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Potential outcomes and identification — Examples

1 · Prerequisites

2 · Summary

Finite worked models show how random assignment identifies a target contrast, how confounding changes an unadjusted comparison while standardization recovers the ATE, and how a positivity failure leaves two full-data laws with different effects compatible with the same observed law.

3 · Logical flowchart

4 · Definitions, theorems and proofs

None yet.

5 · Examples, counterexamples and false statements

ExampleConstruction: AI-generatedVerification: AI-generatedprecheck passjudge pass (gpt-6-luna)Open item page →

Randomized treatment identifies the target mean contrast

Example

Take Ω={u0,u1}×{0,1} with the uniform law. Let U and A be the first and second coordinates, let L be constant, and set Y0=0, Y1=1{U=u1}, and Y=YA. Then random assignment is independent of the potential outcomes, both treatment values have probability 1/2, and the target ATE is 1/2. The conditional means among the two treatment groups recover the same contrast.

Verification

Given: The finite probability space above; the definitions of potential outcomes and consistency, conditional exchangeability, positivity, and ATE; and the discrete-treatment identification theorem.

[A1] Choice is the axiom used by the library's conditional-expectation convention. The Axiom of Choice

[F1] Potential outcomes are indexed by treatment versions and consistency means Y=YA almost surely. Potential outcomes and consistency

[F2] Conditional exchangeability is conditional independence of the potential-outcome family and A given L. Conditional exchangeability of potential outcomes

[F3] Conditional independence given the trivial sigma-algebra is ordinary independence, using the bounded-product identity. Conditional independence given a sigma-algebra

[F4] Positivity requires positive marginal and conditional probability for each treatment value in the contrast. Positivity for discrete treatment

[F5] The ATE is E[Y1−Y0]. Average and conditional average treatment effects

[F6] Under consistency, conditional exchangeability and positivity, the potential-outcome mean equals the target-covariate integral of the observed treatment-stratum mean. Discrete-treatment potential-outcome means are identifiable

1.1givenF1algebra

Each of the four points (ui,a) has probability 1/4. By definition Y=YA, so consistency [F1] holds; Y0,Y1 are bounded and hence integrable.

1.2A1F2F3F4algebra

For i,a∈{0,1}, P(U=ui,A=a)=1/4=P(U=ui)P(A=a). The pair (Y0,Y1) is a function of U, so it is independent of A; since L is constant, [F2] and [F3] give conditional exchangeability. Also P(A=0)=P(A=1)=1/2, and conditioning on constant L leaves these probabilities unchanged, so [F4] holds.

2.1F5F6algebra∎

Under P0, U remains uniform and Y=Y0=0, so m0=0. Under P1, U remains uniform and Y=Y1, so m1=1/2. As PL is a point mass, [F6] gives E[Y0]=0 and E[Y1]=1/2; hence the identified ATE is 1/2, agreeing with [F5].

ExampleConstruction: AI-generatedVerification: AI-generatedprecheck passjudge pass (gpt-6-luna)Open item page →

Binary confounding and standardization

Example

Let Ω={0,1}×{1,2,3,4} with each point having probability 1/8, and write its coordinates as (L,W). Set A=1 when L=0,W=1 or when L=1,W∈{1,2,3}, and set A=0 otherwise. Let Y0=10L, Y1=10L+1, and Y=YA. Assignment depends on the prognostic covariate L, but both treatment arms occur in both strata. The target ATE is 1; the unadjusted treated-minus-untreated mean is 6; standardization over the target law of L returns 1.

Verification

Given: The finite probability space and variables above; the definitions of potential outcomes, conditional exchangeability, positivity, and ATE; and the discrete-treatment identification theorem.

[A1] Choice is assumed for the library's conditional-expectation classes. The Axiom of Choice

[F1] Consistency means that the observed outcome equals the potential outcome at the received treatment version. Potential outcomes and consistency

[F2] Conditional exchangeability is conditional independence of the full potential-outcome family and treatment given L. Conditional exchangeability of potential outcomes

[F3] If one side of conditional independence is measurable with respect to the conditioning sigma-algebra, conditional independence holds. Conditional independence given a sigma-algebra

[F4] Positivity requires positive treatment probability in each target covariate stratum for every treatment in the contrast. Positivity for discrete treatment

[F5] The ATE is the target-population mean of Y1−Y0. Average and conditional average treatment effects

[F6] Under consistency, conditional exchangeability and positivity, standardization identifies each potential-outcome mean. Discrete-treatment potential-outcome means are identifiable

1.1givenF1algebra

The point set has eight equally likely elements, Y0 and Y1 are bounded, and Y=YA by construction, so all required integrability and consistency conditions hold by [F1].

1.2A1F2F3F4algebra

Given L=l, (Y0,Y1)=(10l,10l+1) is fixed, hence its sigma-algebra is contained in σ(L) and [F3] gives conditional exchangeability [F2]. Direct counting gives P(A=1∣L=0)=1/4, P(A=1∣L=1)=3/4, and the complementary probabilities for A=0; both marginal probabilities equal 1/2. Thus [F4] holds.

1.3F5F6algebra

In stratum L=0, the observed outcome means are E[Y∣A=1,L=0]=1 and E[Y∣A=0,L=0]=0. In stratum L=1, they are 11 and 10. Since P(L=0)=P(L=1)=1/2, [F6] standardizes the treatment means to E[Y1]=(1+11)/2=6 and E[Y0]=(0+10)/2=5, so [F5] gives ATE 1.

2.1givenstep 1.2algebra∎

Bayes' rule gives P(L=1∣A=1)=3/4 and P(L=1∣A=0)=1/4. Therefore E[Y∣A=1]=(1/4)1+(3/4)11=8.5 and E[Y∣A=0]=(3/4)0+(1/4)10=2.5, whose difference is 6, not the ATE. The difference comes from the different target-covariate mixtures in the two treatment groups.

ExampleConstruction: AI-generatedVerification: AI-generatedprecheck passjudge pass (gpt-6-luna)Open item page →

Positivity failure leaves the target unsupported

Example

Let Ω={0,1} with each point having probability 1/2, and set L=A=ω. Consider two full-data laws on this same observed space. In both, Y0=0 and Y=YA. In law Q1, set Y1=1 everywhere; in law Q2, set Y1=L. Both laws give the same observed distribution: (L,A,Y)=(0,0,0) or (1,1,1) with probability 1/2 each. Both satisfy consistency and conditional exchangeability given L, but positivity fails. Their ATEs are respectively 1 and 1/2, so the observed law and conditional exchangeability alone do not identify the ATE.

Verification

Given: The two full-data laws described above; the definitions of potential outcomes, conditional exchangeability, positivity, ATE and identifiability; and the theorem's positivity hypothesis.

[A1] Choice is assumed for the library's conditional-expectation classes. The Axiom of Choice

[F1] Consistency requires Y=YA almost surely. Potential outcomes and consistency

[F2] Conditional exchangeability is conditional independence of potential outcomes and treatment given L. Conditional exchangeability of potential outcomes

[F3] Conditional independence holds when one of its sigma-algebras is contained in the conditioning sigma-algebra. Conditional independence given a sigma-algebra

[F4] Positivity for a contrast requires positive treatment probability in each treatment arm almost surely on the target covariate law. Positivity for discrete treatment

[F5] The ATE is E[Y1−Y0]. Average and conditional average treatment effects

[F6] Identifiability means the estimand is constant across parameter values with the same observed law. Identifiability of an estimand

[F7] The displayed standardization theorem assumes positivity for each treatment value in the contrast. Discrete-treatment potential-outcome means are identifiable

1.1givenF1algebra

In both laws, when L=0 one has A=0,Y=Y0=0, and when L=1 one has A=1,Y=Y1=1. Thus the observed law is identical in Q1,Q2, and consistency [F1] holds in each.

1.2A1F2F3F4F7algebra

In each law the potential-outcome vector is σ(L)-measurable and A=L is σ(L)-measurable. By [F3], conditional exchangeability [F2] holds. However, P(A=1∣L=0)=0 and P(A=0∣L=1)=0, so [F4] fails despite P(A=0)=P(A=1)=1/2. Hence the hypotheses of [F7] are not met.

2.1F5F6step 1.1algebra∎

Under Q1, E[Y1−Y0]=1. Under Q2, E[Y1−Y0]=E[L]=1/2. The same observed law therefore corresponds to two target values, so [F6] says the ATE is not identifiable under consistency and conditional exchangeability without positivity.