Alphabeta Math
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How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Em Wave Equation Prerequisites

1 · Prerequisites

2 · Summary

This page supplies the mathematical wave-Cauchy layer that the electromagnetism track consumes: the whole-space three-dimensional wave problem in the normalisation W=c−2∂t2−Δ, so that c2W=□c is the wave operator of speed c. Everything on it carries domain: mathematics and depends only on mathematical suppliers; no physical postulate, observation or empirical claim is made, and the physical reading of c, of the data and of the source remains with the consuming electromagnetism pages.

The page opens with Joint smoothness of the spherical-mean family of a smooth spacetime function, which fixes the conventions of the spherical-mean family M(x,s,v)=(4π)−1∫S2h(x+sn,v) dΩ(n) of a smooth spacetime function h, proves its joint C∞ smoothness in (x,s,v) with every differentiated-integral formula, and records the composed family H~(x,t,v)=(t−v)M(x,c(t−v),v), C∞ near the closed triangle t0≤v≤t≤T. The statement is local: no decay, boundedness or compact support of h is assumed, only uniform bounds on compact parameter sets, and the Axiom of Countable Choice ACω is declared where the surface integral and the parameter differentiation use it.

The three-dimensional wave Cauchy problem: Kirchhoff representation, uniqueness, domain of dependence and compact support then states and proves the wave Cauchy problem for Wu=h with smooth data a,b and smooth source h on a closed time slab: the displayed solution u=∂sHa+Hb+c2∫t0tHh(⋅,v)(⋅,t−v) dv, with Hφ(x,s)=s Mcsφ(x), is C∞ in the extension sense and attains the data; it is the unique C2 solution in that class; it depends only on data in the closed backward c-cone; and compactly supported data propagate with the explicit bound ∣x∣>ρ+c(t−t0). No finite-domain boundary condition, no finite-total-energy hypothesis and no decay at spatial infinity is assumed or asserted. The homogeneous identity Hφ(⋅,0)=0, ∂tHφ(⋅,0)=φ, ∂t2Hφ=c2ΔHφ is supplied by The spherical mean identity behind the wave equation on the prerequisite page em-expanded-analysis-prerequisites; ACω is carried from the published suppliers (The Axiom of Countable Choice (ACω)).

The companion page em-wave-equation-prerequisites-examples records explicit worked checks of the source-support and energy hypotheses of the Cauchy theorem.

3 · Logical flowchart

4 · Definitions, postulates, theorems and proofs

LemmaStatement: AI-adaptedProof: AI-adaptedprecheck passjudge pass (gpt-6.1-sol)Open item page →

Joint smoothness of the spherical-mean family of a smooth spacetime function

Statement

Assume the Axiom of Countable Choice (ACω), declared by the surface-integral and parameter-integral conventions below. Let t0<T and let h∈C∞(R3×[t0,T]) in the extension sense: h is the restriction of a C∞ function on R3×J for some open interval J⊃[t0,T] (Ck Euclidean maps and diffeomorphisms). Let dΩ be the surface measure on the unit sphere S2⊂R3 of total mass ∫S2dΩ=4π (Surface integration on compact C1 hypersurfaces, The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn), and define the spherical-mean family M(x,s,v):=14π∫S2h(x+sn,v) dΩ(n),(x,s,v)∈R3×R×[t0,T]. Then M is of class C∞ on R3×R×[t0,T] in the same extension sense, and for every multi-index α in x and all integers m,l≥0 Dxα∂sm∂vlM(x,s,v)=14π∫S2Dxα∂sm∂vl[h(x+sn,v)] dΩ(n), where the right-hand integrand is the corresponding iterated partial derivative of the composed map (x,s,v)↦h(x+sn,v); in particular ∂s[h(x+sn,v)]=∇xh(x+sn,v)⋅n, where ∇xh(y,v):=(∂y0h(y,v),∂y1h(y,v),∂y2h(y,v))∈R3 is the spatial gradient at fixed v, so the s-derivatives are directional derivatives along n. Consequently, for every c>0 the map H~(x,t,v):=(t−v) M(x,c(t−v),v) is C∞ on R3×[t0,T]×[t0,T] in the extension sense, and for every fixed x∈R3 the map (t,v)↦H~(x,t,v) is C∞ on an open neighbourhood of the closed triangle {(t,v):t0≤v≤t≤T}. Nothing here assumes decay, compact support or boundedness of h; the statement is local in (x,s,v) and uses uniform bounds only on compact parameter sets.

Facts & Assumptions

Given: The Axiom of Countable Choice ACω; times t0<T; a C∞ function h on an open set R3×J with [t0,T]⊂J; and the surface measure dΩ on the unit sphere S2⊂R3 of total mass ∫S2dΩ=4π.

[F1]

A map is of class Ck when every word iterated coordinate partial derivative of order at most k exists and is continuous, and of class C∞ when it is Ck for every k; Dαf=∂0α0⋯∂m−1αm−1f is the canonical-order multi-index derivative, and for a coordinate word w=(i1,…,ir) write Dw:=∂ir⋯∂i1, with the empty word denoting the identity, and let w⋅j denote appending the coordinate j, so Dw⋅j=∂jDw; partial derivatives are the one-variable derivatives along coordinate lines (Ck Euclidean maps and diffeomorphisms, Ck maps and multi-index derivative notation in Euclidean space).

[F2]

Chain rule: if f is totally differentiable at a and g at f(a), then D(g∘f)(a)=Dg(f(a))∘Df(a) (The chain rule for total derivatives: D(g∘f)(a)=Dg(f(a))∘Df(a)).

[F3]

Finite sums, scalar multiples and products of Ck Euclidean maps are Ck, and composites of composable Ck maps are Ck, for every k∈N (Ck Euclidean maps are closed under componentwise algebra and composition); sums, scalar multiples and products of differentiable real functions differentiate by the sum, scalar-multiple and product rules (Sums, scalar multiples, products and quotients: (f+g)′(c)=f′(c)+g′(c), (αf)′(c)=αf′(c), (fg)′(c)=f′(c)g(c)+f(c)g′(c), and (f/g)′(c)=(f′(c)g(c)−f(c)g′(c))/g(c)2 when g(c)≠0).

[F4]

If all first partial derivatives of q exist on a neighbourhood of a and are continuous at a, then q is totally differentiable at a with total derivative the Jacobian matrix; if q is totally differentiable at a, then for every direction u the directional derivative exists and Duq(a)=Dq(a)u=∑j∂jq(a)uj, which for scalar q is ⟨∇q(a),u⟩ with the gradient ∇q of The Jacobian matrix of partial derivatives and the gradient in the scalar-valued case (If all partial derivatives exist on a neighbourhood and are continuous at a point, then the map is totally differentiable there with Jacobian derivative, A total derivative computes every directional derivative, and its matrix is the Jacobian, The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn).

[F5]

Parameter integrals: if K⊆Rn is compact, measurable and of finite Lebesgue measure, a<b, and f and ∂tf are continuous on a neighbourhood of K×[a,b], then t↦∫Kf(x,t) dx is differentiable on [a,b] with derivative ∫K∂tf(x,t) dx; the same conclusion holds, under the ACω convention of Surface integration on compact C1 hypersurfaces, with surface measure on a fixed compact C1 hypersurface in place of K; nothing is asserted for moving parameter sets or singularities crossing the integration set (Differentiation under the integral sign over a compact measurable set and over a compact C1 surface).

[F6]

On a compact embedded C1 hypersurface S the surface integral is defined by the finite chart formula with Gram density; for signed functions with ∫S∣f∣ dS<∞ it is the difference of the integrals of the positive and negative parts; the notation of this item fixes ∫S21 dΩ=4π for the unit sphere S2={n∈R3:⟨n,n⟩=1} (Surface integration on compact C1 hypersurfaces, The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn).

[F7]

For nonnegative measurable f≤g one has ∫f≤∫g, and ∫cf=c∫f for c≥0 (Monotonicity and nonnegative homogeneity of the nonnegative integral).

[F8]

Mean value theorem: if f:[a,b]→R is continuous on [a,b] and differentiable at every point of (a,b), then there is c∈(a,b) with f(b)−f(a)=f′(c)(b−a) (The mean value theorem, as the case g(x)=x of Cauchy's: for f continuous on [a,b] with a<b and differentiable on (a,b) there is c∈(a,b) with f(b)−f(a)=f′(c)(b−a)).

[A1]

The Axiom of Countable Choice ACω: every at most countable family of nonempty sets has a choice function (The Axiom of Countable Choice (ACω)).

Proof

technique · direct
1.1givenA1F5F6

The setting and the reduction to the open set Ω. Let h also denote the C∞ function on the open set R3×J whose restriction to R3×[t0,T] is the h of the statement, put Ω:=R3×R×J, an open subset of R5, and let S2={n∈R3:⟨n,n⟩=1} carry the surface measure dΩ of total mass 4π of [F6]. Define M(x,s,v):=14π∫S2h(x+sn,v) dΩ(n) for (x,s,v)∈Ω; its restriction to the closed set R3×R×[t0,T] is the family of the statement, so every assertion proved below on Ω, or on an open neighbourhood of a closed subset of Ω, restricts to the corresponding extension-sense assertion of the statement. All surface integrals are read under the ACω convention carried by [F5] and [F6].

1.2givenF1F2F3F4

The composed integrand. Define Φ:Ω×R3→R4 by Φ(x,s,v,n):=(x+sn,v). Each component of Φ is a finite sum of products of coordinate functions, so Φ is C∞ on the open set Ω×R3 by [F3], and Φ takes values in R3×J. Hence H:=h∘Φ is C∞ on Ω×R3 by the composition clause of [F3], so every word iterated partial derivative DvH exists and is continuous on Ω×R3 by [F1]. At p=(x,s,v)∈Ω and n∈S2, the chain rule [F2], total differentiability of h [F4] and ∂sΦ(p,n)=(n,0) give ∂sH(p,n)=Dh(x+sn,v)(n,0)=∑j<3∂jh(x+sn,v) nj=⟨∇xh(x+sn,v),n⟩, the directional derivative of h at (x+sn,v) in direction (n,0) [F4]; applying the same computation to the already differentiated integrands shows that the iterated derivatives Dxα∂sm∂vlH(p,n) are the corresponding iterated partial derivatives of the composed map (x,s,v)↦h(x+sn,v), which is H itself, and in particular that ∂smH(p,n) is the m-th iterated derivative at λ=s of λ↦h(x+λn,v).

2.1givenstep 1.2F9

Local bounds on compact boxes. Let K=∏j<5[aj,bj] be a nonempty closed box contained in Ω. Then K×[−1,1]3 is a nonempty closed box in R8, hence compact by [F9], and by step 1.2 every ∣DvH∣ is continuous on the open set Ω×R3, which contains K×[−1,1]3; so by [F9] each ∣DvH∣ attains a maximum there and Cv:=max⁡K×[−1,1]3∣DvH∣ is a finite nonnegative real number with ∣DvH(p,n)∣≤Cv for all (p,n)∈K×S2, because S2⊆[−1,1]3.

2.2givenstep 1.2F2F4F6F7F8F10

Continuity of parameter sphere integrals. Claim: if q:Ω×R3→R is continuous with continuous first partial derivatives, K⊆Ω is a nonempty closed box and ∣∂pjq(p,n)∣≤Cj for all (p,n)∈K×S2 and all j<5, then ∣∫S2q(p,n) dν(n)−∫S2q(p0,n) dν(n)∣≤(∑j<5Cj2)1/2∣p−p0∣ for all p,p0∈K, where ν:=dΩ/4π. Indeed, for fixed n∈S2 the function g(λ):=q(p0+λu,n), u:=p−p0, is defined on [0,1] because the box is convex, and the affine map λ↦(p0+λu,n) has constant partial derivatives, hence is totally differentiable by [F4]; the chain rule [F2] with total differentiability of q [F4] therefore gives g′(λ)=Dq(p0+λu,n)(u,0)=∑j<5∂pjq(p0+λu,n) uj at every λ∈(0,1), and the mean value theorem [F8] bounds ∣q(p,n)−q(p0,n)∣≤sup⁡λ∣∑j∂pjq(p0+λu,n) uj∣≤(∑jCj2)1/2∣u∣ by Cauchy-Schwarz [F10] and the local bounds. Integrating this pointwise bound against ν: the signed surface integral is the difference of the integrals of the positive and negative parts [F6], so ∣∫S2q(p,⋅) dν−∫S2q(p0,⋅) dν∣≤∫S2∣q(p,n)−q(p0,n)∣ dν(n)≤(∑jCj2)1/2∣u∣∫S2dν=(∑jCj2)1/2∣u∣, where the chart formula of [F6] with the monotonicity and scalar rules of [F7] gives monotonicity, the bound ∫S2c dν=c for constants c≥0, and ∫S2dν=1 from the normalisation ∫S2dΩ=4π of [F6].

3.1step 1.1step 1.2step 2.1step 2.2F1F3F5

Induction: every word derivative of M exists with the differentiated-integral formula, continuously. Claim: for every word v in the five coordinate directions of Ω, the iterated derivative DvM exists on Ω and equals ∫S2DvH(p,n) dν(n), and this integral is continuous on Ω. Prove the claim by induction on the length r of the word. For r=0 it is the definition of M in step 1.1 together with ν=dΩ/4π, and continuity is step 2.2 applied with q:=H, whose partial derivatives D(j)H are continuous with bounds C(j) on K×S2 by steps 1.2 and 2.1. Assume the claim for all words of length r; let v be such a word and j a coordinate direction, and fix p0∈Ω, a nonempty closed box K⊆Ω with p0 in its interior and coordinate intervals [aj,bj]. For fixed coordinates other than the j-th and t∈[aj,bj], put Q(n,t):=DvH(p(t),n), where p(t) is the point of the j-th coordinate line with j-th coordinate t; then both Q and ∂tQ=Dv⋅jH(p(t),n) are continuous on an open neighbourhood of S2×[aj,bj] in R3×R, being restrictions of the continuous DvH and Dv⋅jH of step 1.2. By the surface clause of [F5], t↦∫S2Q(n,t) dΩ(n) is differentiable on [aj,bj] with derivative ∫S2∂tQ(n,t) dΩ(n); multiplying by the constant 1/4π (the scalar multiple rule for one-variable derivatives, [F3]) gives ∂j∫S2DvH dν=∫S2Dv⋅jH dν on the line through p0; with the induction hypothesis this shows Dv⋅jM=∫S2Dv⋅jH dν on that line, hence on all of Ω since p0 and j are arbitrary, and this integral is continuous on Ω by step 2.2 applied to q:=Dv⋅jH, whose partial derivatives D(v⋅j)⋅iH are continuous by step 1.2 with bounds C(v⋅j)⋅i on K×S2 by step 2.1. This closes the induction.

4.1step 1.2step 3.1F1

M is C∞ and satisfies the displayed formula. By step 3.1 every word iterated partial derivative of M exists and is continuous on the open set Ω, so M is of class C∞ on Ω by [F1]; in particular its restriction to R3×R×[t0,T] is C∞ in the extension sense of the statement. Every canonical-order derivative Dxα∂sm∂vlM is one of the word derivatives covered by step 3.1, so it equals the sphere integral of the corresponding word derivative Dxα∂sm∂vlH of the composed map, and step 1.2 identifies those integrands as the corresponding iterated partial derivatives of (x,s,v)↦h(x+sn,v); the asserted s-derivative statements are those of step 1.2.

5.1step 2.1step 4.1F3∎

The composed map H~ and the local nature of the argument. Let c>0 and define H~(x,t,v):=(t−v)M(x,c(t−v),v) on the open set R3×R×J. The map Ψ(x,t,v):=(x,c(t−v),v) has components that are finite sums of products of coordinate functions, so it is C∞ by [F3] and takes values in Ω; hence (x,t,v)↦M(Ψ(x,t,v)) is C∞ by composition [F3] with step 4.1, and multiplying by the C∞ function t−v gives that H~ is C∞ on R3×R×J by [F3]. Since [t0,T]⊂J and the closed triangle Δ={(t,v):t0≤v≤t≤T} is contained in [t0,T]×[t0,T]⊂J×J, the restriction shows that H~ is C∞ on R3×[t0,T]×[t0,T] in the extension sense, and for each fixed x the map (t,v)↦H~(x,t,v) is C∞ on the open neighbourhood J×J of Δ. The whole argument used only the bounds of step 2.1 on compact parameter boxes and the compactness of S2; no boundedness, decay or compact spatial support of h was assumed or used.

TheoremStatement: AI-adaptedProof: AI-adaptedprecheck passjudge pass (gpt-6.1-sol)Open item page →

The three-dimensional wave Cauchy problem: Kirchhoff representation, uniqueness, domain of dependence and compact support

Statement

Assume the Axiom of Countable Choice (ACω), used through the cited published suppliers (The Axiom of Countable Choice (ACω)). Let c>0, t0∈R, T>t0, let a,b∈C∞(R3) and let h∈C∞(R3×[t0,T]) in the extension sense that h is the restriction of a C∞ function on R3×J for some open interval J⊃[t0,T] (Ck Euclidean maps and diffeomorphisms). Write W:=c−2∂t2−Δ, so that c2W=□c is the wave operator of speed c (The Laplacian of a C2 function and of a C2 vector field, Wave equation, Cauchy data and wave speed). For φ∈C∞(R3) and s≥0 let Hφ(x,s):=s Mcsφ(x), where Mrφ(x)=14π∫S2φ(x+rn) dΩ(n) is the spherical mean of The spherical mean identity behind the wave equation. Define, with s=t−t0, u(x,t):=∂sHa(x,s)+Hb(x,s)+c2∫t0tHh(⋅,v)(x,t−v) dv,(x,t)∈R3×[t0,T], where h(⋅,v) denotes the map x↦h(x,v) and ∂sHa is the partial derivative of Ha in its second argument, evaluated at s=t−t0. Then:

(a) u is of class C∞ on R3×[t0,T] in the extension sense, Wu=h on R3×(t0,T) (indeed on the open neighbourhood of the closed time interval on which the extension of h is defined), u(⋅,t0)=a and ∂tu(⋅,t0)=b.

(b) Uniqueness: every v∈C2(R3×[t0,T]) in the extension sense with Wv=h on R3×(t0,T), v(⋅,t0)=a and ∂tv(⋅,t0)=b equals u.

(c) Domain of dependence: let a~,b~∈C∞(R3), h~∈C∞(R3×[t0,T]) and let u~ be the corresponding solution. If a~=a and b~=b on the closed ball B‾c(t∗−t0)(x∗) and h~=h on the closed backward cone K(x∗,t∗):={(y,v)∈R3×[t0,t∗]:∣y−x∗∣≤c(t∗−v)} (Forward and backward wave cones, domain of dependence and influence), then u~(x∗,t∗)=u(x∗,t∗) for every x∗∈R3 and t∗∈[t0,T].

(d) Compact support: if a vanishes off a compact Ka⊂R3, b vanishes off a compact Kb, and h(⋅,v) vanishes off a fixed compact Kh for every v∈[t0,T], then for every t∈[t0,T] the function u(⋅,t) has compact spatial support: if Ka∪Kb∪Kh⊆B‾ρ(0) for some ρ>0 (which exists, Heine-Borel in Rn: with the Euclidean metric a subset of Rn is compact if and only if it is closed and bounded, and the proof by bisection uses no choice principle; the same holds on the real line), then u(x,t)=0 whenever ∣x∣>ρ+c(t−t0).

No boundary condition on a finite spatial domain, no finite-total-energy hypothesis, and no decay of a,b,h at infinity is assumed or asserted.

Facts & Assumptions

Given: The Axiom of Countable Choice ACω; a speed c>0; times t0<T; data a,b∈C∞(R3); a function h of class C∞ on R3×[t0,T] in the extension sense, that is, the restriction of a C∞ function on R3×J for some open interval J⊃[t0,T]; the operators W=c−2∂t2−Δ and □c=∂t2−c2Δ; and the surface measure dΩ on the unit sphere S2⊂R3 of total mass 4π.

[F1]

A map is of class Ck when every word iterated coordinate partial derivative of order at most k exists and is continuous, and of class C∞ when it is Ck for every k; the Laplacian is Δf=div⁡∇f=∑i<3∂i∂if (Ck Euclidean maps and diffeomorphisms, The Laplacian of a C2 function and of a C2 vector field).

[F3]

Spherical-mean family of a smooth spacetime function: with h as given and dΩ of total mass 4π, the family m(x,s,v):=14π∫S2h(x+sn,v) dΩ(n) is of class C∞ on R3×R×[t0,T] in the extension sense, and every word iterated partial derivative is obtained by differentiating the composed integrand under the sphere integral; the statement is local, assumes no decay, compact support or boundedness of h, and uses uniform bounds only on compact parameter sets (Joint smoothness of the spherical-mean family of a smooth spacetime function).

[F4]

Spherical means of a fixed smooth datum: for f∈C∞(R3) and Mrf(x)=14π∫S2f(x+rn) dΩ(n), r≥0, the map r↦Mrf(x) is smooth for r≥0 and satisfies the Euler-Poisson-Darboux identity ∂r2Mrf+2r∂rMrf=ΔMrf for r>0, and Hf(x,t):=t Mctf(x), t≥0, satisfies ∂t2Hf=c2ΔHf, Hf(⋅,0)=0 and ∂tHf(⋅,0)=f; all identities are local and assume no decay of f (The spherical mean identity behind the wave equation).

[F5]

Parameter integrals: if K⊆Rn is compact, measurable and of finite Lebesgue measure, a<b, and f,∂tf are continuous on a neighbourhood of K×[a,b], then t↦∫Kf(x,t) dx is differentiable on [a,b] with derivative ∫K∂tf(x,t) dx; the same holds, under the ACω convention of Surface integration on compact C1 hypersurfaces, with surface measure on a fixed compact C1 hypersurface in place of K; moving parameter sets and singularities crossing the integration set are excluded (Differentiation under the integral sign over a compact measurable set and over a compact C1 surface).

[F6]

Differentiating an integral with moving endpoints: if I is an open interval, α,β∈C1(I) with α<β, J is an open interval containing the closures of the intervals [α(t),β(t)] and F:I×J→R is continuous with continuous ∂tF, then G(t)=∫α(t)β(t)F(t,y) dy is C1 on I with G′(t)=F(t,β(t))β′(t)−F(t,α(t))α′(t)+∫α(t)β(t)∂tF(t,y) dy (Differentiating an integral with moving endpoints). Continuous integrands on nondegenerate compact intervals are Riemann integrable and, under ACω, their Riemann and Lebesgue integrals agree (Every continuous function on a closed nondegenerate rectangle in Rm is Riemann integrable, Borel Darboux integrands in finite dimension); thus this rule applies to the continuous Lebesgue integrands used here.

[F7]

A continuous function on a compact metric space is uniformly continuous (Heine-Cantor: a continuous map from a compact metric space to any metric space is uniformly continuous). For integrable functions, the Lebesgue integral is linear and ∣∫f∣≤∫∣f∣ (The Lebesgue integral is linear on L1(μ), The modulus of an integral is bounded by the integral of the modulus); the nonnegative integral is monotone (Monotonicity and nonnegative homogeneity of the nonnegative integral) and λ1([0,1])=1 under ACω (A box in Rn with parameters ai≤bi is Lebesgue measurable of measure ∏i<n(bi−ai), whichever of its faces are included). Consequently ∣∫01(f−g) dz∣≤sup⁡z∈[0,1]∣f(z)−g(z)∣ for continuous f,g.

[F9]

The reflection n↦−n of S2 preserves the surface measure dΩ and ∫S2n dΩ(n)=0; orthogonal transformations of R3 preserve the surface measure (Reflection invariance and vanishing first moment of the sphere measure, Agreement with the existing polar sphere measure).

[F10]

For the Euclidean norm on Rm, ∥u+v∥2≤∥u∥2+∥v∥2 and ∥λu∥2=∣λ∣ ∥u∥2, so also ∥u∥2≥∥u+v∥2−∥v∥2; and Br(x0)={x:∣x−x0∣<r}, B‾r(x0)={x:∣x−x0∣≤r} are the open and closed Euclidean balls (Cauchy-Schwarz ∣⟨x,y⟩∣≤∥x∥2∥y∥2 with its equality case, the triangle inequality for ∥⋅∥2, the parallelogram law and polarisation, The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn).

[F11]

Wave operator and Cauchy data: □c=∂t2−c2Δ and W=c−2∂t2−Δ, so □c=c2W; a classical solution on a time slab is C2 on the open slab and satisfies the equation there, and Cauchy data are the limits as t↓t0; the closed backward cone with vertex (x∗,t∗) and speed c is K(x∗,t∗)={(y,v):t0≤v≤t∗, ∣y−x∗∣≤c(t∗−v)} with base ball B‾c(t∗−t0)(x∗) (Wave equation, Cauchy data and wave speed, Forward and backward wave cones, domain of dependence and influence).

[F12]

Local uniqueness and domain of dependence: under ACω, if u,v∈C2 solve □cu=f and □cv=g on a neighbourhood of the closed backward cone K−(x0,t0) with t0>0, if f=g on the cone and u(⋅,0)=v(⋅,0), ut(⋅,0)=vt(⋅,0) on the base ball Bct0(x0), then u=v on K−(x0,t0) (Domain of dependence and local uniqueness).

[A1]

The Axiom of Countable Choice ACω: every at most countable family of nonempty sets has a choice function (The Axiom of Countable Choice (ACω)).

Proof

technique · direct
1.1givenA1F3F4F5F9F11

The setting. Let h also denote its C∞ extension to R3×J, put Ω:=R3×R×J, and let S2={n∈R3:⟨n,n⟩=1} carry the surface measure dΩ of total mass 4π with normalised probability ν:=dΩ/4π of [F9]. For a fixed datum φ∈C∞(R3) put mφ(x,s,v):=14π∫S2φ(x+sn) dΩ(n) (independent of v), so that Hφ(x,t):=t mφ(x,ct,v0) for any fixed v0∈J is the Hφ of the statement; for the datum h put m(x,s,v):=14π∫S2h(x+sn,v) dΩ(n) on Ω, so that mφ=mhφ for the spacetime datum hφ(x,v):=φ(x). Define, for (x,t)∈R3×R and s:=t−t0, uh(x,t):=∂sHa(x,s)+Hb(x,s),H(x,σ;v):=σ m(x,cσ,v), and, for t∈[t0,T], us(x,t):=c2∫t0tH(x,t−v;v) dv and u:=uh+us; here ∂sHa(x,s) is the derivative of Ha in its second argument at (x,s). All surface integrals are read under the ACω convention carried by [F3] and [F5].

1.2givenF2F3F4F9

Properties of the family. By [F3] applied to h and to each hφ, the families m and mφ are of class C∞ on their domains in the extension sense, and every word iterated partial derivative equals the sphere integral of the corresponding derivative of the composed integrand. In particular m(x,0,v)=h(x,v) and mφ(x,0,v)=φ(x), because the sphere integral of the constant φ(x) is φ(x)⋅4π/4π; consequently Hφ(⋅,0)=0 and ∂tHφ(⋅,0)=φ by the product rule [F2]. The reflection substitution n↦−n with [F9] gives m(x,−s,v)=m(x,s,v) and mφ(x,−s,v)=mφ(x,s,v): both families are even in s. Hence the Euler-Poisson-Darboux identity ∂s2m+2s∂sm=Δm(s≠0) holds on Ω∖{s=0} and likewise with mφ in place of m: for s>0 it is [F4] applied to the fixed smooth datum x↦h(x,v) (respectively x↦φ(x)), and for s<0 it follows from the evenness just proved, since for an even C∞ function of s the derivative ∂s is odd and ∂s2 is even while Δ differentiates only the x-variable.

2.1step 1.2F1F2F4

The homogeneous blocks solve the wave equation with the prescribed data. Fix φ∈C∞(R3). By [F2] the function Hφ(x,t)=t mφ(x,ct,v0) is C∞ on R3×R. Differentiating in t and using the identity of step 1.2 at s=ct, one has ∂t2Hφ=2c ∂smφ+c2t ∂s2mφ and c2ΔHφ=c2t Δmφ=c2t ∂s2mφ+2c ∂smφ for t≠0; at t=0 both sides vanish, since Hφ(⋅,0)=0 gives ΔHφ(⋅,0)=0 and ∂smφ(⋅,0)=0 by evenness. Hence ∂t2Hφ=c2ΔHφ on R3×R. Differentiating this equation in t and commuting ∂t with Δ through [F2] gives the homogeneous equation also for Kφ:=∂tHφ; its data are Kφ(⋅,0)=φ by step 1.2 and ∂tKφ(⋅,0)=c2ΔHφ(⋅,0)=0.

2.2step 1.2F2F5F7F8algebrachoose

Smoothness of the source term and its extension to a neighbourhood. Put θ:=t−t0 and, for θ in an open interval (θ1,θ2) containing [0,T−t0] and small enough that t0+θ(1−z)∈J for all z∈[0,1], define u~s(x,t):=c2θ2∫01z m(x,cθz,t0+θ(1−z)) dz. By step 1.2 and [F2] the integrand A(x,θ,z):=c2z m(x,cθz,t0+θ(1−z)) extends to a C∞ function on R3×(θ1,θ2)×[0,1] whose word derivatives are continuous there. Iterating [F5] in the parameter directions xj and θ over the fixed compact set [0,1] shows that every word derivative in (x,θ) of ∫01A(x,θ,z) dz exists and equals ∫01DwA(x,θ,z) dz; each of these integrals is jointly continuous in p=(x,θ): on a closed spatial-time box Q×K inside the parameter domain, DwA is continuous on the compact product Q×K×[0,1], so [F7] gives uniform continuity there and ∣∫01DwA(p,z) dz−∫01DwA(p0,z) dz∣≤sup⁡z∈[0,1]∣DwA(p,z)−DwA(p0,z)∣⟶0(p→p0). Every parameter point has such a box with that point in its interior by openness, and compactness is [F8]. Hence ∫01A dz is C∞ on R3×(θ1,θ2), and so is u~s=θ2∫01A dz by [F2]. For θ>0 the substitution v=t0+θ(1−z), dv=−θ dz, in the defining integral of us gives u~s=us, while u~s(x,t0)=0=us(x,t0); hence u~:=uh+u~s is a C∞ extension of u to the open neighbourhood R3×(t0−δ,T+δ) of the closed slab, and u is of class C∞ on R3×[t0,T] in the extension sense.

3.1step 1.2step 2.1F2F3F5F6algebrachoose

The Duhamel identity for a smooth datum. Let g be smooth on R3×Jg with Jg an open interval containing t0, and let mg be its signed-radius spherical-mean family. Set Hg(x,σ;v):=σmg(x,cσ,v) and, for τ>0 with t0+τ∈Jg, Jg∗(x,τ):=∫0τHg(x,τ−r;t0+r) dr=∫0τσmg(x,cσ,t0+τ−σ) dσ. The equality follows by σ=τ−r. For each fixed v, step 2.1 applied to g(⋅,v) gives ∂σ2Hg=c2ΔxHg, Hg(x,0;v)=0 and ∂σHg(x,0;v)=g(x,v). At fixed x, the integrand F(τ,r)=Hg(x,τ−r;t0+r) is smooth on R×(Jg−t0) by [F3] and [F2], including negative τ−r. Locally at each admissible τ∗>0, choose an open interval I about τ∗ with inf⁡I>0 and [0,sup⁡I]⊂Jg−t0; thus [F6] applies on a genuine rectangular neighbourhood with endpoints 0 and τ. Two applications give ∂τJg∗=∫0τ∂σHg(x,τ−r;t0+r) dr and ∂τ2Jg∗=g(x,t0+τ)+∫0τ∂σ2Hg(x,τ−r;t0+r) dr. At each fixed τ, [F5] permits two spatial derivatives through the fixed r-integral, hence ∂τ2Jg∗−c2ΔxJg∗=g(x,t0+τ)=mg(x,0,t0+τ). The positive-radius interval was arbitrary; no time derivative of the source is needed for these two endpoint differentiations.

3.2step 2.1step 2.2F2algebra

The initial data. At t=t0 one has u~(x,t0)=∂sHa(x,0)+Hb(x,0)+0=a(x)+0+0, since ∂sHa(x,0)=ma(x,0,v0)=a(x) and Hb(x,0)=0 by step 2.1, while u~s(x,t0)=0 by step 2.2. Likewise ∂tu~(x,t0)=∂s2Ha(x,0)+∂sHb(x,0)+∂tu~s(x,t0)=0+b(x)+0: here ∂s2Ha(x,0)=c2ΔHa(x,0)=0 and ∂sHb(x,0)=b(x) by step 2.1, and ∂tu~s(x,t0)=0 by the product rule [F2] applied to θ2∫01A(x,θ,z) dz at θ=0 in step 2.2. This proves the initial-data clause of (a).

4.1step 2.1step 3.1step 2.2F2F5F11algebra

The wave equation on the whole neighbourhood. Let H~ denote the C∞ extension of h to R3×J and let u~=uh+u~s be the extension of step 2.2, and put R(x,t):=∂t2u~−c2Δu~−c2H~(x,t) on R3×(t0−δ,T+δ); R is continuous there by step 2.2 and [F2]. For θ>0, [F5] gives Δus=c2∫t0tΔxH(x,t−v;v) dv and step 3.1 with g=h and Jg∗=us/c2 gives ∂t2us=c2h+c2Δus on R3×(t0,T+δ); the homogeneous part satisfies ∂t2uh=c2Δuh on all of R3×R by step 2.1 and [F2], so R=0 on R3×(t0,T+δ). For θ<0 put μ:=−θ>0 and h^(x,v):=h(x,2t0−v), an extension-sense smooth datum on an interval around t0, with family m^(x,s,v):=m(x,s,2t0−v); the substitution σ=μz, z∈[0,1], together with the evenness of step 1.2 gives u~s(x,t0−μ)=c2∫0μσ m^(x,cσ,t0+μ−σ) dσ, so step 3.1 applied to h^ gives ∂t2u~s−c2Δu~s=c2m^(x,0,t0+μ)=c2h(x,t0−μ) on R3×(t0−δ,t0), while the homogeneous part satisfies the homogeneous equation there by step 2.1; hence R=0 on R3×(t0−δ,t0). The two open pieces cover every time except t0; continuity gives R(x,t0)=0 as well, so ∂t2u~=c2Δu~+c2H~, that is Wu~=H~, on the open neighbourhood R3×(t0−δ,T+δ); restricting gives Wu=h on R3×(t0,T) and indeed on the open neighbourhood of the closed time interval on which the extension of h is defined.

5.1step 4.1step 3.2F2F11F12

Uniqueness. Let v be of class C2 on R3×[t0,T] in the extension sense with Wv=h on R3×(t0,T), v(⋅,t0)=a and ∂tv(⋅,t0)=b, and form the function v~ equal to v for t≥t0 and to u for t≤t0: the pieces agree in value and in all derivatives through order two at t=t0: their spatial derivatives are those of a, their time derivatives equal b, and their mixed derivatives equal ∂ib; the second time derivative there being ∂t2v(⋅,t0)=∂t2u(⋅,t0)=c2Δa+c2h(⋅,t0) by the equation of step 4.1 and the data, and each second partial derivative is continuous on its side and has the stated common value, so v~ is C2 on a neighbourhood of the closed slab; then w:=u−v~ is C2 on that neighbourhood, satisfies □cw=0 on each of the open half-slabs t>t0 (where both u and v~ solve Wu=h) and t<t0 (where the two pieces coincide), and since □cw is continuous it vanishes at t=t0 as well, so □cw=0 on R3×(t0−δ,T) for some δ>0; no equation for an arbitrary extension of v beyond T is used; also w(⋅,t0)=0 and ∂tw(⋅,t0)=0 on all of R3. Fix (x∗,t∗) with t0<t∗<T and apply [F12] in the translated time coordinates τ:=t−t0 to the pair (w,0) on the closed backward cone with vertex (x∗,t∗): the vertex time is t∗−t0>0, both functions are C2 on a neighbourhood of the closed cone (contained in the neighbourhood of the closed slab on which w is defined), the sources agree on the cone, and the Cauchy data agree on the base ball B‾c(t∗−t0)(x∗); hence w=0 on the cone, so u(x∗,t∗)=v~(x∗,t∗)=v(x∗,t∗). Since (x∗,t∗) is arbitrary in R3×(t0,T), this gives u=v on the open slab. The initial data already give equality at t0, and continuity at T gives equality there by taking t↑T at each fixed x. Thus u=v on the whole closed slab, which is clause (b).

5.2step 4.1step 3.2F11F12

Domain of dependence. Let a~,b~∈C∞(R3), let h~ be of class C∞ on R3×[t0,T] in the extension sense, and let u~ be the solution produced by the construction of steps 2.2 and 4.1 applied to (a~,b~,h~); by those steps u~ is C∞ on R3×[t0,T] in the extension sense, satisfies Wu~=h~ on an open neighbourhood of the closed slab and has data a~,b~ at t0. Suppose a~=a and b~=b on the closed ball B‾c(t∗−t0)(x∗) and h~=h on the closed cone K(x∗,t∗) of [F11]. If t∗=t0, the base ball is {x∗} and the initial values give u(x∗,t0)=a(x∗)=a~(x∗)=u~(x∗,t0). Now assume t∗>t0. Then w:=u−u~ is C2 on a neighbourhood of the closed slab with □cw=c2(h−h~) on each open half-slab, hence on the whole neighbourhood because both sides are continuous, it vanishes together with its time derivative at t0 on the base ball, and h−h~=0 on the cone; applying [F12] in translated time coordinates to the pair (w,0) therefore gives w=0 on the closed backward cone, and in particular u(x∗,t∗)=u~(x∗,t∗). This is clause (c).

6.1step 5.2F8F10F11algebra

Compact support. Assume that a vanishes off a compact Ka⊆R3, that b vanishes off a compact Kb, that h(⋅,v) vanishes off a fixed compact Kh for every v∈[t0,T], and that Ka∪Kb∪Kh⊆B‾ρ(0) for some ρ>0, which exists because every compact subset of R3 is bounded by [F8]. Fix t∈[t0,T] and x with ∣x∣>ρ+c(t−t0) and compare u with the solution u~ of the construction for the data a~=b~=0, h~=0, namely u~=0. Every y∈B‾c(t−t0)(x) satisfies ∣y∣≥∣x∣−∣y−x∣≥∣x∣−c(t−t0)>ρ by the reverse triangle inequality [F10], so y∉Ka∪Kb and a(y)=b(y)=0=a~(y)=b~(y); similarly every (y,v)∈K(x,t) satisfies ∣y∣≥∣x∣−∣y−x∣≥∣x∣−c(t−v)≥∣x∣−c(t−t0)>ρ, so y∉Kh and h(y,v)=0=h~(y,v). The hypotheses of clause (c), proved in step 5.2, are therefore met at the vertex (x,t) and give u(x,t)=u~(x,t)=0. This is clause (d).

7.1step 2.2step 4.1step 3.2step 5.1step 5.2step 6.1F1∎

Conclusion. Steps 2.2 and 4.1 show that u is of class C∞ on R3×[t0,T] in the extension sense and that Wu=h on R3×(t0,T), indeed on the open neighbourhood of the closed time interval on which the extension of h is defined; step 3.2 gives u(⋅,t0)=a and ∂tu(⋅,t0)=b, completing clause (a); clause (b) is step 5.1, clause (c) is step 5.2 and clause (d) is step 6.1. The argument assumed no boundary condition on a finite spatial domain, no finite-total-energy hypothesis and no spatial decay or compact support of the data; only local bounds on compact parameter sets were used.

5 · Examples, experiments and counterexamples

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