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The distributional Riesz functional of a subharmonic function is a positive Radon measure

Statement

Assume Dependent Choice. Let Ω⊆C be a complex domain and let u:Ω→[−∞,∞) be subharmonic on Ω, with the distributional Riesz functional μu(φ)=12π∫Ωu Δφ dA of Distributional Riesz measure of a plane subharmonic function. Then:

  1. μu(φ)≥0 for every real-valued φ∈Cc∞(Ω) with φ≥0;
  2. there is exactly one positive Radon measure ν on Ω with μu(φ)=∫Ωφ dν(φ∈Cc∞(Ω)).

Dependent Choice is used for the Riesz–Markov–Kakutani representation of the extended functional and for its uniqueness; the mollification, distributional-compatibility, density and dominated-convergence steps use only Countable Choice, which Dependent Choice implies, and the remaining steps are choice-free.

Facts & Assumptions

Given: Dependent Choice, a complex domain Ω⊆C, a subharmonic u:Ω→[−∞,∞), and the conventions of Distributional Riesz measure of a plane subharmonic function; write ACω for Countable Choice.

[F1]

μu(φ)=12π∫Ωu Δφ dA for every φ∈Cc∞(Ω), the value is real for real φ, the assignment is linear on test functions, it depends only on the almost-everywhere class of u, and the normalization (2π)−1 gives μlog⁡∣⋅−a∣=δa (Distributional Riesz measure of a plane subharmonic function).

[F2]
[F3]

u is upper semicontinuous, hence Borel measurable; u is not identically −∞ on any connected component of Ω; and u satisfies the submean inequality u(a)≤12π∫02πu(a+reit) dt at every closed disc D‾(a,r)⊆Ω; the integral is the extended circle integral of a Borel function that is bounded above on the circle (Subharmonic functions on plane domains, A complex domain is a nonempty connected open subset of C, Upper semicontinuous functions are Borel and their circle averages are defined).

[F4]

For g∈Lloc1(Ω) the regular distribution Tg(ψ)=∫Ωgψ dA is a distribution on Ω, and with the sign conventions of the distributional Laplacian in the plane one has ⟨ΔTg,ψ⟩=⟨Tg,Δψ⟩, where Δ=∂x∂x+∂y∂y (Locally integrable functions as regular distributions, Distributional derivative, Distributional harmonicity and Poisson's equation on an open subset of Rn).

[F6]

The standard smooth step b satisfies 0≤b≤1, equals 1 on the closed unit ball of R2 and vanishes outside the radius-two ball (Explicit compactly supported smooth cutoffs). Normalizing ρ:=b/∫b and rescaling gives kernels ρε(x)=ε−2ρ(x/ε) with ρε∈Cc∞(R2), ρε≥0, ∫ρε=1 and supp⁡ρε⊆B‾(0,2ε), and under ACω the family (ρε) is an L1 approximate identity (The mollifier family generated by a unit-mass smooth bump, A unit-mass smooth bump generates an L1 approximate identity).

[F7]

Assume ACω. If f∈Lloc1(R2) and φ is a unit-mass smooth bump, the convolution (f∗φε)(x)=∫f(y)φε(x−y) dy is smooth and every derivative passes under the integral sign (Convolution with a mollifier is smooth, and derivatives pass under the integral sign).

[F8]

Assume ACω. Let T∈D′(Ω) and let fε(x)=T(ρε(x−⋅)) be the local convolution on Vε={x:x−supp⁡ρε⊆Ω}. Then the regular distributions of fε converge weakly to T: for every ψ∈Cc∞(Ω) one has ∫fεψ→T(ψ) as ε→0+ (Mollifier approximation in distributions).

[F9]

Distributional differentiation is continuous linear on D′(Ω) for the weak topology, in ZF; and, under ACω, for g∈Ck on an open set and ∣α∣≤k one has ∂αTg=T∂αg (Distributional differentiation is continuous and commutes).

[F10]

A real C2 function on an open subset of C is subharmonic there if and only if its Laplacian is pointwise nonnegative (A C^2 function is subharmonic exactly when its Laplacian is nonnegative).

[F11]

Tonelli's theorem applies to nonnegative product-measurable integrands and Fubini's theorem to integrable integrands on σ-finite products (Tonelli's theorem for nonnegative measurable functions on a sigma-finite product, Fubini's theorem for L^1 functions on a sigma-finite product).

[F12]

In ZF, for compact K⊆Ω with Ω open there is χ∈Cc∞(Ω) with 0≤χ≤1 and χ=1 on a neighbourhood of K (Test function cutoffs and euclidean localization).

[F13]

Assume ACω. If f is bounded and continuous on R2, then f∗ρε→f uniformly on every compact subset (L1 approximate identities converge uniformly on compacta for bounded continuous functions).

[F14]

A convergent sequence of reals whose terms are eventually nonnegative has a nonnegative limit (Limits preserve non-strict inequalities).

[F15]

A compact subset L⊆Ω has a positive margin: there is η>0 with L+B‾(0,η)⊆Ω. If Ω≠R2, the complement is nonempty closed and disjoint from L, and the positive gap lemma (A compact set and a disjoint closed set have a positive norm-distance gap) gives δ>0 with ∣z−c∣≥δ for all z∈L and c∉Ω, so that B(z,δ)⊆Ω and η:=δ/2 works; if Ω=R2 any η works.

[F16]

A real-linear Λ:Cc(X;R)→R is positive when f≥0 pointwise implies Λ(f)≥0; for f≤g one has Λ(f)≤Λ(g) (Positive linear functionals on Cc(X), A positive linear functional on Cc(X) is monotone).

[F17]

Nonempty subsets of R that are bounded above have a supremum and nonempty subsets bounded below have an infimum, with inf⁡S=−sup⁡(−S) (Every nonempty set bounded below has an infimum).

[F18]

Assume DC. For a positive linear functional Λ:Cc(X;R)→R on an LCH space X, the RMK construction produces a Radon measure ν on the Borel sets of X that is inner regular on open sets and finite on compact sets (The RMK functional outer content is well defined, Compact-set formula and local finiteness of the RMK measure, The RMK representing measure is inner regular on open sets, Radon measure on an LCH space), and this measure represents Λ: Λ(f)=∫Xf dν for every f∈Cc(X;R) (Positive functionals on C_c(X) are integration against a Radon measure).

[F19]

Assume DC. Two Radon measures on an LCH space whose integrals agree on every continuous compactly supported function are equal (Assuming Dependent Choice, uniqueness of the RMK representing measure among Radon measures).

[F20]

Dominated convergence for a general measure: if fn→f pointwise almost everywhere and ∣fn∣≤g almost everywhere for a single nonnegative measurable g with ∫g dν<+∞, then ∫fn dν→∫f dν (Dominated convergence).

Proof

technique · direct
1.1F1F2F4given

Since u∈Lloc1(Ω) by [F2], it has a regular distribution Tu on Ω, and [F1] together with [F4] gives μu(φ)=12π∫Ωu Δφ dA=12π⟨ΔTu,φ⟩ for every φ∈Cc∞(Ω).

1.2F5given

By [F5], DC yields ACω, which discharges the choice hypotheses of [F7], [F8], [F9] (second clause) and [F13] used below.

1.3F21given

The open set Ω, with the subspace topology of R2≅C, is an LCH space by [F21]: R2 is locally compact and Hausdorff, open subspaces of locally compact Hausdorff spaces are locally compact, and Hausdorffness is hereditary.

2.1F6step 1.2choose

Choose ρ:=b/∫b from the standard step b of [F6] and put ρε(x)=ε−2ρ(x/ε): then ρε∈Cc∞(R2) is nonnegative, has ∫ρε=1 and support in B‾(0,2ε), and under ACω of step 1.2 the family (ρε) is an L1 approximate identity.

2.2F2F7step 1.2

For z in the open set Ωε:={z∈Ω:B‾(z,3ε)⊆Ω} define uε(z):=∫R2u(z−y)ρε(y) dy; this set equals Ω when Ω=C. It is open: for any of its points, [F15] gives a positive margin for the compact ball B‾(z,3ε) inside Ω, and every sufficiently small translate of that ball stays inside Ω. In general the integrand lives on the compact set z−B‾(0,2ε)⊆B(z,3ε)⊆Ω. For each such z, choose a relatively compact open W⊆Ω containing z−B‾(0,2ε) and all its sufficiently small translates. Replacing u by its product with 1W, extended by zero outside Ω (locally integrable on R2 by [F2]), [F7] and step 1.2 show that uε∈C∞(Ωε) with every derivative given by the convolution of u against the corresponding derivative of ρε; the values are finite real numbers, since u∈L1 near z−B‾(0,2ε).

3.1F2F3F11step 2.2algebra

The mollified function satisfies the submean inequality on Ωε: if a∈Ωε and D‾(a,r)⊆Ωε, then D‾(a,r+2ε)⊆Ω — for ∣w−a∣≤r one has w∈Ωε, and for r<∣w−a∣≤r+2ε the point v:=a+r(w−a)/∣w−a∣ lies in D‾(a,r)⊆Ωε, so B(v,3ε)⊆Ω while ∣w−v∣=∣w−a∣−r≤2ε<3ε gives w∈B(v,3ε)⊆Ω — hence D‾(a−y,r)⊆D‾(a,r+2ε)⊆Ω for every ∣y∣≤2ε; applying the submean inequality of [F3] at the centre a−y, multiplying by ρε(y)≥0 and integrating over ∣y∣≤2ε with Tonelli and Fubini [F11] applied to the positive and negative parts (the absolute double integral is at most 2π∥ρε∥∞∫D‾(a,r+2ε)∣u∣ dA<∞ by [F2]) gives uε(a)≤12π∫02πuε(a+reit) dt.

3.2F8step 1.2step 2.1step 2.2

As ε→0+ the regular distributions of uε converge weakly to Tu on Ω: the local convolution of [F8] with T:=Tu is exactly x↦Tu(ρε(x−⋅))=∫Ωu(y)ρε(x−y) dy=uε(x) on Vε={x:x−supp⁡ρε⊆Ω}, and Vε⊇Ωε because x−B‾(0,2ε)⊆B(x,3ε)⊆Ω for x∈Ωε; hence ⟨Tuε,ψ⟩→⟨Tu,ψ⟩ for every ψ∈Cc∞(Ω).

3.3F9step 1.2step 2.2

Classical compatibility: for every ε>0 and every φ∈Cc∞(Ωε) one has ⟨ΔTuε,φ⟩=∫Ωφ Δuε dA. Indeed uε∈C∞(Ωε) by step 2.2, so the ACω clause of [F9] applied on the open set Ωε to ∂x∂xuε and ∂y∂yuε and added gives ΔTuε=TΔuε there, and only values on Ωε are tested.

4.1F3step 2.2step 3.1

By step 2.2 the function uε is continuous and real-valued on Ωε, and by step 3.1 it satisfies the submean inequality at every closed disc in Ωε; hence uε is subharmonic on each connected component of Ωε in the sense of [F3].

4.2F4F15step 3.2

For any fixed φ∈Cc∞(Ω), the compact support of φ and of Δφ lies inside Ωε for all sufficiently small ε by [F15]. On those open domains, the definition of distributional derivatives gives ⟨ΔTuε,φ⟩=∫uεΔφ dA. Step 3.2 applied to the fixed test Δφ shows that this tends to ⟨Tu,Δφ⟩=⟨ΔTu,φ⟩. These pairings are local for each ε; no distribution on all of Ω is asserted for a locally defined uε.

5.1F10step 4.1

By [F10] applied on the components of the open set Ωε, step 4.1 gives Δuε≥0 pointwise on Ωε.

6.1F14F15step 1.1step 5.1step 4.2step 3.3

Positivity on nonnegative tests: let φ∈Cc∞(Ω) be real with φ≥0. Since supp⁡φ⊆Ω is compact in the open set Ω, the positive-margin fact [F15] gives η>0 with supp⁡φ+B‾(0,η)⊆Ω; then any ε0>0 with 3ε0<η satisfies supp⁡φ⊆Ωε0, because B‾(x,3ε0)⊆B(x,η)⊆supp⁡φ+B‾(0,η)⊆Ω for x∈supp⁡φ. Fix such an ε0, so that supp⁡φ⊆Ωε and φ≥0 for every 0<ε≤ε0. Steps 1.1, 4.2 and 3.3 give μu(φ)=lim⁡n→∞12π⟨ΔTuε0/(n+1),φ⟩=lim⁡n→∞12π∫Ωφ Δuε0/(n+1) dA, and each integrand is nonnegative by step 5.1; [F14] therefore gives μu(φ)≥0.

7.1F1step 6.1algebra

Monotonicity on smooth tests: if φ≤ψ are real-valued compactly supported smooth functions on Ω, then ψ−φ≥0 is a test function with μu(ψ)−μu(φ)=μu(ψ−φ)≥0 by step 6.1 and the linearity of [F1]; hence μu(φ)≤μu(ψ).

8.1F12F17step 7.1construct

For f∈Cc(Ω;R) set Sf:={μu(φ):φ∈Cc∞(Ω;R), φ≤f} and Tf:={μu(ψ):ψ∈Cc∞(Ω;R), ψ≥f}. If f≠0, put M:=∥f∥∞ and use [F12] to choose χ∈Cc∞(Ω) with 0≤χ≤1 and χ=1 on a neighbourhood of supp⁡f; then −Mχ≤f≤Mχ pointwise, so Sf and Tf are nonempty; if f=0, then 0∈Sf∩Tf. By step 7.1 every element of Sf is at most every element of Tf, so Sf is bounded above and Tf bounded below; [F17] makes sup⁡Sf and inf⁡Tf well-defined real numbers with sup⁡Sf≤inf⁡Tf.

9.1F7F12F13F15step 2.1step 8.1choose

Density of smooth tests for a fixed f≠0: let K:=supp⁡f, M:=∥f∥∞, choose χ as in step 8.1, and use [F15] to fix η>0 with L:=supp⁡χ+B‾(0,η)⊆Ω; use [F12] again to choose χ1∈Cc∞(Ω) with 0≤χ1≤1 and χ1=1 on the compact set L. For all large n put fn:=(fχ)∗ρ1/n: each fn is smooth by [F7], supported in supp⁡χ+B‾(0,2/n)⊆L⊆Ω, and fn→fχ=f uniformly on the compact L by [F13], and hence on R2 since both functions vanish outside L, because fχ is continuous with compact support and fχ=f on supp⁡f.

10.1F2step 7.1step 8.1step 9.1algebra

Sandwich for the sets of step 8.1: keep f≠0 and χ,χ1,L of steps 8.1 and 9.1, and let δn:=∥fn−f∥∞→0. Since ∣fn−f∣≤δn everywhere and ∣fn−f∣=0 outside L, one has fn−δnχ1≤f≤fn+δnχ1 pointwise, and both bounds are smooth test functions of the kinds defining Sf and Tf; applying μu and using step 7.1 gives μu(fn)−δnμu(χ1)≤sup⁡Sf≤inf⁡Tf≤μu(fn)+δnμu(χ1). Hence (μu(fn)) is Cauchy, and with Λ(f):=sup⁡Sf=inf⁡Tf one has ∣Λ(f)−μu(fn)∣≤δnμu(χ1)→0 for every admissible sequence (fn) of smooth functions converging uniformly to f with supports in a fixed compact subset of Ω. For f=0 set Λ(0):=0, consistently with step 8.1.

11.1step 10.1step 8.1given

Positivity of Λ: if f≥0 in Cc(Ω;R), then the zero test function satisfies 0≤f, so 0=μu(0)∈Sf and Λ(f)=sup⁡Sf≥0. If f=0 this is step 10.1.

11.2F17step 10.1algebra

Homogeneity of Λ: for c>0 one has Scf=cSf, so Λ(cf)=cΛ(f); for c<0 one has Scf=cTf, so by [F17] Λ(cf)=sup⁡(cTf)=cinf⁡Tf=cΛ(f); and Λ(0)=0. Thus Λ is positively homogeneous and Λ(−f)=−Λ(f).

11.3step 7.1step 10.1

Extension: if φ∈Cc∞(Ω;R) then φ∈Sφ and φ∈Tφ, so step 7.1 gives μu(φ)≤Λ(φ)≤μu(φ); hence Λ(φ)=μu(φ) for every smooth test function.

12.1F1step 10.1step 11.2algebra

Additivity of Λ: given f,g∈Cc(Ω;R) and η>0, choose by the definition of the supremum φ∈Sf, ψ∈Sg with μu(φ)>Λ(f)−η/2 and μu(ψ)>Λ(g)−η/2; then φ+ψ≤f+g, so Λ(f+g)≥μu(φ)+μu(ψ)>Λ(f)+Λ(g)−η, and η↓0 gives Λ(f+g)≥Λ(f)+Λ(g). Dually, choose ψf∈Tf, ψg∈Tg with μu(ψf)<Λ(f)+η/2 and μu(ψg)<Λ(g)+η/2; then ψf+ψg≥f+g, so Λ(f+g)≤Λ(f)+Λ(g)+η and hence Λ(f+g)≤Λ(f)+Λ(g). Therefore Λ is additive; it is real-linear together with the homogeneity of step 11.2.

13.1F16F18step 11.1step 12.1step 1.3

By steps 11.1, 12.1 and 1.3 the map Λ:Cc(Ω;R)→R is a positive real-linear functional on the LCH space Ω in the sense of [F16]; the RMK construction of [F18] therefore produces a Radon measure ν on Ω with Λ(w)=∫Ωw dν for every w∈Cc(Ω;R).

14.1step 11.3step 13.1given

Representing smooth tests: combining steps 11.3 and 13.1, for every φ∈Cc∞(Ω;R) one has μu(φ)=Λ(φ)=∫Ωφ dν; since μu is complex-linear, the same identity holds for complex test functions, so ν represents μu.

14.2F20F19step 10.1step 13.1

Uniqueness: let ν′ be a Radon measure on Ω with μu(φ)=∫Ωφ dν′ for every φ∈Cc∞(Ω;R). For f∈Cc(Ω;R) and an admissible sequence (fn) as in step 10.1 with common support in a compact L′⊆Ω, one has ∫Ωfn dν′=μu(fn)→Λ(f) by step 10.1, while ∫Ωfn dν′→∫Ωf dν′ by [F20], since fn→f pointwise and ∣fn∣≤∥f∥∞+1 on the compact set L′ of finite ν′-measure. Hence ∫Ωf dν′=Λ(f)=∫Ωf dν for every f∈Cc(Ω;R), and [F19] gives ν′=ν.

15.1step 6.1step 14.1step 14.2∎

Conclusion: clause 1 is step 6.1, and clause 2 is the existence of ν in steps 13.1 and 14.1 together with the uniqueness in step 14.2.

Remarks

Dependent Choice is used at exactly two places. The RMK construction of [F18] selects cutoffs between compact and open sets and constructs the outer content along a dependent recursion, and the uniqueness theorem [F19] uses the same cutoff principle; both are stated under DC. Everything else in the proof is carried out under ACω (mollification, uniform density, classical-distributional compatibility) or in ZF (the sandwich and extension construction, which defines Λ by suprema and infima of fixed sets and therefore selects nothing).

Why the extension is needed at all. The positivity of μu on smooth nonnegative tests is proved directly by mollification, but the Riesz–Markov–Kakutani theorem consumes a functional on the whole of Cc(Ω;R). The functional Λ is the unique continuous extension of μu from the dense subspace of smooth tests to Cc; the argument above avoids selecting approximating sequences by defining Λ as the common value of sup⁡Sf and inf⁡Tf.

Compatibility with the point-mass normalization. With u=log⁡∣⋅−a∣ on Ω=C the theorem returns ν=δa, in agreement with the normalization recorded in Distributional Riesz measure of a plane subharmonic function.

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