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How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Sparse grid cubature and mixed regularity

1 · Prerequisites

2 · Summary

This page builds Smolyak cubature from nested composite-Simpson levels. It defines finite downward-closed index sets, tensor details, and deterministic node deduplication with combined signed weights. Rectangular telescoping supplies exactness from one-dimensional level exactness; the actual work count is the distinct node union.

For continuous mixed fourth partials, tensor details have an explicit geometric decay bound. Together with convergence of the dyadic tensor rules, absolute summability gives a reconstruction and omitted-tail theorem, and the isotropic simplex has the explicit Simpson work/error bound recorded here. The dimension-adaptive procedure is finite under its stated cap and budget; a surplus is only an indicator unless a separate tail theorem is available. Constants remain dimension dependent.

3 · Logical flowchart

4 · Definitions, theorems and proofs

DefinitionDefinition: AI-adaptedProof: Not applicableOpen item page →

Nested one-dimensional quadrature levels and differences

Definition

Let Q:{g:[0,1]→R}→R be a finite quadrature functional of the form Q(g)=∑i=1mwig(xi), where m≥1, the nodes xi∈[0,1] are distinct, and wi∈R. A one-dimensional nested level hierarchy is a sequence (Qℓ)ℓ∈N0 of such functionals, with node sets Xℓ={xℓ,i:1≤i≤mℓ} satisfying Xℓ−1⊆Xℓ for every ℓ≥1. Set Q−1:=0, the zero functional, and define the detail functional Δ0:=Q0,Δℓ:=Qℓ−Qℓ−1(ℓ≥1). Finite sums are as in Finite sums and finite products, by recursion. For each d≥1, the integration functional used below is Id(f):=∫[0,1]df, with the multiple Riemann integral convention of The lower and upper Darboux integrals over a nondegenerate rectangle in Rm.

The convergence and rate results in this pair use the dyadic composite- Simpson hierarchy Qℓ(g):=QS(g;0,1,2ℓ+1),Xℓ={k/2ℓ+1:0≤k≤2ℓ+1}, where QS is the even-panel rule of Composite Simpson rule on an even uniform grid. The number of panels is even and at least two. The sets are nested because k/2ℓ=2k/2ℓ+1, and their weights are nonnegative with total weight one: each two-panel block has nonnegative weights H(1,4,1)/6 summing to its length H, and the blocks partition an interval of length one. Level zero has nodes 0,1/2,1 and weights 1/6,4/6,1/6.

For a multi-index ℓ=(ℓ1,…,ℓd)∈N0d, any tensor product Rℓ1(1)⊗⋯⊗Rℓd(d) of these finite functionals means the finite weighted functional obtained by multiplying the coordinate weights and evaluating on the corresponding node tuples. In particular, Δℓ:=Δℓ1(1)⊗⋯⊗Δℓd(d). No exactness or error property is implied by the notation alone.

DefinitionDefinition: AI-adaptedProof: Not applicableOpen item page →

Smolyak cubature on a finite downward-closed index set

Definition

Fix a dimension d≥1. A finite set Λ⊆N0d is downward closed if, whenever ℓ∈Λ and ℓj>0, the index ℓ−ej also belongs to Λ; here ej is the jth coordinate unit vector. In this pair an admissible Smolyak set is a nonempty finite downward- closed Λ that contains 0.

For a level hierarchy from Nested one-dimensional quadrature levels and differences, define the scalar detail value δℓ(f):=(Δℓ1(1)⊗⋯⊗Δℓd(d))(f), and the Smolyak cubature functional QΛ(f):=∑ℓ∈Λδℓ(f). Each summand is a finite signed weighted sum. Expanding all differences and adding coefficients at equal points gives one finite signed weight for each distinct node in NΛ:=⋃ℓ∈ΛXℓ1×⋯×Xℓd. The node-union work count for this direct evaluation convention is W(Λ):=∣NΛ∣, so shared nodes are counted once. A combined weight may be negative or zero; no positivity claim follows from the definition.

LemmaStatement: AI-adaptedProof: AI-adaptedOpen item page →

Convergence of dyadic tensor composite-Simpson rules

Statement

Let d≥1 and let f:[0,1]d→R be continuous. For the dyadic composite-Simpson hierarchy of Nested one-dimensional quadrature levels and differences, the tensor product QL⊗d converges to the multiple Riemann integral: lim⁡L→∞QL⊗d(f)=Id(f).

Facts & Assumptions

Given: d≥1 and a continuous f:[0,1]d→R.

[F1]

Nested one-dimensional quadrature levels and differences: QL is composite Simpson with 2L+1 equal panels. Regrouping into 2L two-panel blocks gives each block length H=2−L and weights H(1,4,1)/6 at its left endpoint, midpoint, and right endpoint.

[F3]

Heine-Cantor: a continuous map from a compact metric space to any metric space is uniformly continuous: a continuous map from a compact metric space to a metric space is uniformly continuous.

[F5]

Grid partitions of a rectangle in Rm, their cells, refinements and mesh: the uniform partition into side-H boxes covers the cube, has disjoint interiors, and its cell volumes sum to one.

[F6]

Lower and upper Darboux sums over a grid partition in Rm and The lower and upper Darboux integrals over a nondegenerate rectangle in Rm: for each cell C, the lower and upper contributions are (inf⁡Cf)vol⁡(C) and (sup⁡Cf)vol⁡(C).

[F7]

Composite Simpson rule on an even uniform grid: every two-panel Simpson block has coefficients proportional to 1,4,1, which are nonnegative and sum to 6.

[F8]

Laws of finite sums and finite products: finite sums distribute and may be regrouped.

[F9]

A continuous real-valued function on a nonempty compact metric space is bounded and attains a greatest and a least value: a continuous function on a nonempty compact metric space has finite maximum and minimum, so its Darboux cell extrema are finite.

[F10]

For ∣r∣<1 the sequence rk is null, and for ∣r∣>1 the sequence ∣r∣k diverges to +∞ and Limits and Cauchy sequences of reals: for every positive rational ρ, all sufficiently large L satisfy (1/2)L<ρ; Laws of integer exponents gives (1/2)L=2−L.

[F11]

The rationals embed densely in the reals: below every positive real lies a positive rational.

Proof

1.1givenF2F3F10F11F12choose

Fix ε>0. By [F2] and [F3], f is uniformly continuous on [0,1]d. Choose δ>0 such that ∥x−y∥2<δ implies ∣f(x)−f(y)∣<ε. By [F12], δ/d>0; use [F11] to choose a positive rational ρ<δ/d, then [F10] to choose L with H=2−L<ρ. Thus d H<δ, and every cell of the uniform d-dimensional grid has diameter d H.

2.1givenF1F5F6F7F8F9step 1.1algebra

For the L chosen in step 1.1, the tensor Simpson rule is the sum over grid cells of their tensor two-panel block rules: each cell contributes Hd times a weighted average of its 3d endpoint/midpoint tensor nodes, with coefficients ∏j=1d(1,4,1)ij/6d. These coefficients are nonnegative and sum to one by [F7]. Each closed cell is compact and nonempty, so [F9] gives finite infimum and supremum of f there. Every node lies in its cell and its value lies between those extrema. Regrouping finite sums by [F8] gives L(f,PL)≤QL⊗d(f)≤U(f,PL), with the factors Hd equal to cell volumes.

3.1givenF4F5F6step 1.1step 2.1algebra∎

By step 1.1, the oscillation of f on each cell is at most ε. Thus [F5]–[F6] give U(f,PL)−L(f,PL)≤ε∑Cvol⁡(C)=ε. By [F4], Id(f) lies between these Darboux sums; step 2.1 places the tensor-Simpson value between them as well. Therefore ∣QL⊗d(f)−Id(f)∣≤ε. This holds for sufficiently large L for each ε>0, proving convergence.

AlgorithmAlgorithm: Literature-sourcedProof: Not applicableOpen item page →

Deterministic node merging for Smolyak cubature

Definition

Input: dimension d≥1, a finite downward-closed Λ⊆N0d containing 0, the finitely many levels required by Λ, a function f evaluable at their nodes, and for each exact node a canonical key in a totally ordered set. Keys must agree exactly if and only if the real node tuples agree. If any required rule or key is missing, return invalid-input.

Output: the sorted list of distinct node tuples with their combined signed weights, the value QΛ(f), and the actual evaluation count W(Λ).

  1. Expand each detail Δℓ in the finite Smolyak sum of Smolyak cubature on a finite downward-closed index set by replacing each coordinate factor Δ0 with Q0 and each Δr (r≥1) with Qr−Qr−1. Enumerate the resulting finite signed tensor rules in lexicographic multi-index order.
  2. For each tensor rule, enumerate its finite node tuples in lexicographic coordinate-key order. Add its signed coefficient to a finite map indexed by the exact tuple key; initialize an unseen key with coefficient 0.
  3. Form NΛ=⋃ℓ∈ΛXℓ1×⋯×Xℓd, sort its distinct exact keys, and evaluate f once at each of these keys. Return the map of combined coefficients and the finite sum of coefficient times function value. Set W(Λ):=∣NΛ∣, including any node whose combined coefficient is zero; this is the work convention used in this pair.

This is an exact-real finite procedure. Approximate floating-point node comparisons, arithmetic, and function-evaluation error are outside its claims.

DefinitionDefinition: AI-adaptedProof: Not applicablejudge pass (gpt-6-luna)Open item page →

Absolute summability of a multi-index detail family

Definition

Let A⊆N0d and let aℓ≥0 for ℓ∈A. The nonnegative sum ∑ℓ∈Aaℓ is defined when the set {∑ℓ∈Faℓ:F⊆A finite} is bounded above; its value is the supremum of that set in the complete ordered field R (Complete ordered field (least-upper-bound property)). The empty finite sum is 0. This definition does not require an enumeration of A.

For the Smolyak details δℓ(f) of Smolyak cubature on a finite downward-closed index set, absolute detail summability means that ∑ℓ∈A∣δℓ(f)∣ is defined for A=N0d. For an omitted set A=N0d∖Λ, the same definition gives the omitted absolute-detail tail.

LemmaStatement: AI-adaptedProof: AI-adaptedOpen item page →

Mixed-derivative bounds for dyadic Simpson details

Statement

Use the dyadic composite-Simpson hierarchy of Nested one-dimensional quadrature levels and differences. Let d≥1. For S={j1<⋯<jk}⊆{1,…,d}, define DSf:=∂xjk4⋯∂xj14f, so these derivatives are applied in increasing coordinate order; set D∅f=f. Assume every DSf is continuous on the closed cube, with the one-sided endpoint convention of Higher derivatives and the classes Ck and C∞, and choose finite bounds MS≥0 such that ∣DSf(x)∣≤MS on [0,1]d. For ℓ∈N0d, put S(ℓ):={j:ℓj≥1} and δℓ(f):=(Δℓ1(1)⊗⋯⊗Δℓd(d))(f). Then ∣δℓ(f)∣≤MS(ℓ)(172880)∣S(ℓ)∣16−∑j∈S(ℓ)ℓj. Moreover, for every finite F⊆N0d, ∑ℓ∈F∣δℓ(f)∣≤∑S⊆{1,…,d}MS(1743200)∣S∣<∞.

Facts & Assumptions

Given: d≥1 and a function with the continuous mixed fourth partials and finite bounds stated above.

[F1]

Nested one-dimensional quadrature levels and differences: Qℓ=QS(⋅;0,1,2ℓ+1), Δ0=Q0, and Δℓ=Qℓ−Qℓ−1 for ℓ≥1.

[F2]

Composite Simpson error bound for a four-times continuously differentiable function: on [0,1], for an even panel count N≥2, ∣∫01g−QS(g;0,1,N)∣≤(180N4)−1∥g(4)∥∞ for g∈C4[0,1].

[F3]

Composite Simpson rule on an even uniform grid: the two-panel level-zero rule has nonnegative weights 1/6,4/6,1/6, which sum to one.

[F4]

Higher derivatives and the classes Ck and C∞: the stated continuous mixed derivatives exist through the required coordinatewise orders, with one-sided endpoint derivatives.

[F5]

Triangle inequality for finite sums: the absolute value of a finite sum is at most the sum of its absolute values.

[F6]

Laws of finite sums and finite products: finite sums may be regrouped and distribute over products, and are monotone in their terms.

[F7]

For ∣r∣<1, ∑k≥0rk=1/(1−r), and for ∣r∣≥1 the series diverges states the series starting at k=0: for ratio 1/16, ∑k≥0(1/16)k=16/15. By Laws of integer exponents, (1/16)k=16−k. Removing the k=0 term, which is 1, gives ∑r≥116−r=1/15; since all terms are nonnegative, every finite partial sum starting at r=1 is at most 1/15.

Proof

1.1givenF1F2F3F5algebra

For ℓ≥1, use [F2] on levels ℓ and ℓ−1, inserting the exact integral between their values. With panel counts 2ℓ+1 and 2ℓ, [F5] gives ∣Δℓg∣≤(2−4(ℓ+1)/180+2−4ℓ/180)∥g(4)∥∞=(17/2880)16−ℓ∥g(4)∥∞. For ℓ=0, [F3] gives ∣Δ0g∣=∣Q0g∣≤∥g∥∞.

2.1givenF1F4step 1.1F6algebra

Apply the one-dimensional bounds successively in the coordinates. A finite quadrature functional commutes with derivatives in any other coordinate because it is a finite weighted sum. In each active coordinate j, apply step 1.1 to the section after the earlier-coordinate derivatives have been taken; the needed fourth derivative is the corresponding sequential mixed derivative. In each inactive coordinate use the level-zero supremum bound. Multiplying the bounds gives MS(ℓ)(17/2880)∣S(ℓ)∣16−∑j∈S(ℓ)ℓj. The stated continuous mixed derivatives justify each section estimate, and [F6] justifies the finite tensor expansions.

3.1givenstep 2.1F6F7algebra∎

Fix finite F and group indices by S=S(ℓ). For a fixed nonempty S, enlarge its levels to the finite box 1≤ℓj≤Rj where Rj is the largest such coordinate level in that group. By step 2.1 and [F6], the sum over that box is at most MS∏j∈S((17/2880)∑r=1Rj16−r)≤MS(17/43200)∣S∣, using [F7]. For S=∅, the only possible index is 0 and its term is at most M∅. Summing over all subsets proves the finite-subsum claim; the right side is finite.

LemmaStatement: AI-adaptedProof: AI-adaptedOpen item page →

Rectangular telescoping of tensor details

Statement

Let d≥1 and m=(m1,…,md)∈N0d. For Rm:={ℓ∈N0d:0≤ℓj≤mj for every j} and the details of Nested one-dimensional quadrature levels and differences, ∑ℓ∈RmΔℓ=Qm1(1)⊗⋯⊗Qmd(d).

Facts & Assumptions

Given: A dimension d≥1, terminal levels mj∈N0, and the nested one-dimensional level hierarchies.

[F1]

Nested one-dimensional quadrature levels and differences: Δ0=Q0 and Δr=Qr−Qr−1 for r≥1, with Q−1=0; tensor rules multiply coordinate weights.

[F2]

Smolyak cubature on a finite downward-closed index set: a cubature on a finite index set is the finite sum of the corresponding tensor details.

[F3]

Laws of finite sums and finite products: scalar finite sums satisfy additivity, scaling, and telescoping.

Proof

1.1givenF1F3algebra

Fix any one-dimensional input g and coordinate j, and put cr:=Qr(g). By [F3], ∑r=1mj(cr−cr−1)=cmj−c0; for mj=0 this is the empty-sum identity. Adding Q0(g) and using [F1] yields ∑r=0mjΔr(g)=Qmj(g). Since g was arbitrary, this is equality of functionals.

2.1givenF1F2F3F4step 1.1algebra∎

For each coordinate j, represent every Δr(j), 0≤r≤mj, on the common finite node set Xmj(j), inserting zero weights at absent nodes; this is possible by nestedness. Write its weight at x as aj,r(x), so ∑r=0mjΔr(j) has weight ∑r=0mjaj,r(x) by scalar additivity. By [F1], the tensor of these coordinate sums has weight ∏j=1d(∑r=0mjaj,r(xj)) at each node tuple. Repeated scalar scaling and additivity [F3], applied to the recursively formed product [F4], expand this weight as ∑ℓ∈Rm∏j=1daj,ℓj(xj). Multiplying by any input value f(x1,…,xd) and summing over the finite node tuples gives ∑ℓ∈RmΔℓ(f), since scalar additivity permits interchanging the finite sums. This is QRm(f) by [F2]. Step 1.1 identifies each coordinate sum with Qmj(j), proving the claimed equality of functionals for every f.

AlgorithmAlgorithm: Literature-sourcedProof: Not applicableOpen item page →

Finite-budget dimension-adaptive Smolyak surplus selection

Definition

Input: dimension d≥1; a finite downward-closed cap Γ⊆N0d containing 0; for each coordinate, the one-dimensional quadrature rules from a hierarchy as in Nested one-dimensional quadrature levels and differences through every level used by Γ, with canonical node keys that agree exactly if and only if the real nodes agree and are totally ordered; a function f evaluable at the nodes; and an integer evaluation budget B≥0. Admissible inputs supply all these rules and keys at every level required by Γ.

Output: a current downward-closed index set Λ⊆Γ, its Smolyak value when the initial rule fits the budget, the computed detail surpluses, the distinct nodes actually sampled, and one status: budget-too-small, budget-exhausted, or frontier-exhausted.

  1. An index ℓ∈Γ∖Λ is admissible when every immediate predecessor ℓ−ej with ℓj>0 already belongs to Λ. Its surplus is the exact detail value δℓ(f) and its selection indicator is ∣δℓ(f)∣.
  2. Form the baseline node set X0d. If its cardinality exceeds B, return budget-too-small, an empty Λ, no cubature value, and no sampled nodes. Otherwise set Λ:={0}, initialize the active candidate set as empty, evaluate f once at every baseline node, and set the current value to Q{0}(f). Then process every initially admissible index in Γ∖Λ in lexicographic order using step 3.
  3. Visit newly admissible indices in lexicographic order, skipping any index already recorded as active, accepted, or uncomputed-budget. To compute one surplus, form its finite tensor-detail node set and the new keys not already sampled. If adding them would exceed B, record this candidate as uncomputed-budget without evaluating those nodes. Otherwise evaluate each new key once, store the values, compute δℓ(f) from the finite signed weights, and add the index to the active candidate set.
  4. If the active set is empty and an admissible uncomputed-budget candidate remains, return budget-exhausted. Otherwise, if the active set is empty, return frontier-exhausted.
  5. Otherwise select the active index with largest absolute surplus, breaking ties lexicographically. Remove it from the active set, mark it accepted, add it to Λ, update the cubature value by adding its signed surplus, and inspect its finite forward neighbors for newly admissible indices; process them by step 3. Repeat from step 4.

The evaluation budget counts the union of distinct keys sampled while computing both accepted and candidate surpluses. The indicator ∣δℓ(f)∣ is a refinement heuristic only. A threshold on this indicator, or exhaustion of the finite candidate cap, is not an error certificate unless a separate omitted-tail bound applies.

TheoremStatement: AI-adaptedProof: AI-adaptedOpen item page →

Absolute detail reconstruction and omitted-tail error bound

Statement

Let d≥1, let f:[0,1]d→R be continuous, and use a level hierarchy as in Nested one-dimensional quadrature levels and differences. Suppose its tensor rules satisfy QL⊗d(f)→Id(f) and its detail family is absolutely summable in the sense of Absolute summability of a multi-index detail family. For every finite downward-closed Λ⊆N0d containing 0, ∣Id(f)−QΛ(f)∣≤∑ℓ∈N0d∖Λ∣δℓ(f)∣. In particular, the dyadic composite-Simpson hierarchy satisfies the convergence hypothesis for continuous f by Convergence of dyadic tensor composite-Simpson rules, and for the mixed-derivative class of Mixed-derivative bounds for dyadic Simpson details the same hierarchy also satisfies absolute summability.

Facts & Assumptions

Given: A dimension d≥1, continuous f:[0,1]d→R, a level hierarchy whose tensor rules converge on f to Id(f), absolute summability of its detail family, and a finite downward-closed Λ containing 0.

[F1]

Smolyak cubature on a finite downward-closed index set: QΛ(f) is the finite sum of the tensor details indexed by Λ.

[F2]

Absolute summability of a multi-index detail family: a nonnegative multi-index sum is the supremum of its finite subsums when these are bounded; the omitted tail uses the same definition on the complement of Λ.

[F3]

Rectangular telescoping of tensor details: the sum of details over RL={ℓ:0≤ℓj≤L} is QL⊗d.

[F4]

Convergence of dyadic tensor composite-Simpson rules: QL⊗d(f)→Id(f).

[F5]

Triangle inequality for finite sums: the absolute value of each finite detail sum is at most the sum of its absolute terms.

[F6]

Laws of finite sums and finite products: finite sums split over disjoint finite index sets.

[F7]

Limits and Cauchy sequences of reals: convergence of a real sequence is tested using every positive rational tolerance.

[F8]

The triangle inequality: ∣x+y∣≤∣x∣+∣y∣ for real x,y.

[F9]

Mixed-derivative bounds for dyadic Simpson details: under its continuous mixed fourth-derivative hypotheses, every finite absolute-detail subsum has the common finite bound ∑S⊆[d]MS(17/43200)∣S∣.

[F10]

The rationals embed densely in the reals: below every positive real lies a positive rational.

Proof

1.1givenF1F3F6choose

Choose L large enough that Λ⊆RL. By [F1], [F3], and [F6], QL⊗d(f)−QΛ(f)=∑ℓ∈RL∖Λδℓ(f). The index set on the right is finite and is contained in N0d∖Λ.

2.1givenF2F5F7F8F10step 1.1algebra

By [F5] and [F2], the absolute value of the right side in step 1.1 is at most the omitted-detail tail TΛ:=∑ℓ∉Λ∣δℓ(f)∣ for every sufficiently large L. Put xL:=QL⊗d(f)−QΛ(f) and z:=Id(f)−QΛ(f); the convergence hypothesis in Given says ∣xL−z∣=∣QL⊗d(f)−Id(f)∣ is eventually below every positive rational tolerance. If ∣z∣>TΛ, [F10] supplies a positive rational ε with 2ε<∣z∣−TΛ. For sufficiently large L, both Λ⊆RL and ∣xL−z∣<ε hold by finiteness of Λ and [F7]. The triangle inequality [F8] then gives ∣xL∣≥∣z∣−∣xL−z∣>∣z∣−ε>TΛ, contradicting the preceding tail bound. Hence the displayed omitted-tail inequality holds.

3.1givenF2F4F9step 2.1algebra∎

For the dyadic composite-Simpson hierarchy, [F4] supplies the convergence hypothesis in Given. If the mixed-derivative hypotheses of [F9] hold, its common bound makes the finite subsums of ∑ℓ∈N0d∣δℓ(f)∣ bounded above. By the definition [F2], the full absolute-detail sum is therefore defined and finite, so step 2.1 applies and proves the stated particular error case.

TheoremStatement: AI-adaptedProof: AI-adaptedOpen item page →

Smolyak polynomial exactness from actual one-dimensional levels

Statement

Let d≥1 and let (Qℓ) be a nested hierarchy as in Nested one-dimensional quadrature levels and differences. Suppose nondecreasing integers rℓ≥0 are supplied such that Qℓ(p)=∫01p for every real polynomial p of degree at most rℓ. Let pj be a polynomial of degree at most sj in coordinate j, and suppose qj is the least level with sj≤rqj. If a finite downward-closed Smolyak set Λ contains the whole rectangle Rq={ℓ:0≤ℓj≤qj}, then its rule Smolyak cubature on a finite downward-closed index set exactly integrates every finite linear combination of the tensor polynomials p1(x1)⋯pd(xd) with those coordinate-degree bounds. In particular, for Λn:={ℓ∈N0d:∣ℓ∣1≤n}, the rule is exact whenever ∑jqj≤n. The rℓ are the exactness degrees of the actual one-dimensional levels, distinct from the node counts mℓ in the hierarchy definition; the conclusion does not infer exactness degrees from node counts.

For the selected composite-Simpson hierarchy, each level is exact through degree three, so every tensor polynomial with coordinate degrees at most three is exact on any admissible Λ.

Facts & Assumptions

Given: d≥1, a nested one-dimensional rule hierarchy with the stated nondecreasing polynomial exactness degrees, coordinate polynomials pj, their degree levels qj, and a finite downward-closed Λ⊇Rq.

[A1]

For every level ℓ, Qℓ integrates every polynomial of degree at most rℓ exactly, and rℓ is nondecreasing.

[F1]

Nested one-dimensional quadrature levels and differences: Δ0=Q0 and Δℓ=Qℓ−Qℓ−1 for ℓ≥1; tensor rules multiply coordinate weights.

[F2]

Smolyak cubature on a finite downward-closed index set: QΛ is the finite sum of tensor details over ℓ∈Λ.

[F3]

Rectangular telescoping of tensor details: the sum of the tensor details over Rq is Qq1⊗⋯⊗Qqd.

[F4]

The integral of a product function on a product rectangle is the product of the two integrals: the integral of a product function on a product of nondegenerate rectangles is the product of the coordinate integrals.

[F5]

Linearity, monotonicity, the absolute-value estimate and coordinate-slice additivity for the Riemann integral in Rm: the multiple Riemann integral is linear on finite sums of integrable functions.

[F6]

Laws of finite sums and finite products: finite sums are additive and obey scalar scaling.

[F7]

Composite Simpson rule is exact through cubic degree: the composite-Simpson rule on [0,1] is exact for every polynomial of degree at most three whenever its panel count is even and at least two.

Proof

1.1givenA1F1algebra

Fix a tensor polynomial p(x)=∏j=1dpj(xj). If some ℓj>qj, then ℓj−1≥qj, so [A1] makes both Qℓj and Qℓj−1 exact on pj; hence Δℓj(pj)=0. Therefore every tensor detail with ℓ∉Rq vanishes on p.

2.1givenA1F2F3F4step 1.1algebra

Since Rq⊆Λ, [F2] and step 1.1 reduce QΛ(p) to the rectangular detail sum. By [F3] this is ∏j=1dQqj(pj), which equals ∏j∫01pj by [A1]. Repeated application of [F4] identifies this product with Id(p).

3.1givenF5F6step 2.1algebra

Every stated tensor polynomial is a finite linear combination of products handled in step 2.1. The finite rule and the multiple integral are linear by [F5]–[F6], so exactness extends term by term. If ∑jqj≤n, every ℓ∈Rq has ∣ℓ∣1≤n, hence Rq⊆Λn, proving the isotropic-simplex claim.

4.1givenF1F7step 3.1∎

For the hierarchy of Nested one-dimensional quadrature levels and differences, each level has panel count 2ℓ+1, which is even and at least two. Thus [F7] makes every Qℓ exact through degree three. Set rℓ=3 for all ℓ; for coordinate degrees sj≤3 the least levels are qj=0, so Rq={0}⊆Λ. Step 3.1 gives the stated exactness for these tensor polynomials.

LemmaStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-6-luna)Open item page →

Termination of finite-cap surplus selection

Statement

Let Γ be the finite downward-closed candidate cap of Finite-budget dimension-adaptive Smolyak surplus selection. The algorithm preserves a downward-closed accepted set Λ⊆Γ and terminates after at most ∣Γ∣ accepted index additions, returning one of its declared statuses.

Facts & Assumptions

Given: The finite cap Γ, a finite evaluation budget, and the procedure of Finite-budget dimension-adaptive Smolyak surplus selection.

[F1]

Finite-budget dimension-adaptive Smolyak surplus selection: if the baseline node count exceeds the budget, the procedure returns budget-too-small with empty Λ and no sampled nodes; otherwise the initial accepted set is {0} and its admissible frontier is processed; an index is admitted only after every immediate predecessor is already accepted; accepted, active, and budget-uncomputed candidates are recorded so they are not processed twice; each nonterminal loop removes one selected index from the active set, accepts it, and processes newly admissible neighbors, or returns a status.

[F2]

Smolyak cubature on a finite downward-closed index set: a multi-index set is downward closed when it contains each immediate predecessor of each positive coordinate index.

Proof

1.1givenF1F2construct

If the baseline node count exceeds the budget, the procedure returns immediately with empty Λ, which is vacuously downward closed. Otherwise the initial set {0} is downward closed. Assume the current Λ is downward closed and the algorithm admits ℓ. For any μ≤ℓ coordinatewise with μ≠ℓ, choose j with μj<ℓj. Then ℓj>0, so admissibility gives ℓ−ej∈Λ, and μ≤ℓ−ej; downward closure gives μ∈Λ. Thus Λ∪{ℓ} is downward closed, and induction over additions preserves the invariant.

2.1givenF1step 1.1algebra∎

Every accepted addition is a previously unaccepted element of finite Γ, and the procedure records each computed or budget-uncomputed candidate so it cannot be processed repeatedly. Each candidate's node set and detail expansion are finite. Hence there are at most ∣Γ∣ additions and finitely many candidate inspections; when none remains computable the algorithm returns budget-exhausted or frontier-exhausted, while the undersized initial budget returns budget-too-small.

TheoremStatement: AI-adaptedProof: AI-adaptedOpen item page →

Explicit work and error rate for dyadic Simpson Smolyak cubature

Statement

Use the dyadic composite-Simpson hierarchy of Nested one-dimensional quadrature levels and differences. Let d≥1, n≥2d, and let f:[0,1]d→R satisfy the continuous mixed fourth-derivative hypotheses and bounds MS of Mixed-derivative bounds for dyadic Simpson details. Define the isotropic index set Λn:={ℓ∈N0d:∣ℓ∣1≤n}, and let Wn,d:=∣NΛn∣ be the distinct-node work count of Smolyak cubature on a finite downward-closed index set and Deterministic node merging for Smolyak cubature. For a dyadic node x, let t(x)=0 for x=0,1,1/2; if x=p/2r+1 is interior and reduced with odd numerator p, let t(x)=r≥1. Put a0:=3,ar:=2r (r≥1), ∥f∥mix,d:=∑∅≠S⊆{1,…,d}(172880)∣S∣MS,Td:=sup⁡N≥1∑r=1Nrd−116−r, Dd:=2⋅3ddd−1,Cd:=Dd4Td(3log⁡2)5(d−1), where log⁡ is the natural logarithm of The natural logarithm as the inverse of the exponential function. Then Td<∞, and the actual node-union count and error satisfy Wn,d=∑t∈N0d∣t∣1≤n∏j=1datj,2n(n−1d−1)≤Wn,d≤Dd2n(n+1)d−1, ∣Id(f)−QΛn(f)∣≤Td∥f∥mix,d16−n(n+1)d−1≤Cd∥f∥mix,dWn,d−4(log⁡(2+Wn,d))5(d−1). All constants and the mixed-derivative quantity display their dimension dependence; no weighted-anisotropic tractability claim is made.

Facts & Assumptions

Given: d≥1, n≥2d, and f with the continuous mixed derivatives and finite bounds in Mixed-derivative bounds for dyadic Simpson details.

[F1]

Smolyak cubature on a finite downward-closed index set: QΛn is the finite sum of tensor details, and NΛn is the union of its tensor-level node sets.

[F2]

Deterministic node merging for Smolyak cubature: each exact distinct node in this union is evaluated once, including nodes with zero combined weight.

[F3]

Mixed-derivative bounds for dyadic Simpson details: ∣δℓ(f)∣≤MS(ℓ)(17/2880)∣S(ℓ)∣16−∑j∈S(ℓ)ℓj; its proof bounds every finite absolute-detail subsum.

[F4]

Convergence of dyadic tensor composite-Simpson rules gives tensor-rule convergence for this dyadic hierarchy; Absolute detail reconstruction and omitted-tail error bound then bounds the error by omitted absolute details when the finite-subsum bounds in [F3] give absolute summability.

[F6]

Compositions of n into k positive parts are counted by (n−1k−1): compositions of m into k positive parts are counted by (m−1k−1) for m,k≥1.

[F7]

For ∣r∣<1, ∑k≥0rk=1/(1−r), and for ∣r∣≥1 the series diverges: a geometric series with ratio of absolute value less than one has bounded partial sums.

[F8]

The natural logarithm as the inverse of the exponential function and Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm: log⁡ is strictly increasing on positive reals, log⁡1=0, log⁡(xy)=log⁡x+log⁡y, and repeated use gives log⁡(2n)=nlog⁡2; in particular log⁡2>0.

[F9]

Finite sums and finite products, by recursion and Laws of finite sums and finite products: finite sums split over disjoint finite index sets, are monotone in nonnegative summands, and telescope.

[F10]

The set [A]k of k-element subsets and the binomial coefficient (nk):=∣[n]k∣: (mk) counts the k-element subsets of an m-element set, with the stated boundary values. An ordered q-tuple from an m-element set has mq possibilities: there is one empty tuple for q=0, and each extension appends one of the m entries, giving the count by induction on q.

[F12]

Dedekind completeness: the least-upper-bound property: every nonempty real set bounded above has a finite supremum.

[F13]

Monotonicity of x↦xn and of n↦an and Inverses of positives are positive, and reciprocation reverses order: if r≥1 and j≥1, then rj≥r>0, so r−j≤r−1 (with equality when rj=r, and reciprocal order when rj>r); powers are as in Integer powers am.

[F14]

Every complete ordered field is Archimedean: for every real x there is a natural R≥1 with x<R.

[F15]

Integer powers am: 20=1 and 2m+1=2m⋅2.

Proof

1.1givenF7F11F12F13F14algebra

Set br=rd−116−r. By [F11] and [F13], for r≥1 and j≥1 we have r−j≤r−1; hence br+1/br=(1+1/r)d−1/16≤(1+(2d−1−1)/r)/16. Put C:=2d−1−1≥0. If C=0, take R=1; if C>0, [F14] gives a natural R≥1 with 2C<R. For every r≥R, the ratio is at most (3/2)/16=3/32<1/2. Induction then bounds the tail by a geometric sequence with ratio 1/2, so [F7] bounds its partial sums; adding the finite initial segment bounds every partial sum. The partial sums form a nonempty bounded set, so [F12] defines a finite supremum Td.

1.2givenF1F2algebra

A node of Xℓ={k/2ℓ+1:0≤k≤2ℓ+1} belongs to every level at least its minimal level t(x). The three nodes of minimal level zero are 0,1/2,1. For r≥1, a node of minimal level r has reduced form p/2r+1 with odd p and 0<p<2r+1, giving exactly 2r choices. A node tuple belongs to NΛn iff its minimal-level vector t satisfies ∣t∣1≤n: that condition itself supplies an admissible index, and any index containing the tuple has each coordinate at least its minimal level. Multiplying the coordinate counts and summing over these vectors proves the exact work formula.

2.1givenF3F4F6F9F10step 1.1algebra

Fix a finite F⊆N0d∖Λn and group its indices by the nonempty active-coordinate subset S of size k. If the positive coordinates sum to m=n+r, then r≥1; there are at most (m−1k−1) such tuples by [F6]. Since this coefficient counts (k−1)-element subsets, listing each subset in increasing order injects them into ordered (k−1)-tuples with entries from a set of m elements; thus (m−1k−1)≤mk−1. Since m=n+r≤(n+1)r, each fixed-S contribution is at most MS(17/2880)k16−n(n+1)d−1rd−116−r. Summing over the finitely many r present in F, enlarging to the partial sum through the largest such r, and then summing over S gives ∑ℓ∈F∣δℓ(f)∣≤Td∥f∥mix,d16−n(n+1)d−1. Taking the supremum over finite F bounds the omitted absolute-detail tail; [F4] gives the first error inequality.

2.2givenF5F6F9F10F15F16step 1.2algebra

By the node classification and exact formula in step 1.2, the number of level vectors with ∣t∣1=m is (m+d−1d−1) by [F5], and each has ∏jatj≤3d2m. Since (m+d−1d−1) counts (d−1)-element subsets, increasing enumeration injects them into ordered (d−1)-tuples from a set of m+d elements, giving (m+d−1d−1)≤(m+d)d−1. The finite geometric sum is ∑m=0n2m=∑m=0n(2m+1−2m)=2n+1−1<2n+1: the term identity follows from [F15], telescoping from [F9], and 1>0 from [F16]. Hence Wn,d≤3d(n+d)d−1∑m=0n2m<2⋅3d2n(n+d)d−1≤Dd2n(n+1)d−1, since n+d≤d(n+1). For a lower bound, restrict to vectors with all tj≥1 and ∣t∣1=n. There are (n−1d−1) by [F6], and each contributes ∏jatj=2n.

3.1givenF8step 1.2step 2.1step 2.2algebra∎

From step 2.2, 2n≥Wn,d/(Dd(n+1)d−1), so 16−n≤Dd4Wn,d−4(n+1)4(d−1). The exact work formula in step 1.2 contains the contribution of the vector t=(n−d+1,1,…,1), whose entries are positive because n≥2d; this contribution is 2n, so Wn,d≥2n. Hence [F8] yields log⁡(2+Wn,d)≥nlog⁡2. As n≥2d≥2, n+1≤(3/2)n≤3log⁡(2+Wn,d)/log⁡2. Substituting these inequalities into step 2.1's error estimate gives the second bound with the stated Cd.

5 · Examples, counterexamples and false statements

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