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Finite-time comparison of bounded vector fields — Examples

1 · Prerequisites

2 · Summary

Scope

This companion evaluates the exact low-speed kinetic-energy remainder at a stipulated speed cutoff of one tenth of the speed parameter c. The speed condition is a model hypothesis, not a measurement or an experimental uncertainty. The example uses the uniform kinematic lemma and the mass-shell energy definition; it does not assert that an apparatus prepared such a state or that any relativistic trajectory is close to a Newtonian one over time.

3 · Logical flowchart

4 · Definitions, postulates, theorems and proofs

None yet.

5 · Examples, experiments and counterexamples

ExampleConstruction: AI-adaptedVerification: AI-adaptedprecheck passverified 2026-10-15 (gpt-6-luna, gpt-6.1-sol, and delegated Codex review/repair agents; see completed run evidence)Open item page →

One-tenth-light-speed kinetic remainder

Physical scope

A conditional pointwise calculation for a massive particle in one flat inertial frame when the model state is stipulated to have speed at most one tenth of c. It reports no measurement, apparatus precision, or trajectory approximation.

Example

Let a massive particle in a named inertial frame have constant mass m>0, speed ∣v∣≤c/10, Lorentz factor γ=(1−∣v∣2/c2)−1/2, observer energy E=γmc2, and kinetic energy T=E−mc2 as in Mass shell inversion, observer work and variable mass. Treat the speed bound as a stipulated state condition. Then

0≤T−12m∣v∣2≤3m∣v∣48c2(99/100)5/2.

Facts & Assumptions

Given: A massive inertial-frame state with constant m>0, c>0, and the stipulated speed bound ∣v∣≤c/10.

[L1]

In the constant-mass flat inertial model, γ=(1−∣v∣2/c2)−1/2, E=γmc2, and T=E−mc2 (Mass shell inversion, observer work and variable mass). This supplier is a draft result in batch 23; this example uses its exact kinematic definitions conditionally.

[L2]

For every 0<δ<1 and ∣v∣/c≤δ, the kinetic-energy remainder is nonnegative and at most 3m∣v∣4/[8c2(1−δ2)5/2] (Explicit low-speed momentum and energy remainders).

Verification

1.1givenL1L2algebra

The hypothesis ∣v∣≤c/10 is the low-speed lemma's condition with δ=1/10. Substituting δ2=1/100 into [L2] gives 1−δ2=99/100 and therefore the displayed lower and upper bounds. The lower bound is the same nonnegativity conclusion in [L2]; no division by ∣v∣ is made, so the case v=0 is included.

2.1givenL1step 1.1∎

The bound is conditional on the stipulated state speed and the definitions in [L1]. It is a pointwise model calculation, not an observation and not an estimate comparing two trajectories.

Sources