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Anisotropic waves and reciprocity

1 · Prerequisites

2 · Summary

3 · Logical flowchart

4 · Definitions, postulates, theorems and proofs

DefinitionDefinition: AI-adaptedProof: Not applicableverified 2026-10-22 (gpt-6.1-sol)Open item page →

Anisotropic Maxwell symbol

Physical scope

A source-free bulk plane-wave sector of the macroscopic Maxwell model in one fixed material rest frame, with constant real symmetric positive-definite absolute permittivity tensor and constant positive scalar absolute permeability, interpreted as an effective phase-response model only on a declared finite positive-frequency band. The symbol algebra is defined for every positive frequency; no broadband material response or universal front speed is asserted. Interfaces, spatial dispersion, loss, experimental material data and finite-energy conditions are outside this definition.

Definition

Use a material-rest frame: an inertial chart in which each modelled material element has fixed spatial coordinates. Use the macroscopic fields of the classical electromagnetic material model. For physical interpretation declare a finite angular-frequency band Iω=[ω−,ω+] with 0<ω−<ω+<∞, in s−1. The constant-coefficient branch below is adopted as an effective phase-response model only for ω∈Iω, as required by the material-closure postulate; it asserts no broadband material response or universal front speed. The symbol and its algebraic Maxwell equivalence remain defined for every ω>0. In a homogeneous source-free region take ρf=0, Jf=0 and select the nonconducting, lossless constitutive branch

D=εE,B=μH,

where ε∈R3×3 is a constant real symmetric positive-definite absolute permittivity tensor in F m−1, and μ>0 is a constant real scalar absolute permeability in H m−1. These are declared model coefficients, not dimensionless relative coefficients. Here lossless means these coefficients are real and the conductive current density Jc=σE is absent, σ=0; no dispersive or absorbing coefficient is included. Fix right-handed Cartesian coordinates and the phasor convention

E(x,t)=Re⁡ ⁣(e ei(k⋅x−ωt)),B(x,t)=Re⁡ ⁣(b ei(k⋅x−ωt)),

with k∈R3∖{0} in m−1, ω>0 in s−1, and complex amplitudes e,b∈C3. Write d=εe and h=μ−1b for the displacement and magnetic-intensity amplitudes, in C m−2 and A m−1. For complex vectors use the bilinear dot product u⋅v=∑r=13urvr, with no conjugation. The anisotropic Maxwell symbol is the linear map

M(k,ω)e:=k×(μ−1(k×e))+ω2εe.

A nonzero amplitude e is a source-free plane-wave mode in this branch exactly when M(k,ω)e=0; its magnetic amplitudes are b=(k×e)/ω and h=b/μ. The cross product is extended complex-bilinearly. In this model k⋅d=0, while k⋅e need not vanish.

Derivation from the source-free Maxwell equations

For the real plane-wave fields above, the source-free macroscopic equations are curl⁡E=−∂tB, curl⁡H=∂tD, div⁡B=0, and div⁡D=0. Their phasor amplitudes are k×e=ωb, k×h=−ωd, k⋅b=0, and k⋅d=0: spatial differentiation multiplies the common phase by ik, time differentiation by −iω, and equality of the real encodings for all (x,t) forces equality of their complex amplitudes.

With d=εe and h=μ−1b, the first curl equation gives b=(k×e)/ω. Substitution into the second gives M(k,ω)e=0. Conversely, if this symbol equation holds, define b=(k×e)/ω and h=b/μ. The first curl equation then holds by definition, and the second is the symbol equation divided by ω. Taking the dot product of the symbol equation with k gives ω2k⋅εe=0, hence k⋅d=0; also k⋅b=0 because k⋅(k×e)=0. Thus the symbol equation is equivalent to the source-free plane-wave Maxwell amplitude system under the declared coefficients and convention. It is a conditional model formulation, not evidence that any substance realizes these coefficients.

DefinitionDefinition: AI-adaptedProof: Not applicableverified 2026-10-22 (gpt-6.1-sol)Open item page →

Fixed-frequency reciprocal tensor medium

Physical scope

A local, linear, fixed-frequency macroscopic phasor model in a material-rest frame, on a bounded C1 Euclidean region, with continuous possibly complex tensor coefficients and C1 solution phasors. This definition imposes transpose symmetry as the reciprocal-coefficient condition; it does not assert causality, passivity, losslessness, existence, uniqueness, or empirical realization.

Definition

Fix a real angular frequency ω∈R and a bounded open region Ω⊂R3 with C1 boundary in a material-rest frame. Here a material-rest frame is the inertial frame in which every modelled material element has fixed spatial coordinates, as stipulated by the framework's material-closure postulate. A map in C1(Ω‾) means the restriction of a C1 map on an open neighborhood of Ω‾. Let ε,μ:Ω‾→C3×3 be continuous coefficient fields with units F m−1 and H m−1. They may be spatially varying and complex. Let Ej,Hj∈C1(Ω‾;C3) and Jj∈C0(Ω‾;C3), for j=1,2, be phasor amplitudes with SI units V m−1, A m−1, and A m−2. The corresponding real fields use e−iωt, for example Ejreal(x,t)=Re⁡(Ej(x)e−iωt). Their displacement and magnetic-induction amplitudes are Dj=εEj in C m−2 and Bj=μHj in T.

The fixed-frequency constitutive and source equations are

Dj=εEj,Bj=μHj,curl⁡Ej=iωBj,curl⁡Hj=Jj−iωDj.

All operators act componentwise on the spatial variable. For u,v∈C3, define the bilinear dot product u⋅v=∑r=13urvr and the complex-bilinear cross product by the usual right-handed component formula. Neither product conjugates either input. The transpose T is the ordinary matrix transpose, without complex conjugation. This definition calls the coefficient model reciprocal when ε(x)T=ε(x) and μ(x)T=μ(x) at every x∈Ω‾. It places no Hermitian, positive-definite, or passivity condition on these complex matrices.

This is a fixed-frequency phasor data class. Its possibly complex coefficients are not inferred from the framework's real, instantaneous material branch; a separate response model is required to justify any such interpretation.

Physics theoremStatement: AI-adaptedProof: AI-adaptedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Ordinary and extraordinary sheets

Physical scope

Conditional classification of nonzero real-wavevector source-free bulk plane-wave modes in a homogeneous lossless uniaxial dielectric with positive real principal permittivities and positive scalar permeability, in the material-rest frame and SI units. The general uniaxial classification uses the xz-plane section; the isotropic specialization covers all real-wavevector directions. Physical use is restricted to a declared finite positive-frequency band of effective phase response. Interfaces, absorption, spatial dispersion and empirical material claims are outside scope.

Statement

In the homogeneous lossless plane-wave model, let ε=diag⁡(ε⊥,ε⊥,ε∥) with ε⊥,ε∥>0 in F m−1, let μ>0 be a scalar in H m−1, and let ω>0 be in s−1. For a nonzero source-free mode with real wavevector k=(kx,0,kz)≠0 in m−1, the nonzero-mode wavevectors lie on exactly the following two sheets:

kx2+kz2=με⊥ω2,kx2ε∥+kz2ε⊥=μω2.

Away from an intersection the first sheet is the ordinary sector, whose electric amplitude is parallel to y^, and the second is the extraordinary sector, whose electric amplitude lies in the xz plane; each then has a one-dimensional polarization space. At an intersection the two sectors span a two-dimensional polarization space. If ε⊥=ε∥=ε, the isotropic specialization also allows arbitrary real k≠0, without the xz-plane restriction: its nonzero-mode wavevectors lie in every direction on the common sphere ∣k∣2=μεω2, and at every such wavevector the polarization space is the two-dimensional complex subspace {e∈C3:k⋅e=0}. In the xz section the ordinary/extraordinary labels then denote the two coordinate sectors, not distinct dispersion branches. If ε⊥≠ε∥, the sheets intersect only for kx=0 and kz2=με⊥ω2; at those optic-axis directions the polarization space is again two-dimensional. The zero amplitude is not a mode in this statement.

The symbol classification holds algebraically for every ω>0. For physical interpretation, declare a finite band Iω=[ω−,ω+] with 0<ω−<ω+<∞, in s−1, and use the constant-coefficient model only for ω∈Iω, as in its defining material closure.

Statement references

Facts & Assumptions

Given: The fixed material-rest frame, right-handed Cartesian axes, SI units, positive coefficients, real wavevector, positive angular frequency and nonzero plane-wave amplitude stated above.

[L1]

Anisotropic Maxwell symbol defines the source-free anisotropic plane-mode equation as μ−1k×(k×e)+ω2εe=0, with d=εe, k⋅d=0, and e≠0.

Proof

1.1givenL1algebra

Write e=(ex,ey,ez). Substituting the stated diagonal tensor and k=(kx,0,kz) into [L1], and expanding the cross products componentwise, gives (ω2ε⊥−kz2/μ0kxkz/μ0ω2ε⊥−(kx2+kz2)/μ0kxkz/μ0ω2ε∥−kx2/μ)(exeyez)=0.

1.2givenL1algebra

If ey≠0, the middle row gives kx2+kz2=με⊥ω2. If (ex,ez)≠(0,0), the xz block must be singular, and its determinant is ω2ε⊥ε∥μ(μω2−kx2ε∥−kz2ε⊥), so it vanishes exactly on the second sheet. Conversely, on the first sheet (0,1,0) is a nonzero kernel vector, and on the second sheet the singular xz block has a nonzero kernel vector. Since the matrix separates the y and xz sectors, these are all nonzero modes. Away from an intersection, the xz block is invertible on the first sheet, so its kernel is exactly the y line. On the second sheet, away from an intersection, the middle coefficient is nonzero and the singular xz block has rank one: its off-diagonal entry is nonzero when kxkz≠0, while on either coordinate axis its other diagonal entry is respectively ω2ε∥ or ω2ε⊥, both positive. Thus both polarization spaces are one-dimensional away from intersections.

2.1givenL1step 1.1step 1.2algebra∎

At an intersection with ε⊥≠ε∥, dividing the first sheet by ε⊥ and subtracting the second gives kx2(1/ε⊥−1/ε∥)=0, hence kx=0; either sheet then gives kz2=με⊥ω2. Conversely, substituting these values into both sheets verifies an intersection. The matrix in step 1.1 is then diag⁡(0,0,ω2ε∥), so its kernel is the complex span of x^,y^. For ε⊥=ε∥=ε, take any real k∈R3∖{0}. Expanding the cross products in [L1] gives M(k,ω)=(εω2−∣k∣2/μ)I3+kkT/μ. Every complex amplitude has the direct decomposition e=e∥+e⊥, where e∥=k(k⋅e)/∣k∣2 and k⋅e⊥=0; the denominator is positive since k is real and nonzero. The symbol acts by Me∥=εω2e∥ and Me⊥=(εω2−∣k∣2/μ)e⊥. Because εω2>0, a nonzero kernel occurs exactly on ∣k∣2=μεω2, and there it is precisely k⊥={e:k⋅e=0}. This complex space has dimension two: choose an index with ki≠0 and solve its one linear equation for ei in terms of the other two complex coordinates. For every real unit direction n, taking k=ωμε n gives a point on that sphere. In the xz section this kernel is the sum of the y and transverse xz coordinate sectors, verifying the common-circle section as well as the full-sphere claim. This proves the stated degeneracies and completes the conditional model classification.

Diagram

For the representative positive-uniaxial ratio ε∥=2ε⊥, normalize both wavevector coordinates by ωμε⊥. The ordinary cross-section is the unit circle; the extraordinary cross-section is the ellipse ux2/2+uz2=1. They intersect at the two optic-axis points (0,±1). The drawing is a normalized cross-section of the two exact equations in the Statement; the proof does not rely on it.

\begin{tikzpicture}[scale=1.25,>=stealth]
  \draw[->] (-1.8,0) -- (1.8,0) node[right] {$u_x$};
  \draw[->] (0,-1.45) -- (0,1.45) node[above] {$u_z$};
  \draw[thick,blue] (0,0) circle (1);
  \draw[thick,red,dashed] (0,0) ellipse [x radius=1.414,y radius=1];
  \fill (0,1) circle (1.4pt);
  \fill (0,-1) circle (1.4pt);
  \node[blue] at (-1.05,0.75) {ordinary};
  \node[red] at (1.15,0.78) {extraordinary};
  \node[below left] at (0,0) {$0$};
\end{tikzpicture}
Physics theoremStatement: AI-adaptedProof: AI-adaptedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Reciprocity in reciprocal linear media

Physical scope

Conditional fixed-frequency reciprocity identity in the local linear macroscopic phasor model on a bounded C1 Euclidean domain, for C1 phasor solutions, continuous sources and pointwise transpose-symmetric possibly complex constitutive tensors. The result requires no passivity or losslessness and asserts no field existence, uniqueness, causal material response or empirical validity.

Statement

Assume ACω. Let Ω⊂R3 be a bounded domain with C1 boundary and outward unit normal n. Fix a real angular frequency ω in s−1. Let Ej,Hj∈C1(Ω‾;C3) and Jj∈C0(Ω‾;C3), for j=1,2, be phasor fields and electric-current densities in V m−1, A m−1, and A m−2, respectively. Suppose both pairs solve the fixed-frequency Maxwell equations there with the same continuous coefficient maps ε,μ:Ω‾→C3×3 and ε(x)T=ε(x), μ(x)T=μ(x) at every x. Use Euclidean volume measure dV and boundary area measure dS. Then

∫∂Ωn⋅(E1×H2−E2×H1) dS=∫Ω(E2⋅J1−E1⋅J2) dV.

The dot and cross products in this identity are the complex-bilinear products defined in the reciprocal phasor model; no complex conjugation occurs. Both integrals have units W. In particular, the real symmetric positive permittivity tensor and positive scalar permeability of the lossless anisotropic plane-wave model satisfy these reciprocal-coefficient hypotheses, so the algebraic identity applies to any two such phasor solutions restricted to a bounded C1 subdomain. Physical use of that anisotropic branch is restricted to its declared finite positive-frequency band Iω=[ω−,ω+], 0<ω−<ω+<∞; the reciprocity identity itself asserts no broadband material response.

Facts & Assumptions

Given: ACω, the bounded C1 domain, the real frequency, C1 phasor fields, continuous sources, common complex constitutive tensors and their pointwise transpose symmetry stated above.

[A1]

ACω is the axiom that every countable family of nonempty sets has a choice function; it is assumed by the divergence-theorem supplier used here (The Axiom of Countable Choice (ACω)).

[F1]

For real C1 vector fields F,G, div⁡(F×G)=G⋅curl⁡F−F⋅curl⁡G (The divergence and curl of a cross product).

[F2]

For a bounded C1 domain and F∈C1(Ω‾;R3), ∫Ωdiv⁡F dV=∫∂ΩF⋅n dS, under ACω (Divergence on a bounded C1 Euclidean domain).

[L1]

In the reciprocal phasor model, Dj=εEj, Bj=μHj, curl⁡Ej=iωBj, and curl⁡Hj=Jj−iωDj; reciprocal coefficients mean the ordinary pointwise transpose equalities εT=ε and μT=μ, even when the entries are complex (Fixed-frequency reciprocal tensor medium).

[L2]

In the lossless anisotropic plane-wave branch, ε is real symmetric positive definite and μ is a positive real scalar; its physical phase-response interpretation is restricted to the declared finite band Iω (Anisotropic Maxwell symbol).

Proof

1.1givenF1L1algebra

Put X=E1×H2−E2×H1. For the first product write E1=U+iV and H2=W+iZ with real C1 fields. The complex-bilinear product is E1×H2=(U×W−V×Z)+i(U×Z+V×W); applying [F1] to each real pair and using the componentwise real-linearity of curl and divergence gives div⁡(E1×H2)=H2⋅curl⁡E1−E1⋅curl⁡H2. The same expansion for E2×H1 yields div⁡X=H2⋅curl⁡E1−E1⋅curl⁡H2−H1⋅curl⁡E2+E2⋅curl⁡H1. Substituting [L1] yields E2⋅J1−E1⋅J2+iω(H2⋅μH1−H1⋅μH2+E1⋅εE2−E2⋅εE1). For any complex vectors u,v, u⋅εv=∑r,surεrsvs=v⋅εu by swapping r,s and using εrs=εsr; the same calculation applies to μ. Thus the tensor terms cancel without conjugation and div⁡X=E2⋅J1−E1⋅J2.

2.1givenA1F2step 1.1algebra

The field X is C1 on Ω‾. Apply [F2] separately to its real and imaginary parts, which satisfy the theorem's real-valued hypotheses, and combine the two identities complex-linearly. Substituting step 1.1 into the resulting equality gives the displayed boundary identity.

3.1givenL1L2step 2.1∎

By [L2], the lossless anisotropic plane-wave branch has a real symmetric tensor ε and scalar μ; therefore its ordinary transposes equal themselves, so it is a subcase of the coefficient class in [L1]. Applying step 2.1 to any two C1 phasor solutions in that subcase proves the anisotropic specialization, with its physical use restricted to the finite band in [L2].

Remarks

The symmetric conditions use transpose, not conjugate transpose. Positive absorption can therefore coexist with this reciprocity identity; the identity alone asserts neither losslessness nor time-reversal invariance.

5 · Examples, experiments and counterexamples

None yet.

Sources