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Casson–Gordon invariants and sliceness obstructions — Examples and Counterexamples

1 · Prerequisites

2 · Logical flowchart

3 · Definitions, theorems and proofs

None yet.

4 · Examples, counterexamples and false statements

CounterexampleConstruction: Literature-sourcedVerification: AI-generatedverified 2026-10-22 (gpt-6.1-sol)Open item page →

A prime-power torsion linking form need not have a metabolizer

Statement refuted

Assume AC. The assertion that every nonsingular linking form on a finite group of odd prime-power order has a metabolizer is false: the double branched cover of the positive trefoil has cyclic first homology of order three and no metabolizer.

Facts & Assumptions

Given: The positive trefoil, its Seifert matrix V, and the double branched-cover orientation convention.

[A1]

Full AC is assumed wherever the cover and orientation conventions use the choice axiom. The Axiom of Choice

[F1]

V=(−10−1−1). A positive Hopf plumbing gives the trefoil Seifert matrix

[F2]

The double-cover surgery matrix is A=V+VT. Surgery presentation from a Seifert surface

[F3]

The oriented linking form on the surgery cokernel is −A−1 mod Z. Inverse-matrix formula for a surgery linking form

[F4]

A finite nonsingular linking form has a metabolizer only if some subgroup has square-root order. Finite nonsingular linking forms and metabolizers

[F5]

The surgery linking matrix computes the same oriented torsion linking pairing as the signed bounding-chain formula. Bounding-chain expression for a torsion linking pairing Inverse-matrix formula for a surgery linking form

[F6]

A closed oriented 3-manifold with finite first homology has nonsingular torsion linking form. The torsion linking pairing of a rational homology sphere is nonsingular

Counterexample

1.1F1F2F3F5givenalgebraA1

Computing gives A=(−2−1−1−2) with determinant 3, and unimodular row and column operations reduce it to diag⁡(1,3). Therefore H1(Σ2(T);Z)≅Z/3. The matrix formula [F3] gives generator self-linking 2/3≡−1/3 mod Z under [F5], so the full group is not isotropic.

2.1F4F6step 1.1algebra∎

The only subgroups of Z/3 have order 1 or 3, while a metabolizer would have order 3 by [F4]. The form is nonsingular by [F6] and step 1.1, so it satisfies the assertion's nonsingularity hypothesis. No subgroup has that order, so no metabolizer exists. This finite nonsingular form of odd prime-power order refutes the assertion.

ExampleConstruction: Literature-sourcedVerification: AI-generatedverified 2026-10-22 (gpt-6.1-sol)Open item page →

The square knot has a nontrivial character vanishing on a linking metabolizer

Example

Assume AC. For the square knot K=T#T†, where T is the positive trefoil and T† is its reverse mirror, the double branched cover has H1≅Z/3⊕Z/3 with linking form diag⁡(1/3,−1/3). Its diagonal subgroup is a metabolizer, and the order-three character χ(a,b)=(a−b)/3 mod Z vanishes on it. The knot is smoothly slice.

Facts & Assumptions

Given: The positive trefoil T, its reverse mirror T†, their boundary-connected-sum Seifert surface, the positive-push convention, and the double branched cover.

[A1]

Full AC is assumed wherever the cover and orientation conventions use the choice axiom. The Axiom of Choice

[F1]

A positive trefoil Seifert matrix is V=(−10−1−1). A positive Hopf plumbing gives the trefoil Seifert matrix

[F2]

The reverse-mirror surface is −r(F); its positive normal is the reflected positive normal because the two orientation reversals cancel. Reflection negates linking, so the transported basis has positive-push matrix −V. Seifert pairing and matrix of an oriented knot Well-definedness of the Seifert pairing Reverse mirror of an oriented knot

[F3]

For q=2, a Seifert matrix U gives a surgery presentation of the double branched cover with symmetric matrix U+UT. Surgery presentation from a Seifert surface

[F4]

For a nonsingular integral surgery matrix A, the first homology is Zn/AZn and the oriented linking form is −A−1 mod Z. Inverse-matrix formula for a surgery linking form

[F5]

Every knot plus its reverse mirror bounds a smooth ribbon disk. A knot summed with its reverse mirror bounds a ribbon disk

[F6]

In a finite nonsingular linking form, an isotropic subgroup of square-root order is a metabolizer. Finite nonsingular linking forms and metabolizers

[F7]

For integral 1-cycles a,b representing the two torsion classes and an integral 2-chain C with ∂C=na, n>0, the oriented torsion linking pairing is (C⋅b)/n mod Z, with C transverse to b. Bounding-chain expression for a torsion linking pairing

[F8]

A finite-order character is a homomorphism to Q/Z, with order measured in the character group. Finite-order characters of a cyclic branched cover

[F9]

The oriented connected sum joins the oriented knot arcs in the fixed two-ball model; the boundary-connected-sum surface in the Given therefore represents T#T†. Oriented connected sum and prime knot

[F10]

A knot bounding a smooth proper disk in B4 is smoothly slice. Smooth and topological slice genus

Verification

1.1F1F2F9givenconstructA1

The boundary-connected-sum surface for K has block-diagonal Seifert matrix U=V⊕(−V): curves in the two summands are disjoint, so mixed linking entries vanish. Hence U+UT=A⊕(−A), where A=V+VT=(−2−1−1−2).

2.1F3step 1.1constructalgebra

The double-cover surgery presentation [F3] gives the linking group as coker⁡(A)⊕coker⁡(−A). Unimodular row and column operations reduce A to diag⁡(1,3), so each cokernel is Z/3.

2.2F4F7step 1.1algebra

Since A−1=−13(2−1−12), [F4] gives self-linking 2/3≡−1/3 on a generator of the original-trefoil block. The reverse-mirror block has matrix −A, and therefore generator self-linking −2/3≡1/3. Choose the coordinates (a,b) with the reverse-mirror block first and the original-trefoil block second. The mixed terms vanish, so in these explicitly ordered coordinates the linking form is diag⁡(1/3,−1/3), as asserted.

3.1F6F8givenstep 2.2algebra

The diagonal subgroup P={(a,a):a∈Z/3} has order 3 and λ((a,a),(b,b))=ab/3−ab/3=0. The ambient group has order 9, so ∣P∣2=9 and [F6] makes P a metabolizer. By [F8], the map χ(a,b)=(a−b)/3 mod Z is a character of order 3 and vanishes on P.

4.1F5F10given∎

By [F5], T#T† bounds a smooth ribbon disk and is smoothly slice by [F10]. This establishes sliceness independently of the homology and character calculation.

Diagram

The following is the positive trefoil as the closure of the two-strand braid σ13. Here σ1 means the strand entering from the left passes under the strand entering from the right; the closure arcs connect endpoints in equal horizontal positions. Three crossings exchange the two endpoints, so the closure has one component. The proof uses the Seifert-matrix calculations above and does not rely on the drawing.

\begin{tikzpicture}[x=0.9cm,y=0.9cm,baseline=(current bounding box.center)]
  \draw[thick] (-1,3)--(1,2)--(-1,1)--(1,0);
  \draw[thick] (1,3)--(-1,2)--(1,1)--(-1,0);
  \fill[white] (0,2.5) circle (2.5pt);
  \draw[thick] (-0.28,2.36)--(0.28,2.64);
  \fill[white] (0,1.5) circle (2.5pt);
  \draw[thick] (-0.28,1.36)--(0.28,1.64);
  \fill[white] (0,0.5) circle (2.5pt);
  \draw[thick] (-0.28,0.36)--(0.28,0.64);
  \draw[thick] (-1,0)..controls(-1.7,0)and(-1.7,3)..(-1,3);
  \draw[thick] (1,0)..controls(1.7,0)and(1.7,3)..(1,3);
\end{tikzpicture}

The reverse mirror factor is obtained by reflecting the diagram and reversing its orientation; the square knot is their connected sum. The diagram only records the braid convention used to name T.

Sources