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TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-09-01
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The Euclidean tubular neighbourhood theorem

Statement

Let SRm be an embedded smooth submanifold. Then there is a positive smooth function δ:S(0,) such that the restricted normal addition map E:ΩδRm,Ωδ:={(p,v)NS:v<δ(p)}, is a diffeomorphism onto an open neighbourhood of S. In particular, S has a tubular neighbourhood in Rm.

Facts & Assumptions

Given: An embedded smooth submanifold SRm.

[L1]

The model map in this statement is the normal addition map (The normal addition map for a Euclidean submanifold).

[L2]

Normal addition is a local diffeomorphism along the zero section and is injective on a sufficiently small smooth variable-radius neighbourhood (Normal addition is a local diffeomorphism along the zero section, Variable-radius injectivity for normal addition).

[L3]

Smooth partitions of unity exist on manifolds (Smooth partitions of unity exist on manifolds).

Proof

technique · direct
1.1

If S=, take the unique function δ:S(0,). Then Ωδ=, and E is a diffeomorphism from the empty manifold onto the open neighbourhood of S. Hence assume S.

L1given
2.1

Let W be the union of all normal-bundle neighbourhoods on which [L2] makes E a local diffeomorphism. It is open and contains the zero section. By shrinking bundle trivializations around their base points, choose an open cover (Ui) of S and numbers ri>0 such that {(p,v):pUi, v<ri}W. By [L3], choose a locally finite smooth partition (ϕi) subordinate to this cover.

L2L3step 1.1choose
3.1

Define r(p):=(iϕi(p)ri)1. The locally finite sum is smooth and positive. At each p, the finite nonempty set I(p):={i:ϕi(p)>0} has an index i0 with ri0=maxiI(p)ri. Since r(p)ri0 and psupp(ϕi0)Ui0, the whole fibre ball v<r(p) over p lies in W.

L3step 2.1algebra
4.1

Let δ0:S(0,) be the positive smooth injectivity radius supplied by [L2], and put δ(p):=δ0(p)r(p)δ0(p)+r(p). This function is positive and smooth, with δ<δ0 and δ<r.

L2step 3.1constructalgebra
5.1

The set Ωδ is open in NS because (p,v)vδ(p) is continuous. Since δ<r, step 3.1 gives ΩδW, so E is a local diffeomorphism at every point of Ωδ. Since δ<δ0, [L2] also makes E injective on Ωδ.

L2step 3.1step 4.1
6.1

A local diffeomorphism is open. Hence U:=E(Ωδ) is open and contains S because E(p,0)=p. The injective local diffeomorphism E:ΩδU is a homeomorphism, and its local smooth inverses agree and assemble to a smooth global inverse. Thus E is the required diffeomorphism. Together with the empty case in step 1.1, this proves the theorem.

L1step 1.1step 5.1

Depends on

Used by

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Sources