Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (gpt-5.6-terra)audited 2026-08-26
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A localised module fraction is zero exactly when one denominator kills its numerator

Statement

For mM and sS,

ms=0 in S1Mum=0 for some uS.

Facts & Assumptions

Given: A commutative ring R, a multiplicative subset SR, a left R-module M, an element mM, and an element sS.

[L1]

In S1M, the equality m/s=n/t means that u(tmsn)=0 for some uS (Localisation of a module at a multiplicative subset).

Proof

technique · direct
1.1

If m/s=0/1, then [L1] gives u(1ms0)=um=0 for some uS.

L1
1.2

If um=0 for some uS, then u(1ms0)=0, so [L1] gives m/s=0/1=0 in S1M.

L1
2.1

Steps 1.1 and 1.2 prove the equivalence.

step 1.1step 1.2

Depends on

Used by

Dependency tree · two levels

3 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources