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Vassiliev invariants and chord diagrams — Examples and Counterexamples

1 · Prerequisites

2 · Logical flowchart

3 · Definitions, theorems and proofs

None yet.

4 · Examples, counterexamples and false statements

CounterexampleConstruction: Literature-sourcedVerification: AI-adaptedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Writhe is not an unframed knot invariant

Statement refuted

For every oriented knot diagram D, the writhe w(D)=∑csgn⁡(c), with sgn⁡(c)=sgn⁡det⁡(vover,vunder) in the oriented projection plane with positive viewing normal, is unchanged by unframed Reidemeister moves and therefore defines an unframed finite-type invariant of type at most 1.

Diagram

The picture is a local Reidemeister I pair: the vertical branch passes over the horizontal branch in the one-crossing curl, while the rest of the knot is unchanged.

D0D1

At the single crossing of D1, the vertical over-tangent points down and the horizontal under-tangent points right, so the determinant convention gives sign +1.

Facts & Assumptions

Given: The two oriented diagrams in the counterexample below, and the sign convention in the refuted statement.

[F1]

Each oriented Reidemeister move is realized by an ambient isotopy: each local oriented Reidemeister I move is realized by an ambient isotopy of the represented oriented link.

[F2]

Singular knots and Vassiliev derivatives: a finite-type invariant must first be an invariant of ambient-isotopy classes of oriented knots.

[F3]

Oriented crossing signs, diagram writhe, and blackboard framing: writhe is the sum of the crossing signs, with the determinant convention stated in the refuted statement.

Counterexample

Let D0 be a crossing-free diagram of the oriented unknot and let D1 be obtained from it by inserting one positive Reidemeister I curl. Both diagrams represent the same oriented unknot. The writhe values are w(D0)=0 and w(D1)=1.

1.1givenF1

By [F1], D0 and D1 represent the same unframed oriented knot, since they differ by one oriented Reidemeister I move.

2.1givenF2F3step 1.1algebra∎

The diagram D0 has no crossings, so w(D0)=0. The diagram D1 adds exactly one positive crossing and leaves all other crossings absent, so w(D1)=+1 by [F3]. Therefore writhe is not constant on the ambient-isotopy class of the unknot; by [F2] it cannot be an unframed finite-type knot invariant.

ExampleConstruction: Literature-sourcedVerification: AI-adaptedverified 2026-10-22 (gpt-6.1-sol)Open item page →

The degree-one derivative of linking number

Example

Assume ACω. For an oriented two-component link L=L1∪L2, let lk⁡(L1,L2) be one half the sum of the signs of all crossings between distinct components, using sgn⁡det⁡(vover,vunder) in the oriented projection plane with positive viewing normal. Extend the singular finite-difference formula to links by resolving marked crossings independently. At one marked mixed crossing, the positive-minus-negative derivative of lk⁡ is +1; reversing the order of those two resolutions gives −1. A marked self-crossing has derivative 0. At any two distinct marked crossings, mixed or self, the second derivative is 0, so linking number is a type-at-most-one invariant of two-component links and, by the nonzero first derivative, has exact type one. The total pairwise linking number of a one-component knot is 0, because the defining sum over distinct component pairs is empty.

Facts & Assumptions

Given: The crossing-sign convention and the two-component oriented-link linking-number formula in the Example statement. The topological invariance of this quantity uses the separate ACω supplier branch.

[F1]

Singular knots and Vassiliev derivatives: link finite differences are the alternating sums over independent marked-crossing resolutions.

[F2]

Oriented crossing signs, diagram writhe, and blackboard framing: a crossing sign is sgn⁡det⁡(vover,vunder); a positive crossing has sign +1 and a negative crossing has sign −1.

[F3]

Compute oriented linking number from a diagram: on a two-component diagram the linking-number algorithm returns one half of the signed sum of mixed crossings.

[F4]

The diagram linking-number scan terminates and returns the stated integer: under ACω, the finite diagram scan terminates and returns the integer linking number.

[F5]

Linking number is invariant and writhe changes under a kink: under ACω, the algorithmic linking number is unchanged by oriented Reidemeister moves and hence is invariant under ambient isotopy.

[A1]

The Axiom of Countable Choice (ACω): ACω asserts that every sequence of nonempty sets has a choice function; only the topological supplier chain [F4]–[F5] uses it.

Verification

1.1givenA1F1F2F3F4F5algebra

Let C be half the signed sum of all mixed crossings except the marked one. Under [A1], [F4] identifies the diagram half-sum with the integer linking number and [F5] makes it an ambient-isotopy invariant. By [F2] and [F3], the positive and negative resolutions contribute respectively +12 and −12 to this linking number, so lk⁡(L1,L2)+−lk⁡(L1,L2)−=(C+12)−(C−12)=1. This is the stated positive-minus-negative derivative under [F1]; reversing that subtraction changes its sign.

1.2givenalgebra

A knot has one component and therefore no unordered pair of distinct components; the total pairwise linking sum contains no terms and equals 0.

2.1givenA1F1F2F3F4step 1.1algebra∎

If both marked crossings are mixed, write their resolution signs as ϵ1,ϵ2∈{+1,−1} and absorb every other mixed crossing into C. By [F2]–[F4], lk⁡(Lϵ1,ϵ2)=C+12(ϵ1+ϵ2). The alternating second difference is zero: the constant has coefficient 1−1−1+1=0, and each term linear in one ϵi cancels when the other sign is summed. If either marked crossing is a self-crossing, the link formula [F3] is independent of that resolution, so the alternating sum over its two choices cancels term by term. Thus D2=0 for every pair of marked crossings by [F1].

Sources