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How statement and proof provenance work

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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Calibration, proper losses, and surrogate classification

1 · Prerequisites

2 · Logical flowchart

3 · Definitions, theorems and proofs

DefinitionDefinition: Literature-sourcedProof: Not applicableOpen item page →

Strictly proper scoring rules on a finite label set

Definition

For an integer K≥2, let the label set be Y={1,…,K} and let ΔK={q∈[0,1]K:∑j=1Kqj=1}. A finite-label score loss is a function S:ΔK×Y→[0,+∞] whose section q↦S(q,j) is Borel measurable for every label j. If the true label distribution is p∈ΔK and the reported forecast is q∈ΔK, its expected score loss is Sˉ(p,q)=∑j=1KpjS(q,j), where a term with pj=0 contributes zero even when S(q,j)=+∞. The loss is proper if Sˉ(p,p)≤Sˉ(p,q) for every p,q∈ΔK, and strictly proper if it is proper and equality implies q=p. The logarithmic loss is Slog⁡(q,j)=−log⁡qj, with −log⁡0=+∞, where log⁡ is the natural logarithm; the Brier loss is SB(q,j)=∑i=1K(qi−1{i=j})2.

Definition references

Loss functions and risk: a loss is nonnegative and measurable in its action for each fixed parameter; no measurability on the parameter space is required, and its risk is the corresponding extended nonnegative integral.

The natural logarithm as the inverse of the exponential function: log⁡ is the inverse of the exponential function on positive reals.

The Borel sigma-algebra of a topological space: Borel subsets are the sets in the sigma-algebra generated by the open subsets of a topological space.

Wikipedia, Scoring rule: Definitions and Proper scoring rules specify forecasts, expected score, loss orientation, properness, and strictness; Categorical variables gives the finite-label logarithmic and Brier examples. The measurable extended nonnegative-loss conventions are stated explicitly here; the logarithmic reward example is negated.

LemmaStatement: AI-adaptedProof: AI-generatedjudge pass (gpt-6-luna)Open item page →

Jensen's inequality for pairs of simplex-valued forecasts

Statement

For an integer K≥2, let ΔK={p∈[0,1]K:∑j=1Kpj=1}⊂RK with its subspace Borel sigma-algebra, and let C=ΔK×ΔK⊂R2K with its subspace Borel sigma-algebra. Let (Ω,F,P) be a probability space, let Z=(U,V):Ω→C be measurable, and let ψ:C→R be continuous and jointly convex, meaning ψ(λz+(1−λ)w)≤λψ(z)+(1−λ)ψ(w) for all z,w∈C and λ∈[0,1]. Define EZ coordinatewise. Then EZ=(EU,EV)∈C and ψ(EU,EV)≤E[ψ(U,V)].

Statement references

Durrett, Theorem 1.6.2: scalar Jensen inequality for an integrable random variable.

Vaicenavicius et al., supplementary Theorem 2: applies convexity to the pair of conditional mean forecasts in each fixed bin.

Facts & Assumptions

Given: A probability space, a measurable C-valued random vector Z=(U,V), and a continuous jointly convex function ψ:C→R.

[F2]

A continuous map from a compact metric space to a metric space is uniformly continuous. Heine-Cantor: a continuous map from a compact metric space to any metric space is uniformly continuous

[F3]

Probability is total mass one, expectation is integration, and the integral of a nonnegative simple function is the finite weighted sum of its values. Probability measures and probability spaces Expectation of a nonnegative or integrable random variable The integral of a nonnegative simple function

[F4]

A measurable sequence converging almost everywhere under one integrable majorant has convergent integrals. Dominated convergence

[F5]

A measurable map is one whose preimages of measurable sets are measurable. A measurable function between measurable spaces

Proof

1.1F1F3givenalgebra

If Z has finite range z1,…,zm∈C with probabilities p1,…,pm, then each coordinate of Z is a nonnegative simple function, so [F3] gives EZ=∑ipizi, a convex combination in C. The real finite-range random variable ψ(Z) is integrable. Its positive and negative parts are nonnegative simple functions, so applying [F3] to each and subtracting their finite expectations gives E[ψ(Z)]=∑ipiψ(zi). Joint convexity now proves ψ(EZ)≤E[ψ(Z)] by induction on the number of positive weights: combine the first m−1 points into their normalized convex average, apply the induction hypothesis, then apply two-point convexity with weights 1−pm and pm.

1.2F1F5construct

For n≥1 set Dn={(m1/n,…,mK/n):mi∈N0,∑imi=n}⊆ΔK. This is a finite set with a canonical lexicographic order. For p∈ΔK, put mi=⌊npi⌋ for i<K and mK=n−∑i<Kmi. Then mK≥0, the coordinates sum to n, and the first K−1 coordinate errors are below 1/n while the last is below (K−1)/n. Thus some q∈Dn has ∥p−q∥2<K(K−1)/n. The product grid Dn×Dn therefore approximates every point of C within 2K/n. List its finitely many points canonically as cn,1,…,cn,mn. Their relative open balls of radius 2K/n cover C, and the cells obtained by removing all earlier balls from each ball are Borel in the stated subspace sigma-algebra. Assign each point to its first covering ball; replacing Z on each cell by its center defines a measurable finite-range Zn∈C with ∥Zn−Z∥2<2K/n everywhere. The grid, order and assignment are explicit, so no choice axiom is used.

2.1F1F3F4step 1.1

Step 1.1 gives EZn∈C for every n. Each coordinate of Zn and Z is bounded by 1, so dominated convergence [F4] gives EZn→EZ coordinatewise; because the coordinate constraints defining C are closed, EZ∈C.

2.2F1F2F4step 1.2

By [F2], ψ is uniformly continuous on C. Choose δ>0 so that points within distance δ have ψ-values within 1, and then choose n with 2K/n<δ. The finite grid in step 1.2 is a δ-net, so ∣ψ(z)∣≤1+max⁡c∈Dn×Dn∣ψ(c)∣ for every z∈C. This is a common finite bound. Since ∥Zn−Z∥2→0, continuity gives ψ(Zn)→ψ(Z) pointwise; [F4] then gives Eψ(Zn)→Eψ(Z).

3.1F1step 1.1step 2.1step 2.2∎

Applying step 1.1 to each Zn gives ψ(EZn)≤Eψ(Zn). By continuity of ψ and steps 2.1 and 2.2, taking limits proves ψ(EZ)≤Eψ(Z).

LemmaStatement: AI-adaptedProof: AI-generatedjudge pass (gpt-6-luna)Open item page →

The negative reciprocal-power function is convex

Statement

For every real s≥1, the function φs:[0,∞)→R defined by φs(t)=−t1/s, with 01/s=0, is convex.

Statement references

Real powers for positive bases, with the zero-base positive-exponent convention: defines positive-base real powers and the zero-power convention used here.

Facts & Assumptions

Given: A real number s≥1 and the stated real-power convention.

[F1]

For t>0 and real α, tα is continuous and differentiable with derivative αtα−1. Continuity and derivatives of positive-base real powers

[F2]

A twice differentiable function on an open interval with nonnegative second derivative is convex there. A twice-differentiable function on an open interval is convex if and only if its second derivative is nonnegative

[F3]

For positive real t and α>0, tα=exp⁡(αlog⁡t), and 0α=0. Real powers for positive bases, with the zero-base positive-exponent convention

Proof

1.1F1F2givenalgebra

Put α=1/s, so 0<α≤1. If α=1, then φs(t)=−t is affine and hence convex. If 0<α<1, on (0,∞) the derivative formula [F1] gives φs′′(t)=α(1−α)tα−2≥0. Thus [F2] makes φs convex on (0,∞).

2.1F3F4F5step 1.1algebra∎

In the second case tα→0 as t↓0. Indeed, for ε>0 put δ=ε1/α. The derivative αtα−1 is positive on (0,∞), so [F5] makes t↦tα increasing there; if 0<t<δ, then tα<δα=ε by [F4]. Thus φs is continuous at zero with the stated value. For a,b≥0 and 0≤λ≤1, apply the convexity inequality on (0,∞) to a+ε and b+ε, then let ε↓0; continuity at zero and on positive inputs gives the inequality on [0,∞). In the affine case the same inequality holds directly.

Source notes

This elementary lemma is derived locally from the published positive-real-power derivative and second-derivative convexity suppliers cited in its facts; no external source claim is imported.

DefinitionDefinition: Literature-sourcedProof: Not applicablejudge pass (gpt-6-luna)Open item page →

Probability calibration and calibration error

Definition

Let K≥2, let Y be a random variable into the finite label set {1,…,K} with its full power-set sigma-algebra on a probability space (Ω,F,P), and let G=(G1,…,GK):Ω→ΔK be a measurable forecast, where ΔK={p∈[0,1]K:∑jpj=1}. The forecast is fully reliable if for every label j and every Borel set B⊆ΔK, P(Y=j, G∈B)=E[1{G∈B}Gj]. It is classwise calibrated if for every j and every Borel set B⊆[0,1], P(Y=j, Gj∈B)=E[1{Gj∈B}Gj]. For the top-confidence calibration condition, define C=max⁡jGj and Y^=min⁡{j:Gj=C}, so ties go to the smallest label. The forecast is top-confidence calibrated if for every Borel set B⊆[0,1], P(Y=Y^, C∈B)=E[1{C∈B}C]. A measurable function r:ΔK→ΔK is a calibration function for G if for every j and every Borel set B⊆ΔK, P(Y=j, G∈B)=E[1{G∈B}rj(G)]. When such a function is supplied and d:ΔK×ΔK→[0,+∞) is measurable, the expected calibration error with discrepancy d is ηd=E[d(r(G),G)].

Definition references

Supervised prediction problems: fixes the measurable instance and label spaces, the joint law, and measurable predictors.

Conditional expectation given a sigma algebra: the event-integral identities in this definition are the conditional-expectation characterization when the indicated versions exist.

Probability measures and probability spaces: a probability law is a measure of total mass one.

The Borel sigma-algebra of a topological space: Borel subsets are generated by the open sets of the simplex's Euclidean subspace topology.

Vaicenavicius et al., full paper PDF: reliability, calibration functions, and expected miscalibration are defined in Sections 2, 3.1, and 3.2.

LemmaStatement: AI-adaptedProof: AI-generatedjudge pass (gpt-6-luna)Open item page →

A finite label has a conditional probability function

Statement

Assume AC. Let a supervised prediction problem have a measurable instance space (X,ΣX), finite label set Y={y1,…,yK} with distinct labels, the full power-set sigma-algebra on Y, and K≥2, and joint probability law P on X×Y; let X and Y be its coordinate random variables and let G={X−1(A):A∈ΣX}, the sigma-algebra generated by X. There is a measurable function η=(η1,…,ηK):X→ΔK, where ΔK={p∈[0,1]K:∑jpj=1}⊂RK has its subspace Borel sigma-algebra, such that for every label index j and A∈ΣX, P(X∈A, Y=yj)=E[ηj(X)1{X∈A}].

Statement references

Supervised prediction problems: supplies measurable instance and label spaces, the joint law, and the coordinate random variables; here the finite label sigma-algebra is explicitly the full power set.

Conditional expectation given a sigma algebra: a conditional-expectation version is measurable with respect to the conditioning sigma-algebra and has the same integrals on its events.

Conditional expectation exists by radon nikodym: under AC, an integrable real random variable has a conditional-expectation version given any sub-sigma-algebra.

Durrett, Section 4.1: defines conditional expectation by event integrals and constructs it from Radon–Nikodym derivatives.

Facts & Assumptions

Given: AC; a finite-label supervised prediction problem with joint law P and full power-set label sigma-algebra; the instance coordinate X; and the sub-sigma-algebra G={X−1(A):A∈ΣX}.

[A1]

Assume AC, the choice principle used by the published conditional-expectation existence theorem. The Axiom of Choice

[F1]

Each indicator 1{Y=yj} is integrable because it is bounded by 1 on a probability space; under AC, its conditional-expectation version exists and has the defining event integrals. Probability measures and probability spaces Conditional expectation given a sigma algebra Conditional expectation exists by radon nikodym

[F2]

Conditional expectation preserves order and constants almost surely. Basic algebra and order properties of conditional expectation

[F6]

A conditional-expectation version is unique almost surely. Conditional expectation is unique almost surely

[F3]

Integrable functions equal almost surely have identical integrals over every measurable event. Two integrable functions are equal almost everywhere exactly when all of their indefinite integrals agree

[F4]

Measurability is determined by preimages of measurable sets. A measurable function between measurable spaces

[F5]

The family of all inverse images X−1(A) is a sigma-algebra because inverse images preserve complements and countable unions; by definition it is σ(X).

[F7]

Finite sums, products by indicators, and level sets of measurable real functions are measurable. Closure properties of measurable functions used by the integral A measurable function between measurable spaces

Proof

1.1A1F1F2F3F6F7given

For each j, choose a version Zj of E[1{Y=yj}∣G], which exists by [A1,F1]. Order preservation and preservation of constants give 0≤Zj≤1 almost surely by [F2]. Set Nj={Zj<0}∪{Zj>1}∈G and define Zj′ to equal Zj on Njc and 0 on Nj. Since both pieces are G-measurable, Zj′ is G-measurable; it takes values in [0,1] everywhere and equals Zj almost surely. By [F3], it has the same event integrals, so it remains a conditional-expectation version. Linearity shows that ∑jZj is a version of the conditional expectation of ∑j1{Y=yj}=1; the constant 1 is another version, so [F6] gives ∑jZj=1 almost surely. Hence ∑jZj′=1 almost surely.

2.1A1F4F5F7step 1.1chooseconstruct

For each label j and rational q∈Q∩[0,1], the event {Zj′<q}∈G equals X−1(Aj,q) for some Aj,q∈ΣX by [F5]. AC permits choosing these sets for the countable family of label-rational pairs. Define η~j(x)=inf⁡({q∈Q∩[0,1]:x∈Aj,q}∪{1}). For 0<t≤1, {x:η~j(x)<t}=⋃q<tAj,q; for t≤0 this sublevel set is empty and for t>1 it is all of X. Thus each η~j is measurable and takes values in [0,1] by [F4,F7].

3.1F7step 1.1step 2.1construct

For every j and ω, the rationals q satisfying X(ω)∈Aj,q are exactly those with Zj′(ω)<q. Their infimum is Zj′(ω) when this value is below 1; at value 1 the rational set is empty and the filler 1 gives the same value. Thus η~j(X)=Zj′ everywhere. The measurable set D={x:∑jη~j(x)=1} is well-defined by [F7]. Define η(x)=(η~1(x),…,η~K(x)) on D and η(x)=(1,0,…,0) off D. Its coordinates are measurable. The inverse image of an open rational box in RK is a finite intersection of coordinate preimages, and these boxes form a countable basis, so η is Borel measurable into RK and hence measurable into the subspace ΔK. It takes values in ΔK everywhere, and ηj(X)=Zj′ almost surely because ∑jZj′=1 almost surely.

4.1F1F3step 1.1step 3.1given∎

For every A∈ΣX and label index j, the event {X∈A} belongs to G. The conditional-expectation identity [F1] and almost-sure equality [F3] therefore give P(X∈A,Y=yj)=E[1{X∈A}Zj]=E[1{X∈A}Zj′]=E[1{X∈A}ηj(X)]. This is the claimed event identity for every class.

TheoremStatement: Literature-sourcedProof: AI-adaptedOpen item page →

Log and Brier losses are strictly proper

Statement

For every K≥2 and p,q∈ΔK, the logarithmic and Brier losses in the definition of finite-label score loss satisfy Sˉ(p,p)≤Sˉ(p,q), with equality only when q=p. The expected logarithmic loss at the truthful forecast is finite, including when some coordinates of p vanish.

Statement references

Strictly proper scoring rules on a finite label set: defines the simplex, expected loss, logarithmic loss, Brier loss, and propriety conventions.

The natural logarithm as the inverse of the exponential function: fixes the natural logarithm used in the logarithmic score.

Facts & Assumptions

Given: An integer K≥2 and p,q∈ΔK.

[F1]

For pj=0, the expected-score term is zero even if the corresponding score is infinite; the logarithmic and Brier losses are the two functions in the definition. Strictly proper scoring rules on a finite label set

[F2]

For t>0, log⁡t=∫1tdu/u and log⁡1=0. The natural logarithm has derivative 1/x and equals the integral from 1 to x of 1/t

[F3]

The expected score is the finite sum Sˉ(p,q)=∑jpjS(q,j). Strictly proper scoring rules on a finite label set

Proof

1.1F2algebra

If t>1, then 1/u<1 for 1<u≤t, so [F2] gives log⁡t<t−1. If 0<t<1, then 1/u>1 for t≤u<1, so log⁡t=−∫t1du/u<−(1−t)=t−1. At t=1 equality holds. Therefore −log⁡t≥1−t for every t>0, with equality exactly at t=1.

1.2F1F3algebra

If pj>0 and qj=0 for some j, then [F1] gives Sˉlog⁡(p,q)=+∞, while Sˉlog⁡(p,p)=−∑j:pj>0pjlog⁡pj<∞ because this is a finite sum of finite terms. Thus propriety is strict in this case.

2.1F1F3step 1.1algebra

Otherwise qj>0 for every j with pj>0. The truthful risk is finite, and cancellation on the support of p gives Sˉlog⁡(p,q)−Sˉlog⁡(p,p)=∑j:pj>0pjlog⁡pjqj. Applying step 1.1 to t=qj/pj yields ∑j:pj>0pjlog⁡pjqj≥1−∑j:pj>0qj≥0. If the displayed difference is zero, both nonnegative gaps in this chain are zero. Equality in step 1.1 then forces qj/pj=1 on the support of p, and the second gap forces q to have no mass outside that support. Hence q=p. This proves strict propriety for the logarithmic loss.

3.1F1F3algebra∎

Expanding the Brier loss and using ∑jpj=1 gives SˉB(p,q)=∑iqi2−2∑ipiqi+1, whereas SˉB(p,p)=1−∑ipi2. Subtraction yields SˉB(p,q)−SˉB(p,p)=∑i(qi−pi)2≥0, with equality exactly when every qi=pi. Thus the Brier loss is strictly proper as well.

Source notes

The distinct encyclopedia treatment gives the scoring-rule conventions and categorical formulas (with the logarithmic reward negated). Strictness is proved locally from the declared logarithm supplier, rather than imported from a representation theorem. The displayed finite-sum arguments above separately verify the boundary cases pj=0 and qj=0 under this library's nonnegative-loss convention.

CorollaryStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-6-luna)Open item page →

Conditioning on a feature induces a calibrated forecast

Statement

Assume AC. Let a finite-label supervised prediction problem have measurable instance space (X,ΣX) and finite labels Y={y1,…,yK} with the full power-set sigma-algebra, where K≥2. Identify label yj with its index j when applying numbered-label calibration, so forecast coordinate j always represents the event Y=yj. For every measurable feature T:X→(Z,ΣZ), there is a measurable ηT:Z→ΔK such that G=ηT(T(X)) is a conditional class-probability forecast given T(X) and is fully reliable. This includes the identity feature and a constant feature.

Statement references

A finite label has a conditional probability function: supplies the measurable simplex-valued conditional probability function and its event identities under AC.

Probability calibration and calibration error: full reliability is the event-integral identity for every Borel subset of the forecast simplex.

Facts & Assumptions

Given: AC, a finite-label supervised prediction problem with coordinate random variables X,Y, and a measurable feature T:X→(Z,ΣZ).

[A1]

Assume AC, as used in the finite-label conditional-probability lemma. The Axiom of Choice

[F1]

There is a measurable η:X→ΔK such that P(X∈A,Y=yj)=E[ηj(X)1{X∈A}] for every measurable A and label j. A finite label has a conditional probability function

[F2]

Full reliability means P(Y=yj,G∈B)=E[1{G∈B}Gj] for every Borel B⊆ΔK and each label j. Probability calibration and calibration error

[F3]

A measurable map has measurable preimages of measurable sets. A measurable function between measurable spaces

Proof

1.1A1F1F2F3given

Apply [F1] to the joint law of (T(X),Y) on Z×Y, which is a measurable joint probability law because T is measurable. Equip this law with simplex-valued constant predictors and the zero loss to obtain a supervised prediction problem; [F1] only uses its joint law. It supplies a measurable ηT:Z→ΔK with P(T(X)∈A,Y=yj)=E[ηT,j(T(X))1{T(X)∈A}] for every A∈ΣZ. Set G=ηT(T(X)). For a Borel set B⊆ΔK, [F3] makes A=ηT−1(B) measurable; the event identity then gives P(Y=yj,G∈B)=E[Gj1{G∈B}]. This is precisely the reliability identity [F2].

2.1step 1.1∎

Since j and B were arbitrary, all label and Borel-event identities hold, so G is fully reliable.

Source notes

Vaicenavicius et al. Proposition 1 states the reliability of a conditional class-probability forecast. The event-integral proof above makes the version and measurable-event hypotheses explicit.

TheoremStatement: Literature-sourcedProof: AI-adaptedOpen item page →

The posterior forecast minimizes strictly proper scoring risk

Statement

Assume AC. Let X and a finite label Y∈{1,…,K} with the full power-set sigma-algebra, K≥2, have a joint probability law on standard-Borel spaces. For a proper finite-label score loss S, a measurable posterior forecast G(x)=P(Y∈⋅∣X=x) minimizes the expected score loss among all measurable forecasts. If S is strictly proper and the posterior forecast has finite expected score loss, equality of risk for another forecast q(X) implies q(X)=G(X) almost surely.

Statement references

Strictly proper scoring rules on a finite label set: defines a proper or strictly proper nonnegative score loss on the finite label simplex.

Standard Borel spaces: standard-Borel spaces are measurably isomorphic to Polish spaces.

A posterior-risk minimizer minimizes prior risk: a measurable posterior-risk minimizer minimizes prior-integrated risk.

Disintegration of a joint law on standard borel spaces: supplies a measurable posterior kernel for the standard-Borel joint law.

Facts & Assumptions

Given: AC, a standard-Borel feature and finite label with joint law, and a proper score loss S.

[A1]

Assume AC, as required by standard-Borel disintegration and the Bayes-risk interface. The Axiom of Choice

[F2]

Properness says that for every class distribution p, reporting p minimizes Sˉ(p,q) over forecast actions q. Strict propriety makes this minimizer unique. Strictly proper scoring rules on a finite label set

[F3]

A finite-label score loss is jointly measurable on the finite label space and forecast simplex; its expected score is the nonnegative risk of the associated decision problem. Strictly proper scoring rules on a finite label set Loss functions and risk

[F4]

Conditional risk integrals against the posterior kernel are measurable functions of the feature. Measurability of integration against a kernel

[F5]

A nonnegative measurable function with integral zero is zero almost surely. A nonnegative measurable function has integral 0 exactly when it vanishes almost everywhere

[F6]

A measurable posterior-risk minimizing rule minimizes prior-integrated risk among deterministic and randomized decision rules under the stated standard-Borel model hypotheses. A posterior-risk minimizer minimizes prior risk

[F7]

A nonnegative measurable function with finite integral is finite almost everywhere. A nonnegative measurable function with finite integral is finite almost everywhere

[F8]

The nonnegative integral is additive for nonnegative measurable functions, and its integral over a measurable null set is zero. Additivity of the nonnegative Lebesgue integral A nonnegative integral over a null set vanishes

[F9]

The Lebesgue integral is linear on integrable real functions. The Lebesgue integral is linear on L1(μ)

[F10]

Defined arithmetic operations on measurable extended-real functions preserve measurability. Arithmetic and lattice operations preserve measurability whenever they are defined

Proof

1.1A1F1F2F4F6

By [F1], choose a measurable posterior probability kernel Πx on the finite label set; identify it with the measurable vector G(x)=(Πx(1),…,Πx(K))∈ΔK. For each x, the posterior expected score of reporting q is Sˉ(G(x),q), which is minimized at q=G(x) by [F2]. The posterior risk of this rule is measurable by [F4], so the rule meets the measurable-minimizer hypothesis in [F6].

1.2F1F3F6givenconstruct

To apply the Bayes-risk interface to the original joint law, let πj=P(Y=j). For πj>0, define Kj(A)=P(X∈A,Y=j)/πj on feature events A; for πj=0, set Kj=PX. Each Kj is a probability measure, and the finite map j↦Kj is a probability kernel. The joint prior-data law built from prior (πj) and kernel Kj agrees with the original joint law because for every A and j its (A,j) mass is P(X∈A,Y=j), including zero-prior labels. Consequently the Bayes-risk theorem [F6] states that the posterior rule G minimizes the original expected score risk over all measurable randomized forecasts, hence over deterministic forecasts.

2.1F1F2F3F4F5F7F8F9F10givenalgebra∎

Now suppose S is strictly proper and another measurable forecast q has the same risk as G, whose risk is finite by hypothesis. Write Rq(x)=Sˉ(G(x),q(x)) and RG(x)=Sˉ(G(x),G(x)). They are nonnegative measurable functions by [F3,F4], and posterior disintegration gives their integrals as the two risks, so both integrals are finite. By [F7], the measurable set N={Rq=+∞}∪{RG=+∞} is null. Set R~q=Rq and R~G=RG off N, and set both to zero on N; these modified functions are measurable by [F10]. By [F8], the changes preserve their integrals: each original function is the sum of its restriction to Nc and its restriction to the null set N. The functions R~q,R~G are finite and integrable. By propriety, D=R~q−R~G is nonnegative, and it is measurable by [F10]; [F9] gives ED=ER~q−ER~G=0. Thus [F5] makes D=0 almost surely. Off N this is equality of the finite posterior risks, so strict propriety in [F2] gives q(X)=G(X) almost surely.

Source notes

The local definition supplies pointwise propriety; this proof integrates that defining inequality against the posterior law and does not import any scoring-rule representation theorem. The standard-Borel and Bayes-risk suppliers provide the measurable posterior and its prior-risk interpretation. Finite posterior risk is stated explicitly because equality of two infinite extended risks alone cannot yield uniqueness.

DefinitionDefinition: Literature-sourcedProof: Not applicablejudge pass (gpt-6-luna)Open item page →

Binary surrogate classification risk

Definition

Let Y∈{−1,+1} be the label in a supervised prediction problem with the full power-set sigma-algebra on this binary label set, and choose the finite-label conditional probability function ordered as (−1,+1); write η(x)=η+1(x). Let Φ:R→[0,∞) be finite, convex and nondecreasing. It is continuous on R; extend it to R‾=R∪{−∞,+∞} by its one-sided monotone limits, which may equal +∞. The resulting extended function is Borel measurable. For u∈R‾ define the conditional margin risk LΦ(x,u)=η(x)Φ(−u)+(1−η(x))Φ(u), using 0⋅(+∞)=0 at endpoints. A measurable extended-real conditional minimizer is a measurable hΦ∗:X→R‾ satisfying LΦ(x,hΦ∗(x))≤LΦ(x,u) for every x and every u∈R‾. For a measurable real-valued score h, its margin loss is ℓΦ(h(x),y)=Φ(−yh(x)), its surrogate risk is LΦ(h)=E[Φ(−Yh(X))], and its conditional-minimum risk is LΦ∗=E[LΦ(X,hΦ∗(X))]. Under the zero-score-is-error convention, its classification risk is R01(h)=P(Yh(X)≤0), and the Bayes classification risk is R01∗=E[min⁡{η(X),1−η(X)}]. Write h∗(x)=η(x)−12 for the centered conditional class probability.

Definition references

Supervised prediction problems: fixes the measurable instance and label spaces and joint law.

A finite label has a conditional probability function: the chosen η is a measurable version whose event integrals give the conditional label probabilities.

Population and empirical risk: population risk is an extended nonnegative integral of the loss under the joint law.

Loss functions and risk: fixes the loss and risk conventions used for the margin loss.

A measurable function between measurable spaces: a function is measurable when preimages of measurable sets are measurable.

A convex function on an open convex set is continuous: every finite convex function on the open convex set R is continuous.

TheoremStatement: Literature-sourcedProof: AI-adaptedOpen item page →

Fixed-bin calibration limits underestimate for jointly convex discrepancies; refining bins can be consistent

Statement

Let Y be a random variable into {1,…,K} with its full power-set sigma-algebra, K≥2, and let G∈ΔK be a random forecast with measurable calibration function r:ΔK→ΔK. Let d:ΔK×ΔK→[0,∞) be continuous and satisfy d(p,p)=0. For a finite data-independent Borel partition P of ΔK, draw an iid sequence (Gi,Yi) from the joint law of (G,Y), let Vi=eYi be the corresponding standard basis vector, and form the empirical estimator E^n,P=∑B∈PNBn d(VˉB,GˉB), where NB=#{i≤n:Gi∈B} and, when NB>0, VˉB and GˉB are the sample averages in bin B; when NB=0, set both to any fixed q0∈ΔK. Define EP=∑B∈P:P(G∈B)>0P(G∈B) d ⁣(E[r(G)∣G∈B],E[G∣G∈B]). For each fixed P, E^n,P→EP almost surely. If d is additionally jointly convex, then EP≤E[d(r(G),G)]. Without requiring convexity, if Pm is a sequence of finite data-independent Borel partitions whose mesh max⁡B∈Pmdiam⁡2(B) tends to zero, where diam⁡2(B)=sup⁡u,v∈B∥u−v∥2, and r is Lipschitz with respect to the Euclidean metric on ΔK, then EPm→E[d(r(G),G)]. Thus the iterated limit lim⁡m→∞lim⁡n→∞E^n,Pm equals the expected calibration error almost surely; no diagonal rate is asserted.

Statement references

Probability calibration and calibration error: defines a calibration function, the event-integral identity, and expected calibration error.

The Borel sigma-algebra of a topological space: Borel sets are generated by the open sets in the forecast simplex topology.

Kolmogorov iid l1 strong law: gives almost-sure convergence of averages of iid integrable real random variables.

Jensen's inequality for pairs of simplex-valued forecasts: gives Jensen's inequality for the pair of mean label and forecast vectors in each bin.

Facts & Assumptions

Given: A finite-label random forecast with calibration function r, a continuous discrepancy d (additionally jointly convex for the underestimation conclusion), and the iid sample and finite partition specified above.

[F1]

For every label j and Borel bin B, E[1{G∈B}1{Y=j}]=E[1{G∈B}rj(G)]. Probability calibration and calibration error

[F2]

A measurable simplex-pair random vector and continuous jointly convex function satisfy ψ(EU,EV)≤Eψ(U,V), and the mean pair lies in ΔK×ΔK. Jensen's inequality for pairs of simplex-valued forecasts

[F3]

Measurable coordinate functions of independent observations remain independent; applying the same measurable map to identically distributed observations gives identically distributed outputs by the preimage identity. Averages of iid integrable real variables converge almost surely to their means. Identical distribution and IID families Measurable coordinatewise functions preserve independence Kolmogorov iid l1 strong law

[F5]

The Euclidean distance d2(u,v)=∥u−v∥2 is a metric on RK; its formula gives ∥λz∥2=∣λ∣∥z∥2. Rn as the set of functions n→R, and d1, d2, d∞ are metrics on it

Proof

1.1F1F3givenalgebra

Fix a partition P. For every bin B and each coordinate, the variables 1{Gi∈B}, 1{Gi∈B}(Vi)j, and 1{Gi∈B}(Gi)j are bounded iid real variables: the same measurable coordinate map is applied to each iid pair, so the outputs have the same law by taking preimages, and their independence follows from [F3]. Their sample averages therefore converge almost surely to their expectations. On the event P(G∈B)>0, division by NB/n→P(G∈B) gives convergence of the bin means to E[V∣G∈B] and E[G∣G∈B]. On a zero-probability bin every sample has count zero almost surely. Since the partition and label set are finite, these convergences hold together almost surely; continuity of d then gives E^n,P→EP. By [F1], E[V∣G∈B]=E[r(G)∣G∈B] coordinatewise.

1.2F2F4F5givenalgebra

Let δm be the maximum Euclidean diameter of a cell of Pm. For any fixed v∈ΔK, the function ψ(u,w)=∥u−w∥2 is continuous and jointly convex: the metric triangle inequality gives continuity in (u,w), and ∥λ(u−w)+(1−λ)(u′−w′)∥2≤λ∥u−w∥2+(1−λ)∥u′−w′∥2 for 0≤λ≤1 by the triangle inequality and homogeneity in [F5]. For a positive-probability bin B, define PB(A)=P(A∩{G∈B})/P(G∈B). If G(ω)∈B, apply [F2] under PB to the simplex pair (G,G(ω)). It gives ∥E[G∣G∈B]−G(ω)∥2≤E[∥G−G(ω)∥2∣G∈B]≤δm. Apply the same argument to (r(G),r(G(ω))) to obtain ∥E[r(G)∣G∈B]−r(G(ω))∥2≤Lδm. Thus the Euclidean distance between the ordered pairs is at most 1+L2 δm≤(1+L)δm. By [F4], d is uniformly continuous on the compact product simplex, so the absolute difference between the bin value and d(r(G(ω)),G(ω)) is bounded by a modulus tending to zero with δm, uniformly over all bins and ω. Integrating over bins yields EPm→E[d(r(G),G)].

2.1F2step 1.1algebra

For the underestimation conclusion assume additionally that d is jointly convex. For each positive-probability bin define the conditional probability measure PB(A)=P(A∩{G∈B})/P(G∈B). Under PB, the pair (r(G),G) takes values in ΔK×ΔK. Apply [F2] to ψ=d and multiply by P(G∈B) to obtain P(G∈B)d ⁣(E[r(G)∣G∈B],E[G∣G∈B])≤E[1{G∈B}d(r(G),G)]. Summing over the partition proves EP≤E[d(r(G),G)].

3.1step 1.1step 1.2algebra∎

For each fixed m, step 1.1 gives the almost-sure limit in n. There are countably many m, so the intersection of these probability-one events still has probability one; step 1.2 then gives the iterated limit as stated. This order takes the sample-size limit before the partition refinement and makes no claim about a jointly chosen diagonal sequence.

Source notes

Vaicenavicius et al. Theorems 1–2 and Appendix A.2 provide the fixed-bin Jensen lower bound and the iterated refining-bin consistency route. The proof here explicitly handles empty bins, zero-mass bins, and the order of limits.

LemmaStatement: AI-adaptedProof: AI-generatedjudge pass (gpt-6-luna)Open item page →

Binary zero-one excess risk with a zero-score error convention

Statement

For a binary supervised problem with the full power-set sigma-algebra on Y∈{−1,+1}, conditional positive-label probability η, and any measurable real-valued score h, use R01(h)=P(Yh(X)≤0) and R01∗=Emin⁡{η(X),1−η(X)}. Then R01(h)−R01∗=2E ⁣[∣η(X)−12∣1{h(X)(η(X)−12)≤0}]+E ⁣[min⁡{η(X),1−η(X)}1{h(X)=0}].

Statement references

Binary surrogate classification risk: fixes η, R01, and R01∗, including the zero-score-is-error convention.

Mohri et al., Lemma 4.5, printed pp. 74–75 (PDF pp. 91–92): the source predicts +1 at zero, and its displayed equality overcounts when h(x)=0 and η(x)>1/2; the corrected zero-score-is-error identity above is proved here.

Facts & Assumptions

Given: A binary supervised problem, its conditional probability function η, and a measurable real-valued score h.

[F1]

For every measurable feature event {X∈A}, P(Y=+1,X∈A)=E[η(X)1{X∈A}]. A finite label has a conditional probability function

[F2]

R01(h) is the population risk of the indicator loss 1{yh≤0}, and R01∗=Emin⁡(η,1−η). Population and empirical risk Binary surrogate classification risk

[F3]

A measurable real-valued function has measurable preimages of Borel intervals, including its sign sets and the threshold set {η≥1/2}. A measurable function between measurable spaces

Proof

1.1F1F2F3givenalgebra

Put A−={x:h(x)≤0} and A+={x:h(x)≥0}, which are measurable by [F3]. The event {Yh(X)≤0} is the disjoint union of {Y=+1,X∈A−} and {Y=−1,X∈A+}. Applying [F1] to A− and using P(X∈A+,Y=−1)=P(X∈A+)−P(X∈A+,Y=+1) gives R01(h)=E[η(X)1A−(X)+(1−η(X))1A+(X)]. Subtracting [F2]'s Bayes-risk integrand reduces the identity to a pointwise comparison for each x.

2.1step 1.1F2algebra

Fix x and abbreviate a=η(x). If a>1/2, then on h(x)>0 the conditional risk is 1−a and the excess is zero; on h(x)<0 it is a, so the excess is 2a−1=2∣a−1/2∣; on h(x)=0 it is 1, so the excess is a=(2a−1)+(1−a). If a<1/2, the same three cases h(x)<0, h(x)>0, and h(x)=0 give excesses 0, 1−2a=2∣a−1/2∣, and 1−a=(1−2a)+a, respectively. If a=1/2, every nonzero score has excess zero and a zero score has excess 1/2. In each case the excess equals 2∣a−1/2∣1{h(x)(a−1/2)≤0}+min⁡(a,1−a)1{h(x)=0}.

3.1step 1.1step 2.1algebra

Integrating the pointwise equality in step 2.1 and using step 1.1 proves the displayed risk identity.

4.1F1F2F3step 3.1algebra∎

The right side of the identity is nonnegative, so every measurable score has risk at least R01∗. Define hB(x)=+1 when η(x)≥1/2 and hB(x)=−1 otherwise. Its two level sets are measurable by [F3]; at each x, its conditional zero-one risk is min⁡{η(x),1−η(x)}, including equality at η=1/2. Thus R01(hB)=R01∗, verifying that the stated Bayes risk is the attained infimum.

False statementConstruction: AI-adaptedVerification: AI-generatedjudge pass (gpt-6-luna)Open item page →

The unadjusted surrogate-regret bound has the wrong scale and tie convention

Statement

The following proposed implication is false. In the binary-surrogate setup, take R01(h)=P(Yh(X)≤0), so zero scores count as errors. If s≥1,c>0 and for every x, ∣η(x)−1/2∣s≤c[LΦ(x,0)−LΦ(x,hΦ∗(x))], then every measurable real-valued score h with finite surrogate risk satisfies R01(h)−R01∗≤2c[LΦ(h)−LΦ∗]1/s. Even replacing 2c by 2c1/s does not make this zero-remainder implication true under the stated zero-score-is-error convention.

Statement references

Binary surrogate classification risk: specifies the full convex nondecreasing nonnegative margin-loss setup, extended conditional minimizer, and both risks.

Facts & Assumptions

Given: The proposed implication and the zero-score-is-error convention in the statement.

[F1]

The conditional risk is LΦ(x,u)=η(x)Φ(−u)+(1−η(x))Φ(u) and R01∗=Emin⁡(η,1−η). Binary surrogate classification risk

Refutation

1.1F1constructalgebra

Give the one-point feature space its power-set sigma-algebra and take Y=+1 surely. Let Φ(t)=max⁡(0,1+t), a finite nonnegative nondecreasing convex function: each affine term is nondecreasing and their maximum satisfies the convexity inequality by bounding each affine term at a convex combination by the corresponding convex combination of the two maxima. Here η=1, LΦ(x,u)=max⁡(0,1−u), and the constant minimizer hΦ∗=1 has risk zero. With s=2,c=1/4, the margin premise is 1/4≤(1/4)(1−0), an equality. For h=−1/2, classification excess is 1 and surrogate excess is 3/2, whereas the claimed bound is (1/2)3/2<1 since its square is 3/8<1. All scores and risks are measurable and finite. Thus the proposed coefficient is false even without zero scores and with a finite conditional minimizer.

2.1F1constructstep 1.1algebra∎

Independently use the same one-point feature space and hinge loss, but let each label have probability 1/2. Then LΦ(x,u)=[max⁡(0,1−u)+max⁡(0,1+u)]/2≥1, with equality at u=0, so take hΦ∗=h=0. For s=1,c=1 the premise is 0≤0 and surrogate excess is zero. But R01(h)=1 while R01∗=1/2, so classification excess is 1/2. Both 2c and 2c1/s times the zero surrogate excess vanish. This refutes the uncorrected tie convention independently of the scale defect and completes the refutation.

Source notes

The displayed false implication preserves the controlling ML-07 formula exactly. Mohri et al. Theorem 4.7 instead puts cs in its premise and predicts +1 at a zero score. Its regret theorem remains sound using an upper bound in place of its Lemma 4.5 equality at zero. The two witnesses here use the same approved class of losses and do not rely on any endpoint, selection, or limiting assumption.

TheoremStatement: AI-adaptedProof: AI-generatedjudge pass (gpt-6-luna)Open item page →

Surrogate regret controls classification regret with explicit tie and scale terms

Statement

Assume AC and the binary-surrogate setup, including a measurable extended-real conditional minimizer hΦ∗. Let s≥1 and c>0. Suppose for every x, ∣η(x)−12∣s≤c [LΦ(x,0)−LΦ(x,hΦ∗(x))]. Then every measurable real-valued score h with finite surrogate risk satisfies the sound zero-score-is-error bound R01(h)−R01∗≤2c1/s[LΦ(h)−LΦ∗]1/s+E ⁣[min⁡{η(X),1−η(X)}1{h(X)=0}].

In particular, if P(h(X)=0)=0, the correction vanishes. Define instead the label classifier fh(x)=+1 for h(x)≥0 and fh(x)=−1 for h(x)<0, and write R+(h)=P(fh(X)≠Y). For all scores covered above, including scores with zeros, R+(h)−R01∗≤2c1/s[LΦ(h)−LΦ∗]1/s. Equivalently, parameterizing the same margin premise by ∣η(x)−1/2∣s≤as[LΦ(x,0)−LΦ(x,hΦ∗(x))] gives coefficient 2a in both inequalities, with the same zero-score correction when using R01.

Statement references

Binary surrogate classification risk: defines η, the conditional margin risk, its minimizer, and the surrogate and classification risks.

Binary zero-one excess risk with a zero-score error convention: gives the exact classification-risk excess under the convention that zero scores are errors.

The negative reciprocal-power function is convex: supplies the convexity needed for the reciprocal-power Jensen step.

Facts & Assumptions

Given: AC, a binary supervised problem with Y∈{−1,+1}, the selected conditional probability function η, a finite convex nondecreasing margin loss Φ, its measurable extended-real conditional minimizer hΦ∗, s≥1, c>0, the displayed margin hypothesis, and a measurable real-valued score h with LΦ(h)<∞.

[A1]

Assume AC; it supplies the conditional-probability version used to define η. The Axiom of Choice A finite label has a conditional probability function

[F1]

The conditional class probabilities satisfy the event-integral identities for all measurable feature events. A finite label has a conditional probability function

[F2]

The conditional loss is LΦ(x,u)=η(x)Φ(−u)+(1−η(x))Φ(u); hΦ∗(x) minimizes it over the extended real line; R01 uses Yh≤0 and LΦ(h) is the population risk of Φ(−Yh). Binary surrogate classification risk Population and empirical risk

[F3]

A nonnegative measurable function admits increasing simple approximations, and monotone convergence passes their integrals to the limit. Every nonnegative measurable function is the increasing limit of simple measurable functions Monotone convergence for the integral

[F4]

A finite convex real function on R is continuous. A convex function on an open convex set is continuous

[F5]

For nonnegative integrable D and convex φ(t)=−t1/s on [0,∞), Jensen gives E[D1/s]≤(ED)1/s. The negative reciprocal-power function is convex Jensen's inequality for expectation

[F6]

The exact binary classification-risk excess is the sum of the wrong-sign term and the zero-score correction displayed in the risk-excess lemma. Binary zero-one excess risk with a zero-score error convention

[F7]

Measurability is preserved by composition with Borel maps and by defined arithmetic operations on measurable extended-real functions. A measurable function between measurable spaces Arithmetic and lattice operations preserve measurability whenever they are defined

[F8]

The nonnegative integral is additive on nonnegative measurable functions. Additivity of the nonnegative Lebesgue integral

[F9]

A nonnegative measurable function with finite integral is finite almost everywhere. A nonnegative measurable function with finite integral is finite almost everywhere

[F10]

The nonnegative integral of a measurable function over a null set is zero. A nonnegative integral over a null set vanishes

[F11]

The nonnegative integral is monotone for pointwise ordered nonnegative measurable functions and homogeneous under positive finite real scalars. Monotonicity and nonnegative homogeneity of the nonnegative integral

Proof

1.1A1F1F3algebra

Under AC [A1], the event identities [F1] imply, first for indicators and finite nonnegative simple functions and then by [F3] for every nonnegative measurable f:X→[0,∞], that E[1{Y=+1}f(X)]=E[η(X)f(X)],E[1{Y=−1}f(X)]=E[(1−η(X))f(X)]. For simple f this follows by finite additivity of the event identities; increasing simple approximation and monotone convergence give the general case.

2.1F2F4F7step 1.1

The function Φ is continuous by [F4], hence Borel; its endpoint extension by one-sided limits is Borel on the extended real line. Since h is measurable, the measurable-map definition [F7] makes Φ∘h and Φ∘(−h) measurable and nonnegative. Applying step 1.1 to these functions gives LΦ(h)=E[LΦ(X,h(X))]. This identity also verifies measurability of the conditional-risk integrand used below.

3.1F2F7F8F9F10step 2.1givenalgebra

Put m(x)=LΦ(x,hΦ∗(x)) and g(x)=LΦ(x,0)−m(x). Minimality gives 0≤m(x)≤LΦ(x,0)=Φ(0) and g(x)≥0 for every x, so LΦ∗=Em(X)<∞. Here m is measurable: for the endpoint-valued minimizer, each weighted term is the limit of the measurable functions η(x)min⁡{Φ(−hΦ∗(x)),n} or (1−η(x))min⁡{Φ(hΦ∗(x)),n}, respectively; this also implements 0⋅∞=0. For the score h, put R(x)=LΦ(x,h(x)) and D0(x)=R(x)−m(x)≥0. By step 2.1, ER(X)=LΦ(h), while R=D0+m pointwise because m is finite. Additivity [F8] gives ED0(X)=LΦ(h)−LΦ∗<∞. By [F9], N={D0=+∞} is measurable and null. Set D=D0 on Nc and D=0 on N; [F7] makes this finite representative measurable. Additivity [F8] and [F10] show that it has ED=ED0=LΦ(h)−LΦ∗.

4.1F2step 3.1givenalgebra

Fix x, write a=η(x), and let u be a real score satisfying u(a−1/2)≤0. For all real u, convexity gives Φ(−u)+Φ(u)−2Φ(0)≥0. If a>1/2 then u≤0, so monotonicity gives Φ(−u)−Φ(u)≥0; if a<1/2 then u≥0, so Φ(−u)−Φ(u)≤0. The identity LΦ(x,u)−LΦ(x,0)=12[Φ(−u)+Φ(u)−2Φ(0)]+(a−12)[Φ(−u)−Φ(u)] therefore shows LΦ(x,u)≥LΦ(x,0) whenever a≠1/2 and u(a−1/2)≤0. When a=1/2, the same identity has zero second term and proves LΦ(x,u)≥LΦ(x,0) for every u, so the conditional minimum is at 0 and g(x)=0. Consequently, on {h(x)(a−1/2)≤0}∖N one has D(x)=D0(x)≥g(x)≥0; the excluded set is null.

5.1F2F6F8F10F11step 3.1step 4.1givenalgebra

Almost surely on the event h(X)(η(X)−1/2)≤0, we are outside the null set N from step 3.1, so the margin hypothesis and step 4.1 give ∣η(X)−1/2∣s≤cg(X)≤cD(X), hence ∣η(X)−1/2∣≤c1/sD(X)1/s. For nonnegative measurable integrands, [F8] and [F10] identify each full expectation with its integral on Nc; on that set the displayed inequality is pointwise, so monotonicity and positive-scalar homogeneity [F11] pass it to expectations and extract the factor 2c1/s. Apply the exact excess identity [F6], bound its first integrand in this way, and use 1{h=0}≤1 to obtain R01(h)−R01∗≤2c1/sE[D(X)1/s]+E[min⁡{η(X),1−η(X)}1{h(X)=0}].

6.1F5F8F11step 3.1step 5.1algebra

Put α=1/s∈(0,1]. For 0≤t≤1, tα≤1, while for t≥1, tα≤t; hence Dα≤1+D. Monotonicity [F11] and additivity [F8] give E[Dα]≤E[1+D]=1+ED<∞ by step 3.1, so Dα is integrable. By [F5], Jensen applied to the integrable convex function −tα gives E[D1/s]≤(ED)1/s=[LΦ(h)−LΦ∗]1/s by step 3.1. Substitution in step 5.1 proves the zero-score-is-error bound.

7.1F1F2step 5.1step 6.1algebra∎

Under P(h(X)=0)=0 the correction has expectation zero. For the label classifier fh, at each x its conditional excess over min⁡(η(x),1−η(x)) is 2∣η(x)−1/2∣ on {h(x)<0,η(x)>1/2}∪{h(x)≥0,η(x)<1/2} and zero elsewhere. This follows by comparing the conditional error η(x) for prediction −1 and 1−η(x) for prediction +1. This adverse-sign set is contained in the event of step 5.1, so steps 5.1 and 6.1 bound its expectation by 2c1/s[LΦ(h)−LΦ∗]1/s without a tie correction. Finally, replacing c by as makes c1/s=a and proves the equivalent source parameterization.

Source notes

Mohri et al. Theorem 4.7 assumes the margin right-hand side is cs[LΦ(x,0)−LΦ(x,hΦ∗(x))] to obtain coefficient 2c. The controlling plan instead has c there, which yields 2c1/s. The source classifier predicts +1 at zero, while the plan counts zero as an error; the exact local risk identity therefore requires the displayed zero-score correction. The original planned zero-remainder formula with coefficient 2c is false: a deterministic positive label with natural-log logistic loss, s=2, c=1/2, and score h=−0.1 satisfies its premise but has excess classification error 1>ln⁡(1+e0.1). Independently, at η=1/2 the zero score has surrogate excess zero and zero-score-is-error excess 1/2, so changing only the coefficient cannot repair that convention. The corrected general bound and both clean specializations above retain the complete planned surrogate scope. Mohri Lemma 4.5 overcounts at zero under its own +1 tie rule; only its valid upper bound is used here, proved directly in step 7.1.

4 · Examples, counterexamples and false statements

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