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How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

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Exact finite algebra entropy identities and holography boundaries — Examples

1 · Prerequisites

2 · Summary

3 · Logical flowchart

4 · Definitions, postulates, theorems and proofs

None yet.

5 · Examples, experiments and counterexamples

ExampleConstruction: AI-generatedVerification: AI-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Sector-dependent ancillary entropy

Example

Take two sectors with probabilities p1,p2>0 and p1+p2=1. Let H1,H2 be nonzero finite-dimensional complex inner-product spaces, choose density matrices ρ1,ρ2 on them, and choose q1,q2>0 with q1+q2=1 and faithful reference density matrices σ1,σ2 on the same spaces. Let the first ancillary space be one-dimensional with χ1=[1], and let the second be Cd for an integer d≥1, with χ2=Id/d. The encoded state has entropy

s(ρA)=H(p1,p2)+p1s(ρ1)+p2s(ρ2)+p2log⁡d,

where H(p1,p2):=−p1log⁡p1−p2log⁡p2 is the sector-probability entropy in nats. The sector-probability contribution is H(p1,p2) and the ancillary contribution is p2log⁡d; when d=1, the ancillary contribution is zero. This is an exact finite matrix example and asserts no literal black-hole area law.

Facts & Assumptions

Given: The two-sector data in the Statement and the finite sector entropy identity.

[F1]

Sector entropy and relative entropy identities: s(ρA)=H(p)+∑αpα(s(ρα)+s(χα)) for finite sectors with fixed faithful ancillary density matrices and a faithful encoded reference.

[F2]

Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm: for positive x,y, log⁡(x/y)=log⁡x−log⁡y and log⁡1=0.

Verification

1.1givenF2algebra

The one-dimensional matrix χ1=[1] has the single eigenvalue 1, so s(χ1)=−1log⁡1=0 by [F2].

1.2givenF2algebra

The eigenvalues of χ2=Id/d are 1/d with multiplicity d, hence s(χ2)=−d(1/d)log⁡(1/d)=log⁡d by [F2]; for d=1 this is log⁡1=0.

2.1givenF1step 1.1step 1.2algebra∎

Substitute s(χ1)=0 and s(χ2)=log⁡d from steps 1.1–1.2 into [F1] with I={1,2}. The result is s(ρA)=H(p1,p2)+p1s(ρ1)+p2s(ρ2)+p2log⁡d, with the sector-probability and ancillary contributions as stated.

Sources