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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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✓ 3 results · all verified · 2 also independently AI-judged
Every result on this page is machine-checked by a proof checker and read in full and owner-audited; the judge is an additional, independent cross-model AI review of the proofs. The 1 not AI-judged were verified by owner audit (typically over a confirmed judge false positive), not failures.

Semiparametric Models and Tangent Spaces

1 · Prerequisites

2 · Summary

This page builds semiparametric score geometry from common-dominated paths that are differentiable in quadratic mean. It proves score mean-zero and uniqueness, defines the tangent set and its closed linear span separately, and fixes the nuisance tangent space by designated paths with zero right derivative of the target. It also records the nuisance orthogonal complement in the mean-zero L2(P) Hilbert space. Countable Choice is the exact assumption used for L2 completeness; the broader likelihood-density convention retains its separate Axiom-of-Choice dependency. One-sided boundary score cones remain distinct from their linear tangent spaces.

3 · Logical flowchart

4 · Definitions, theorems and proofs

DefinitionDefinition: AI-adaptedProof: Not applicablejudge pass (gpt-6-luna)Open item page →

Mean-zero square-integrable functions

Definition

Let P be a probability measure on (X,A). Here L2(P) is the real space of square-integrable measurable functions modulo equality P-almost surely, with its usual quotient norm (The space Lp(μ) as the quotient by null functions, The Lp norm descends to the quotient and makes Lp a normed space for 1≤p≤∞). For f∈L2(P), the integral Pf:=∫f dP is finite and independent of the representative: Cauchy–Schwarz on the probability space gives ∫∣f∣ dP≤∥f∥2, and the expectation of integrable representatives is invariant under almost-sure equality (Cauchy-Schwarz inequality for L2, Expectation depends only on the almost-everywhere class).

Define the mean-zero square-integrable space by

L02(P):={f∈L2(P):Pf=0}.

It carries the norm inherited from L2(P). Countable Choice is not needed for this definition; a later local Hilbert-space argument uses it only to inherit completeness from the library's general L2 Hilbert-space result.

DefinitionDefinition: Literature-sourcedProof: Not applicablejudge pass (gpt-6-luna)Open item page →

A dominated differentiable-in-quadratic-mean submodel

Definition

Let M be a model of probability measures on a measurable space (X,A), let ϵ>0, and let t↦Pt∈M be a path for 0≤t<ϵ with P0=P. It is dominated by a common measure when one supplied sigma-finite positive measure μ satisfies Pt≪μ for every t (Dominated statistical experiments). Write pt=dPt/dμ and p=p0 for simultaneously supplied nonnegative density versions; the existence and normalization of each density are the Radon–Nikodym properties in Likelihood densities and A sigma-finite signed measure that is absolutely continuous with respect to a sigma-finite positive measure has a unique almost-everywhere density. The Axiom of Choice is the library convention for selecting such a family of versions along a path (The Axiom of Choice). The DQM property below is unchanged by replacing any pt by another version, since each L2(μ) norm is unchanged by a μ-null modification.

The path is differentiable in quadratic mean at 0, with score s∈L2(P), when

∥pt−p−t2sp∥L2(μ)=o(t)(t↓0).

Here o(t) means that the displayed norm divided by t tends to 0 as t↓0; L2(P) and L2(μ) are quotient spaces modulo almost-everywhere equality (The space Lp(μ) as the quotient by null functions). The definition is directional. A two-sided regular submodel qualifies by restricting it to t≥0. No mean-zero condition is assumed in this definition.

TheoremStatement: AI-adaptedProof: AI-adaptedprecheck passjudge pass (gpt-6-luna)Open item page →

The mean-zero L² space is a Hilbert space

Statement

Assume Countable Choice (The Axiom of Countable Choice (ACω)). For any probability measure P, the space L02(P) of Mean-zero square-integrable functions is a closed real linear subspace of real L2(P) with pairing ⟨f,g⟩P:=∫fg dP; consequently it is a real Hilbert space (Hilbert space). The only choice use is the Countable Choice assumption already required by the general L2(P) completeness supplier.

Facts & Assumptions

Given: Countable Choice and a probability measure P on (X,A).

[A1]

Countable Choice is the stated selection principle (The Axiom of Countable Choice (ACω)).

[F1]

Under Countable Choice, real L2(P) with pairing ⟨f,g⟩=∫fg dP is a complete real inner-product space (L2 with the integral pairing is a Hilbert space).

[F2]

Cauchy–Schwarz in an inner-product space gives ∣⟨f,g⟩∣≤∥f∥∥g∥ (Cauchy–Schwarz: ∣⟨x,y⟩∣≤∥x∥ ∥y∥, with equality exactly for dependent pairs).

[F3]

L02(P)={f∈L2(P):Pf=0}, with Pf well-defined on equivalence classes (Mean-zero square-integrable functions).

Proof

technique · Identify the mean-zero space as the kernel of the continuous expectation functional
1.1F1F2F3algebra

The constant function 1 belongs to L2(P) and has norm 1, since P(X)=1. For each f∈L2(P), the pairing in [F1] satisfies Pf=⟨f,1⟩P, so [F2] gives ∣Pf∣≤∥f∥2. Thus f↦Pf is a bounded linear functional, and its kernel is exactly L02(P) by [F3].

2.1step 1.1F1F3

The kernel is linear. If fn∈L02(P) and fn→f in L2(P), then ∣Pf∣=∣P(f−fn)∣≤∥f−fn∥2→0 by step 1.1 and linearity of the pairing [F1], so f∈L02(P). Hence the kernel is closed.

3.1A1F1step 2.1∎

Every Cauchy sequence in L02(P) is Cauchy in L2(P), which is complete by [F1] under the Countable Choice assumption [A1]; its L2(P) limit lies in L02(P) by step 2.1. The restricted inner product is therefore complete, proving the asserted Hilbert-space property.

TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-6-luna)Open item page →

A DQM score has mean zero and is unique

Statement

Assume the density-version convention for the path in A dominated differentiable-in-quadratic-mean submodel. If s∈L2(P) is a DQM score, then Ps=0, so s∈L02(P) (Mean-zero square-integrable functions). Moreover, any two scores satisfying the same DQM expansion agree P-almost surely. The normalization argument itself uses no choice beyond the density versions already supplied in the definition.

Facts & Assumptions

Given: A common-dominated probability path Pt through P=P0, with density versions pt and a DQM score s∈L2(P).

[F1]

DQM means ∥pt−p−(t/2)sp∥L2(μ)=o(t) as t↓0 (A dominated differentiable-in-quadratic-mean submodel).

[F2]

A Radon–Nikodym density pt represents Pt by Pt(E)=∫Ept dμ for every measurable E (A sigma-finite signed measure that is absolutely continuous with respect to a sigma-finite positive measure has a unique almost-everywhere density).

[F3]

The L2 pairing is finite and satisfies Cauchy–Schwarz (Cauchy-Schwarz inequality for L2).

[F4]

The Lebesgue integral is linear on L1(μ) (The Lebesgue integral is linear on L1(μ)).

Proof

technique · Expand the squared norm and use normalization of the path
1.1F1F2

Put q=p, qt=pt, and rt=qt−q−(t/2)sq. By [F1], ∥rt∥2=o(t), while [F2] gives ∥q∥22=∫p dμ=1 and ∥qt∥22=∫pt dμ=1.

1.2F1algebra

If s′ is another score with remainder rt′=oL2(t), subtracting its expansion from [F1] gives ∥(t/2)(s−s′)q∥2≤∥rt∥2+∥rt′∥2=o(t).

2.1step 1.1F3F4algebra

Set ut=(t/2)sq+rt. Since ∥sq∥22=∫s2p dμ=Ps2<∞, we have ∥ut∥2=O(t) and qt=q+ut. The products qrt and ut2 are integrable by [F3]. Pointwise expansion and linearity [F4] give 0=∫(q+ut)2dμ−∫q2dμ=t Ps+2∫qrt dμ+∥ut∥22. By [F3], ∣∫qrt dμ∣≤∥q∥2∥rt∥2=o(t) and ∥ut∥22=O(t2)=o(t). Dividing by t>0 and taking t↓0 gives Ps=0.

3.1step 1.2step 2.1algebra∎

Divide by t/2 and let t↓0. Then ∥(s−s′)q∥22=P[(s−s′)2]=0, so s=s′ as an element of L2(P). Together with step 2.1 this proves mean zero and uniqueness.

DefinitionDefinition: Literature-sourcedProof: Not applicablejudge pass (gpt-6-luna)Open item page →

Tangent set of a statistical model at a law

Definition

Fix a model M containing a law P and designate a collection of allowed submodels through P. Each allowed submodel is a one-sided DQM path as in A dominated differentiable-in-quadratic-mean submodel. Its score is the P-almost-sure equivalence class proved unique by A DQM score has mean zero and is unique, and it belongs to L02(P) (Mean-zero square-integrable functions).

The tangent set M˙(P) is the set of scores of the designated paths. The model specification determines which paths are allowed. In particular, the tangent set need not be a linear space: it may be a cone, meaning it is closed under multiplication by nonnegative real scalars, while failing closure under negative scalars. One-sided restrictions can produce this behavior. The closed linear span of the tangent set is a separate construction.

DefinitionDefinition: Literature-sourcedProof: Not applicablejudge pass (gpt-6-luna)Open item page →

Closed tangent space

Definition

Assume Countable Choice (The Axiom of Countable Choice (ACω)) so that L02(P) is the real Hilbert space established by The mean-zero L² space is a Hilbert space. For a tangent set M˙(P)⊆L02(P), its linear span is the set of all finite real linear combinations of elements of M˙(P); the span of the empty set is {0}. Its tangent space T(P) is the closure of that span in the L2(P) norm. The closure consists of limits of sequences from the span, equivalently of points every positive-radius norm ball around which meets the span.

The tangent set itself is retained separately and may be a cone rather than a vector space.

TheoremStatement: AI-adaptedProof: AI-adaptedprecheck passOpen item page →

A tangent space is a closed linear subspace

Statement

Assume Countable Choice. Let M˙(P) be any tangent set in the real Hilbert space L02(P). Its tangent space T(P), defined as the norm closure of its finite real linear span (Closed tangent space), is a closed linear subspace of L02(P) (Linear subspace of a vector space).

Facts & Assumptions

Given: Countable Choice, a probability law P, and a tangent set M˙(P)⊆L02(P).

[A1]

Countable Choice is the selection principle required by the general L2(P) completeness supplier (The Axiom of Countable Choice (ACω)).

[F1]

The tangent space is the norm closure of all finite real linear combinations of tangent-set scores (Closed tangent space).

[F2]

Under Countable Choice, L02(P) is a complete real inner-product space (The mean-zero L² space is a Hilbert space).

[F3]

A linear subspace is a subset containing the zero vector and closed under addition and real scalar multiplication (Linear subspace of a vector space).

Proof

technique · Prove the closure is linear, closed, and complete in the inherited norm
1.1F1F3algebra

Let V be the finite real span in [F1]. By collecting coefficients of each score, the sum of two finite linear combinations is another finite linear combination; scalar multiples have the same form, and 0 is the empty sum. Thus V is a linear subspace by [F3].

1.2F1algebra

If x∉V‾, some r>0 has B(x,r)∩V=∅. For any y with ∥y−x∥2<r/2, the triangle inequality gives B(y,r/2)⊂B(x,r), so y∉V‾. Hence the complement of V‾ is open and V‾ is closed.

2.1step 1.1F1algebra

Write V‾=T(P). If x,y∈V‾ and ε>0, choose u,v∈V with ∥x−u∥2<ε/2 and ∥y−v∥2<ε/2. Then u+v∈V and ∥(x+y)−(u+v)∥2<ε, so x+y∈V‾. For a∈R, if a=0 then ax=0∈V; if a≠0, choose u∈V with ∥x−u∥2<ε/∣a∣, giving au∈V and ∥ax−au∥2<ε. Thus V‾ is linear.

3.1F2A1step 1.2step 2.1∎

A Cauchy sequence in V‾ converges in L02(P) by [F2] under [A1]. Since V‾ is closed by step 1.2, that limit lies in V‾. Therefore the tangent space is complete as well as a closed linear subspace, as asserted.

DefinitionDefinition: Literature-sourcedProof: Not applicableOpen item page →

Nuisance tangent space

Definition

Assume Countable Choice (The Axiom of Countable Choice (ACω)), as required by the ambient Hilbert-space and tangent-space conventions. Let M be a model through P, let ψ:M→Rk be a specified finite-dimensional parameter-of-interest functional, and let the model designate its nuisance submodels. A nuisance submodel is a designated allowed DQM path t↦Pt through P for which the right derivative lim⁡t↓0(ψ(Pt)−ψ(P))/t exists and is the zero vector in Rk. Its score belongs to the tangent set M˙(P) (Tangent set of a statistical model at a law).

The nuisance tangent space Tη(P) is the norm closure in L02(P) of the finite real linear span of scores of nuisance submodels. It is a closed linear subspace by Closed tangent space and A tangent space is a closed linear subspace. The designated nuisance submodels are part of the model specification; this definition does not assert that every path with zero first-order target derivative is nuisance unless the model designates it as such.

DefinitionDefinition: Literature-sourcedProof: Not applicableOpen item page →

Orthogonal complement of a nuisance tangent space

Definition

Assume Countable Choice (The Axiom of Countable Choice (ACω)), so that L02(P) is the real Hilbert space of The mean-zero L² space is a Hilbert space. The orthogonal complement of the nuisance tangent space within L02(P) is

Tη(P)⊥:={h∈L02(P):⟨h,g⟩P=0 for every g∈Tη(P)},⟨h,g⟩P:=P(hg).

This is the ordinary orthogonal complement from Orthogonality and the orthogonal complement applied in the mean-zero Hilbert space, not in all of L2(P). It is a closed linear subspace by Orthogonal complements are closed.

5 · Examples, counterexamples and false statements

None yet.

Sources