Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-26
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A localised module fraction is zero exactly when one denominator kills its numerator

Statement

For m∈M and s∈S, ms=0 in S−1M⟺um=0 for some u∈S.

Facts & Assumptions

Given: A commutative ring R, a multiplicative subset S⊆R, a left R-module M, an element m∈M, and an element s∈S.

[L1]

In S−1M, the equality m/s=n/t means that u(tm−sn)=0 for some u∈S (Localisation of a module at a multiplicative subset).

Proof

technique · direct
1.1L1

If m/s=0/1, then [L1] gives u(1m−s0)=um=0 for some u∈S.

1.2L1

If um=0 for some u∈S, then u(1m−s0)=0, so [L1] gives m/s=0/1=0 in S−1M.

2.1step 1.1step 1.2∎

Steps 1.1 and 1.2 prove the equivalence.

Depends on

Used by

Dependency tree · two levels

3 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources