0,0,0) m has η=−(50121)2<0, so it is timelike, and the reversed displacement A0−A1=(50121,0,0,0) has time component 50121>0=∣Ds∣, so A0∈I+(A1) by [L1]: the arrival is in the strict chronological past of the emission. The return displacement in x is (−160121,−220121,0,0) m because its x1-component is −2011=−220121 m, and its interval is η=−(160121)2+(220121)2>0, so it is spacelike; this is (c).

6.1step 5.1given∎

Steps 1.1 to 5.1 are an arithmetic specialization of the hypothetical fixed-speed relay model with its stated inputs, and no step uses any property beyond the Lorentz kinematics of the boost and the causal classification of the two displacements; the reception of the relayed signal strictly before its emission in the chart of the emitter is therefore a conditional conclusion of that model, not a report of a measurement and not an assertion that superluminal signals or the devices realizing the relay exist; this is (d).

CounterexampleConstruction: AI-generatedVerification: AI-generatedjudge pass (gpt-6.1-sol)Open item page →

Counterexample: a causally related pair of events need not be joinable by a future timelike worldline

Statement refuted

False claim. If q lies in J+(p) then q lies in I+(p), that is, every causally related pair of events can be joined by a future timelike worldline (Causal reachability, causal futures and pasts, causal diamonds, and reachability by future causal paths in affine Minkowski space).

Facts & Assumptions

Given: An inertial frame with chart x, the events p=x−1(0,0,0,0) and q=x−1(3,3,0,0), and the displacement D=q−p with coordinates (3,3,0,0).

[L1]

Coordinate criterion and cone description: q∈J+(p) iff D0≥∣Ds∣, and q∈I+(p) iff D0>∣Ds∣; a vector v is future null exactly when ∣vs∣=v0>0 (The closed future cone in inertial coordinates: description, finite sums, and the coordinate criterion for causal reachability).

[L2]

Causal classification: η(v,v)=−(v0)2+∣vs∣2; a nonzero vector with η(v,v)=0 is null, and a vector with η(v,v)>0 is spacelike (Timelike, null, spacelike and causal vectors of a Lorentz vector space).

[L3]

Reachability: J+(p) and I+(p) are the causal and chronological futures of p defined by the displacements q−p∈C+‾ and q−p∈C+, and a future timelike worldline is a C1 curve with future timelike tangent everywhere (Causal reachability, causal futures and pasts, causal diamonds, and reachability by future causal paths in affine Minkowski space, Curves, regular causal curves and future timelike worldlines in affine Minkowski space).

[L4]

Displacement of a future causal path: for a piecewise C1 future causal path with a future timelike one-sided tangent at some point, the displacement lies in C+ (Future causal reachability, absence of causal loops, time monotonicity and the straight-worldline proper-time maximum).

[L5]

The false claim of the statement refuted section.

Counterexample

technique · direct
1.1givenL1L2algebra

The displacement has coordinates D=(3,3,0,0), so η(D,D)=−9+9=0 with D≠0 and D0=3>0; by [L2] and [L1] the vector D is future null, since ∣Ds∣=3=D0>0.

2.1step 1.1L1L3algebra

By [L1], 3≥3 gives q∈J+(p), while 3>3 is false, so q∉I+(p); hence the pair is causally related without belonging to the chronological relation, and the straight path from p to q has the constant tangent D, which is future null and not future timelike.

2.2step 1.1L2L3L4

No future timelike worldline y:[a,b]→A with y(a)=p and y(b)=q exists: if y were one, it would be in particular a piecewise C1 future causal path with a future timelike tangent at every point by [L3], so [L4] would put its displacement q−p=D in C+, and then [L2] would give η(D,D)<0, contradicting η(D,D)=0 from step 1.1.

3.1step 2.1step 2.2L5∎

Steps 2.1 and 2.2 exhibit a pair with q∈J+(p) and q∉I+(p) that is not joinable by any future timelike worldline, while the null straight segment realizes the causal relation; the claim of [L5] is therefore false, and no choice principle is used.

CounterexampleConstruction: AI-generatedVerification: AI-generatedjudge pass (gpt-6.1-sol)Open item page →

Counterexample: the temporal order of a spacelike-separated pair is not the same in every inertial frame

Statement refuted

False claim. For any two distinct events p,q of the affine Minkowski model, the sign of the time-coordinate difference x0(q)−x0(p) is independent of the inertial frame (Inertial frames and inertial charts of the affine Minkowski model).

Facts & Assumptions

Given: An inertial frame with chart x, the events p=x−1(0,0,0,0) and q=x−1(11,13,0,0), and the displacement D=q−p with coordinates (11,13,0,0).

[L1]

For a spacelike displacement ∣D0∣<∣Ds∣ holds in every inertial chart, and for every ∣b∣<1 the chart xb of the inertial frame with basis B(be1)−1ea (same origin) satisfies xb=B(be1)∘x and xb0(q)−xb0(p)=γb(D0−b∣Ds∣) with γb=(1−b2)−1/2 (Spacelike-separated events: the spacelike coordinate inequality in every inertial chart, and an explicit family of inertial frames realizing every time-order sign).

[L2]

For ∣b∣<1 the passive boost acts in the (0,1)-plane by x′0=γ(x0−bx1), x′1=γ(x1−bx0) and is a proper orthochronous Lorentz map (The passive Lorentz boost with parameter beta, The passive boost is a proper orthochronous Lorentz map with inverse B(-beta)).

[L3]

Diagonal form and classification: η(D,D)=−(D0)2+∣Ds∣2; a nonzero vector with positive squared norm is spacelike (Timelike, null, spacelike and causal vectors of a Lorentz vector space).

[L4]

Time monotonicity: for every piecewise C1 future causal path that is nonconstant on [a′,b′], every inertial chart gives (x0∘y)(b′)>(x0∘y)(a′); and for q≠p with q∈J+(p) the straight path from p to q is a future causal path (Future causal reachability, absence of causal loops, time monotonicity and the straight-worldline proper-time maximum).

[L5]

The false claim of the statement refuted section.

Counterexample

technique · direct
1.1givenL1L3algebra

The displacement has coordinates D=(11,13,0,0), so η(D,D)=−121+169=48>0 and ∣D0∣=11<13=∣Ds∣; by [L3] the displacement is spacelike, so [L1] applies to the pair.

2.1step 1.1L1L2algebra

With b=3/5, admissible since ∣b∣<1, one has γb=(1−9/25)−1/2=5/4, so the chart x3/5 of the inertial frame of [L1] satisfies x3/50(q)−x3/50(p)=γb(11−13b)=(5/4)(11−39/5)=(5/4)(16/5)=4>0.

2.2step 1.1L1L2algebra

With b=12/13, admissible since ∣b∣<1, one has γb=(1−144/169)−1/2=13/5, so x12/130(q)−x12/130(p)=γb(11−13b)=(13/5)(11−12)=−13/5<0.

3.1step 1.1step 2.1step 2.2L1L4L5∎

The charts x3/5 and x12/13 are charts of inertial frames of the model by [L1] and [L2], and they assign to the same pair of events (p,q) time-coordinate differences of opposite sign by steps 2.1 and 2.2; the claim of [L5] is therefore false. The failure is confined to spacelike-separated pairs: if q≠p with q−p future causal, then [L4] gives the straight path from p to q as a nonconstant future causal path, so every inertial chart gives x0(q)−x0(p)>0; no choice principle is used.

ExampleConstruction: AI-generatedVerification: AI-generatedOpen item page →

Two nonparallel future null legs compose to a future timelike displacement

Example

Worked computation in the chart x of an inertial frame (Inertial frames and inertial charts of the affine Minkowski model). Let p:=x−1(0,0,0,0) and let xcurve:[0,2]→A be the piecewise straight path with xcurve(s)=x−1(s,s,0,0)  (s∈[0,1]),xcurve(s)=x−1(s,1,s−1,0)  (s∈[1,2]).

(a) Both legs have constant future null tangents: η((1,1,0,0),(1,1,0,0))=−1+1=0 and η((1,0,1,0),(1,0,1,0))=−1+1=0, with positive time components.

(b) The total displacement is D=(2,1,1,0) with η(D,D)=−4+1+1=−2<0 and D0=2>0, so D is future timelike (Timelike, null, spacelike and causal vectors of a Lorentz vector space, Time orientation, future and past timelike/null/causal vectors, and the closed cones) and the endpoint q:=x−1(2,1,1,0) lies in I+(p) by the coordinate criterion (The closed future cone in inertial coordinates: description, finite sums, and the coordinate criterion for causal reachability), although every tangent of the path is null.

(c) Consistently with the sum clause of the same lemma, the sum of the two nonparallel future null vectors is future timelike, and the straight path from p to q, whose tangent is D, is a future timelike straight worldline by Future causal reachability, absence of causal loops, time monotonicity and the straight-worldline proper-time maximum. The path xcurve is a future causal path whose displacement is strictly timelike and whose tangents are nowhere timelike; the strict clause of part (a) of that theorem is an implication from a timelike tangent to a timelike displacement and not an equivalence, so no contradiction arises.

Facts & Assumptions

Given: An inertial frame with chart x and η0=diag⁡(−1,1,1,1), the event p=x−1(0,0,0,0), the piecewise straight path xcurve with legs x−1(s,s,0,0) on [0,1] and x−1(s,1,s−1,0) on [1,2], and the endpoint q=x−1(2,1,1,0).

[L1]

Diagonal form and classification: for coordinates v=(v0,vs), η(v,v)=−(v0)2+∣vs∣2; a nonzero vector is null when η(v,v)=0, spacelike when η(v,v)>0, and timelike when η(v,v)<0; future null means nonzero null with positive time coordinate (Timelike, null, spacelike and causal vectors of a Lorentz vector space, Time orientation, future and past timelike/null/causal vectors, and the closed cones).

[L2]

Coordinate criterion and sums: q∈I+(p) iff D0>∣Ds∣ for D=x(q)−x(p), and the sum of finitely many future causal vectors is future causal, strictly timelike if one summand is future timelike (The closed future cone in inertial coordinates: description, finite sums, and the coordinate criterion for causal reachability). The nonparallel null case is a local calculation, not an extra conclusion of that supplier: write the vectors (a,p) and (b,q) with a=∣p∣>0 and b=∣q∣>0. If they are not parallel, p/a≠q/b, so ∣p/a−q/b∣2=2−2(p⋅q)/(ab)>0 by the spatial Euclidean structure. Thus η((a,p)+(b,q),(a,p)+(b,q))=2(p⋅q−ab)=−ab∣p/a−q/b∣2<0, and the positive time component a+b makes the sum future timelike. The spatial norm and scalar product are those of the named inertial frame (The Euclidean spatial structure and cross product of an inertial frame, The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn).

[L3]

Straight paths and reachability: the straight path s↦p+s(q−p) has constant tangent q−p, and for q≠p one has q∈J+(p) iff that straight path is a future causal path, with I+(p) characterized by the straight path being future timelike; part (a) of the theorem also says that a future causal path with a future timelike one-sided tangent has future timelike displacement (Future causal reachability, absence of causal loops, time monotonicity and the straight-worldline proper-time maximum, Causal reachability, causal futures and pasts, causal diamonds, and reachability by future causal paths in affine Minkowski space).

[L4]

Piecewise C1 curves: the concatenation of the two straight legs is a piecewise C1 curve with constant tangents (1,1,0,0) and (1,0,1,0) on the open pieces and one-sided difference-quotient tangents equal to those vectors at every point of [0,2] (Curves, regular causal curves and future timelike worldlines in affine Minkowski space, The Euclidean spatial structure and cross product of an inertial frame, The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn).

Verification

technique · direct
1.1givenL1L4algebra

The first leg s↦x−1(s,s,0,0) has constant coordinate tangent (1,1,0,0), whose squared norm is −1+1=0 with time component 1>0, so it is future null by [L1]; the second leg s↦x−1(s,1,s−1,0) has constant coordinate tangent (1,0,1,0), whose squared norm is −1+1=0 with time component 1>0, so it is future null too; both legs are straight and their endpoint values at s=1 agree, so xcurve is continuous with those one-sided tangents throughout by [L4]; this is (a).

2.1step 1.1L1L2L4algebra

The total displacement is D=q−p with coordinates (2,1,1,0), namely the telescoping sum (1,1,0,0)+(1,0,1,0) of the two constant tangents; then η(D,D)=−4+1+1=−2<0 and D0=2>0, so D is future timelike by [L1], and D0=2>2=∣Ds∣ shows q∈I+(p) by [L2].

3.1step 1.1step 2.1L1L2L3algebra

The two null tangents (1,1,0,0) and (1,0,1,0) are not parallel (neither is a multiple of the other, as their second and third components show), and their sum D is future timelike by step 2.1, in agreement with the local nonparallel-null computation in [L2]; the straight path from p to q has the constant tangent D, which is future timelike, so it is a future timelike straight worldline and realizes the relation q∈I+(p) by [L3].

4.1step 1.1step 2.1step 3.1L2L3∎

The path xcurve is a piecewise C1 future causal path by [L4] and step 1.1 whose displacement is future timelike by step 2.1 while none of its tangents is timelike; the strict clause of part (a) of [L3] (a future timelike one-sided tangent forces a timelike displacement) is therefore not an equivalence, and the computed example is consistent with both the sum clause of [L2] and the strict clause of the theorem; no choice principle is used.

Sources