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How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

2 results · all verified · 2 also independently AI-judged
Every result on this page is machine-checked by a proof checker and read in full and owner-audited; the judge is an additional, independent cross-model AI review of the proofs; all 2 also cleared it.

Pure Pairs, Forests and Path–Antipath Classes — Examples

1 · Prerequisites

2 · Summary

These examples record the first concrete endpoint of the page's path–antipath theorem and make the co-leaf convention explicit on the standard P5 test case. The remaining planned examples depend on forest and leaf-deletion results that are still blocked at step 5.

3 · Logical flowchart

4 · Definitions, theorems and proofs

None yet.

5 · Examples, counterexamples and false statements

ExampleConstruction: AI-generatedVerification: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-28Open item page →

The path-antipath theorem specialized to P5 and P5

Example

Graphs with no induced P5 and no induced P5 have the Erdős–Hajnal property.

Facts & Assumptions

Given: The standard five-vertex path P5.

[L1]

For every integer k2, the class forbidding Pk and Pk has the Erdős–Hajnal property (For every k, the class forbidding Pk and Pk has the Erdős–Hajnal property).

Verification

technique · direct
1.1

By [L2], the parameter choice k=5 in [L1] is exactly the class forbidding P5 and P5.

L1L2
2.1

Therefore graphs with no induced P5 and no induced P5 have the Erdős–Hajnal property.

step 1.1
ExampleConstruction: AI-generatedVerification: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-28Open item page →

A co-leaf of P5 is exactly a leaf of P5

Example

Let P5 have vertices 1,2,3,4,5 in path order. In P5 the vertices 1 and 5 are co-leaves, and no other vertex is.

Facts & Assumptions

Given: The five-vertex path P5 with edges 12,23,34,45.

[L1]

A co-leaf of a graph is a vertex that is a leaf in the complement, equivalently a vertex of degree V(G)2 (Co-leaves of a finite graph).

[L2]

The complement contains exactly the nonedges of the original graph (Graph isomorphisms, automorphisms and graph complements).

Verification

technique · direct
1.1

By [L2], the complement P5 has edges 13,14,15,24,25,35. So vertices 1 and 5 each have degree 3=52 in P5, while vertices 2,3,4 each have degree 2.

givenL2algebra
2.1

Step 1.1 and [L1] show that 1 and 5 are co-leaves of P5, and that 2,3,4 are not. Since 1 and 5 are exactly the leaves of the path P5, the co-leaves of P5 are precisely the leaves of P5.

step 1.1L1