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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
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Chern–Simons boundary geometry and the three-dimensional gravity interface — Examples

1 · Prerequisites

2 · Summary

3 · Logical flowchart

4 · Definitions, postulates, theorems and proofs

None yet.

5 · Examples, experiments and counterexamples

CounterexampleConstruction: AI-generatedVerification: AI-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

A degenerate BF triad defines no Lorentz metric

Physical scope

Pure mathematics; an explicit classical configuration, with no empirical or quantum claim.

Statement refuted

Every smooth solution of the zero-cosmological-constant three-dimensional BF equations has an invertible triad and determines a nondegenerate Lorentz metric satisfying the vacuum Einstein equation.

Facts & Assumptions

Given: ACω, a nonempty oriented three-manifold M with a global trivialization, and the zero-cosmological-constant BF field equations.

[A1]

The Axiom of Countable Choice (ACω): countable choice, as required by the conditional gravity proposition used for comparison.

[F1]

Chern–Simons and BF action data: the BF curvature is Fω=dω+12[ω,ω] and the covariant derivative of the BF field is Dωe.

[F2]

Invertible triads identify zero-cosmological-constant three-dimensional BF gravity: the BF equations are Fω=0 and Dωe=0, and only the invertible-coframe sector defines a nondegenerate Lorentz metric equivalent to vacuum gravity.

Counterexample

1.1A1F1F2givenconstruct

Take M to be the closed unit three-ball, choose the trivial so(2,1) bundle, and set e≡0 and ω≡0. Direct substitution gives Fω=d0+12[0,0]=0 and Dωe=d0+[0,0]=0, so [F2] says this is a BF solution.

2.1F2step 1.1algebra∎

At every x∈M, the map ex:TxM→R2,1 has rank zero, so it is not invertible. The induced symmetric tensor ge(X,Y)=η(eX,eY) is identically zero and therefore degenerate; it is not a Lorentz metric. This solution lies outside the metric-gravity sector, refuting the statement.

Sources