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How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

✓ 2 results · all verified · 2 also independently AI-judged
Every result on this page is machine-checked by a proof checker and read in full and owner-audited; the judge is an additional, independent cross-model AI review of the proofs; all 2 also cleared it.

Quantum Communication and Fingerprinting — Examples

1 · Prerequisites

2 · Summary

These companion calculations display the difference between public and private random seeds and compute a length-eight fingerprint overlap and swap-test outcome probability.

3 · Logical flowchart

4 · Definitions, theorems and proofs

None yet.

5 · Examples, counterexamples and false statements

CounterexampleConstruction: Literature-sourcedVerification: AI-generatedprecheck passjudge pass (gpt-6-luna)Open item page →

Public-coin and private-coin SMP are different models

Statement

For each n≥1, a shared uniformly random pair r₁,r₂∈𝔽₂ⁿ lets Alice send (r₁·x,r₂·x) and Bob send (r₁·y,r₂·y); the referee accepts equality iff both bits match. Equal inputs always match and unequal inputs collide with probability 1/4. The shared seed has 2n bits and is a separately declared public resource; independent private seeds do not give this guarantee.

Facts & Assumptions

Given: Equality inputs x,y∈F2n, where n≥1.

[F1]

Equality communication problem: Equality requires output 1 when x=y and 0 when x≠y.

[F2]

Finite communication problem and protocol model: Shared randomness is a separately declared resource, and transmitted bits are counted as communication.

Proof

technique · explicit construction and counterexample
1.1givenF1F2choosealgebra

Let public shared seeds r1,r2 be independent uniform vectors in F2n. Alice sends (r1⋅x,r2⋅x) and Bob sends (r1⋅y,r2⋅y); the referee outputs equality exactly when both bits match. If x=y, both match surely. If z=x+y≠0, choose a coordinate k with zk=1; flipping rk pairs seeds bijectively with opposite values of r⋅z, so each ri⋅z is uniform, and independence gives collision probability 1/4. The protocol uses two transmitted bits per sender and a shared seed of 2n bits, which [F2] keeps separate from communication.

2.1step 1.1F1algebra∎

If the parties instead use independent private seed pairs, take the equal input x=y=e1. Each sender's two-bit message is uniform on F22, independently of the other's, so the messages disagree with probability 3/4. This violates any bounded-error Equality guarantee such as error at most 1/3, showing that the common seed is doing real work.

ExampleConstruction: Literature-sourcedVerification: AI-generatedprecheck passjudge pass (gpt-6-luna)Open item page →

Finite length-eight fingerprint overlap

Statement

Let four inputs be assigned codewords 00000000, 00001111, 11110000, and 11111111. Distinct codewords have distance at least four. For the first two, the fingerprint overlap is 1/2 and one swap test declares unequal with probability 3/8; equal inputs yield anti probability zero. Each fingerprint uses four qubits.

Facts & Assumptions

Given: Assign 00,01,10,11 respectively to u0=00000000, u1=00001111, u2=11110000, and u3=11111111.

[F1]

Fingerprint states are normalized and encode agreement as overlap: The fingerprint overlap is the fraction of agreeing code coordinates.

[F2]

Swap-test measurement and pure-state outcome law: The antisymmetric probability on pure unit states is (1−∣⟨ψ∣ϕ⟩∣2)/2.

Proof

technique · direct finite calculation
1.1givenF1algebra

Direct coordinate comparison gives the six pairwise distances d(u0,u1)=4, d(u0,u2)=4, d(u0,u3)=8, d(u1,u2)=8, d(u1,u3)=4, and d(u2,u3)=4. In particular u0,u1 agree in their first four positions and differ in the last four; [F1] gives ⟨h00∣h01⟩=4/8=1/2.

2.1step 1.1F1F2algebra∎

By [F2], one swap test declares unequal with probability (1−(1/2)2)/2=3/8. For any equal codeword pair the overlap is one and the same formula gives probability zero. The index needs ⌈log⁡28⌉=3 qubits and the data bit adds one, so each fingerprint uses four qubits.

Sources