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LemmaStatement: AI-adaptedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6.1-sol)audited 2026-10-02
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Continuous quotient translation cocycle

Statement

Assume AC. For the rho-derived μρ and g∈G, d(g∗μρ)/dμρ(xH)=Dg(xH)=ρ(g−1x)/ρ(x)>0. This is independent of representative, jointly continuous, and satisfies Dg1g2(q)=Dg1(q)Dg2(g1−1q).

Facts & Assumptions

Given: Closed H≤G, a rho-function ρ, its Weil measure μρ, and elements g,g1,g2∈G.

[A1]

AC is assumed as stated (The Axiom of Choice).

[F1]

Rho-functions satisfy ρ(xh)=ΔH(h)ΔG(h)−1ρ(x) (Rho-function for a closed subgroup).

[F2]

The rho-derived measure satisfies the Weil formula (Weil formula with a rho-function).

[F3]

Every ϕ∈Cc(G/H) equals THf for some f∈Cc(G) (Compact lifts and averaging onto C_c(G/H)).

[F4]
[F5]

The quotient map is open and G/H is LCH (Compact lifts and averaging onto C_c(G/H)).

[A2]

AC implies DC, so the Radon-measure uniqueness supplier applies (AC implies DC implies countable choice).

Proof

technique · direct
1.1F1F5construct

Define Dg(xH)=ρ(g−1x)/ρ(x). Replacing x by xh multiplies numerator and denominator by the same factor from [F1], so the ratio is well-defined and positive. The continuous function (g,x)↦ρ(g−1x)/ρ(x) is constant on fibers in the second coordinate; [F5] makes its descent through G×G→G×G/H continuous.

2.1A1A2F2F3F4step 1.1

For ϕ=THf, Weil’s formula and left invariance give ∫G/Hϕ(gq)dμρ(q)=∫Gf(gx)ρ(x)dx=∫Gf(y)ρ(g−1y)dy=∫G/Hϕ(q)Dg(q)dμρ(q). The positive continuous density is locally bounded, so it defines a Radon measure relative to the Radon measure μρ. By [F3] the equality holds on every Cc(G/H) function; [F4] identifies g∗μρ=Dgμρ. This proves the derivative formula.

3.1A1A2step 1.1step 2.1algebra

For q=xH, the ratios telescope: Dg1(q)Dg2(g1−1q)=ρ(g1−1x)ρ(x)ρ(g2−1g1−1x)ρ(g1−1x)=Dg1g2(q). Together with step 1.1, this proves the stated cocycle identity and continuity. ∎

Sources

Bekka–de la Harpe–Valette, Kazhdan’s Property (T), Appendix B §B.1, Theorem B.1.4 and its quotient-measure density calculation, PDF pp. 352–354. Full relevant text was inspected.

Depends on

Used by

Dependency tree · two levels

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Sources