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Topological boundary state counts without universal gravity claims

1 · Prerequisites

2 · Summary

3 · Logical flowchart

4 · Definitions, postulates, theorems and proofs

DefinitionDefinition: AI-adaptedProof: Not applicableprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Finite fusion transfer count model

Definition

A finite fusion transfer count model consists of a finite nonempty label set I, a distinguished label 0∈I, and an explicitly supplied matrix N=(Nab)a,b∈I whose entries lie in {0,1,2,…}. The entry Nab is the multiplicity of elementary transitions from label b to label a; formally, the transition copies from b to a are the triples (b,a,j) with integer 1≤j≤Nab. A length-n path is a sequence of n+1 labels together with a chosen transition copy between each consecutive pair. View each natural-number entry as a real number under the usual inclusion N⊂R. For a finite set J and F=R or C, FJ means the functions J→F, with pointwise addition (x+y)j=xj+yj and scalar multiplication (λx)j=λxj. For real matrices A,B indexed by I, define (A+B)ab:=Aab+Bab. Their action on x∈RI is (Ax)a:=∑b∈IAabxb. Matrix multiplication is (AB)ac:=∑b∈IAabBbc; it is associative by regrouping finite sums. These definitions are compatible because ((AB)x)a=∑b,c∈IAabBbcxc=∑b∈IAab(Bx)b=(A(Bx))a, and ((A+B)C)ac=∑b(Aab+Bab)Cbc=(AC)ac+(BC)ac. Thus the natural-entry powers can also act on real vectors and the addition used below distributes over matrix multiplication. Let II be the identity matrix with entries (II)ab=1 if a=b and 0 otherwise, and use the power convention N0:=II and Nn+1:=NNn for n≥0. Define the vacuum-return count Dn:=(Nn)00. If Dn>0, set Hn:=CDn, with coordinates x=(x1,…,xDn) and inner product ⟨x,y⟩:=∑j=1Dnxjyj‾, linear in the first argument. This pairing satisfies the inner-product axioms of Real and complex inner product spaces, with the inner product linear in the first argument: finite distributivity gives ⟨αx+βz,y⟩=α⟨x,y⟩+β⟨z,y⟩, and conjugating the finite sum gives ⟨y,x⟩‾=∑jyj‾xj=⟨x,y⟩. Writing xj=aj+ibj with real aj,bj gives ⟨x,x⟩=∑j(aj2+bj2)≥0; if this sum is zero, each nonnegative summand is zero, hence every aj=bj=0 and x=0. Conversely x=0 gives zero. The conjugation identities used here follow directly from a+ib‾=a−ib and finite distributivity. Therefore Hn is a finite-dimensional complex inner-product space; its coordinate unit vectors form a basis since every x equals their linear combination with coefficients xj, and a zero combination forces every coefficient to vanish. Let IHn be its identity endomorphism and define ρn:=Dn−1IHn. If Dn=0, no normalized operator ρn is assigned. The matrix N is model data; no fusion category, quantum group, or representation is presumed to realize it.

Remarks

The definition records a finite matrix count only. It does not assert the existence of a fusion category or identify Dn with a gravitational state count.

PropositionStatement: AI-adaptedProof: AI-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Fusion path recursion and entropy

Statement

For a finite fusion transfer count model, let e0∈RI be the coordinate vector equal to 1 at label 0 and 0 elsewhere, and define vn:=Nne0. Then v0=e0, vn+1=Nvn, and the number of length-n paths from 0 to a label a is (vn)a=(Nn)a0. Whenever Dn>0, the operator ρn=Dn−1ICDn is a density matrix and has von Neumann entropy s(ρn)=log⁡Dn in nats. For the supplied two-label matrix N=(0111), with labels ordered 0,1, one has D0=1, D1=0, D2=1, and Dn+2=Dn+1+Dn for every n≥0.

Diagram convention

The diagram displays the two-label matrix only. An arrow b→a with label m represents Nab=m transitions; the count proof below uses matrix multiplication and does not rely on the drawing.

01111

Facts & Assumptions

Given: The finite set I, label 0, matrix N, and counts Dn of the Definition, together with the displayed two-label specialization.

[F1]

Finite fusion transfer count model: Nab counts transitions from b to a, (AB)ac=∑b∈IAabBbc, N0=II, Nn+1=NNn, Dn=(Nn)00, and ρn=IHn/Dn is assigned only for Dn>0; its coordinate inner product is linear in the first argument and is ⟨x,y⟩=∑jxjyj‾. The Definition verifies the inner-product axioms and defines real matrix addition and vector action by (A+B)ab=Aab+Bab and (Ax)a=∑bAabxb, using N⊂R for the entries of N; it verifies compatibility of products and actions and distributivity.

[F2]

Direct-sum sector code entropy model: a density matrix on a finite-dimensional complex inner-product space is self-adjoint, has nonnegative eigenvalues, and has trace one.

[F3]

Sector entropy and relative entropy identities: for a finite density matrix τ, s(τ)=−∑λj(τ)>0λj(τ)log⁡λj(τ), with 0log⁡0=0 and natural logarithms, so entropy is in nats.

[F4]

The basis-independent trace of an endomorphism of a finite-dimensional vector space: the trace is the basis-independent sum of diagonal entries of a finite-dimensional endomorphism.

[F5]

Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm: for x>0, log⁡(1/x)=−log⁡x and log⁡1=0.

[A1]

The two-label matrix is N=(0111) in the ordered basis (0,1).

Proof

1.1givenF1base

For n=0, the unique path of length zero is the empty path from 0 to 0, and there is no length-zero path from 0 to any a≠0. Thus the number of length-zero paths from 0 to a is (II)a0=(N0)a0=(e0)a.

1.2F1F2F3F4F5algebra

If Dn>0, then Dn is a positive integer and ρn=Dn−1IHn has eigenvalue 1/Dn with multiplicity Dn. Its trace is Dn(1/Dn)=1, and it is self-adjoint since ⟨ρnx,y⟩=Dn−1⟨x,y⟩=⟨x,ρny⟩ with the real scalar Dn−1, and its eigenvalues are nonnegative; hence it is a density matrix by [F2]. Substitution into [F3] gives s(ρn)=−Dn(1/Dn)log⁡(1/Dn)=log⁡Dn by [F5].

2.1step 1.1F1algebrainductiondischarge-induction

Suppose for a fixed n≥0 that the number of length-n paths from 0 to each b∈I is (Nn)b0. Every length-(n+1) path from 0 to a has a unique penultimate label b and a final transition copy from b to a, so the number of such paths is ∑b∈INab(Nn)b0=(NNn)a0=(Nn+1)a0 by the stated matrix-product and power conventions. Induction proves (vn)a=(Nn)a0 for every n≥0 and a∈I; in particular v0=e0 and vn+1=Nvn.

3.1A1F1algebra∎

Under [A1], direct multiplication gives N2=(1112)=N+II. Therefore D0=1, D1=0, and D2=1. From the power recursion and associativity, Nn+2=N2Nn=(N+II)Nn=Nn+1+Nn for every n≥0; taking the (0,0) entry proves Dn+2=Dn+1+Dn.

DefinitionDefinition: AI-adaptedProof: Not applicableprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Finite Hilbert boundary representation of Temperley-Lieb

Definition

Fix an integer n≥1 and a real loop parameter δ. Define [0]δ=0, [1]δ=1, and [r+1]δ=δ[r]δ−[r−1]δ for r≥1. Assume [k]δ≠0 for 2≤k≤n; this list is empty when n=1. The abstract generator algebra Pn(C,δ) is the unital complex algebra with generators u1,…,un−1 and relations ui2=δui, uiui±1ui=ui, and uiuj=ujui when ∣i−j∣>1. The diagram algebra TLn(C,δ) has basis the noncrossing pairings of n ordered bottom and n ordered top points; its product stacks the left factor above the right, deletes each closed loop, and multiplies by δ per loop. Its elementary diagram di has a cap joining top points i,i+1, a cup joining bottom points i,i+1, and vertical strands elsewhere. The isomorphism Φn:Pn(C,δ)→TLn(C,δ) sends ui to di.

For every 1≤i≤n−2, the adjacent relations in the presentation mean both uiui+1ui=ui and ui+1uiui+1=ui+1. For matching the imported recursion's notation, write Ui:=di.

Set p1=11. For 1≤r<n, put Qr=pr⊗11 by adjoining one rightmost vertical strand and define

pr+1:=Qr−[r]δ[r+1]δQrdrQr.

The denominator hypotheses make this recursion defined. For each 1≤r≤n, let p^r:=Φr−1(pr). The cited Jones-Wenzl result gives pn2=pn under these unit-denominator hypotheses. For 1≤r≤n, let ιr,n:Pr(C,δ)→Pn(C,δ) send each generator ui to the same-named generator, and let ȷr,n:TLr(C,δ)→TLn(C,δ) append n−r rightmost vertical strands. The maps commute with Φ: on each generator, both composites send ui to di with those added strands, and both send the unit to the identity diagram. Since generators and unit generate Pr, the composites agree on every element.

Let H be a nonzero finite-dimensional complex inner-product space whose inner product is linear in its first argument and conjugate-linear in its second. A unital complex-algebra representation is a complex-linear map π:Pn(C,δ)→End⁡C(H) such that π(xy)=π(x)π(y) for all x,y∈Pn(C,δ) and π(1)=IH. Here End⁡C(H) is the algebra of complex-linear endomorphisms, with composition as multiplication and IH as unit. Require each generator image to be self-adjoint, meaning ⟨π(ui)x,y⟩=⟨x,π(ui)y⟩ for all x,y∈H. Define P:=π(p^n), define rank⁡P:=dim⁡Cim⁡P, and restrict to data with rank⁡P>0. The algebraic representation as a physical boundary state space is an additional model identification and is not part of this definition.

Tower-map convention

For r<n, the presentation tower map ιr,n is well-defined because the defining relations are unchanged and it preserves the unit. For basis diagrams E,D∈TLr, appending n−r rightmost vertical strands before stacking gives the same matching as stacking E above D first and then appending those strands; the appended strands create no closed loops. Hence ȷr,n(E∘D)=ȷr,n(E)∘ȷr,n(D), and ȷr,n(1r)=1n. Bilinearity then makes ȷr,n a unital algebra homomorphism. The two unital algebra homomorphisms Φn∘ιr,n and ȷr,n∘Φr agree on every generator and the unit, so they agree on all of Pr; this identity transfers the unit-denominator recursion on diagrams to the presentation used by π.

Diagram convention

The box is notation for the three-strand algebra element p3; strands are ordered from left to right and continue through the box. For general n, the same box notation has n strands. The picture records no physical apparatus, and no proof below relies on it.

p3

Remarks

Only [2]δ,…,[n]δ are required to be nonzero; [n+1]δ may vanish. The item asserts no root-of-unity quotient, modular representation classification, trace-preserving realization, or physical area law.

PropositionStatement: AI-adaptedProof: AI-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Jones-Wenzl image gives a finite maximally mixed sector

Statement

Under the finite Hilbert representation data, let r:=rank⁡P>0 and ρ:=P/r. An orthogonal projection on H means a complex-linear endomorphism Q satisfying Q2=Q and ⟨Qx,y⟩=⟨x,Qy⟩ for all x,y∈H. Then P is an orthogonal projection, ρ is a density matrix with eigenvalue 1/r of multiplicity r and eigenvalue 0 on ker⁡P, and its entropy is s(ρ)=log⁡r in nats. Under the published closure convention, the unnormalized diagrammatic closure trace of the algebraic Jones-Wenzl element is Tr⁡n(pn)=[n+1]δ. The proposition records this separately from the ordinary Hilbert-space trace tr⁡H(P)=r and does not assert the two values agree. A sufficient additional hypothesis for equality on this element is that the representation preserve these traces, tr⁡H(π(Φn−1(X)))=Tr⁡n(X) for every X∈TLn(C,δ).

Statement references

Facts & Assumptions

Given: The data of the finite Hilbert representation definition, including n≥1, δ∈R, nonzero denominators [2]δ,…,[n]δ, a unital representation with self-adjoint generator images, and r=rank⁡P>0.

[L1]

Finite Hilbert boundary representation of Temperley-Lieb: p^n is the presentation image of the recursively defined diagram projector, P=π(p^n), every π(ui) is self-adjoint, and r=dim⁡Cim⁡P>0.

[F1]

Jones–Wenzl recursion over unit quantum integers: p1=11 and pk+1=(pk⊗11)−([k]δ/[k+1]δ)(pk⊗11)dk(pk⊗11).

[F2]

Jones–Wenzl projectors: annihilation, uniqueness, partial trace, and closure: if [2]δ,…,[n]δ are units, then pn2=pn and its unnormalized diagram closure trace is [n+1]δ.

[F3]

Unnormalized diagram closure and partial trace: Tr⁡n is the linear functional obtained by closing each top point to the corresponding bottom point and assigning a factor δ to each resulting loop.

[F4]

Direct-sum sector code entropy model: a finite density matrix is self-adjoint, has nonnegative eigenvalues, and has trace one.

[F5]

The basis-independent trace of an endomorphism of a finite-dimensional vector space: the trace is the basis-independent sum of diagonal entries in any basis.

[F6]

Sector entropy and relative entropy identities: for a density matrix τ, s(τ)=−∑λj(τ)>0λj(τ)log⁡λj(τ), with 0log⁡0=0 and natural logarithms.

[F8]

Kernel and image of a linear map: ker⁡T={x:T(x)=0} and im⁡T={T(x):x∈H} for a linear endomorphism T of H.

Proof

technique · Induct along the Jones-Wenzl recursion index to prove self-adjointness, then use the range-kernel decomposition of an idempotent
1.1L1F2algebra

By [F2], pn2=pn. The map Φn and the representation π are algebra homomorphisms, so P2=π(p^n2)=π(p^n)=P.

1.2F2F3

The imported projector result [F2] gives the unnormalized closure value Tr⁡n(pn)=[n+1]δ, where [F3] defines Tr⁡n by closing the corresponding diagram endpoints and weighting each resulting loop by δ. This is the diagram-algebra functional recorded separately from the Hilbert-space trace.

1.3L1F1base

At recursion index 1, Q1:=π(ι1,n(p^1))=IH is self-adjoint because p^1=1 and ⟨IHx,y⟩=⟨x,IHy⟩ for all x,y∈H.

1.4L1F1ihalgebra

Suppose 1≤k<n and Qk:=π(ιk,n(p^k)) is self-adjoint. By the commuting tower identity in [L1], the diagram recursion [F1] transfers under Φn−1 and π to Qk+1=Qk−ckQkπ(uk)Qk, where ck=[k]δ/[k+1]δ∈R because δ is real and the recurrence defines real quantum integers. For all x,y∈H, self-adjointness of Qk and π(uk), together with ck∈R, gives ⟨Qk+1x,y⟩=⟨Qkx,y⟩−ck⟨Qkπ(uk)Qkx,y⟩=⟨x,Qky⟩−ck⟨x,Qkπ(uk)Qky⟩=⟨x,Qk+1y⟩. Thus Qk+1 is self-adjoint.

2.1step 1.3step 1.4inductiondischarge-induction

Applying the finite step 1.4 from base step 1.3 through k=n−1 gives Qn=P, with P self-adjoint in the stated inner-product sense; when n=1, step 1.3 already gives the conclusion.

3.1F8step 1.1step 2.1algebra

For every x∈H, x=Px+(IH−P)x, with Px∈im⁡P and P(IH−P)x=0, so (IH−P)x∈ker⁡P by [F8]. If y=Pu∈im⁡P and z∈ker⁡P, then ⟨y,z⟩=⟨Pu,z⟩=⟨u,Pz⟩=0 by step 2.1 and Pz=0. Thus the two subspaces are orthogonal and sum to H, so their intersection is zero and H=im⁡P⊕ker⁡P. The idempotent P acts as the identity on im⁡P and as zero on ker⁡P, so it is an orthogonal projection with eigenvalues 1 on its r-dimensional image and 0 on the kernel.

4.1F4F5F6F7step 1.2step 3.1step 2.1algebradischarge-induction∎

By step 3.1 and [F5], the ordinary Hilbert-space trace is tr⁡H(P)=r, while step 1.2 gives the separate diagrammatic closure value. The operator ρ=P/r is self-adjoint and has eigenvalues 1/r on im⁡P and 0 on ker⁡P. In a basis formed from bases of these subspaces its trace is r(1/r)=1, so it is a density matrix by [F4,F5]. Its entropy is −r(1/r)log⁡(1/r)=log⁡r by [F6,F7]. This concludes the proof using the self-adjointness established by induction in step 2.1.

5 · Examples, experiments and counterexamples

None yet.

Sources