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Frobenius Characteristic and the Symmetric-Group Character Dictionary

1 · Prerequisites

2 · Summary

This page builds the classical dictionary between the ordinary character theory of the symmetric groups and the ring of symmetric functions. It begins with the graded abelian group RS=⨁nR(Sn) of symmetric-group characters and the outer induction product ∘, and it defines the Frobenius characteristic ch⁡(f)=∑ρf(ρ)pρ/zρ on complex class functions, with the Hall form providing the metric on the symmetric function side. A local power-sum expansion of the complete homogeneous functions supplies the cycle-distribution coefficients used throughout.

The main structure theorem proves that ch⁡, restricted to the integral lattice RS, is an isometric isomorphism of graded rings from the outer-product ring onto Λ: the isometry comes from the class sizes n!/zρ, multiplicativity from Frobenius' induced-character formula and the split identity zρ/(zμzν)=∏i(mi(ρ)mi(μ)), and integrality and surjectivity from Young's rule together with the unitriangular Kostka change of basis and the integral basis of complete homogeneous functions. On Specht characters the dictionary reads ch⁡(χλ)=sλ, so character values become power-sum coefficients, χλ(ρ)=⟨sλ,pρ⟩H; the sign twist and the regular character appear as the omega involution and as p1 n=∑λfλsλ respectively.

3 · Logical flowchart

4 · Definitions, theorems and proofs

DefinitionDefinition: Literature-sourcedProof: Not applicableOpen item page →

The graded ordinary representation ring of the symmetric groups

Definition

For n≥0 let R(Sn) be the character ring of the finite group Sn, the Z-span of its irreducible complex characters (Virtual characters and the character ring R(G) of a finite group), so that R(S0)=Z⋅1 for the trivial group S0={1} (The finite symmetric group Sn, one-line notation, and cycle notation). The graded ordinary representation ring of the symmetric groups is the direct sum

RS:=⨁n≥0R(Sn),

the abelian group of finitely supported tuples (fn)n≥0 with fn∈R(Sn) and componentwise addition; an element f∈R(Sn) is homogeneous of degree n, and the degree-n component of an element f=∑nfn of RS is fn. This item defines only the graded abelian group and its degree decomposition: the multiplication used on RS is the outer induction product of The outer induction product of symmetric-group characters, not the tensor-product multiplication inside a single R(Sn), and no ring axioms for the outer product are assumed here. We write

RS,Q:=Q⊗ZRS,RS,C:=C⊗ZRS

for the scalar extensions. No choice principle is used.

DefinitionDefinition: Literature-sourcedProof: Not applicableOpen item page →

The outer induction product of symmetric-group characters

Definition

For m,n≥0, Sm is the symmetric group of {1,…,m}, with S0={1} (Young subgroups, tabloids, and permutation modules). Identify Sm×Sn (The external direct product G×H with componentwise multiplication) with the subgroup of Sm+n preserving each of the two blocks: the first factor acts on {1,…,m} and the second on {m+1,…,m+n}, so that (σ,τ) acts as σ on the first block and as τ on the second after shifting its labels by m. Either block may be empty; its symmetric group is trivial. These actions give an injective homomorphism, and every permutation preserving the blocks has a unique pair of restrictions, so its image is exactly the stated subgroup. For honest characters χ of Sm and ψ of Sn, let χ⊠ψ be the character of Sm×Sn on the tensor product V⊗CW of representations affording χ and ψ, with (σ,τ)⋅(v⊗w):=σv⊗τw, so that

(χ⊠ψ)(σ,τ)=χ(σ)ψ(τ)

(The tensor product of two complex representations, Characters add on direct sums, multiply on tensor products, and conjugate on duals).

Every virtual character f∈R(Sm) is an integral combination f=∑iaiχi of the irreducible characters χi of Sm (Virtual characters and the character ring R(G) of a finite group), and the coefficients ai are unique because the irreducible characters of a finite group are orthonormal, hence Z-linearly independent, in cf(Sm) (The irreducible complex characters form an orthonormal basis of cf(G)). So for f=∑iaiχi and g=∑jbjψj we may set

f⊠g:=∑i,jaibj (χi⊠ψj)∈R(Sm×Sn),

an integral combination of honest characters of Sm×Sn. Its value at (σ,τ) is f(σ)g(τ) by the displayed character formula, and uniqueness of the coefficients makes f⊠g well defined. The assignment is Z-bilinear in (f,g). The outer induction product is

f∘g:=∑i,jaibj Ind⁡Sm×SnSm+n(χi⊠ψj)∈R(Sm+n),

the induction of honest characters in the sense of The induced character Ind⁡HGχ of a complex character. The trivial character of S0 is the unit of degree zero. This is the outer product, defined across different symmetric groups; the same-rank tensor product f⋅g on a single R(Sn) is a different operation, and the two are never conflated. No choice principle is used.

LemmaStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-6.1-sol)Open item page →

Complete homogeneous functions expand in power sums with cycle-distribution coefficients

Statement

Work in ΛQ=Q⊗ZΛ. For a partition ρ write mi(ρ):=#{j:ρj=i} and zρ:=∏i≥1imi(ρ)mi(ρ)! (Partitions, English diagrams, and conjugation, Power sums pk and complete homogeneous symmetric polynomials hk).

For partitions λ and ρ of the same integer, let N(λ,ρ) be the number of ways to distribute the cycles of a permutation w of cycle type ρ among the ℓ(λ) rows, labelled 1,…,ℓ(λ), so that row j receives cycles whose lengths sum to λj. Cycles of equal length count as distinct here, because they are distinct cycles of w; equivalently,

N(λ,ρ)=∑(mi(j)) ∏i≥1mi(ρ)!∏jmi(j)!,

the sum over all matrices (mi(j)) of nonnegative integers with ∑jmi(j)=mi(ρ) for every i and ∑ii mi(j)=λj for every j; each summand is the product over i of the number of ways to assign the mi(ρ) labelled cycles of length i to rows with the prescribed multiplicities mi(j), so N(λ,ρ) is a nonnegative integer. Then

hλ=∑ρ⊢∣λ∣N(λ,ρ) pρzρin ΛQ.

In particular hd=∑ρ⊢dpρ/zρ for every d≥0.

Facts & Assumptions

Given: Partitions λ and ρ of the same integer n, with λ=(λ1,…,λk) and ρ⊢n.

[F1]

Λ=⨁d≥0Λd, where an element of Λd is a compatible sequence of degree-d symmetric polynomials in N variables whose transition maps set the last variables to zero, and multiplication is coordinatewise polynomial multiplication (The stable graded ring of symmetric functions).

[F2]

For every d≥0 the family {hμ:μ⊢d} is a Z-basis of Λd, where hμ:=∏ihμi and h∅=1 (Elementary and complete families freely generate the stable ring).

[F3]

For k≥1 the stable power sum pk∈Λk is the compatible sequence of the finite power sums pk(x1,…,xN)=x1k+⋯+xNk, and for a partition μ one sets pμ:=∏ipμi, with p∅=1; likewise hk(x1,…,xN)=∑a1+⋯+aN=kx1a1⋯xNaN (Power sums pk and complete homogeneous symmetric polynomials hk).

[F4]

For every d≥0 the family {pμ:μ⊢d} is a Q-basis of ΛQd=Q⊗ZΛd (Power sums form a rational but not integral stable basis).

[F5]

A partition of n is a weakly decreasing finite sequence of positive integers with sum n; the empty partition ∅ is the only partition of 0, and mi(μ) denotes the number of parts of μ equal to i (Partitions, English diagrams, and conjugation).

Proof

technique · direct
1.1F3algebra

Fix a rank N≥0, work in Q[x1,…,xN][ ⁣[t] ⁣], and write hd(N):=hd(x1,…,xN) and pk(N):=pk(x1,…,xN) for the rank-N specializations. The coefficient of td in ∏i=1N(1−xit)−1 is ∑a1+⋯+aN=dx1a1⋯xNaN=hd(N), so ∑d≥0hd(N)td=∏i=1N(1−xit)−1; taking the formal logarithm gives log⁡∏i=1N(1−xit)−1=∑i=1N∑k≥1xiktk/k=∑k≥1pk(N)tk/k, and applying the formal exponential (with exp⁡(log⁡U)=U for U∈1+tQ[x1,…,xN][ ⁣[t] ⁣] and exp⁡(A+B)=exp⁡(A)exp⁡(B) for series A,B with zero constant term) yields ∏i=1N(1−xit)−1=exp⁡(∑k≥1pk(N)tk/k). Expanding, exp⁡(∑k≥1pk(N)tk/k)=∏k≥1exp⁡(pk(N)tk/k), and in degree td only the factors with k≤d contribute, so hd(N) equals the sum of ∏k≥1(pk(N))mk/(kmkmk!) over all tuples (mk)k≥1 of nonnegative integers with ∑kkmk=d; grouping the tuple by the partition ρ with mk(ρ)=mk, and using ∏kpkmk=pρ and ∏kkmkmk!=zρ, gives hd(N)=∑ρ⊢dpρ(N)/zρ.

2.1F1F3step 1.1

For M≥N the transition map that sets xN+1,…,xM to zero sends hd(M)↦hd(N) and pk(M)↦pk(N), by their finite-rank definitions; hence the rank-N identities of step 1.1 are the projections of a single compatible sequence of degree-d symmetric polynomials. Therefore hd=∑ρ⊢dpρ/zρ in ΛQd for every d≥0, since two compatible sequences with equal projections are equal by [F1].

3.1F2step 2.1algebra

Let λ=(λ1,…,λk)⊢n. By definition hλ=∏j=1khλj [F2], and applying step 2.1 to each part gives hλj=∑ρ(j)⊢λjpρ(j)/zρ(j); multiplying these k finite sums, hλ=∑(ρ(1),…,ρ(k))∏j=1kpρ(j)/zρ(j), the sum over all k-tuples of partitions with ρ(j)⊢λj.

4.1F4F5step 3.1algebra

The monomial ∏jpρ(j) equals pρ exactly when merging the parts of ρ(1),…,ρ(k) gives the multiset of parts of ρ, that is, when ∑jmi(j)=mi(ρ) for every i, where mi(j):=mi(ρ(j)); a k-tuple is uniquely recovered from its matrix (mi(j)) by listing mi(j) copies of each i in decreasing order, and the further condition ∑ii mi(j)=λj records that ρ(j)⊢λj. Hence the coefficient of pρ in hλ equals ∑(mi(j))∏j1/zρ(j), the sum over all matrices with those two properties; and for such a matrix ∑jmi(j)=mi(ρ) gives ∏jimi(j)=imi(ρ), so ∏j1/zρ(j)=(∏imi(ρ)!/∏i,jmi(j)!)/zρ. Therefore the coefficient of pρ in hλ is N(λ,ρ)/zρ, because the sum displayed in the statement counts, for each i independently, the assignments of the mi(ρ) distinct cycles of length i of a fixed permutation of cycle type ρ to the k labelled rows with the multiplicities mi(j). Since {pρ:ρ⊢n} is a Q-basis of ΛQn [F4], the coefficient comparison gives hλ=∑ρ⊢nN(λ,ρ)pρ/zρ in ΛQn.

5.1F2F3step 2.1step 4.1algebra∎

For n=0 one has λ=ρ=∅, k=0, and the empty product conventions give h∅=1=N(∅,∅) p∅/z∅, while for λ=(d) the single row must receive every cycle, so N((d),ρ)=1 for every ρ⊢d and step 4.1 gives hd=∑ρ⊢dpρ/zρ; combined with step 2.1 this is the stated one-row case for every d≥0, including d=0, where both sides equal 1. The general identity of the statement now follows from step 4.1 in all cases, with the empty partition handled by the computation just given.

DefinitionDefinition: AI-adaptedProof: Not applicablejudge pass (gpt-6.1-sol)Open item page →

The Frobenius characteristic map

Definition

Fix n≥0 and let cf(Sn) be the complex vector space of class functions on Sn (Class functions and the complex vector space cf(G)). For f∈cf(Sn) and a partition ρ⊢n let f(ρ) denote the common value of f on permutations of cycle type ρ, which is well defined because cycle type determines the conjugacy class (The conjugacy classes of Sn are indexed by the tuples (c1,…,cn) with ∑kck=n). Let

zρ:=∏i≥1imi(ρ)mi(ρ)!,

where mi(ρ) is the number of parts of ρ equal to i; this is the order of the centralizer of an element of cycle type ρ (If σ∈Sn has ck cycles of length k, then ∣CSn(σ)∣=∏k=1nkckck!), so zρ is a positive integer. The Frobenius characteristic of f is

ch⁡(f):=∑ρ⊢nf(ρ) pρzρ∈ΛCn,ΛC:=C⊗ZΛ.

The sum is finite and well defined because {pρ:ρ⊢n} is a Q-basis of ΛQn (Power sums form a rational but not integral stable basis); equivalently the family {pρ/zρ:ρ⊢n} is a Q-basis of ΛQn and is orthogonal for the Hall form, with ⟨pρ/zρ,pσ/zσ⟩H=δρσ/zρ (Power sums are orthogonal for the Hall form). The codomain is ΛC, not ΛQ: for an arbitrary complex class function the coefficients f(ρ)/zρ are complex. If all values of f lie in Q, then ch⁡(f)∈ΛQn; the dictionary theorems proved later on this page show that every virtual character of Sn is rational-valued, and in fact integral-valued, so that its characteristic lies in the integral lattice Λn.

Writing cfS:=⨁n≥0cf(Sn), the map ch⁡:cfS→ΛC is defined degreewise by the displayed formula on each cf(Sn). It is C-linear on each summand, because evaluation f↦f(ρ) and scalar multiplication are linear. Its restriction to the character ring RS=⨁n≥0R(Sn) is the Frobenius characteristic dictionary studied in the remaining items of this page. No choice principle is used.

LemmaStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-6.1-sol)Open item page →

The Frobenius characteristic is an isometry

Statement

Extend the Hall form on Λ Q-bilinearly to ΛQ and then sesquilinearly to ΛC=C⊗QΛQ, linear in the first argument and conjugate-linear in the second, so that ⟨pρ,pσ⟩H=δρσzρ for all partitions ρ,σ (Power sums are orthogonal for the Hall form, The Hall inner product on symmetric functions). For all f,g∈cf(Sn),

⟨ch⁡(f),ch⁡(g)⟩H=⟨f,g⟩Sn=1n!∑w∈Snf(w)g(w)‾.

Consequently ch⁡ is injective on cf(Sn), and ⟨f,f⟩Sn=∑ρ⊢n∣f(ρ)∣2/zρ≥0 with equality if and only if f=0.

Facts & Assumptions

Given: An integer n≥0 and class functions f,g∈cf(Sn).

[F1]

ch⁡(f)=∑ρ⊢nf(ρ)pρ/zρ∈ΛCn, where f(ρ) is the common value of f on elements of cycle type ρ and zρ=∏iimi(ρ)mi(ρ)! (The Frobenius characteristic map).

[F2]

A class function is constant on conjugacy classes, and a class function is determined by its values on one representative of each conjugacy class; the space cf(Sn) carries pointwise addition and scalar multiplication (Class functions and the complex vector space cf(G)).

[F3]

The standard inner product on cf(Sn) is ⟨φ,ψ⟩Sn=1n!∑w∈Snφ(w)ψ(w)‾, linear in the first argument and conjugate-linear in the second, and it is positive definite (The standard inner product on cf(G)).

[F4]

The Hall form is the graded Z-bilinear form on Λ with ⟨hλ,mμ⟩H=δλμ; its Q-bilinear extension to ΛQ satisfies ⟨pρ,pσ⟩H=δρσzρ for all partitions ρ,σ (The Hall inner product on symmetric functions, Power sums are orthogonal for the Hall form).

[F5]

If σ∈Sn has exactly mi(ρ) cycles of length i, then its centralizer has order zρ=∏iimi(ρ)mi(ρ)! (If σ∈Sn has ck cycles of length k, then ∣CSn(σ)∣=∏k=1nkckck!).

[F6]

The conjugacy classes of Sn are indexed by the cycle types ρ⊢n, and for w∈Sn the class of w has cardinality [Sn:CSn(w)]=n!/∣CSn(w)∣ (The conjugacy classes of Sn are indexed by the tuples (c1,…,cn) with ∑kck=n, G/CG(x)→Cl⁡G(x) is a bijection, so ∣Cl⁡G(x)∣=[G:CG(x)] whenever these cardinalities are finite).

Proof

technique · direct
1.1F4

The Q-bilinear extension of the Hall form to ΛQ extends to a sesquilinear form on ΛC=C⊗QΛQ by ⟨a⊗x,b⊗y⟩H:=ab‾ ⟨x,y⟩H on decomposable tensors; it is well defined because the form is Q-bilinear, it is linear in the first argument and conjugate-linear in the second, and on power sums it has ⟨pρ/zρ,pσ/zσ⟩H=δρσ/zρ by [F4] and zρ>0.

1.2F2F3F5F6algebra

On the group side, grouping the defining sum of [F3] by conjugacy classes, which by [F6] are indexed by the cycle types ρ⊢n and have cardinality n!/zρ by [F5] and [F6], and using that f,g are constant on classes by [F2], gives ⟨f,g⟩Sn=1n!∑ρ⊢nn!zρf(ρ)g(ρ)‾=∑ρ⊢nf(ρ)g(ρ)‾/zρ.

2.1F1F4step 1.1algebra

Expanding both characteristics in the basis {pρ/zρ:ρ⊢n} of ΛQn via [F1] and using the sesquilinearity of step 1.1 and the values ⟨pρ/zρ,pσ/zσ⟩H=δρσ/zρ, ⟨ch⁡(f),ch⁡(g)⟩H=∑ρ,σf(ρ)g(σ)‾⟨pρ/zρ,pσ/zσ⟩H=∑ρ⊢nf(ρ)g(ρ)‾/zρ.

3.1F3step 2.1step 1.2∎

Steps 2.1 and 1.2 prove the displayed isometry ⟨ch⁡(f),ch⁡(g)⟩H=⟨f,g⟩Sn for all f,g∈cf(Sn). Taking g=f and using positive definiteness of the standard inner product [F3], ⟨f,f⟩Sn=∑ρ⊢n∣f(ρ)∣2/zρ≥0, with equality exactly when f(ρ)=0 for every ρ, that is, when f=0; hence if ch⁡(f)=0 then ⟨f,f⟩Sn=⟨ch⁡(f),ch⁡(f)⟩H=0 and f=0, so ch⁡ is injective on cf(Sn).

LemmaStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-6.1-sol)Open item page →

The characteristic of a Young permutation character is complete homogeneous

Statement

For every n≥0 and λ⊢n, let φλ be the character of the Young permutation module Mλ, the permutation module on λ-tabloids, so that Mλ≅Ind⁡SλSn1 (Young permutation modules are induced trivial modules, Young subgroups, tabloids, and permutation modules). Then

ch⁡(φλ)=hλ∈Λn,

the product of the complete homogeneous symmetric functions of the parts of λ.

Facts & Assumptions

Given: An integer n≥0, a partition λ=(λ1,…,λk)⊢n with standard Young subgroup Sλ≤Sn, and a permutation w∈Sn of cycle type ρ⊢n.

[F1]

Mλ is the permutation representation of Sn on the finite set Ωλ of λ-tabloids, and Mλ≅Ind⁡SλSn1 as complex representations, so φλ is the character of Ind⁡SλSn1 (Young permutation modules are induced trivial modules).

[F2]

The character of a permutation representation on a finite G-set X is χC(X)(g)=#{x∈X:g⋅x=x} (The character of a permutation representation counts fixed points).

[F3]

A λ-tabloid is the row equivalence class {t} of a λ-tableau t; it records the unordered row sets, and σ⋅{t}:={σ⋅t} defines the left action of Sn on Ωλ (Young subgroups, tabloids, and permutation modules).

[F4]

For partitions λ,ρ of the same integer n, the number N(λ,ρ) counts the distributions of the cycles of a permutation of cycle type ρ among the labelled rows with total row lengths λj, cycles of equal length being distinct; and hλ=∑ρ⊢nN(λ,ρ)pρ/zρ in ΛQ, with zρ=∏iimi(ρ)mi(ρ)! (Complete homogeneous functions expand in power sums with cycle-distribution coefficients).

[F5]

hλ=∏j=1khλj, with h∅=1; the family {hμ:μ⊢n} is a Z-basis of Λn (Elementary and complete families freely generate the stable ring).

[F6]

For f∈cf(Sn), ch⁡(f)=∑ρ⊢nf(ρ) pρ/zρ, where f(ρ) is the common value of f on elements of cycle type ρ (The Frobenius characteristic map).

Proof

technique · direct
1.1F1F2given

By [F1] and [F2], φλ(w) is the number of λ-tabloids fixed by w: φλ(w)=#{{t}∈Ωλ:w⋅{t}={t}}.

2.1F3step 1.1algebra

A λ-tabloid {t} with rows B1,…,Bk, where Bj is the set of entries of the j-th row of t, is a partition of {1,…,n} into labelled blocks with ∣Bj∣=λj; the tabloid is fixed by w exactly when w(Bj)=Bj for every j, because equality of tabloids means equality of the row sets at each row index, even when rows have equal sizes. A subset of {1,…,n} is w-invariant if and only if it is a union of cycles of w.

3.1F4step 2.1

It follows from step 2.1 that φλ(w) is the number of ways to distribute the cycles of w among the k labelled rows with the j-th row receiving cycles of total length λj; since the cycles of w are distinct subsets of {1,…,n}, cycles of equal length are distinct, and this number is exactly N(λ,ρ) for w of cycle type ρ. Hence φλ(ρ)=N(λ,ρ) for every ρ⊢n.

4.1F4F5F6step 3.1algebra

Substituting f=φλ into the definition of the characteristic and using step 3.1 and [F4], ch⁡(φλ)=∑ρ⊢nφλ(ρ)pρ/zρ=∑ρ⊢nN(λ,ρ)pρ/zρ=hλ.

5.1F4F5F6step 4.1∎

For n=0 one has λ=∅, M∅=C is the trivial representation of the trivial group, N(∅,∅)=1, z∅=1 and h∅=1, so ch⁡(φ∅)=p∅/z∅=1=h∅; the identity of step 4.1 therefore holds for every n≥0 and every λ⊢n.

LemmaStatement: Literature-sourcedProof: AI-adaptedOpen item page →

The Frobenius characteristic preserves outer products

Statement

For all m,n≥0 and all f∈R(Sm), g∈R(Sn),

ch⁡(f∘g)=ch⁡(f) ch⁡(g)in ΛCm+n,

where ∘ is the outer induction product of The outer induction product of symmetric-group characters and the right-hand side is the algebra product in ΛC. If f and g are rational-valued, the identity holds in ΛQm+n.

Facts & Assumptions

Given: Integers m,n≥0, honest characters χ of Sm and ψ of Sn, an element w∈Sm+n of cycle type ρ⊢m+n, and the block-preserving subgroup H:=Sm×Sn≤Sm+n with blocks {1,…,m} and {m+1,…,m+n}.

[F1]

For f=∑iaiχi∈R(Sm) and g=∑jbjψj∈R(Sn), the outer product is f∘g=∑i,jaibjInd⁡Sm×SnSm+n(χi⊠ψj), where (χi⊠ψj)(σ,τ)=χi(σ)ψj(τ); the assignment (f,g)↦f∘g is Z-bilinear (The outer induction product of symmetric-group characters).

[F2]

The characteristic map is ch⁡(f)=∑ρf(ρ)pρ/zρ, is defined on every class function and is linear, and R(Sm) is by definition the set of integral combinations of the honest (irreducible) characters of Sm (The Frobenius characteristic map, Virtual characters and the character ring R(G) of a finite group).

[F3]

Frobenius' formula: for a finite group G, a subgroup H≤G and the character θ of a finite-dimensional complex representation of H, Ind⁡HGθ(g)=1∣H∣∑x∈G: x−1gx∈Hθ(x−1gx) for every g∈G (Frobenius' formula for the character of an induced representation).

[F4]

For every d≥0, {pμ:μ⊢d} is a Q-basis of ΛQd, and pμ=∏jpμj, with p∅=1 (Power sums form a rational but not integral stable basis). Since each zμ is nonzero, {pμ/zμ:μ⊢d} is also a rational basis; extending scalars to C makes it a C-basis of ΛCd.

[F5]

Identify Sm×Sn with the subgroup of Sm+n preserving the blocks {1,…,m} and {m+1,…,m+n}. The two restrictions identify this subgroup with the direct product, including when a block is empty (The outer induction product of symmetric-group characters).

[F6]

For a partition ρ, zρ=∏iimi(ρ)mi(ρ)! is a positive integer (If σ∈Sn has ck cycles of length k, then ∣CSn(σ)∣=∏k=1nkckck!).

Proof

technique · direct
1.1F1F2algebra

Both sides of the asserted identity are Z-bilinear in (f,g): the outer product is bilinear by [F1], the characteristic map is linear by [F2], and multiplication in ΛC is bilinear. Since every element of R(Sm) is an integral combination of honest characters, and likewise for R(Sn), it suffices to prove ch⁡(χ∘ψ)=ch⁡(χ)ch⁡(ψ) for honest characters χ of Sm and ψ of Sn.

1.2F3F5

For honest χ,ψ, the character χ⊠ψ of H is honest, so Frobenius' formula [F3] applied to G=Sm+n and the subgroup H of [F5] gives (χ∘ψ)(w)=1m!n!∑x∈Sm+n: x−1wx∈H(χ⊠ψ)(x−1wx).

2.1F5step 1.2algebra

The condition x−1wx∈H says that x−1wx preserves {1,…,m}, equivalently that w preserves A:=x({1,…,m}). Hence the x occurring in the sum are exactly those with x({1,…,m})=A for some m-element w-invariant subset A⊆{1,…,m+n}, and for each such A there are exactly m! n! permutations x with x({1,…,m})=A. For all x with the same A, the permutation x−1wx∈H has its Sm-component conjugate through x to w∣A and its Sn-component conjugate to w∣Ac, so (χ⊠ψ)(x−1wx)=χ(μA)ψ(νA), where μA is the cycle type of w∣A and νA the cycle type of w∣Ac; this is independent of x. With the factor m!n!/m!n! cancelling, (χ∘ψ)(w)=∑Aχ(μA)ψ(νA), the sum over the m-element w-invariant subsets A.

3.1step 2.1algebra

An m-element set A is w-invariant exactly when it is a union of cycles of w, and then ∣μA∣=m and the multisets of parts of μA and νA merge to the multiset of parts of ρ. Conversely, every split ρ=μ⊎ν with ∣μ∣=m arises this way. For a fixed split, the number of m-element w-invariant A with μA=μ is ∏i≥1(mi(ρ)mi(μ)), because for each cycle length i one independently chooses which mi(μ) of the mi(ρ) cycles of w of length i are included in A. Therefore (χ∘ψ)(ρ)=∑μ⊎ν=ρ, ∣μ∣=m(∏i≥1(mi(ρ)mi(μ)))χ(μ)ψ(ν), an expression depending only on the cycle type ρ of w.

4.1F1F2F4F6step 3.1algebra

On the other side ch⁡(χ)ch⁡(ψ)=∑μ⊢m∑ν⊢nχ(μ)ψ(ν) pμpν/(zμzν), using pμpν=pμ⊎ν from [F4], the coefficient of pρ/zρ equals ∑μ⊎ν=ρχ(μ)ψ(ν)zρ/(zμzν); for a split μ⊎ν=ρ one has zρzμzν=∏i≥1mi(ρ)!mi(μ)! mi(ν)!=∏i≥1(mi(ρ)mi(μ)), since mi(ν)=mi(ρ)−mi(μ). This is exactly the coefficient in step 3.1; since {pρ/zρ:ρ⊢m+n} is a C-basis of ΛCm+n by scalar extension [F4] and [F2] gives the same power-sum coefficients for the characteristic, ch⁡(χ∘ψ)=ch⁡(χ)ch⁡(ψ).

5.1F1F2step 1.1step 3.1step 4.1∎

By step 1.1 the identity holds for all virtual characters f∈R(Sm) and g∈R(Sn). The cycle-split formula in step 3.1 also extends to these f,g by bilinearity: (f∘g)(ρ)=∑μ⊎ν=ρ, ∣μ∣=m(∏i(mi(ρ)mi(μ)))f(μ)g(ν). If f,g are rational-valued, every term is rational, so f∘g is rational-valued. By [F2], ch⁡(f)∈ΛQm and ch⁡(g)∈ΛQn, while their product and ch⁡(f∘g) lie in ΛQm+n. Thus the identity holds over Q as claimed.

TheoremStatement: AI-adaptedProof: AI-adaptedOpen item page →

The Frobenius characteristic is an isometric graded ring isomorphism

Statement

Restrict the characteristic map to the integral lattice RS=⨁n≥0R(Sn) of The graded ordinary representation ring of the symmetric groups. Then

ch⁡:RS⟶Λ

is a degree-preserving Z-module isomorphism. It carries the outer induction product ∘ of The outer induction product of symmetric-group characters to multiplication, ch⁡(f∘g)=ch⁡(f)ch⁡(g), and the unit (the trivial character of S0) to 1; consequently RS is a commutative graded Z-algebra and ch⁡ is an isomorphism of graded rings onto Λ. With the sesquilinear Hall form, ch⁡ is an isometry as in The Frobenius characteristic is an isometry. After scalar extension, ch⁡⊗Q:RS,Q→ΛQ and ch⁡⊗C:RS,C→ΛC are isomorphisms. No choice principle is used.

Facts & Assumptions

Given: An integer n≥0, the graded abelian group RS=⨁nR(Sn) with the outer product ∘, the characteristic map ch⁡ on cfS, and the Specht characters χλ of Sn.

[F1]

R(Sn) is the character ring of Sn, the integral span of its irreducible complex characters; RS is the direct sum of the R(Sn) with degree-n homogeneous parts, and RS,Q=Q⊗ZRS, RS,C=C⊗ZRS (The graded ordinary representation ring of the symmetric groups).

[F2]

For f=∑iaiχi∈R(Sm), g=∑jbjψj∈R(Sn), the outer product is f∘g=∑i,jaibjInd⁡Sm×SnSm+n(χi⊠ψj); it is Z-bilinear and maps R(Sm)×R(Sn) into R(Sm+n), and the trivial character of S0 is the unit (The outer induction product of symmetric-group characters).

[F3]

ch⁡(f)=∑ρ⊢nf(ρ)pρ/zρ on cf(Sn) and ch⁡ is linear on cfS; the degree-n component of ch⁡(f) for f∈cf(Sm) is zero when n≠m, so ch⁡ preserves degrees (The Frobenius characteristic map).

[F4]

⟨ch⁡(f),ch⁡(g)⟩H=⟨f,g⟩Sn for all f,g∈cf(Sn), ch⁡ is injective on cf(Sn), and ⟨f,f⟩Sn=∑ρ⊢n∣f(ρ)∣2/zρ vanishes only for f=0 (The Frobenius characteristic is an isometry).

[F5]

For every μ⊢n, ch⁡(φμ)=hμ, where φμ is the character of the Young permutation module Mμ (The characteristic of a Young permutation character is complete homogeneous).

[F6]

ch⁡(f∘g)=ch⁡(f)ch⁡(g) for all f∈R(Sm), g∈R(Sn) (The Frobenius characteristic preserves outer products).

[F7]

For every d≥0, {hμ:μ⊢d} is a Z-basis of Λd (Elementary and complete families freely generate the stable ring).

[F8]

Young's rule: Mμ≅⨁λ⊢n(Sλ)⊕Kλμ, so φμ=∑λ⊢nKλμχλ by additivity of characters (Young's rule for complex permutation modules, Characters add on direct sums, multiply on tensor products, and conjugate on duals).

[F9]

The matrix (Kλμ) satisfies hμ=∑λKλμsλ and is unitriangular in a linear extension of dominance, hence invertible over Z (The Kostka change of basis is dominance-unitriangular).

[F10]

Every finite-dimensional complex representation of Sn is completely reducible (Maschke's theorem over C), and the modules {Sλ:λ⊢n} are pairwise inequivalent and exhaust the irreducible complex Sn-representations; hence every honest character of Sn is a nonnegative integral combination of the χλ, and the family {χλ:λ⊢n} is a Z-basis of R(Sn) (Maschke's theorem for finite groups over fields whose characteristic does not divide ∣G∣, Specht modules classify the complex irreducibles of Sn, Distinct complex Specht modules are inequivalent, Virtual characters and the character ring R(G) of a finite group, Column antisymmetrizers, polytabloids, and Specht modules).

Proof

technique · direct
1.1F3F5F8F9F10

Membership ch⁡(R(Sn))⊆Λn: for μ⊢n, [F8] gives φμ=∑λKλμχλ∈R(Sn) and [F5] gives ch⁡(φμ)=hμ∈Λn. Since (Kλμ) is invertible over Z [F9], each χλ=∑μ(K−1)μλφμ and, by linearity of ch⁡ [F3], ch⁡(χλ)=∑μ(K−1)μλhμ∈Λn. As the χλ span R(Sn) over Z [F10], ch⁡(R(Sn))⊆Λn for every n, hence ch⁡(RS)⊆Λ.

1.2F3F4

Injectivity: if f=∑nfn∈RS satisfies ch⁡(f)=0, then each degree component ch⁡(fn) vanishes by degree preservation [F3]; the isometry formula [F4] then gives ⟨fn,fn⟩Sn=⟨ch⁡(fn),ch⁡(fn)⟩H=0, and vanishing of ∑ρ⊢n∣fn(ρ)∣2/zρ forces fn=0; hence f=0 and ch⁡ is injective on RS.

1.3F2F3F6

Multiplicativity and unit: for homogeneous f∈R(Sm), g∈R(Sn) one has ch⁡(f∘g)=ch⁡(f)ch⁡(g) [F6]; for general f=∑mfm, g=∑ngn bilinearity of ∘ [F2] and linearity of ch⁡ [F3] give ch⁡(f∘g)=∑m,nch⁡(fm)ch⁡(gn)=ch⁡(f)ch⁡(g). For the trivial character e of S0 one has ch⁡(e)=e(∅)p∅/z∅=1 since e(∅)=1 and z∅=p∅=1.

2.1F5F7step 1.1

Surjectivity onto Λ: step 1.1 shows ch⁡(RS)⊆Λ, and hμ=ch⁡(φμ)∈ch⁡(RS) for every partition μ [F5]; since {hμ:μ⊢d} is a Z-basis of Λd for every d [F7], the image contains a Z-basis of Λ and therefore equals Λ.

3.1F2F3F4step 1.2step 1.3step 2.1

By steps 1.1, 2.1 and 1.2 the map ch⁡:RS→Λ is a bijective degree-preserving Z-linear map, hence a Z-module isomorphism; by step 1.3 it is multiplicative and sends the unit to 1. Transporting the ring axioms of Λ along the bijection: for f,g,h∈RS, associativity and commutativity of ∘ follow from ch⁡((f∘g)∘h)=ch⁡(f)ch⁡(g)ch⁡(h)=ch⁡(f∘(g∘h)) and ch⁡(f∘g)=ch⁡(g∘f) together with injectivity of ch⁡, distributivity is the bilinearity of ∘ [F2], and e∘f=f because ch⁡(e∘f)=1⋅ch⁡(f); so RS is a commutative graded Z-algebra and ch⁡ is a graded ring isomorphism. The isometry clause is [F4].

4.1F1step 3.1algebra∎

Both RS and Λ are free Z-modules, graded with finitely generated homogeneous components; a Z-module isomorphism between them remains an isomorphism after tensoring with Q or C, with inverse ch⁡−1⊗id. Hence ch⁡⊗Q:RS,Q→ΛQ and ch⁡⊗C:RS,C→ΛC are isomorphisms.

TheoremStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-6.1-sol)Open item page →

The characteristic of a Specht character is a Schur function

Statement

For every n≥0 and every λ⊢n, let Sλ be the complex Specht module of shape λ (Column antisymmetrizers, polytabloids, and Specht modules) and χλ its character, an irreducible character of Sn (Specht modules classify the complex irreducibles of Sn). Then

ch⁡(χλ)=sλ∈Λn,

the stable Schur function of shape λ (Stable Schur functions from bialternants). In particular ch⁡ maps the Z-basis {χλ:λ⊢n} of R(Sn) to the Z-basis {sλ:λ⊢n} of Λn, and all values χλ(ρ) are integers.

Facts & Assumptions

Given: An integer n≥0 and partitions λ,μ⊢n; the Young permutation module Mμ with character φμ and the Specht modules Sλ with characters χλ.

[F1]

Young's rule: Mμ≅⨁λ⊢n(Sλ)⊕Kλμ as CSn-modules, where Kλμ is the Kostka number (Young's rule for complex permutation modules).

[F2]

Kλμ is the number of semistandard λ-tableaux of content μ, so it is a nonnegative integer (Semistandard tableaux and Kostka numbers).

[F3]

Characters of finite-dimensional complex representations are additive on direct sums: χV⊕W=χV+χW (Characters add on direct sums, multiply on tensor products, and conjugate on duals).

[F4]

The characteristic map is ch⁡(f)=∑ρ⊢nf(ρ)pρ/zρ and is Z-linear on class functions; R(Sn) is by definition the integral span of the irreducible characters of Sn (The Frobenius characteristic map, Virtual characters and the character ring R(G) of a finite group).

[F5]

ch⁡(φμ)=hμ for every μ⊢n (The characteristic of a Young permutation character is complete homogeneous).

[F6]

For partitions λ,μ: hμ=∑λ⊢nKλμsλ, Kλμ=0 unless λ⊵μ, and Kμμ=1; hence, in a linear extension of dominance from smaller to larger, (Kλμ) is lower unitriangular with diagonal entries 1 and is invertible over Z (The Kostka change of basis is dominance-unitriangular).

[F7]

For every d≥0 the Schur functions {sλ:λ⊢d} form a Z-basis of Λd (Schur functions form an orthonormal integral basis).

[F8]

hμ=∑ρ⊢nN(μ,ρ)pρ/zρ in ΛQn, with N(μ,ρ)∈Z and zρ=∏iimi(ρ)mi(ρ)! (Complete homogeneous functions expand in power sums with cycle-distribution coefficients).

[F9]

The Specht modules Sλ, λ⊢n, are pairwise inequivalent and exhaust the irreducible complex representations of Sn; the irreducible complex characters of a finite group are orthonormal, hence Z-linearly independent, in the space of class functions (Specht modules classify the complex irreducibles of Sn, Distinct complex Specht modules are inequivalent, The irreducible complex characters form an orthonormal basis of cf(G)).

Proof

technique · direct
1.1F1F2F3

For every μ⊢n, taking characters in Young's rule [F1] and using additivity on direct sums [F3] gives φμ=∑λ⊢nKλμχλ in cf(Sn), the sum being finite.

2.1F4F5step 1.1algebra

Applying the Z-linear map ch⁡ to step 1.1 and using [F5] gives hμ=ch⁡(φμ)=∑λ⊢nKλμch⁡(χλ) in ΛCn.

3.1F6step 2.1algebra

Subtracting the identity hμ=∑λKλμsλ of [F6] from step 2.1 yields ∑λ⊢nKλμ(ch⁡(χλ)−sλ)=0 for every μ⊢n, a homogeneous linear system with coefficient matrix KT, where K=(Kλμ); since K is unitriangular in a linear extension of dominance, both K and KT are invertible over Z, so the only solution is the zero vector and ch⁡(χλ)=sλ for every λ⊢n.

4.1F4F8step 3.1algebra

Inverting the integral matrices, sλ=∑μ⊢n(K−1)μλhμ with (K−1)μλ∈Z; substituting hμ=∑ρ⊢nN(μ,ρ)pρ/zρ with integral N(μ,ρ) gives sλ=∑ρ⊢ncλρ pρ/zρ with cλρ=∑μ(K−1)μλN(μ,ρ)∈Z. Since {pρ/zρ:ρ⊢n} is a Q-basis of ΛQn and ch⁡(χλ)=∑ρχλ(ρ)pρ/zρ by definition, comparing coefficients gives χλ(ρ)=cλρ∈Z for every ρ⊢n.

5.1F4F7F9step 3.1step 4.1∎

The characters χλ are pairwise distinct irreducible characters of Sn and the irreducible characters are Z-linearly independent [F9]; since R(Sn) is by definition their integral span [F4], the family {χλ:λ⊢n} is a Z-basis of R(Sn). By [F7] the family {sλ:λ⊢n} is a Z-basis of Λn, and by step 3.1 the map ch⁡ carries the first basis bijectively onto the second; step 4.1 shows that all character values are integers.

CorollaryStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-6.1-sol)Open item page →

Irreducible symmetric-group character values are power-sum coefficients

Statement

For all λ,ρ⊢n,

χλ(ρ)=⟨sλ,pρ⟩H,

the coefficient of pρ/zρ in the power-sum expansion of sλ. Equivalently,

sλ=∑ρ⊢nχλ(ρ) pρzρ.

Facts & Assumptions

Given: An integer n≥0 and partitions λ,ρ⊢n.

[F1]

ch⁡(χλ)=sλ in Λn, where χλ is the character of the Specht module Sλ and all its values are integers (The characteristic of a Specht character is a Schur function).

[F2]

ch⁡(f)=∑σ⊢nf(σ)pσ/zσ for f∈cf(Sn), where zσ=∏iimi(σ)mi(σ)!>0 (The Frobenius characteristic map).

[F3]

The Hall form is the Z-bilinear form with ⟨hα,mβ⟩H=δαβ and Q-bilinear extension to ΛQ, and ⟨pσ,pρ⟩H=δσρzρ (The Hall inner product on symmetric functions, Power sums are orthogonal for the Hall form).

Proof

technique · direct
1.1F1F2

By [F1] and the definition of the characteristic [F2], sλ=ch⁡(χλ)=∑σ⊢nχλ(σ) pσ/zσ in ΛQn.

2.1F3step 1.1algebra

Pairing both sides of step 1.1 with pρ and using Q-bilinearity of the Hall form and the orthogonality ⟨pσ,pρ⟩H=δσρzρ of [F3], ⟨sλ,pρ⟩H=∑σ⊢nχλ(σ)zσ⟨pσ,pρ⟩H=χλ(ρ)zρ zρ=χλ(ρ).

3.1step 1.1step 2.1∎

Step 2.1 is the first displayed identity; step 1.1 exhibits χλ(ρ) as the coefficient of pρ/zρ in the expansion of sλ in the basis {pσ/zσ:σ⊢n} of ΛQn, which is the equivalent second display.

PropositionStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-6.1-sol)Open item page →

Sign twist corresponds to the omega involution

Statement

Let sgn⁡ be the sign representation of Sn and let V be a finite-dimensional complex representation of Sn with character χV and characteristic F=ch⁡(χV). Then

ch⁡(χV⊗sgn⁡)=ω(F),

where ω is the involutive algebra endomorphism of Λ with ω(er)=hr, extended to ΛC by complex linearity. In particular, for every λ⊢n,

ch⁡(χSλ⊗sgn⁡)=ω(sλ)=sλ′,

so Sλ⊗sgn⁡≅Sλ′ and χλ′(w)=(−1)n−ℓ(ρ)χλ(w) on elements of cycle type ρ.

Facts & Assumptions

Given: An integer n≥0, a finite-dimensional complex representation V of Sn with character χV, the sign representation sgn⁡, and w∈Sn of cycle type ρ⊢n with ℓ(ρ) parts.

[F1]

ch⁡(χ)=∑ρ⊢nχ(ρ)pρ/zρ for a character χ, where χ(ρ) is its value on cycle type ρ and zρ=∏iimi(ρ)mi(ρ)! (The Frobenius characteristic map).

[F2]

For finite-dimensional complex representations V,W of Sn one has χV⊗W(g)=χV(g)χW(g) for every g, where V⊗W is the tensor product representation with g⋅(v⊗w)=gv⊗gw (Characters add on direct sums, multiply on tensor products, and conjugate on duals, The tensor product of two complex representations).

[F3]

The sign representation of Sn is one-dimensional with σ⋅a=sgn⁡(σ)a; a k-cycle has sign (−1)k−1, and sgn⁡(w)=(−1)n−c(w), where c(w)=ℓ(ρ) is the number of cycles of w counted with fixed points (The sign representation of Sn and the restriction Res⁡HG(V) of a representation to a subgroup, A k-cycle has sign (−1)k−1, and sgn⁡(σ)=(−1)n−c(σ) when fixed points are counted as cycles).

[F4]

The Z-algebra endomorphism ω:Λ→Λ with ω(er)=hr is an involution and satisfies ω(pr)=(−1)r−1pr in ΛQ and ω(sλ)=sλ′ for every partition λ; it extends to a C-linear algebra endomorphism of ΛC (The omega involution conjugates Schur functions).

[F5]

ch⁡(χλ)=sλ for every λ⊢n, where χλ is the character of the Specht module Sλ (The characteristic of a Specht character is a Schur function).

[F6]

Two finite-dimensional complex representations of a finite group are isomorphic if and only if their characters are equal (Finite-dimensional complex representations of a finite group are determined up to isomorphism by their characters).

[F7]

The characteristic map is injective on cf(Sn) (The Frobenius characteristic is an isometry).

Proof

technique · direct
1.1F2F3

By [F2] and [F3], for w of cycle type ρ the tensor-product character is χV⊗sgn⁡(w)=χV(w)sgn⁡(w)=χV(ρ)(−1)n−ℓ(ρ).

1.2F4given

Since ω is a C-algebra endomorphism of ΛC [F4] and pρ=∏ipρi with ℓ(ρ) factors, ω(pρ)=∏iω(pρi)=∏i(−1)ρi−1pρi=(−1)∑i(ρi−1)pρ=(−1)n−ℓ(ρ)pρ.

2.1F1step 1.1

From the definition of the characteristic [F1] and step 1.1, ch⁡(χV⊗sgn⁡)=∑ρ⊢nχV⊗sgn⁡(ρ) pρ/zρ=∑ρ⊢nχV(ρ)(−1)n−ℓ(ρ) pρ/zρ.

2.2F1F4step 1.2

By C-linearity of ω [F4], [F1] and step 1.2, ω(F)=ω(∑ρ⊢nχV(ρ)pρ/zρ)=∑ρ⊢nχV(ρ)ω(pρ)/zρ=∑ρ⊢nχV(ρ)(−1)n−ℓ(ρ)pρ/zρ.

3.1step 2.1step 2.2

Steps 2.1 and 2.2 exhibit two equal expressions, so ch⁡(χV⊗sgn⁡)=ω(F) for every finite-dimensional complex representation V of Sn.

4.1F4F5step 3.1

Taking V=Sλ in step 3.1 and using [F5], ch⁡(χSλ⊗sgn⁡)=ω(sλ)=sλ′ by [F4].

5.1F5F6F7step 1.1step 4.1∎

Since ch⁡ is injective on cf(Sn) [F7] and ch⁡(χλ′)=sλ′ [F5], step 4.1 gives χSλ⊗sgn⁡=χλ′; by [F6] this equality of characters is equivalent to Sλ⊗sgn⁡≅Sλ′. Evaluating the character identity from step 1.1 for V=Sλ gives χλ′(w)=(−1)n−ℓ(ρ)χλ(w) for w of cycle type ρ.

PropositionStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-6.1-sol)Open item page →

The regular character has characteristic p1n

Statement

Let χreg be the regular character of Sn and let fλ:=dim⁡CSλ, the number of standard λ-tableaux (Standard polytabloids form a basis of a complex Specht module). Then

ch⁡(χreg)=p1 n,and expanding in the Schur basisp1 n=∑λ⊢nfλ sλ.

Facts & Assumptions

Given: An integer n≥0, the regular representation C[Sn] with character χreg, and the Specht modules Sλ with characters χλ and dimensions fλ=dim⁡CSλ.

[F1]

ch⁡(f)=∑ρ⊢nf(ρ)pρ/zρ for class functions f∈cf(Sn), with zρ=∏iimi(ρ)mi(ρ)! positive (The Frobenius characteristic map).

[F2]

χreg(1)=n!=∣Sn∣ and χreg(w)=0 for w≠1 (The regular character is ∣G∣ at 1 and 0 away from 1).

[F3]

C[Sn] is a finite-dimensional complex representation of the finite group Sn and is completely reducible, by Maschke's theorem applied to the characteristic-zero field C (Maschke's theorem for finite groups over fields whose characteristic does not divide ∣G∣).

[F4]

The modules {Sλ:λ⊢n} form a complete irredundant list, up to isomorphism, of the irreducible complex Sn-representations (Specht modules classify the complex irreducibles of Sn, Distinct complex Specht modules are inequivalent).

[F5]

If V≅⨁jmjVj with Vj a complete set of representatives of the irreducible representations and χj=χVj, then mj=⟨χV,χj⟩ (The multiplicity of an irreducible summand is a character inner product).

[F6]

The standard inner product is ⟨φ,ψ⟩=1n!∑w∈Snφ(w)ψ(w)‾ (The standard inner product on cf(G)).

[F7]

dim⁡CSλ=fλ, the number of standard λ-tableaux (Standard polytabloids form a basis of a complex Specht module).

[F8]

ch⁡(χλ)=sλ for every λ⊢n (The characteristic of a Specht character is a Schur function).

Proof

technique · direct
1.1F2given

By [F2], χreg vanishes except at the identity, whose cycle type is (1n); for that partition m1((1n))=n, so z(1n)=1n⋅n!=n!.

1.2F3F4F5F6

By [F3] the regular representation is completely reducible, and by [F4] its irreducible summands are copies of the Specht modules, so C[Sn]≅⨁λ⊢nmλSλ for nonnegative integers mλ; by [F5] and [F6] each multiplicity is mλ=⟨χreg,χλ⟩=1n!∑w∈Snχreg(w)χλ(w)‾, and [F2] reduces the sum to its identity term.

2.1F1step 1.1algebra

Substituting f=χreg into [F1] and using step 1.1, ch⁡(χreg)=∑ρ⊢nχreg(ρ)pρ/zρ=n! p(1n)/n!=p1 n, since p(1n)=p1n by the product convention for power sums.

2.2F5F6F7step 1.2algebra

By step 1.2, mλ=1n! n! χλ(1)‾=fλ, because χreg vanishes away from 1 and χλ(1)=dim⁡CSλ=fλ is a nonnegative integer by [F7], so it equals its conjugate. Hence χreg=∑λ⊢nfλχλ.

3.1F1F8step 2.1step 2.2algebra∎

Applying the linear map ch⁡ to step 2.2 and using [F8] gives p1 n=ch⁡(χreg)=∑λ⊢nfλch⁡(χλ)=∑λ⊢nfλsλ, the displayed Schur expansion.

The identity is a consistency check of the dictionary: it does not reprove the RSK sum-of-squares formula ∑λ(fλ)2=n!.

5 · Examples, counterexamples and false statements

None yet.

Sources