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Finite-range continuum Gibbs kernels and DLR notion — Examples

1 · Prerequisites

2 · Summary

These examples separate interaction range from stability, and stability from the stronger cell-superstability bound. The final calculation shows why a spatially uniform one-body energy can change grand pressure at fixed activity: it is a volume contribution, not a tempered exterior boundary. The examples establish only their stated conditional model calculations; they do not report empirical measurements.

3 · Logical flowchart

4 · Definitions, postulates, theorems and proofs

None yet.

5 · Examples, experiments and counterexamples

CounterexampleConstruction: AI-adaptedVerification: AI-adaptedjudge pass (gpt-6-luna)Open item page →

Finite range alone does not imply stability

Statement refuted

Every even Borel finite-range pair potential is stable.

Facts & Assumptions

Given: An integer d≥1, constants ϵ>0 and R>0, and the stability convention in the current continuum-interaction definition.

[A1]

The current draft Stability, superstability and regular tails defines stability by the existence of a finite B≥0 such that UN(X)≥−BN for every finite position list X=(x1,…,xN). For simple configurations this is the same pair-energy bound after enumerating their points. The supplier is a definition; this counterexample uses its stated interface without a proof-status claim.

[F1]

Integer part: for every real x there is exactly one integer m with m≤x<m+1: for every real x there is an integer m with m≤x<m+1.

Counterexample

1.1givenconstruct

Define ϕ(0)=0, ϕ(x)=−ϵ for 0<∥x∥2≤R, and ϕ(x)=0 for ∥x∥2>R. Since the norm is continuous, the defining sets are Borel; ϕ(−x)=ϕ(x), and ϕ vanishes outside the radius-R ball. Hence ϕ is an even Borel finite-range pair potential.

2.1givenstep 1.1construct

For any integer N≥2, let δ=R/(2N) and take xj=jδe1 for 0≤j<N. They are distinct and every separation is less than R, so the pair energy is exactly Uϕ=−ϵN(N−1)/2.

3.1A1F1step 2.1algebra∎

If a finite stability constant B existed, apply [F1] to x=1+2B/ϵ and let m≤x<m+1 be its integer part. Set N=m+2, so N>x and step 2.1 gives Uϕ=−ϵN(N−1)/2<−BN. This contradicts [A1], so the finite-range potential is not stable and the statement is false.

CounterexampleConstruction: AI-adaptedVerification: AI-adaptedjudge pass (gpt-6-luna)Open item page →

Stability does not imply cell superstability

Statement refuted

Every stable pair potential is cell-superstable.

Facts & Assumptions

Given: An integer d≥1 and the stability and cell-superstability conventions in the current continuum-interaction definition.

[A1]

The current draft Stability, superstability and regular tails fixes the half-open cubic tiling Ck=ℓ(k+[0,1)d) for some ℓ>0 and defines cell superstability by the existence of constants A∗>0, B∗≥0 such that UN(X)≥A∗∑knk(X)2−B∗N for every finite position list. It defines stability by UN(X)≥−BN. This counterexample uses these exact interfaces; the supplier is a definition and no proof-status claim is made.

[F1]

Integer part: for every real x there is exactly one integer m with m≤x<m+1: for every real x there is an integer m with m≤x<m+1.

Counterexample

1.1givenA1construct

Set ϕ(x)=0 for every x∈Rd. It is even and Borel, vanishes outside every finite range, and has Uϕ(ω)=0 for every finite configuration. Thus it is stable with B=0 under [A1].

2.1givenA1step 1.1construct

Fix any proposed cubical partition with side s>0 and constants A>0, Bs≥0 for cell superstability. Choose a cell with center c and, for any integer N≥1, place the distinct points xj=c+s(j/(N+1)−1/2)e1, 1≤j≤N, in that cell and none elsewhere. All coordinates lie strictly inside the cell, and their first coordinates are distinct. Hence ∑iNCi2=N2 while Uϕ=0.

3.1A1F1step 2.1algebra∎

Apply [F1] to x=Bs/A and let m≤x<m+1. Set N=m+1, so N>x. The proposed cell-superstability inequality would require 0≥AN2−BsN=AN(N−x)>0, a contradiction. Since every proposed positive A and finite Bs fails, the zero potential is stable but not cell-superstable.

CounterexampleConstruction: Literature-sourcedVerification: AI-adaptedOpen item page →

A uniform one-body energy changes fixed-activity ideal-gas pressure

Physical scope

Ideal positional gas of one operationally indistinguishable species in a bounded three-dimensional Euclidean cube, at fixed dimensionless activity, positive inverse-energy parameter and physical temperature, with a spatially uniform one-body energy c_SI>0 joules per particle. Pressure is the reduced log-partition rate converted by k_BT per physical volume. This is a conditional model calculation only; it reports no observation and is outside the square-count exterior-boundary hypothesis of the cited theorem.

Statement refuted

At fixed positive activity, adding a spatially uniform one-body energy to each particle never changes the thermodynamic grand pressure.

Facts & Assumptions

Given: Assume AC. Let d=3, ΛL=[0,L)3 in numerical coordinates, one species with operationally indistinguishable particles, unit-intensity Poisson reference QΛL, reference scales E0>0 joules and ℓ0>0 metres, temperature T>0 kelvin, Boltzmann constant kB>0 J/K, reference action href>0 J s, particle mass mp>0 kg, chemical potential μ∈R joules, and uniform one-body energy cSI>0 joules per particle. Set βSI=(kBT)−1, λT=href/2πmpkBT, physical activity zc=eβSIμλT−3, α=log⁡(ℓ03zc), and dimensionless β=E0βSI, z=eα=ℓ03zc, and c=cSI/E0.

[A1]

The current draft Interacting classical Gibbs equilibrium adoption adopts finite-region Gibbs conditional laws when normalizers are positive and finite; the current draft Classical particle counting and physical observables supplies the 1/N! sector factor for operationally indistinguishable particles. For this model, identify its locally prescribed action reference with href as required by the adopted thermal-wavelength convention of Interacting classical Gibbs equilibrium adoption; this equality is a declared common-reference choice, not a numerical value supplied by the counting postulate. These are an adopted postulate and reference convention, not proven claims.

[A2]

The current draft Classical Gibbs quantities and SI reference conventions defines βSI=(kBT)−1 and continuum activity zc=eβSIμλT−3 with λT=href/2πmpkBT.

[A3]

Set the pair potential to ϕ≡0. For each uniform energy cSI≥0, additionally adopt the ideal positional grand-sector weight zNe−βcN at fixed physical activity zc. Numerical coordinates satisfy xSI=ℓ0q, so zcNd3NxSI=zNd3Nq and βSIcSI=βc. Define its standard positional grand partition by ΞLc=∑N≥0(zN/N!)∫ΛLNe−βcN dq1⋯dqN. Define its reduced pressure as p(c)=lim⁡L→∞L−3log⁡ΞLc and SI pressure by PSI(c)=(kBT/ℓ03)p(c). Here α,z,β,c are dimensionless. This is an explicit ideal-gas model and pressure convention, conditional on [A1] and [A2], not an empirical claim.

[A4]

Assume the Axiom of Choice The Axiom of Choice, as required by the unit-Poisson reference and its count-properties theorem.

[F1]

Qualified interacting continuum thermodynamic and positional ensemble limits restricts its uniform exterior-pressure conclusion to the stated square-count exterior class. A one-body term cN throughout the volume is not an exterior boundary configuration in that class.

[F2]

Poisson Configuration Reference defines the unit-intensity Poisson reference Q and its bounded-region restrictions QD.

[F3]

Stable finite-range continuum specification normalization and consistency states that for bounded Borel D and N≥0, the N-point sector of QD is the pushforward of e−∣D∣/N! times product Lebesgue measure on ordered simple tuples.

[F4]

Poisson Reference Counts and Translation Invariance gives NΛL∼Poisson(L3) and the exact exponential moment EQesNΛL=exp⁡(L3(es−1)).

[F5]

The real exponential function and the number e by a power series defines exp⁡ by its real power series; The exponential addition formula exp⁡(x+y)=exp⁡(x)exp⁡(y) gives exp⁡(x+y)=exp⁡(x)exp⁡(y), and The exponential function is strictly increasing gives strict monotonicity.

[F6]

The natural logarithm as the inverse of the exponential function defines log⁡ as the inverse of the real exponential, so exp⁡(log⁡x)=x for x>0.

Counterexample

1.1givenA1A2A3A4F2F4F5F6algebra

Under [A3], an N-particle configuration has numerical positional energy HNc=cN. Its unit-Poisson normalized grand partition is ZQ,Lc=EQΛL ⁣[eαNΛLe−βcNΛL]=EQΛLe(α−βc)NΛL=exp⁡ ⁣(L3(eα−βc−1)) by [F4] and the exponential addition law [F5].

2.1A3A4F2F3F6step 1.1algebra

By [F3], the N-point sector of QΛL contributes e−L3/N! times the positional integral in [A3]. Summing sectors therefore gives ZQ,Lc=e−L3ΞLc, so [A3] yields ΞLc=exp⁡(L3eα−βc). Its reduced pressure is p(c)=lim⁡L→∞L−3log⁡ΞLc=eα−βc by [F6]. The SI conversion in [A3] is PSI(c)=E0p(c)/(βℓ03) pascals.

3.1A3F1F5step 2.1algebra∎

Repeating steps 1.1–2.1 in the cSI=0 member of [A3]'s model family gives p(0)=eα. For the selected cSI>0, βc=βSIcSI>0, so strict monotonicity [F5] yields p(c)=eα−βc<eα=p(0). The fixed-activity SI pressures differ by the same positive factor E0/(βℓ03), while the volume term is not covered by the restricted exterior-boundary theorem in [F1]. Thus the stated universal claim is false.

Sources