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Perfect stress and particle balances with entropy identity

1 · Prerequisites

2 · Summary

This page derives the energy and spatial projections of a perfect stress balance, the corresponding particle and entropy identities, and the local Carter–Lichnerowicz circulation relation. It then proves an exact entropy production formula for a frame-decomposed dissipative stress and particle current. The final lemma gives a nonnegative first-order entropy residual and two conditional model limitations: instantaneous tails for the Fourier branch and a growing homogeneous Eckart mode. Each conclusion is mathematical and conditional on its stated smooth fields, constitutive equations, and supplier interfaces; no nonlinear evolution or empirical applicability is inferred.

3 · Logical flowchart

4 · Definitions, postulates, theorems and proofs

LemmaStatement: AI-adaptedProof: AI-generatedjudge pass (gpt-6-luna)Open item page →

Perfect stress and particle balances with entropy identity

Statement

Let (M,g,N) be a smooth time-oriented Lorentzian four-manifold of signature (−,+,+,+), let ∇ be its metric-compatible torsion-free connection, and let u be a smooth future-directed vector field with g(u,u)=−1. Put Δab=gab+uaub, D=ua∇a, θ=∇aua, ab=ua∇aub, and Δba=δba+ubua. Take a smooth fixed-composition state from Rest fluid state, frame and geometric current definitions with n>0, T>0, s=nσp, and h=ϵ+p=Ts+μn as in Local Gibbs, Euler, parcel first law and response identities. Define the perfect stress tensor and particle current by

Tab=ϵuaub+pΔab,Ja=nua.

For any smooth vector field fb, the balance equation ∇aTab=fb is equivalent to the pair

Dϵ+hθ=−ubfb,hac+Δca∇ap=Δcbfb,

and ∇aJa=0 is equivalent to Dn+nθ=0. Whenever both balances hold, the exact entropy identities are

T∇a(sua)=−ubfb,nTDσp=−ubfb.

In particular, when f=0, the entropy current su is divergence-free and specific entropy is advected, Dσp=0. These are conditional identities for supplied smooth fields; they assert no solution existence or physical applicability beyond the stated model data.

Facts & Assumptions

Given: A nonempty open set O in a smooth time-oriented Lorentzian four-manifold (M,g,N) of signature (−,+,+,+); a smooth future unit field u on O; a C2 state map into a nonempty open material-state domain; and the fields and balances specified in the Statement.

[A1]

The geometric and tensor-bundle construction carries Countable Choice ACω (The Axiom of Countable Choice (ACω)); no stronger choice principle is assumed.

[F1]

Smooth time-oriented Lorentzian four-manifolds: the geometric objects of the model: M is a smooth four-manifold without boundary, g is a smooth symmetric nondegenerate metric of signature (−,+,+,+), and N selects the future cone. Its stated tangent-bundle construction assumes only ACω.

[F2]

Rest fluid state, frame and geometric current definitions: on a nonempty open set O, the observer field is smooth and future unit timelike; a local state has a nonempty open domain X⊂(0,∞)×R, a specified e∈C2(X), and a C2 state map (v,σp):O→X. It defines n=v−1, s=nσp, ϵ=ne, T=eσp, p=−ev, H=e+pv, h=ϵ+p=nH, and μ=H−Tσp. The convention is signature (−,+,+,+) with x0=ct; c has units m s−1, u is dimensionless, n has units marker m−3, s has units J K−1 m−3, T has units K, μ has units J marker−1, and ϵ,p,h have units Pa.

[F3]

Local Gibbs, Euler, parcel first law and response identities (current batch-53 draft): for this state, dϵ=T ds+μ dn and ϵ+p=Ts+μn as identities of differentials and state functions. The identities are used conditionally at the current carrier's stated C2 hypotheses.

[F4]

Existence and uniqueness of the metric-selected connection of a nondegenerate metric, and its extension to tensor fields: for a smooth nondegenerate metric, the metric-selected connection is torsion-free and metric-compatible, and its induced tensor derivative obeys the product and contraction rules. This is the published mathematical supplier actually inspected here.

[A2]

Define Δab=gab+uaub, D=ua∇a, θ=∇aua, and ab=ua∇aub. The perfect model data are Tab=ϵuaub+pΔab, Ja=nua, and ∇aTab=fb, ∇aJa=0. In SI, fa has units N m−3, ϵ,p,h have units Pa, n has units marker m−3, and s has units J K−1m−3.

Proof

1.1A1A2F1F4algebra

Metric compatibility gives ∇aΔab=θub+ab, and ubab=0 follows by differentiating ubub=−1. Expanding the two terms of Tab with the tensor product rule in [F4] yields ∇aTab=(Dϵ+hθ)ub+hab+Δab∇ap. Contracting with ub gives −(Dϵ+hθ)=ubfb; projecting with Δcb gives hac+Δca∇ap=Δcbfb. The parallel and orthogonal projections sum to the identity, so these two equations also imply the full balance equation.

2.1A2F2F3step 1.1algebra∎

The product rule gives ∇aJa=Dn+nθ. Along the state map, [F3] gives Dϵ=TDs+μDn and h=Ts+μn, hence Dϵ+hθ=T(Ds+sθ)+μ(Dn+nθ)=T∇a(sua)+μ∇aJa. Substituting the two balances proves T∇a(sua)=−ubfb. Since s=nσp, the particle balance also gives ∇a(sua)=nDσp+σp∇aJa=nDσp; therefore nTDσp=−ubfb. Positivity of n,T permits the isolated conclusions when f=0.

LemmaStatement: AI-adaptedProof: AI-generatedOpen item page →

Enthalpy vorticity and restricted material circulation

Statement

Use the state, signature, connection, and perfect-fluid data of Rest fluid state, frame and geometric current definitions and Perfect stress and particle balances with entropy identity, with f=0, n>0, and T>0. On their common open domain O, assume both isolated balance equations

∇aTab=0,∇aJa=0,Tab=ϵuaub+pΔab,Ja=nua,

where Δab=gab+uaub. Put v=1/n, H=(ϵ+p)/n=e+pv, and let c>0 be the fixed speed-of-light normalization in the convention x0=ct. For the momentum one-form P=(H/c)u♭, consider a smooth closed curve γ0:[0,1]→O with equal endpoint values and a local flow Φλ of u in O defined on a neighborhood of its compact image. Write γλ=Φλ∘γ0 and C(λ)=∫γλP. Then

ιud(Hu♭)=T dσp,dCdλ=1c∫γλT dσp.

Consequently, circulation is conserved if σp is constant on the region swept out by the loop. The local identity does not assert circulation conservation merely from Dσp=0, nor does it assume a global flow, complete spacetime, or shock solution.

Facts & Assumptions

Given: A nonempty open set O in a smooth time-oriented Lorentzian four-manifold (M,g,N) of signature (−,+,+,+), a smooth future unit field u on O, a C2 state map into a nonempty open material-state domain, an isolated perfect-fluid stress and particle balances ∇aTab=0 and ∇a(nua)=0, a compact closed curve in O, and c>0.

[A1]

The geometric and tensor-bundle constructions use only Countable Choice ACω (The Axiom of Countable Choice (ACω)).

[F1]

Rest fluid state, frame and geometric current definitions (current batch-53 draft): on a nonempty open set O, the observer field is smooth and future unit timelike; a local state has a nonempty open domain X⊂(0,∞)×R, a specified e∈C2(X), and a C2 state map (v,σp):O→X. It defines n=v−1, s=nσp, ϵ=ne, T=eσp, p=−ev, H=e+pv, h=ϵ+p=nH, and μ=H−Tσp. The SI convention has signature (−,+,+,+) and x0=ct; c has units m s−1, u is dimensionless, H has units J marker−1, and the components of (H/c)u♭ have units kg m s−1 marker−1. The circulation C has units kg m2 s−1 marker−1. Here H is enthalpy per marker and h is an energy density.

[F2]

Perfect stress and particle balances with entropy identity (current batch-55 draft): for smooth state fields, perfect stress and particle current, ∇aTab=fb and ∇aJa=0 are equivalent to the stated parallel/spatial stress balances and Dn+nθ=0. With both balances, it states T∇a(sua)=−ubfb and nTDσp=−ubfb. Here D=ua∇a, θ=∇aua, ab=ua∇aub, and (Δα)b=αb+ubuaαa for a covector α. The supplier's smooth-state hypothesis is stronger than [F1]; step 1.2 proves the needed isolated identities directly at [F1]'s regularity.

[F3]

Smooth time-oriented Lorentzian four-manifolds: the geometric objects of the model: the metric is smooth, nondegenerate, time-oriented, and has signature (−,+,+,+).

[F4]

Existence and uniqueness of the metric-selected connection of a nondegenerate metric, and its extension to tensor fields: ∇g=0, the connection is torsion-free, and it obeys the tensor product rule.

[F5]

Local flows by a contraction argument supplies unique local flows for C1 coordinate vector fields, and Variational equations and commuting local flows supplies their joint C2 dependence when the field is C2. Both are published mathematical items; the coordinate hypotheses are checked in the proof.

[A2]

The given closed curve is smooth, γ0(0)=γ0(1), and its image is compact. The local flow is parameterized by ∂λΦλ=u. For a one-form α, dα(X,Y)=X(α(Y))−Y(α(X))−α([X,Y]); ιuω=ω(u,⋅) and u♭=g(u,⋅).

Proof

1.1A1A2F3F5construct

In each chart meeting γ0([0,1]), the coordinate components of the smooth field u are C2. The local-flow suppliers [F5] therefore give a jointly C2 flow on a neighborhood of each point of the curve. Compactness of the curve image gives a finite subcover; taking the minimum of the finitely many positive flow times gives a common interval about λ=0. Coordinate changes carry solutions to solutions, and local uniqueness makes the chartwise flows agree on overlaps. Thus γλ is a C2 closed-curve family on a common local interval.

1.2givenF1F2F3F4algebra

By [F1] and the chain rule, n,s,ϵ are C2, while p,T,H are C1; hence the stress and P are C1 and J is C2. For these tensors use [F4]'s coordinate derivative formula: differentiate the coefficients and add one Christoffel term for each upper index and subtract one for each lower index. It defines an intrinsic derivative also for C1 coefficients, since differentiating their tensor transformation law uses only the first-order chain rule and the same cancellation of derivatives of the smooth coordinate changes. The product and contraction rules follow from the ordinary product rule, and ∇g=0 remains valid. Thus all the following derivatives exist classically. From [F1], de=−p dv+T dσp, so dH=T dσp+v dp and, using dv=−n−2dn, dϵ=H dn+nT dσp. Differentiating g(u,u)=−1 gives ubab=0 and ∇aΔab=θub+ab. The product rule now gives 0=∇aTab=(Dϵ+hθ)ub+hab+Δab∇ap,0=∇aJa=Dn+nθ. Contracting the stress equation with ub gives Dϵ+hθ=0; applying Δcb=δcb+ucub gives hac+Δca∇ap=0. Since h=nH, the differential identity for ϵ gives 0=Dϵ+hθ=H(Dn+nθ)+nTDσp=nTDσp. Positivity of n,T yields Dσp=0; lowering the projected stress equation and dividing by n yields Ha♭+vΔ dp=0. No division by H is used.

2.1step 1.2F3F4algebra

Torsion freedom and the product rule yield, in any chart, (ιud(Hu♭))b=ua∇a(Hub)−ua∇b(Hua)=(DH)ub+Hab+∇bH=Hab+Δba∇aH. Here ua∇bua=12∇b(uaua)=0, and the last equality is the definition of the spatial covector projection. Substituting the expression for dH from step 1.2 and using Δ dσp=dσp from Dσp=0 gives ιud(Hu♭)=Ha♭+Tdσp+vΔ dp=Tdσp.

3.1A2F4F5step 2.1algebra∎

Subdivide [0,1] into finitely many closed subintervals whose curve images lie in coordinate charts; compactness gives such a subdivision, and endpoint terms will telescope. On each chart subarc put F(λ,s)=Pa(γλ(s))∂sγλa(s). It is C1 on each compact parameter rectangle. The one-variable fundamental theorem of calculus gives [F(λ+h,s)−F(λ,s)]/h=h−1∫λλ+h∂rF(r,s) dr; uniform continuity of ∂λF on the compact rectangle makes this quotient converge uniformly in s to ∂λF(λ,s). Integrating that uniform limit proves differentiation under the line integral. Since ∂λγ=u, ∂λF=(ub∂bPa+Pb∂aub)∂sγλa. Thus C′=∫γλLuP, where in coordinates (LuP)a=ub∂bPa+Pb∂aub. Direct expansion gives (ιudP+d(P(u)))a=ub(∂bPa−∂aPb)+∂a(ubPb), so direct expansion proves LuP=ιudP+d(P(u)). The exact one-form integrates on each subarc to its endpoint difference, and these differences telescope to zero because γλ(0)=γλ(1). Since dP=(1/c)d(Hu♭), step 2.1 yields C′=c−1∫γλT dσp. If σp is constant throughout the swept region, then for each fixed λ the composition s↦σp(γλ(s)) is constant. The chain rule therefore gives dσp(∂sγλ)=∂s(σp∘γλ)=0, so the displayed line integral and hence C′ vanish. No vanishing of the ambient covector dσp transverse to the swept image is needed.

LemmaStatement: AI-adaptedProof: AI-generatedjudge pass (gpt-6-luna)Open item page →

Frame-qualified dissipative entropy cancellation

Statement

Let (M,g,N), u, ∇, and the fixed-composition state be as in Rest fluid state, frame and geometric current definitions and Local Gibbs, Euler, parcel first law and response identities, with g(u,u)=−1, n>0, and T>0. Define Δab=gab+uaub, Δab=gab+uaub, Δab=δab+uaub, and D=ua∇a, θ=∇aua, ab=ua∇aub, and the spatial symmetric trace-free shear

σab=ΔacΔbd∇(cud)−θ3Δab,

where parentheses denote the averaged symmetric part. Suppose smooth fields Π, Qa, Va, and πab obey uaQa=uaVa=0, uaπab=0, and πab is symmetric with gabπab=0. Set

Tab=ϵuaub+(p+Π)Δab+uaQb+Qaub+πab,Ja=nua+Va.

If ∇aTab=fb and ∇aJa=0, the vector field

Sa=sua+QaT−μVaT

satisfies the exact identity

∇aSa=−Πθ+πabσabT−Qa(∇aT+Taa)T2−Va∇a ⁣(μT)−ubfbT.

This identity applies to the stated smooth fields and conventions; it does not select a constitutive law or assert that any such fields solve an evolution problem.

Facts & Assumptions

Given: A nonempty open set O and the smooth Lorentzian data of Rest fluid state, frame and geometric current definitions, a C2 state map into a nonempty open state domain, the thermodynamic identities of Local Gibbs, Euler, parcel first law and response identities, and the stress and particle balances displayed in the Statement.

[A1]

The spacetime and tensor construction assumes Countable Choice ACω (The Axiom of Countable Choice (ACω)); no stronger choice principle is used.

[F1]

Rest fluid state, frame and geometric current definitions (current batch-53 draft): on a nonempty open set O, the observer field is smooth and future unit timelike; a local state has a nonempty open domain X⊂(0,∞)×R, a specified e∈C2(X), and a C2 state map (v,σp):O→X. It defines n=v−1>0, s=nσp, ϵ=ne, T=eσp, p=−ev, H=e+pv, h=ϵ+p=nH, and μ=H−Tσp.

[F2]

Local Gibbs, Euler, parcel first law and response identities (current batch-53 draft): under the stated nonempty open-domain and C2 hypotheses, it gives dϵ=T ds+μ dn and ϵ+p=Ts+μn. Applying the first identity to the state map along D gives the directional identity used below. This use is conditional on the current draft carrier.

[F3]

Existence and uniqueness of the metric-selected connection of a nondegenerate metric, and its extension to tensor fields: the induced tensor derivative satisfies the product rule, ∇g=0, and contraction commutes with differentiation.

[F4]

In the SI convention of [F1], u and Δ are dimensionless, D,θ,a,σ have inverse-length components, ϵ,p,Π,Q,π have units Pa, n,V have units marker m−3, s has units J K−1m−3, T has units K, and μ has units J per marker. The force density f has units N m−3, the physical heat flux is q=cQ, and c has units m s−1.

[A2]

Define Δab=gab+uaub, D=ua∇a, θ=∇aua, and ab=ua∇aub. The stress decomposition, spatial symmetries, and balance equations are exactly those in the Statement.

Proof

1.1A1A2F1F3algebra

From metric compatibility, ∇aΔab=θub+ab and ub∇aub=0. The perfect energy term contracts as ub∇a(ϵuaub)=−Dϵ−ϵθ; the isotropic pressure term contributes −(p+Π)θ. Orthogonality and the product rule give ub∇a(uaQb)=−Qbab and ub∇a(Qaub)=−∇aQa. Finally ub∇aπab=−πab∇aub=−πabσab: the spatial symmetric trace-free tensor π annihilates the antisymmetric part of ∇u and its isotropic spatial trace. Thus the stress balance is Dϵ+hθ+Πθ+∇aQa+Qaaa+πabσab=−ubfb.

2.1A2F2step 1.1algebra

The particle balance gives Dn+nθ=−∇aVa. By [F2], Dϵ+hθ=T(Ds+sθ)+μ(Dn+nθ)=T∇a(sua)−μ∇aVa. Substitution in step 1.1 yields T∇a(sua)=−Πθ−πabσab−∇aQa−Qaaa+μ∇aVa−ubfb.

3.1step 2.1A2algebra∎

By the definition Sa=sua+Qa/T−μVa/T, its divergence is ∇a(sua)+∇a(Qa/T)−∇a(μVa/T): the last derivative is subtracted. The product rule gives ∇a ⁣(QaT)=∇aQaT−Qa∇aTT2,∇a ⁣(μVaT)=μT∇aVa+Va∇a ⁣(μT). Substituting these expressions and step 2.1 gives ∇aSa=−Πθ−πabσab−∇aQa−Qaaa+μ∇aVa−ubfbT+∇aQaT−Qa∇aTT2−μ∇aVaT−Va∇a ⁣(μT). The ∇aQa/T and μ∇aVa/T terms cancel with the displayed opposite-sign terms. The remaining heat terms combine as −Qa∇aT/T2−Qaaa/T=−Qa(∇aT+Taa)/T2, proving the stated identity. Since Q,V are spatial, only the rest-space projections of the corresponding gradients contribute.

LemmaStatement: AI-adaptedProof: AI-generatedjudge pass (gpt-6-luna)Open item page →

Positive first-order residual and actual instability/tail counterexamples

Statement

Use the smooth state, frame, and dissipative stress/particle decomposition of Rest fluid state, frame and geometric current definitions and Frame-qualified dissipative entropy cancellation. Assume the stress and particle balances ∇aTab=fb and ∇aJa=0. Let c>0, T>0, and let η,ζ,κ,L≥0. Impose

Π=−ζcθ,πab=−2ηcσab,Qa=−κcΔab(∇bT+Tab),Va=−LΔab∇b(μ/T).

On any branch with no rest-frame work, ubfb=0 (including the isolated case fb=0), the entropy identity reduces to

∇aSa=ζcθ2+2ηc σabσabT+κcT2Δab(∇aT+Taa)(∇bT+Tab)+LΔab∇a(μ/T)∇b(μ/T)≥0.

This sign condition alone implies neither finite propagation nor linear stability, as the following two conditional model calculations show.

  1. Supported fixed-rest Fourier branch. Let M=R4 have Minkowski metric g=diag⁡(−1,1,1,1), choose N=(1,0,0,0) as time orientation, and write x0=ct. On the positive-time field domain O={(x0,x):x0>0, x∈R3} set u=(1,0,0,0). Set V=Π=π=0 and η=ζ=L=0, and maintain the fixed rest field with external support f0=0, fi=∂ip+c−1∂tQi, hence ubfb=0 even if fi is nonzero. On a fixed-volume state slice v=v0, let T=T0+ϑ and ϵ=ϵ0+Cϑ, where T0,C>0 are constant and the temperature coordinate is valid on an interval [T0,T0+δ] contained in the material-state domain for some δ>0. With constant κ>0, set q=cQ=−κ∇ϑ. For any ϑ0∈Cc∞(R3) satisfying 0≤ϑ0≤δ and ϑ0≢0, the heat solution ϑ(x,t):=∫R3Γ(x−y,κt/C)ϑ0(y) dy for t>0 has initial boundary trace ϑ0 locally uniformly as t↓0+ and is strictly positive at every x∈R3 for every t>0. Hence no finite speed v satisfies supp⁡ϑ(⋅,t)⊆supp⁡ϑ0+B‾vt(0) for all t>0.

  2. Homogeneous Eckart linearization. On the same Minkowski spacetime take f=0 and a homogeneous rest state with n0,T0>0, h0=ϵ0+p0>0, and κ>0. Set the density and temperature perturbations to zero, δn=δT=0, take V=0, and impose no spatial gradients. Let w:(0,∞)→R3 be the first-order spatial perturbation of u. The linearized first-order heat and momentum equations are Qi=−(κT0/c2)w˙i and h0w˙+Q˙=0. Hence for λ=h0c2/(κT0)>0, every nonzero constant vector w∗ gives the growing linearized mode w(t)=w∗eλt. This is a statement about the linearized equations, not a nonlinear solution claim.

The results are conditional mathematical deductions from the displayed model equations. They do not establish a constitutive law for nature, a nonlinear existence theorem, or a general instability theorem.

Facts & Assumptions

Given: Countable Choice; a nonempty open spacetime domain with the smooth Lorentzian frame and C2 local state specified by Rest fluid state, frame and geometric current definitions, with n,T>0; and the model equations and constants stated above.

[A1]

Countable Choice ACω is assumed where the heat-kernel and Lorentzian suppliers require it (The Axiom of Countable Choice (ACω)).

[F1]

Frame-qualified dissipative entropy cancellation: for the displayed stress and particle balances, ∇aSa=−Πθ+πabσabT−Qa(∇aT+Taa)T2−Va∇a(μ/T)−ubfbT. This is the current batch-55 conditional draft; its tgr-mc01 input hashes are stale, so its use remains conditional.

[F2]

The heat kernel on Rn and its causal extension: for τ>0, Γ(x,τ)=(4πτ)−3/2exp⁡(−∣x∣2/(4τ)), which is strictly positive.

[F3]

Normalisation, parabolic scaling, heat equation and derivative bounds for the heat kernel: assuming Countable Choice, Γ(⋅,τ)>0 and has unit integral for every τ>0.

[F4]

The heat Cauchy problem for bounded uniformly continuous data: assuming Countable Choice, for bounded uniformly continuous ϑ0:R3→R, the convolution ∫Γ(x−y,τ)ϑ0(y) dy is smooth for τ>0, solves Uτ=ΔU, is bounded, and recovers ϑ0 locally uniformly at τ=0; it also obeys ∥U(⋅,τ)∥∞≤∥ϑ0∥∞.

[A2]

For the supported fixed-rest branch, M=R4 has Minkowski metric g=diag⁡(−1,1,1,1), x0=ct, the field domain is t>0, x∈R3, and u=(1,0,0,0). With V=Π=π=0 and η=ζ=L=0, the external support is specified by f0=0 and fi=∂ip+c−1∂tQi. On a fixed-volume state slice v=v0, T=eσp is a valid coordinate and (∂ϵ/∂T)v0=C>0 is constant on an interval [T0,T0+δ] inside the material-state domain, so ϵ=ϵ0+C(T−T0) there. Here T0,δ,κ>0 and ϑ0∈Cc∞(R3) satisfies 0≤ϑ0≤δ and ϑ0≢0.

[A3]

In the entropy-sign branch assume ubfb=0. This includes the isolated case fb=0; in the supported fixed-rest branch of [A2], ubfb=−f0=0 although the spatial support force may be nonzero.

[A4]

In the homogeneous Eckart linearization, f=0, the background is constant with n0,T0>0, h0=ϵ0+p0>0, and κ>0; δn=δT=0, V=0, and all spatial gradients vanish. In SI, C has units J m−3K−1, κ has units W m−1K−1, q has units W m−2, h0 has units Pa, λ has units s−1, η,ζ have units Pa s, L has units marker2 K J−1m−2, and Q,Π,π have units Pa; c has units m s−1.

[F5]

Smooth time-oriented Lorentzian four-manifolds: the geometric objects of the model: in signature (−,+,+,+), the orthogonal complement of a unit timelike vector has positive-definite metric; this supplies the sign of the projected quadratic terms.

[F6]

Rest fluid state, frame and geometric current definitions (current batch-53 draft): on a nonempty open set O, a local state is specified by e∈C2(X) on nonempty open X⊂(0,∞)×R and a C2 state map (v,σp):O→X. It defines n=v−1, s=nσp, ϵ=ne, T=eσp, p=−ev, H=e+pv, and μ=H−Tσp. The convention has signature (−,+,+,+) and x0=ct, with c in m s−1.

Proof

1.1A1F1F5F6givenalgebra

Substitute the first-order laws into [F1] under the no-work assumption ubfb=0 of [A3]. They give −Πθ/T=ζcθ2/T, −πabσab/T=2ηc σabσab/T, −Qa(∇aT+Taa)/T2=κΔab(∇aT+Taa)(∇bT+Tab)/(cT2), and −Va∇a(μ/T)=LΔab∇a(μ/T)∇b(μ/T). The rest-space metric induced by Δ is positive definite by [F5]; with T,c>0 and nonnegative coefficients every summand is nonnegative, proving the stated residual inequality.

1.2A1A2F2F3F4F6algebra

In Minkowski coordinates, T00=ϵ and Ti0=Qi for the fixed-rest stress of [A2]. The temporal balance ∇aTa0=f0=0 is c−1∂tϵ+∂iQi=0. The spatial components are ∇aTai=c−1∂tQi+∂ip=fi, as required by [A2]. Using ϵ=ϵ0+Cϑ and q=cQ=−κ∇ϑ, the temporal balance becomes C∂tϑ+∇⋅q=0, or C∂tϑ−κΔϑ=0. Put ah=κ/C>0 and U(x,τ)=∫R3Γ(x−y,τ)ϑ0(y) dy. The smooth compactly supported datum in [A2] is bounded and uniformly continuous, so [F4] gives a smooth solution of Uτ=ΔU for τ>0 with initial trace ϑ0 locally uniformly. Then ϑ(x,t)=U(x,aht) solves the fixed-rest equation and has the stated boundary trace. Kernel positivity [F2] and ϑ0≥0 give ϑ≥0. The unit integral from [F3] and ϑ0≤δ give ϑ(x,t)≤δ∫R3Γ(x−y,aht) dy=δ, so the temperature remains in the specified state interval.

1.3A4F1algebra

Write u0=1+O(∣w∣2) and ui=wi+O(∣w∣2) in the homogeneous rest perturbation of [A4]. With x0=ct, ai=ua∇aui=c−1w˙i to first order, so the first-order acceleration heat law gives Qi=−κT0w˙i/c2. In ∇aTai=0, the linearized mixed component is T0i=h0wi+Qi: the perfect part contributes h0wi, the term u0Qi contributes Qi, and Q0ui is second order. All spatial derivatives vanish, so ∂0T0i=0 gives h0w˙i/c+Q˙i/c=0. Multiplication by c gives h0w˙i+Q˙i=0, the stated homogeneous linearized momentum equation.

2.1F2step 1.2algebra

Since ϑ0 is continuous, nonnegative, and nonzero, it is bounded below by a positive constant on some closed ball of positive radius. For every fixed x and t>0, the continuous kernel Γ(x−y,aht) has a positive minimum on that ball by [F2], so the convolution from step 1.2 is strictly positive. Thus supp⁡ϑ(⋅,t)=R3. For any finite v≥0, supp⁡ϑ0+B‾vt(0) is bounded at each fixed t>0 because supp⁡ϑ0 is compact; it cannot contain supp⁡ϑ(⋅,t). This proves the claimed failure of finite propagation.

3.1step 1.3A4algebra∎

Let α=κT0/c2>0. Substitution of Qi=−αw˙i into the equation of step 1.3 gives w¨i=(h0/α)w˙i=λw˙i. For any w∗≠0, wi(t)=w∗ieλt satisfies this equation because w¨i=λ2wi=λw˙i. Since λ>0, its norm grows exponentially. This proves a linearly growing mode without asserting that the linearized solution remains within the regime of a nonlinear material model.

5 · Examples, experiments and counterexamples

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