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Shelah's Baire-Property Model and Inner-Model Lower Bounds — Examples

1 · Prerequisites

2 · Summary

The examples display the concrete computations behind the two branches. Under its displayed matched-width hypothesis, the universal-meagre example grafts the finitely many sections of an old nowhere-dense tree onto distinct sections of a stronger witness tree, assigns the resulting prefix permutations their indices in the canonical enumeration, and shows that the direct extension forces the old body into a finite subunion of the generic meagre envelope. The general assertion is supplied by the absorption lemma, and the example also includes an unconditional level-by-level display for the singleton {0ω}. The Raisonnier example produces the cofinite tails as members of F(x) from the cylinder covers of the constructible reals, and the capture example computes the tail intersections Nf for the constant block function and verifies that the capture indices 0φU(n) are eventual rather than pointwise. The sweet-amalgam example instantiates the amalgamation, modulus, class and complete embedding data for two sweet models over a common complete subalgebra.

The false statement records the exact contrast between the two regularity properties: ZFC alone suffices for the relative consistency of the all-Baire-property model, while universal measurability is equiconsistent with an inaccessible, and a single relative model satisfies the first without the second. It makes no separate claim that one bare consistency statement cannot imply another.

3 · Logical flowchart

4 · Definitions, theorems and proofs

None yet.

5 · Examples, counterexamples and false statements

ExampleConstruction: Literature-sourcedVerification: AI-adaptedaudited 2026-09-22Open item page →

A universal-meagre stage absorbs an old nowhere-dense tree

Example

Let S be an old perfect nowhere-dense binary tree and let (t,T) be a UM condition. The absorption lemma gives a direct extension whose generic F-sigma code contains [S]. When the two trees have a level beyond t at which the witness tree has at least as many nodes as S, the extension has the explicit finite graft below. The singleton closed nowhere-dense set {0ω} has a separate one-node perfect graft, displayed level by level below; its prefix tree is not called perfect. Below the distinguished weakest condition, first take the explicit nontrivial condition of the UM definition.

Verification

Given: A condition (t,T) of UM and an old perfect nowhere-dense tree S, with the generic tree UG of Shelah's universal-meagre forcing.

[F1] Shelah's universal-meagre forcing: conditions, order, and the containment of every witness tree of a generic condition in the generic tree.

[F2] A universal-meagre generic absorbs old nowhere-dense sets: the meagre envelope is formed from a fixed canonical enumeration (πm)m<ω of all finite-prefix rearrangements of the generic tree.

[F3] Trees and their bodies: tree bodies and prefix closure; the section and graft formulas are verified below.

[F4] Nowhere dense, meagre, residual, and comeagre subsets of a topological space: nowhere density means that the closure has empty interior; a finite union of closed nowhere-dense sets is closed nowhere dense, since any cylinder can be refined successively to avoid each of the finitely many sets.

1.1

For the explicit matched-width case, fix a level n>ht(t) satisfying T2nS2n; this is an additional hypothesis for the display, not a consequence of perfection. Write S2n={s1,,sk} and choose distinct η1,,ηkT2n.

F1
1.2

Let T be the set of all nodes of T together with all nodes ηiτ for tails τ satisfying siτS, together with their initial segments; that is, replace the prefix si by ηi rather than concatenate the full old word. Prefixes shorter than n already lie in T. Then T is a tree containing T, its recorded initial tree through height ht(t) is t, it is perfect because the nodes of T keep their splitting extensions and each ηi inherits the splitting of the perfect tree S below si, and it is nowhere dense because its body is the union of the nowhere-dense set [T] with the finitely many homeomorphic images of the closed nowhere-dense sets [S][si]. Hence (t,T) is a direct extension of (t,T).

F1F3
1.3

For every x[S] there is exactly one i with 1ik and x[si]. Let ρi be the full level-n permutation swapping ηi with si (the identity if they agree) and leaving all other level words and all subsequent tail bits unchanged. Since [F2] fixes an enumeration of every finite-prefix rearrangement, define mi to be the least m with πm=ρi. Then ρi1(x)[ηi][T][UG], because the graft is recorded in the witness tree T and every witness tree of a condition in the generic filter is contained in the generic tree. Hence xπmi([UG]), and the condition (t,T) forces [S]1ikπmi([UG]), a finite subunion of the countable meagre envelope of the absorption lemma.

F2F4step 1.2
2.1

Singleton case displayed level by level: for A={0ω}, choose n>ht(t), a node ηT2n, and let Z={σ2<ω:(j)(2j<σσ(2j)=0)}. Its body contains 0ω, has arbitrarily late free odd coordinates and is nowhere dense because a later even coordinate can be set to 1; graft Z below η, so T=T{ησ:σZ}. At every level mn the graft contributes the nodes ησ with σ=mn (some may already belong to T). The body remains nowhere dense by the finite-union argument of step 1.2; no same-level sibling of η is required. The full prefix permutation swapping 0n and η sends the grafted branch η0ω[UG] to 0ω, so 0ωπ([UG]), and this single finite substitution is the whole code at this stage.

F1F4step 1.2
3.1

The general existence assertion is the exact content of [F2]. Under the additional matched-width hypothesis, steps 1.1--1.3 exhibit the finite graft explicitly, and step 2.1 supplies the unconditional singleton instance. No claim is made that perfection alone yields the width comparison or that the generic tree itself contains every old tree.

F2step 1.1step 1.3step 2.1
ExampleConstruction: Literature-sourcedVerification: Literature-sourcedaudited 2026-09-22Open item page →

Cylinder covers generate the Frechet tails in the Raisonnier filter

Example

For fixed n, enumerate the finitely many length-n binary strings s and use their cylinders [s] as a countable cover of L[x]2ω. Any two distinct reals in one cylinder first differ at a coordinate at least n. Hence ωn belongs to F(x), concretely demonstrating that F(x) extends the Fréchet filter.

Verification

Given: A real x, a natural number n, and the Raisonnier family F(x) of the definition item.

[F1] Rapid filters and the Raisonnier family: cylinders, the first-difference function and the defining cover criterion for F(x).

1.1

Let s0,,s2n1 enumerate all binary strings of length n in the canonical order and put Fi=[si] for i<2n, padded by empty sets for i2n. Every real in L[x]2ω extends exactly one of the listed strings, so L[x]2ωiFi; this is a countable cover of the required kind.

F1
2.1

If uv both lie in one cylinder [s] with s=n, then u and v agree on all coordinates below n. Their first differing coordinate is therefore at least n, so the prefix length defined by [F1] satisfies h(u,v)n+1, and in particular iH(Fi){k:kn}=ωn.

F1step 1.1
3.1

Therefore ωnF(x) by the defining cover criterion, for every n<ω, so F(x) contains the Fréchet filter.

F1step 2.1
3.2

The case n=0 is included: the unique length-0 string has cylinder 2ω, every pair of distinct reals in it has first differing prefix length at least 1, and the cover is the single set 2ω padded by empty sets, giving ω=ω0F(x).

step 2.1
4.1

The steps above exhibit the cofinite tails as members of F(x) through explicit cylinder covers, which is the claim.

step 3.1step 3.2
ExampleConstruction: Literature-sourcedVerification: Literature-sourcedaudited 2026-09-22Open item page →

Uniform null capture for a constant block function

Example

For the constant function f(n)=0, the uniform capture lemma assigns a null Gδ set Nf. Whenever an open U of measure below one contains Nf, the associated finite capture sets satisfy 0φU(n) for all sufficiently large n.

Verification

Given: The constant function f:ωω, f(n)=0, and an open set UNf of coin measure below one.

[F1] Uniform null G-delta sets capture block functions: for every fωω there is a uniformly assigned null Gδ set Nf, and if an open U of measure below one contains Nf, then the finite capture sets satisfy f(n)φU(n) for all sufficiently large n.

1.1

Apply [F1] to the constant function f(n)=0. It supplies the uniformly assigned set Nf and says directly that Nf is a null Gδ.

F1
1.2

Since the given U is open, has measure below one, and contains Nf, the capture clause of [F1] gives f(n)φU(n) for all sufficiently large n. Because f(n)=0 for every n, this is exactly 0φU(n) eventually.

F1
2.1

Thus [step 1.1] gives the claimed null Gδ, and [step 1.2] gives the claimed eventual, rather than pointwise, capture of the constant function.

step 1.1step 1.2
False statementConstruction: AI-adaptedVerification: AI-adaptedaudited 2026-09-22Open item page →

False: the all-Baire-property model needs an inaccessible

Statement

False: an inaccessible-cardinal hypothesis is needed as an upper-bound assumption to establish the relative consistency of a model of ZF+DC in which every set of reals has the Baire property. In fact Con(ZFC) already implies the consistency of that theory, whereas making every set of reals Lebesgue measurable is equiconsistent with an inaccessible cardinal. This refutes the claimed need for that stronger hypothesis; it does not assert the separate metatheoretic negation of Con(ZF+DC+all BP)Con(ZFC+an inaccessible).

Facts & Assumptions

Given: The equiconsistency theorems of this pair and the separation theorem.

[F1]

The exact equiconsistency of ZFC and the all-Baire-property model: the equiconsistency of ZFC with ZF+DC plus universal Baire property.

[F2]

Exact equiconsistency of universal measurability and an inaccessible: the equiconsistency of universal measurability with an inaccessible.

[F3]

Shelah's model separates universal Baire property from universal measurability: the separating model with Baire property but not measurability.

Refutation

1.1

The claim under refutation is the usual relative-consistency assertion that an inaccessible-cardinal hypothesis is needed to obtain the all-Baire-property model. To refute that requirement it suffices to produce the model relative to ZFC alone. This reading is weaker than, and must not be replaced by, the formal assertion that the target theory's consistency disproves the consistency of ZFC plus an inaccessible.

givenF1
1.2

By The exact equiconsistency of ZFC and the all-Baire-property model, the theory ZF+DC plus "every set of reals has the Baire property" is equiconsistent with ZFC alone: in particular, Con(ZFC)Con(ZF+DC+all BP). The construction therefore needs no inaccessible-cardinal assumption, which refutes the requirement fixed in step 1.1. Equiconsistency with ZFC by itself does not prove that the target consistency fails to imply the consistency of a stronger theory, and no such claim is used here.

F1step 1.1
1.3

The comparison with measurability is a separate calibration: by Exact equiconsistency of universal measurability and an inaccessible, universal Lebesgue measurability is equiconsistent with ZFC plus an inaccessible cardinal. This fact neither supplies a separating model nor, by itself, proves a strict nonimplication between the two bare consistency statements; no such inference is made here.

F2
1.4

The semantic separation is also witnessed: by Shelah's model separates universal Baire property from universal measurability there is, relative to Con(ZFC), a model of ZF+DC in which every set of reals has the Baire property and some set of reals is not Lebesgue measurable. This shows that the two regularity assertions themselves separate; it is not offered as a proof that one formal consistency statement fails to imply another.

F3
2.1

Steps 1.2 and 1.3 refute the alleged need to assume an inaccessible in the relative-consistency construction and identify the established equiconsistency calibrations; step 1.4 supplies the semantic contrast. No lower bound for measurability transfers to the Baire property, and no unproved nonimplication between bare consistency statements is asserted.

step 1.2step 1.3step 1.4
ExampleConstruction: Literature-sourcedVerification: Literature-sourcedaudited 2026-09-22Open item page →

Amalgamating two sweet models over a common complete subalgebra

Example

Let (P1,D1,En1) and (P2,D2,En2) be sweetness models whose complete Boolean algebras share a common complete subalgebra B0, with B0 contained in BA(P1) and in BA(P2). Then the amalgam P1B0P2 is sweet: below each admitted pair in the canonical dense set there is a least admission modulus, and the equivalence relations obtained by shifting the two factor relations by that modulus have countably many downward-directed classes and satisfy the sweetness diagonal and transfer clauses. The canonical embeddings of P1 and P2 into the amalgam are complete, and BA(P1B0P2) is ccc because every sweet forcing is ccc.

Verification

Given: Sweetness models (P1,D1,En1) and (P2,D2,En2), named complete embeddings of the complete algebra B0 into both Boolean completions, and the positive forcing P0=B0{0} with those two images identified.

[F1] Shelah sweetness models for forcing: the sweetness clauses and the extension relation.

[F2] Sweet density transfers along complete suborders: the two-part uniformity and density conclusion of Claim 7.4 used to synchronize the quotient witnesses in both coordinates.

[F3] Shelah amalgamation preserves sweetness: the amalgam classes and the denseness of the amalgam data.

[F4] Sweet forcings are countable unions of directed sets and ccc: completeness of suborders and the sigma-directed decomposition.

1.1

The amalgam data are those of [F3]: O=P1P0P2 consists of the pairs admitted by a common positive B0-condition and is ordered coordinatewise. Its canonical dense subset is D={(q1,q2)O:qD for =1,2}. The denseness assertion already includes the synchronization of the two quotient witnesses; it is not inferred from coordinatewise denseness alone.

F2F3
1.2

For x=(q1,q2)D, let m(x) be the least m such that every pair (q1,q2) with qEmq is admitted. Existence is the double application of [F2] in the proof of [F3]: a countable directed cover of P0 is used first for P1 and then, after retaining the dense subfamily below the admission witness, for P2. Two reductions in the same directed piece have a common strengthening and hence admit the perturbed pair. The least number m(x) depends only on the two equivalence classes and admission, not on a chosen witness.

F2F3
1.3

No partial-isomorphism extension theorem is needed. The theorem [F3] applies directly to the two named complete embeddings of the arbitrary common complete subalgebra B0. The weak-coordinate maps give complete canonical copies of both factors in the full amalgam, independently of whether those canonical conditions belong to the selected dense presentation D.

F3
2.1

If x=(q1,q2) has qEm(x)q in both coordinates, then the relevant factor classes are unchanged and minimality gives m(x)=m(x). Hence [F3] defines xEnxm(x)=m(x)=:m  and  q1Em+n1q1  and  q2Em+n2q2. These relations refine with n, have countably many classes, and every class is downward directed. In particular every two members of one En-class are compatible. The diagonal and transfer assertions are the coordinatewise sweetness clauses combined with the same common-admission property; they are not consequences of pairwise compatibility alone.

F1F3step 1.2
2.2

The canonical embeddings are complete by the exact conclusion of [F3]; no countable-generation hypothesis on B0 is present in that theorem.

F3step 1.1
3.1

Countable chain condition: the amalgam is sweet by [F3] and step 2.1, and a sweet forcing is a countable union of directed sets, hence ccc by [F4].

F3F4step 2.1
4.1

The steps above exhibit the intrinsic least modulus, the En-classes, the two canonical complete embeddings and the ccc conclusion for the amalgam over an arbitrary common complete subalgebra, verifying the claimed instance.

step 2.1step 2.2step 3.1

Sources