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Wave energy and black-hole perturbation interfaces

1 · Prerequisites

2 · Summary

3 · Logical flowchart

4 · Definitions, postulates, theorems and proofs

DefinitionDefinition: Literature-sourcedProof: Not applicableverified 2026-10-22 (gpt-6.1-sol)Open item page →

Scalar test-wave stress and multiplier current

Physical scope

A mathematical stress tensor and multiplier current for a real test scalar on a fixed Lorentzian background; it is not coupled matter stress-energy and does not evolve the metric.

Definition

Assume the axiom of countable choice ACω for the smooth tangent-bundle conventions. Let (M,g,N) be a time-oriented smooth Lorentzian four-manifold of signature (−,+,+,+) with metric-selected connection ∇ and inverse metric gab. Let U⊆M be open, let ψ∈C∞(U,R) be a real scalar field, and let X be a smooth vector field on U. Define the wave operator □gψ:=gab∇a∇bψ and the symmetric covariant tensor

Qab[ψ]:=(∇aψ)(∇bψ)−12gabgcd(∇cψ)(∇dψ).

Define the multiplier covector by JaX[ψ]:=Qab[ψ]Xb. The associated energy-current vector is jXa[ψ]:=−gabJbX[ψ]; this sign convention makes its flux through a future spacelike slice equal to the density QabnaXb when n is the future unit normal. The test-wave equation is □gψ=0 on U. These objects are defined on the fixed background g; Q is not automatically an SI matter stress-energy tensor, is not inserted into an Einstein equation here, and does not evolve g.

If ψ is dimensionless and the coordinates have length units, the components of Q have units of inverse length squared. This dimensional fact does not identify Q with a physical stress tensor without an independently specified field normalization and coupling.

Remarks

This Qab is the stress tensor of a mathematical test scalar on a fixed background. It is not identified with the physical Einstein-matter tensor. The page supplies no gauge-invariant Regge–Wheeler, Zerilli, or Teukolsky master variables, no reconstruction theorem, and no mode exclusions or gravitational boundary conditions. Those definitions and reductions remain prerequisites for any theorem about linear gravitational perturbations. A scalar-wave estimate here is not a gravitational or nonlinear Kerr stability result.

PropositionStatement: Literature-sourcedProof: AI-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Wave multiplier divergence identity

Physical scope

A differential identity for a real test scalar on a fixed smooth Lorentzian background; it asserts no decay or coupled gravitational response.

Statement

Assume ACω. Let (M,g,N) be a time-oriented smooth Lorentzian four-manifold, let U⊆M be open, let ψ∈C∞(U,R), and let X be a smooth vector field on U. For the tensor Qab[ψ] and multiplier covector JaX[ψ]=Qab[ψ]Xb defined from the metric-selected connection,

∇aJaX[ψ]=(□gψ) Xb∇bψ+12Qab[ψ](LXg)ab.

Consequently, when □gψ=0 and X is Killing, the multiplier current has zero divergence.

Facts & Assumptions

Given: The smooth Lorentzian background, open set, scalar field, vector field, and ACω assumption in the Statement.

[F1]

Scalar test-wave stress and multiplier current: Qab=∇aψ∇bψ−12gab∇cψ∇cψ, JaX=QabXb, and □gψ=gab∇a∇bψ.

[F2]

Existence and uniqueness of the metric-selected connection of a nondegenerate metric, and its extension to tensor fields: ∇g=0, the metric-selected connection is torsion-free, and its tensor derivative obeys the product rule and commutes with metric contractions.

[F3]

Killing fields of a Lorentzian metric: X is Killing precisely when LXg=0.

[F4]

Killing fields and conserved currents, and on-shell conservation of the Hilbert stress-energy tensor: for the metric-selected torsion-free connection, (LXg)ab=∇aXb+∇bXa.

[A1]

ACω is the only choice principle assumed for the smooth tangent-bundle and connection conventions used by [F2] (The Axiom of Countable Choice (ACω)).

Proof

1.1givenA1F1F2algebra

Differentiate the definition of Q using ∇g=0 from [F2]: ∇aQab=(□gψ)∇bψ+∇aψ ∇a∇bψ−∇cψ ∇b∇cψ. Since ψ is a scalar and the connection is torsion-free, ∇a∇bψ=∇b∇aψ; after relabelling the contracted index, the last two terms cancel. Thus ∇aQab=(□gψ)∇bψ.

2.1step 1.1F1F2algebra

Apply the product rule to JaX=QabXb and substitute step 1.1: ∇aJaX=(□gψ)Xb∇bψ+Qab∇aXb.

3.1step 2.1F1F4algebra

The tensor Qab is symmetric by [F1]. Therefore Qab∇aXb=12Qab(∇aXb+∇bXa)=12Qab(LXg)ab by [F4], which proves the displayed identity.

4.1givenF3step 3.1algebra∎

If □gψ=0 and X is Killing, the first term in the identity vanishes by the equation and the second vanishes by [F3]. Hence ∇aJaX=0. This is a conditional model identity, not a decay estimate.

LemmaStatement: Literature-sourcedProof: AI-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Dominant energy inequality for the real scalar test tensor

Physical scope

A pointwise algebraic inequality for the mathematical test-scalar tensor on a Lorentzian tangent space; it does not assert that the tensor is coupled matter.

Statement

Assume ACω. At a point p of a time-oriented Lorentzian four-manifold, let n be a future-directed unit timelike vector, let X∈TpM be future causal, and let ψ be a smooth real scalar. Put ℓ:=♯g(dψ), a:=dψ(n), b:=hn(ℓ)∈n⊥, and ∣b∣2:=g(b,b), where hn is the spatial projection relative to n. Then

Q(n,n)=12(a2+∣b∣2),Q(n,X)≥0.

Facts & Assumptions

Given: A time-oriented Lorentzian tangent space of signature (−,+,+,+), a future unit timelike vector n, a future causal vector X, and dψ.

[F1]

Scalar test-wave stress and multiplier current: Q(u,v)=dψ(u)dψ(v)−12g(u,v)g−1(dψ,dψ).

[F2]

Observers, rest spaces and the spatial projection at an event: g(n,n)=−1, n⊥ is the rest space, and hn(v)=v+g(n,v)n.

[F3]

The observer rest-space decomposition and the spatial projection: n⊥ is positive definite and hn is the orthogonal projection onto it.

[F4]

Timelike, null, spacelike and causal vectors of a Lorentz vector space: causal vectors are nonzero and satisfy g(X,X)≤0. By Classification of future and past causal vectors by a timelike field, future timelike vectors form the connected component Cp+ containing Np, and future causal vectors are exactly cl⁡(Cp+)∖{0}. In particular n∈Cp+ and X∈cl⁡(Cp+).

[F5]

Cauchy–Schwarz: ∣⟨u,v⟩∣≤∥u∥∥v∥, with equality exactly for linearly dependent vectors: in the positive-definite real inner product space n⊥, ∣g(b,Y)∣≤∣b∣ ∣Y∣.

[A1]

ACω is the only choice principle assumed in the smooth tangent-bundle conventions used by [F2] and [F3] (The Axiom of Countable Choice (ACω)).

Proof

1.1givenA1F1F2F3algebra

Set ℓ=♯g(dψ) and a=g(ℓ,n). Then b=hn(ℓ)=ℓ+an, so ℓ=b−an and g(b,n)=0 by [F2]–[F3]. It follows that g−1(dψ,dψ)=g(ℓ,ℓ)=−a2+∣b∣2. Substitution into [F1], using g(n,n)=−1, gives Q(n,n)=a2+12(−a2+∣b∣2)=12(a2+∣b∣2).

1.2givenF2F3F4algebra

Let α:=−g(n,X) and Y:=X−αn. The continuous linear function v↦g(n,v) never vanishes on the timelike component Cp+: a timelike vector in n⊥ would contradict its positive definiteness in [F3]. Since Cp+ is connected and contains n, where this function is −1, it is negative throughout Cp+. Continuity makes it nonpositive on its closure, so [F4] gives α≥0. By [F2], Y=hn(X)∈n⊥. Since g(X,X)=−α2+∣Y∣2≤0, one has ∣Y∣≤α.

2.1F1step 1.1step 1.2algebra

By [F1] and step 1.1, Q(n,X)=αa2+a g(b,Y)+α2(−a2+∣b∣2)=α2(a2+∣b∣2)+a g(b,Y).

3.1F5step 1.2step 2.1algebra∎

Apply [F5] and ∣Y∣≤α from step 1.2: Q(n,X)≥α2(a2+∣b∣2)−α∣a∣∣b∣=α2(∣a∣−∣b∣)2≥0. If α=0, step 1.2 gives Y=0 and hence X=0, for which Q(n,X)=0 as well. This proves the causal flux inequality, including the null case.

PropositionStatement: Literature-sourcedProof: AI-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Schwarzschild scalar Killing-flux balance

Physical scope

A finite-region conservation identity for a mathematical test scalar on the fixed Schwarzschild exterior and its regular advanced extension; it proves no decay or gravitational backreaction.

Statement

Assume ACω. Let s>0 and let gext be the regular advanced-chart extension of the Schwarzschild exterior, with f(r)=1−s/r and stationary field T=∂v. Give its domain Mext=Rv×(0,∞)r×S2 the product orientation determined by dv∧dr∧ωS2, where ωS2 is the positive area form of the unit round sphere in its outward orientation; write dΩ for its associated positive area measure. In this orientation, volgext=r2 dv∧dr∧ωS2. Let C be a compact finite smooth singular four-chain in the exterior closure r≥s, with oriented boundary ∂C=Σ2−Σ1+H++Bout, where Σ1,Σ2 are spacelike faces with future unit normals n1,n2, H+ is a future-horizon face, and Bout is the remaining signed outer boundary. Let ψ be smooth on a neighborhood of C and solve □gextψ=0. Define jTa:=−Qab[ψ]Tb. Orient each spacelike face Σj so that its adapted unit normal is the future unit normal nj, and define

Ej:=ΦjT(Σj)=∫ΣjQab[ψ]njaTb dμΣj.

Define Fout as the signed flux of jT through Bout and FH:=∫H+(Tψ)2 dμH, where dμH=s2 dv dΩ is the positive horizon measure in the advanced chart. Then E1,E2,FH≥0 and

E2+FH+Fout=E1.

The signed outer flux need not be nonnegative. On the exterior static slices x0=constant, n=f−1/2T and Q(n,T)=f Q(n,n); this stationary slice energy degenerates as r↓s, where T becomes null in the regular extension.

Facts & Assumptions

Given: The chain, boundary decomposition, smooth wave, and Schwarzschild extension in the Statement.

[F1]

Scalar test-wave stress and multiplier current: JaT=QabTb and the energy-current vector is jTa=−gabJbT.

[F2]

Wave multiplier divergence identity: on a solution of □gψ=0, a Killing multiplier T gives ∇aJaT=0.

[F3]

Killing fields of a Lorentzian metric: T is Killing when LTg=0.

[F4]

The Schwarzschild exterior model datum: domain, metric, mass parameter and time orientation and The Schwarzschild exterior datum is a smooth time-oriented Lorentzian four-manifold: in the exterior T=∂0 is future timelike, g(T,T)=−f, and the metric coefficients are independent of x0.

[F5]

Smooth horizon-crossing extension of the Schwarzschild exterior metric in the advanced chart: the advanced extension has gext=−f dv2+2 dv dr+r2dΩ2, the exterior is isometric to r>s, and r=s is a future null hypersurface generated by T=∂v.

[F6]

Dominant energy inequality for the real scalar test tensor: for a future unit timelike n and future causal X, Q(n,X)≥0.

[F7]

The metric volume form, current flux through 3-faces and finite-chain charges and Divergence, Stokes flux balance and the non-null face formula for a Lorentzian current: for a smooth vector field j, d(ιjvolg)=(∇aja)volg and Φj(∂C)=∫C(∇aja)volg.

[F8]

Divergence, Stokes flux balance and the non-null face formula for a Lorentzian current clause (c): its face formula gives flux density εg(j,ν∗)∣det⁡(g(vi,vj))∣ for the adapted unit normal ν∗; on a spacelike face oriented with future unit normal n, this is −g(j,n) dμΣ for the induced positive volume measure.

[A1]

ACω is the only choice principle used in the smooth Schwarzschild extension and tangent-bundle conventions (The Axiom of Countable Choice (ACω)).

Proof

1.1givenA1F2F3F5algebra

In the advanced coordinates all coefficients of gext are independent of v, so the coordinate formula for L∂vgext gives LTgext=0 and T is Killing by [F3]. The multiplier identity [F2] therefore gives ∇aJaT=0 on C. Since jTa=−gabJbT, its divergence also vanishes.

1.2F1F8algebra

The Statement orients each spacelike face so its adapted unit normal is the future unit normal nj. By [F8] its current flux density is −g(jT,nj) dμΣj. The definition jTa=−gabQbcTc gives g(jT,nj)=−QabnjaTb, so integration yields ΦjT(Σj)=∫ΣjQabnjaTb dμΣj=Ej.

1.3givenF4F5F6

The isometric exterior has T future timelike for r>s, and [F5] makes T future null on H+. Thus T is future causal throughout the stated closure. Applying [F6] to each spacelike face gives E1,E2≥0.

2.1F1F5F7step 1.3algebra

On H+, the inverse of the (v,r) metric block has grv=1 and grr=f=0. Hence jTr=−grbQbv=−Qvv=−(Tψ)2, since gvv=0 there. With volgext=r2 dv∧dr∧ωS2 and the outward boundary orientation at the inner face r=s, the pullback of ιjTvolgext is (Tψ)2s2 dv∧ωS2. Therefore this face flux is exactly FH≥0.

3.1givenF7step 1.1step 1.2step 2.1algebra

By [F7] and step 1.1, ΦjT(∂C)=0. The stated boundary decomposition and additivity of flux give ΦjT(Σ2)−ΦjT(Σ1)+FH+Fout=0. Using step 1.2 to identify the two face fluxes with E2 and E1 gives the asserted balance.

4.1F4F5F6step 1.3algebra∎

On the static exterior slices g(T,T)=−f and n=f−1/2T, so T=f n and bilinearity gives Q(n,T)=f Q(n,n). By [F6] with X=n, Q(n,n)≥0, while the coefficient f tends to zero as r↓s. In the regular extension g(T,T)=−f vanishes at r=s by [F5], so T becomes null there and the static Killing slice density loses its transverse coercivity.

Remarks

The calculation proves conservation with the stated side flux and the degeneracy of the stationary Schwarzschild energy at the horizon. A redshift estimate remains deferred: its proof route requires a multiplier vector field that is timelike across the horizon and has positive deformation tensor near the nonextremal horizon. A Morawetz estimate also remains deferred: its proof route requires a radial multiplier whose bulk term degenerates at the photon sphere r=3s/2 (here s=2M), together with a controlled far-region r-weighted estimate. This finite-region stationary balance proves none of those estimates. The item does not supply a Kerr scalar-decay theorem or any gravitational perturbation stability result.

DefinitionDefinition: AI-adaptedProof: Not applicableverified 2026-10-22 (gpt-6.1-sol)Open item page →

Nondegenerate integrated local energy estimate near the Schwarzschild photon sphere

Physical scope

A precise mathematical form of a first-derivative, unweighted local-energy bound on a fixed Schwarzschild exterior; it is a definition of an estimate, not a claim that the estimate holds.

Definition

Assume ACω. Let (M,g,N) be the Schwarzschild exterior datum with s>0, f(r)=1−s/r, exterior coordinate x0, and stationary field T=∂0. Let 0<δ<s/2 and put Kδ:={(x0,r,ω):∣r−3s/2∣≤δ} for ω∈S2. Then Kδ is contained in r>s. On the static slice Σx0:={x0=constant} the future unit normal is n=f−1/2T. For a smooth real test wave ψ with finite initial stationary energy, define

ET[ψ](x0):=∫Σx0Qab[ψ]naTb dμΣx0,ET,δ[ψ](x0):=∫Σx0∩KδQab[ψ]naTb dμΣx0.

A nondegenerate integrated local energy estimate with no trapping loss on Kδ means that there is a finite constant C, independent of ψ, such that every smooth solution of □gψ=0 with finite ET[ψ](0) satisfies

∫0∞ET,δ[ψ](x0) dx0≤CET[ψ](0).

Here “nondegenerate” means that the estimate integrates the full unweighted first-derivative density, with no weight vanishing at r=3s/2; “no trapping loss” means that the right side contains only the initial first-derivative stationary energy, with no additional derivatives or degenerating weights. This definition asserts no existence or nonexistence of such a constant.

DefinitionDefinition: Literature-sourcedProof: Not applicableverified 2026-10-22 (gpt-6.1-sol)Open item page →

Kerr horizon mode and shifted horizon frequency

Physical scope

A local mathematical definition of a scalar mode trace on a regular subextremal Kerr future horizon; it asserts no global wave solution, scattering state, or amplification.

Definition

Assume ACω. Let M>0, 0<∣a∣<M, and use the length coordinates of the subextremal Kerr datum. Use the smooth ingoing extension with its proved compatible time orientation N‾=∂v−(2Mr/Σ)∂r from Kerr horizon angular velocity and the ergoregion. Set H+:={r=r+} and let P⊂H+ be a smooth open patch in the hypersurface topology. Let T and Φ be the stationary and axial Killing fields restricted to P, and let χ:=T+ΩHΦ with ΩH:=a/(r+2+a2) be the future null generator there; the supplier proves g(χ,N‾)=−1 on H+. A smooth complex scalar u∈C∞(P,C) is an (ω,m) horizon mode when ω∈R, m∈Z, and

Tu=−iωu,Φu=imu.

Its shifted horizon frequency is ω~:=ω−mΩH. By linearity of χ, every such mode satisfies χu=−iω~u. The parameter ω has units reciprocal to the Kerr time coordinate, m is dimensionless, and ΩH has the same units as ω. This is a local definition of mode data only; it does not assert that a nonzero mode extends to a global solution of the wave equation.

LemmaStatement: Literature-sourcedProof: AI-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Time-averaged stationary flux of a Kerr horizon mode

Physical scope

A local algebraic flux identity for a smooth scalar mode trace on a regular subextremal Kerr future horizon; it asserts no global mode existence or scattering amplification.

Statement

Assume ACω. Let 0<∣a∣<M, and let P⊂H+={r=r+} be the smooth open mode patch, with stationary field T, axial field Φ, future null generator χ=T+ΩHΦ, and ΩH=a/(r+2+a2). Let u∈C∞(P,C) be a nonzero (ω,m) mode trace, where ω>0, m∈Z, and suppose that ψ=Re⁡u is the trace of a smooth real scalar field near P. No wave equation or global extension of the mode is assumed. For each p∈P, let γp:Ip→H+ be the unique maximal integral curve of T through p, with γp(0)=p and maximal open interval domain Ip⊆R. For p with [0,2π/ω]⊂Ip and γp([0,2π/ω])⊂P, define

⟨Q(χ,T)⟩T(p):=ω2π∫02π/ωQab[ψ](γp(τ))χaTb dτ.

Write Pω,T for the set of such points. Then, for every p∈Pω,T,

⟨Q(χ,T)⟩T=12ω(ω−mΩH)∣u∣2.

Consequently, when mΩH>ω>0, this averaged stationary horizon-flux density is nonpositive at every point of Pω,T, is zero at every node u=0, and is strictly negative exactly where u≠0.

For a compact smooth spacelike horizon-cut patch D⊂Pω,T with nonempty interior and smooth boundary, let dμD be the positive area measure of its induced metric. Thus the mode domain contains the full integral-curve segment of length 2π/ω from every point of D. Define the integrated averaged stationary flux by FD:=∫D⟨Q(χ,T)⟩T dμD=12ω(ω−mΩH)∫D∣u∣2 dμD. In the same frequency band, FD<0 whenever u∣D is not identically zero. At any p∈Pω,T with u(p)≠0, such an admissible patch can be chosen around p. This is a conditional local mode-trace calculation; it does not assert the existence of a global wave or scattering solution.

Facts & Assumptions

Given: The regular Kerr horizon geometry, a nonzero smooth mode trace, and the smooth real scalar field with that trace.

[F1]

Kerr horizon mode and shifted horizon frequency: Tu=−iωu, Φu=imu, and χu=−i(ω−mΩH)u.

[F2]

Scalar test-wave stress and multiplier current: Qab[ψ]=∇aψ∇bψ−12gabgcd∇cψ∇dψ.

[F3]

Kerr horizon angular velocity and the ergoregion: H+ is null, χ=T+ΩHΦ is its null normal generator, and T,Φ preserve the horizon.

[F4]

Integral curves of a vector field: an integral curve γ of T satisfies γ′(τ)=Tγ(τ) on its interval domain.

[F5]

Through each point there is a unique maximal integral curve: there is a unique maximal integral curve γp:Ip→H+ of T through every p∈H+.

[F6]

Local existence, uniqueness, and smooth dependence for manifold integral curves: near each point of H+, the local integral curves of the smooth field T exist on a common time interval and depend smoothly on their initial points.

[A1]

ACω is the only choice principle used in the Kerr horizon extension and smooth tangent-bundle conventions of [F3] (The Axiom of Countable Choice (ACω)).

Proof

1.1givenA1F2F3algebra

Since χ is normal to the null hypersurface H+ and both T and Φ are tangent to it by [F3], g(χ,T)=g(χ,Φ)=0 on H+. Hence the metric-trace term in [F2] vanishes when contracted with χaTb, so Q(χ,T)=(χψ)(Tψ).

2.1givenF1F4step 1.1algebra

Fix p∈Pω,T and put A:=u(p). Along its stationary integral-curve segment, ddτu(γp(τ))=(Tu)(γp(τ))=−iωu(γp(τ)) by [F4], so u(γp(τ))=Ae−iωτ. The mode equations [F1] give Tψ=Re⁡(−iωu) and χψ=Re⁡(−i(ω−mΩH)u).

3.1step 2.1algebra

If A=0, both differentiated real fields vanish along this orbit and the displayed average identity is 0=0. Otherwise put ϑ=arg⁡A−ωτ. Then Tψ=ω∣A∣sin⁡ϑ and χψ=(ω−mΩH)∣A∣sin⁡ϑ. Averaging their product over τ∈[0,2π/ω] uses ω2π∫02π/ωsin⁡2(arg⁡A−ωτ) dτ=12, and gives the displayed identity.

4.1givenstep 3.1algebra

If mΩH>ω>0, the coefficient ω(ω−mΩH)/2 is strictly negative. Since ∣u∣2≥0, step 3.1 gives a nonpositive averaged density, with equality exactly at u=0 and strict negativity exactly at u≠0. A mode that is not identically zero need not be nonvanishing at every point.

5.1givenF3F4F5F6step 3.1step 4.1algebra∎

On the compact patch D, smoothness bounds ∣u∣2 and the induced area density, so both displayed integrals are finite. Integrating step 3.1 gives the formula for FD. If u∣D is not identically zero, continuity and density of the interior give an interior point where ∣u∣2>0 and a smaller coordinate disk where ∣u∣2≥b>0. The positive smooth area density has a positive lower bound a>0 on a still smaller closed disk; its positive Euclidean area makes ∫D∣u∣2dμD≥ab area⁡(disk)>0. Step 4.1 then makes FD<0. To find a patch near a point p∈Pω,T with u(p)≠0, cover the compact integral-curve segment γp([0,2π/ω]) by finitely many neighborhoods supplied by [F6] and subdivide the parameter interval so each piece lies in one such neighborhood. Composing the corresponding local solution maps gives smooth dependence on initial data through the whole interval. Since γp([0,2π/ω])⊂P and P is open, shrink the initial neighborhood of p so all these curves remain in P; nearby points then also lie in Pω,T. By [F3], TpH+=χp⊥ for a nonzero null normal χp. Nondegeneracy gives v with g(χp,v)=−1; then k=v+12g(v,v)χp is null and g(χp,k)=−1. The plane spanned by χp,k has one negative and one positive direction, so its orthogonal complement is a positive two-plane in TpH+. Choose a smooth hypersurface chart whose first two coordinate vectors span that plane at p, fix its third coordinate, and shrink a closed coordinate disk about p. Positivity persists by continuity of its metric matrix, and the disk can be chosen inside the neighborhood and the nonzero set. No integral over a full noncompact horizon is used.

LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Exact Schwarzschild waves concentrated in a photon-sphere annulus

Physical scope

Exact real test-scalar waves on the fixed Schwarzschild exterior, concentrated in the entire specified radial annulus for any prescribed finite time; no gravitational perturbation or coupled-matter assertion.

Statement

Assume ACω. Fix the Schwarzschild exterior datum with s>0, the stationary field T=∂0, and 0<δ<s/2. Let Kδ={∣r−3s/2∣≤δ} include the whole sphere factor, and use the stationary total and annular energies ET and ET,δ defined for the real scalar test tensor. For every H>0 and every 0<ϵ<1, there is a real ψ∈C∞(R×(s,∞)×S2) solving □gψ=0, with compact smooth Cauchy data at x0=0, such that

ET[ψ](0)=1,ET,δ[ψ](x0)≥1−ϵfor every 0≤x0≤H.

The same solution works on the entire prescribed interval. Its stationary energy is finite and equal to one on every static slice. The frequency may depend on H,ϵ,s,δ; no infinite-time concentration, horizon extension, or concentration in a smaller angular neighborhood is asserted.

Facts & Assumptions

Given: The exact fixed Schwarzschild exterior, parameters, real scalar stress, annulus and energies in the Statement.

[A1]

Countable Choice is retained through the smooth Schwarzschild and tangent-bundle conventions; no Dependent Choice or additional global geometric assumption is used. The Axiom of Countable Choice (ACω)

[F1]

The exterior metric is g=−f dt2+f−1 dr2+r2γS2, f=1−s/r>0, on R×(s,∞)×S2, with future field T=∂0. Throughout this proof, t:=x0 is a local alias for the length coordinate, not the physical-time coordinate x0/c denoted by t in clause (d) of the supplier. Thus T=∂t in this local notation; no assumption c=1 is made. The Schwarzschild exterior model datum: domain, metric, mass parameter and time orientation

[F2]

The real scalar tensor is Qab=∂aψ∂bψ−12gabgcd∂cψ∂dψ and the equation is □gψ=0. Scalar test-wave stress and multiplier current

[F3]

On a static slice n=f−1/2T and ET=∫Q(n,T) dμΣ; ET,δ is the same integral over ∣r−3s/2∣≤δ and all ω∈S2. Nondegenerate integrated local energy estimate near the Schwarzschild photon sphere

[F4]

Smooth cutoffs equal to one on an inner interval and zero outside a larger interval are obtained by translating and rescaling smooth Euclidean bumps. A smooth bump between concentric Euclidean balls

Proof

1.1givenA1F1constructalgebra

Coordinates and angular functions. Put r0=3s/2 and define logy:=∫1ydρ/ρ for y>0; its difference quotient gives (log⁡y)′=1/y. On each dyadic interval [2j,2j+1] and [2−j−1,2−j], the integral of 1/ρ is at least 1/2, so log⁡y→+∞ as y→∞ and log⁡y→−∞ as y↓0. Define the length offset C∗:=r0+slog⁡(r0/s−1) and set x(r)=r+slog⁡(r/s−1)−C∗, so x(r0)=0. Then x′(r)=1+s/(r−s)=1/f(r)>0 and the endpoint limits are −∞,+∞, so x:(s,∞)→R is bijective. Its inverse r(x) is continuous by strict monotonicity; taking difference quotients in x(r(x+h))−x(r(x))=h gives rx=1/x′(r)=f(r). Thus r is C1, and the identity rx=f(r) inductively makes r Ck for every k, since f is smooth. In polar coordinates for the unit round sphere define ΔS2v:=(sin⁡ϑ)−1∂ϑ(sin⁡ϑ ∂ϑv)+(sin⁡ϑ)−2∂φ2v and ∣∇S2v∣2:=∣∂ϑv∣2+(sin⁡ϑ)−2∣∂φv∣2; these are the scalar Laplace--Beltrami operator and the squared metric norm of the gradient for dΩ=sin⁡ϑ dϑ dφ. For an integer l≥1 set In:=∫0πsin⁡nϑ dϑ, cl:=(2πI2l+1)−1/2>0, and Yl:=cl(ω1+iω2)l. The polynomial expression makes Yl smooth at both poles; in polar coordinates Yl=clsin⁡lϑ eilφ. Direct differentiation gives ΔS2Yl=−l(l+1)Yl. Integration in φ gives ∫S2∣Yl∣2dΩ=1, ∫S2Yl2dΩ=0, and ∫S2∇S2Yl⋅∇S2Yl dΩ=0, the latter two because their integrands have the factor e2ilφ. Also ∣∇S2Yl∣2=cl2l2sin⁡2l−2ϑ(1+cos⁡2ϑ). Integration by parts gives (2l+1)I2l+1=2lI2l−1, and hence ∫S2∣∇S2Yl∣2dΩ=2πcl2l2(2I2l−1−I2l+1)=l(l+1).

2.1F1F2step 1.1algebra

Exact scalar reduction. In (t,x,ω) the metric is f(−dt2+dx2)+r2γS2. In a polar sphere chart its inverse components are (−f−1,f−1,r−2,(r2sin⁡2ϑ)−1) and ∣det⁡g∣=fr2sin⁡ϑ. The Christoffel symbols of this metric-selected connection are Γcab=12gcd(∂agbd+∂bgad−∂dgab); for a scalar u, ∇a∇bu=∂a∂bu−Γcab∂cu; substituting the diagonal metric into the Christoffel formula gives gabΓxab=−2/r, gabΓϑab=−cot⁡ϑ/r2, and zero for the other two traced components. Consequently □gu=−f−1utt+f−1uxx+2r−1ux+r−2(uϑϑ+cot⁡ϑ uϑ+sin⁡−2ϑ uφφ)=f−1(−utt+r−2∂x(r2ux))+r−2ΔS2u. Substituting u=q(t,x)Yl(ω)/r(x) and rx=f yields □gu=Ylfr(−qtt+qxx−Wlq), where Wl=f(l(l+1)/r2+s/r3)≥0 and fx=fs/r2. For each fixed l, Wl and every x derivative are bounded on R: ∂x=f∂r, the rational functions extend smoothly to r=s, and their derivatives decay at infinity. No uniform-in-l bound is needed for existence.

3.1F1F2F3step 1.1step 2.1algebra

Positive energy and real fields. For a compactly supported complex q define el[q]=12∫R(∣qt∣2+∣qx∣2+Wl∣q∣2) dx. Use the sum of the real and imaginary scalar energies for a complex field. From [F2]--[F3], its energy density in x,ω is 12(r2∣ut∣2+r2∣ux∣2+f∣∇S2u∣2). For qYl/r, integration over S2 gives 12(∣qt∣2+∣qx−bq∣2+fl(l+1)∣q∣2/r2), b=f/r. The identity b′+b2=fs/r3 and integration of −b∂x∣q∣2, with zero endpoint terms, prove that its total energy equals el[q]. The zero bilinear angular integrals in step 1.1 give exactly ET[Re⁡(qYl/r)]=el[q]/2. The original local energy density is nonnegative on every radial subset. The factor 1/2 for real fields also holds before the radial integration by parts, so no false boundary-term identity on a finite annulus is being used.

3.2step 2.1constructalgebra

Global smooth radial Cauchy construction. For arbitrary compact smooth data p,v, solve the integral equation q=q0+Kq, where q0=(p(x+t)+p(x−t))/2+12∫x−tx+tv(y) dy and Kq=−12∫0t∫x−(t−a)x+(t−a)Wl(y)q(a,y) dy da. On a slab of width d its operator norm on bounded continuous functions is at most ∥Wl∥∞d2/2. Choose this below one. Picard iteration from q0 then has geometrically summable successive sup-norm differences, so converges uniformly to the unique bounded continuous solution. Each iterate vanishes outside the unit-speed cone of the initial compact support. Spatial difference quotients of the integral equation inductively give continuous derivatives of every order: the highest differentiated unknown is acted on by the same K, while all lower terms involve already known derivatives and bounded derivatives of Wl. Uniform convergence of these difference quotients follows from that same geometric estimate; the fundamental theorem of calculus identifies their limits as the derivatives. Differentiating the integral equation in time gives the initial velocity, qtt=qxx−Wlq, and all higher time derivatives. Thus the solution is jointly smooth. The fixed slab width depends on l but not on the data size, so restart at successive endpoints and use uniqueness on overlaps to obtain a solution for every real time. Time reversal treats negative times. The iterates and their restarted solutions retain the compact unit-speed support cone. This is an actual Cauchy construction; global hyperbolicity or an unproved scalar-wave existence theorem has not been invoked.

3.3givenstep 2.1constructalgebra

Explicit Gaussian envelope. Let h=(l+1/2)−1, V0=f/r2, V1=fs/r3−V0/4. Then Wl=h−2V0+V1. At x=0 direct differentiation gives V0(0)=Ω2, V0′(0)=0, V0′′(0)/2=−Ω4, where Ω=2/(33s)>0. Indeed ∂rV0=(−2r+3s)/r4, and ∂r2V0(r0)=−3s/r05, with ∂x=f∂r. Put z(t)=cosh⁡(Ωt)+isinh⁡(Ωt), b(t)=Ω2(cosh⁡(Ωt)−isinh⁡(Ωt))/z(t), and a(t,y)=z(t)−1/2e−b(t)y2/2, using the smooth square-root branch equal to one initially. Since Re⁡z>0, it never vanishes. Calculation gives Re⁡b=Ω2/∣z∣2>0, b′=−i(b2+Ω4)/Ω, and (z−1/2)′/z−1/2=−ib/(2Ω). Therefore 2iΩat=−ayy−Ω4y2a. On every fixed ∣t∣≤H, all derivatives of a are polynomials in y with bounded coefficients times a Gaussian having Re⁡b≥cH>0; all required weighted L2 norms are bounded uniformly there.

4.1step 2.1step 3.1step 3.2algebra

Frequency-independent energy stability. The same integral construction with an added d'Alembert forcing term treats smooth forcing on finite slabs. For a smooth spatially compact solution of qtt−qxx+Wlq=F, direct differentiation and integration by parts give el′[q]=Re⁡∫Fqt‾ dx. For nonzero A=∥F∥2 and B=∥qt∥2, integration of (∣F∣/A−∣qt∣/B)2≥0 gives ∫∣Fqt∣≤AB; zero-norm cases give the same inequality immediately. Since Wl≥0, this bounds the energy derivative in absolute value by 2el[q] ∥F∥2. Apply this first to el+η, integrate and let η↓0 to obtain el[q](t)≤el[q](0)+2−1/2∫0t∥F(a)∥2 da. In particular the energy of a homogeneous wave from step 3.2 is conserved. Compact support on every finite slab justifies all integrations, even though the full spatial line is noncompact.

4.2F4step 1.1step 3.3constructalgebra

Compact approximation and residual. Choose a real χ∈Cc∞(R) from [F4], equal to one near 0 and supported inside {∣r(x)−r0∣<δ}. Set Qh=h3/4e−iΩt/hχ(x)a(t,x/h). Its support and the support of each derivative lie in the exact annulus. In Rh=(∂t2−∂x2+Wl)Qh, the h−2 term cancels by V0(0)=Ω2 and the h−1 term cancels by the envelope equation in step 3.3. The remaining terms away from cutoff derivatives are h3/4e−iΩt/hχ times att+V1a+h−2(V0(x)−Ω2+Ω4x2)a. Taylor's theorem on the fixed compact support gives ∣V0(x)−Ω2+Ω4x2∣≤C∣x∣3, with C independent of h. With dx=h dy, the amplitude prefactor changes an envelope L2 norm by h. Thus the first two terms are OH(h) in Lx2 and the cubic term is bounded by Ch h−2h3/2∥∣y∣3a∥2=OH(h). Cutoff commutators are −2χ′∂x of the uncut amplitude and −χ′′ times that amplitude. Their supports have ∣x∣≥d0>0; Gaussian decay there makes their norms OH,N(hN) for every N, despite any fixed derivative powers of h−1. Consequently sup⁡0≤t≤H∥Rh(t)∥2≤CHh.

5.1step 3.1step 3.3step 4.2algebra

Positive normalization. At t=0, the substitution x=h y and Gaussian tail bounds show el[Qh](0)→C0=Ω2∫∣a(0,y)∣2 dy=Ωπ>0. More explicitly, the time derivative's leading term −iΩQh/h contributes Ω2∫∣a0∣2 to the unhalved energy integral; h−2V0∣Qh∣2 contributes the same limit. Their cross/time-envelope terms are O(h), the radial derivative energy is O(h), and the V1 term is O(h2). The factor 1/2 in el therefore gives C0+O(h). In particular this energy has a positive lower bound for sufficiently large integers l.

5.2step 1.1step 2.1step 3.1step 3.2step 4.1step 4.2algebra

Exact correction. Use step 3.2 to solve the homogeneous radial equation with exactly the smooth compact initial data Qh(0),∂tQh(0), obtaining qh on all real times. Then wh=qh−Qh has zero initial data and forcing −Rh. Steps 4.1 and 4.2 give sup⁡0≤t≤Hel[wh](t)≤(H2/2)sup⁡∥Rh(t)∥22≤CHh. Its compact support on finite slabs follows from the support of qh and Qh. Define Uh=Re⁡(qhYl/r). By steps 1.1--2.1 it is a real globally smooth exact scalar wave, including at the sphere poles, with compact smooth initial data. Its conserved stationary energy is exactly el[Qh](0)/2 by steps 3.1 and 4.1.

6.1givenA1F3step 3.1step 5.1step 5.2constructalgebra∎

Concentration on every required slice. Normalize ψh=Uh/el[Qh](0)/2; its stationary energy is exactly one on every slice. Outside Kδ, the approximate field Re⁡(QhYl/r) and all its derivatives vanish. There the exact field equals the correction Re⁡(whYl/r). The original positive density of step 3.1 and the global energy identity consequently give ET,outside Kδ[ψh](t)≤el[wh](t)/el[Qh](0)≤CH′h. The boundary spheres have measure zero, so total energy one implies ET,δ[ψh](t)≥1−CH′h simultaneously for all t∈[0,H]. Choose one sufficiently large integer l with CH′/(l+1/2)<ϵ. This proves the exact quantifiers and real-field assertion. The construction uses the full specified radial annulus and makes no assertion about a smaller angular neighborhood or a frequency uniform in H.

Remarks

The exact annular localization permits a separated high-angular-frequency Gaussian; no general Gaussian-beam theorem is taken as an external proof input. The local radial Cauchy construction above also avoids imposing extra global-hyperbolicity or Dependent-Choice hypotheses on the original Schwarzschild claim. This is a mathematical test-wave result on the fixed exterior and gives no coupled-matter, horizon-regularity or gravitational-stability theorem.

5 · Examples, experiments and counterexamples

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