Alphabeta Math
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Mirror descent and adaptive regularization

1 · Prerequisites

2 · Logical flowchart

3 · Definitions, theorems and proofs

DefinitionDefinition: Literature-sourcedProof: Not applicableOpen item page →

Mirror maps, Bregman divergence, and local Hessian norms

Definition

Let d≥1, let K⊆Rd be a nonempty bounded closed convex set with nonempty interior, and let U⊆Rd be an open convex set such that int⁡(K)⊆U and K⊆U‾. If a decision set is lower-dimensional in an ambient Euclidean space, take Rd to be orthonormal affine coordinates on its affine hull (the smallest affine subspace containing it); thus interior, gradients, Hessians, and norms are relative to that affine hull. A mirror regularizer on (K,U) is a real-valued function R on K∪U that is continuous on K, twice continuously differentiable on U, agrees on K∩U, and has symmetric positive-definite Hessian HR(z):=∇2R(z) for every z∈U. We call R m-strongly convex on K in the Euclidean norm if, for some m>0, all x,y∈K and λ∈[0,1] satisfy

R((1−λ)x+λy)≤(1−λ)R(x)+λR(y)−m2λ(1−λ)∥x−y∥22.

For x∈K∪U and y∈U, the Bregman divergence generated by R is

BR(x∥y):=R(x)−R(y)−⟨∇R(y),x−y⟩.

For z∈U and vectors v,h∈Rd, define the squared local primal norm and local dual norm by

∥v∥z2:=v⊤HR(z)v,∥h∥∗,z2:=h⊤HR(z)−1h.

Definition references

A convex subset of Rm contains every line segment between two of its points: convexity means that every segment between points of the set lies in the set.

Convex and strictly convex functions on Euclidean convex sets: defines ordinary and strict convexity; the displayed quantitative inequality defines strong convexity locally here.

The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn: the pairing and norm are the standard Euclidean inner product and norm.

The Jacobian matrix of partial derivatives and the gradient in the scalar-valued case: ∇R is the vector of first partial derivatives.

The Hessian matrix and critical points of a scalar field: ∇2R is the Hessian matrix of second partial derivatives.

The metric topology: a set is open when every one of its points has a ball around it inside the set; closed means open complement: open and closed use the Euclidean metric topology.

Interior, closure, boundary, limit point, isolated point and dense subset of a metric space: int⁡(K) and U‾ are the interior and closure in that topology.

Bounded subset, diameter, distance from a point to a set, and distance between two sets in a metric space: boundedness uses the Euclidean metric.

LemmaStatement: Literature-sourcedProof: AI-generatedjudge pass (gpt-6-luna)Open item page →

A positive-semidefinite matrix has a unique positive-semidefinite square root

Statement

Let d≥1 and let G∈Rd×d be symmetric and positive semidefinite, meaning v⊤Gv≥0 for every v∈Rd. Then there is a unique symmetric positive-semidefinite matrix H such that H2=G. If G=Qdiag⁡(λ1,…,λd)Q⊤ is an orthogonal diagonalization, this root is H=Qdiag⁡(λ1,…,λd)Q⊤.

Statement references

Real spectral theorem: a self-adjoint endomorphism of a finite-dimensional real inner product space has an orthonormal eigenbasis: a real self-adjoint matrix has an orthonormal eigenbasis.

In orthonormal bases, the matrix of the adjoint is the conjugate transpose of the matrix: for a real Euclidean matrix, self-adjointness is symmetry.

Rectangular matrix multiplication and the identity matrix In, including zero-sized shapes: matrix products and transposes use ordinary finite-dimensional matrix algebra.

Matrix multiplication is associative, unital, distributive, and compatible with scalar multiplication: matrix multiplication is associative.

Square roots exist: a unique a≥0 with (a)2=a; the positives are {x2:x≠0}: every nonnegative real eigenvalue has a unique nonnegative scalar square root.

The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn: the quadratic form and orthogonality use the standard Euclidean inner product.

Facts & Assumptions

Given: A symmetric positive-semidefinite G∈Rd×d with d≥1.

[F1]

Real spectral theorem: a self-adjoint endomorphism of a finite-dimensional real inner product space has an orthonormal eigenbasis: a self-adjoint endomorphism of a finite-dimensional real inner-product space has an orthonormal eigenbasis.

[F2]

In orthonormal bases, the matrix of the adjoint is the conjugate transpose of the matrix: in an orthonormal real basis, the adjoint matrix is the transpose, so a symmetric matrix is self-adjoint.

[F3]

Rectangular matrix multiplication and the identity matrix In, including zero-sized shapes: products, powers, and transposes are the usual finite-dimensional matrix operations.

[F4]

Square roots exist: a unique a≥0 with (a)2=a; the positives are {x2:x≠0}: every real λ≥0 has a unique scalar r≥0 with r2=λ.

[F5]

The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn: v⊤w=⟨v,w⟩ and ∥v∥22=⟨v,v⟩ in standard orthonormal coordinates.

[F6]

Matrix multiplication is associative, unital, distributive, and compatible with scalar multiplication: matrix multiplication is associative and unital, so SS2=S2S and Q⊤Q=I for an orthogonal matrix Q.

[A1]

G is symmetric and satisfies v⊤Gv≥0 for all v∈Rd.

Proof

1.1givenA1F1F2F5choosealgebra

By [F1, F2], choose an orthogonal matrix Q whose columns are an orthonormal eigenbasis of G, so G=Qdiag⁡(λ1,…,λd)Q⊤. For each unit eigenvector qi, λi=qi⊤Gqi≥0 by [A1].

1.2givenA1F1F2F3F4F6algebra

Let S be any symmetric positive-semidefinite matrix with S2=G. By [F6], SG=SS2=S3=S2S=GS, so S preserves every eigenspace Eλ(G): if Gv=λv, then G(Sv)=S(Gv)=λSv. Its restriction to each Eλ(G) is symmetric and positive semidefinite. By [F1, F2] that restriction has an orthonormal eigenbasis; each eigenvalue μ satisfies μ≥0 and μ2=λ, hence [F4] forces μ=λ. Therefore S=λI on each Eλ(G).

2.1step 1.1F3F4F5F6constructalgebra

By [F4], choose ri=λi≥0 with ri2=λi, and set H=Qdiag⁡(r1,…,rd)Q⊤. This matrix is symmetric and, using [F6] and Q⊤Q=I, H2=Qdiag⁡(λ1,…,λd)Q⊤=G. For every v, v⊤Hv=∑iri(qi⊤v)2≥0, so H is positive semidefinite.

3.1step 1.1step 2.1step 1.2F1algebra∎

The eigenspaces in step 1.1 form an orthogonal basis of Rd, and step 1.2 shows that S and H act identically on every vector in that basis. Hence S=H, proving uniqueness.

LemmaStatement: Literature-sourcedProof: AI-generatedOpen item page →

The Bregman three-point identity

Statement

Let K⊆Rd, let U⊆Rd be open, and let R be a mirror regularizer whose Bregman divergence is BR(x∥y)=R(x)−R(y)−⟨∇R(y),x−y⟩ for x∈K∪U and y∈U. For a∈K∪U and b,c∈U,

⟨a−b,∇R(c)−∇R(b)⟩=BR(a∥b)−BR(a∥c)+BR(b∥c).

Statement references

Mirror maps, Bregman divergence, and local Hessian norms: defines BR(a∥b)=R(a)−R(b)−⟨∇R(b),a−b⟩ whenever a∈K∪U and b∈U.

Facts & Assumptions

Given: A mirror regularizer (K,U,R), a∈K∪U, and b,c∈U.

[F1]

Mirror maps, Bregman divergence, and local Hessian norms: BR(x∥y)=R(x)−R(y)−⟨∇R(y),x−y⟩ for x∈K and y∈U, with the same formula on U×U.

Proof

1.1givenF1algebra

Expand the right side using [F1]. The terms R(a), R(b), and R(c) cancel, leaving −⟨∇R(b),a−b⟩+⟨∇R(c),a−c⟩−⟨∇R(c),b−c⟩.

2.1step 1.1algebra∎

Since (a−c)−(b−c)=a−b, the remaining expression is ⟨a−b,∇R(c)−∇R(b)⟩.

LemmaStatement: Literature-sourcedProof: AI-generatedOpen item page →

Positive Hessians make Bregman divergence nonnegative

Statement

Let (K,U,R) be a mirror regularizer, and suppose R is m-strongly convex on K for some m>0. For x,y∈U,

BR(x∥y)≥0,

with strict inequality when x≠y. For x∈K and y∈K∩U,

BR(x∥y)≥m2∥x−y∥22.

Statement references

Mirror maps, Bregman divergence, and local Hessian norms: defines the Bregman formula, the positive-definite Hessian on U, and strong convexity on K.

Multivariable Taylor formula with a Lagrange remainder along a line segment: gives a second-order Taylor formula with a Hessian evaluated at an intermediate point of the segment.

Facts & Assumptions

Given: A mirror regularizer (K,U,R), a strong-convexity constant m>0 on K, and the points in the Statement.

[F1]

Mirror maps, Bregman divergence, and local Hessian norms: BR(x∥y)=R(x)−R(y)−⟨∇R(y),x−y⟩; R is C2 with positive-definite Hessian on open convex U, and its strong-convexity inequality holds on K.

[F2]

Multivariable Taylor formula with a Lagrange remainder along a line segment: for a C2 scalar function on open convex U and a,a+h∈U, some θ∈(0,1) gives R(a+h)=R(a)+⟨∇R(a),h⟩+12h⊤HR(a+θh)h.

Proof

1.1givenF1F2casesalgebra

For distinct x,y∈U, apply [F2] at a=y and h=x−y. By [F1], the remainder identity gives BR(x∥y)=12(x−y)⊤HR(y+θ(x−y))(x−y)>0, because the Hessian is positive definite and x−y≠0. If x=y, the defining formula gives BR(x∥y)=0. Thus the first claim holds.

1.2givenF1algebra

Fix x∈K and y∈K∩U, and put d=x−y. For 0<λ<1, strong convexity in [F1] gives R(y+λd)≤(1−λ)R(y)+λR(x)−m2λ(1−λ)∥d∥22. Rearranging yields R(x)−R(y)−[R(y+λd)−R(y)]/λ≥m2(1−λ)∥d∥22.

2.1step 1.2F1algebra∎

As λ↓0, y+λd lies in the open set U for all sufficiently small λ, and differentiability gives [R(y+λd)−R(y)]/λ→⟨∇R(y),d⟩. Taking the derivative limit in step 1.2 gives BR(x∥y)≥m2∥d∥22.

LemmaStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-6-luna)Open item page →

Negative entropy on the simplex is strongly convex and has range log n

Statement

Let n≥2. Coordinates in Rn−1 use the library's function-space convention: for v∈Rn−1 and 1≤i<n, write vi:=v(i−1). Let

Kn:={q∈Rn−1:qi≥0 for all 1≤i<n, ∑i=1n−1qi≤1},

and for q∈Kn put pi=qi for 1≤i<n and pn=1−∑i=1n−1qi. Define R(q)=∑i=1npilog⁡pi, with 0log⁡0:=0. In the independent coordinates q1,…,qn−1, R is continuous on Kn, is twice continuously differentiable on its interior, is 1-strongly convex in the Euclidean norm, and satisfies

−log⁡n≤R(q)≤0.

The minimum −log⁡n is attained at pi=1/n for every i, and the maximum 0 is attained at each vertex of the simplex.

Statement references

Mirror maps, Bregman divergence, and local Hessian norms: defines strong convexity by the displayed Euclidean quadratic inequality and defines the interior Hessian norms used by this regularizer.

A convex subset of Rm contains every line segment between two of its points: convexity means every segment between simplex points remains in the simplex.

Facts & Assumptions

Given: An integer n≥2 and the finite simplex Kn with the coordinates and boundary convention in the Statement.

[F1]

Mirror maps, Bregman divergence, and local Hessian norms: a regularizer is strongly convex with constant m when R((1−λ)x+λy)≤(1−λ)R(x)+λR(y)−m2λ(1−λ)∥x−y∥22; its Hessian is the matrix of second partial derivatives.

[F4]

Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm: log⁡ is continuous and strictly increasing, log⁡1=0, and log⁡(1/x)=−log⁡x for x>0.

[F5]

The natural logarithm is bounded above by its positive argument minus one: 0≤log⁡u≤u−1 for u≥1.

[F6]

A twice-differentiable function on an open interval is convex if and only if its second derivative is nonnegative: on an open real interval, a twice-differentiable scalar function is convex if its second derivative is nonnegative everywhere.

[F7]

Finite Jensen inequality for convex functions on Rn: for a convex scalar function and finitely many points in its convex domain, its value at a convex combination is at most the same combination of its values.

[F8]

A convex subset of Rm contains every line segment between two of its points: a set is convex when it contains every segment between its points; Kn is convex because its nonnegativity and sum-at-most-one inequalities are preserved by convex combinations.

Proof

1.1givenF3F4F5algebra

For 0<x≤1, set u=x−1/2≥1. Then ∣xlog⁡x∣=2xlog⁡u≤2x(u−1)≤2x by [F4, F5], and 2x→0 as x↓0. Thus s↦slog⁡s, defined to be 0 at s=0, is continuous on [0,1], and its finite sum R is continuous on Kn.

1.2givenF2F3algebra

On the interior, differentiation using [F2, F3] gives ∂iR=log⁡qi−log⁡pn and ∇2R(q)=diag⁡(1/q1,…,1/qn−1)+1pn11⊤. Since 0<qi≤1 and pn>0, v⊤(∇2R(q)−I)v=∑i<n(1/qi−1)vi2+(∑i<nvi)2/pn≥0.

2.1givenstep 1.2F1F6F8algebra

For interior q,r, [F8] keeps (1−s)q+sr in Kn. The restriction s↦R((1−s)q+sr)−12∥(1−s)q+sr∥22 has nonnegative second derivative on 0<s<1 by step 1.2, hence is convex there by [F6]; continuity extends its convexity inequality to s=0,1. Expanding the squared norm yields the strong-convexity inequality with constant 1 from the definition in [F1] for interior q,r.

2.2givenF2F3F6step 1.1algebra

Each pi∈[0,1] gives pilog⁡pi≤0, so R(q)≤0. The scalar function ϕ(s)=slog⁡s, extended by ϕ(0)=0, is continuous by step 1.1 and convex on (0,1) because ϕ′′(s)=1/s>0; [F6] and continuity extend convexity to [0,1].

3.1givenF1step 1.1step 2.1algebra

Let e be the uniform point of Kn. For arbitrary q,r∈Kn and 0<ϵ<1, both (1−ϵ)q+ϵe and (1−ϵ)r+ϵe are interior. Apply step 2.1 to them and let ϵ↓0; step 1.1 gives continuity, so the same inequality in [F1] holds for all q,r∈Kn.

4.1givenF4F7F8step 2.2algebra∎

Apply [F7] to p1,…,pn with equal weights 1/n. Since their average is 1/n, it gives R(q)/n≥ϕ(1/n)=−(log⁡n)/n, so R(q)≥−log⁡n. At the uniform point equality holds, while at a vertex the only nonzero summand is 1log⁡1=0; these attain both endpoints.

AlgorithmAlgorithm: Literature-sourcedProof: Not applicableOpen item page →

Gram-matrix AdaGrad with full or singular diagonal metrics

Definition

Let d≥1 be an integer and let K⊆Rd be nonempty, bounded, closed, and convex; let x1∈K, let T≥1 be an integer, and fix a step size η>0. Coordinate and matrix-entry subscripts in this procedure are one-based labels: for i,j∈{1,…,d}, write gi=g(i−1) and Gij=G(i−1,j−1) in the underlying zero-based Euclidean and matrix conventions, and use the same relabeling for the other vectors and matrices. Initialize G0=0. For each round t=1,…,T, play xt, then receive the full current loss information and its prescribed gradient vector gt∈Rd, and set

Gt=Gt−1+gtgt⊤=∑s=1tgsgs⊤.

The accumulated matrix Gt is symmetric and positive semidefinite. Choose either the full-matrix scale Ht=Gt1/2, the unique positive-semidefinite square root, or the diagonal scale Ht=diag⁡((Gt)11,…,(Gt)dd). Define Ht† to be the Moore–Penrose pseudoinverse and update

yt+1=xt−ηHt†gt,xt+1∈arg⁡min⁡x∈K(x−yt+1)⊤Ht(x−yt+1).

A minimizer exists; if it is not unique, select any minimizer. Return x1,…,xT. The matrix seminorm notation in the objective means ∥v∥Ht2=v⊤Htv. The diagonal scale here is formed by taking each diagonal entry of Gt and then its scalar square root; in general it is not diag⁡(Gt1/2). This is an update definition only and asserts no regret bound.

Definition references

AdaGrad accumulated Gram matrices and both scales are positive semidefinite ↗: proves the accumulated matrix is symmetric positive semidefinite and both full and diagonal scales are well-defined positive-semidefinite matrices.

Online decision protocol: the learner plays xt before receiving round-t feedback.

Adversary and feedback models: full-information feedback reveals the full current loss function after the choice. The prescribed gradient vector is an additional input explicitly required by this procedure.

The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn: vectors use the standard Euclidean inner product.

The Jacobian matrix of partial derivatives and the gradient in the scalar-valued case: gt is a vector in the standard coordinate basis.

A convex subset of Rm contains every line segment between two of its points: every segment between points of K lies in K.

The metric topology: a set is open when every one of its points has a ball around it inside the set; closed means open complement: closedness uses the Euclidean metric topology.

Bounded subset, diameter, distance from a point to a set, and distance between two sets in a metric space: boundedness uses the Euclidean metric.

Rectangular matrix multiplication and the identity matrix In, including zero-sized shapes: the outer product gtgt⊤ and matrix sums use ordinary finite-dimensional matrix multiplication.

In orthonormal bases, the matrix of the adjoint is the conjugate transpose of the matrix: for real Euclidean matrices, the adjoint matrix is the transpose.

Real spectral theorem: a self-adjoint endomorphism of a finite-dimensional real inner product space has an orthonormal eigenbasis: a real symmetric matrix admits an orthonormal eigenbasis.

Square roots exist: a unique a≥0 with (a)2=a; the positives are {x2:x≠0}: every nonnegative real has a unique nonnegative scalar square root.

The Moore--Penrose pseudoinverse A+ as the solution of the four Penrose equations: Ht† is the Moore–Penrose pseudoinverse, including for singular Ht.

Every finite real or complex matrix has a unique Moore--Penrose pseudoinverse: every finite-dimensional real matrix has a unique Moore–Penrose pseudoinverse.

A positive-semidefinite matrix has a unique positive-semidefinite square root: proves the unique symmetric positive-semidefinite matrix root from the real spectral theorem and scalar square roots.

LemmaStatement: Literature-sourcedProof: AI-generatedjudge pass (gpt-6-luna)Open item page →

AdaGrad accumulated Gram matrices and both scales are positive semidefinite

Statement

For the AdaGrad inputs, at each round t∈{0,…,T} the accumulated matrix Gt=∑s=1tgsgs⊤, with G0=0, is a finite real symmetric positive-semidefinite matrix. More precisely, for every v∈Rd, v⊤Gtv=∑s=1t(gs⊤v)2≥0,(Gt)ii=∑s=1tgs,i2≥0. Here the coordinate and matrix-entry labels i,j∈{1,…,d} are one-based: gs,i=gs(i−1) and (Gt)ij=Gt(i−1,j−1) in the underlying zero-based conventions. Empty sums have value zero. Therefore both the full-matrix scale Gt1/2 and the diagonal scale diag⁡((Gt)11,…,(Gt)dd) exist and are finite real symmetric positive-semidefinite matrices. Singular and zero accumulated matrices are allowed.

Statement references

Gram-matrix AdaGrad with full or singular diagonal metrics: defines the accumulated gradient outer products and the two choices of scale.

Facts & Assumptions

Given: Any finite gradient history g1,…,gt∈Rd admitted by AdaGrad, including t=0. Coordinate and matrix-entry subscripts use the one-based relabeling specified in the Statement.

[F1]

Gram-matrix AdaGrad with full or singular diagonal metrics: the accumulator is Gt=∑s=1tgsgs⊤; its full and diagonal scales are the two matrices in the Statement.

[F2]

Rectangular matrix multiplication and the identity matrix In, including zero-sized shapes The transpose AT of a matrix: finite matrix multiplication is given by sums of entrywise products, and transposition interchanges the two indices.

[F3]

Sign rules for products and monotonicity of multiplication: a square of a real number is nonnegative, by the positive, negative, and zero cases; a finite sum of such squares is nonnegative.

[F4]

A positive-semidefinite matrix has a unique positive-semidefinite square root: every real symmetric positive-semidefinite matrix has a unique real symmetric positive-semidefinite square root.

[F5]

Square roots exist: a unique a≥0 with (a)2=a; the positives are {x2:x≠0}: every nonnegative real number has a unique nonnegative real square root.

Proof

1.1givenF1F2algebra

Write gs,i for the ith coordinate of gs. By [F1, F2], (Gt)ij=∑s=1tgs,igs,j. These are finite real sums, and commutativity of real multiplication gives (Gt)ij=(Gt)ji. Thus Gt is finite and symmetric, also when t=0.

2.1step 1.1F2F3algebra

For arbitrary v∈Rd, expand v⊤Gtv by [F2] and interchange the finite sum over s with the two coordinate sums. For each s, the coordinate sums factor as (∑igs,ivi)(∑jgs,jvj)=(gs⊤v)2. Hence v⊤Gtv=∑s(gs⊤v)2≥0 by [F3], including the empty sum when t=0. Taking i=j in step 1.1 also gives (Gt)ii=∑sgs,i2≥0.

3.1step 1.1step 2.1F2F3F4F5algebra∎

Steps 1.1 and 2.1 verify every input hypothesis of [F4], which gives the unique full-matrix scale as a finite real symmetric positive-semidefinite matrix. By [F5], each ri=(Gt)ii exists and is a nonnegative finite real. The diagonal matrix D=diag⁡(r1,…,rd) is symmetric, and v⊤Dv=∑irivi2≥0 by [F2, F3]. Thus the diagonal scale has the same required properties, with no positive-definiteness assumption.

AlgorithmAlgorithm: Literature-sourcedProof: Not applicablejudge pass (gpt-6-luna)Open item page →

Agile online mirror descent

Definition

Let (K,U,R) be a mirror regularizer with R m-strongly convex on K for some m>0. Fix an integer horizon T≥1 and a step size η>0. Admissibility requires the unique minimizer of R on K to lie in U; initialize x1 at this minimizer. At each round t=1,…,T, play xt before observing the full current loss ft, with losses and gradients written in the same affine coordinates used for K. Use either of these feedback cases:

  1. ft is differentiable and convex on an open convex set containing K, and gt=∇ft(xt).
  2. ft is convex on a convex set containing K, and a supplied vector gt satisfies ft(u)≥ft(xt)+⟨gt,u−xt⟩ for every u∈K.

For each round require that there is a unique yt+1∈U satisfying

∇R(yt+1)=∇R(xt)−ηgt.

Set xt+1 to the minimizer of BR(x∥yt+1) over x∈K, and require this minimizer to lie in U so that the next dual update is defined. The Bregman minimizer exists and is unique under the stated strong-convexity and compactness hypotheses. Output the decisions x1,…,xT; the final xT+1 is the internal post-round iterate.

Definition references

Mirror maps, Bregman divergence, and local Hessian norms: gives the domains, strong-convexity condition, Bregman divergence, and Hessian notation.

Online decision protocol: the learner chooses using only the previous history before the round's current loss is observed.

Adversary and feedback models: full-information feedback reveals the current loss after the learner's choice.

A convex subset of Rm contains every line segment between two of its points: convex domains contain every segment between their points.

Convex and strictly convex functions on Euclidean convex sets: defines convexity of each loss function.

The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn: the pairing in the subgradient condition is the Euclidean inner product.

The Jacobian matrix of partial derivatives and the gradient in the scalar-valued case: ∇ft(xt) is the Euclidean gradient vector.

Subgradients and the subdifferential of a convex function: a supplied vector satisfying the stated supporting inequality is a subgradient at xt.

Differentiable convex functions are characterized by the gradient inequality: the smooth feedback case supplies the same supporting inequality for every comparator in K.

LemmaStatement: Literature-sourcedProof: AI-generatedjudge pass (gpt-6-luna)Open item page →

A singular AdaGrad metric still has a projection minimizer

Statement

Let d≥1, let K⊆Rd be nonempty, bounded, closed, and convex, let H be a fixed real positive-semidefinite matrix, and let y∈Rd. The function x↦(x−y)⊤H(x−y) attains a minimum on K. This conclusion allows H to be singular and makes no uniqueness claim.

Statement references

Gram-matrix AdaGrad with full or singular diagonal metrics: the AdaGrad update uses this quadratic objective with H=Ht and y=yt+1.

Facts & Assumptions

Given: A nonempty bounded closed convex K⊆Rd, a fixed positive-semidefinite matrix H, and y∈Rd.

[F1]

Gram-matrix AdaGrad with full or singular diagonal metrics: the metric projection objective is Q(x)=(x−y)⊤H(x−y), with H positive semidefinite; its minimizer may be nonunique.

[F2]

The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn: ∥v∥22=∑i=1dvi2, so each coordinate satisfies ∣vi∣≤∥v∥2.

[F3]

Upper and lower semicontinuity on subsets of Rn: every continuous real-valued function on a Euclidean subset is lower semicontinuous there.

[F4]

Semicontinuous extreme value theorem on compact Euclidean sets: a real-valued lower semicontinuous function on a nonempty compact Euclidean set attains its minimum.

Proof

1.1givenF5

By [F5], the nonempty closed bounded set K is compact.

1.2givenF1F2algebrachoose

Since K is bounded, choose B<∞ with ∥x∥2≤B for every x∈K, and put M=B+∥y∥2. For x,z∈K, expanding the finite matrix products and factoring each difference gives Q(x)−Q(z)=∑i,j=1dHij((xi−zi)(xj−yj)+(zi−yi)(xj−zj)). Thus ∣Q(x)−Q(z)∣≤2M(∑i,j∣Hij∣)∥x−z∥2, by [F2]; hence Q is continuous on K.

2.1step 1.1step 1.2F3F4∎

By [F3], Q is lower semicontinuous on K. Apply [F4] to the nonempty compact set in step 1.1 to obtain a minimizer. No step requires H to be invertible, and the argument does not distinguish or select a unique minimizer.

LemmaStatement: Literature-sourcedProof: AI-generatedjudge pass (gpt-6-luna)Open item page →

The diagonal AdaGrad scale is the coordinatewise square root

Statement

For the diagonal AdaGrad choice Ht=diag⁡((Gt)11,…,(Gt)dd) with Gt=∑s=1tgsgs⊤, the ith diagonal entry is

(Ht)ii=∑s=1tgs,i2,i=1,…,d.

Statement references

Gram-matrix AdaGrad with full or singular diagonal metrics: defines the accumulated Gram matrix and the diagonal AdaGrad scale.

Rectangular matrix multiplication and the identity matrix In, including zero-sized shapes: defines the coordinate formula for matrix products.

In orthonormal bases, the matrix of the adjoint is the conjugate transpose of the matrix: identifies the transpose entries used in the outer product.

Facts & Assumptions

Given: The vectors g1,…,gt∈Rd and the diagonal-scale definition in the statement.

[F1]

Gram-matrix AdaGrad with full or singular diagonal metrics: Gt=∑s=1tgsgs⊤ and Ht=diag⁡((Gt)11,…,(Gt)dd) for the diagonal choice.

[F2]

Proof

1.1givenF1F2algebra

For each i, the definition of matrix multiplication gives (Gt)ii=∑s=1t(gsgs⊤)ii=∑s=1tgs,igs,i=∑s=1tgs,i2.

2.1step 1.1F1algebra∎

Taking the nonnegative scalar square root of the identity in step 1.1 and using the diagonal-scale definition in [F1] gives (Ht)ii=∑s=1tgs,i2 for every i.

LemmaStatement: Literature-sourcedProof: AI-generatedjudge pass (gpt-6-luna)Open item page →

Compactness makes the Bregman projection well-defined

Statement

Let d≥1, let K⊆Rd be nonempty, bounded, closed, and convex, and let (K,U,R) be a mirror regularizer with R m-strongly convex on K for some m>0. Then R has a unique minimizer on K, and for every y∈U the function x↦BR(x∥y) has a unique minimizer x+(y) on K. If x+(y)∈U, then for every u∈K,

⟨∇R(x+(y))−∇R(y),u−x+(y)⟩≥0

and

BR(u∥y)≥BR(u∥x+(y))+BR(x+(y)∥y).

Statement references

Agile online mirror descent: uses a minimizer of R to initialize and a minimizer of BR(⋅∥y) for each dual point y.

Mirror maps, Bregman divergence, and local Hessian norms: gives continuity of R on K, the strong-convexity inequality, and the Bregman formula.

The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn: the strong-convexity inequality uses the standard Euclidean norm.

The Bregman three-point identity: states the algebraic identity used for the Pythagorean inequality.

Upper and lower semicontinuity on subsets of Rn: continuity implies lower semicontinuity on a Euclidean subset.

Facts & Assumptions

Given: The set K, the mirror regularizer (K,U,R), its strong-convexity constant m>0, and any fixed y∈U.

[F1]

Agile online mirror descent: K is bounded, closed, and convex, R is strongly convex on K, and the Bregman projection minimizes BR(x∥y) over x∈K.

[F2]

Mirror maps, Bregman divergence, and local Hessian norms: R is continuous on K, and BR(x∥y)=R(x)−R(y)−⟨∇R(y),x−y⟩ for x∈K, y∈U.

[F4]

Semicontinuous extreme value theorem on compact Euclidean sets: every real-valued lower semicontinuous function on a nonempty compact Euclidean set attains its minimum.

[F5]

A convex subset of Rm contains every line segment between two of its points: every segment between two points of K lies in K.

[F6]

The Bregman three-point identity: for u∈K and x,y∈U, ⟨u−x,∇R(y)−∇R(x)⟩=BR(u∥x)−BR(u∥y)+BR(x∥y).

[F7]

Upper and lower semicontinuity on subsets of Rn: a continuous real-valued function on a Euclidean subset is lower semicontinuous there.

Proof

1.1givenF2F3F4F7

By [F3], K is compact. Continuity of R on the nonempty set K and [F7] make it lower semicontinuous; [F4] then implies that R attains a minimum on K.

1.2givenF2F5algebra

Suppose x+(y)∈U and fix u∈K. The segment from x+(y) to u lies in K by [F5], and because U is open it remains in U for all sufficiently small nonnegative segment parameters. Since x+(y) minimizes BR(⋅∥y), the right derivative at zero of s↦BR(x+(y)+s(u−x+(y))∥y) is nonnegative. Differentiating its defining formula at s=0 gives ⟨∇R(x+(y))−∇R(y),u−x+(y)⟩≥0.

2.1step 1.1F1F5algebra

If two distinct points minimized R, their midpoint would lie in K by [F5]. The strong-convexity inequality at λ=1/2 would make its value at least m∥x−y∥22/8 below the common minimum, a contradiction. Thus the minimizer is unique.

3.1givenstep 2.1F1F2F3F4F7algebra

For fixed y∈U, the formula in [F2] writes BR(x∥y) as the continuous function R(x) plus an affine function of x. It is therefore lower semicontinuous by [F7] and attains a minimum on compact K by [F3, F4]. If two distinct points minimized it, the affine term would cancel from the strong-convexity inequality for R, giving the same strict midpoint contradiction as in step 2.1. Hence its minimizer x+(y) is unique.

4.1step 1.2F6algebra∎

Apply [F6] with x=x+(y). Step 1.2 makes its left side nonpositive, so BR(u∥x+(y))−BR(u∥y)+BR(x+(y)∥y)≤0. Rearranging proves the stated Pythagorean inequality.

TheoremStatement: AI-adaptedProof: AI-generatedOpen item page →

A corrected regret bound for agile mirror descent

Statement

Let d≥1 and let (K,U,R) be a mirror regularizer on K⊆Rd, with K nonempty, bounded, closed, and convex, U open and convex, positive-definite Hessian on U, and R m-strongly convex on K for some m>0. Let T≥1 be an integer and η>0. Let x1∈K∩U minimize R on K. For every t=1,…,T, suppose xt,xt+1∈K∩U, yt+1∈U, and

∇R(yt+1)=∇R(xt)−ηgt,xt+1∈arg⁡min⁡x∈KBR(x∥yt+1).

For each t, let either ft be differentiable and convex on an open convex set containing K with gt=∇ft(xt), or let ft be convex on a convex set containing K with ft(u)≥ft(xt)+⟨gt,u−xt⟩ for every u∈K. Define the pointwise regret by RT(u):=∑t=1T(ft(xt)−ft(u)). For each t, there exists zt on the segment [xt,yt+1] such that

2BR(yt+1∥xt)=∥xt−yt+1∥zt2.

For every comparator u∈K,

RT(u)≤R(u)−R(x1)η+η2∑t=1T∥gt∥∗,zt2.

The range diameter DR2:=max⁡x,y∈K(R(x)−R(y)) is finite, and DR:=DR2. If DR>0, GR>0, and ∥gt∥∗,zt≤GR for all t, then η=DR/(GRT) gives RT(u)≤32DRGRT. Minimizing the corrected right-hand expression over η>0 instead gives η=2DR/(GRT) and RT(u)≤2DRGRT.

Statement references

Agile online mirror descent: defines the agile dual update, the Bregman projection, the full-information timing, and the optional supplied-subgradient branch.

Mirror maps, Bregman divergence, and local Hessian norms: defines BR, the local primal/dual Hessian norms, and strong convexity on K.

Static, dynamic, interval, and strongly adaptive regret: defines pointwise regret against a fixed comparator u∈K.

A convex subset of Rm contains every line segment between two of its points: convexity of K supplies the segments used in the minimizer and projection arguments.

Convex and strictly convex functions on Euclidean convex sets: defines convexity of the loss functions.

The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn: defines the pairings and Euclidean norms in the local Hessian calculations.

The Jacobian matrix of partial derivatives and the gradient in the scalar-valued case: defines each loss gradient as its standard-coordinate partial-derivative vector.

Differentiable convex functions are characterized by the gradient inequality: the smooth loss case gives the supporting inequality used in the proof.

Subgradients and the subdifferential of a convex function: defines the supplied supporting vector in the nonsmooth case.

The Bregman three-point identity: provides the algebraic identity that converts the dual step into a potential difference.

Positive Hessians make Bregman divergence nonnegative: provides the nonnegative potential terms used when telescoping.

Compactness makes the Bregman projection well-defined: establishes existence/uniqueness and the projection variational and Pythagorean inequalities.

Multivariable Taylor formula with a Lagrange remainder along a line segment: supplies the intermediate Hessian point zt on each update segment.

Facts & Assumptions

Given: The mirror regularizer, horizon, step size, iterates, update equations, loss conditions, and comparator in the Statement.

[A1]

At every round xt,xt+1∈K∩U, yt+1∈U, the agile gradient identity holds, and xt+1 minimizes BR(⋅∥yt+1) on K.

[A2]

The initial point x1∈K∩U minimizes R on K.

[A3]

At each round, either the differentiable convex gradient condition or the explicitly stated supporting-subgradient condition holds for every comparator in K.

[A4]

DR>0, GR>0, and ∥gt∥∗,zt≤GR for every t when the tuned corollaries are invoked.

[F1]

Mirror maps, Bregman divergence, and local Hessian norms: BR(a∥b)=R(a)−R(b)−⟨∇R(b),a−b⟩; for z∈U, HR(z) is positive definite and ∥v∥z2=v⊤HR(z)v, ∥h∥∗,z2=h⊤HR(z)−1h.

[F2]

The Bregman three-point identity: ⟨a−b,∇R(c)−∇R(b)⟩=BR(a∥b)−BR(a∥c)+BR(b∥c) for a∈K∪U and b,c∈U.

[F3]

Positive Hessians make Bregman divergence nonnegative: BR(a∥b)≥0 for a,b∈U, and BR(a∥b)≥m2∥a−b∥22 for a∈K, b∈K∩U.

[F4]

Agile online mirror descent: ∇R(yt+1)=∇R(xt)−ηgt and xt+1 is the Bregman minimizer.

[F5]

Compactness makes the Bregman projection well-defined: for every u∈K, BR(u∥yt+1)≥BR(u∥xt+1)+BR(xt+1∥yt+1).

[F6]

Differentiable convex functions are characterized by the gradient inequality: if ft is differentiable and convex on an open convex domain containing K, then ft(xt)−ft(u)≤⟨∇ft(xt),xt−u⟩.

[F7]

Subgradients and the subdifferential of a convex function: in the supplied-subgradient branch, ft(xt)−ft(u)≤⟨gt,xt−u⟩ for every u∈K by the stated supporting inequality.

[F8]

Multivariable Taylor formula with a Lagrange remainder along a line segment: for R∈C2(U) and xt,yt+1∈U, some θt∈(0,1) gives the second-order Taylor formula at xt along yt+1−xt.

[F9]

Static, dynamic, interval, and strongly adaptive regret: pointwise regret against u is ∑t(ft(xt)−ft(u)).

[F11]

Semicontinuous extreme value theorem on compact Euclidean sets: a continuous real-valued function on a nonempty compact Euclidean set attains both its minimum and maximum.

[F12]

A convex subset of Rm contains every line segment between two of its points: for x,y∈K and s∈[0,1], (1−s)x+sy∈K.

[F13]

Convex and strictly convex functions on Euclidean convex sets: a loss is convex when its value on a segment is at most the corresponding affine combination of endpoint values.

[F14]

The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn: the Euclidean pairing is ⟨v,w⟩=∑iviwi and its norm is induced by that inner product.

[F15]

The Jacobian matrix of partial derivatives and the gradient in the scalar-valued case: ∇ft(xt) is the standard-coordinate vector of partial derivatives.

Proof

1.1givenA3F6F7F13F15cases

In either loss case [F6] or [F7] gives ft(xt)−ft(u)≤⟨gt,xt−u⟩ for every u∈K; the loss convexity convention is [F13], and gradients are the vectors in [F15].

1.2givenF1F8caseschoosealgebra

Apply [F8] to R along the segment from xt to yt+1. If xt≠yt+1 it gives zt=xt+θt(yt+1−xt)∈U and BR(yt+1∥xt)=12(xt−yt+1)⊤HR(zt)(xt−yt+1); if the two points coincide, choose zt=xt and both sides are zero. Thus the stated intermediate-point identity holds.

1.3givenA1F1algebra

Put dt=xt−yt+1. Expanding the two Bregman terms by [F1] gives BR(xt∥yt+1)+BR(yt+1∥xt)=⟨∇R(xt)−∇R(yt+1),dt⟩=η⟨gt,dt⟩ by [A1].

1.4givenF1F10F11choosealgebra

By [F10], K is compact; by [F1], R is continuous there; hence [F11] gives M=max⁡KR and m0=min⁡KR. Every difference R(x)−R(y) is at most M−m0, and points attaining M and m0 attain this difference, so DR2=M−m0 is finite and nonnegative.

2.1step 1.2step 1.3F1F14algebracases

Let A=HR(zt), a=∥gt∥∗,zt, and b=∥dt∥zt. For every real λ, positive definiteness gives 0≤(dt−λA−1gt)⊤A(dt−λA−1gt)=b2−2λ⟨gt,dt⟩+λ2a2, with the pairing from [F14]. If a>0, substitute λ=⟨gt,dt⟩/a2 to get ⟨gt,dt⟩2≤a2b2; if a=0, positive definiteness of A−1 forces gt=0. In either case ⟨gt,dt⟩≤ab. By steps 1.2 and 1.3, BR(xt∥yt+1)=η⟨gt,dt⟩−b2/2≤ηab−b2/2≤η2a2/2, the last inequality following from (b−ηa)2≥0.

3.1step 1.1step 2.1A1F2F3F4F5algebra

Use [F2] with a=u, b=xt, and c=yt+1, together with [A1], to write η⟨gt,xt−u⟩=BR(u∥xt)−BR(u∥yt+1)+BR(xt∥yt+1). Apply [F5] to the middle potential and [F3] to BR(xt+1∥yt+1); then apply step 2.1. With step 1.1 this gives η(ft(xt)−ft(u))≤BR(u∥xt)−BR(u∥xt+1)+η22∥gt∥∗,zt2.

4.1step 3.1F3F9algebra

Sum step 3.1 over t. The Bregman terms telescope, and [F3] gives BR(u∥xT+1)≥0 because u∈K and xT+1∈K∩U. Divide by η>0 to obtain RT(u)≤BR(u∥x1)/η+(η/2)∑t=1T∥gt∥∗,zt2.

5.1givenA2F1F9F12step 4.1algebra

For fixed u∈K, [F12] puts the segment x1+s(u−x1) in K, and R has a minimum at s=0. Since x1∈U, the right derivative is ⟨∇R(x1),u−x1⟩≥0. The Bregman identity gives R(u)−R(x1)=BR(u∥x1)+⟨∇R(x1),u−x1⟩≥BR(u∥x1). Substitute in step 4.1 to prove the pointwise bound.

6.1step 1.4step 5.1A4algebra∎

For every u∈K, R(u)−R(x1)≤DR2. Under [A4], step 5.1 gives RT(u)≤DR2/η+ηTGR2/2. Substituting η=DR/(GRT) gives 32DRGRT. For arbitrary η>0, the difference between DR2/η+ηTGR2/2 and 2DRGRT is (DR/η−GRTη/2)2≥0. Equality holds when DR2/η=ηTGR2/2, that is, η=2DR/(GRT). This proves the optimized corrected bound.

Remarks

The unhalved initial potential and the η/2 local-norm term are essential. The original planned η/4 term and [R(u)−R(x1)]/(2η) initial term, together with its DRGRT corollary at η=DR/(GRT), are false. Their exact original clause and a complete admissible one-round refutation are preserved in fs-mirror-descent-halved-regret-constants. The corrected 2DRGRT optimized constant here is attained by that quadratic witness at η=1.

False statementConstruction: AI-adaptedVerification: AI-generatedjudge pass (gpt-6-luna)Open item page →

Halving both terms in the agile mirror-descent regret bound

Statement

Let d≥1, let K⊆Rd be nonempty, bounded, closed and convex with nonempty interior, and let U be an open convex set containing int⁡K, with K⊆U‾. Let R be continuous on K, twice continuously differentiable with positive-definite Hessian on U, and strongly convex on K. Initialize x1∈K∩U at a minimizer of R on K. For an integer T≥1 and a constant η>0, run the well-defined agile update ∇R(yt+1)=∇R(xt)−ηgt,xt+1∈arg⁡min⁡x∈KBR(x∥yt+1), with xt,xt+1∈K∩U, yt+1∈U, and gt=∇ft(xt) for differentiable convex losses on an open convex neighborhood of K. Define BR(x∥y)=R(x)−R(y)−⟨∇R(y),x−y⟩. For each t, choose an intermediate point zt∈[xt,yt+1] satisfying 2BR(yt+1∥xt)=(xt−yt+1)⊤∇2R(zt)(xt−yt+1) and put ∥gt∥∗,t2=gt⊤[∇2R(zt)]−1gt.

The following two assertions hold for every comparator u∈K:

  1. The pointwise regret RT(u)=∑t=1T(ft(xt)−ft(u)) satisfies RT(u)≤η4∑t=1T∥gt∥∗,t2+R(u)−R(x1)2η.
  2. If DR2=max⁡x,y∈K(R(x)−R(y)), DR=DR2>0, and GR>0 bounds ∥gt∥∗,t, then the choice η=DR/(GRT) gives RT(u)≤DRGRT.

Facts & Assumptions

Given: The two universal assertions and all their hypotheses in the Statement.

[F1]

Agile online mirror descent: the initial decision minimizes R on K; the agile step solves ∇R(y)=∇R(x)−ηg and then minimizes BR(⋅∥y) over K.

[F2]

Mirror maps, Bregman divergence, and local Hessian norms: the oriented divergence is R(x)−R(y)−⟨∇R(y),x−y⟩, and the local dual squared norm is g⊤[∇2R(z)]−1g.

Refutation

1.1givenconstructalgebra

Set d=T=1, K=[0,1], U=R, R(x)=x2/2, x1=0, f1(x)=−x, g1=−1, and comparator u=1. The interval is nonempty, bounded, closed and convex with nonempty interior; U is open and convex. The regularizer is continuous and C2 on R, with Hessian 1. The identity R((1−λ)x+λy)=(1−λ)R(x)+λR(y)−λ(1−λ)(x−y)2/2 proves 1-strong convexity, and 0 uniquely minimizes R on K. The loss is differentiable and affine, hence convex, with gradient −1 everywhere. All regularizer, initialization and loss hypotheses hold.

2.1step 1.1F1F2algebra

For any 0<η≤1, [F1] gives y2=η, since ∇R(x)=x. By [F2], BR(x∥y)=(x−y)2/2, which has its unique minimum on K at x2=y2=η. Thus every update is well-defined and the required iterates lie in K∩U. Also 2BR(y2∥x1)=η2=(x1−y2)2∇2R(z) for every z on the segment, and ∥g1∥∗,1=1. Taking GR=1 is admissible.

3.1step 1.1step 2.1algebra

The one-round regret against u=1 is f1(0)−f1(1)=1, independently of the internal post-round iterate. At η=1, the first assertion's right side is 1/4+(R(1)−R(0))/2=1/4+1/4=1/2. Thus its claimed inequality would be 1≤1/2, which is false.

3.2step 1.1step 2.1algebra

The maximum difference of regularizer values on [0,1] is R(1)−R(0)=1/2, so DR=1/2. The second assertion's prescribed step is η=DR/(GRT)=1/2, which belongs to (0,1] and therefore gives a valid trajectory by step 2.1. Its claimed regret bound is DRGRT=1/2<1, whereas the regret is still 1. This separately refutes the tuned assertion.

4.1step 3.1step 3.2algebra∎

Both original conclusions fail under their stated hypotheses. The same witness also shows sharpness of the corrected constants: at η=1 the unhalved potential bound is (R(1)−R(0))/η+(η/2)∥g1∥∗,12=1, and the optimized corrected expression 2DRGRT is also 1. Thus retaining the full correct bound resolves the false constants without losing the comparator, local-norm or optimized-rate conclusions.

Remarks

The original canonical ML-67 clause is retained verbatim in the repair packet's original-false-clause.md, with its exact substring hash and controlling-plan source recorded in original-clause-record.json. The local positive theorem supplies a complete proof with the initial term divided by η and the accumulated local-norm term multiplied by η/2. At the original prescribed step its valid rate is 3DRGRT/2; optimizing gives 2DRGRT. This refutation does not alter any update rule or assert an AdaGrad convergence rate.

4 · Examples, counterexamples and false statements

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