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How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Category O Finiteness Duality and Blocks — Examples

1 · Prerequisites

2 · Summary

The rank-one examples separate a regular integral block from a nonintegral central-character summand with two blocks; the type A2 calculation tests a singular weight. The counterexamples isolate finite generation, bounded upward support, Cartan semisimplicity, restricted duality and the finite-dimensional tensor-factor hypothesis. Throughout, b=hn+ and the Chevalley dual preserves weights.

3 · Logical flowchart

4 · Definitions, theorems and proofs

None yet.

5 · Examples, counterexamples and false statements

ExampleConstruction: Literature-sourcedVerification: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

The regular integral sl2 block

Example

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ.

For g=sl2 identify a highest weight with its value on h, so ρ=1 and sλ=λ2. For every integer n0, the regular integral block has simple labels n and n2. Its standards are M(n) and M(n2)=L(n2), and

0L(n2)M(n)L(n)0

is nonsplit. Its costandards are (n) and (n2)=L(n2), with the nonsplit sequence 0L(n)(n)L(n2)0. The linkage order is n2<n.

Facts & Assumptions

Given: The setting above and the hypotheses in the example.

[F1]

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ. For a linkage class C=Wλλ, let OC be the full subcategory of objects all of whose simple composition factors have labels in C. Then O=COC, and each nonzero OC is indecomposable as a categorical direct summand. These are precisely the blocks. Each OC lies in Oχλ; a central-character summand can contain several blocks. Independently, grouping weights by cosets of the root lattice Q gives a canonical coarser decomposition by weight cosets. (Central-character summands refine into linkage blocks)

[F2]

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ. Restricted Chevalley duality is an exact contravariant equivalence D:OOop, with a natural isomorphism D2id. It preserves each weight-space dimension, the formal character, and every simple composition multiplicity. (Restricted duality is exact and involutive on O)

[F3]

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ. The costandard object (λ) has a unique simple submodule, isomorphic to L(λ). Its socle, the sum of all simple submodules, is that submodule. (The simple socle of a costandard object)

[F4]

If λ+ρ,αiZ>0, there is an embedding M(siλ)M(λ). (Simple-reflection embeddings of Verma modules)

[F5]

The proper submodule J(λ) which is the sum of all proper submodules is the unique maximal submodule of M(λ). The quotient L(λ):=M(λ)/J(λ) is simple and is its unique simple quotient. (A Verma module has a unique simple quotient)

[F6]

M(λ) is simple if and only if λ+ρ,αZ>0 for every αΦ+. (The Verma irreducibility criterion from Shapovalov determinants)

[F7]

The weights of M(λ) are exactly λβ for βQ+; every weight space is finite dimensional, and M(λ)λ=Cvλ. (Weights of a Verma module lie below lambda)

[F8]

For every highest weight η, D(L(η))L(η) as g-modules. (Restricted self-duality of simple highest-weight modules)

[F9]

The standard and costandard objects are Δ(η)=M(η) and (η)=D(M(η)). (Standard and costandard objects)

Verification

1.1

The integral pairing is n+1>0, and the two distinct dot-orbit labels are n and n2. The integral Weyl group is the full order-two Weyl group, so these labels form one block. At n2 the shifted pairing is n1<0, and the irreducibility criterion makes its Verma simple.

F1F6
2.1

Write vk=fkvn in M(n). The relations [h,f]=2f and [e,f]=h give hvk=(n2k)vk and evk=k(nk+1)vk1 for k1, by commuting e past the k copies of f; ev0=0. The negative nilpotent algebra is one dimensional, so its PBW monomials give one-dimensional Verma weight spaces. The singular vector vn+1 generates the embedded M(n2), which is also the embedding supplied by F4.

F4F7algebrastep 1.1
3.1

The quotient has basis v0,,vn. A nonzero submodule contains a weight vector, and applying e repeatedly reaches v0, since k(nk+1)0 for 1kn. Applying f then generates the whole quotient. It is simple, hence is L(n). A split sequence would make M(n) a sum of two proper submodules, contrary to its unique maximal submodule. For n=0 the quotient consists just of v0 and the same argument holds.

F5algebrastep 2.1
4.1

By F8, exact duality fixes both simples; it reverses the sequence, and F9 identifies the middle term as (n), giving the displayed costandard sequence. If it split, its dual would split the original. The costandard socle is L(n) by F3. Since M(n2)=L(n2), F8 and F9 also give (n2)=L(n2).

F2F3F8F9step 3.1
ExampleConstruction: Literature-sourcedVerification: AI-adaptedaudited 2026-09-07Open item page →

Nonintegral sl2 central characters split into two simple blocks

Example

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ.

For g=sl2 and λCZ, Oχλ has exactly two distinct singleton linkage blocks, with labels λ and λ2. Each block is equivalent to finite-dimensional complex vector spaces. In particular the central-character summand is semisimple but is not one indecomposable block.

Facts & Assumptions

Given: The setting above and the hypotheses in the example.

[F1]

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ. For a linkage class C=Wλλ, let OC be the full subcategory of objects all of whose simple composition factors have labels in C. Then O=COC, and each nonzero OC is indecomposable as a categorical direct summand. These are precisely the blocks. Each OC lies in Oχλ; a central-character summand can contain several blocks. Independently, grouping weights by cosets of the root lattice Q gives a canonical coarser decomposition by weight cosets. (Central-character summands refine into linkage blocks)

[F2]

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ. Every short exact sequence 0M(λ)EpM(λ)0 in O splits. (Verma self-extensions in O split)

[F3]

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ. For M,NO, HomO(M,N) is finite dimensional. For every weight λ, EndO(L(λ))=Cid. (Finite-dimensional Hom spaces in O)

[F4]

M(λ) is simple if and only if λ+ρ,αZ>0 for every αΦ+. (The Verma irreducibility criterion from Shapovalov determinants)

[F5]

Let Z=Z(U(g)), let χ:ZC be a unital complex-algebra character, and put mχ=kerχ. For MO, the generalized central-character submodule is Mχ={vM:mχNv=0 for some N1}, and Oχ consists of the objects with M=Mχ. (Generalized central-character subcategories)

[F6]

The simple objects of O are exactly the modules L(μ), μh, and L(μ)L(ν) if and only if μ=ν. (The simple objects of O)

[F7]

If a cyclic highest-weight module has highest weight μ, then every zZ(U(g)) acts on it by the scalar pr(z)(μ)=χμ(z). (The Harish-Chandra projection computes the highest-weight scalar)

[F8]

The highest-weight central characters satisfy χμ=χλ if and only if μWλ. (Central characters are dot-Weyl orbits)

[F9]

Every object of O has a finite composition series and is both Noetherian and Artinian. The length of zero is zero. (Every object of O has finite length)

Verification

1.1

For sl2, the dot orbit of λ is exactly {λ,λ2}. Its two labels are nonintegral and distinct: equality would imply λ=1. By F8 they have the same central character. Conversely, if a simple object belongs to Oχλ, F6 writes it as L(μ). Its highest vector is killed by a power of every zχλ(z) by F5, while F7 says that z acts on it as χμ(z). Hence χμ=χλ, and F8 forces μ{λ,λ2}. Neither label has an integral root pairing, so each integral-reflection group is trivial. Both Vermas are simple by F4, and F1 therefore identifies exactly the two asserted singleton blocks.

F1F4F5F6F7F8
2.1

Fix one label η and put S=M(η)=L(η). Every object in this block has a finite composition series by F9, and all its factors are S by F1. Every extension of S by itself splits by F2. More generally an extension 0SrES0 splits: push out along each coordinate projection SrS, obtaining Ei=(ES)/{(a,ai):aSr}. Each has a retraction to its kernel S. Composing these retractions with EEi and collecting coordinates gives a retraction ESr, hence a splitting. The case r=0 is immediate.

F1F2F9algebrastep 1.1
3.1

Induction on a composition series now expresses every object as a finite direct sum of S. Since End(S)=C, maps between Sr and Ss are exactly complex matrices. Thus VSV (with trivial action on the finite-dimensional multiplicity space) and XHom(S,X) are inverse equivalences. Zero corresponds to the zero-dimensional vector space.

F3algebrastep 2.1
ExampleConstruction: AI-adaptedVerification: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

A singular integral A2 central-character summand

Example

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ.

In type A2, take λ=ω1, with fundamental-weight coordinates ρ=(1,1). Then λ+ρ=ω2 has Weyl stabilizer s1. The dot orbit consists of

ω1,2ω2,2ω1ω2.

These three simple labels form a single singular integral central-character block. Only labels and stabilizer are computed here.

Facts & Assumptions

Given: The setting above and the hypotheses in the example.

[F1]

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ. For a linkage class C=Wλλ, let OC be the full subcategory of objects all of whose simple composition factors have labels in C. Then O=COC, and each nonzero OC is indecomposable as a categorical direct summand. These are precisely the blocks. Each OC lies in Oχλ; a central-character summand can contain several blocks. Independently, grouping weights by cosets of the root lattice Q gives a canonical coarser decomposition by weight cosets. (Central-character summands refine into linkage blocks)

[F2]

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ. For a weight λ, define Φλ={αΦ:λ+ρ,αZ},Wλ=sα:αΦλW. Reflections and coroots are those of def-root-reflections-and-the-weyl-group-action, with the shift from def-weyl-vector-rho-for-a-chosen-positive-system. The integral-reflection linkage class through λ is Wλλ. The word integral includes zero and negative integral pairings. If Φλ is empty the generated group is {1}. This definition uses generating reflections; no identification with a root-lattice-coset stabilizer is assumed. (The integral Weyl group of a weight)

[F3]

Let χλ and χμ be the central characters obtained from highest weights λ and μ. Then χλ=χμif and only ifμWλ, where Wλ:={w(λ+ρ)ρ:wW}. (Central characters are dot-Weyl orbits)

[F4]

Let Φ be the root system from thm-the-root-set-is-a-reduced-crystallographic-root-system. For a root α, define the corresponding coroot by α:=2Hαα(Hα)h, where Hα is the vector from def-killing-dual-vector-attached-to-a-root. The associated root reflection is the linear map sα(λ):=λλ(α)α(λh). The subgroup of GL(h) generated by these reflections is the Weyl group W, acting on h in the usual way. (Root reflections and the Weyl group action)

Verification

1.1

With α1=2ω1ω2 and α2=ω1+2ω2, the reflection formula gives s1(a,b)=(a,a+b) and s2(a,b)=(a+b,b). Acting on (0,1) produces exactly (0,1),(1,1),(1,0): both reflection formulas permute this set and the three displayed points are reachable. Subtracting (1,1) gives (1,0),(0,2),(2,1), the claimed labels.

F4algebra
2.1

Type A2 has six Weyl elements, as is also seen by the six distinct matrices 1,s1,s2,s1s2,s2s1,s1s2s1: multiplication by either generator permutes these six matrices. Exactly 1 and s1 fix (0,1), by evaluating them. Thus the stabilizer is s1, and the orbit is singular.

algebrastep 1.1
3.1

The pairings of (0,1) with the positive coroots are 0,1,1. All are integers, so Φλ=Φ and Wλ=W. The full dot orbit has one central character and forms one integral-reflection block. The zero pairing explains the stabilizer and does not remove its reflection from the integral group.

F1F2F3step 2.1

Notes

The source gives a typical three-element singular A2 class with an antidominant representative. This item chooses the explicit representative -omega1 of such a class and computes its coordinates; statement provenance is ai-altered to record that specialization.

CounterexampleConstruction: Literature-sourcedVerification: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

The full algebraic Verma dual is too large

Statement refuted

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ.

False claim: replacing the restricted sum in Chevalley duality by the full algebraic dual always gives an object of O.

For sl2 and any λC, the full Chevalley-twisted dual HomC(M(λ),C) is not h-semisimple and hence is not in O.

Facts & Assumptions

Given: The setting above and the hypotheses in the statement refuted.

[F1]

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ. For an h-semisimple module M with finite-dimensional weight spaces, its restricted Chevalley dual is D(M)=μhMμ,(xφ)(m)=φ(τ(x)m)(xU(g)). Here each functional is extended by zero on the other weight spaces and τ is the fixed anti-involution of def-chevalley-contravariant-form. In particular τ(h)=h and D(M)μ=Mμ. A map f:MN induces D(f):D(N)D(M) by precomposition. The action law follows from τ(xy)=τ(y)τ(x); a root vector of weight α sends Mμ to Mμ+α, so the restricted sum is stable. This is a complex-linear algebraic dual, with no conjugation. Ordinary Lie-module duality has a minus sign and reverses weights; twisting that dual by the Lie automorphism xτ(x) gives the convention used here. (Restricted Chevalley dual)

[F2]

For λh, the Verma module is the induced g-module M(λ):=U(g)U(b)Cλ, where U(g) is the quotient algebra of def-universal-enveloping-algebra-as-a-tensor-quotient and Cλ is def-one-dimensional-borel-module-of-weight-lambda. Write vλ:=1cλ. Thus M(λ) is the quotient of U(g) by the left ideal generated by x for xn+ and hλ(h) for hh; in particular, n+vλ=0 and hvλ=λ(h)vλ. (Verma modules)

[F3]

The weights of M(λ) are exactly λβ for βQ+; every weight space is finite dimensional, and M(λ)λ=Cvλ. (Weights of a Verma module lie below lambda)

Counterexample

1.1

The induced Verma model has basis vk=fkvλ for k0 and hvk=(λ2k)vk. Define φ(vk)=1 for all k and extend linearly. This is an algebraic functional because vectors of M(λ) are finite sums, although its nonzero weight coordinates are infinite. On the full twisted dual use the same formula (hφ)(v)=φ(hv) as for restricted duality.

F1F2F3construct
2.1

For every polynomial p, (p(h)φ)(vk)=p(λ2k). The values λ2k are pairwise distinct over C, so a polynomial annihilating φ has infinitely many distinct zeros and must be the zero polynomial. Thus the C[h]-orbit of φ is infinite dimensional. A vector in a direct sum of eigenspaces has only finitely many eigencomponents and is annihilated by the product of their linear eigenvalue polynomials. Therefore this full dual cannot be a weight module.

algebrastep 1.1
CounterexampleConstruction: AI-generatedVerification: AI-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Finite weight spaces and bounded support do not replace finite generation

Statement refuted

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ.

False claim: local n+-finiteness, finite-dimensional weight spaces and support in finitely many downward cones suffice for membership in O without finite generation.

For sl2, X=n0M(2n) has these three local properties, with suppX=2Z0 and dimX2k=k+1 for k0, but is not finitely generated.

Facts & Assumptions

Given: The setting above and the hypotheses in the statement refuted.

[F1]

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ. The BGG category O is the full subcategory of left U(g)-modules M satisfying all three conditions: M is finitely generated; M=μhMμ where Mμ={v:hv=μ(h)v for all hh}; and U(n+)v is finite dimensional for each vM. Its morphisms are all g-linear maps. The zero module is included, generated by the empty set. The enveloping and triangular conventions are those of thm-pbw-ordered-monomial-basis-for-the-enveloping-algebra and thm-triangular-decomposition-from-a-chosen-positive-root-system. (The classical BGG category O)

[F2]

The weights of M(λ) are exactly λβ for βQ+; every weight space is finite dimensional, and M(λ)λ=Cvλ. (Weights of a Verma module lie below lambda)

Counterexample

1.1

Each Verma has one basis vector at each weight 2n2j, j0: the negative root algebra has the single generator f, so the induced Verma basis is fjv2n. At weight 2k the contributing summands are exactly n=0,,k, proving the count k+1. The direct sum is a weight module supported in the single cone 0Q+.

F2algebra
2.1

The operator e raises the Verma weight, so it kills every vector after sufficiently many applications inside each summand. A vector of the direct sum has nonzero coordinates in finitely many summands; taking the maximum of their bounds proves local C[e]-finiteness.

algebrastep 1.1
3.1

Any finite list of vectors is supported in a finite set of summands. Those summands form a g-submodule, so the submodule generated by the list remains there. There is always a further nonzero Verma summand outside that finite set. Hence the list cannot generate X, which fails the finite-generation axiom of O. The empty list generates zero, not X.

F1algebrastep 2.1
CounterexampleConstruction: AI-generatedVerification: AI-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Finite weight spaces alone do not give category O

Statement refuted

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ.

False claim: a finitely generated weight module with finite-dimensional weight spaces must belong to O.

For sl2, induce the weight-zero one-dimensional module from the negative Borel ChCf. The resulting lowest-weight Verma module X is cyclic, has one-dimensional weight spaces at 2k for k0, and is not in O.

Facts & Assumptions

Given: The setting above and the hypotheses in the statement refuted.

[F1]

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ. The BGG category O is the full subcategory of left U(g)-modules M satisfying all three conditions: M is finitely generated; M=μhMμ where Mμ={v:hv=μ(h)v for all hh}; and U(n+)v is finite dimensional for each vM. Its morphisms are all g-linear maps. The zero module is included, generated by the empty set. The enveloping and triangular conventions are those of thm-pbw-ordered-monomial-basis-for-the-enveloping-algebra and thm-triangular-decomposition-from-a-chosen-positive-root-system. (The classical BGG category O)

[F2]

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ. Let M be a finitely generated h-semisimple g-module. Then MO if and only if suppMi=1r(λiQ+) for some finite list of weights. In either case every Mμ is finite dimensional. The list may be empty for M=0; finite generation is an independent hypothesis. (The support description of category O with finite generation)

[F3]

Let x1,,xr be an ordered basis of a finite-dimensional complex Lie algebra g. Then the monomials x1a1x2a2xrar(aiN0) form a basis of U(g). In particular, multiplication identifies grU(g) with the symmetric algebra S(g) on the symbols of the xi. (PBW gives an ordered monomial basis for the enveloping algebra)

Counterexample

1.1

Let w=11 in X=U(sl2)U(ChCf)C0, where h and f kill 1. Ordering e before the negative Borel in PBW gives the basis wk=ekw, k0. The relation [h,e]=2e gives hwk=2kwk. This proves cyclicity and the one-dimensional weight-space assertion.

F3construct
2.1

The vectors ekw=wk are linearly independent, so U(n+)w=C[e]w is infinite dimensional and violates the local-finiteness axiom. Moreover no finite union of sets λi2Z0 can contain all 2k: any cone meeting this real arithmetic progression has a fixed finite upper bound there, and finitely many bounds cannot contain its unbounded sequence. Thus the support criterion fails as well.

F1F2algebrastep 1.1
CounterexampleConstruction: Literature-sourcedVerification: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

An ambient extension can leave category O

Statement refuted

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ.

False claim: O is extension closed in the category of all g-modules.

For sl2 and any λC, let V=CvCw be a positive-Borel module with ev=ew=0, hv=λv and hw=λw+v. Then E=U(g)U(b)V is an extension of M(λ) by itself in ambient modules, but is not in O.

Facts & Assumptions

Given: The setting above and the hypotheses in the statement refuted.

[F1]

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ. The BGG category O is the full subcategory of left U(g)-modules M satisfying all three conditions: M is finitely generated; M=μhMμ where Mμ={v:hv=μ(h)v for all hh}; and U(n+)v is finite dimensional for each vM. Its morphisms are all g-linear maps. The zero module is included, generated by the empty set. The enveloping and triangular conventions are those of thm-pbw-ordered-monomial-basis-for-the-enveloping-algebra and thm-triangular-decomposition-from-a-chosen-positive-root-system. (The classical BGG category O)

[F2]

Let x1,,xr be an ordered basis of a finite-dimensional complex Lie algebra g. Then the monomials x1a1x2a2xrar(aiN0) form a basis of U(g). In particular, multiplication identifies grU(g) with the symmetric algebra S(g) on the symbols of the xi. (PBW gives an ordered monomial basis for the enveloping algebra)

[F3]

For λh, the Verma module is the induced g-module M(λ):=U(g)U(b)Cλ, where U(g) is the quotient algebra of def-universal-enveloping-algebra-as-a-tensor-quotient and Cλ is def-one-dimensional-borel-module-of-weight-lambda. Write vλ:=1cλ. Thus M(λ) is the quotient of U(g) by the left ideal generated by x for xn+ and hλ(h) for hh; in particular, n+vλ=0 and hvλ=λ(h)vλ. (Verma modules)

Counterexample

1.1

The Borel relation [h,e]=2e holds on V because e acts by zero. There is a short exact sequence 0CλVCλ0, with submodule Cv and quotient generated by the image of w. PBW makes U(g) right free over U(b), so induction preserves this exact sequence. Its two ends are the Verma modules by definition.

F2F3construct
2.1

PBW identifies E with C[f]V as a vector space. Thus 1v0, while (hλ)(1w)=1v and (hλ)2(1w)=0. In a weight module, ker(hλ)2=ker(hλ), by evaluating on its eigenspace decomposition. This Jordan pair proves that E is not a weight module. Its end terms do satisfy the category-O axioms: their PBW basis has weights λ2k and locally nilpotent e action, and they are cyclic. Consequently the ambient extension leaves O.

F1F2algebrastep 1.1
CounterexampleConstruction: Literature-sourcedVerification: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

O is not closed under arbitrary tensor products

Statement refuted

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ.

False claim: the tensor product of two objects of O always belongs to O.

For sl2, X=M(0)M(0) with diagonal action has support 2Z0, weight multiplicities dimX2k=k+1, and locally nilpotent e action, but is not finitely generated over U(g).

Facts & Assumptions

Given: The setting above and the hypotheses in the statement refuted.

[F1]

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ. The BGG category O is the full subcategory of left U(g)-modules M satisfying all three conditions: M is finitely generated; M=μhMμ where Mμ={v:hv=μ(h)v for all hh}; and U(n+)v is finite dimensional for each vM. Its morphisms are all g-linear maps. The zero module is included, generated by the empty set. The enveloping and triangular conventions are those of thm-pbw-ordered-monomial-basis-for-the-enveloping-algebra and thm-triangular-decomposition-from-a-chosen-positive-root-system. (The classical BGG category O)

[F2]

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ. Every MO is a quotient of a module with a finite Verma flag. Consequently it has a finite filtration whose nonzero factors are quotients of Verma modules, and is finitely generated over U(n). The empty filtration is allowed for zero. No truncation hypothesis is needed, and a Verma flag of M itself is not asserted. (Finite filtrations by highest-weight quotients)

[F3]

Let x1,,xr be an ordered basis of a finite-dimensional complex Lie algebra g. Then the monomials x1a1x2a2xrar(aiN0) form a basis of U(g). In particular, multiplication identifies grU(g) with the symmetric algebra S(g) on the symbols of the xi. (PBW gives an ordered monomial basis for the enveloping algebra)

Counterexample

1.1

The Verma PBW bases identify X with C[x,y], where xiyj corresponds to fiv0fjv0. Its h-weight is 2(i+j), so its weight multiplicities are k+1. The diagonal f acts by multiplication by x+y. Each tensor of two basis vectors is killed by a high enough power of the diagonal e: expanding (e1+1e)N, every term vanishes once N>i+j. Hence e acts locally nilpotently on X.

F3algebra
2.1

If X were finitely generated over U(g), its weight decomposition and local e-finiteness would put it in O. F2 then implies it is finitely generated over U(n)=C[f], hence over C[x+y] in the displayed model.

F1F2step 1.1
3.1

But C[x,y]/(x+y)C[x,y]C[x] is infinite dimensional over C. A module generated by r< elements over C[x+y] has quotient by x+y generated by their r images over C, so that quotient has dimension at most r. This proves that X is not finitely generated and therefore is not in O, although each factor is cyclic with locally nilpotent e and is a weight module.

algebrastep 2.1

Sources