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Primitive Ideals and Duflo Theorem - Examples

1 · Prerequisites

2 · Summary

These sl2-level examples and counterexamples make the page's conventions concrete: the associated variety of a finite-dimensional simple annihilator is the origin, an intersection of primitive ideals need not be primitive, a central character need not determine its primitive ideal, the trivial module's annihilator is the augmentation ideal rather than the Casimir ideal, and over a generic central character the unique primitive ideal is the unavoidable central ideal U(g)ker⁡χ.

3 · Logical flowchart

4 · Definitions, theorems and proofs

None yet.

5 · Examples, counterexamples and false statements

ExampleConstruction: Literature-sourcedVerification: AI-adaptedjudge pass (gpt-6.1-sol)Open item page →

The associated variety of a finite-dimensional simple annihilator is the origin

Example

Let g be a finite-dimensional complex semisimple Lie algebra and let L(λ) be a finite-dimensional simple U(g)-module, with λ dominant integral. Then I(λ)=Ann⁡U(g)L(λ) has finite codimension in U(g), and its associated variety is the origin:

V(I(λ))={0}⊆g∗. Indeed, with d=dim⁡CL(λ), Cayley-Hamilton shows that for every y∈g the power yd is the symbol of an element of I(λ), so gr⁡I(λ) contains the d-th powers of all of g. Over C, the polarization identity shows that these pure d-th powers span Sd(g): for y1,…,yd∈g, d! y1⋯yd=∑J⊆{1,…,d}(−1)d−∣J∣(∑j∈Jyj)d. Since gr⁡I(λ) is an ideal in S(g), it contains every Sk(g) for k≥d. Its zero set is therefore {0}; equivalently, every point ξ in it satisfies ξ(y)d=0 for all y∈g. The finite-dimensionality of L(λ) is essential here. Infinite-dimensional (Verma-type) annihilators behave differently: their associated varieties need not be {0}, and on this page no positive-dimensionality statement about them is asserted.

Facts & Assumptions

Given: A finite-dimensional complex semisimple Lie algebra g, a dominant integral weight λ, and the finite-dimensional simple module L(λ) with d:=dim⁡CL(λ)≥1.

[F1]

I(λ) is the kernel of the unital algebra homomorphism U(g)→End⁡C(L(λ)) given by the action, so it is a proper two-sided ideal and U(g)/I(λ) embeds into the finite-dimensional algebra End⁡C(L(λ)) (The annihilator of a module over an enveloping algebra, Finite-dimensional simple modules are classified by dominant highest weights).

[F2]

Cayley-Hamilton: for every endomorphism T of the finite-dimensional space L(λ), the characteristic polynomial χT satisfies χT(T)=0; it is monic of degree d (Cayley-Hamilton: every finite-dimensional endomorphism satisfies its characteristic polynomial, χT(T)=0, Polynomial evaluation at an endomorphism: p(T)=∑kakTk).

[F3]

The symbol of an element p(y)=yd+(terms of degree <d) of the PBW filtration is yd∈Sd(g); symbols multiply, and V(I) is the zero locus of gr⁡I in g∗ with g∗ in duality with the degree-one symbols (The associated graded variety of a two-sided ideal, The PBW filtration by tensor degree on the enveloping algebra, PBW gives an ordered monomial basis for the enveloping algebra, Classical affine zero loci form the Zariski closed sets).

Verification

technique · direct
1.1F1given

The action map U(g)→End⁡C(L(λ)) has kernel I(λ) by definition, so U(g)/I(λ) is isomorphic to a subalgebra of the finite-dimensional algebra End⁡C(L(λ)); hence I(λ) has finite codimension in U(g). It is proper because 1 acts as the identity on the nonzero module L(λ).

1.2F2F3algebra

Fix y∈g and let χy be the characteristic polynomial of the operator by which y acts on L(λ); by [F2] it is monic of degree d and χy(y) acts as 0 on L(λ), that is, χy(y)∈I(λ). Writing χy(y)=yd+(terms of PBW degree <d), its symbol in the associated graded is yd by [F3]; hence yd∈(gr⁡I(λ))d⊆Sd(g).

2.1step 1.2F1F3algebra∎

Let ξ∈V(I(λ)). By step 1.2 and the definition of the associated variety, 0=ξ(yd)=ξ(y)d for every y∈g, so ξ(y)=0 for every y∈g and hence ξ=0; thus V(I(λ))⊆{0}. Conversely, I(λ) is a proper ideal, so I(λ)∩C⋅1=0 and gr⁡I(λ) has no nonzero degree-zero element; every f∈gr⁡I(λ) therefore has zero constant term and satisfies f(0)=0, so 0∈V(I(λ)). Hence V(I(λ))={0}.

CounterexampleConstruction: AI-generatedVerification: AI-generatedjudge pass (gpt-6.1-sol)Open item page →

An intersection of two primitive ideals need not be primitive

Statement refuted

The assertion that the set of primitive ideals of an enveloping algebra is closed under finite intersections is false. In U(sl2(C)) the ideals I0=Ann⁡L(0) (the trivial module) and I1=Ann⁡L(1) (the two-dimensional simple module) are primitive, but their intersection I0∩I1 is not primitive. The central-character criterion detects this: (I0∩I1)∩Z(U(g))=ker⁡χ0∩ker⁡χ1 is not a maximal ideal.

Facts & Assumptions

Given: g=sl2(C) with Casimir Ω, the finite-dimensional simple modules L(0)=C and L(1) (the standard two-dimensional module), and the ideals I0=Ann⁡U(g)L(0), I1=Ann⁡U(g)L(1).

[F2]

A primitive ideal I satisfies I∩Z(U(g))=ker⁡χI, and this intersection is a maximal ideal of Z(U(g)) (A primitive ideal determines a central character, Prime ideals and maximal ideals in a commutative ring).

[F3]

Put Ω:=ef+fe+12h2∈Z(U(g)); it is central because the relations [h,e]=2e, [h,f]=−2f, [e,f]=h give [h,Ω]=[e,Ω]=[f,Ω]=0 (The special linear Lie algebra sl_2). The finite-dimensional simple modules are the L(n), n≥0 (Finite-dimensional simple modules are classified by dominant highest weights), and on the highest-weight vector of L(n) one has ev=0, efv=[e,f]v+f(ev)=hv=nv, fev=0, so Ωv=(n+0+12n2)v=n(n+2)2v; in particular χ0(Ω)=0 and χ1(Ω)=32 (Central character of a Lie algebra module).

[F4]

In a commutative ring, two distinct maximal ideals have non-maximal intersection: if M=m∩n with m≠n maximal were maximal, then m⊇M and maximality of M would force M=m, so m⊆n and maximality of m would force m=n, a contradiction (Prime ideals and maximal ideals in a commutative ring).

Counterexample

technique · direct
1.1F1F2given

By [F1] the ideals I0 and I1 are primitive. By [F2] their central intersections are I0∩Z=ker⁡χ0 and I1∩Z=ker⁡χ1.

1.2F3F2algebra

By [F3] the central character values on the central element Ω are χ0(Ω)=0 and χ1(Ω)=1⋅(1+2)/2=3/2; since these differ, χ0≠χ1, so their kernels are distinct maximal ideals by [F2].

2.1step 1.1step 1.2F4

Intersecting the central intersections of step 1.1 gives (I0∩I1)∩Z=ker⁡χ0∩ker⁡χ1, and this is not a maximal ideal by [F4] applied to the distinct maximal ideals ker⁡χ0,ker⁡χ1.

3.1step 2.1F2∎

If I0∩I1 were primitive, then by [F2] its intersection with Z would be maximal, contradicting step 2.1. Therefore I0∩I1 is not primitive, and the set of primitive ideals is not closed under finite intersections.

CounterexampleConstruction: Literature-sourcedVerification: AI-adaptedjudge pass (gpt-6.1-sol)Open item page →

The central character does not determine the primitive ideal

Statement refuted

Assume the Axiom of Choice. The assertion that a central character determines the primitive ideal over it is false. In U(sl2(C)), for every integer n≥0 the primitive ideals I(n)=Ann⁡L(n) and J(n)=Ann⁡M(−n−2) are distinct, although L(n) and the simple Verma module M(−n−2) have the same central character χn=χ−n−2. Thus the fibre of the central-character map on primitive ideals has at least two points over every such χn, and the assignment λ↦Ann⁡L(λ) is not injective. In particular the fibre over the regular integral central character χ0 already has two points.

Facts & Assumptions

Given: The Axiom of Choice, g=sl2(C) with Casimir Ω, an integer n≥0, the finite-dimensional simple module L(n), and the Verma module M(−n−2).

[F1]

L(n) is a finite-dimensional simple module, and I(n)=Ann⁡U(g)L(n) is primitive; here Ω:=ef+fe+12h2 is the normalized central Casimir, and the central-reduction lemma also gives Z(U(g))=C[Ω] and the eigenvalue Ω↦n(n+2)/2 on L(n) (Finite-dimensional simple modules are classified by dominant highest weights, Annihilators of simple highest-weight modules are primitive, The central reduction of U(sl2) is simple away from the finite-dimensional central characters).

[F2]

M(−n−2) is simple — its highest weight is antidominant, ⟨λ+ρ,α∨⟩<0 for the positive root — so J(n)=Ann⁡U(g)M(−n−2) is primitive; Ω acts on M(−n−2) by (−n−2)(−n)/2=n(n+2)/2, and every weight space of M(−n−2) is finite-dimensional with weights (−n−2)−2k, k∈Z≥0, so M(−n−2) is infinite-dimensional (Antidominant regular Verma modules are simple, Verma modules, The central reduction of U(sl2) is simple away from the finite-dimensional central characters, Weights of a Verma module lie below lambda, The Axiom of Choice).

[F3]

For sl2, equal values of the character on Ω give equal central characters: χn=χ−n−2 by [F1], [F2] and Central characters are dot-Weyl orbits, because 0 and −2 (and generally n and −n−2) lie in the same dot orbit. [F1, F2]

[F4]

If K is the annihilator of a module M, then U(g)/K embeds into End⁡C(M) and acts faithfully on M; the image of a finite-dimensional vector space under a linear map is finite-dimensional, since the images of a finite basis span the image (The annihilator of a module over an enveloping algebra, Primitive ideals of an enveloping algebra).

[F5]

If the normalized Casimir value c is not m(m+2)/2 for any integer m≥0, every Verma module with that value is simple and its annihilator is the central ideal (The central reduction of U(sl2) is simple away from the finite-dimensional central characters). A simple Verma module equals its unique simple quotient L(λ) (Annihilators of simple highest-weight modules are primitive).

Counterexample

technique · contradiction
1.1F1F2F3

By [F1] and [F2] both I(n) and J(n) are primitive ideals, and both modules have the same central character χn by [F3].

1.2F1F5algebra

To verify the separate noninjectivity assertion, take the distinct highest weights 1/2 and −5/2. Their normalized Casimir eigenvalue is 5/8, and their central characters agree because Z(U(g))=C[Ω]. This value is not a finite-dimensional Casimir value: n(n+2)/2 is 0 at n=0 and at least 3/2 at every integer n≥1. Therefore The central reduction of U(sl2) is simple away from the finite-dimensional central characters makes both Verma modules simple and gives the same central ideal as their annihilator. Their unique simple quotients are the Verma modules themselves, so I(1/2)=I(−5/2) although 1/2≠−5/2.

1.3F1F4assume-contra

Suppose I(n)=J(n)=:K. By [F4] the algebra A:=U(g)/K embeds into End⁡CL(n), because K is the kernel of the action on L(n); hence A is finite-dimensional.

2.1step 1.3F2F4algebra

Also by [F4] A acts faithfully on M(−n−2). Fix 0≠m∈M(−n−2) and consider the map A→M(−n−2), a↦am: it is A-linear because b(am)=(ba)m, and its image is a nonzero A-submodule of M(−n−2), hence equals M(−n−2) because M(−n−2) is simple by [F2]. The images of a finite basis of A thus span M(−n−2), which is finite-dimensional.

3.1step 2.1F2F3discharge-contradiction∎

But M(−n−2) is infinite-dimensional by [F2], since its weights (−n−2)−2k, k∈Z≥0, are infinitely many distinct weights with finite-dimensional weight spaces. This contradiction shows I(n)≠J(n); the two distinct primitive ideals share the central character χn, so a central character does not determine the primitive ideal. Taking n=0 exhibits two points in the fibre over the regular integral central character χ0.

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The annihilator of the trivial sl(2)-module

Example

Assume the Axiom of Choice. Let g=sl2(C) with standard basis e,f,h and Casimir element Ω, so that Z(U(g))=C[Ω]. The annihilator of the trivial module C is the augmentation ideal Ann⁡U(g)C=U(g)g=(e,f,h), the two-sided ideal generated by g; it is a primitive ideal whose central character χ0 is the one with χ0(Ω)=0, and Ann⁡U(g)C∩Z(U(g))=(Ω) is a maximal ideal of Z(U(g)). The central ideal U(g)ker⁡χ0=(Ω)U(g) is strictly smaller than the annihilator: the highest vector of the simple Verma module M(−2) is an eigenvector of h with eigenvalue −2, so h∈Ann⁡C but h∉(Ω)U(g). Thus at the trivial central character the annihilator of the trivial module is not generated by the Casimir relation.

Facts & Assumptions

Given: The Axiom of Choice, g=sl2(C) with basis e,f,h, the trivial module C, and the ideal Ann⁡U(g)C of operators acting by 0 on C.

[F1]

The trivial module is the unital module on which e,f,h act by 0; the corresponding algebra homomorphism is the augmentation ε ⁣:U(g)→C with ε(g)=0, so its kernel is the two-sided ideal generated by g: after killing e,f,h, every nonempty tensor word is zero and the quotient is spanned by 1; ε(1)=1 makes the remaining scalar quotient exactly C (The annihilator of a module over an enveloping algebra, The special linear Lie algebra sl_2).

[F2]

Under AC the center is C[Ω], so ker⁡χ0=(Ω) and U(g)ker⁡χ0=(Ω)U(g); the trivial module is simple and nonzero, so its annihilator is primitive and the center acts on it through the central character χ0 with χ0(Ω)=0, the Casimir eigenvalue of the trivial module (The central reduction of U(sl2) is simple away from the finite-dimensional central characters, The center of the enveloping algebra is polynomial on rank-many generators, The Axiom of Choice, Primitive ideals of an enveloping algebra, A primitive ideal determines a central character, Central character of a Lie algebra module, The quadratic Casimir eigenvalue on a highest-weight module is (λ,λ+2ρ)).

[F3]

M(−2) is a simple Verma module by the Verma irreducibility criterion, since −2+1=−1∉Z>0; its highest vector v−2 satisfies hv−2=−2v−2, and its central character is χ−2, which equals χ0 because the normalized Casimir Ω=ef+fe+12h2 acts on both by 0, by the eigenvalue formula Ω↦λ(λ+2)/2 and −2⋅0/2=0 (Verma modules, The Verma irreducibility criterion from Shapovalov determinants, Highest-weight vectors and cyclic highest-weight modules, The central reduction of U(sl2) is simple away from the finite-dimensional central characters).

[F4]

U(g)ker⁡χλ⊆Ann⁡U(g)M(λ) for every λ (The Verma annihilator contains the central-character ideal).

Verification

technique · direct
1.1F1F2given

By [F1], Ann⁡U(g)C=ker⁡ε=U(g)g=(e,f,h); this is a proper two-sided ideal, and since C is simple and nonzero it is primitive by [F2].

1.2F2algebra

The trivial module has Casimir eigenvalue Ω↦0, so its central character is χ0 with χ0(Ω)=0; by [F2], Ann⁡U(g)C∩Z(U(g))=ker⁡χ0, which contains Ω and is a maximal ideal of Z(U(g)). The two-sided ideal generated by ker⁡χ0 is U(g)ker⁡χ0=(Ω)U(g), contained in the annihilator by [F2].

1.3F3F4algebra

By [F3], χ−2=χ0, so [F4] applied to M(−2) gives (Ω)U(g)⊆Ann⁡U(g)M(−2). The highest vector satisfies hv−2=−2v−2≠0, so h∉Ann⁡U(g)M(−2) and hence h∉(Ω)U(g).

2.1step 1.1step 1.3F1algebra∎

On the other hand h acts on the trivial module by 0, so h∈Ann⁡U(g)C by [F1]. Thus (Ω)U(g)⊊Ann⁡U(g)C: the central ideal does not exhaust the annihilator.

ExampleConstruction: Literature-sourcedVerification: AI-adaptedjudge pass (gpt-6.1-sol)Open item page →

Primitive ideals of U(sl2) at a generic central character

Example

Assume the Axiom of Choice. Let g=sl2(C) and let χ be a central character which is not the central character of any nonzero finite-dimensional U(g)-module. Then the central reduction Uχ is a simple ring, and the unique primitive ideal of U(g) with central character χ is U(g)ker⁡χ: for every λ∈h∗ with χλ=χ the Verma module M(λ) is simple and Ann⁡U(g)M(λ)=U(g)ker⁡χ, so the annihilator is generated by the Casimir relation Ω−χ(Ω) alone. This is the smallest instance of a Duflo annihilator: over a generic central character the primitive ideal is exactly the unavoidable central ideal.

Facts & Assumptions

Given: The Axiom of Choice, g=sl2(C), a central character χ that is not the central character of any nonzero finite-dimensional U(g)-module, and the central reduction Uχ=U(g)/U(g)ker⁡χ.

[F1]

Under AC, Uχ is simple if and only if χ is not a finite-dimensional central character; when Uχ is simple, every nonzero module with central character χ is faithful over Uχ, every Verma module M(λ) with χλ=χ is simple, and Ann⁡U(g)M(λ)=U(g)ker⁡χ (The central reduction of U(sl2) is simple away from the finite-dimensional central characters, The central reduction of the enveloping algebra at a central character, The Axiom of Choice).

[F2]

For every primitive ideal I with central character χ one has I∩Z(U(g))=ker⁡χ and U(g)ker⁡χ⊆I (A primitive ideal determines a central character, Primitive ideals of an enveloping algebra, Central character of a Lie algebra module).

[F3]

The two-sided ideals of Uχ correspond to the two-sided ideals of U(g) containing U(g)ker⁡χ (The central reduction of U(sl2) is simple away from the finite-dimensional central characters, Left, right and two-sided ideals).

[F4]

Put Ω=ef+fe+12h2. Under AC the center of U(g) is C[Ω], so ker⁡χ=(Ω−χ(Ω)) and U(g)ker⁡χ=(Ω−χ(Ω))U(g); moreover Ω acts on M(λ) by λ(λ+2)/2, so every λ with χλ=χ satisfies λ(λ+2)=2χ(Ω), where λ denotes λ(h). Conversely, algebraic closure supplies a root λ of this quadratic; the Casimir eigenvalue then equals χ(Ω), and since Ω generates the center, χλ=χ (The complex numbers are algebraically closed) (The central reduction of U(sl2) is simple away from the finite-dimensional central characters, The quadratic Casimir eigenvalue on a highest-weight module is (λ,λ+2ρ), Verma modules, The special linear Lie algebra sl_2).

Verification

technique · direct
1.1F1given

Since χ is not a finite-dimensional central character, [F1] gives that Uχ is a simple ring with no nonzero proper two-sided ideal.

2.1step 1.1F2F3algebra

Let I be a primitive ideal of U(g) with central character χ. By [F2] one has U(g)ker⁡χ⊆I; the image Iˉ of I in Uχ is therefore a two-sided ideal, hence is 0 or Uχ by step 1.1. If Iˉ=Uχ then I+U(g)ker⁡χ=U(g), so I=U(g) by [F2], contradicting that a primitive ideal is proper; therefore Iˉ=0, i.e. I⊆U(g)ker⁡χ. With the reverse inclusion from [F2], I=U(g)ker⁡χ: the central ideal is the only primitive ideal with central character χ.

3.1step 2.1F1F4algebra∎

By [F4] there exists a weight λ with χλ=χ, so the primitive fibre is nonempty. For any such λ, by [F1] the Verma module M(λ) is simple with Ann⁡U(g)M(λ)=U(g)ker⁡χ, so U(g)ker⁡χ is primitive (indeed it is the annihilator of a simple module) and is the unique primitive ideal over χ by step 2.1. Since ker⁡χ=(Ω−χ(Ω)) in Z(U(g))=C[Ω], the annihilator is the two-sided ideal generated by the single Casimir relation Ω−χ(Ω), so over a generic central character the primitive ideal is exactly the unavoidable central ideal.

Sources