Alphabeta Math
Pipeline-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Strong Laws of Large Numbers

1 · Prerequisites

2 · Summary

Truncation and variance summability establish the IID integrable strong law. The converse identifies integrability as necessary for finite almost-sure limits; Etemadi uses only pairwise independence. A separate maximal-ergodic argument proves the probability-space Birkhoff theorem and recovers the IID result on coordinate shifts. Finite variance gives the stated logarithmic normalization. Product constructions explicitly assume AC.

3 · Logical flowchart

4 · Definitions, theorems and proofs

DefinitionDefinition: AI-adaptedProof: Not applicablejudge pass (gpt-5.6-terra)audited 2026-09-10Open item page →

Strong law of large numbers for a sequence

Definition

Let (Xn)n1 be integrable real random variables on one probability space, with Sn=k=1nXk. The centered strong law means (SnESn)/n0 almost surely. If the variables have a common law, their finite expectations equal μ=EX1, so this is equivalent to Sn/nμ almost surely. Independence is not part of this definition.

CorollaryStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-10Open item page →

Kolmogorov strong law for independent uniformly bounded variances

Statement

Independent square-integrable real (Xn)n1 with C=supnVar(Xn)< satisfy (SnESn)/n0 almost surely.

Facts & Assumptions

[F1]

Strong law under summable normalized variances: Let (Xn)n1 be independent square-integrable real random variables. Let 0<bn be deterministic and nondecreasing with bn. If n1Var(Xn)bn2<, then 1bnk=1n(XkEXk)0almost surely. In particular, for IID centered square-integrable variables and any ε>0, Sn/[n(logn)1/2+ε]0 almost surely (the displayed normalization is used for n2).

Proof

Given: The objects, hypotheses and definitions in the statement. Its conclusions are to be established below.

1.1

For n2, n2(n1)1n1. Therefore n=1NVar(Xn)/n2C(21/N)2C; these nonnegative partial sums have a finite supremum, so the variance series converges.

givenalgebra
2.1

The normalizers bn=n are positive, nondecreasing and tend to infinity. The independence and square-integrability are given, and step 1.1 verifies the summability hypothesis of F1. Its almost-sure conclusion is exactly the stated centered law.

F1step 1.1
CorollaryStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-10Open item page →

Iid finite variance strong law

Statement

IID square-integrable real variables satisfy Sn/nEX1 almost surely.

Facts & Assumptions

[F1]

Identical distribution and IID families: Let (Xi)iI be random elements with the same measurable target (E,E). They are identically distributed if P(XiB)=P(XjB) for all i,jI and BE, that is, their laws in def-law-or-distribution-of-a-random-element agree. They are independent and identically distributed (IID) if, in addition, the whole family is independent in def-independent-random-elements. Independence means mutual independence, not merely pairwise independence. No moment assumption is part of either definition. The empty family satisfies these universal conditions vacuously.

[F2]

Kolmogorov strong law for independent uniformly bounded variances: Independent square-integrable real (Xn)n1 with C=supnVar(Xn)< satisfy (SnESn)/n0 almost surely.

Proof

Given: The objects, hypotheses and definitions in the statement. Its conclusions are to be established below.

1.1

By F1, every coordinate has the same law and the whole family is independent. Integrating x and x2 against that common law gives common finite mean μ and common variance v. In particular supnVar(Xn)=v<.

F1
2.1

Apply F2 using step 1.1. Its centered sum is Snnμ, so adding μ gives the claimed limit.

F2step 1.1
LemmaStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-10Open item page →

Tail sum integrability equivalence

Statement

For a measurable X:Ω[0,] on a probability space, n1P(X>n)EX1+n1P(X>n). Thus EX< if and only if the tail series is finite.

Facts & Assumptions

[F1]

Monotone convergence for the integral: Let 0f1f2 be measurable and suppose fn(x)f(x) for every x. Then fndμfdμ.

Proof

Given: The objects, hypotheses and definitions in the statement. Its conclusions are to be established below.

1.1

For 0t<, let N(t) count positive integers strictly less than t. When t=0 the count is zero; when t=m1 is an integer it is m1; between consecutive integers it is the lower integer. Thus N(t)t1+N(t). At t= both N(t) and t are infinite, and the extended inequalities remain valid.

givenalgebra
2.1

The functions n=1m1{X>n} increase pointwise to N(X). F1 therefore gives EN(X)=n1P(X>n). Integrate both inequalities in step 1.1 and use E1=1 to obtain the bracket.

F1step 1.1
3.1

If EX is finite, the left inequality in step 2.1 bounds the series. Conversely a finite series makes the right inequality finite. This proves both directions, including extended-valued X.

step 2.1
LemmaStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-10Open item page →

Iid linear truncation occurs only finitely often

Statement

For identically distributed integrable real (Xn), put Yn=Xn1{Xnn}. Almost surely Yn=Xn for all sufficiently large n. Consequently n1k=1n(XkYk)0. Independence is unnecessary.

Facts & Assumptions

[F1]

Tail sum integrability equivalence: For a measurable X:Ω[0,] on a probability space, n1P(X>n)EX1+n1P(X>n). Thus EX< if and only if the tail series is finite.

[F2]

First Borel-Cantelli lemma for events: Let (An)nN be events in a probability space. If n=0P(An)<+, then P(An i.o.)=0.

No independence hypothesis is needed.

Proof

Given: The objects, hypotheses and definitions in the statement. Its conclusions are to be established below.

1.1

The common law gives P(Xn>n)=P(X1>n). By F1 their sum is at most EX1<.

F1
2.1

Apply F2 to these events. Outside their null limsup, a finite N(ω) bounds all exceptional indices and XkYk=0 for k>N(ω). Hence for n>N(ω) the numerator is the fixed finite real sum kN(ω)(XkYk), and its quotient by n tends to zero.

F2
LemmaStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-10Open item page →

Summability of truncated normalized variances

Statement

For identically distributed integrable real (Xn) and Yn=Xn1{Xnn}, n1Var(Yn)/n22EX1<. No independence is required.

Facts & Assumptions

[F1]

Variance and covariance identities for random variables: Let X,Y be square-integrable real random variables on one probability space. Then Var(X)=E[X2]E[X]2, Cov(X,Y)=E[XY]E[X]E[Y]. Moreover, covariance is symmetric and bilinear on finite linear combinations. On finite full-power-set probability spaces these formulas reduce to the published finite identities.

[F2]

Change of variables for expectation: Let X:(Ω,F,P)(S,Σ) be a random element, let PX be its law, and let g:(S,Σ)R or g:(S,Σ)C be measurable.

  1. If g0, then E[g(X)]=SgdPX.
  2. If g(X) is integrable, then g is integrable with respect to PX and the same formula holds: E[g(X)]=SgdPX.
[F3]

Integer part: for every real x there is exactly one integer m with mx<m+1: Identify Z with its canonical copy inside R, along the embeddings NZQR (lem-nat-embeds-int, lem-int-embeds-rat, lem-rat-embeds-dense, def-integers). Then for every real x there is exactly one integer m with

m    x  <  m+1.

It is written x and called the integer part, or floor, of x.

Two independent ingredients are needed and neither may be dropped. Existence is the Archimedean property (thm-of-archimedean) together with the well-ordering of N (thm-well-ordering-principle): the first says that x is caught between two integers at all, the second picks the least integer above x. Uniqueness is the discreteness of Z: no integer lies strictly between m and m+1.

This lemma is stated once here and reused. It is what turns "the nearest integer to x" from a picture into an object, and the companion page's oscillator ψ(x)=infnZxn is computed from it in one line.

[F4]

Monotone convergence for the integral: Let 0f1f2 be measurable and suppose fn(x)f(x) for every x. Then fndμfdμ.

Proof

Given: The objects, hypotheses and definitions in the statement. Its conclusions are to be established below.

1.1

The truncations satisfy Ynn, so they are square-integrable. The variance identity F1 yields Var(Yn)EYn2. By the common law and F2, the latter is E[X121{X1n}].

F1F2
1.2

For t>1 put m=t=t, as supplied by F3. Then m1<tm and nmn2m2+n>m((n1)1n1)=m2+m12/t. For 0t1, the same telescoping bound from n=1 gives t2n1n22t22t. Thus in all cases n1t21{tn}/n22t.

F3
2.1

Apply F4 to the increasing finite sums of the nonnegative functions in step 1.2 evaluated at X1. Combining step 1.1 and step 1.2 gives nVar(Yn)/n2EnX121{X1n}/n22EX1.

F4step 1.2step 1.1
LemmaStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-10Open item page →

Cesaro limit of truncated means

Statement

For identically distributed integrable real (Xn), with Yk=Xk1{Xkk}, one has n1k=1nEYkEX1.

Facts & Assumptions

[F1]

Change of variables for expectation: Let X:(Ω,F,P)(S,Σ) be a random element, let PX be its law, and let g:(S,Σ)R or g:(S,Σ)C be measurable.

  1. If g0, then E[g(X)]=SgdPX.
  2. If g(X) is integrable, then g is integrable with respect to PX and the same formula holds: E[g(X)]=SgdPX.
[F2]

Dominated convergence: Let f and (fn) be measurable complex-valued functions such that fnf almost everywhere and fng almost everywhere for a single nonnegative measurable function g with gdμ<+. Then fL1(μ), fnfdμ0, and hence fndμfdμ.

[F3]

If xkL then σnL: convergence implies (C,1)-summability to the same value: Let (xk) be a sequence of reals that converges (def-sequence, def-real-limit), and let (σn) be its sequence of Cesaro means (def-cesaro-mean). Then (σn) converges as well, and

limnσn  =  limkxk.

Both limits are asserted to exist: the right-hand one by hypothesis, the left-hand one as part of the conclusion. Equivalently: a convergent sequence is (C,1)-summable, to its own limit. The notation is licensed by uniqueness of limits of real sequences (lem-limit-unique).

The converse is false (fs-cesaro-converse).

Proof

Given: The objects, hypotheses and definitions in the statement. Its conclusions are to be established below.

1.1

F1 and the common law give EYk=E[X11{X1k}]. The integrands tend pointwise to X1 and their absolute values are bounded by the integrable X1. Thus F2 gives EYkEX1.

F1F2
2.1

Apply F3 to the numerical sequence of finite expectations in step 1.1; reindexing its initial index from zero to one does not change its averages or their limit.

F3step 1.1
TheoremStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-10Open item page →

Kolmogorov iid l1 strong law

Statement

For IID real (Xn)n1 with EX1<, Sn/nμ=EX1 almost surely.

Facts & Assumptions

[F1]

Measurable coordinatewise functions preserve independence: Let (Xi)iI be an independent family of random elements Xi:(Ω,F,P)(Si,Σi). For each i, let gi:(Si,Σi)(Ti,Ti) be measurable. Then the family (giXi)iI is independent.

[F2]

Summability of truncated normalized variances: For identically distributed integrable real (Xn) and Yn=Xn1{Xnn}, n1Var(Yn)/n22EX1<. No independence is required.

[F3]

Strong law under summable normalized variances: Let (Xn)n1 be independent square-integrable real random variables. Let 0<bn be deterministic and nondecreasing with bn. If n1Var(Xn)bn2<, then 1bnk=1n(XkEXk)0almost surely. In particular, for IID centered square-integrable variables and any ε>0, Sn/[n(logn)1/2+ε]0 almost surely (the displayed normalization is used for n2).

[F4]

Cesaro limit of truncated means: For identically distributed integrable real (Xn), with Yk=Xk1{Xkk}, one has n1k=1nEYkEX1.

[F5]

Iid linear truncation occurs only finitely often: For identically distributed integrable real (Xn), put Yn=Xn1{Xnn}. Almost surely Yn=Xn for all sufficiently large n. Consequently n1k=1n(XkYk)0. Independence is unnecessary.

Proof

Given: The objects, hypotheses and definitions in the statement. Its conclusions are to be established below.

1.1

Set Yn=Xn1{Xnn}. The truncation maps are Borel, so F1 makes (Yn) mutually independent. They are bounded by n and hence square-integrable.

F1
2.1

F2 gives nVar(Yn)/n2<. With bn=n, F3 applies to step 1.1 and yields n1kn(YkEYk)0 almost surely.

F2F3step 1.1
3.1

By F4, n1knEYkμ. By F5, n1kn(XkYk)0 almost surely. Intersecting the two conull events with step 2.1 and adding these three terms gives Sn/nμ.

F4F5step 2.1
TheoremStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-10Open item page →

Integrability is necessary for an iid finite mean strong law

Statement

If IID real (Xn) have Sn/n converging almost surely to a finite, possibly random, limit L, then EX1< and L=EX1 almost surely.

Facts & Assumptions

[F1]

Second Borel-Cantelli lemma under pairwise independence: Let (An)nN be pairwise independent events with n=0P(An)=+. Then P(An i.o.)=1.

[F2]

Tail sum integrability equivalence: For a measurable X:Ω[0,] on a probability space, n1P(X>n)EX1+n1P(X>n). Thus EX< if and only if the tail series is finite.

[F3]

Kolmogorov iid l1 strong law: For IID real (Xn)n1 with EX1<, Sn/nμ=EX1 almost surely.

Proof

Given: The objects, hypotheses and definitions in the statement. Its conclusions are to be established below.

1.1

On the given conull convergence event, for n2 one has Xn/n=Sn/n((n1)/n)(Sn1/(n1))LL=0. Therefore the events An={Xn>n} occur only finitely often almost surely.

givenalgebra
2.1

The events An are independent because each belongs to the σ-algebra of its own coordinate. If nP(An) were infinite, F1 would make their limsup conull, contradicting step 1.1. The series is therefore finite, and identical laws turn it into nP(X1>n).

F1step 1.1
3.1

F2 applied to step 2.1 gives EX1<. Now F3 gives Sn/nEX1 almost surely. Uniqueness of a finite real limit on the intersection of the two conull events identifies L as claimed.

F2F3step 2.1
TheoremStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-10Open item page →

Etemadi strong law for pairwise independent iid variables

Statement

Pairwise independent, identically distributed integrable real (Xn) satisfy Sn/nEX1 almost surely.

Facts & Assumptions

[F1]

Measurable coordinatewise functions preserve independence: Let (Xi)iI be an independent family of random elements Xi:(Ω,F,P)(Si,Σi). For each i, let gi:(Si,Σi)(Ti,Ti) be measurable. Then the family (giXi)iI is independent.

[F2]

Independence forces covariance to vanish: If X and Y are independent square-integrable real random variables, then Cov(X,Y)=0.

Thus independence implies zero covariance. The converse is false in general.

[F3]

Variance and covariance identities for random variables: Let X,Y be square-integrable real random variables on one probability space. Then Var(X)=E[X2]E[X]2, Cov(X,Y)=E[XY]E[X]E[Y]. Moreover, covariance is symmetric and bilinear on finite linear combinations. On finite full-power-set probability spaces these formulas reduce to the published finite identities.

[F4]

Integer part: for every real x there is exactly one integer m with mx<m+1: Identify Z with its canonical copy inside R, along the embeddings NZQR (lem-nat-embeds-int, lem-int-embeds-rat, lem-rat-embeds-dense, def-integers). Then for every real x there is exactly one integer m with

m    x  <  m+1.

It is written x and called the integer part, or floor, of x.

Two independent ingredients are needed and neither may be dropped. Existence is the Archimedean property (thm-of-archimedean) together with the well-ordering of N (thm-well-ordering-principle): the first says that x is caught between two integers at all, the second picks the least integer above x. Uniqueness is the discreteness of Z: no integer lies strictly between m and m+1.

This lemma is stated once here and reused. It is what turns "the nearest integer to x" from a picture into an object, and the companion page's oscillator ψ(x)=infnZxn is computed from it in one line.

[F5]

Integer powers am: Let aR, where R is the ambient ordered field (def-ordered-field, def-field).

Natural exponents. By the recursion theorem (thm-recursion) applied to the set R, the starting element 1 and the function f(x)=xa, there is a unique function NR, written nan, with

a0=1,an+1=ana(nN).

Thus a1=a, a2=aa, and so on. Note that this is defined for every a, including a=0.

Negative exponents. If a0 and nN with n1, set

an:=(an)1.

Why that is legitimate. The right-hand side presupposes that an is invertible, that is, that an0. This is a proof obligation and not an observation, and it is discharged by claim 2 of lem-power-laws: for a0 in a field, an0 for every nN, proved there by induction on n from the fact that a field has no zero divisors (lem-of-no-zero-divisors). That lemma is a statement about the operation introduced here, so it depends on this definition and is recorded in this item's justified_by rather than in its deps (SCHEMA §3). Given an0, the value (an)1 is a single well-determined element, because multiplicative inverses in a field are unique (lem-of-inverse-unique).

Integer exponents. Every integer m (def-integers) is either ι(n) or ι(n) for a unique natural n, where ι is the embedding NZ (lem-nat-embeds-int, def-int-operations). This too is a citation and not a slogan: the order on Z is total (thm-int-ordered-ring), so m0 or m<0; the image of ι is exactly the set of nonnegative integers, and each of them is ι(n) for a unique natural n (lem-nat-embeds-int); and if m<0 then m>0, by compatibility of the order with addition (thm-int-ordered-ring), so m=ι(n) and m=ι(n), with n unique because ι is injective. The two clauses above therefore define am for every mZ whenever a0, and for every mN for arbitrary a. The clauses are consistent where they overlap: the only overlap is m=0, where ι(0)=ι(0) and (a0)1=11=1=a0.

[F6]

For r<1, k0rk=1/(1r), and for r1 the series diverges: Let rR and let rk be the integer power (def-integer-power), so that r0=1 for every r, including r=0.

  1. If r<1 then the series rk converges (def-series) and k=0rk  =  11r.
  2. If r1 then rk diverges.

The series starts at k=0 and its first term is r0=1; in particular k=02k=2, while the series starting at k=1 sums to 1. Which starting index is meant has to be said, and it is said here.

[F7]

Summability of truncated normalized variances: For identically distributed integrable real (Xn) and Yn=Xn1{Xnn}, n1Var(Yn)/n22EX1<. No independence is required.

[F8]

Chebyshev's inequality for random variables: If X is a square-integrable real random variable and a>0, then P(XE[X]a)Var(X)a2.

[F9]

First Borel-Cantelli lemma for events: Let (An)nN be events in a probability space. If n=0P(An)<+, then P(An i.o.)=0.

No independence hypothesis is needed.

[F10]

Cesaro limit of truncated means: For identically distributed integrable real (Xn), with Yk=Xk1{Xkk}, one has n1k=1nEYkEX1.

[F11]

Iid linear truncation occurs only finitely often: For identically distributed integrable real (Xn), put Yn=Xn1{Xnn}. Almost surely Yn=Xn for all sufficiently large n. Consequently n1k=1n(XkYk)0. Independence is unnecessary.

Proof

Given: The objects, hypotheses and definitions in the statement. Its conclusions are to be established below.

1.1

First suppose Xn0. Put Ym=Xm1{Xmm}, Tn=mnYm, and vm=Var(Ym). Pairwise independence survives these coordinatewise Borel maps by applying F1 separately to each independent pair. F2 and F3 give Var(Tn)=mnvm.

F1F2F3
1.2

Fix an integer r1 and α=1+1/r>1. By F4 set kj=αj for j0, using F5. For large j, kjαj/2 and kj+1/kjα; this follows on dividing αj1<kjαj by αj. The sequence is eventually strictly increasing, since αj+1αj tends to infinity.

F4F5
1.3

For each m, let j0 be the first nonnegative j with αjm. Apart from finitely many small j, j:kjmkj24jj0α2j=4α2j0/(1α2)4m2/(1α2) by F6. The omitted finitely many j affect only m<=max kj, so increasing the constant gives j:kjmkj2Cαm2 for every m.

F6
2.1

Interchanging finite nonnegative double sums and then taking suprema, step 1.1 and step 1.3 give jVar(Tkj)/kj2Cαmvm/m2<, the last inequality by F7. For each positive integer l, F8 bounds P(TkjETkj>kj/l) by l2Var(Tkj)/kj2. F9 and a countable intersection over l imply (TkjETkj)/kj0 almost surely.

F7F8F9step 1.1step 1.3
3.1

F10 gives ETn/nμ=EX1. For kjn<kj+1, nonnegativity makes Tkj/kj+1Tn/nTkj+1/kj. Consequently step 1.2 and step 2.1 give μ/αlim infnTn/nlim supnTn/nαμ on a conull event.

F10step 1.2step 2.1
4.1

Intersect these events over r1. Since 1+1/r1 and μ is finite and nonnegative, step 3.1 gives Tn/nμ. F11 removes the truncation error. For general real variables, apply this nonnegative result separately to Xn+ and Xn; their integrability and pairwise independence follow from the given hypotheses and coordinatewise measurability. Subtracting the two finite limits proves the assertion.

F11step 3.1
CorollaryStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-10Open item page →

Iid strong law implies the weak law

Statement

For IID integrable real variables, Sn/nEX1 in probability.

Facts & Assumptions

[F1]

Kolmogorov iid l1 strong law: For IID real (Xn)n1 with EX1<, Sn/nμ=EX1 almost surely.

[F2]

Almost-sure convergence implies convergence in probability: If XnX almost surely, then XnX in probability.

Proof

Given: The objects, hypotheses and definitions in the statement. Its conclusions are to be established below.

1.1

F1 applies to the given IID integrable sequence and gives Sn/nEX1 almost surely.

F1
2.1

The sample means and the constant limit are real random variables on that same probability space. Thus F2 applies to step 1.1 and gives the claimed probability convergence.

F2step 1.1
LemmaStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-10Open item page →

The maximal ergodic inequality on a probability space

Statement

Let T preserve a probability measure P, and let f be integrable, real-valued and measurable. Put Skf=j=0k1fTj, MN=max(0,S1f,,SNf) and EN={MN>0} for N1. Then ENfdP0, and also EfdP0 for E={supk1Skf>0}.

Facts & Assumptions

[F1]

Measure-preserving transformations and systems: Let (X,A,μ) be a measure space. A measurable self-map T:XX is measure preserving if μ(T1E)=μ(E) for every EA. The quadruple (X,A,μ,T) is a measure-preserving system; it is a probability system if μ(X)=1. Here T1E={x:T(x)E} denotes an inverse image, whether or not T is invertible. Neither completeness nor finiteness is implicit. The measure-space and measurable-map conventions are def-measure-space and def-measurable-function-between-measurable-spaces.

[F2]

Arithmetic and lattice operations preserve measurability whenever they are defined: Let (X,A) be a measurable space and let f,g:XR be measurable. Then:

  1. cf is measurable for every real scalar c;
  2. max(f,g), min(f,g), f, f+, and f are measurable;
  3. if f+g is pointwise defined, then f+g is measurable;
  4. with the convention of rem-zero-times-infinity-convention-for-pointwise-products, the pointwise product fg is measurable.
[F3]

Integral invariance under measure-preserving maps: If T preserves μ and f:X[0,] is measurable, then fTdμ=fdμ, allowing infinity. If f is integrable real or complex valued, fT is integrable and the same equality holds. Conversely, for a measurable self-map, equality for every measurable indicator implies measure preservation.

[F4]

The Lebesgue integral is linear on L1(μ): The class L1(μ) is a complex vector space, and the Lebesgue integral is complex-linear on it: (αf+βg)dμ=αfdμ+βgdμ(α,βC, f,gL1(μ)).

[F5]

Dominated convergence: Let f and (fn) be measurable complex-valued functions such that fnf almost everywhere and fng almost everywhere for a single nonnegative measurable function g with gdμ<+. Then fL1(μ), fnfdμ0, and hence fndμfdμ.

Proof

Given: The objects, hypotheses and definitions in the statement. Its conclusions are to be established below.

1.1

The measurable self-map in F1 and F2 make all finite sums and maxima measurable. Also 0MNj<NfTj, whose integral is NfdP< by F3. Thus M_N and its composition with T are integrable.

F1F2F3
1.2

For 1kN, Skf=f+(Sk1f)Tf+MNT, with S0f=0. On E_N take a maximizing k to get fMNMNT. On the complement M_N=0 and MNT0. Hence everywhere f1ENMNMNT.

givenalgebra
2.1

Integrate the inequality in step 1.2. Integrability is supplied by step 1.1; F4 and F3 give ENfdPMNdPMNTdP=0.

F3F4step 1.2step 1.1
3.1

The sets E_N increase to E. Since f1ENf and f1ENf1E pointwise, F5 takes step 2.1 to EfdP0.

F5step 2.1
TheoremStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-10Open item page →

Birkhoff's theorem for an ergodic probability system

Statement

If T is an ergodic measure-preserving transformation of a probability space and f is an integrable real-valued measurable function, then, for n1, the averages Anf=n1j=0n1fTj satisfy Anfc=fdP almost surely and in L1. Invertibility is not required.

Facts & Assumptions

[F1]

The Lebesgue integral is linear on L1(μ): The class L1(μ) is a complex vector space, and the Lebesgue integral is complex-linear on it: (αf+βg)dμ=αfdμ+βgdμ(α,βC, f,gL1(μ)).

[F2]

Arithmetic and lattice operations preserve measurability whenever they are defined: Let (X,A) be a measurable space and let f,g:XR be measurable. Then:

  1. cf is measurable for every real scalar c;
  2. max(f,g), min(f,g), f, f+, and f are measurable;
  3. if f+g is pointwise defined, then f+g is measurable;
  4. with the convention of rem-zero-times-infinity-convention-for-pointwise-products, the pointwise product fg is measurable.
[F3]

Sequential suprema, infima, limsup, liminf, and pointwise limits of measurable functions are measurable: Let (X,A) be a measurable space and let fn:XR be measurable for every nN. Then the functions

supnfn,infnfn,lim supnfn,lim infnfn

are measurable. The set

{x:limnfn(x) exists in R}

is measurable. In particular, if fnf pointwise, then f is measurable.

[F4]

The maximal ergodic inequality on a probability space: Let T preserve a probability measure P, and let f be integrable, real-valued and measurable. Put Skf=j=0k1fTj, MN=max(0,S1f,,SNf) and EN={MN>0} for N1. Then ENfdP0, and also EfdP0 for E={supk1Skf>0}.

[F5]

Ergodicity relative to an invariant measure: A measure-preserving system is ergodic for μ if each EI has μ(E)=0 or μ(XE)=0, with I as in def-strict-and-mod-null-invariant-σ-algebras. For a probability system this means μ(E){0,1}. The definition is relative to the invariant measure; no probability assumption is implicit in the general null/conull formulation.

[F6]

Finite and countable subadditivity of measures: Let μ be a measure and let (Ek)kN be measurable. Then

μ(kNEk)k=0μ(Ek).

For every mN one also has

μ(k<mEk)k<mμ(Ek),

including m=0, where both sides are 0.

[F7]

Dominated convergence: Let f and (fn) be measurable complex-valued functions such that fnf almost everywhere and fng almost everywhere for a single nonnegative measurable function g with gdμ<+. Then fL1(μ), fnfdμ0, and hence fndμfdμ.

[F8]

The modulus of an integral is bounded by the integral of the modulus: If fL1(μ), then fdμfdμ.

[F9]

Integral invariance under measure-preserving maps: If T preserves μ and f:X[0,] is measurable, then fTdμ=fdμ, allowing infinity. If f is integrable real or complex valued, fT is integrable and the same equality holds. Conversely, for a measurable self-map, equality for every measurable indicator implies measure preservation.

Proof

Given: The objects, hypotheses and definitions in the statement. Its conclusions are to be established below.

1.1

Set h=fc so hdP=0 by F1. For n1, the finite averages are measurable by F2, and L=lim supnAnh is extended-real measurable by F3.

F1F2F3
1.2

At every x and every n1, Anh(Tx)=((n+1)/n)An+1h(x)h(x)/n. This implies L(Tx)=L(x) even if L is infinite: multiplying a real sequence by positive factors tending to one preserves finite limsup by eventual upper bounds and a subsequence tending to that limsup; if the limsup is positive infinity there is a subsequence tending to positive infinity, and if it is negative infinity all sufficiently late terms lie below every fixed negative bound. Subtraction of h(x)/n tends to zero because h is finite everywhere. Thus for every ε>0 the measurable set D={L>ε} is strictly invariant.

givenalgebra
2.1

Let g=(hε)1D, an integrable function. Strict invariance in step 1.2 gives Sng=1D(Snhnε) for n1. Outside D all these sums vanish; inside D the defining strict limsup gives some positive sum. Thus {supn1Sng>0}=D, and F4 gives D(hε)dP0.

F4step 1.2
3.1

By F5, P(D) is zero or one. If it were one, step 1.1 would give D(hε)=ε<0, contrary to step 2.1. Hence P(D)=0. Apply this conclusion to h and -h and to ε=1/m for every positive integer m. F6 makes the union of the exceptional events null, so lim supAnh0lim infAnh almost surely. This proves the almost-sure assertion.

F5F6step 1.1step 2.1
4.1

For each integer K1 put fK=f1{fK} and cK=fK. Step 3.1 applied to f_K gives AnfKcK almost surely, and AnfKcK2K. F7 yields AnfKcK10.

F7
5.1

By F8 and F9, An(ffK)1ffK1 and ccKffK1. Consequently Anfc12ffK1+AnfKcK1. Dominated convergence makes the first term tend to zero as K increases, uniformly in n; step 4.1 then handles the second term with K fixed. This proves L1 convergence.

F8F9step 4.1
CorollaryStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-10Open item page →

Birkhoff strong law for iid coordinate shifts

Statement

Assume AC. On the canonical countable product of an integrable real probability law, the left shift is measure preserving and ergodic. Its coordinate averages converge almost surely and in L1 to the common mean by the ergodic theorem.

Facts & Assumptions

[F1]

The Axiom of Choice: The Axiom of Choice (AC) is the following statement.

Every family of nonempty sets has a choice function (def-choice-function).

Written out: for every set F all of whose members are nonempty, there exists a function g with domain F satisfying g(S)S for all SF.

An equivalent formulation is that a product of nonempty sets is nonempty: if Xi for every iI, then iIXi. Here iIXi is the set of functions f with domain I such that f(i)Xi for every iI; when a family of nonempty sets is indexed by itself, such an f is precisely a choice function for it.

[F2]

The Axiom of Countable Choice (ACω): The Axiom of Countable Choice, written ACω, is the following statement.

For every family (Xn)nN of nonempty sets indexed by N there is a function f with domain N such that f(n)Xn for every nN.

Equivalently, in the vocabulary of def-choice-function: every at most countable family of nonempty sets (def-countable) has a choice function.

[F3]

The recursion theorem: Let (N,0,σ) be a Peano system (def-peano-system), in particular the natural numbers N (def-natural-numbers). For any set A, any element aA, and any function f:AA, there is a unique function g:NA such that g(0)=a and g(σ(n))=f(g(n)) for all nN.

[F4]

The axiom of dependent choice: a relation in which every element is related to something admits an N-indexed chain: Let X be a set and let RX×X be a binary relation on X. Call R entire on X when

for every xX there is yX with xRy.

The Axiom of Dependent Choice, written DC, is the following statement.

For every nonempty set X, every relation R entire on X, and every aX, there is a function x:NX (def-function, def-natural-numbers) with x0=aandxnRxn+1  for every nN.

Here a sequence in X means a function from N to X, not necessarily a real-valued sequence. As everywhere in this library N contains 0, and the sequence is indexed from 0; the term x0 is the prescribed starting point a and every later term is related to its predecessor.

What DC adds to what came before. def-choice-function and def-axiom-of-choice select one element from each member of a family that is fixed in advance, and def-countable-choice does the same for a family indexed by N. In both, the family is given before any selection is made. DC is the principle needed when the n-th set to select from is not known until the first n selections have been made: here the admissible values of xn+1 are exactly the R-successors of xn, so the family being chosen from is built along the choosing. That is precisely the situation ACω does not cover, and it is why a construction "pick xn+1 depending on xn, for every n at once" is not licensed by countable choice.

The starting point may be dropped. The formally weaker statement obtained by deleting the clause x0=a — for every nonempty X and every entire R there is a sequence with xnRxn+1 for all n — is an immediate consequence of the form above, since X is nonempty and any of its elements may be taken as a. The reverse derivation is standard and is not needed anywhere in this library, so it is not carried out; every use below prescribes x0.

R need not be an order and the terms need not be distinct. What DC delivers is a sequence, that is a function NX, not a chain in the order-theoretic sense (def-chain). The relation may be symmetric, and the sequence may repeat a value or be constant; all that is asserted is xnRxn+1 at every index.

[F5]

Assuming countable and dependent choice, countable products of arbitrary probability spaces: Assume countable choice and dependent choice. For probability spaces (En,En,μn)nN there is a unique probability measure on the canonical countable-product sigma-algebra having the prescribed finite product marginals.

[F6]

Coordinate random elements of a countable product are independent: Under the measure of F5, the coordinate maps Xn(x)=xn have laws μn and are independent.

[F7]

Measure preservation can be checked on a generating pi-system: Let T:XX be measurable on (X,A,μ). Let P be a π-system generating A, with an increasing sequence PnP covering X and satisfying μ(Pn)<. If μ(T1P)=μ(P) for every PP, then T preserves μ. For finite μ, a generating π-system can be enlarged by X to meet the exhaustion condition.

[F8]

Kolmogorov zero-one law: Let (Xn)nN be an independent sequence of random elements, and let T(Xn:nN) be its tail σ-algebra. Then every event AT(Xn:nN) satisfies P(A){0,1}.

[F9]

Ergodicity relative to an invariant measure: A measure-preserving system is ergodic for μ if each EI has μ(E)=0 or μ(XE)=0, with I as in def-strict-and-mod-null-invariant-σ-algebras. For a probability system this means μ(E){0,1}. The definition is relative to the invariant measure; no probability assumption is implicit in the general null/conull formulation.

[F10]

Birkhoff's theorem for an ergodic probability system: If T is an ergodic measure-preserving transformation of a probability space and f is an integrable real-valued measurable function, then Anf=n1j=0n1fTjc=fdP almost surely and in L1. Invertibility is not required.

Proof

Given: The objects, hypotheses and definitions in the statement. Its conclusions are to be established below.

1.1

AC (F1) selects a member of each set in any prescribed countable nonempty family, giving F2. For an entire relation R on a nonempty A, AC selects s(a){b:aRb} for every a. F3 iterates s from any prescribed a0, yielding an+1=s(an) and thus F4. Hence F5 has its CC and DC hypotheses satisfied and constructs the canonical countable product; F6 gives its coordinate maps their common law and independence.

F1F2F3F4F5F6
1.2

Write T(x0,x1,)=(x1,x2,). Pullbacks of finite coordinate cylinders are cylinders with shifted indices, so T is measurable. The product of the marginal probabilities of any such cylinder is unchanged on shifting all indices. F7 therefore extends equality of cylinder probabilities to all product-measurable sets, proving measure preservation.

F6F7
1.3

If a measurable E is strictly invariant, E=TnE for every n. For each n, the class of sets B whose TnB belongs to σ(Xn,Xn+1,) is a σ-algebra containing the cylinders, hence contains E. Thus E belongs to the coordinate tail σ-algebra. F8 gives P(E) in {0,1}, which is precisely F9.

F8F9
2.1

The zeroth coordinate f(x)=x0 is integrable with integral equal to the common mean. Step 1.2 and step 1.3 verify the system hypotheses of F10. Its averages are exactly Anf=(x0++xn1)/n for n1, so both asserted modes of convergence follow without using the IID strong-law proof.

F10step 1.3
RemarkRemark: AI-adaptedProof: Not applicablejudge pass (gpt-5.6-terra)audited 2026-09-10Open item page →

Strong law does not assert a rate

Remarks

The conclusion of Kolmogorov iid l1 strong law is almost-sure convergence of sample means. It specifies no numerical rate of decay of the error. The finite-variance logarithmic-rate theorem requires an additional second-moment assumption; neither that assumption nor a law of the iterated logarithm is implicit in the L1 law.

TheoremStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-10Open item page →

Finite variance logarithmic rate for iid sums

Statement

If IID real variables have mean μ and finite variance v, then for every ε>0, (Snnμ)/(n(logn)1/2+ε)0 almost surely, with the displayed normalization used for n2.

Facts & Assumptions

[F1]

Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm: The function log:(0,)R is continuous and strictly increasing, is onto R, and satisfies, for x,y>0, log(xy)=logx+logy,log(x/y)=logxlogy,log(1/x)=logx. Also log1=0.

[F2]

Continuity and derivatives of positive-base real powers: For a>0, the function xax is continuous on R and (ax)=axloga. For αR, the function xxα is continuous and differentiable on (0,), with (xα)=αxα1.

[F3]

The exponent, product, quotient, and iterated-power laws for positive real bases and real exponents: For a,b>0 and r,sR, ar+s=aras,(ab)r=arbr,(a/b)r=ar/br,(ar)s=ars.

[F4]

The p-series for a real exponent p converges exactly when p is greater than one: For every real p, k11kp convergesp>1.

0    ak    bkfor all kK.

Then:

  1. if bk converges then ak converges (def-series);
  2. if ak diverges then bk diverges.

The same statement holds verbatim for series with a general starting index m, applied to the shifted sequences of def-series.

The hypothesis is on the terms from some index on, not on all of them: finitely many terms of either sequence may violate it, or be negative, without affecting the conclusion. What may not be dropped is nonnegativity of (ak) from that index on.

[F6]

Strong law under summable normalized variances: Let (Xn)n1 be independent square-integrable real random variables. Let 0<bn be deterministic and nondecreasing with bn. If n1Var(Xn)bn2<, then 1bnk=1n(XkEXk)0almost surely. In particular, for IID centered square-integrable variables and any ε>0, Sn/[n(logn)1/2+ε]0 almost surely (the displayed normalization is used for n2).

Proof

Given: The objects, hypotheses and definitions in the statement. Its conclusions are to be established below.

1.1

Fix ε>0 and put q=1/2+ε. By F1, log n>0 for n2. The derivatives in F2 show that positive powers are increasing; thus bn=n(logn)q is positive and increasing for n2 and tends to infinity. Set b1=b2 to obtain a positive nondecreasing sequence at every index.

F1F2
1.2

Using integer powers of 2 and F3, for 2kn<2k+1 with k1, 1/[n(logn)1+2ε]2k(klog2)12ε. There are 2k terms in this block, so its sum is at most (log2)12εk12ε. F4 and F5 bound all partial sums of the nonnegative block series, because 1+2epsilon>1. Therefore nv/bn2<, including the single finite n=1 term.

F3F4F5
2.1

The original variables are independent and square-integrable. Step 1.1 and step 1.2 verify all hypotheses of the general normalized-variance conclusion of F6. It gives (Snnμ)/bn0 almost surely, as required for the arbitrarily fixed ε.

F6step 1.2

5 · Examples, counterexamples and false statements

None yet.

Sources