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Complete symmetrized constant-coefficient evolution

1 · Prerequisites

2 · Summary

This page first constructs the global smooth evolution for constant matrix systems with a positive symmetrizer and nonnegative damping, including its weighted energy estimate and finite propagation bound. It then applies that theorem to a frozen adiabatic sound system and a corrected bulk-relaxation system. Every conclusion is conditional on the displayed mathematical hypotheses; the linear analysis does not assert a nonlinear fluid evolution theorem.

3 · Logical flowchart

4 · Definitions, postulates, theorems and proofs

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Complete symmetrized constant-coefficient evolution

Statement

Assume countable choice. Let m≥1, let U:R×R3→Rm, and let A1,A2,A3,B,M∈Rm×m be constant matrices. Assume M=MT is positive definite, each MAj is symmetric, and S:=(MB+BTM)/2 is positive semidefinite. Consider

∂tU+∑j=13Aj∂xjU+BU=0.

Use Schwartz space and its seminorms: for f∈C∞(R3;C) and multi-indices α,β∈N3, the scalar seminorm is pαβ(f):=sup⁡x∈R3∣xα∂βf(x)∣, and S(R3) consists of functions for which all these seminorms are finite. Here S(R3;Rm) means maps U=(U1,…,Um) with real-valued components such that each component, viewed as complex-valued with zero imaginary part, belongs to S(R3); its vector seminorms are pαβ(m)(U):=max⁡1≤ℓ≤mpαβ(Uℓ). For U0∈S(R3;Rm) there is a unique global smooth solution, Schwartz in x at each time and continuous in every pαβ(m) on compact time intervals. With the negative-sign, 2π-normalized Fourier transform, put U^(ξ)=∫R3e−2πix⋅ξU(x) dx and define, for s≥0,

∥U∥HMs2:=∫R3(1+∣ξ∣2)sU^(ξ)∗MU^(ξ) dξ.

For t≥0, ∥U(t)∥HMs≤∥U0∥HMs for every s≥0; hence the solution depends continuously on the data in each such norm. The same conclusions hold for smooth periodic data on the flat torus TL3:=(R/LZ)3, L>0, with Fourier coefficients U^k=L−3∫[0,L]3U(x)e−2πik⋅x/L dx and

∥U∥HMs(TL3)2:=∑k∈Z3(1+∣k/L∣2)sU^k∗MU^k.

For periodic data, ∥U(t)∥∞≤Cs,L,M∥U0∥HMs(TL3) for each integer s>3/2.

For a unit vector ν∈R3, write A(ν)=∑jνjAj and A~(ν)=M1/2A(ν)M−1/2. The finite speed

v∗:=sup⁡∣ν∣=1max⁡{∣λ∣:λ∈spec⁡(A~(ν))}

is finite. If v∗>0, R>v∗t, and U0 vanishes on BR(x0), then U(t) vanishes on BR−v∗t(x0) for 0≤t<R/v∗. The same assertion holds on TL3 using its geodesic distance. If v∗=0, every Aj=0 and the system is a pointwise linear ODE, so spatial support does not move. These are conclusions for the displayed linear systems; no variable-coefficient or nonlinear existence claim is included.

Facts & Assumptions

Given: m≥1, constant real matrices Aj,B,M with the stated symmetry and positivity conditions, U0∈S(R3;Rm) or U0∈C∞(TL3;Rm), and L>0 in the periodic case. Use the Fourier convention fixed in the Statement.

[A1]

Countable choice ACω is assumed, with no stronger choice principle (The Axiom of Countable Choice (ACω)). It is the choice strength carried by the Fourier and divergence suppliers below.

[F1]

Fourier transform acts continuously on Schwartz space: the negative-sign, 2π-normalized Fourier transform maps S(R3) continuously into itself.

[F2]

Fourier inversion on Schwartz space: for f∈S(R3), f(x)=∫f^(ξ)e2πix⋅ξ dξ absolutely for every x.

[F3]

Plancherel theorem: under ACω, the same transform extends uniquely to a unitary map on complex L2(R3).

[F4]

Fourier transform agrees with l one and plancherel transforms: the integral and Plancherel transforms agree as tempered distributions on L1 and L2 inputs, so the Schwartz Fourier-mode construction has the stated distributional and L2 meanings.

[F5]

Divergence on a bounded C1 Euclidean domain: under ACω, a C1 vector field on the closure of a bounded C1 domain in Rn, n≥2, satisfies ∫Ωdiv⁡F=∫∂ΩF⋅ν dS with the outward normal and Euclidean surface measure.

[F6]

Schwartz space and its seminorms defines the scalar complex Schwartz space by the seminorms pαβ above. The real Rm-valued data class and its seminorms in the Statement are the componentwise real subspace, with the finite maximum convention stated there.

Proof

1.1givenalgebra

For any real symmetric matrix H, maximize zTHz on the compact unit sphere. Differentiating along every tangent direction shows the maximizing vector is an eigenvector; its orthogonal complement is invariant under H, so induction gives an orthonormal eigenbasis. Applying this to M constructs M1/2 and M−1/2. The condition MAj=AjTM makes A~j=M1/2AjM−1/2 symmetric. Therefore each eigenvalue in v∗ is real and has absolute value at most ∑j∥A~j∥, so v∗<∞. With e=UTMU/2 and Fj=UTMAjU/2, the product rule gives ∂te+∑j∂xjFj=−UTSU≤0 for every smooth solution, and ∣F⋅ν∣≤v∗e by diagonalizing A~(ν).

1.2A1F1givenalgebraF6

For Schwartz data, [F1] permits componentwise Fourier transformation of the system, giving ∂tU^=C(ξ)U^ with C(ξ)=−2πi∑jξjAj−B. The matrix exponential E(t,ξ)=etC(ξ), defined by its locally uniformly convergent power series, solves this finite-dimensional ODE. For z(t)=E(t,ξ)z0, ddt(z∗Mz)=−2z∗Sz≤0, because MA(ξ) is real symmetric and its multiple by −i has zero real quadratic part. Thus ∥E(t,ξ)∥M≤1 for t≥0, uniformly in ξ; for t<0, ∣ddt(z∗Mz)∣≤2∥M−1/2SM−1/2∥z∗Mz, so Grönwall gives a uniform eC∣t∣ bound on bounded time intervals.

2.1A1step 1.2F1algebraF6

Differentiating the matrix exponential with respect to ξj gives ∂ξjE(t,ξ)=∫0tE(t−s,ξ)(−2πiAj)E(s,ξ) ds. Repeating this identity expresses every fixed ξ-derivative as a finite sum of ordered insertion integrals with constant matrix factors between evolution matrices. The uniform bounds from step 1.2 and the finite integration-simplex volumes bound each such derivative uniformly in ξ on compact time intervals. Time derivatives multiply by C(ξ) and therefore have at most polynomial growth in ξ. Leibniz's rule now shows E(t,⋅)U^0 is Schwartz, uniformly in its seminorms on compact time intervals.

2.2step 1.2algebra

For periodic smooth data, integration by parts in a coordinate with maximal ∣kj∣ gives ∣U^k(0)∣≤CN(1+∣k∣)−N for every N. The series U(t,x)=∑k∈Z3e2πik⋅x/LE(t,k/L)U^k(0) and every differentiated series converge uniformly on compact time intervals, by the same matrix-exponential derivative bounds and the lattice-shell estimate that a unit-width shell in Z3 has O((1+r)2) points. Hence it is a global smooth periodic solution and solves the PDE termwise. The modewise M-estimate from step 1.2 yields contraction of every weighted coefficient norm. For s>3/2, Cauchy–Schwarz and M≥λmin⁡(M)I give ∑k∣U^k(t)∣≤λmin⁡(M)−1/2(∑k(1+∣k/L∣2)−s)1/2(∑k(1+∣k/L∣2)sU^k(t)∗MU^k(t))1/2; the first sum converges by the shell bound, proving the asserted uniform norm estimate. Integrating the equation against each periodic exponential shows that every solution coefficient solves the same finite-dimensional ODE, proving uniqueness.

3.1A1F2step 2.1algebra

Define U(t)=F−1(E(t,⋅)U^0). By [F2] this inverse is pointwise the absolutely convergent Fourier integral; the decay proved in step 2.1 permits every spatial and time derivative to pass under that integral, proves the PDE, and recovers U(0)=U0. Conjugation symmetry of C(ξ) and U^0(−ξ)=U^0(ξ)‾ makes U real.

4.1A1F3F4step 1.2step 3.1algebra

By [F3] the Plancherel transform is unitary, and [F4] identifies it with the integral transform in S′. Multiplying the pointwise M-norm estimate in step 1.2 by (1+∣ξ∣2)s and integrating gives the stated HMs contraction for every s≥0.

5.1A1F5step 1.1algebra∎

Fix t∗>0, x∗, and 0≤t<t∗. Put R(t)=v∗(t∗−t) and E(t)=∫BR(t)(x∗)e(t,x) dx. In polar coordinates, the fundamental theorem of calculus differentiates this moving-ball integral; the PDE energy identity and [F5] then give E′(t)=−∫∂BR(t)(F⋅ν+v∗e) dS−∫BR(t)UTSU dx≤0, since ∣F⋅ν∣≤v∗e. If the initial data vanish on Bv∗t∗(x∗), then E(0)=0; positivity of M and E(t)≥0 force U(t,x∗)=0 by continuity as t↑t∗. For any x with ∣x−x0∣<R−v∗t∗, the ball Bv∗t∗(x) is contained in BR(x0), proving the stated shrinking-ball conclusion. Applying the same argument to the difference of two solutions proves local uniqueness. Periodic lifts give the identical geodesic-ball conclusion on TL3. If v∗=0, every symmetric A~j has zero spectrum and hence is zero, so each Aj=0; the pointwise ODE preserves spatial support.

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Perfect sound characteristic and actual stable causal linear branch

Statement

Fix c>0 and take M=R4 with global length coordinates (x0,x1,x2,x3)=(ct,x), metric η=diag⁡(−1,1,1,1), and future causal cone {V∈R4:V0≥0, ηabVaVb≤0}. For V=(V0,V)∈R4 with V0>0, define its coordinate velocity by v(V):=cV/V0. Since η(V,V)=(V0)2(∣v(V)∣2/c2−1), membership in this cone is equivalent to ∣v(V)∣≤c, with equality on its nonzero null boundary. The zero vector belongs to the cone but has no coordinate velocity under this definition. The constant rest observer is uˉ=(1,0,0,0).

Let X⊂(0,∞)×R be open, let e∈C2(X;R), and fix (v0,σp0)∈X. Define n0:=1/v0, ϵ0:=n0e(v0,σp0), p0:=−ev(v0,σp0), T0:=eσp(v0,σp0), and h0:=ϵ0+p0. Assume n0,T0,h0,evv>0, with evv evaluated at fixed σp. A first variation is defined by a family of state maps (vλ,σp,λ):M→X and fields uλ:M→R4, jointly smooth in dimensionless λ near 0 and in x, with the displayed reference state and uˉ as their constant λ=0 values and with η(uλ,uλ)=−1, uλ0>0. For any such field fλ, write δf:=∂λfλ∣λ=0; put r:=δϵ, w:=(δu1,δu2,δu3), and impose the adiabatic first-variation condition δσp=0. The linearized equations mean the first variations at λ=0 of the no-force balances ∂aTλab=0 and ∂aJλa=0, with nλ=1/vλ, ϵλ=nλe(vλ,σp,λ), pλ=−ev(vλ,σp,λ), Δλab=ηab+uλauλb, Tλab=ϵλuλauλb+pλΔλab, and Jλa=nλuλa; no member with λ≠0 is required to solve the nonlinear balances. Differentiating η(uλ,uλ)=−1 gives δu0=0.

The local Gibbs identity of Local Gibbs, Euler, parcel first law and response identities gives

as:=(∂p∂ϵ)σp=evv(v0,σp0)n0h0,

and assume additionally as≤1. In the adopted units, c has units m s−1, r and h0 have units Pa, and w and as are dimensionless. Since x0=ct and uˉ=∂x0, the first variations of the no-force perfect-fluid projection equations of Perfect stress and particle balances with entropy identity are

rt+ch0div⁡w=0,wt+cash0∇r=0.

For initial data U0=(r0,w0) whose real components belong componentwise to S(R3) as defined by Schwartz space and its seminorms, or for smooth periodic data on TL3 with L>0, these equations have the unique global smooth solution supplied by Complete symmetrized constant-coefficient evolution. The positive quadratic energy density E=12[(as/h0)r2+h0∣w∣2] has flux casrw, and the solution is contractive in the corresponding weighted L2 and Sobolev norms. Its characteristic speeds are 0 and ±cas; for positive as, this propagation cone lies inside the Minkowski reference cone exactly when as≤1. These are statements about this frozen linear system only; they do not assert a nonlinear or curved-spacetime evolution theorem.

For the formal coefficient comparison in [A3], if the same linear equations are assigned as>1, their plane-wave speed is cas>c. If they are assigned as<0, smooth periodic modes grow as ec−as∣k∣t at arbitrarily large wave numbers. The case as=0 is degenerate: the displayed positive energy matrix is no longer positive definite, so the stability proof above does not apply.

Facts & Assumptions

Given: The reference state, first-variation convention, Minkowski geometry, and coefficient hypotheses in the Statement.

[A1]

The reference speed condition as≤1 is an additional hypothesis for the causal branch, not a consequence of evv>0 or h0>0.

[A2]

Countable choice ACω is carried by the geometric and Fourier suppliers; no stronger choice principle is assumed (The Axiom of Countable Choice (ACω)).

[A3]

For the coefficient comparisons in the final paragraph only, consider the same two displayed linear equations with h0,c>0 and as∈R. These are coefficient-only comparisons, not claims that the parameters are realized by a material: as>1 drops the causal-branch hypothesis as≤1, and as<0 also drops the positive-response hypothesis evv>0.

[F1]

Perfect stress and particle balances with entropy identity (current batch-55 draft): for the smooth (−,+,+,+) Lorentzian data and fixed-composition state, ∇aTab=0 and ∇a(nua)=0 imply Dϵ+hθ=0, haaccb+Δba∇ap=0, and Dn+nθ=0. Its proof is conditional on the current draft state and Gibbs carriers; no independent proof acceptance is inferred.

[F2]

Local Gibbs, Euler, parcel first law and response identities (current batch-53 draft): for an open state domain and e∈C2(X), it gives dϵ=T ds+μ dn and h=Ts+μn. At fixed σp, ∂nϵ=h/n and ∂np=evv/n2; when evv>0 and h>0, as=evv/(nh)>0. This use is conditional on those hypotheses and the current draft Gibbs carrier; authoring readiness does not establish proof acceptance.

[F3]

Complete symmetrized constant-coefficient evolution: for constant matrices with positive symmetrizer M, symmetric MAj, and nonnegative symmetrized damping, the system has a unique global smooth solution for componentwise real Schwartz or smooth periodic data, with contraction and finite propagation at the largest absolute eigenvalue of M1/2A(ν)M−1/2 over unit directions.

[F4]

Schwartz space and its seminorms: scalar Schwartz functions are smooth complex-valued functions with every seminorm sup⁡x∣xα∂βf(x)∣ finite; the Statement uses the componentwise real-valued subspace for vector data.

Proof

1.1A2F1F2givenalgebra

The family is normalized by η(uλ,uλ)=−1 and is future-directed, so at λ=0 it has u0=uˉ and differentiating normalization gives δu0=0. Since ∂0=c−1∂t, the first variation of Dϵ is c−1rt, that of θ is div⁡w, and that of the spatial acceleration is c−1∂tw. By [F2], δp=asr and δn=(n0/h0)r. Taking first variations of the energy and spatial equations in [F1] therefore gives rt+ch0div⁡w=0 and wt+(cas/h0)∇r=0; the particle equation follows from δn=(n0/h0)r and the first equation.

2.1A2F3step 1.1algebraF4

Put U=(r,w) and M=diag⁡(as/h0,h0I3). The matrix M is positive definite because as,h0>0. For each j, define Aj by (Aj)r,wj=ch0, (Aj)wj,r=cas/h0, with all other entries zero. Then MAj is symmetric. In a unit direction ν, the longitudinal block of A(ν) on (r,w⋅ν) has eigenvalues ±cas and the two transverse components have eigenvalue 0. Thus [F3] constructs the actual global smooth solution and yields its uniqueness, contraction, and propagation speed cas.

3.1A1step 2.1algebra

Direct multiplication of the equations by (as/h0)r and h0w gives ∂tE+div⁡(casrw)=0. For a unit normal ν, ∣casr w⋅ν∣≤cas E by 2XY≤X2+Y2 with X=as/h0∣r∣ and Y=h0∣w∣. Since 0<as≤1, this flux cone lies inside the reference cone of speed c.

4.1A3algebra∎

Under the formal coefficient convention [A3], for k≠0 and as>0, r=Acos⁡(k⋅x−ωt), w=(ωA/(ch0∣k∣2))kcos⁡(k⋅x−ωt) solves both equations when ω2=c2as∣k∣2; substitution gives both equalities. Hence as>1 has exact modes with speed greater than c. If as<0, put λ=c−as∣k∣ and take r=Aeλtcos⁡(k⋅x), w=−(λA/(ch0∣k∣2))keλtsin⁡(k⋅x); differentiating verifies both equations and gives unbounded growth rates as ∣k∣→∞. At as=0 the weight as/h0 vanishes, so the positive-definite argument in step 2.1 is inapplicable.

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Corrected bulk relaxation and exact extended entropy

Statement

Use the smooth (−,+,+,+) Lorentzian data, local state, and conventions of Perfect stress and particle balances with entropy identity and Frame-qualified dissipative entropy cancellation, with n>0, T>0, c>0, x0=ct, and smooth future unit u. On the nonempty open spacetime domain O of those suppliers, let ζ,τ∈C1(O;(0,∞)) be scalar coefficient fields, set β:=τ/ζ∈C1(O;(0,∞)), and let Π:O→R be smooth. In the bulk-only branch take

Tab=ϵuaub+(p+Π)Δab,Ja=nua,∇aTab=0,∇aJa=0,

where Δab=gab+uaub, D=ua∇a, θ=∇aua, and aaccb=Dub. Adopt the corrected relaxation law

βDΠ+Πζc=−θ−TΠ2∇a ⁣(βuaT)

and the extended entropy current Sa=[s−βΠ2/(2T)]ua. Then the stress and particle equations imply

Dϵ+(h+Π)θ=0,(h+Π)aaccb+Δba∇a(p+Π)=0,Dn+nθ=0,

and every actual smooth solution of the stated corrected law satisfies

∇aSa=Π2ζcT≥0.

Here β has units Pa−1, Π,ϵ,p,h have units Pa, D,θ,aacc have inverse-length components, and the correction βΠ2/(2T) has the units of entropy density. The law is an explicit model assumption; dropping its derivative term does not yield the stated sign identity in general.

There is an exact homogeneous solution on the explicitly specified Minkowski spacetime M=R4 with global length coordinates (x0,x1,x2,x3)=(ct,x1,x2,x3), metric η=diag⁡(−1,1,1,1), and future direction ∂x0; its Levi-Civita derivative is ordinary coordinate differentiation. Fix a state point (v0,σp0) in the supplied local state domain with v0>0 and T0=eσp(v0,σp0)>0, and take the constant state map (v,σp)(x)=(v0,σp0), so n0=1/v0, ϵ0=n0e(v0,σp0), and p0=−ev(v0,σp0) are constant. For constant positive coefficients ζ0,τ0, let u=∂x0=(1,0,0,0), T=T0, and define the smooth scalar field Π(x)=Π0e−t/τ0 on all of M, where t=x0/c. The stress and particle balances and the corrected law hold, with strict entropy production wherever Π(x)≠0. This mathematical witness is not a general nonlinear existence theorem or a claim of physical applicability in any separately selected near-equilibrium regime.

Facts & Assumptions

Given: The smooth state and metric data specified above, coefficient fields ζ,τ∈C1(O;(0,∞)), smooth bulk scalar Π:O→R, the displayed stress and particle balances, and the displayed corrected relaxation law. All derivatives are classical; no solution existence is assumed beyond any particular smooth field set under discussion.

[A1]

Countable choice ACω is the only choice strength in the geometric supplier chain (The Axiom of Countable Choice (ACω)).

[F1]

Perfect stress and particle balances with entropy identity (current batch-55 draft): for a smooth fixed-composition state and arbitrary smooth force f, the perfect stress T0ab=ϵuaub+pΔab and Ja=nua satisfy Dϵ+hθ=−ubfb, haaccb+Δba∇ap=Δbcfc, and ∇aJa=0  ⟺  Dn+nθ=0. This use is conditional on the current draft state and Gibbs carriers; no independent proof acceptance is inferred.

[F2]

Frame-qualified dissipative entropy cancellation (current batch-55 draft): for the smooth dissipative stress with bulk pressure Π, zero heat flux, zero particle diffusion, zero shear, force f=0, and ∇aJa=0, the entropy current su obeys ∇a(sua)=−Πθ/T. Its proof body is complete conditional on the same current draft state/Gibbs interfaces; authoring readiness does not establish proof acceptance.

Proof

1.1A1F1givenalgebra

Put T0ab=ϵuaub+pΔab and define fb:=∇aT0ab=−∇a(ΠΔab). Since ∇g=0, ∇aΔab=θub+aaccb, so ∇a(ΠΔab)=Δba∇aΠ+Π(θub+aaccb). Apply [F1] to T0 with this force: contracting the force term with ub yields Dϵ+hθ=−Πθ, while its spatial projection gives haaccb+Δba∇ap=−Δba∇aΠ−Πaaccb. The particle balance is unchanged. Rearrangement gives the three projected equations in the Statement.

1.2A1F2givenalgebra

Apply [F2] to the full bulk-only stress and particle balance with zero force; it gives ∇a(sua)=−Πθ/T. Product differentiation of the correction gives ∇a[(βΠ2/(2T))ua]=βΠDΠ/T+(Π2/2)∇a(βua/T). Therefore ∇aSa=−(Π/T)[θ+βDΠ+(TΠ/2)∇a(βua/T)]. The corrected law makes the bracket −Π/(ζc), proving ∇aSa=Π2/(ζcT)≥0 because ζ,c,T>0.

2.1givenstep 1.2algebra∎

For the homogeneous witness, constant n,σp,T,ϵ,p,u give ∇aJa=0 and ∇aTa0=0, ∇aTai=∂i(p+Π)=0. Also DΠ=c−1∂tΠ=−Π/(cτ), θ=0, and ∇a(βua/T)=0, so the two terms on the left of the corrected law cancel and its right side vanishes. The entropy formula in step 1.2 is strict when Π0≠0. If a chosen near-equilibrium domain bounds ∣Π∣, any sufficiently small ∣Π0∣ remains in it for t≥0.

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Bulk linear relaxation energy, stability and causal speed

Statement

Use M=R4 with global length coordinates (x0,x1,x2,x3)=(ct,x), metric η=diag⁡(−1,1,1,1), future direction ∂x0, and reference causal cone {V∈R4:V0≥0, ηabVaVb≤0}. For V=(V0,V) with V0>0, define v(V):=cV/V0; then η(V,V)=(V0)2(∣v(V)∣2/c2−1), so cone membership is equivalent to ∣v(V)∣≤c, with equality on its nonzero null boundary. The zero vector belongs to the cone but has no coordinate velocity under this definition. Let X⊂(0,∞)×R be open, e∈C2(X;R), and (v0,σp0)∈X. Define n0:=1/v0, ϵ0:=n0e(v0,σp0), p0:=−ev(v0,σp0), T0:=eσp(v0,σp0), and h0:=ϵ0+p0. The background fields are this constant state, u0=∂x0=(1,0,0,0), and Π0=0. Assume n0,T0,h0,evv,c>0, with evv evaluated at fixed σp.

A first variation is defined by a family (vλ,σp,λ,uλ,Πλ) jointly smooth in dimensionless λ near 0 and in x, through the displayed background, with uλ future unit, meaning η(uλ,uλ)=−1 and uλ0>0. For any such field fλ, set δf:=∂λfλ∣λ=0. At each λ, set nλ=1/vλ, ϵλ=nλe(vλ,σp,λ), pλ=−ev(vλ,σp,λ), Tλ=eσp(vλ,σp,λ), Δλab=ηab+uλauλb, Dλ=uλa∂a, and θλ=∂auλa. The bulk stress and current are Tλab=ϵλuλauλb+(pλ+Πλ)Δλab and Jλa=nλuλa, and the corrected law of Corrected bulk relaxation and exact extended entropy is βDλΠλ+Πλ/(ζc)=−θλ−(TλΠλ/2)∂a(βuλa/Tλ), where β=τ/ζ. The linearized equations mean the first variations at λ=0 of ∂aTλab=0, ∂aJλa=0, and this corrected law, set equal to zero; no member with λ≠0 is required to solve the nonlinear system. Impose δσp=0, put r:=δϵ, w:=(δu1,δu2,δu3), and denote δΠ by Π in the linearized system below. Take constant coefficients ζ,τ>0.

as:=(∂p∂ϵ)σp=evvn0h0>0

as supplied by Local Gibbs, Euler, parcel first law and response identities. The resulting linearized system is

rt+ch0div⁡w=0,wt+ch0∇(asr+Π)=0,τΠt+Π=−ζcdiv⁡w.

Its positive quadratic energy density

Ebulk=12[ash0r2+h0∣w∣2+τζΠ2]

satisfies ∂tEbulk+div⁡[c(asr+Π)w]=−Π2/ζ. The normal characteristic speeds are 0 and ±vbulk, where

vbulk=cas+ζτh0.

By Complete symmetrized constant-coefficient evolution, initial data U0∈S(R3;R5) with the componentwise real convention of Schwartz space and its seminorms, or smooth periodic data on TL3 with L>0, have unique global smooth solutions, contractive in the corresponding energy and Sobolev norms, with finite propagation at vbulk. The branch is inside the Minkowski reference cone exactly when as+ζ/(τh0)≤1. Constant density and transverse velocity modes can persist, so contraction does not mean every mode decays. No nonlinear or variable-coefficient existence theorem is claimed.

Facts & Assumptions

Given: The reference geometry, state, first-variation convention, and positive coefficients of the Statement. In SI bookkeeping, r,h0,Π,ζ/τ have units Pa, w,as are dimensionless, ζ has units Pa s, τ has units s, and c has units m s−1.

[A1]

n0>0, T0>0, evv>0, h0>0, as>0, ζ>0, τ>0, and c>0. The strict inequalities make the displayed energy positive definite and every displayed denominator nonzero.

[A2]

Countable choice ACω is carried by the current mathematical supplier chain; no stronger choice principle is used (The Axiom of Countable Choice (ACω)).

[F1]

Corrected bulk relaxation and exact extended entropy (current batch-56 draft): the corrected bulk model supplies the exact covariant stress and particle projections Dϵ+(h+Π)θ=0, (h+Π)aaccb+Δba∇a(p+Π)=0, and Dn+nθ=0, as well as the stated derivative-corrected entropy law. Its lower-level MC02 inputs remain draft, and this use remains conditional on their stated mathematical interfaces.

[F2]

Local Gibbs, Euler, parcel first law and response identities (current batch-53 draft): for the open C2 state domain it gives dϵ=T ds+μ dn and h=Ts+μn; at fixed σp, ∂nϵ=h/n and ∂np=evv/n2, so as=evv/(n0h0)>0 when n0,evv,h0>0. This use remains conditional on the current draft Gibbs carrier; authoring readiness does not establish proof acceptance.

[F3]

Complete symmetrized constant-coefficient evolution: a constant real matrix system with a positive symmetrizer, symmetric symmetrized principal matrices, and nonnegative symmetrized damping has a unique global smooth solution, contraction, and propagation at its largest absolute symmetrized characteristic eigenvalue.

[F4]

Schwartz space and its seminorms: scalar Schwartz functions are smooth complex-valued functions with every seminorm sup⁡x∣xα∂βf(x)∣ finite; the data class in the Statement is the componentwise real-valued subspace.

Proof

1.1A1A2F1F2givenalgebra

At λ=0, u0=∂x0 and ∂0=c−1∂t. Differentiating the unit normalization gives δu0=0, so the first variations of Dϵ, θ, and the spatial acceleration are respectively c−1rt, div⁡w, and c−1∂tw. Because Π0=0 and the background u,T,β are constant, the product Π∇a(βua/T) has zero first variation. By [F2], δp=asr. Linearizing the energy projection in [F1] gives rt+ch0div⁡w=0, and its spatial projection gives wt+(c/h0)∇(asr+Π)=0. The linearized corrected law is (τ/(ζc))∂tΠ+Π/(ζc)=−div⁡w; multiplication by ζc gives the third equation. For consistency, at fixed σp [F2] gives ∂nϵ=Tσp+μ=h/n, hence δn=(n0/h0)r; the first equation then implies (δn)t+cn0div⁡w=0, the linearized particle balance.

2.1A1step 1.1algebra

Differentiate Ebulk and substitute the system: the rdiv⁡w terms cancel, the Πdiv⁡w terms cancel, and the remaining relaxation term is −Π2/ζ. Thus ∂tEbulk+div⁡[c(asr+Π)w]=−Π2/ζ≤0.

2.2A1A2F3step 1.1algebraF4

Let U=(r,w,Π) and M=diag⁡(as/h0,h0I3,τ/ζ). For each spatial index j, the nonzero entries of the principal matrix are (Aj)r,wj=ch0, (Aj)wj,r=cas/h0, (Aj)wj,Π=c/h0, and (Aj)Π,wj=ζc/τ; hence MAj is symmetric. The damping matrix is B=diag⁡(0,03×3,1/τ), with MB=diag⁡(0,03×3,1/ζ)≥0. The longitudinal block of A(ν) is (0ch00cas/h00c/h00ζc/τ0), whose characteristic polynomial is −λ[λ2−c2(as+ζ/(τh0))]; transverse velocities have zero speed. Apply [F3] to obtain the actual global solution, uniqueness, energy contraction, and finite propagation at vbulk.

3.1A1step 2.1step 2.2algebra∎

Weighted Cauchy–Schwarz gives (asr+Π)2≤(h0as+ζ/τ)[(as/h0)r2+(τ/ζ)Π2]. Therefore for every unit ν, ∣c(asr+Π)w⋅ν∣≤cas+ζ/(τh0) Ebulk by 2XY≤X2+Y2. Since c>0, vbulk≤c is equivalent to as+ζ/(τh0)≤1. With r spatially constant, w=0, and Π=0, the first mode is stationary; constant transverse w with r=Π=0 is stationary as well.

5 · Examples, experiments and counterexamples

None yet.

Sources