Alphabeta Math
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How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Sparse recovery and nullspace certificates — Examples and Counterexamples

1 · Prerequisites

2 · Logical flowchart

3 · Definitions, theorems and proofs

None yet.

4 · Examples, counterexamples and false statements

ExampleConstruction: AI-generatedVerification: AI-generatedjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)Open item page →

A two-column matrix where basis pursuit is not unique

Example

Let A=[1  1]∈M1×2(R) and s=1, using one-based coordinate labels j=1,2 corresponding to library indices j−1. The vector h=(1,−1) lies in ker⁡A, and for S={1} the strict nullspace inequality fails because ∥hS∥1=∥hSc∥1=1. Under the constraint z1+z2=1, the function ∣z1∣+∣z2∣ has minimum 1, attained both by x†=(1,0) and by z=(0,1); therefore the displayed optimization problem has two distinct minimizers.

Facts & Assumptions

Given: A=[1  1], s=1, and the vectors h=(1,−1), x†=(1,0), and z=(0,1) in R2.

[F1]

The strict nullspace property: strict NSP requires ∥hS∥1<∥hSc∥1 for every nonzero kernel vector and every S of size at most s.

[F2]

The p-norms ∥x∥p for rational p≥1, and ∥x∥∞: on R2, ∥u∥1=∣u1∣+∣u2∣.

[F3]

The triangle inequality: ∣a+b∣≤∣a∣+∣b∣ for real a,b.

[F4]

The strict nullspace property: the matrix-vector product is computed by the one-based row formula in the definition.

Verification

1.1givenF1F2F4algebra

By [F4], Ah=1−1=0, and h≠0. For S=∅, hS=(0,0) and hSc=h, so [F2] gives ∥hS∥1=0<2=∥hSc∥1. For S={1}, hS=(1,0) and hSc=(0,−1), so [F2] gives ∥hS∥1=1=∥hSc∥1. Thus the required strict inequality fails for this admissible support, as claimed by [F1].

2.1givenF2F3F4algebra∎

By [F4], every vector w=(w1,w2) feasible for this datum satisfies w1+w2=1, so [F3] gives 1=∣w1+w2∣≤∣w1∣+∣w2∣. Both x† and z are feasible and have objective value 1 by [F2]; they are distinct, so both attain the minimum of the displayed objective and it is not unique.

ExampleConstruction: AI-generatedVerification: AI-generatedjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)Open item page →

A nontrivial three-column matrix with the nullspace property

Example

Let A=(1−10101)∈M2×3(R) and s=1, using one-based coordinate labels j=1,2,3 corresponding to library indices j−1. Then ker⁡A={λ(1,1,−1):λ∈R}, A satisfies the strict nullspace property of order 1, and every vector x†∈R3 with at most one nonzero coordinate is the unique minimizer of ∑j=13∣zj∣ subject to Az=Ax†.

Facts & Assumptions

Given: The matrix A=(1−10101) and sparsity order s=1.

[F1]

The strict nullspace property: strict NSP requires ∥hS∥1<∥hSc∥1 for each nonzero kernel vector and every S with ∣S∣≤s.

[F2]

The p-norms ∥x∥p for rational p≥1, and ∥x∥∞: the ℓ1 norm is the sum of coordinate absolute values.

[F3]

Exact basis-pursuit recovery under the strict nullspace property: a matrix with strict NSP of order s uniquely recovers every vector with at most s nonzero coordinates by exact ℓ1 minimization.

[F5]

The strict nullspace property: under its coordinate relabeling, (Au)i=∑j=1nAijuj for each row i.

Verification

1.1givenF5algebra

For h=(u,v,w), the row formula [F5] gives Ah=(u−v,u+w), so Ah=0 exactly when v=u and w=−u. Hence ker⁡A={λ(1,1,−1):λ∈R}.

2.1givenF1F2step 1.1algebra

Write a nonzero kernel vector as h=λ(1,1,−1) with λ≠0. If S=∅, then ∥hS∥1=0<3∣λ∣=∥hSc∥1. If S is a singleton, then ∥hS∥1=∣λ∣<2∣λ∣=∥hSc∥1. These are all sets with ∣S∣≤1, so [F1] holds.

3.1givenF2F3F4step 2.1∎

Applying [F3] with s=1 now gives the claimed unique minimizer for every vector with at most one nonzero coordinate; [F2] identifies the objective formula as the ℓ1 norm by [F4].

ExampleConstruction: AI-generatedVerification: AI-generatedjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)Open item page →

Identity design: noiseless recovery and a noisy minimax lower bound

Example

Assume the Axiom of Choice. Let n,d,s∈N with n≥1, d≥2, 1≤s≤d/2, and σ>0. Use one-based coordinate labels j=1,…,d, with coordinate j identified with the library's coordinate j−1, and put Θs,d:={θ∈Rd:∣{j∈{1,…,d}:θj≠0}∣≤s}, and let Id be the d×d identity matrix. For θ∈Θs,d, observe independent coordinates Yj∼N((Idθ)j,σ2/n),1≤j≤d. The zero kernel of Id implies the strict nullspace property of order s, so the noiseless basis-pursuit problem uniquely recovers each s-sparse θ. In this noisy Gaussian model, every Borel estimator T:Rd→Rd satisfies sup⁡θ∈Θs,dEθ[∑j=1d(T(Y)j−θj)2]≥σ2slog⁡(ed/s)200000n.

Facts & Assumptions

Given: The Axiom of Choice; integers n≥1, d≥2, and 1≤s≤d/2; σ>0; the class Θs,d and independent Gaussian observation law in the Example; and a Borel estimator T:Rd→Rd.

[A1]

The Axiom of Choice: the Axiom of Choice states that every family of nonempty sets has a choice function; the minimax supplier used below explicitly assumes this axiom.

[F1]

The strict nullspace property: the strict nullspace property tests every nonzero h∈ker⁡A; if ker⁡A={0}, the condition is vacuous for every admissible order 1≤s≤d.

[F2]

Exact basis-pursuit recovery under the strict nullspace property: strict NSP of order s implies unique noiseless ℓ1 recovery for every vector with at most s nonzero coordinates.

[F3]

Gaussian sparse-sequence minimax lower bound: under AC, for n,d≥1, σ>0, and 1≤s≤d/2, independent N(θj,σ2/n) coordinates over Θs,d give every Borel estimator squared-ℓ2 risk at least σ2slog⁡(ed/s)/(200000n) in the worst case.

[F4]

The p-norms ∥x∥p for rational p≥1, and ∥x∥∞: ∥u∥22=∑j=1duj2 for u∈Rd.

[F6]
[F7]

The strict nullspace property: (Au)i=∑j=1dAijuj under the one-based coordinate relabeling.

[F8]

Laws of finite sums and finite products: finite sums split at an index, and the sum of a list with exactly one nonzero term is that term.

Verification

1.1givenF1F2F6F7F8algebra

For each i∈[d], [F6] and [F7] give (Idh)i=∑j=1dδijhj=hi by [F8], so Idh=0 forces h=0 and ker⁡Id={0}. Hence Id satisfies strict NSP of order s vacuously by [F1], and [F2] gives unique noiseless ℓ1 recovery for every θ∈Θs,d.

2.1givenA1F3F4F5algebra∎

For each θ∈Θs,d, (Idθ)j=θj, so the stated independent observation coordinates have exactly the Gaussian sequence laws in [F3]. The parameter, sample-size, noise, sparsity, estimator, and AC hypotheses in [A1] and [F3] are all among the Given; applying [F3] proves the displayed minimax lower bound in its sum-of-squares form by [F4], where [F5] confirms that the displayed squared error is the squared Euclidean norm.