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Energy currents and conditional stability estimates

1 · Prerequisites

2 · Summary

3 · Logical flowchart

4 · Definitions, postulates, theorems and proofs

DefinitionDefinition: AI-adaptedProof: Not applicableverified 2026-10-22 (gpt-6.1-sol)Open item page →

Wave stress and multiplier currents

Definition

Let (M,g,N,o) be an oriented, time-oriented smooth Lorentzian four-manifold of signature (−,+,+,+), with metric-selected Levi-Civita connection ∇. Let U⊆M be open, let u,V,s∈C∞(U,R), and let X be a smooth vector field on U. Define □gu:=∇a∇au,∣du∣g2:=gab(∇au)(∇bu). If □gu=Vu+s, define the symmetric covariant tensor Tab[u,V]:=(∇au)(∇bu)−12gab(∣du∣g2+Vu2), the vector current JXa:=gacTcbXb, and the scalar deformation term KX:=Tab∇(aXb), where ∇(aXb)=(∇aXb+∇bXa)/2.

For a finite smooth singular 3-chain Σ=∑i=1kciσi with k≥0 and ci∈R, take each simplex σi to be a map Δ3→U that extends smoothly to a map into M on an open neighborhood of Δ3 in its affine span. Here Δ3:={(t0,t1,t2,t3)∈R4:tj≥0, ∑j=03tj=1}, with its standard orientation from the ordered vertices e0,e1,e2,e3, where each ej is the jth standard basis vector of R4. Define the local flux by ΦJX(Σ):=∑i=1kci∫Δ3σi∗(ιJXvolg).

Here volg is the oriented metric 4-form whose expression in an oriented chart is ∣det⁡(gab)∣ dx0∧dx1∧dx2∧dx3, and ιJXvolg is the 3-form that sends (Y1,Y2,Y3)∈(TpM)3 to volg,p(JX(p),Y1,Y2,Y3) at each p∈U. The map σi∗ is pullback of differential forms, and each simplex integral uses the pullback form-integration convention of the metric-volume current-flux definition listed in the following references section. Linearity makes the sum independent of the written chain representation. The integral uses the differential-form convention on null faces and assigns no flux to a chain with points outside U; it never extends JX outside U. In length coordinates, if u has unit [u], then V has unit m−2, s has unit [u]m−2, and the components of T have unit [u]2m−2; no physical normalization of u or X is imposed.

Remarks

The background assumption ACω is inherited from the supplied smooth Lorentzian and tangent-bundle definitions. The definition makes no additional selection. The current is a vector field; its flux is fixed by the cited metric-volume definition, so no unit normal to a null hypersurface is introduced here.

LemmaStatement: Literature-sourcedProof: AI-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Exact potential-wave multiplier identity

Statement

Let (M,g,N,o), U, u, V, s, and X satisfy the data and definitions of the wave-current definition, including □gu=Vu+s. Then ∇aJXa=KX+sX(u)−12X(V)u2. In particular, if X satisfies the Killing equation ∇(aXb)=0, X(V)=0, and s=0, then ∇aJXa=0. At a point where n is a future unit timelike vector and X is timelike with −g(X,n)>0, the density TabXanb is nonnegative whenever V≥0.

Facts & Assumptions

Given: The Lorentzian data, smooth real fields u,V,s, a smooth vector field X, the equation □gu=Vu+s, and the background countable-choice convention inherited from the cited geometry suppliers.

[F1]

Wave stress and multiplier currents: Tab=∇au∇bu−12gab(∣du∣g2+Vu2), JXa=TabXb, and KX=Tab∇(aXb).

[F2]

Smooth time-oriented Lorentzian four-manifolds: the geometric objects of the model: the time orientation selects future timelike vectors at each point, and each tangent space has signature (−,+,+,+).

[F3]

The Axiom of Countable Choice (ACω): the background axiom is countable choice ACω; no additional choice principle is assumed.

[F4]

Existence and uniqueness of the metric-selected connection of a nondegenerate metric, and its extension to tensor fields: the metric-selected connection is metric compatible and torsion free, so ∇agbc=0 and the Hessian of a scalar is symmetric.

[F5]

The observer rest-space decomposition and the spatial projection: for a unit future timelike n, TpM=Rn⊕n⊥, the restriction of g to n⊥ is positive definite, and g(v,v)=−α2+∣w∣2 when v=αn+w.

[F6]

Cauchy–Schwarz: ∣⟨u,v⟩∣≤∥u∥∥v∥, with equality exactly for linearly dependent vectors: on the positive-definite rest space n⊥, ∣du(w)∣≤∣w∣ ∣du∣n⊥.

[F7]

Observers, rest spaces and the spatial projection at an event: an observer is a future unit timelike vector, and its rest space is n⊥.

[A1]

□gu=Vu+s on U, with u,V,s smooth and real, as required in the Statement.

[A2]

For the positivity conclusion only, V≥0 at the point, n is a future unit timelike vector, and X is timelike with −g(X,n)>0.

Proof

1.1givenF1F3F4A1algebra

Metric compatibility and the product rule give ∇aTab=(□gu)∇bu+∇au ∇a∇bu−12∇b(∣du∣g2)−12∇b(Vu2). For a scalar, the Hessian is symmetric and ∇b(∣du∣g2)=2∇au ∇b∇au, so the middle two terms cancel. Substituting □gu=Vu+s into the remaining terms yields ∇aTab=s∇bu−12u2∇bV.

2.1step 1.1F1algebra

By the product rule, ∇aJXa=(∇aTab)Xb+Tab∇aXb. The tensor T is symmetric, so its contraction with ∇aXb equals its contraction with ∇(aXb), which is KX. Substituting step 1.1 gives the claimed divergence identity. If ∇(aXb)=0, then KX=0, and the stated divergence-free case follows.

3.1givenF2F5F6F7A2algebra∎

Decompose X=αn+w with w∈n⊥ by [F5]. By [A2], α=−g(X,n)>0, and timelikeness gives ∣w∣<α. Put A:=n(u), and let ∣du∣n⊥ be the norm of the restriction of du to the positive-definite rest space, using its dual metric. By the definition of T and the orthogonal decomposition, Tabnanb=12(A2+∣du∣n⊥2+Vu2),Tabwanb=w(u)A. Therefore [F6] and 2∣A∣∣du∣n⊥≤A2+∣du∣n⊥2 give TabXanb≥12(α−∣w∣)(A2+∣du∣n⊥2)+12αVu2≥0. This is the required pointwise positivity.

Remarks

This is a conditional identity for the stated scalar equation. It does not assert that any particular coupled Einstein–Maxwell perturbation has this scalar form.

TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Positive matrix-potential wave system energy

Statement

Let N≥1, I:=[0,T) with 0<T≤∞, and let J⊆R be an open interval containing I. Let U,S∈C∞(J×R,RN). Write Sym⁡N(R) for the real symmetric N×N matrices and use the Euclidean dot product and norm on RN. Let V∈C∞(R,Sym⁡N(R)) be bounded, independent of t, and positive semidefinite at every x, meaning zTV(x)z≥0 for every z∈RN. Assume U and all its mixed derivatives of total order at most two, and S, are Schwartz in x locally uniformly for t∈J: for every compact K⊂J, every such derivative D and every integer m≥0, sup⁡t∈K,x∈R(1+∣x∣)m∣DU(t,x)∣<∞, and the analogous bounds hold for S. If Utt−Uxx+V(x)U=S, define E(t):=12∫R(∣Ut∣2+∣Ux∣2+UTV(x)U) dx, where ∣⋅∣ is the Euclidean norm and ∥v(t,⋅)∥22:=∫R∣v(t,x)∣2 dx for any vector-valued function v. Then E(t)≥0, E′(t)=∫RUt⋅S dx,E(t)≤E(0)+12∫0t∥S(τ,⋅)∥2 dτ(t∈I). In particular E is constant when S=0. If t,x have length units and U has unit [U], then V has unit m−2, S has unit [U]m−2, E has unit [U]2m−1, and both sides of the square-root estimate have unit [U]m−1/2. This abstract estimate supplies neither pointwise decay nor a reconstruction of coupled Einstein–Maxwell perturbations.

Facts & Assumptions

Given: The stated smooth matrix wave system and the spatial decay assumptions.

[F1]

Differentiation under the integral sign: if f(x,t) is integrable in x for each t in an open interval, has a measurable pointwise t-derivative, and that derivative has one integrable majorant locally in t, then ddt∫f(x,t) dx=∫∂tf(x,t) dx.

[F2]
[A1]

N≥1, I=[0,T) with T>0, J⊆R is open and contains I, U,S∈C∞(J×R,RN), and V is bounded, real symmetric, positive semidefinite and independent of t. The stated local Schwartz bounds justify differentiation under the integral and vanishing spatial boundary terms.

Proof

1.1givenA1algebra

For each component multiply Ui,tt−Ui,xx+∑jVijUj=Si by Ui,t and sum over i. The product rule gives ∂t12∣Ut∣2−∂x(Ut⋅Ux)+∂t12∣Ux∣2+UtTVU=Ut⋅S. Because V is symmetric and independent of t, UtTVU=∂t(12UTVU). Thus with e:=12(∣Ut∣2+∣Ux∣2+UTVU) the identity is ∂te−∂x(Ut⋅Ux)=Ut⋅S.

2.1step 1.1F1A1algebra

Integrate step 1.1 over [−R,R]. By the Schwartz assumptions, the boundary term [Ut⋅Ux]−RR tends to 0 as R→∞. The derivative of the energy density is bounded locally in t by an integrable multiple of (1+∣x∣)−2: its terms are products of derivatives of U through order two and the bounded coefficient V times such products. Thus [F1] applies to the energy density and gives E′(t)=∫R∂te dx. Taking the limit in the integrated identity from step 1.1 yields E′(t)=∫RUt⋅S dx. Positive semidefiniteness in [A1] also gives E≥12∥Ut∥22≥0.

3.1step 2.1F2A1algebra∎

By [F2] and step 2.1, E′≤∥Ut∥2∥S∥2≤2E∥S∥2. For ε>0, differentiation yields ddtE+ε=E′2E+ε≤∥S∥22EE+ε≤∥S∥22. Integrate from 0 to t and let ε↓0 to obtain the claimed estimate, including times at which E=0.

Remarks

The estimate is finite-time energy control, not decay. To use it for an actual coupled perturbation, one must first derive that system's exact variables, angular sectors, symmetric structure, and reconstruction.

LemmaStatement: AI-adaptedProof: AI-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Subextremal RN scalar mode potential and conditional energy

Statement

Let m>0 and qe,qm∈R be length parameters, put Q2=qe2+qm2, and assume Q2<m2. Define r±:=m±m2−Q2,f(r):=1−2mr+Q2r2(r>0). On the fixed exterior Mext=Rt×(r+,∞)r×S2, use the exact dyonic Reissner–Nordström metric specified by the preceding mathematical definition with its mass parameter identified as M=m and charges qe,qm, and set t=x0. Define a real normalized spherical harmonic of degree ℓ∈{0,1,2,…} to mean a smooth real Y:S2→R such that ∫S2Y2 dωS2=1,ΔγS2Y=−ℓ(ℓ+1)Y, where in the standard polar chart ΔγS2Y=1sin⁡θ∂θ(sin⁡θ ∂θY)+1sin⁡2θ∂ϕ2Y. Here dωS2 is the area measure of the unit round metric γS2, and f′(r) denotes the ordinary derivative of f with respect to r. Since r+>0, the basepoint r0:=2r+ lies in the exterior; define the tortoise coordinate by the oriented integral r∗(r):=∫r0rf(ρ)−1 dρ. For any such Y, let ψ(t,r,ω)=ϕ(t,r)Y(ω) be a smooth real solution of □gψ=0, and put Uℓ(t,r∗):=rϕ(t,r). Then r∗ is a smooth coordinate from (r+,∞) onto R, and ∂t2Uℓ−∂r∗2Uℓ+Vℓ(r∗)Uℓ=0,Vℓ(r∗):=f(r)(ℓ(ℓ+1)r2+f′(r)r). The potential is smooth, bounded, and strictly positive on R. If Uℓ and its derivatives satisfy the decay assumptions of the positive matrix-potential wave-energy theorem on the time interval considered, then Eℓ(t):=12∫R((∂tUℓ)2+(∂r∗Uℓ)2+VℓUℓ2) dr∗ is constant there. In the original radial coordinate, its radial derivative term is 12∫r+∞f(r)∣∂rUℓ∣2 dr; this energy loses control of ∂rUℓ as r↓r+. It asserts no nondegenerate horizon-crossing derivative estimate, decay estimate, or coupled Einstein–Maxwell stability result. The coordinates t,r,r∗ and parameters m,qe,qm have unit metres, f is dimensionless, and Vℓ has unit m−2. If ψ,ϕ have a common arbitrary field unit Φ, then Y is dimensionless, Uℓ has unit Φ m, and Eℓ has unit Φ2 m.

Facts & Assumptions

Given: The exact subextremal RN exterior, the real normalized angular eigenfunction Y, the separated smooth solution ψ=ϕY, and the inherited countable-choice background of the geometric suppliers.

[F1]

Dyonic Reissner-Nordström metric and field domains: the exterior metric is g=−f dt2+f−1dr2+r2γS2 with f=1−2m/r+Q2/r2 and unit round sphere metric γS2.

[F2]

The derivative of the metric density and the chart formula for the divergence of a vector field: in a chart, ∇aJa=w−1∂a(wJa) for w=∣det⁡(gab)∣; applying this to Ja=gab∂bψ gives the scalar wave operator in divergence form.

[F3]

Positive matrix-potential wave system energy: for a smooth one-component wave on Rt×Rr∗ with bounded static nonnegative potential and zero source, its finite energy has derivative zero under the stated decay hypotheses.

[F4]

The Axiom of Countable Choice (ACω): the geometric supplier background includes ACω; no further choice principle is used.

[F5]

Wave stress and multiplier currents: □gψ is the metric trace gab∇a∇bψ of the scalar Hessian for the metric-selected Levi-Civita connection.

[F6]

Every continuous function on an interval has a primitive; two primitives differ by a constant; and ∫abf=G(b)−G(a) for any primitive G: for a continuous function on an interval and a supplied basepoint, its oriented integral defines a primitive whose derivative is that function.

[F7]

Choice-free smooth inverse function theorem in Euclidean space: a smooth map on an open subset of R with nonzero derivative at a point has a smooth local inverse near that point.

[F8]

The normalization ∫S2Y2 dωS2=1 implies that there is a fixed ω0∈S2 with Y(ω0)≠0. Since ψ(t,r,ω)=ϕ(t,r)Y(ω), the smooth map iω0(t,r):=(t,r,ω0) gives ϕ(t,r)=ψ(iω0(t,r))/Y(ω0). Therefore ϕ∈C∞(R×(r+,∞)); selecting this single point uses no choice axiom.

[A1]

m>0, qe,qm∈R, Q2=qe2+qm2<m2, and ℓ∈{0,1,2,…}.

[A2]

Y is a smooth real normalized eigenfunction as defined in the Statement, and ψ=ϕY is a smooth solution of □gψ=0. These are conditional inputs; this item makes no spectral existence assertion.

[A3]

The metric suppliers use their stated ACω background; no additional choice is taken.

Proof

1.1givenF1F6F7A1algebra

Put d:=m2−Q2>0. By [F6] the specified oriented integral defines r∗ with dr∗/dr=f−1; its integrand is smooth on the exterior, so r∗ is smooth. Then r+−r−=2d, r+r−=Q2, and f(r)=(r−r+)(r−r−)r2>0(r>r+),f′(r)=2(mr−Q2)r3. Since mr>mr+=m2+md>Q2=m2−d2, we have f′(r)>0 throughout the exterior. Also f′(r+)=(r+−r−)/r+2>0, so near r+ the positive function f(r) is bounded above and below by positive multiples of r−r+. Therefore the specified integral diverges to −∞ as r↓r+; as r→∞, f(r)→1, so it diverges to +∞. Thus r∗ is strictly increasing and onto R. Its derivative is nonzero everywhere, so [F7] gives a smooth local inverse at every point; strict increase makes these local inverses agree with the global inverse. It is therefore a smooth coordinate on the whole exterior.

1.2givenF1F2F4F5F8A1A2A3algebra

In the polar chart, ∣det⁡g∣=r2sin⁡θ, gtt=−f−1, grr=f, and gAB=r−2γAB. Applying the divergence formula in [F2] to gab∂bψ gives □gψ=−f−1∂t2ψ+1r2∂r(r2f∂rψ)+1r2ΔγS2ψ. Substitution of ψ=ϕY and the specified eigenvalue gives −f−1ϕtt+1r2∂r(r2fϕr)−ℓ(ℓ+1)r2ϕ=0. This scalar coefficient vanishes because its product with Y vanishes for all angles and ∫S2Y2 dωS2=1. The regularity needed for these differentiations is [F8].

2.1step 1.1step 1.2F8A1algebra

With Uℓ=rϕ and ∂r∗=f∂r, direct differentiation gives r2fϕr=r ∂r∗Uℓ−fUℓ. Multiply the equation in step 1.2 by fr, then fr∂r(r2fϕr)=1r∂r∗(r ∂r∗Uℓ−fUℓ)=∂r∗2Uℓ−ff′rUℓ. Together with −rϕtt=−∂t2Uℓ, and using ∂r∗f=ff′, this yields the stated one-dimensional equation and Vℓ=f[ℓ(ℓ+1)/r2+f′/r]. The derivatives are justified by [F8].

3.1step 1.1F3algebra∎

The factorization in step 1.1 gives f>0, and f′>0 there, so Vℓ>0 for every ℓ≥0. The formula is smooth for r>r+; it tends to 0 at r↓r+ because f→0 while the bracket stays finite, and it tends to 0 at infinity because f→1 and both bracket terms tend to 0. Thus Vℓ is bounded as a continuous function on the r∗ line. Under the additional decay hypothesis, apply [F3] with N=1, V=Vℓ, and S=0 to obtain Eℓ′(t)=0. Finally, dr∗=dr/f and ∂r∗Uℓ=f∂rUℓ give ∫∣∂r∗Uℓ∣2dr∗=∫f∣∂rUℓ∣2dr, whose coefficient vanishes at the horizon. This proves the stated degeneracy and no stronger horizon estimate.

Remarks

This is a test scalar on a fixed RN geometry, not a metric or Maxwell perturbation. A coupled gravitational/electromagnetic master system must be derived with its exact low angular modes and reconstruction before this positive scalar potential argument can be applied to it.

PropositionStatement: AI-adaptedProof: AI-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

An explicit conditional nonlinear energy closure

Statement

Let I=[0,T) with 0<T≤∞, and let E:I→[0,∞) be the energy functional of a wave system of the kind specified in the preceding positive matrix-potential energy theorem, restricted to its existence interval. Here absolute continuity on compact subintervals has the endpoint-increment meaning in the cited definition. Suppose E is absolutely continuous on every compact subinterval of I and, for constants C≥0, δ>0, satisfies for almost every t∈I E′(t)≤C(1+t)−1−δE(t)3/2. If E(0)>0 and CE(0)<2δ, then E(t)≤E(0)[1−CE(0)2δ]−2(t∈I). This is a bound only on the given existence interval; a separate continuation theorem is needed to infer global existence. For comparison, if C>0 and the coefficient is changed to (1+t)−1, the equality model E′=C(1+t)−1E3/2 with the same positive initial value blows up at the finite time exp⁡(2/(CE(0)))−1. This comparison is an ODE example, not a claim that an RN or Kerr–Newman perturbation satisfies either differential inequality. Time and energy are dimensionless in this scalar comparison.

Facts & Assumptions

Given: The nonnegative energy from the coupled-potential estimate, the stated interval, absolute continuity, constants C,δ, the differential inequality, ACω, and DC.

[F1]

Positive matrix-potential wave system energy: its matrix wave energy is nonnegative and absolutely continuous for the stated smooth solutions, with its exact energy functional and finite-time derivative identity.

[F2]

Absolute continuity on a compact interval: F is absolutely continuous on [a,b] when for every ε>0 there is η>0 such that every finite family of pairwise interior-disjoint subintervals of total length below η has total endpoint increments below ε; taking a single interval also gives continuity.

[F3]

Absolutely continuous functions have integrable derivatives: under ACω, an absolutely continuous real function has a derivative almost everywhere and that derivative is integrable.

[F4]

Fundamental theorem of calculus for absolutely continuous functions: under ACω and DC, an absolutely continuous F satisfies F(b)−F(a)=∫abF′(t) dt.

[F5]

A Lipschitz function after an absolutely continuous function is absolutely continuous: composing an absolutely continuous function with a Lipschitz function on its image preserves absolute continuity.

[F6]

The mean value theorem, as the case g(x)=x of Cauchy's: for f continuous on [a,b] with a<b and differentiable on (a,b) there is c∈(a,b) with f(b)−f(a)=f′(c)(b−a): for a continuous function on [a,b] differentiable on (a,b), its endpoint increment is f′(c)(b−a) for some c∈(a,b).

[F7]

Continuity and derivatives of positive-base real powers: for every real α, x↦xα is differentiable on (0,∞) with derivative αxα−1; in particular (x−1/2)′=−12x−3/2.

[F8]

The chain rule for total derivatives: D(g∘f)(a)=Dg(f(a))∘Df(a): at every point where E is differentiable and h is differentiable at E(t), (h∘E)′(t)=h′(E(t))E′(t).

[F9]

Every continuous function on an interval has a primitive; two primitives differ by a constant; and ∫abf=G(b)−G(a) for any primitive G Continuity and derivatives of positive-base real powers: the primitive of a continuous scalar function evaluates by the oriented integral; applying the power derivative in [F7] to −(1+s)−δ/δ gives ∫0t(1+s)−1−δds=[1−(1+t)−δ]/δ.

[F10]

The natural logarithm has derivative 1/x and equals the integral from 1 to x of 1/t: (log⁡(1+t))′=1/(1+t) for t>−1.

[A1]

E(0)>0, C≥0, δ>0, and CE(0)<2δ.

[A2]

E′(t)≤C(1+t)−1−δE(t)3/2 for almost every t in the existence interval.

[A3]

The real-analysis suppliers use countable choice ACω (The Axiom of Countable Choice (ACω)) and dependent choice DC (The axiom of dependent choice: a relation in which every element is related to something admits an N-indexed chain); no full axiom of choice is assumed.

[A4]

In the comparison example only, C>0.

Proof

1.1givenF1F2F3F4F5F6F7F8F9A1A2A3algebra

Fix t>0 in the positive component of {s:E(s)>0} containing 0. Since E is absolutely continuous on [0,t], [F2]'s definition applied to a single subinterval gives continuity there; positivity on this component and compactness then give a positive minimum and a finite maximum for E on [0,t]. The derivative of h(x):=x−1/2 is bounded on this range by [F7]. If the range is a singleton then h is constant on it; otherwise [F6] makes h Lipschitz there by the mean value theorem. In either case [F5] makes z:=h∘E absolutely continuous. By [F3], E′ exists almost everywhere, and [F8] gives z′(t)=−12E(t)−3/2E′(t)≥−C2(1+t)−1−δ. The absolutely continuous fundamental theorem [F4] and the primitive evaluation [F9] now give z(t)≥E(0)−1/2−C2δ(1−(1+t)−δ)≥E(0)−1/2−C2δ>0. Taking inverse squares gives the claimed bound wherever E(t)>0 in that component.

2.1step 1.1F2F3F4F5F6F7F8F9A2A3algebra

If E reaches 0, the claimed inequality is immediate at that time. It cannot later become positive: otherwise some connected component (a,b) of {t:E(t)>0} has a at or after a zero and E(a)=0, by continuity from [F2]. For any fixed t∈(a,b) and s∈(a,t), the same compact-interval argument as in step 1.1 makes z absolutely continuous on [s,t]. Integrating with [F4] gives z(t)≥z(s)−C/(2δ). As s↓a, continuity gives E(s)→0 and z(s)→∞, contradicting finite z(t). Thus after a zero E remains zero, and the bound holds throughout I.

3.1givenF7F8F10A1A4algebra∎

For the comparison kernel (1+t)−1, set t∗:=exp⁡ ⁣(2CE(0))−1,E(t):=(E(0)−1/2−C2log⁡(1+t))−2(0≤t<t∗). The denominator is positive on this interval and tends to 0 as t↑t∗. By [F10], [F7], and [F8], differentiation gives E′=C(1+t)−1E3/2, so this solution is unbounded on its existence interval. Therefore the nonintegrable coefficient does not give the uniform bound proved above.

Remarks

No continuation criterion or PDE estimate establishing [A2] is included. The proposition cannot by itself be used as a global stability theorem.

5 · Examples, experiments and counterexamples

None yet.

Sources