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Quantized Enveloping Algebras and Quantum Serre Relations
1 · Prerequisites
- Algebraic Closure, Embeddings, and Separability
- Binary Operations, Monoids, Groups and Subgroups
- Chain Conditions, Semisimple Modules and the Wedderburn–Artin Theorem
- Constant Rank, Submersions, Immersions and Regular Level Sets
- Construction of the Natural Numbers
- Construction of the Real Numbers via Cauchy Sequences
- Construction of the Real Numbers via Dedekind Cuts
- Cosets, Index and Lagrange's Theorem
- Countability and Uncountability
- Determinants of Matrices over a Commutative Ring
- Divisibility, Euclidean Domains, Principal Ideal Domains and Unique Factorisation
- Dual Spaces, Bilinear and Quadratic Forms, and Sylvester's Law of Inertia
- Exterior Powers, Orientation and Hodge Duality
- Finite Counting, Factorials and Binomial Coefficients
- Formal Power Series
- Foundations of the Real Numbers for Analysis
- Free Groups and Presentations
- Free Modules, Exact Sequences, Projective and Injective Modules
- Gaussian Elimination, Elementary Matrices and Reduced Row Echelon Form
- Group Actions, Orbits, Stabilisers and Cayley's Theorem
- Group Homomorphisms and the Isomorphism Theorems
- Harish Chandra Isomorphism Casimir and Central Characters
- Ideals, Quotient Rings and the Isomorphism Theorems for Rings
- Kac Moody Algebras from Generalized Cartan Matrices
- Lie Algebra Representations, Enveloping Algebras, and PBW
- Linear Independence, Bases and Dimension
- Linear Transformations, Rank-Nullity and Quotient Spaces
- Matrices, the Matrix of a Linear Map, and Change of Basis
- Modules over a Principal Ideal Domain and the Canonical Forms
- Modules, Submodules, Quotient Modules and the Isomorphism Theorems
- Normal Subgroups and Quotient Groups
- Order, Zorn's Lemma, and the Axiom of Choice
- Ordinals, Cardinals, and Transfinite Recursion
- Permutation Statistics, Inversions and Eulerian Numbers
- Polynomial Rings, the Division Algorithm and Roots
- Relations, Functions, and Quotients
- Rings, Subrings, Integral Domains and Fields
- Roots, Rational Powers, and Classical Inequalities
- Symmetric Groups, Cycle Decomposition and the Sign Homomorphism
- Tensor Products of Modules
- The Burau Representations
- The Determinant of a Linear Operator, Cofactors and Cramer's Rule
- The Field of Fractions and Localisation
- The ZFC Axioms and the Basic Set Constructions
- Triangularisation, Generalised Eigenspaces and Jordan Canonical Form
- Vector Spaces, Linear Subspaces, Span and Direct Sums
2 · Summary
This page constructs the Drinfeld–Jimbo quantized enveloping algebra of a symmetrizable Cartan datum and develops its quantum Serre relations, its Hopf structure and its triangular decomposition. The datum with its symmetrizer, lattices and normalization is fixed in Symmetrizable Cartan data for quantum groups, and the -integers, factorials and divided powers used throughout are set up in Quantum integers, factorials, Gaussian binomials and divided powers at with the Gaussian calculus of The quantum Pascal recurrences, the Gauss product formula and Gaussian integrality and The quantum binomial expansion for -commuting elements.
Presentation, Serre relations and Hopf structure
The algebra is presented by generators and the toral, mixed and quantum Serre relations in The Drinfeld-Jimbo quantized enveloping algebra by generators and relations, with the Hopf foundations Bialgebras, counits and antipodes over a commutative ring and Uniqueness of the antipode. The coproduct of a Serre element is controlled by The coproduct preserves the positive and negative quantum Serre ideals, the bar and Chevalley involutions are checked on all relations in The Chevalley involution, bar involution, and contravariant anti-involution preserve the Drinfeld–Jimbo ideal, and The Drinfeld–Jimbo formulas define a Hopf algebra assembles the coproduct, counit and antipode into a Hopf algebra with the subalgebras of Positive, negative and toral quantum subalgebras and their root gradings.
PBW ranks, duality and the triangular decomposition
The formal shuffle model of The formal quantum shuffle Borel and its Cartan crossed product supplies the coefficientwise Borel, the positive shuffle identity of The quantum Serre sums vanish in the shuffle algebra, and the opposite Serre ideal annihilates the shuffle half and the -binomial cancellation behind The formal quantum Serre half embeds in the shuffle algebra and is degreewise free, whose inputs include the coideal lemma An augmented coideal ideal of an enveloping algebra is generated by its primitive part and the root-graded bialgebra duality of Lie bialgebras, degreewise duality, and root-graded Manin triples, A root-graded Manin triple gives dual Lie bialgebras and The opposite Borels of a symmetrizable Kac–Moody algebra are root-degreewise dual Lie bialgebras; A nonsingular principal minor of the symmetrized Cartan matrix of size the rank supplies the Cartan coordinates. The classical PBW ranks and the nondegenerate pairing of the halves are established in Generic quantum Serre halves have classical PBW ranks and a nondegenerate Hopf pairing. The generic quantum halves form a Drinfeld–Jimbo crossed double presents the algebra as the crossed double of its two halves and the torus, and Triangular decomposition of a quantized enveloping algebra proves the resulting vector-space decomposition after the local normal-form and opposite-Serre commutator calculations. The total root grading retains all summands with positive degree minus negative degree equal to the prescribed degree, including the additional degree-zero summands. The rank-one string modules used in later pages are computed in Divided-power commutation and the simple string modules.
The companion quantized-enveloping-algebras-and-quantum-serre-relations-examples works through the coproduct and antipode, a type- Serre calculation, the double-edge affine relation, and a counterexample showing that unsymmetrized -parameters break the Cartan normalization.
3 · Logical flowchart
4 · Definitions, theorems and proofs
Bialgebras, counits and antipodes over a commutative ring
Definition
Let be a commutative ring. A bialgebra over is a unital associative -algebra (Algebras over a commutative ring, central structure maps, and algebra homomorphisms) together with -algebra homomorphisms (the coproduct) and (the counit) such that is coassociative and the counit axioms hold:
The counit equations use the canonical identifications . The target has the -algebra structure of The tensor product of -algebras has multiplication .
A Hopf algebra over is a bialgebra together with an -linear antipode satisfying both convolution-inverse equations
where . We do not assume that is invertible, involutive or multiplicative. Throughout, and are algebra homomorphisms, and the displayed order of the antipode factors is our convention.
Lie bialgebras, degreewise duality, and root-graded Manin triples
Definition
Let be a field of characteristic . A Lie bialgebra is a Lie algebra over together with a linear map such that
and for all . The bracket action on is .
Let be an additive abelian group. Suppose and are -graded vector spaces with finite-dimensional graded pieces, and suppose that, within each space separately, only finitely many pairs of nonzero graded pieces have degrees summing to any fixed degree. A pairing between them is degreewise perfect if pairs perfectly with and all other degree pairs are orthogonal. It then identifies with the restricted graded dual . The induced pairing on exterior powers is the determinant pairing: .
For the Lie bialgebra duality below, require both brackets to preserve degree: and . Two such Lie bialgebras are dual when these pairings are degreewise perfect and their cobrackets are transposes of the opposite brackets: and . For , degree preservation and orthogonality make vanish unless . There are only finitely many such nonzero pairs, and their finite-dimensional perfect pairings identify the transpose with a unique element of under the determinant pairing. The same argument applies with the two algebras exchanged, and linear extension handles arbitrary elements. Thus the transposes lie in the ordinary exterior squares rather than formal infinite sums.
A root-graded Manin triple is a -graded Lie algebra with finite-dimensional graded pieces, a symmetric invariant bilinear form pairing perfectly with and satisfying whenever , and graded Lie subalgebras and such that as a vector space and . The cross pairing is degreewise perfect: a vector in annihilating also annihilates by isotropy, so it is zero by perfectness on the double. The same argument applies with the two halves exchanged, and finite dimensionality gives perfectness of the cross pairing. All other degree pairs are orthogonal by the condition on . Require finite degree decompositions within each of and separately, as above; a triple satisfying this requirement is called locally finite. No finite-decomposition condition is imposed on the whole double. This permits opposite Borels with infinitely many roots, since each Borel has support in one root cone. The finite-dimensional Manin-triple definition is the special case with finitely many nonzero graded pieces.
Symmetrizable Cartan data for quantum groups
Definition
A symmetrizable Cartan datum for a quantum group consists of a finite nonempty index set , a symmetrizable generalized Cartan matrix (Generalized cartan matrix, Symmetrizable generalized cartan matrix) and a chosen diagonal symmetrizer with and for all ; free abelian groups and (Free abelian group on a set) with an integer-valued bilinear pairing ; simple coroots that are linearly independent in ; and simple roots that freely generate the root lattice (Kac Moody root lattice height and positive cone) and satisfy for all (Realization of a generalized cartan matrix, Minimal realizations exist and are unique up to isomorphism).
The index set is finite and need not be nonsingular. We do not require the simple coroots to span , and the pairing is not required to be perfect; choosing and is part of the datum, not something determined by the matrix alone.
We fix an indeterminate over , work over , and set . For , is the exponent in . We use the row convention throughout. No fundamental weights with prescribed values on all are part of this definition.
A nonsingular principal minor of the symmetrized Cartan matrix of size the rank
Statement
Let and let be a real symmetric matrix of rank . For , write for its principal submatrix. Use the convention that the empty matrix has determinant and is invertible. There is a subset with for which is nonsingular.
If in addition is a real matrix and has with , then for the same ,
Thus is also nonsingular and has size , and . In particular, if is symmetrizable and has corank one, then has corank one and the conclusion gives a nonsingular principal submatrix.
Facts & Assumptions
Given: A real symmetric matrix of rank ; in the second assertion, also with positive diagonal and .
A symmetrizable generalized Cartan matrix has a positive diagonal symmetrizer for which is symmetric (Symmetrizable generalized cartan matrix).
For positive size, determinant is defined by the Leibniz formula; we additionally use the local empty-matrix convention stated above (For , the determinant over a commutative ring by the Leibniz formula, and for a real matrix).
A real square matrix is invertible exactly when its determinant is nonzero (A finite square real matrix is invertible if and only if its determinant is nonzero); nonsingular means invertible (Invertible square matrices and similarity over a commutative ring).
If a symmetric block matrix has an invertible leading block , its determinant is times the determinant of the Schur complement (For symmetric with invertible, a block-unitriangular congruence gives and factors ).
Matrix rank is row rank (Row space, column space, nullspace, row rank, column rank and matrix rank).
A nonzero -rowed minor of a real matrix forces its rank to be at least (A matrix has rank at least exactly when it has a nonzero -rowed minor).
Determinants are multiplicative, and the determinant of a diagonal matrix is the product of its diagonal entries (For same-sized finite square matrices over a commutative ring, , The determinant of a triangular matrix is the product of its diagonal entries).
Transpose reverses matrix products, and an invertible matrix has a unique inverse (Matrix arithmetic over a commutative ring is associative, unital and distributive, and transpose reverses products, Invertible square matrices and similarity over a commutative ring).
Proof
If , then and works by the stated empty-matrix convention. When with positive diagonal , as well, so the determinant identity is . Hence assume .
Since , either some , giving a nonsingular one-by-one principal submatrix, or all diagonal entries vanish and some with , giving the nonsingular two-by-two principal submatrix with determinant . Choose, from the finite family of principal submatrices with nonzero determinant, a set maximal under inclusion. Then is invertible by [F3]; put .
For any , maximality makes . Write . The Schur-complement formula [F4] gives , so .
For distinct , maximality also gives . Since , transposing and using [F8] shows that is also a two-sided inverse of , hence . The two-by-two Schur complement therefore has zero diagonal by step 2.1 and equal off-diagonal entries . Its determinant is , so [F4] and the fact that imply . Therefore every entry of the complementary block equals the corresponding entry of , where .
Partitioning by and , the equality in step 3.1 yields . By matrix multiplication, every row of is a linear combination of the rows of the right factor, so [F5] gives . Since , has a nonzero -rowed minor, so [F6] gives . Hence .
If , diagonality gives , and [F7] gives . The product is nonzero, so the already nonzero forces . For a symmetrizable of corank one, positive diagonal row-scaling preserves rank, hence .
Remarks
Symmetry is essential: has rank but no nonsingular one-by-one principal submatrix. Berkeley's Gabber–Kac example in Ch. 10 §10.4.2.6 assumes the positive-semidefinite corank-one case; the principal-minor argument above needs only symmetry and therefore also applies to indefinite symmetrizable matrices.
Quantum integers, factorials, Gaussian binomials and divided powers at
Definition
Let be a symmetrizable Cartan datum for a quantum group (Symmetrizable Cartan data for quantum groups) and put . For , define the -integer
and the -factorial
For , define the Gaussian binomial , and set it to when or . In the published one-parameter convention, write for the two-part -multinomial coefficient of The -integer, -factorial and -multinomial coefficients.
For an element of a unital -algebra and , define its divided power at by , so and .
The symmetric convention and the published asymmetric convention are related, for and , by
In particular is invariant under . These quantities depend on the symmetrizer only through .
Facts & Assumptions
Given: A symmetrizable Cartan datum with indeterminate over , and an element of a unital -algebra.
The datum has with positive integer (Symmetrizable Cartan data for quantum groups).
The asymmetric -integer and -factorial are and , with and ; the -multinomial is the factorial quotient (The -integer, -factorial and -multinomial coefficients).
Verification
For , cancel the nonzero factors to obtain . At the same identity holds by the zero convention. For the quotient is nonzero because its numerator and denominator are nonzero in by [F1].
Multiplying the identity of step 1.1 for gives ; for this is the equality of empty products. Hence for , division by the nonzero factorials is valid and , since .
Since every for is nonzero, is a nonzero scalar and therefore invertible in ; this makes well-defined. Replacing by negates numerator and denominator in , so is invariant, as are its factorials and Gaussian quotients.
An augmented coideal ideal of an enveloping algebra is generated by its primitive part
Statement
Assume the Axiom of Choice (The Axiom of Choice). Let be a field of characteristic (Field, The characteristic of a ring: the least with when one exists, and otherwise) and let be a Lie algebra over (Lie algebras over a field). Equip its universal enveloping algebra with the standard cocommutative Hopf structure (Hopf-algebra structure on U(g)), with coproduct for and counit . If is a two-sided ideal such that
then is a Lie ideal and . Thus is uniquely determined by among two-sided ideals satisfying both displayed conditions.
Facts & Assumptions
Given: AC, a characteristic-zero field , a Lie algebra , and a two-sided ideal satisfying the coproduct and augmentation conditions.
AC is the assertion that every family of nonempty sets has a choice function (The Axiom of Choice).
Under AC, every vector space has a basis (Every vector space has a basis), and every independent set can be extended to a basis (Zorn's lemma gives a basis between any linearly independent set and any spanning set containing it: if with independent and , there is a basis of with ).
Under AC, every set, hence any chosen basis, can be well ordered (The well-ordering theorem).
For a supplied totally ordered basis of , ordered monomials form a basis of and the PBW symbol map identifies with (Poincaré–Birkhoff–Witt theorem).
The standard coproduct and counit are algebra maps, and are primitive on (Hopf-algebra structure on U(g), Bialgebras, counits and antipodes over a commutative ring).
The PBW filtration is exhaustive and is spanned by products of at most elements of (PBW filtration on the enveloping algebra).
Linear maps into commutative unital algebras extend uniquely to , and ring maps killing an ideal factor through the quotient (Symmetric algebra of a vector space, The quotient vector space and its canonical projection, The ideal generated by a subset and principal ideals, Universal property of the symmetric algebra, A ring homomorphism whose kernel contains a two-sided ideal factors uniquely through the quotient ring).
In a characteristic-zero field, every positive integer is nonzero and invertible (Field, The characteristic of a ring: the least with when one exists, and otherwise).
Proof
By [A1] and [L1], choose a basis of ; by [L2], give it a total well-order. Apply [L3]. In particular embeds in , and the associated graded algebra of the filtration [L5] is .
By [L4], is filtered for the total-degree filtration on : this holds on each degree-one generator because , and hence on products because is an algebra map. Its associated graded coproduct on is the algebra map making every primitive, since the two maps agree on the algebra generators.
Put and . The ideal property makes a graded ideal of . To see its coideal property, use AC and [L1] to choose a complement of in ; its image in is a subspace, so choose a complement there and lift it to . Thus and . The total-degree filtration then has associated graded pieces and for . Taking highest-degree symbols in the assumed containment gives .
Since and , we have . PBW gives , so and . Also is a Lie ideal: for and , the commutator lies in because is two-sided, and lies in by the enveloping relation.
Let be the ideal of generated by , and let be the map induced by the vector-space quotient. The universal properties in [L6] construct inverse algebra maps between and : maps from either algebra to a commutative unital -algebra correspond exactly to linear maps vanishing on . The maps are inverse because they agree with the identity on the algebra generators. Hence .
We prove by induction on that . The claim holds in degrees and by step 1.4. For , take . Its reduced coproduct has, in bidegree with and , a component in by step 1.3; both , so the induction hypothesis makes its image under zero. Thus has zero reduced coproduct and is primitive in . The component of the coproduct of a homogeneous degree- element is the sum obtained by placing each of its factors in the second tensor slot; multiplying the two slots gives . If is primitive this component is zero, so [L7] forces . Consequently and .
The reverse inclusion follows because is an ideal and contains . Hence .
Since is two-sided, the left and right ideals and lie in , so their associated graded spaces lie in by step 3.1. Conversely, each degree- element of is a finite sum of products in , and PBW lifts that sum to an element of with the same symbol. The right-handed products lift identically. Hence both associated graded spaces equal .
For , step 4.1 supplies with the same degree- symbol as . Then ; descending induction, starting with from step 1.4, gives . The identical argument with the right-generated ideal gives . Thus , and applying this equality to any other ideal satisfying the same two conditions and the same intersection proves the stated uniqueness.
Remarks
- The zero Lie algebra is included: then , , and the only admissible ideal is .
- The augmentation hypothesis is necessary. For nonzero , the ideal satisfies the coproduct containment, but while .
- The unrestricted “largest ideal with fixed primitive part” claim is false: for , , the ideals and have the same intersection with , and .
- AC is used to choose and well-order a basis of arbitrary , as required by the supplied general PBW theorem, and to split the induced filtration of in step 1.3. These are the only nonconstructive choices in this proof; the characteristic-zero use is exactly the invertibility of in step 2.1. No assertion is made in positive characteristic.
Uniqueness of the antipode
Statement
Let be a bialgebra over a commutative ring (Bialgebras, counits and antipodes over a commutative ring) and let be antipodes. Then . Thus a bialgebra admits at most one Hopf algebra structure with its fixed multiplication, unit, coproduct and counit. Every antipode also satisfies .
Facts & Assumptions
Given: A bialgebra over a commutative ring and two antipodes .
The multiplication is associative and the coproduct is coassociative (Bialgebras, counits and antipodes over a commutative ring).
The counit identities are (Bialgebras, counits and antipodes over a commutative ring).
The unit map and the algebra maps are unital, so and (Bialgebras, counits and antipodes over a commutative ring).
Each antipode satisfies (Bialgebras, counits and antipodes over a commutative ring).
Proof
For define . Coassociativity of and associativity of give for all .
The map is a two-sided unit for : for every and , and , by the two counit identities and -linearity of .
Evaluating either antipode equation for at , and using and , gives . Hence .
By [F4], ; using [F1] and step 1.2, . Therefore the antipode is unique, and the stated bialgebra has at most one Hopf structure.
A root-graded Manin triple gives dual Lie bialgebras
Statement
Let be a field of characteristic , and let be a locally finite root-graded Manin triple in the sense of Lie bialgebras, degreewise duality, and root-graded Manin triples. Define and by transposing the opposite brackets under the degreewise perfect pairing induced by :
Then these maps are well defined and make and dual Lie bialgebras.
Facts & Assumptions
Given: A field of characteristic and a locally finite root-graded Manin triple.
The two complementary isotropic subalgebras have finite-dimensional graded pieces, a degreewise perfect cross pairing, and only finitely many degree decompositions within each subalgebra in any fixed degree (Lie bialgebras, degreewise duality, and root-graded Manin triples).
The wedge pairing is the determinant pairing on exterior powers, and a Lie bialgebra cobracket is a cocycle satisfying co-Jacobi (The graded exterior algebra , Lie bialgebras, degreewise duality, and root-graded Manin triples).
Proof
By [F1], for each homogeneous only finitely many opposite-degree pairs of components of can bracket to a degree paired with . The perfect pairings therefore give a unique finite sum satisfying the first transpose identity; the same construction defines , and both maps are linear and preserve total root degree.
Choose dual bases and in the finitely many homogeneous pieces involved in a fixed calculation, and write and . Invariance gives and ; since the two subalgebras are isotropic and pair perfectly, these identities determine . For each fixed input pair, grading restricts these sums to two fixed finite-dimensional pieces, so they are finite by [F1].
Pair with in the opposite subalgebra. By the defining transpose identity, the result is by Jacobi in . Degreewise perfectness makes the co-Jacobi expression zero; the identical argument with signs exchanged proves co-Jacobi for .
Jacobi in for , paired with , gives . By the transpose definition, this is exactly the coefficient identity for . Interchanging and and using Jacobi for proves the cocycle identity for . Since the homogeneous bases were arbitrary and the pairings are perfect, both cocycle identities hold for all elements. Together with step 2.1, this proves that the two transposed maps are dual Lie bialgebra structures.
The Drinfeld-Jimbo quantized enveloping algebra by generators and relations
Definition
Let be a symmetrizable Cartan datum for a quantum group (Symmetrizable Cartan data for quantum groups) and put . Write and . Let be the -vector space with basis the symbols , and let be its free unital associative -algebra (Tensor algebra of a vector space, Universal property of the tensor algebra). Let be the two-sided ideal of generated by (The ideal generated by a subset and principal ideals) the following relations:
where the Gaussian binomials are those of Quantum integers, factorials, Gaussian binomials and divided powers at . The Drinfeld-Jimbo quantized enveloping algebra is
(The quotient ring with ), with denoting the images of the generators. In this quotient, is the two-sided inverse of .
It is graded by the root lattice (Kac Moody root lattice height and positive cone), with , and ; thus .
For every unital associative -algebra , any assignment of elements satisfying these relations extends uniquely to a -algebra homomorphism (A ring homomorphism whose kernel contains a two-sided ideal factors uniquely through the quotient ring).
Facts & Assumptions
Given: A symmetrizable Cartan datum and its root lattice ; the displayed symbols and relations are formed over .
The root lattice is freely generated by the simple roots, and for (Symmetrizable Cartan data for quantum groups, Kac Moody root lattice height and positive cone).
The tensor algebra is a direct sum of finite words with concatenation product; assigning group degrees to its generator symbols gives the direct-sum grading by total degree. A linear map from the generating vector space extends uniquely to an algebra homomorphism (Tensor algebra of a vector space, Universal property of the tensor algebra).
The two-sided ideal generated by the listed relations is an ideal, its quotient ring is defined by cosets, and maps whose kernel contains that ideal factor uniquely through the quotient (The ideal generated by a subset and principal ideals, The quotient ring with , A ring homomorphism whose kernel contains a two-sided ideal factors uniquely through the quotient ring).
Verification
The relations and give in the quotient. In particular is a well-defined two-sided inverse, and the mixed commutator relation has a defined coefficient by [F2].
Give each generator its stated degree in . The toral relations have degree ; the and relations have degrees and ; the relation is homogeneous of degree if and degree if ; and the two Serre sums have degrees and its negative. Thus every generator of is homogeneous.
Every element of the two-sided ideal is a finite sum of products with a homogeneous defining relation. Decomposing and into their finite homogeneous components shows that each homogeneous component of every element of again belongs to . Hence the ideal is homogeneous and the quotient has the direct-sum root-lattice grading stated above.
Given an assignment into satisfying the relations, [F3] extends its values to a unique -algebra homomorphism . Every generator of maps to zero, so the ideal lies in the kernel; [F4] then gives the unique ring factor . Since the quotient map and the original map preserve scalars, surjectivity of the quotient map makes the factor preserve scalars as well. Conversely, any such factor is determined by the images of the generators because they generate the quotient.
The opposite Borels of a symmetrizable Kac–Moody algebra are root-degreewise dual Lie bialgebras
Statement
Let be a finite symmetrizable generalized Cartan matrix over , with positive symmetrizer and rank . Let be defined from a minimal realization, with triangular decomposition and Borels . Use the invariant form normalized by and .
(i) Root-degreewise enveloping-algebra duality. The form pairs and perfectly. It induces a canonical degreewise perfect vector-space pairing on and by PBW symmetrization. Each fixed root-degree component is finite-dimensional, and the pairing identifies , the restricted graded dual; the reverse identification holds as well. This is a vector-space pairing, not a Hopf pairing for the standard primitive coproducts.
(ii) Dual Borel Lie bialgebras. Let be such that the principal block is nonsingular, with ; such a set is supplied by A nonsingular principal minor of the symmetrized Cartan matrix of size the rank. Choose complementary Cartan coordinates for with . In the quadratic Lie algebra , with form , the maps and embed the Borels as complementary isotropic subalgebras. Thus they form a root-graded Manin triple. The cross pairing is on and ; its transpose brackets define dual Lie bialgebra structures on and . Both cobrackets vanish on , and the positive cobracket satisfies . The enveloping-algebra vector-space pairing in (i) retains the original invariant-form normalization; it is independent of this rescaled Manin pairing.
Facts & Assumptions
Given: A finite symmetrizable generalized Cartan matrix, a minimal realization, and the associated Kac–Moody algebra over .
The simple roots and coroots are independent, and a minimal realization has (Realization of a generalized cartan matrix).
The algebra has the triangular decomposition and separate finite-simple generator Serre presentations of (Kac moody algebra associated to a gcm, Contragredient algebra has a triangular decomposition, Serre presentation of a kac moody algebra).
Root spaces are finite-dimensional, and pairs perfectly with under the invariant form; the Cartan restriction is nondegenerate (Kac moody root spaces are finite dimensional, Invariant bilinear form for a symmetrizable kac moody algebra).
A nonsingular principal block of size exists for (A nonsingular principal minor of the symmetrized Cartan matrix of size the rank).
A countably spanned Kac–Moody half with a supplied countable ordered basis has the PBW ordered-monomial basis, and in characteristic zero PBW symmetrization is a filtered vector-space isomorphism (PBW for countably presented Kac Moody Lie algebras, PBW symmetrization in characteristic zero).
A locally finite root-graded Manin triple gives dual Lie bialgebras by transposing the opposite brackets (A root-graded Manin triple gives dual Lie bialgebras).
Proof
Put and define by . By [F1], is onto and of dimension . For the set in [F4], projection of this image to is an isomorphism: it is surjective because its restriction to the -coordinate subspace has matrix , and both spaces have dimension . Hence . For each , choose with the th coordinate vector. Their span intersects trivially, and its dimension makes it a complement to ; the form normalization gives . If this is the empty complementary family and .
By [F3], the invariant form has perfect opposite-root pairings and is nondegenerate on the Cartan subalgebra. Also are positively and negatively root-graded, respectively.
For fixed , the degree- words in the finite simple-generator tensor algebra are finite in number, so the separate Serre presentations [F2] make finite-dimensional; the same argument applies to . The height-zero component is on both sides.
Each half is countably spanned by its finite bracket words. Enumerating those words by length and lexicographic order and retaining the first vectors outside the preceding span gives a countable ordered basis; applying [F5] provides the PBW basis and the symmetrization isomorphism for both halves. This construction uses no choice principle.
For and , define a pairing on the symmetric algebras to be zero when , and when put , with the empty products paired as . It is well defined under permutations of each list.
In a fixed root degree and symmetric length , only finitely many tuples of positive roots sum to . The tensor-product pairings on each such tuple are perfect by [F3]; averaging over identifies coinvariants with invariants because in , so the induced pairing on is perfect. Summing over the finitely many lengths gives a perfect pairing on the full symmetric-algebra root components.
Let be a second copy of and define on with the componentwise bracket. Jacobi holds componentwise, and [F3] makes this form invariant, symmetric and nondegenerate. The maps and in (ii) are Lie homomorphisms because is abelian and the bracket of two Borel elements has zero Cartan component. Their images are complementary: the positive and negative root components split by the triangular decomposition, and the two Cartan copies split into diagonal and antidiagonal subspaces. Each image is isotropic, since the invariant form is orthogonal between the Cartan and nonzero root spaces and vanishes on pairs of positive roots or on pairs of negative roots. The cross pairing is ; it is degreewise perfect by [F3]. Within either Borel, a degree has only finitely many decompositions into degrees in its root cone, and all pieces are finite-dimensional. Thus these images satisfy the same-side finiteness required of the root-graded Manin triple; the whole double need not have finite decompositions.
Transport the invariant-form symmetric-power pairing of steps 1.5–1.6 through the PBW symmetrization isomorphisms of step 1.4. They preserve root degree, so they give a perfect pairing of with for every . Taking the direct sum of these finite-dimensional dualities gives the restricted graded-dual isomorphism in (i), in both directions; at it is the pairing .
By [F6], the transposed brackets give dual Lie bialgebra structures on the two Borel copies. For , every bracket of two elements of has either negative root degree or is zero in degree zero, so its cross pairing with vanishes; hence . The same argument gives . For a Cartan vector , the determinant pairing gives , whereas . There are no other possible degree decompositions of the simple root except its simple-root and Cartan parts. Hence transposition gives , proving (ii) with the normalization used by the formal shuffle coproduct.
Remarks
The pairing on enveloping algebras in (i) is transported from symmetric algebras by PBW symmetrization. It is not asserted to satisfy Hopf-pairing adjunction for the standard primitive coproducts. Indeed, in type let and . The primitive coproduct gives , so any Hopf pairing with and would force both and to vanish. It would then give , contrary to the perfect opposite-root pairing in [F3].
The quantum Pascal recurrences, the Gauss product formula and Gaussian integrality
Statement
Fix a symmetrizable Cartan datum and , and use the conventions of Quantum integers, factorials, Gaussian binomials and divided powers at . Write , with when or .
(i) Pascal recurrences. For and every integer ,
(ii) Symmetry. For , .
(iii) Gauss product formula. For every , in the polynomial ring ,
Consequently, for ,
(iv) Integrality. For ,
Thus every Gaussian quotient is a Laurent polynomial in with integer coefficients, and the Pascal recurrences hold in that Laurent polynomial ring.
Facts & Assumptions
Given: A symmetrizable Cartan datum, a fixed , and the symmetric -integer, factorial and Gaussian quotient from Quantum integers, factorials, Gaussian binomials and divided powers at .
for an indeterminate and positive integer ; all symmetric -factorials in the quotient are nonzero (Quantum integers, factorials, Gaussian binomials and divided powers at ).
is the polynomial ring over a commutative ring , and consists of finite Laurent sums with integer coefficients (The polynomial ring over a commutative ring as finitely supported coefficient sequences with convolution, The Laurent polynomial ring as the principal localisation of Z[t] at t).
Proof
For , the numerator identity gives .
For , multiply the identity of step 1.1 by and use the factorial quotient to obtain . The same formula holds at by and the out-of-range zero convention; for or every term is zero. The factorial definition gives for ; applying the first recurrence at and using this symmetry gives the second recurrence.
Put . The first recurrence in step 2.1 gives, for , . Since , induction on shows is a polynomial in with integer coefficients; this proves . Because and is indeterminate, distinct powers of are linearly independent over , so this evaluation embeds the Laurent polynomial ring and gives the stated inclusion and Laurent-polynomial recurrences.
Let . For both sides of the Gauss formula are . If it holds for , the coefficient of in is ; by the first recurrence in step 2.1 this equals , since . Thus induction proves the product formula in .
For , evaluate the formula of step 3.2 at . The factor with makes the product zero, so its right side is the alternating Gaussian sum in the statement and is zero. This proves the final assertion and completes all parts.
The formal quantum shuffle Borel and its Cartan crossed product
Definition
Let be a symmetrizable Cartan datum (Symmetrizable Cartan data for quantum groups), , and . Choose with and , as supplied by A nonsingular principal minor of the symmetrized Cartan matrix of size the rank. Work over with and .
(a) Word space and shuffle product. Let with . Set and denote by . For homogeneous letters, let consist of permutations mapping original positions to output positions, with and . Define
This product is associative and makes an -graded algebra; every color-degree component is a finite free -module. Write for the subalgebra generated by the one-letter words .
(b) Cartan derivations and crossed products. Define -linear derivations on letters by and for , and extend them to words by summing their action over positions. They extend as commuting derivations of and preserve . Let consist of commuting symbols corresponding to and commuting symbols corresponding to . Put , so each coefficient of is a finite Cartan polynomial. The Cartan crossed-product modules are
The Cartan symbols are independent polynomial generators; the operators describe their commutators and are not their images under a Cartan inclusion. The Cartan coefficient algebra is -adically complete; no algebraic-freeness claim is made for the crossed products. Their products extend the products of the two factors and obey for the corresponding derivation . Equivalently, for multi-indices ,
where and . The coroot directions indexed by are linearly independent because is nonsingular, and the remaining directions supplement the minimal realization of dimension (Realization of a generalized cartan matrix); the number of Cartan symbols is .
(c) -adic Hopf structure and conditional Serre map. In the commutative formal Cartan factor, define for each Cartan polynomial ; every coefficient is a finite polynomial, so this is an element of . Write for the color-degreewise -adically completed tensor product: for each total color degree , complete in the -adic topology, then take the direct sum over ; use the same convention for and for iterated tensor products. There are finitely many splittings of each . The algebras are complete in each color degree, and multiplication extends on these degreewise completed tensors. Their direct sums are not asserted to be complete for limits with unbounded color support. These formulas make a topological Hopf -algebra: and are continuous algebra maps, is coassociative with both counit identities, and the continuous antipode satisfies both convolution-inverse equations.
The counit sends every nonempty word and every to and sends to . The antipode is the common convolution inverse constructed recursively in word length and Cartan-polynomial degree. The same structure maps make a topological Hopf subalgebra.
Let and be its tensor algebra with concatenation; every assignment of the to a unital -algebra extends uniquely by wordwise multiplication. Let be the quotient of by the two-sided ideal generated by
where the symmetric Gaussian coefficients are evaluated at . Let be the crossed product of this quotient with the commuting Cartan symbols , using the multiplication rule of part (b) for the induced derivations and acting by and . If the quantum Serre sums vanish in , then , , and , with the first two images the independent target Cartan symbols in define an algebra homomorphism . This definition makes no assertion that the Serre-vanishing condition holds or that is injective. All formal exponentials are interpreted -adically, and tensor completions are taken color-degreewise as specified above; no limit with unbounded color support is placed in either direct-sum algebra.
Facts & Assumptions
Given: A finite symmetrizable Cartan datum, its minimal realization, and the formal parameter .
, so is a symmetric bilinear form (Symmetrizable Cartan data for quantum groups).
There is a set with and (A nonsingular principal minor of the symmetrized Cartan matrix of size the rank).
A minimal realization has dimension and its simple coroots are linearly independent (Realization of a generalized cartan matrix).
Formal power series use coefficientwise addition and finite Cauchy products; is complete and separated in its -adic topology (Formal power series over a commutative ring and the coefficient-extraction functional ).
For a commutative -algebra and divisible by the formal variable, (Formal exponential, logarithm, and binomial powers over a commutative -algebra).
The symmetric Gaussian coefficients specialize to Laurent-polynomial coefficients in , so their substitution lies in (Quantum integers, factorials, Gaussian binomials and divided powers at , The quantum Pascal recurrences, the Gauss product formula and Gaussian integrality).
Tensor powers form the direct-sum word space and concatenation is associative (Tensor algebra of a vector space).
The bialgebra and Hopf axioms are algebra-map coproduct and counit, coassociativity, both counit identities, and both antipode convolution-inverse equations; here their tensor products are -adically completed as specified in (c) (Bialgebras, counits and antipodes over a commutative ring).
A map killing a two-sided ideal factors through its quotient (The ideal generated by a subset and principal ideals, The quotient ring with , A ring homomorphism whose kernel contains a two-sided ideal factors uniquely through the quotient ring).
Tensor products of algebras have multiplication (The tensor product of -algebras has multiplication ).
No axiom of choice is used: is a single subset of the finite set supplied by [F2]; all sums are finite and the recursion terminates on finite word length and Cartan degree.
A polynomial ring on the finite family of Cartan symbols consists of finite polynomials in those commuting symbols (The polynomial ring as finitely supported coefficient families on monomials).
A formal series over is a unit exactly when its constant coefficient is nonzero; a submodule of a finite free module over a PID is finite free (A formal power series is a unit exactly when its constant coefficient is a unit, Principal ideal domain, A submodule of a free module of finite rank over a PID is free of no larger rank).
Proof
For three word blocks, a shuffle of all letters is uniquely a shuffle of the first two blocks followed by a shuffle with the third, and also uniquely a shuffle of the last two followed by one with the first. In either description every inverted pair of letters occurs exactly once and contributes ; scalar weights therefore agree, proving associativity. The color degree is additive, and a fixed color multidegree has only finitely many words, each an -basis vector in the tensor-word space. Thus every graded component of is finite free. Also is a PID: a nonzero ideal has a least order , an element of that order is times a unit by [F13], and every other element is divisible by , so the ideal is . Each is a submodule of the finite free word module and hence finite free by [F13]. Tensoring these finite bases with shows that each color-degree component of and is a finite direct sum of copies of the complete coefficient algebra . Consequently each is -adically complete, and continuous multiplication on a fixed degree split extends to its completion; the finitely many splits of a fixed total degree give the stated completed multiplication.
On a word, acts by the sum of the weights of its letters and by the number of color- letters. Every shuffle term preserves these color counts, so each operator satisfies Leibniz for the shuffle product; their diagonal actions commute. Since each sends to a scalar multiple of itself, it preserves the subalgebra .
Repeatedly commute each past a coefficient using ; the commuting derivations and Leibniz rule give the finite multi-binomial formula in (b). Associativity follows from the two possible reductions of , which agree because , and the two reductions of , which agree because . Products of formal -series have finite coefficient sums and each multi-index sum is finite, so multiplication is well-defined coefficientwise.
The principal minor gives ; the minimal realization has independent simple coroots and dimension , so the coroot symbols and supplementary symbols give the required count. This uses no claim that alone spans the Cartan.
The exponent is a polynomial in commuting Cartan variables. Apply [F5] in the commutative coefficient algebra with formal variable : at order the coefficient is the finite polynomial . The coefficient of in is , equal to for and for , so is invertible with inverse . Since each Cartan variable is primitive, coefficientwise binomial expansion gives .
Fix cuts and , and write for a prefix of color degree . If has color degree , then , so . A global shuffle with this cut consists of a shuffle of the prefixes and a shuffle of the suffixes; its cross-cut inversions contribute by [F1]. On the right, multiplying the second tensor factors gives ; moving past contributes the same cross-cut factor. Rewriting the resulting combined prefix exponential in word-times-Cartan normal form contributes . Rewriting the corresponding Cartan-left factor on the left-hand coproduct gives this identical normal-form factor. The prefix and suffix shuffle weights also agree, so every cut and pair of shuffles has the same coefficient on both sides. Thus preserves the shuffle product.
The operators are additive over a word cut and annihilate the Cartan symbols, so they fix each Cartan exponential. Hence , which is exactly the commutator of with . Thus the coproduct preserves every crossed relation and extends as an algebra map to .
Both iterated coproducts of a word sum over two cuts; the factors agree because each prefix exponential is group-like, so is coassociative. Define as projection to the empty-word, constant-Cartan coefficient. It is an algebra map: positive color degree maps to zero, and every crossed commutator with a positive-degree word also maps to zero. The counit identities hold because only the empty-prefix term survives after applying to the first factor, only the all-letter prefix term survives after applying it to the second, and every Cartan exponential has counit .
Let be a word and a Cartan monomial, and induct lexicographically on (word length, Cartan degree). On Cartan polynomials set ; these are the antipode equations for the primitive commuting Cartan generators. For positive word length, in the unique term with the full word and full Cartan degree in the first tensor factor is . Every other term has a shorter first word or smaller first Cartan degree. Since is invertible, the left convolution equation recursively determines . The unique term with full word and full Cartan degree in the second tensor factor is ; all other terms have a shorter second word or smaller second Cartan degree, so the right convolution equation recursively determines a right inverse as well. The recursions terminate at every pair of finite word length and Cartan degree; each coefficient of every is a finite Cartan polynomial, so they extend coefficientwise to the formal -series in the stated modules. The left and right convolution inverses coincide by associativity. For a letter , , so the equations give .
In with convolution from the completed tensor coalgebra, is a two-sided convolution inverse of : since and are algebra maps, applying the two antipode equations to gives both inverse equations. The map is also a two-sided inverse, since and . These equalities follow by first applying the left and right antipode equations to and , respectively. Uniqueness of convolution inverses gives , so is anti-multiplicative. Hence and show . The coproduct and counit also restrict, so is a topological Hopf subalgebra.
The Cartan derivations preserve the two-sided ideal generated by the quantum Serre sums because each sum is homogeneous in the color grading. Under the stated vanishing condition, the free-algebra assignment kills every defining Serre generator; its Cartan commutators match the crossed-product derivations. By [F9] it therefore factors uniquely through to the stated algebra map.
Positive, negative and toral quantum subalgebras and their root gradings
Statement
Let be the Drinfeld–Jimbo algebra of The Drinfeld-Jimbo quantized enveloping algebra by generators and relations with its root-lattice grading . Define
the -subalgebras generated by the indicated images, and let . Then
The degree-zero component contains , and for every and ,
Thus each acts by conjugation on the degree- component as the scalar . The elements span and satisfy with ; hence is a quotient of the group algebra . The subalgebras are spanned by finite monomials in the and , respectively. Define the nonnegative and nonpositive product spans by
This definition asserts no linear independence of these spanning families and no injectivity of the natural maps; those claims belong to Triangular decomposition of a quantized enveloping algebra.
Facts & Assumptions
Given: The Drinfeld–Jimbo presentation is homogeneous in the root lattice, with the degrees of specified in The Drinfeld-Jimbo quantized enveloping algebra by generators and relations. The datum provides the pairing of roots and coroots in Symmetrizable Cartan data for quantum groups.
For a ring homomorphism , the first isomorphism theorem gives (First isomorphism theorem for rings: ).
The root lattice is , and its pairing with is integer-valued and additive (Symmetrizable Cartan data for quantum groups).
Proof
Every word in the is homogeneous of degree in ; the empty word has degree . By generation, every element of is a finite sum of such words. Grouping those terms by degree and using the direct grading of gives .
Every word in the is homogeneous of degree in , including the degree-zero empty word. Grouping finite sums by their degrees in the direct grading gives .
Define to be the vector space of finite sums with multiplication . By [F3], extends linearly and multiplicatively to a unital algebra homomorphism into . Its image is all of , since the image contains every generator and consists of finite linear combinations of them. Thus [F4] identifies with , and the span it.
The relations in [F3] give . By [F2], conjugation by acts on a word of degree by multiplying each factor by , each factor by , and each factor by . Additivity of the pairing in [F5] makes the product scalar . Every element is a finite sum of generator-word images; grouping those words by degree and using the direct grading [F1] shows that an element of is a finite linear combination of degree- word images. Thus the formula holds for every such . Since the have degree zero, their generated subalgebra lies in .
By definition, finite monomials in the and span and . Finite sums of products with and with span the two stated product subspaces. No basis or independence assertion is involved.
The quantum binomial expansion for -commuting elements
Statement
Let be an indeterminate over , and let be a unital associative -algebra. For and , set
and set when or . If satisfy , then for every ,
For a symmetrizable Cartan datum and , any unital -algebra can be viewed as a -algebra via . In that algebra, if , then
using the symmetric Gaussian binomials of Quantum integers, factorials, Gaussian binomials and divided powers at . If instead , the same expansion has coefficients .
Facts & Assumptions
Given: The conventions above, the Gaussian quotient definitions, and the relation when the generic expansion is used.
The asymmetric -integer and factorial use and the empty product ; for , is a nonzero polynomial, so the Gaussian factorial quotient is defined in (The -integer, -factorial and -multinomial coefficients).
The symmetric Gaussian coefficient satisfies (The quantum Pascal recurrences, the Gauss product formula and Gaussian integrality).
The symmetric and asymmetric Gaussian coefficients satisfy , with and (Quantum integers, factorials, Gaussian binomials and divided powers at ).
Since is indeterminate and , is transcendental; substitution therefore embeds into (Quantum integers, factorials, Gaussian binomials and divided powers at ).
Proof
For , ; multiplying for and dividing the factorials gives . The exponent equality follows by expanding the three quadratic terms; for both coefficients equal .
Put . Multiplying the recurrence [F2] by and using [F3] gives for ; outside this range all terms vanish. The first exponent becomes , and the second differs from by . By the injectivity in [F4], this is the generic recurrence .
For the formula is . Suppose it holds for . From , induction on gives : it is true for , and . Multiplying the expansion on the right by and reindexing the terms from the final gives the coefficient at . By step 1.2 this is , proving the generic expansion. Under , [F3] turns this coefficient into and gives the symmetric formula.
If , apply the generic expansion of step 2.1 with parameter . Step 1.1 rewrites its coefficients as , proving the inverse-parameter formula as well.
The Chevalley involution, bar involution, and contravariant anti-involution preserve the Drinfeld–Jimbo ideal
Statement
Let and be the free algebra and defining ideal of The Drinfeld-Jimbo quantized enveloping algebra by generators and relations, and put and for its displayed Serre sums. Define on generators by
Here fixes , while and apply the field involution to coefficients; and extend as algebra maps, and extends as an anti-algebra map. Each map preserves and descends to . All three are involutions; is a -algebra automorphism, a semilinear algebra automorphism, and a semilinear algebra anti-involution. On the Serre sums,
Facts & Assumptions
Given: The free algebra and the four families of generators of in the Drinfeld–Jimbo presentation.
The ideal is generated by the toral, toral-action, mixed , and positive and negative Serre relations displayed in The Drinfeld-Jimbo quantized enveloping algebra by generators and relations.
The symmetric Gaussian coefficients satisfy and are invariant under ; has the same inversion symmetry (Quantum integers, factorials, Gaussian binomials and divided powers at ).
Assignments of the free generators extend uniquely to algebra maps on (Universal property of the tensor algebra); reversing the order of each word gives the corresponding anti-algebra extension.
Proof
The substitution is an involutive field automorphism of . By [F3], the displayed assignments extend to a -algebra endomorphism , a -semilinear algebra endomorphism , and a -semilinear anti-algebra endomorphism of . Each square fixes every generator and coefficient, so all three squares are the identity on .
The maps send to itself. They send respectively to , the same relation, and , the same family with its two indices reversed. Thus each image lies in .
Write , , and . Then and ; and ; and and . Each is a scalar multiple of a defining toral-action relation.
Let . Direct substitution, including the semilinear inversion of the coefficient in and , gives , , and . The ratio is unchanged when both numerator and denominator are inverted. Hence these images lie in .
Put . Applying to a positive Serre sum contributes minus signs and preserves the order of factors, so ; the negative case is symmetric. By [F2], fixes the coefficients and each , so it fixes both Serre sums. The anti-map reverses each monomial; reindexing and using [F2] gives . Thus all Serre images belong to .
The preceding steps show that each map sends every generator of into that ideal. Since is two-sided, the algebra maps and the anti-algebra map send the whole ideal into itself. They therefore descend to the quotient; their squares remain the identity there, which makes the descended maps automorphisms or an anti-automorphism of the stated types. This proves the assertion.
The coproduct preserves the positive and negative quantum Serre ideals
Statement
Let be a symmetrizable Cartan datum, use the notation , and of The Drinfeld-Jimbo quantized enveloping algebra by generators and relations, and put for . Let and be the free -algebras on the symbols and , respectively. Let and be the two-sided ideals generated by , , and respectively or . Define the toral-action algebras and , and let and be their two-sided ideals generated by the images of the corresponding Drinfeld–Jimbo Serre elements.
The generator assignments
define algebra homomorphisms . For every , the Serre elements are quasiprimitive:
Consequently . The canonical maps send the displayed coproducts of the Serre elements to zero in ; thus these formulas provide the Serre-family part of the check that the Drinfeld–Jimbo coproduct descends.
Facts & Assumptions
Given: A symmetrizable Cartan datum over and the defining relations and Serre sums in The Drinfeld-Jimbo quantized enveloping algebra by generators and relations.
For and , symmetrizability gives , so ; also (Symmetrizable Cartan data for quantum groups).
The Drinfeld–Jimbo toral-action relations are those displayed in The Drinfeld-Jimbo quantized enveloping algebra by generators and relations.
The positive and negative Serre sums are those displayed in The Drinfeld-Jimbo quantized enveloping algebra by generators and relations.
The symmetric Gaussian coefficients are factorial quotients and satisfy (Quantum integers, factorials, Gaussian binomials and divided powers at ).
If lie in an algebra and , then (The quantum binomial expansion for -commuting elements).
The tensor product has multiplication (The tensor product of -algebras has multiplication ).
The tensor algebra on the free generators admits the unique algebra extension of every generator assignment (Tensor algebra of a vector space, Universal property of the tensor algebra).
Quotient algebras and factor maps are as in The quotient ring with and A ring homomorphism whose kernel contains a two-sided ideal factors uniquely through the quotient ring.
A two-sided ideal generated by a subset is as in The ideal generated by a subset and principal ideals.
Proof
Write , , , and let be as in the statement. The algebra maps on prescribed by the displayed coproduct assignments exist by the tensor-algebra universal property in [F8], with the target tensor products made into algebras by [F7].
For every , the coefficient identity [F6] cancels the alternating sum with exponent . For the corresponding one-term sum equals . These two cases will distinguish the mixed terms from the two extreme bidegrees below.
The images of and vanish because and . For , in the positive algebra : its two summands cancel by in the first tensor factor and in the second tensor factor, while the toral elements commute. In the negative algebra, by in the first and second tensor factors and commutation of toral elements. Thus both maps kill and descend to by [F9].
In , put and . The toral-action relation gives , so [F5] yields . Also is grouplike and invertible since in .
Expand and first take the term from the middle factor. Fix with , and put ; the allowed indices are . Using [F5] on the two powers of , the corresponding tensor word is , and its coefficient is . Here follows by cancelling the factorial quotients, and the exponent comes from moving past and .
Now take the term from the middle factor. Fix with ; after moving toral factors to the left, the tensor word is . Its coefficient, summed over with , is , where . Indeed the unsummed Gaussian factor is , and the two q-binomial expansions and toral crossings give exponent , using . The prefactor is independent of and is when .
If , summing the coefficients in step 4.1 over gives a scalar multiple of by step 1.2. If , only remains; then , and summing over these pairs gives , using . Thus the part contributes exactly the first term in the claimed formula.
For , the sum in step 4.2 is zero by step 1.2. For , the only term has , and its coefficient is ; these terms sum to . Combining this with step 5.1 proves the positive quasiprimitive identity.
Define by and . The toral and positive action relations map to the toral and negative action relations (the action relation at ), so this is a well-defined algebra map. Directly on generators, : on both sides equal , and on both sides equal . Moreover by applying the substitution to its factors. Applying this identity to the positive quasiprimitive formula gives .
The subspace is a two-sided ideal of by the tensor multiplication in [F7], and likewise for the negative sign. The two quasiprimitive identities therefore imply , since each is generated as a two-sided ideal by the Serre elements and is an algebra map. The canonical maps send every Serre generator to zero; applying their tensor squares to the formulas gives zero, so the Serre relations are preserved by the prescribed coproduct in the full Drinfeld–Jimbo quotient. Once the other defining relation families are checked, the quotient universal property in [F9] gives the descended coproduct.
Source note
The Berkeley text defines its toral-action-only positive Borel and gives the positive quasiprimitivity statement in Lemma 13.1.3.9, then says the cited Jantzen proof is a tedious q-binomial computation; it does not print the computation or the explicit grouplike factors. Jeong–Kang–Kashiwara display the coproduct convention used here in (1.6) but assert the Hopf structure without proving relation preservation. The coefficient cancellations in steps 4.1–6.1 are supplied locally; the original scaffold's claim that Serre-only ideals in the completely free algebra are coideals was replaced because its toral commutations are not valid before quotienting by the toral-action relations.
The quantum Serre sums vanish in the shuffle algebra, and the opposite Serre ideal annihilates the shuffle half
Statement
Let , and be as in The formal quantum shuffle Borel and its Cartan crossed product.
(i) In the Serre sums vanish: for all , where is the shuffle product of The formal quantum shuffle Borel and its Cartan crossed product.
(ii) Let be the dual space with , let be the tensor algebra on with concatenation product, graded by , and let be the braided coproduct with , the target carrying the braided product . Let be the two-sided ideal generated by the negative Serre elements , . Let be the wordwise pairing, extended bilinearly from the tensor-word bases. Then annihilates the shuffle half : equivalently the wordwise pairing descends to a bilinear pairing . The twisted product on is used only in the definition of the braided coproduct, and no claim is made about the radical of the pairing on all of (see the note after the proof).
Facts & Assumptions
Given: The formal shuffle Borel of a finite symmetrizable Cartan datum and the wordwise pairing stated in part (ii).
For , , , , and , so is a symmetric bilinear form (Symmetrizable Cartan data for quantum groups).
, is the product of the symmetric -integers, and with (Quantum integers, factorials, Gaussian binomials and divided powers at ).
are the coefficients in the q-binomial expansion when , and (The quantum binomial expansion for -commuting elements, The quantum Pascal recurrences, the Gauss product formula and Gaussian integrality).
The symmetric Gaussian coefficients are Laurent polynomials in and satisfy the q-Pascal and Gauss product identities (The quantum Pascal recurrences, the Gauss product formula and Gaussian integrality).
The wordwise quantum shuffle product on uses inversion weight with ; one-letter words are elements of (The formal quantum shuffle Borel and its Cartan crossed product).
The pairing of part (ii) is diagonal in the tensor-word bases: for tensor words and it equals ; in particular it carries no sign and it is invariant under the interchange of letters. The letter weights and are symmetric.
The proof uses only finite word shuffles, coefficient identities, explicit word comparisons and the finitely many permutations of letters; no axiom of choice is used.
Proof
Put , , , , and outside . Let (with letters), and let be the word with copies of , then , then copies of (omitting a zero-length block). Repeatedly shuffling one into a block of equal -letters gives , where : the insertion weights sum to . In a three-block shuffle , with , fix , and let (respectively ) count the -block letters before (respectively after) , so . The prefix interleavings contribute , the suffix interleavings contribute , the letters before cross and the letters after it, and each of those letters crosses those suffix -letters; therefore .
The pairing is diagonal in the tensor-word bases: for tensor words and the defining formula gives , and depends only on . Consequently, for and tensor words with letter-sequences , both sides of equal : the left side because only the word has nonzero pairing with , the right side because only the cut contributes, the product in being concatenation and the cut coproduct of the word being . Extending by bilinearity, this adjunction rule holds for all and all .
For homogeneous one-letter words put . Then . Here maps each original letter position to its output position, consistently with [F5]. For this is the identity. If it holds for , write the product as ; inserting into the -th position of a word multiplies its coefficient by , exactly the sum of the weights of the pairs inverted by the resulting permutation, so the block formula reproduces the displayed expansion; the map the resulting permutation is a bijection onto .
In the coefficient of in , set , write , and use and . The coefficient simplifies to . The quotient definition gives ; induction then yields . Thus the first factor in parentheses is and vanishes when ; the second is and vanishes when . Since , at least one factor vanishes for every . These words exhaust the color degree , proving part (i).
Fix and , and put , ; these are the values , and is symmetric by [F1]. Let ; since , the element differs from the printed Serre generator by the global sign , so the two generate the same two-sided ideal. For let , and for let be the tensor word with letters , then , then letters . By [F6] and steps 1.2 and 1.3, , where and is the weight of the letters at positions of the sequence . Then : the map is a bijection from the permutations with onto those with , and it preserves the exponent, because the inversion pairs of correspond to those of with the same pair of letters: if for an inverted pair , then , and the weight of the pair equals the weight of the letter pair at the positions of the transposed sequence , since carries the position of onto the position , so the letter at position of the transposed sequence is the letter at position of the original sequence for every .
The cut coproduct is an algebra map from to its tensor square with product . Indeed a shuffle followed by a cut consists uniquely of shuffles of the two prefixes and two suffixes; its cross-cut inversions contribute , exactly the scalar in this tensor product. On a letter the coproduct is primitive, so it sends every product of letters into . Write this finite sum as with ; individual prefixes of ambient tensor words need not themselves belong to the generated half. If annihilates , step 1.2 gives and likewise . Thus is a two-sided ideal.
By part (i) the element is zero in , so all of its tensor-word coefficients vanish. By step 1.3 the coefficient of in is , hence for every . Substituting and using (so that is the global factor ) gives for every ; by the symmetry of step 2.2 this is for every . Hence step 2.2 gives for every .
A shuffle product of one-letter words is homogeneous of color degree , and is generated by the one-letter words, so every is a finite sum of such products. Unless the letters are exactly copies of and one copy of , their color degree differs from that of , so the diagonal pairing vanishes. In the remaining case the letter weights agree with the two-letter computation of step 2.2, and step 3.1 gives . By linearity for every , that is, . Consequently every Serre generator lies in the two-sided ideal of step 2.3, and hence so does the ideal they generate: . This is the stated annihilation and the asserted descent of the wordwise pairing.
Remarks
The literal analogue of (ii) with all of in place of is false, so the restriction of the domain is necessary: the tensor word with copies of pairs with the term of the Serre generator and with no other term, giving . The source's literal full- radical clause therefore fails for the diagonal pairing. The restricted generated-half annihilation used here is proved independently above and supplies the final half-to-half duality. Printed formula (28) also has a single prefactor; the multiplicative adjunction with generator weights requires the length- weight used in this item and verified in step 1.2.
The generic quantum halves form a Drinfeld–Jimbo crossed double
Statement
Fix a finite symmetrizable Cartan datum over , with and . Let and be the independently presented -algebras on and , respectively, modulo their separate symmetric quantum Serre relations, and let have basis , . Then the vector space carries a unique associative unital algebra structure in which equals the product of the three embedded factors, the factors retain their algebra structures, and This is the Drinfeld–Jimbo crossed double. Its normal-factor multiplication map to the presented algebra of The Drinfeld-Jimbo quantized enveloping algebra by generators and relations is an algebra isomorphism, whose inverse sends to the indicated factor generators. Thus all three abstract factor maps are injective; their images are the subalgebras of Positive, negative and toral quantum subalgebras and their root gradings.
In the presentation obtained by omitting both Serre families, the halves are free, the toral factor is , and multiplication identifies . Every Serre element satisfies Writing for the separate Serre ideals, the full Serre ideal of is exactly No nonsingularity of the Cartan matrix and no choice principle is required.
Facts & Assumptions
Given: A finite symmetrizable Cartan datum and its Drinfeld–Jimbo presentation.
The toral, toral-action and mixed relations give the Serre-free presentation; adding the separate Serre sums gives , and assignments satisfying these relations extend uniquely (The Drinfeld-Jimbo quantized enveloping algebra by generators and relations, Universal property of the tensor algebra, A ring homomorphism whose kernel contains a two-sided ideal factors uniquely through the quotient ring).
The integral weight characters are additive, , and by symmetrizability (Symmetrizable Cartan data for quantum groups).
For , the symmetric Gaussian coefficients satisfy and for . The first identity is factorial cancellation and the second follows from the Gauss formula and its inverse-parameter substitution (Quantum integers, factorials, Gaussian binomials and divided powers at , The quantum Pascal recurrences, the Gauss product formula and Gaussian integrality).
Tensoring quotient maps is surjective and has kernel the sum of the factor kernels, by repeated right exactness (Tensoring is right exact).
The positive, negative and toral subalgebras are the generated images of the corresponding presentation generators (Positive, negative and toral quantum subalgebras and their root gradings).
Proof
Put . In the free Serre-free presentation reduce to , to , to , to , and to . For each monomial use the lexicographic triple consisting of the number of letters, the number of inverted type pairs for , and the number of toral letters. Every resulting term decreases this triple: the mixed correction decreases the first coordinate, the other mixed or crossing terms decrease inversions, and toral merging or deletion decreases inversions or the final coordinate. Each rule has finitely many outputs, so the finitely branching reduction tree terminates; an infinite tree of arbitrarily deep descendants would give an infinite decreasing path by choosing its first such child at each stage. The irreducible words are precisely , with interpreted as the empty toral factor.
Fix , set , , , and , so . Expanding the commutator in each position and moving toral factors to the right gives for : the two geometric sums are . For , the commutator is zero because every letter commutes with . For , only the contributes, and moving past the last copies of gives The crossing uses from [F2], and both sums vanish by [F3] because .
The overlapping reductions are , , , and , together with deletion of against an adjacent crossing or toral product. The first three give respectively , , and along both routes. In the fourth, the two routes give the common term and corrections and ; they agree since the toral elements commute and whenever the correction is present. The zero-index cases and a toral sum agree by character additivity and . There is no overlapping pair of rules, since its shared letter would have to be both and . Disjoint reductions commute by distributivity. Inducting on the decreasing triple in step 1.1, these joined first reductions therefore have the same final normal form in every word context. The linear normal-form map kills each relation multiplied on the left and right by arbitrary words, while every word minus its normal form lies in the relation ideal. It consequently induces inverse linear maps between and the freely based normal-word space. This proves the full Serre-free tensor decomposition, including injectivity on arbitrary finite sums.
For , expand in the left and right blocks using step 1.2. The left-block term with and right-block term with both have positive word . In the left-block term, the exponent after moving to the right is , since ; the inverse toral exponent is . The right-block term has those same exponents. Thus The coefficient identity is [F3], including both endpoints. The assignment , , is an involutive algebra map of the Serre-free presentation: toral actions reverse their signs, and both the mixed commutator and change sign. Applying it proves . Toral conjugation of either Serre generator is scalar, since its color degree is homogeneous.
In the normal-word space put . It contains the Serre generators and is a two-sided ideal. Same-side multiplication and toral multiplication preserve its two summands, using homogeneous toral conjugation. For the remaining crossed multiplications, expanding for a positive word yields positive-word/toral terms, and expanding for a negative word yields negative-word/toral terms, by the mixed relation. If , the Leibniz rule gives because the middle commutator vanishes by steps 1.2 and 2.2. Moving the resulting toral factors past the homogeneous Serre sum preserves its ideal. Hence , and similarly . When moving a crossed generator through an arbitrary normal product, these inclusions show that every term still belongs to ; multiplication in the other half only multiplies the existing ideal factor. This checks closure under all on both sides. Conversely each summand of lies in the ambient two-sided Serre ideal, by its definition. Therefore equals that ideal, with the exact tensor-factor description claimed.
By [F4], the tensor quotient is the quotient of by precisely . Steps 2.1 and 3.1 therefore identify it linearly with , proving genuine tensor injectivity. Transport the associative quotient multiplication to this tensor space to define . Its factor products, normal-factor products and cross-relations are as stated, and the factor embeddings are injective because survives both homogeneous positive-height Serre ideals. Conversely any multiplication with those properties is determined by repeatedly using the crossing rules to rewrite a product of two normal tensors; these rules terminate by step 1.1. Thus the algebra structure is unique. Its generator map to and its inverse respect the defining relations by [F1] and the factor Serre relations, so are mutually inverse algebra homomorphisms. Their factor images are exactly [F5]. This proves all assertions.
The Drinfeld–Jimbo formulas define a Hopf algebra
Statement
Let and be the free -algebra and defining ideal of The Drinfeld-Jimbo quantized enveloping algebra by generators and relations, and write . Let and be the algebra homomorphisms determined by
Let be the -linear algebra anti-homomorphism determined by
Then
Hence these maps descend to and make it a Hopf algebra over (Bialgebras, counits and antipodes over a commutative ring): is coassociative, is a counit, and
The antipode is unique for this multiplication, unit, coproduct and counit (Uniqueness of the antipode), and its square satisfies
Facts & Assumptions
Given: A symmetrizable Cartan datum over and its Drinfeld–Jimbo presentation.
The symmetrizer satisfies , so the two crossing factors and are equal (Symmetrizable Cartan data for quantum groups).
The defining ideal is generated by the toral, toral-action, mixed , and positive and negative Serre relation families (The Drinfeld-Jimbo quantized enveloping algebra by generators and relations).
The -Gaussian coefficients are symmetric in and , and (Quantum integers, factorials, Gaussian binomials and divided powers at ).
In the toral-action algebras, the Serre coproducts are the quasiprimitive formulas stated in The coproduct preserves the positive and negative quantum Serre ideals; their images in are zero.
The tensor product of algebras has multiplication (The tensor product of -algebras has multiplication ).
Generator assignments extend uniquely to algebra maps on the free tensor algebra (Universal property of the tensor algebra).
A map that kills a two-sided ideal factors through the quotient ring (The quotient ring with , A ring homomorphism whose kernel contains a two-sided ideal factors uniquely through the quotient ring).
A two-sided ideal generated by a subset is as in The ideal generated by a subset and principal ideals.
Tensoring an exact sequence ending in zero preserves exactness at the two rightmost terms (Tensoring is right exact).
Tensor products over have the symmetry isomorphism (Symmetry and associativity isomorphisms for tensor products over a commutative ring).
A bialgebra has algebra maps satisfying coassociativity and the counit equations; a Hopf algebra has an antipode satisfying both convolution-inverse equations (Bialgebras, counits and antipodes over a commutative ring).
An antipode, if it exists, is unique (Uniqueness of the antipode).
Proof
The displayed assignments extend from the free generators to an algebra map by [F6], using the tensor product algebra structure in [F5]. The counit assignment extends to an algebra map by [F6], and reversing words extends the assignment for to a -linear anti-homomorphism.
Let be the quotient map. Write and for the images of the corresponding tensor-product maps in . Right exactness [F9] gives ; by applying [F9] again after the flip [F10], , and is surjective. If , then lies in this second kernel, so choose with the same image; then . Thus . This uses only a lift for one tensor at a time, not a choice function.
The counit sends and to . It sends each toral-action relation to , each mixed relation to , and every Serre sum to zero because each monomial contains an or an . Thus .
The anti-homomorphism sends to itself and to , another toral generator. For , applying to the toral-action relation gives in by the relation at ; applying it to the relation gives by the same relation and commutation of the toral elements.
In , the toral relations are preserved: and . For , the two terms in cancel by in each tensor factor and commutation of toral elements; the two terms in cancel by the negative toral-action relation in each factor. Therefore kills the toral and toral-action generators of .
Applying to and moving toral factors with the defining relations gives in . For the first factor vanishes by ; for its scalar is , , and , so the two terms cancel. Hence in .
Let . In , each of the substituted generators contributes a minus sign; moving the inserted to the right contributes exponent . Reindexing and using the symmetric Gaussian coefficients [F3] contributes the remaining sign, so . For the negative family, gives by induction. Moving all toral factors to the right contributes exponent ; the equality from [F1] is used when crosses , and supplies the additional factor . Reindexing and using [F3] gives . These identities are computed modulo the toral and toral-action relations only; their right sides lie in the two-sided Serre ideal. Thus both Serre families map into .
Put and . Expanding the commutator of the coproducts, the cross terms cancel because and , where the equality is [F1]. Hence . In , , and direct expansion gives . Thus the image under of every mixed relation is zero.
For each positive or negative Serre generator, [F4] maps its coproduct to zero in . Therefore kills all remaining generators of .
Steps 1.4, 2.2 and 2.3 show that sends every generator of into . Since reverses products and is a two-sided generated ideal, ; the quotient property [F7] gives the descended anti-homomorphism on .
By step 1.2, steps 2.1, 3.1 and 3.2 put every defining generator's coproduct in . This sum is a two-sided ideal: for pure tensors, left and right multiplication preserve each summand because is a two-sided ideal; the product formula in [F5] gives these products. Since is an algebra map, it contains the coproduct of every element of the generated ideal .
For , both antipode products are and . For , they are and . For , they are and . Since by construction, the equations hold on the unit as well. These are the two convolution equations of [F11] on every generator and on the unit.
The maps and descend by steps 4.1 and 1.3. For , both iterated coproducts equal . For , each equals ; for , each equals . Thus coassociativity holds on generators. On both counit composites equal ; on they give and ; on they give and . Each side of these identities is an algebra homomorphism, so equality on the generators and unit proves equality on all of , giving the bialgebra axioms in [F11].
Write . If the two convolution equations hold for words and , then anti-multiplicativity of and multiplicativity of give . Likewise . Since is multiplicative and all words are products of generators, induction gives both identities on every word and hence every element of . Thus is an antipode as defined in [F11].
Uniqueness follows from [F12]. Since reverses products, is an algebra homomorphism, and on generators , , and . This proves the statement.
Source note
JKK §1, display (1.6), printed p. 6, gives exactly the coproduct, counit and antipode convention used here but asserts the Hopf structure without proving relation preservation. Berkeley Ch. 13 §13.1.3, printed pp. 308–309, gives the positive Serre quasiprimitivity/Hopf-ideal results and a different coproduct convention; the convention-sensitive relation calculations are local. The scaffold's claim that the convolution antipode equations extend from generators because all maps involved are algebra or anti-algebra homomorphisms is invalid: is not generally an algebra homomorphism. Step 5.2 supplies the required word-induction argument. The free-ideal coideal claim uses the explicitly proved tensor-quotient kernel calculation in step 1.2, rather than an unproved freeness or choice argument.
The formal quantum Serre half embeds in the shuffle algebra and is degreewise free
Statement
Let , , , and be as in The formal quantum shuffle Borel and its Cartan crossed product, with and , and let be the positive half of the Kac–Moody algebra. Assume AC; it is used only to apply the two-sided coideal lemma in step 3.1. For an indeterminate , let be the algebra over with the same generators and positive quantum Serre relations, with . Then:
(i) The composite is an isomorphism of -algebras onto . In particular, is a free -module and each root-graded component is a finite-rank free -module.
(ii) The classical limit is the classical half: as -graded algebras, by .
(iii) For every ,
Facts & Assumptions
Given: A finite symmetrizable Cartan datum and the formal Borel and quantum half of The formal quantum shuffle Borel and its Cartan crossed product.
The formal Borel defines the conditional algebra map , gives as an -module, and gives the coproduct on Cartan symbols and words (The formal quantum shuffle Borel and its Cartan crossed product).
For each , the positive quantum Serre sum vanishes in ; this is part (i) only of The quantum Serre sums vanish in the shuffle algebra, and the opposite Serre ideal annihilates the shuffle half. The supplier's annihilation statement (ii) is not needed for this embedding proof.
At , the positive Serre relations present , and the classical Borel is generated by its Cartan and positive simple generators (Serre presentation of a kac moody algebra).
Under AC, an augmented two-sided coideal ideal in is generated by its primitive intersection (An augmented coideal ideal of an enveloping algebra is generated by its primitive part).
The opposite classical Borels are degreewise perfectly paired Lie bialgebras (The opposite Borels of a symmetrizable Kac–Moody algebra are root-degreewise dual Lie bialgebras).
The formal order on is additive on nonzero products, and is a domain (Formal order is non-Archimedean under sums and additive under products over a domain).
A finitely generated module over a PID is its torsion submodule plus a finite free summand (A finitely generated PID module is its torsion submodule direct-summed with a finite free module).
The symmetric Gaussian binomial is defined by the quantum-factorial quotient (Quantum integers, factorials, Gaussian binomials and divided powers at ).
AC is the assertion that every family of nonempty sets has a choice function (The Axiom of Choice).
A positive-sized square matrix over a commutative ring is invertible exactly when its determinant is a unit (For , the determinant over a commutative ring by the Leibniz formula, and for a real matrix, A positive-sized square matrix over a commutative ring is invertible if and only if its determinant is a unit).
For a finite-dimensional vector space, the dimension of a quotient by a finite-dimensional subspace is the ambient dimension minus the subspace dimension (Rank-nullity: ).
The fraction field of a domain is a field, and every injective map from the domain to a field extends uniquely and injectively to its fraction field (The field of fractions of an integral domain, is a field and embeds the integral domain , Every injective ring map from a domain into a field factors uniquely through its field of fractions).
A PID is a domain in which every ideal is principal (Principal ideal domain).
Every finitely generated module over a PID is a finite direct sum of cyclic modules (Invariant-factor decomposition of a finitely generated module over a PID).
The enveloping algebra is the tensor algebra quotient by the Lie-relator ideal, and Lie algebra maps into associative algebras extend uniquely to it (Universal enveloping algebra, Universal property of the enveloping algebra).
Tensoring is right exact, so a quotient presentation remains a quotient by the scalar-extended relation subspace (Tensoring is right exact).
The standard coproduct on makes its Lie generators primitive and is cocommutative (Hopf-algebra structure on U(g)).
A generalized Cartan matrix has a finite nonempty index set with (Generalized cartan matrix).
The symmetrizer entries are positive integers and (Symmetrizable Cartan data for quantum groups).
is the formal power-series ring with coefficientwise operations (Formal power series over a commutative ring and the coefficient-extraction functional ).
is the formal exponential (Formal exponential, logarithm, and binomial powers over a commutative -algebra).
A formal power series is a unit exactly when its constant coefficient is a unit (A formal power series is a unit exactly when its constant coefficient is a unit).
A submodule of a finite-rank free PID module is finite-rank free (A submodule of a free module of finite rank over a PID is free of no larger rank).
Every symmetric Gaussian coefficient is a Laurent polynomial in (The quantum Pascal recurrences, the Gauss product formula and Gaussian integrality).
Proof
By [F2], the generator assignment of [F1] defines . Its restriction to the Cartan coefficient algebra is the identity, and its image contains every one-letter word . Every element of is a finite sum of products of a letter-generated element and an element of , so is surjective. In the symmetric formula, specializes to at ; therefore specializes to and each Gaussian coefficient specializes to . By [F3], the reduced source is and reduction defines a surjective graded algebra map .
The ring is a PID: if is an ideal, the orders of its nonzero elements have a least value ; choose of order . It has the form with a unit by [F22], so , while every has order at least and is divisible by . Thus ; the zero ideal is principal as well, and [F6] says is a domain, so [F13] applies.
Each generator of the classical Borel has primitive coproduct by [F17], and its image under is primitive in : this follows for Cartan symbols from [F1] and for by reducing its displayed coproduct modulo . Hence commutes with coproduct and counit on generators, and therefore on the generated algebra. Thus is a surjective Hopf map; since is cocommutative by [F17], so is . This argument establishes Hopf compatibility only after reduction and makes no Hopf claim about .
Put and . As the kernel of a Hopf map, is a two-sided ideal and has zero counit. For , ; right exactness of tensor products and surjectivity of give , so is a coideal. Under the stated AC hypothesis, apply [F4] to obtain with a Lie ideal. The universal property [F15] identifies the quotient with , where , and with the quotient map. AC is used here only through [F4]; all other choices below are finite-dimensional or explicitly specified.
The first-order skew part of the formal Borel coproduct is well-defined on : its numerator reduces to zero by step 2.1, and changing a lift by changes the quotient by , which is zero modulo because is cocommutative. The quotient is unique because is a domain and the coefficientwise word–Cartan module is -torsion-free. To see this, each is a submodule of a finite free word module and hence finite free by [F23] and step 1.2; tensoring each such component with the coefficientwise torsion-free in [F1] preserves -torsion-freeness, as do its coefficientwise completed tensor powers. Put and let cyclically permute three tensor factors. Coassociativity gives : expanding gives four permutations of , whose cyclic sums cancel in pairs. Since is divisible by , division by and reduction prove co-Jacobi for , and flip gives antisymmetry. For primitive , subtracting the two algebra-map commutator identities for and , dividing by , and reducing gives , the required -cocycle rule. Directly from [F1], and . These values lie in ; since is generated by their images and the cobracket is a -cocycle, restricts to a Lie-bialgebra cobracket on . The transposed bracket in [F5] gives the same formulas on : its Cartan cobracket is zero and its explicit rescaled-Manin normalization gives . Thus is a Lie-bialgebra map, because both cobrackets obey the -cocycle rule and agree on the Cartan and simple generators.
The graded dual is injective and is a Lie-algebra map by step 3.2 and [F5]; every root component is finite-dimensional. Its image contains the full Cartan subalgebra because maps the classical Cartan basis to the independent polynomial Cartan variables, and it contains each because in the one-dimensional simple-root component. Since is generated by its Cartan and the by the separate Serre presentation [F3], the image is all of . Dualizing each finite-dimensional root component shows is an isomorphism, so and is an isomorphism.
The map preserves the grading and sends to . The module decomposition in [F1] identifies the image of in with . Restricting the isomorphism of step 4.1 to the positive subalgebra proves and identifies that classical half with .
Fix . Since is finite by [F18], the word space has finitely many words and is finite free over , so is finite-rank free by [F23]. The presented component is finitely generated, since it is a quotient of the finite free span of words of degree . By [F7] and [F14] over the PID of step 1.2, write , with for positive integers : every nonzero nonunit of is a unit times a power of . Since by step 5.1, if , then .
The surjection restricts to , and has rank because its reduction is the classical component in step 5.1. The target is torsion-free, so this map kills ; reducing the induced surjection modulo gives . Together with , this forces and . At , both components are and the map sends unit to unit. If , the decomposition gives . For , choose bases: the surjection is a square matrix whose determinant reduces to a nonzero determinant over , hence is a unit by [F22]; [F10] makes it invertible. Therefore is an isomorphism for every , proving (i) and the first equality in (iii).
Put . Evaluation embeds into : for a nonzero polynomial, factor out its maximal power of ; the remaining factor has nonzero value at , while , so its evaluation is nonzero in the domain . By [F19] and [F21], this substitution sends to ; [F12] extends the injection to . For fixed , the relations in that degree are the columns of a finite matrix over ; finiteness follows because there are finitely many words of degree , and [F24] makes every Gaussian entry Laurent polynomial. Substituting gives the formal presentation matrix for . By [F16], its quotient after extension to is the quotient by the same specialized columns. A field embedding preserves which matrix minors vanish, so the generic and formal matrices have the same rank; [F11] and step 7.1 give . This proves the remaining equality in (iii) and completes all assertions. The theorem is not an iff statement, so there are no reverse implications to prove.
Generic quantum Serre halves have classical PBW ranks and a nondegenerate Hopf pairing
Statement
Let , , , and for a finite symmetrizable Cartan datum. Let , and the shuffle product be as in The formal quantum shuffle Borel and its Cartan crossed product, and put using The quantum Serre sums vanish in the shuffle algebra, and the opposite Serre ideal annihilates the shuffle half. Assume AC (The Axiom of Choice), used only through the formal embedding theorem. For an indeterminate , let be the algebras over presented by the separate symmetric quantum Serre relations, with parameters .
(i) Each is finite free over , and Every family of homogeneous lifts of a basis of the classical component is an -basis. Likewise, homogeneous word expressions with coefficients rational in , regular at , which reduce to a classical component basis form a basis of the corresponding generic component. In particular, for a supplied ordered homogeneous basis of , ordered monomials in any such regular lifts form a generic PBW basis.
(ii) Both formal halves are graded braided Hopf algebras. Their generators are primitive, their counits kill positive height, and their tensor squares use with negative degrees for . The word pairing restricts and descends to a nondegenerate -valued pairing with and . It is zero on unequal opposite degrees and satisfies the braided Hopf adjunctions The generic halves have the same braided Hopf structures and a nondegenerate -valued pairing normalized by . Thus opposite graded components are dual. All generic assertions also hold for the corresponding -presentations and their rational pairing, with the PBW lift clause using bases of the rational classical Serre form.
Facts & Assumptions
Given: The finite symmetrizable datum, its formal and generic Serre presentations and the formal parameter.
The positive formal half is isomorphic to , its intrinsic reduction is , and its finite free components have the stated classical and generic ranks; AC enters only in its coideal argument (The formal quantum Serre half embeds in the shuffle algebra and is degreewise free, The Axiom of Choice).
The negative Serre ideal annihilates under the diagonal pairing of word bases with value on matching length- words. The cut coproduct is an algebra map to the scalar-braided tensor square and preserves the generated half (The quantum Serre sums vanish in the shuffle algebra, and the opposite Serre ideal annihilates the shuffle half).
The formal word space is degreewise finite free, its scalar form is symmetric, and the Serre coefficients are symmetric Gaussian Laurent polynomials (The formal quantum shuffle Borel and its Cartan crossed product, The quantum Pascal recurrences, the Gauss product formula and Gaussian integrality).
The classical half admits an ordered homogeneous basis obtained by enumerating its finite bracket words, and ordered monomials in that basis form its enveloping-algebra basis (PBW for countably presented Kac Moody Lie algebras).
Tensoring is right exact, so the tensor quotient kernel is the sum of the two factor kernels; over a field every injection remains injective after scalar extension (Tensoring is right exact, Restriction of scalars and extension of scalars along a ring homomorphism ).
The fraction field of is , and a domain embedding into a field extends to its fraction field (The field of fractions of an integral domain).
Proof
The identification of free generators carries the positive Serre presentation onto the negative one, reversing degrees; the same holds classically and generically. Thus [F1] gives all three rank equalities and finite freeness on both sides. In a fixed finite free component, lifts of a classical basis have a coordinate matrix whose reduction is invertible over , so its determinant has nonzero constant term and is an -unit. The adjugate identity makes this matrix invertible over , proving the formal lift assertion.
Give the free positive tensor algebra the primitive-generator coproduct into its scalar-braided tensor square. Its map to commutes with the cut coproduct: both are algebra maps by [F2] and agree on each letter. By [F1] its kernel is precisely the positive Serre ideal. Hence the composite of the tensor coproduct with the two quotient maps kills that ideal, and [F5] gives its coideal inclusion and descended coproduct. The same presentation identification gives the negative coproduct. Coassociativity and counit follow on primitive generators and hence on the generated algebras. The color-height grading is connected, so the reduced coproduct of a positive-height homogeneous element has both factors of strictly smaller height. The recursion and its right-handed counterpart provide left and right convolution inverses by height induction; associativity of convolution makes them equal. Thus both quotients are braided Hopf algebras.
The substitution embeds into : a nonzero polynomial is with , and its value is the nonzero product in the domain ; fractions then embed by [F6]. In each color degree the generic and formal quotients after extension to have the same finite word presentation, since the Serre coefficients specialize as in [F3]. A regular rational lift of a classical component basis therefore gives the formal basis of step 1.1 and, after field extension, a generic basis. Applying this degree by degree to the ordered monomials of [F4] proves the PBW monomial clause.
By [F2], the diagonal pairing restricts to , and [F1] identifies the first factor with . The cut adjunction is the wordwise concatenation identity. For the other adjunction, the coefficient of a word in a shuffle equals the coefficient of in the primitive braided tensor coproduct of : both sum over the assignments of letters to the two blocks with inversion scalar . The degree form is symmetric by [F3], and the diagonal generator weights multiply in the same way on both sides. Thus both adjunctions hold on free representatives, and step 1.2 and the descended pairing make them adjunctions on the quotient coproducts themselves. The empty word gives and all positive-degree counit pairings vanish.
Fix . If an element of pairs to zero with every negative class, its realization in the shuffle word space pairs to zero with every negative tensor word, since all those words map to quotient classes. The diagonal word pairing has zero left annihilator, so that realization is zero. The realization remains injective after extension to by [F1] and [F5]. The opposite components have equal finite dimension by step 1.1; an injective map from one into the other's dual is consequently bijective. Thus both annihilators vanish. For nonhomogeneous elements, separate the finitely many homogeneous components, proving the asserted nondegeneracy.
Define the generic word pairing using shuffle coefficients and matching-word weights . These are rational functions, and under their ratio to the formal pairing in a fixed color degree is , where is an -unit with constant term . This color-multiplicative rescaling preserves the two adjunctions and nondegeneracy. The specialized generic pairing therefore kills the Serre ideals and is nondegenerate by steps 2.2–2.3; the field embedding of step 2.1 implies the same descent and invertible pairing matrices over . Likewise, coassociativity, coideal inclusions and the coproduct formulas descend generically: in each finite degree their errors vanish after the injective field extension, and the antipode recursion applies there as well. All generic presentations and word pairing coefficients lie in , so the same injective extension to proves the statements over that field. This establishes the full braided Hopf pairing with the rational normalization needed for the Drinfeld–Jimbo commutator.
Triangular decomposition of a quantized enveloping algebra
Statement
Let be the Drinfeld–Jimbo algebra of a finite symmetrizable Cartan datum, over , and let be its generated subalgebras of Positive, negative and toral quantum subalgebras and their root gradings.
(i) Multiplication is a vector-space isomorphism Products , with ranging over supplied bases of the two halves and , form a basis of . Arbitrary simple-generator words span the halves; their Serre relations preclude claiming their independence.
(ii) The halves are exactly the algebras presented by their separate Serre relations, and . Thus all three abstract factor maps are injective and the are linearly independent.
(iii) For every , the total root grading satisfies In particular degree zero contains all equal-positive/negative-degree summands, including ; it is not just the toral subalgebra. As a left -module this component is free, with rank equal to the possibly infinite sum of the products of the two half-component dimensions. Under AC (The Axiom of Choice), the half-component dimensions are their classical PBW ranks, and products of the generic PBW bases of Generic quantum Serre halves have classical PBW ranks and a nondegenerate Hopf pairing with the toral basis give a PBW basis of the whole algebra. AC enters only through that supplier's formal-embedding proof; (i), (ii) and the graded tensor decomposition are choice-free.
Facts & Assumptions
Given: The datum, its Drinfeld–Jimbo algebra and its generated subalgebras.
The independently presented halves and free toral algebra form an associative algebra on ; its normal-factor multiplication to is an isomorphism and identifies the factor images with the generated subalgebras. This follows from the locally proved Serre-free normal forms, opposite Serre commutators and factor-ideal identity (The generic quantum halves form a Drinfeld–Jimbo crossed double).
The generated subalgebras are root-graded with , , , and toral conjugation on a homogeneous element is given by its additive weight (Positive, negative and toral quantum subalgebras and their root gradings).
Under AC, both separately presented generic halves have classical PBW ranks and their regular lifts of ordered classical PBW monomials are generic bases, including over (Generic quantum Serre halves have classical PBW ranks and a nondegenerate Hopf pairing, The Axiom of Choice).
Proof
By [F1], the algebra is identified with the tensor space of the independently presented factors, and their injective images are . Under these identifications the multiplication map is exactly the normal-factor isomorphism in [F1]. This proves (i) and (ii) without any additional assumption about a quotient presentation's freeness. For supplied factor bases, finite bilinear expansions show that their pure tensors span the tensor product; coordinate functionals on the supplied bases separate the coefficients of every finite sum of those tensors. Thus their pure tensors, and hence their images , are a basis.
The normal-factor isomorphism preserves total root degree by [F2], so the degree- tensor subspace is precisely the direct sum over displayed in (iii). Every algebra element uses finitely many such summands. The equal-degree summands at include ; both factors are nonzero because their simple-root component presentations have no Serre relations. Their independence from follows from the tensor decomposition. Hence contains these additional summands and is not just .
Homogeneous bases of the halves can be obtained by enumerating their words and retaining the first vectors outside the previous span, without choice. For homogeneous half basis vectors of degree and of degree , the map sending to identifies a free left toral copy: moving past multiplies by the nonzero scalar . Step 1.1 therefore identifies the fixed total-degree component with the direct sum of these free left toral copies. Its rank is the sum of the products of the two component dimensions, which may be infinite. With the stated AC hypothesis, [F3] identifies those finite half dimensions with the classical PBW ranks and supplies the generic ordered-monomial bases; inserting their products into step 1.1 gives the asserted full PBW basis. This completes all claims with the exact total grading.
Divided-power commutation and the simple string modules
Statement
Fix a symmetrizable Cartan datum , an index , and put . Let be the Drinfeld–Jimbo algebra and let be the subalgebra generated by (The Drinfeld-Jimbo quantized enveloping algebra by generators and relations, Positive, negative and toral quantum subalgebras and their root gradings); write for the divided powers of Quantum integers, factorials, Gaussian binomials and divided powers at .
(i) The assignment , , , defines an algebra isomorphism from the standard rank-one algebra over , presented by with , and onto ; the images of the monomials (, ) are linearly independent in , being images of the PBW monomials of the triangular decomposition (Triangular decomposition of a quantized enveloping algebra).
(ii) For all , and , and for the divided powers satisfy the exact commutation formula iterating it computes as a finite sum of monomials () with coefficients in .
(iii) For every there is a simple -module of dimension : it is the quotient of the cyclic module by the submodule generated by , where is the image of , with basis the images of , , on which , and (with ); is the unique simple -module generated by a vector with , and .
Facts & Assumptions
Given: A symmetrizable Cartan datum, an index , and the subalgebra generated by .
; and ; is the inverse of (The Drinfeld-Jimbo quantized enveloping algebra by generators and relations).
is the subalgebra generated by ; the universal property of assigns a homomorphism to every assignment satisfying the defining relations; the same quotient universal property applies to the explicit rank-one presentation (The Drinfeld-Jimbo quantized enveloping algebra by generators and relations, Positive, negative and toral quantum subalgebras and their root gradings, A ring homomorphism whose kernel contains a two-sided ideal factors uniquely through the quotient ring).
Triangular decomposition: the multiplication map is an isomorphism, so the images of the monomials are linearly independent and span the rank-one subalgebra (Triangular decomposition of a quantized enveloping algebra); only the unconditional tensor-decomposition clauses (i)–(ii) of that supplier are needed here.
The independent coroots and make distinct for distinct integers (Symmetrizable Cartan data for quantum groups). The finite geometric-sum identities hold because is transcendental and ; likewise for by [F3].
Proof
Weight rules. By [F1], and for all by induction on the exponent via multiplicativity of conjugation; dividing by the nonzero scalars and of [F3] gives and .
Commutation induction. Put and for . We prove by induction on . For this is [F1]. For the induction step, , and [F1] gives after reindexing ; the two correction terms cancel and the identity follows.
Divided-power formula. Dividing the identity of 1.2 by gives because and ; this is the displayed formula of (ii). Multiplying the formula for and for on the left and using repeatedly computes as a finite sum of monomials with , since each application of the formula moves one to the right at the cost of one -power.
The cyclic module. Let and . Every element of is a finite -linear combination of monomials with and : words are rearranged with [F1] and 1.1, and each application of the identity of 2.1 moves one to the right of an -power at the cost of one -power and finitely many -factors, so the rearrangement terminates. By [F4] these normal monomials are a basis. The left ideal is their span with . Modulo that span, a product from with positive -exponent still has positive exponent after toral crossing, and its terms with exponent zero are exactly for Laurent polynomials . Thus the remaining toral factor is quotiented by evaluation , and the cyclic quotient has basis the images of , ; a toral monomial maps to , not to zero. Writing for , the relations [F1] and 1.1 give (using and ), by [F3], and, using 2.1 with , for , and ; the bracket equals by the geometric-sum identity [F5].
The quotient and its action. Let . The submodule is spanned by the with : it is contained in that span by the action formulas of 3.1, and it contains them because up to the nonzero scalar by [F3]. Hence in the vectors satisfy the displayed action formulas with , and they span ; their nonvanishing and independence follow from the cyclic-module basis in step 3.1, since the specified tail submodule is spanned by the disjoint basis indices .
Simplicity and uniqueness. Let be a nonzero submodule and pick with maximal and . By 3.1, (each application of lowers the index by one with the stated nonzero scalar; all displayed scalars are nonzero because for by [F3] and the nonvanishing of ), so ; then puts every in , so and is simple and generated by with , and . Conversely, if is any simple -module generated by with these three properties, then the assignment defines a surjection whose kernel contains by the third property, hence factors through ; as is simple and , this map is an isomorphism, which gives the asserted uniqueness.
Part (i). The generators satisfy precisely the explicit rank-one relations by [F1], so sending to them gives a surjective map by the quotient universal property in [F2]. The same finite rearrangement used in step 3.1 shows that spans this presented rank-one algebra; its torus here is generated by alone, rather than by additional lattice roots of . In the full algebra, the pure color- component of either separate half has one word and no Serre relation, so its powers are nonzero and independent. The toral powers are distinct because the datum's coroots are independent and . By the tensor decomposition [F4], the images are therefore independent. The spanning rank-one monomials have independent images, proving injectivity and the claimed isomorphism.
5 · Examples, counterexamples and false statements
None yet.
Sources
- Pavel Etingof and Mykola Semenyakin, A Brief Introduction to Quantum Groups (lecture notes, arXiv:2106.05252v3)
- Richard Borcherds, Mark Haiman, Theo Johnson-Freyd, Nicolai Reshetikhin and Vera Serganova, Berkeley Lectures on Lie Groups and Quantum Groups (book-length lecture notes, last updated 18 January 2024)
- Richard Borcherds, Mark Haiman, Theo Johnson-Freyd, Nicolai Reshetikhin and Vera Serganova, Berkeley Lectures on Lie Groups and Quantum Groups
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- Benjamin Enriquez, PBW and Duality Theorems for Quantum Groups and Quantum Current Algebras, Journal of Lie Theory 13 (2003), 21-64
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