Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passaudited 2026-10-08
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Measurable Gram-Schmidt and constant-field trivializations on dimension strata

Statement

Assume the Axiom of Choice. Let (X,B,μ) be a sigma-finite standard-Borel measure space and let (Hx,en(x))x∈X be a measurable complex Hilbert field with countable fundamental family. Then: (1) there are measurable sections fn such that for every x the nonzero fn(x) form a complete orthonormal system in Hx, and x↦⟨ξ(x),fn(x)⟩ is Borel for every measurable section ξ; (2) for each p∈{1,2,…}∪{∞}, the dimension stratum Xp:={x:dim⁡Hx=p} is Borel, and for every fixed separable Hilbert space Kp of dimension p there are unitaries Ux:Hx→Kp on Xp such that ξ is a measurable section on Xp if and only if x↦Uxξ(x) is a Borel map; explicitly, Uxξ has coordinates ⟨ξ(x),fn(x)⟩ after deleting zero frame vectors; (3) weakly measurable operator fields have Borel transported matrix coefficients on each Xp, and uniformly bounded transported fields are Borel maps into their weak-operator-topology balls; (4) for every countable family of measurable sections ξk, the pointwise closed spans Sx:=span⁡‾{ξk(x):k∈N} form a measurable closed Hilbert subfield, and its direct integral is the closed linear span in ∫X⊕Hx dμ(x) of all square-integrable localizations f1Eξk, where E=Dj∩{x:∥ξk(x)∥≤r}, (Dj) is any countable finite-measure cover of X, r∈R with r≥1, and f is any bounded Borel scalar function supported in E. The zero-dimensional stratum is Borel as the complement of the positive and infinite-dimensional strata.

Facts & Assumptions

Given: The fibres Hx are separable Hilbert spaces, the fundamental sections en have Borel Gram coefficients and dense fibrewise span, X has a standard-Borel sigma-algebra and a sigma-finite measure, and the inner product is linear in its first variable.

[F1]

A measurable Hilbert field has separable fibres, measurable fundamental Gram coefficients, and dense fundamental spans; its base is a standard Borel measure space with sigma-finite measure (Measurable Hilbert field from a countable fundamental family, Standard Borel spaces, Measure spaces, Finite, sigma-finite, and semifinite measures).

[F2]

The complex inner product is linear in its first variable; measurable sections have Borel norms and pairings and are closed under Borel scalar operations and pointwise norm limits (Real and complex inner-product spaces and their induced length, Measurable sections have measurable pointwise inner products).

[F3]

The direct integral is the quotient of square-integrable measurable sections with its integrated inner product. Its construction proves the pairing integrand is integrable by fibre and scalar L2 Cauchy--Schwarz; under AC, the direct integral of any such field is a Hilbert space (Direct integral of a measurable Hilbert field, Direct integrals of measurable Hilbert fields are Hilbert spaces).

[F6]

A sigma-finite measure has a countable finite-measure cover; countable unions of null sets are null; and a nonnegative measurable function has integral zero exactly when it vanishes almost everywhere (Finite, sigma-finite, and semifinite measures, Finite and countable subadditivity of measures, A nonnegative measurable function has integral 0 exactly when it vanishes almost everywhere).

[F8]

Weak measurability of an operator field is equivalent to Borel pairings against all measurable sections; WOT on bounded operators is initial for scalar functionals, and Hilbert-space Riesz representation writes those functionals as inner products (Measurable and decomposable operator fields, Strong and weak operator topologies, Riesz representation for Hilbert spaces, The spaces (\mathcal B(X,Y)) and (\mathcal B(X)) of bounded linear operators, The operator norm as the least bound and as the unit-sphere or unit-ball supremum).

[F10]

Cauchy--Schwarz makes inner products continuous, and for a linear subspace of a Hilbert space the double orthogonal complement is its closure under Countable Choice (Cauchy–Schwarz: ∣⟨x,y⟩∣≤∥x∥ ∥y∥, with equality exactly for dependent pairs, The double orthogonal complement of a subspace is its closure).

[F11]

If two measurable sections are square-integrable, the modulus of their pointwise pairing is integrable; the direct-integral construction proves this by fibrewise and scalar L2 Cauchy--Schwarz (Direct integral of a measurable Hilbert field).

[F12]

The Cauchy-sequence real field has the least-upper-bound property, hence is a complete ordered field; every real number is strictly below a natural number by the Archimedean theorem (The Cauchy-sequence reals have the least-upper-bound property, Every complete ordered field is Archimedean, Order on the reals).

Proof

technique · direct

Given: AC, the field (Hx,en(x)), and, for the closed-span claim, a sequence (ξk) of measurable sections.

1.1F1F2F7construct

For any sequence (un) of measurable sections, set vn=un−∑j<n⟨un,fj⟩fj and fn=vn/∥vn∥ when ∥vn∥>0, with fn=0 otherwise. Inductively, measurable-section closure [F2] makes each finite coefficient, sum, residual, and residual norm measurable; the reciprocal on (0,∞) extended by zero at zero is Borel, so each fn is measurable. If the earlier nonzero fj are orthonormal, then for each nonzero fℓ with ℓ<n, ⟨vn,fℓ⟩=⟨un,fℓ⟩−∑j<n⟨un,fj⟩⟨fj,fℓ⟩=0; normalizing a nonzero residual preserves orthogonality. Also un lies in the span of f0,…,fn, and induction gives equality of the spans of the terms with indices 0,…,n of (un) and (fn). Thus the nonzero fn form an orthonormal family whose closed span equals that of (un). Apply this recursion to the fundamental family (en) to obtain a complete system in each Hx; [F2] also gives Borel x↦⟨ξ(x),fn(x)⟩ for every measurable section ξ.

2.1F1F2F7step 1.1

Let an(x)=1{∥fn(x)∥=1}, set N−1(x)=0, and for m≥0 put Nm(x)=∑0≤n≤man(x). These are Borel by [F2,F7]. For finite p≥1, Xp=(⋂m{Nm≤p})∩(⋃m{Nm=p}); also X∞=⋂q≥1⋃m{Nm≥q} and X0=⋂m{Nm=0}. Sigma-algebra closure makes these sets Borel. Since each nonzero fn(x) has norm one and their family is complete, Nm(x) counts the active vectors at indices 0,…,m; the formulas therefore give exactly the finite, infinite, and zero dimensions.

2.2F1F2F3F4F5step 1.1

Apply the recursion of step 1.1 to (ξk), obtaining measurable hn whose nonzero values form an orthonormal basis of Sx=span⁡‾{ξk(x):k∈N}. Each Sx is a closed Hilbert subspace of Hx, and the Borel Gram coefficients and dense span of (hn) make (Sx,hn(x)) a measurable closed Hilbert subfield by [F1,F2]. Every S-measurable section ζ is H-measurable: its finite expansions ∑n≤N⟨ζ,hn⟩hn are measurable H-sections and converge pointwise in norm to ζ by [F4,F5], so [F2] applies. Conversely, every H-measurable section taking values in Sx is S-measurable because its pairings with the measurable hn are Borel by [F2]. Thus inclusion induces an isometric embedding HS↪HH. The direct-integral Hilbert theorem [F3] makes its domain complete, so its image is closed.

3.1F1F2F4F5F7step 1.1step 2.1

On Xp, put Jp={1,…,p} for finite p and J∞=N>0. Enumerate the active frame indices increasingly: for j∈Jp, let νj(x) be the jth n≥0 with an(x)=1, and put gj(x)=fνj(x)(x). Using the convention N−1=0, the fibers are {νj=n}=Xp∩{Nn−1=j−1}∩{an=1} for n≥0; hence each piece is Borel and the sections gj are measurable. Their values form an orthonormal basis of Hx. For a fixed separable Kp of dimension p, take an at most countable dense set, enumerate it using [F5], and apply the dense-sequence Gram--Schmidt theorem to obtain an orthonormal basis (bj)j∈Jp. The map gj(x)↦bj on finite linear combinations is well-defined and isometric because both families are orthonormal. For any v∈Hx, choose finite combinations vn converging to v; their images are Cauchy, so completeness of Kp defines Uxv:=lim⁡nUxvn, independently of the approximating sequence and preserving linearity and norm. If Uxvn→w for a sequence in the range, isometry makes (vn) Cauchy; completeness of Hx gives vn→v, whence w=Uxv and the range is closed. It contains the dense span of (bj), so Ux is onto. Parseval [F5] gives ⟨Uxξ(x),bj⟩=⟨ξ(x),gj(x)⟩ and convergence of the corresponding partial expansions.

3.2F2F3F4F6F10F11F12step 2.2

Let L be the closed span in HH of all f1Eξk, where E=Dj∩{x:∥ξk(x)∥≤r}, (Dj) ranges over a countable finite-measure Borel cover, r∈R with r≥1, and f ranges over bounded Borel scalar functions supported in E. It is enough to use integer radii: for any real r≥1, [F12] gives an integer R≥r, so Er⊆ER; since f is supported in Er, f1Erξk=f1ERξk. Thus the real-radius and integer-radius generating families coincide. Each generator is an S-measurable section by step 2.2 and is square-integrable because ∥f1Eξk∥≤r∥f∥∞1Dj; hence L⊆HS. Let η∈L⊥ and fix k,j and an integer r≥1. The pairing h(x)=⟨ξk(x),η(x)⟩ is Borel by [F2], and 1Eh is integrable: 1Eξk and 1Eη are square-integrable, so [F11] supplies the direct-integral Cauchy--Schwarz estimate. Define f=1Eh‾/∣h∣ where h≠0, and f=0 where h=0. This is bounded Borel and supported in E by [F7]. Since the inner product is linear in its first variable, 0=⟨[fξk],[η]⟩=∫E∣h∣ dμ, so [F6] gives that the Borel set Nk,j,r:=E∩{x:h(x)≠0} is null. For each k, the sets E with j varying and integer r≥1 cover X: the Dj cover X, and every finite norm is bounded by some integer. There are countably many triples (k,j,r) by iterating the pairing in [F9], so their null sets have a null union by [F6]. Off that union, η(x)⊥ξk(x) for every k, hence η(x)⊥Sx. Thus η⊥HS, so L⊥⊆HS⊥. Since L⊆HS and both are closed, [F10] yields HS=HS⊥⊥⊆L⊥⊥=L. Therefore L=HS.

4.1F2F4F5F7F9F10step 3.1

Let D⊆Kp be a countable dense set and enumerate it, and enumerate Q>0. The balls B(d,q) for d∈D and q∈Q>0 form a countable base: given x∈B(y,ε), put δ=(ε−∥x−y∥)/3>0 and choose d∈D with ∥x−d∥<δ. Then ∥d−y∥≤∥d−x∥+∥x−y∥<ε−2δ, so ∥x−d∥<ε−∥d−y∥. Choose rational q strictly between these two bounds. It follows that x∈B(d,q)⊆B(y,ε). For the measurable section ξ, write cj(x)=⟨ξ(x),gj(x)⟩ for j∈Jp. If ξ is measurable, each cj is Borel by [F2]; for every fixed y∈Kp, Parseval gives ∥Uxξ(x)−y∥2=lim⁡N→∞∑j∈Jpj≤N∣cj(x)−⟨y,bj⟩∣2, a Borel function by [F7]. Hence inverse images of the countable basic balls are Borel, proving x↦Uxξ(x) Borel. Conversely, if this map is Borel, continuity of its coordinate functionals follows from Cauchy--Schwarz [F10] and makes each cj Borel; the partial sections ∑j∈Jpj≤Ncjgj are measurable and converge pointwise in norm to ξ by [F4,F5], so [F2] makes ξ measurable. This proves both directions of the section criterion.

5.1F4F8F9F10step 3.1∎

Let Tx∈B(Hx) be weakly measurable and set T~x=UxTxUx−1 on Kp. For basis indices i,j∈Jp, ⟨T~xbi,bj⟩=⟨Txgi(x),gj(x)⟩ is Borel by [F8] and the measurable sections of step 3.1. On the radius-C operator ball, the basis matrix coefficients generate the WOT: if ξm,ηm are finite basis expansions converging to ξ,η, then uniformly for ∥T∥≤C, Cauchy--Schwarz and the operator norm give ∣⟨Tξ,η⟩−⟨Tξm,ηm⟩∣≤C(∥ξ−ξm∥∥η∥+∥ξm∥∥η−ηm∥). The matrix coefficients separate operators by density of the finite basis spans, and every WOT coefficient is a uniform limit on the ball of finite linear combinations of these coordinates; conversely each matrix coordinate is WOT-continuous. Thus the ball's WOT topology is its subspace topology from CJp×Jp, with the index set Jp from step 3.1. This is a countable product of second-countable copies of C by [F9], using AC through [F4]. Since all coordinate maps are Borel, x↦T~x is Borel into the WOT ball whenever ∥Tx∥≤C for every x∈Xp.

Depends on

Used by

Dependency tree · two levels

192 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources