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All-order scalar causal extension and finite renormalization — Examples

1 · Prerequisites

2 · Summary

3 · Logical flowchart

4 · Definitions, postulates, theorems and proofs

None yet.

5 · Examples, experiments and counterexamples

CounterexampleConstruction: AI-generatedVerification: AI-adaptedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Differentiation can force a contact term from a zero punctured coefficient

Statement refuted

For all admissible flat scalar free data, time-ordered maps on the full off-shell finite-jet local functional class can preserve the exact scaling degree of every punctured differentiated numerical coefficient and its linear combinations, while being independent of the chosen density presentation. In particular, a differentiated coefficient that vanishes off the diagonal would have to extend as zero.

Facts & Assumptions

Given: Four-dimensional Minkowski coordinates (t,x) with the scalar contract's conventions, m=0, and P=∂t2−Δx.

[A1]

Assume the Axiom of Choice The Axiom of Choice and Countable Choice The Axiom of Countable Choice (ACω), as in the extension and Fourier suppliers.

[F1]

Local scalar time-ordered product contract specifies admissible scalar free data, causal factorization and graph contractions. Its corrected scaling clause permits engineering-bounded contact terms; the Statement refutes the stronger exact-degree requirement, not that corrected clause.

[F2]

Balanced jets give unique local functional representatives and the definition of local functionals give ∫fPϕ=∫(Pf)ϕ by integration by parts, with the same actual functional as input.

[F3]

Scaling degree and local extension space gives degree −∞ for the zero distribution and degree 4 for δ0; Point-extension counterterms form a finite delta-jet space gives uniqueness of an extension of degree 2<4. By Distributions supported at one point, a nonzero extension of zero off the origin is a finite delta-jet sum and has degree at least 4, so cannot have degree −∞.

[F4]

Product and pullback under wavefront transversality and Wavefront sets are invariant under smooth coordinate changes give smooth localization and coordinate transport of wavefront cones. Fourier inversion on Schwartz space fixes the Fourier delta normalization.

Counterexample

Given: [A1], [F1]–[F4].

1.1A1F1F4constructalgebra

Define the positive-frequency massless distribution by w(t,x)=∫R3e−i∣k∣t+ik⋅x2∣k∣(2π)3 d3k. This is a distribution: pairing a compact smooth spacetime test gives its rapidly decreasing Fourier transform on the null mass shell, and ∣k∣−1d3k is integrable at zero and has polynomial growth at infinity. The mass-shell relation gives Pw=0. The measure is the restriction of θ(k0)δ((k0)2−∣k∣2)d4k, hence is invariant under the proper orthochronous Lorentz group; its reflection gives w∗=w(−t,−x). Scaling k shows that w is nonzero homogeneous of degree −2. With a damping factor e−ϵ∣k∣, angular integration and the elementary Laplace integral give wϵ(t,x)=14π21∣x∣2−(t−iϵ)2. The damped spectral integrals converge to w on tests by the preceding absolute Fourier bound.

2.1F1F4step 1.1algebra

This datum has precisely the required wavefront condition. At any nonzero point of the null cone, the preceding formula is, in a normal coordinate to that cone, a nonvanishing smooth multiple of a one-sided boundary value (s±i0)−1. Its Laplace representation has Fourier support in one half-line and nonzero constant magnitude there; convolution with a compact cutoff therefore gives precisely that one-sided conormal direction. The sign selected by t−iϵ makes the covector future null under the contract's metric-dual convention. Away from the cone the formula is smooth. At the origin, convolution of the null-shell measure with the rapidly decreasing transform of a test cutoff decreases arbitrarily fast in every cone separated from the future null cone: on that cone the frequency difference is bounded below by a fixed positive multiple of the sum of the two frequency magnitudes, and the mass-shell measure has polynomial growth. Thus no other origin directions occur. Every future null origin direction does occur, by closedness of the wavefront set and approach along nonzero null points with that conormal direction. In the two-point lift W(x,y)=w(x−y) the covectors are (ξ,−ξ) by [F4], giving exactly the specified relation. The boundary-value difference w−w(−t,−x) is supported on the null cone, so E=(W−WT)/i has causal support. This verifies the free W conditions in [F1].

3.1F1F3F4step 1.1step 2.1constructalgebra

Define the time-ordered distribution by its spatial Fourier representation hF(t,x)=∫R3e−i∣k∣∣t∣+ik⋅x2∣k∣(2π)3 d3k. It acts continuously on tests by first taking their spatial Fourier transform, which decreases rapidly uniformly on compact time intervals; the same polynomial measure bound as in step 1.1 is integrable after this decay. It is symmetric under (t,x)↦(−t,−x), equals the required ordering of w, and is homogeneous of degree −2, hence has scaling degree 2. Off zero, time ordering and step 2.1 give exactly the permitted Feynman wavefront directions. At zero every relative covector is allowed by [F1]. Lorentz transformations preserve its off-zero ordering, since time order is preserved on causal pairs and the two orderings agree on spacelike pairs; the transformed distribution is another degree-2 extension of the same punctured kernel. Uniqueness from [F3] gives Lorentz invariance globally. Translation invariance of HF(x,y)=hF(x−y) is immediate. Thus (W,HF) is an admissible free datum, with all its stated hypotheses checked.

4.1F1F2F3F4step 3.1algebra∎

For a fixed spatial frequency k≠0, e−i∣k∣∣t∣/(2∣k∣) is continuous at t=0, and its first derivative has jump −i. Twice differentiating it as a one-dimensional distribution therefore gives (∂t2+∣k∣2)e−i∣k∣∣t∣2∣k∣=−iδ(t). The integrable small-frequency bound and the rapidly decreasing spatial test transform justify this differentiation inside the pairing; the value at the single frequency zero is immaterial. Fourier inversion [F4] yields PhF=−iδ0 in four spacetime dimensions. Its punctured restriction is zero, of degree −∞, while the forced contact term has degree 4. Two undifferentiated linear vertices have a contraction of degree 2<4, whose unique degree-preserving extension is hF. Replacing the first vertex ∫(Pf)ϕ by the equal functional ∫fPϕ in [F2] forces its differentiated contraction to be PhF=−iδ0. Requiring instead that the zero punctured differentiated coefficient extend with degree −∞ forces zero, giving different values for the same input functional. This refutes the Statement. The engineering bound is 2+2=4, which permits precisely this contact term and is compatible with the corrected contract.

Remarks

The witness uses the corrected null-cotangent strip relation, including tangency to the connecting null line. It is not claimed admissible under the earlier overbroad wording that transported arbitrary null covectors along that line. Correcting that relation and correcting the incompatible differentiated-degree condition are separate necessary repairs.

ExampleConstruction: AI-adaptedVerification: AI-adaptedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Two-vertex scalar logarithm and its local ambiguity

Example

Assume the Axiom of Choice and Countable Choice. In four-dimensional Euclidean space, let C0(z)=14π2∣z∣2,z∈R4∖{0}. The two-vertex four-point scalar graph with two internal lines has relative numerical kernel u(z)=C0(z)2=116π4∣z∣4. Its scaling degree at the origin is 4. A same-degree extension is ambiguous only by cδ0, and the specified extensions Tμ satisfy Tμ−Tν=18π2log⁡(μ/ν) δ0,μ,ν>0. The scale difference is a local Euclidean distribution term; it is not a numerical scattering probability and makes no assertion about a Lorentzian boundary-value product.

The diagram records two vertices x,y, two external scalar slots at each vertex, and two internal scalar contractions. Each internal edge contributes one factor C0(x−y); the picture fixes no integration or extension convention.

xy

Facts & Assumptions

Given: The Euclidean four-dimensional scalar kernel C0, the Axiom of Choice and Countable Choice, and the local causal-extension theorem at its stated formal scope.

[A1]

Assume the Axiom of Choice The Axiom of Choice and Countable Choice The Axiom of Countable Choice (ACω), as required by the scaling-degree extension and polar-integral suppliers of Exact four-dimensional Euclidean logarithmic scale anomaly.

[F1]

Scalar Epstein–Glaser induction at finite perturbative order: at each finite graph order the scalar causal construction extends the numerical graph distribution across the total diagonal with finite engineering upper bounds; independent balanced coefficients admit degree-preserving analytic extensions.

[F2]

Exact four-dimensional Euclidean logarithmic scale anomaly: for u(z)=1/(16π4∣z∣4) and its specified Euclidean extensions Tμ, sd⁡0(u)=4 and Tμ−Tν=(8π2)−1log⁡(μ/ν)δ0.

[F3]

Scaling degree and local extension space: sd⁡0 uses the positive dilation Tρ(φ)=ρ−4T(φ(⋅/ρ)) in R4.

[F4]

Point-extension counterterms form a finite delta-jet space: in dimension 4, same-degree extensions of a degree-4 punctured distribution differ by a multiple of δ0 only.

Proof

technique · direct

Given: [A1] and [F1]–[F4].

1.1givenF1F2construct

The graph in the Example has two distinct vertices and two parallel internal edges, so its numerical relative kernel is the product of the two Euclidean edge kernels, C0(z)2=u(z). By [F2], this punctured distribution has scaling degree 4; the causal extension theorem [F1] supplies the separately stated Lorentzian graph construction for admissible scalar free data at the same formal order. The Euclidean calculation uses [F2] and makes no identification of the Euclidean kernel with that Lorentzian graph.

1.2F1F2F3F4algebra

Here the relative dimension is 4 and the scaling degree is also 4. Thus ⌊4−4⌋=0, so [F4] says every two same-degree extensions differ by cδ0 for a scalar c∈C; no derivative of δ0 is allowed. This proves the local ambiguity claim without identifying the Euclidean kernel with HF.

2.1A1F2step 1.2algebra∎

Applying the exact Euclidean calculation in [F2] to the chosen scale parameters gives Tμ−Tν=(8π2)−1log⁡(μ/ν)δ0. Since the difference is supported at z=0 and is proportional to δ0, it is local. The calculation concerns only the stated Euclidean extension family, so it supplies no Lorentzian amplitude or measured probability.

Sources