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Rigid-body dynamics and stability

1 · Prerequisites

2 · Summary

This page adds dynamics to the rigid-material branch of cm10-rigid-body-configuration-and-inertia. The postulate Adoption of the external-torque branch of the rigid-material model: declared torque data and the balance of angular momentum about the centre of mass adopts the external-torque branch: a model may declare a continuous torque datum τ of dimension μℓ2τ−2 read as the total external torque about the centre of mass, and the admitted law of the branch is the balance Lc′=τ of the angular momentum about the centre of mass. Nothing about the force producing τ, no momentum balance for the centre of mass and no conservation law is assumed; friction, contact and drive torques must be declared as part of τ with their own models, and the frame transformation of a torque datum is fixed there.

Euler's equations with torque for the rigid-material model, the rotational power identity, the torque-free reduction and frame covariance turns the adopted balance into the body-frame Euler equations Iω′+ω×Iω=RTτ, gives their principal-axis components, proves the rotational power identity ddt(12ωTIω)=ω⋅RTτ, reduces the torque-free case to l′=l×(I−1l) under nondegeneracy, and verifies the frame covariance of the whole formulation. Torque-free motion of the rigid-material model: conservation of the angular momentum about the centre of mass, the energy-momentum invariants, the principal-axis equations and global existence of the spin dynamics then establishes the conservation of the spatial angular momentum Lc, the two invariants C=∥l∥22 and E=12ωTIω with the principal-axis component equations, the identification of E with the rotational kinetic energy, the boundedness of ω, and the global solvability in time of the torque-free spin field.

Principal-axis uniform rotations of the torque-free rigid-material model: existence, a fixed spatial direction, the invariants, and the converse classification classifies the torque-free motions with constant body angular velocity: for every principal axis and every rate there is a uniform rotation about a fixed spatial direction, and conversely a constant body angular velocity must be a principal-axis spin. Linearization of the torque-free spin of the rigid-material model at a principal-axis spin: the oscillatory/exponential dichotomy and linear stability computes the linearization of the torque-free spin at such a spin and proves the oscillatory/exponential dichotomy with the explicit frequencies κj, together with the corresponding linear-stability verdicts, while making clear that these are statements about the linearized system only. Nonlinear stability of the torque-free spin of the rigid-material model about an extreme principal axis, and instability about the intermediate axis, with an explicit escape time and the orientation caveat proves the nonlinear statements: Lyapunov stability of the spins about the extremal principal axes with an explicit conserved deviation bound, and instability of the intermediate-axis spin with an explicit escape datum, escape radius and escape-time bound, realised by an actual torque-free motion; it also records the orientation caveat that the spin phase is not controlled. The page closes with the heavy symmetric top: the postulate Adoption of the heavy symmetric top branch: axisymmetric rigid material, a fixed pivot material point, a uniform gravitational field and the balance of angular momentum about the pivot adopts an axisymmetric rigid material with a material point held fixed at the origin (the pivot, on the symmetry axis at distance d from the centre of mass), an ideal pivot reaction contributing no torque about the pivot in the framework's sense of a frictionless hinge, a uniform gravitational field of strength g, and the balance of angular momentum about the pivot; Reduction of the heavy symmetric top branch: pivotal angular momentum, Euler-angle equations, the two conserved momenta and the one-dimensional θ equation computes the pivotal angular momentum RI~ω with I~=diag(A,A,C) and A=Ac+md2, derives the body-frame pivot equations, and shows that on any interval carrying an Euler-angle description with θ∈(0,π) the motion satisfies the heavy-top system with parameters (A,C,m,d,g), giving the two conserved momenta, the reduced energy and the one-dimensional θ equation. Worked checks on explicit inertia matrices — free principal-axis spins, a non-uniform torque-free motion with its invariants, the linearized frequencies of an asymmetric top, an explicit escape from the intermediate-axis spin and a steady precession of the heavy top — are collected on cm11-rigid-body-dynamics-and-stability-examples.

3 · Logical flowchart

4 · Definitions, postulates, theorems and proofs

PostulateStatement: AI-adaptedProof: Not applicableOpen item page →

Adoption of the external-torque branch of the rigid-material model: declared torque data and the balance of angular momentum about the centre of mass

Physical scope

Adoption of the external-torque branch of the rigid-material model branch of Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope: a declared continuous external-torque datum τ:I0→R3 (dimension μℓ2τ−2, newton metres), read as the total external torque about the centre of mass, and the adopted balance Lc′=τ of the angular momentum about the centre of mass. The postulate asserts no force law producing τ, no balance for the centre-of-mass motion, no conservation law, no uniformity of rotation and no measured torque or observation; the countable-choice assumption is carried only for the finiteness of the defining integrals of the model's angular momentum. The branch excludes deformable bodies, impacts and variable mass; friction, contact and drive torques must be declared as part of τ with their own models.

Postulate

Adopt as physical assumptions of the framework the following external-torque branch of the rigid-material model, in the setting of Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope.

(i) Setting. A model of the branch carries the data of Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope: a reference mass distribution ν with total mass m>0 and centred reference coordinates, a time window I0, an inertial frame with adapted coordinates (t,x) (Inertial frames, stationary observers and the adopted Galilean transformations between frames), and a motion x(t,ρ)=c(t)+R(t)ρ with configuration path (c,R) of class C2 (Configuration, configuration space and orientation of a rigid-material model in an inertial frame). Assume the Axiom of Countable Choice ACω (The Axiom of Countable Choice (ACω)), used only through Total momentum, kinetic-energy splitting and centre-of-mass angular momentum of a rigid-material motion to make the defining integrals of the model's inertial quantities finite. Along the motion the body angular velocity ω and the body inertia matrix I are those of Body and spatial angular velocity of a rigid-material motion, and the material velocity field and Inertia matrix, spatial inertia tensor, inertia tensor about a point and moment of inertia about an axis of a rigid-material model, and the angular momentum about the centre of mass is Lc(t):=∫(x(t,ρ)−c(t))×(∂tx(t,ρ)−c′(t)) dν(ρ), the finite vector of clause 1 of Total momentum, kinetic-energy splitting and centre-of-mass angular momentum of a rigid-material motion, which by clause 4 of that item satisfies the identity Lc(t)=R(t) I ω(t)(t∈I0).

(ii) External torque datum. An external torque datum of the branch on the time window I0 is a continuous map τ:I0⟶R3,[τ]=μℓ2τ−2, the dimension being read in newton metres (Dimensions and SI unit conventions of the non-relativistic classical mechanics framework). Its intended physical reading is: τ(t) is the total external torque about the centre of mass at time t, the resultant moment about c(t) of the forces external to the model that act on the body at time t: weight in a declared gravitational field, forces exerted by supports, pivots, axles or contacts, thrusts and drives, applied couples, and frictional torques. Which external agencies occur and which datum they jointly produce is model data fixed by the model's further assumptions; this postulate does not derive τ from any force system, and the statements of the pair use τ only through the balance below.

(iii) The adopted balance. Along every motion of a model of the branch with external torque datum τ, adopt the external-torque balance Lc′(t)=τ(t)(t∈I0). This is an adopted dynamical law of the model. Through the identity Lc=RIω of clause (i) it is one vector equation relating the configuration path, its first two time derivatives and the datum; it does not by itself determine (c,R), and it is not a consequence of the kinematic definitions of Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope.

(iv) Torque-free motions. A model of the branch whose datum vanishes, τ≡0 on I0, is called torque-free; for such a model the balance reads Lc′≡0 on I0. Torque-free is a property of the declared datum, not of the mass distribution: every model of Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope may be used with the zero datum, and the statements of this page about torque-free motions are conditional on that use.

(v) Relation to the particle branch. The framework's angular-momentum balance for finitely many particle labels is Angular momentum balance about a fixed or moving reference point, the internal torque sum, and the centrality case: for a model that declares the external-plus-pair presentation with antisymmetric pair forces, the angular momentum about a fixed reference point has derivative equal to the total torque about that point, the internal torque sum cancelling when the evaluated pair forces are central. The rigid-material model has no particle labels; its mass data are the measure ν, and all its physical statements weight material points by ν. That balance is therefore not available verbatim for the model of clause (i), and clause (iii) is adopted here as the rigid-material analogue. No claim that clause (iii) follows from Angular momentum balance about a fixed or moving reference point, the internal torque sum, and the centrality case, or from any other item of the framework, is made by this postulate or proved anywhere on this page.

(vi) No other balances. This postulate asserts no balance for the total momentum mc′ and no equation of motion for the centre of mass: an external force datum is not part of the branch, the curve c remains free except as restricted by further model assumptions (for instance a pivot constraint adopted on this page), and the theorems of the pair use only the balance (iii). In particular the branch neither asserts nor denies that the centre of masses moves uniformly, and it asserts no conservation of the rotational kinetic energy; the power identity for the rotational term is a theorem of this page, not an assumption.

(vii) Frame consistency. Let a second inertial frame be related to the chosen one by the transformation t′=t+b, x′=Qx+ut+a of Inertial frames, stationary observers and the adopted Galilean transformations between frames clause (iv), with b∈R, a,u∈R3 and Q∈SO(3), and let x~(t′,ρ):=Q x(t′−b,ρ)+u (t′−b)+a be the description of the same motion in the second frame (Behaviour of the rigid-material configuration, angular velocity, inertia data and inertial quantities under a change of inertial frame clause 1). Adopt: this description is again a motion of the same model of the branch, and an external torque datum of the model transforms between the two descriptions by τ~(t′):=Q τ(t′−b), the transformation of a spatial vector under the rotation Q alone, with no contribution from the boost u, the translation a or the time shift b. The consistency of the balance (iii) with this transformation law — namely that the description in the second frame satisfies the balance with datum τ~, because L~c(t′)=QLc(t′−b) by clause 5 of Behaviour of the rigid-material configuration, angular velocity, inertia data and inertial quantities under a change of inertial frame and differentiation commutes with the constant rotation Q and the time shift — is recorded and proved as a clause of the frame-covariance theorem of this page; it is not an assumption of the present postulate.

(viii) Scope and exclusions. The branch excludes deformable bodies, internal degrees of freedom, variable mass, ablation, impact and contact events, and every constitutive law for friction, rolling or slipping; any such effect that is present must be declared as part of the datum τ of clause (ii) with its own model, and a datum is a model object, not a measurement. The branch also excludes relativistic and quantum descriptions. Wherever a statement of the pair needs the inverse I−1 it assumes the model is nondegenerate in the sense of Inertia matrix, spatial inertia tensor, inertia tensor about a point and moment of inertia about an axis of a rigid-material model clause (a), and that hypothesis is stated explicitly in the theorem that uses it. The postulate asserts no measured torque, no numerical value, and no claim that any concrete body or apparatus is described by the branch; whether a given datum is adequate for a given apparatus is decided by comparing the model's conditional predictions with reported observations under the apparatus's stated regime.

Physics theoremStatement: AI-adaptedProof: AI-adaptedprecheck passOpen item page →

Euler's equations with torque for the rigid-material model, the rotational power identity, the torque-free reduction and frame covariance

Physical scope

Conditional deductions inside the external-torque branch of Adoption of the external-torque branch of the rigid-material model: declared torque data and the balance of angular momentum about the centre of mass for the rigid-material model of Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope: the body-frame Euler equations with the declared torque datum, their principal-axis components, the power identity ddt12ωTIω=ω⋅RTτ (and constancy of the rotational kinetic energy in the torque-free case), the torque-free reduction l′=l×(I−1l) under nondegeneracy, and the preservation of the balance under changes of inertial frame with the declared transformation of the torque datum. No force law producing τ, no conservation of Lc (which is proved on the same page), no measurement and no empirical value is asserted.

Statement

Assume the Axiom of Countable Choice ACω (The Axiom of Countable Choice (ACω)), used only through the integrals of Total momentum, kinetic-energy splitting and centre-of-mass angular momentum of a rigid-material motion; the theorems below neither use nor imply any other choice principle. Adopt a model of the rigid-material branch Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope with the external-torque branch Adoption of the external-torque branch of the rigid-material model: declared torque data and the balance of angular momentum about the centre of mass: a reference mass distribution ν with total mass m and centred reference coordinates, a time window I0 (Intervals of R: the nine order-convex forms, nondegeneracy, and length), an inertial frame, a motion x(t,ρ)=c(t)+R(t)ρ with configuration path (c,R) of class C2 (Configuration, configuration space and orientation of a rigid-material model in an inertial frame), body angular velocity ω (Body and spatial angular velocity of a rigid-material motion, and the material velocity field) and body inertia matrix I (Inertia matrix, spatial inertia tensor, inertia tensor about a point and moment of inertia about an axis of a rigid-material model), and a continuous external torque datum τ:I0→R3 with respect to which the adopted balance of Adoption of the external-torque branch of the rigid-material model: declared torque data and the balance of angular momentum about the centre of mass clause (iii) holds along the motion. Then:

  1. Euler's equations with torque. Writing l:=Iω, one has l′=RTτ−ω×Iω and Iω′(t)+ω(t)×Iω(t)=R(t)Tτ(t)(t∈I0).
  2. Principal-axis components. If (e1,e2,e3) is a positively oriented orthonormal eigenbasis of I with Iej=Ijej (Principal axes and principal moments of the inertia data of a rigid-material model, axis moments and extremal values clause (a)) and ω=∑jωjej, RTτ=∑jτjej, then the equations are componentwise I1ω1′=(I2−I3)ω2ω3+τ1,I2ω2′=(I3−I1)ω3ω1+τ2,I3ω3′=(I1−I2)ω1ω2+τ3.
  3. Rotational power identity. The rotational kinetic energy Krot(t):=12ω(t)TIω(t) is differentiable on I0 with ddtKrot(t)=ω(t)⋅R(t)Tτ(t)(t∈I0); in particular, if τ≡0, then Krot is constant on I0, and Krot coincides with the rotational term 12ωTIω of the model's kinetic energy in clause 3 of Total momentum, kinetic-energy splitting and centre-of-mass angular momentum of a rigid-material motion.
  4. Torque-free reduction and nondegeneracy. Suppose τ≡0 and the model is nondegenerate in the sense of Inertia matrix, spatial inertia tensor, inertia tensor about a point and moment of inertia about an axis of a rigid-material model clause (a), so that I is invertible with I−1l=ω. Then, writing ω as a function of l, l′=l×(I−1l),ω′=F(ω):=−I−1(ω×Iω); the second form exhibits the torque-free body angular velocity as a solution of the autonomous field F on R3.
  5. Frame covariance. Let a second inertial frame be related to the first by t′=t+b, x′=Qx+ut+a with b∈R, a,u∈R3, Q∈SO(3) (Inertial frames, stationary observers and the adopted Galilean transformations between frames clause (iv)), and let x~(t′,ρ):=Qx(t′−b,ρ)+u(t′−b)+a, τ~(t′):=Qτ(t′−b) be the transformed motion and datum of Adoption of the external-torque branch of the rigid-material model: declared torque data and the balance of angular momentum about the centre of mass clause (vii). Then the balance holds in the second frame, and Iω~′(t′)+ω~(t′)×Iω~(t′)=R~(t′)Tτ~(t′)(t′∈I0+b), where ω~(t′)=ω(t′−b) and R~(t′)=QR(t′−b); the body-frame torque is unchanged: R~(t′)Tτ~(t′)=R(t′−b)Tτ(t′−b).

The statement is conditional on the adopted model and torque balance; it asserts no force law for τ, no conservation of Lc and no measured value.

Facts & Assumptions

Given: The model data and motion of the statement, the balance hypothesis Lc′=τ of Adoption of the external-torque branch of the rigid-material model: declared torque data and the balance of angular momentum about the centre of mass clause (iii), and the derivative of the configuration path.

[L2]

The balance: Lc′(t)=τ(t) on I0, and τ is continuous (Adoption of the external-torque branch of the rigid-material model: declared torque data and the balance of angular momentum about the centre of mass clauses (ii) and (iii)).

[L3]

Matrix-curve calculus: for the C1 curves R:I0→SO(3) and l:I0→R3 one has (Rl)′=R′l+Rl′; RTR′=[ω]× and R′=R[ω]×; [ω]×z=ω×z; and RTR=I3, so RTw=0 implies w=0 (Derivative rules for differentiable matrix-valued curves, and skewness of RTR′ for a curve in SO(3), The skew-matrix/cross-product correspondence [ω]×z=ω×z and its conjugation law R[ω]×RT=[Rω]×, The orthogonal group O(3) and the rotation group SO(3), Rectangular matrix multiplication and the identity matrix In, including zero-sized shapes).

[L4]

Cross-product algebra: u×v is bilinear and alternating, u×u=0, u×v=−(v×u), and ⟨u,v×w⟩=det⁡[u v w], so a cross product is orthogonal to each factor (The cross product is bilinear, alternating, and orthogonal to both factors, The cross product in R3, The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn).

[L5]

Principal data: the positively oriented orthonormal eigenbasis (ej) and principal moments Ij of I, with Iω=∑jIjωjej when ω=∑jωjej (Principal axes and principal moments of the inertia data of a rigid-material model, axis moments and extremal values clauses (a)-(b)).

[L6]

Pairing derivative and constancy: for differentiable curves u,v the scalar product t↦⟨u(t),v(t)⟩ is differentiable with derivative ⟨u′,v⟩+⟨u,v′⟩ (Differentiation of sums, scalar multiples, inner products, cross products and squared norms of differentiable curves in R3 clause 2); a continuous real function on an interval whose derivative vanishes at every interior point is constant (A function continuous on an interval I whose derivative vanishes at every interior point of I is constant on I; consequently two such functions with the same derivative differ by a constant).

[L7]

Frame changes: the description of the motion in the second frame has configuration path (c~,R~) with R~(t′)=QR(t′−b), body angular velocity ω~(t′)=ω(t′−b), and inertial quantities L~c(t′)=QLc(t′−b) (Behaviour of the rigid-material configuration, angular velocity, inertia data and inertial quantities under a change of inertial frame clauses 1, 2 and 5); differentiation of a composition with the affine reparametrisation t↦t′−b and the constant rotation Q follows the chain rule (The chain rule for total derivatives: D(g∘f)(a)=Dg(f(a))∘Df(a)).

[L8]

Nondegeneracy: for a nondegenerate model the symmetric matrix I is positive definite and invertible (Principal axes and principal moments of the inertia data of a rigid-material model, axis moments and extremal values clause (d)); consequently I−1l=I−1Iω=ω for l=Iω, the inverse satisfying I−1I=I3 (Invertible matrices and the general linear group GL⁡n(F), Rectangular matrix multiplication and the identity matrix In, including zero-sized shapes).

Proof

technique · direct; differentiate $Rl$ with the product rule, translate the balance into the body frame, read off components in a principal basis, differentiate the quadratic form, and instantiate the frame-transformation laws
1.1givenL1L2L3algebra

By [L1] and [L3] the product Rl is differentiable on I0 with (Rl)′=R′l+Rl′=R([ω]×l+l′)=R(ω×l+l′), and by [L2] this equals τ. Multiplying by RT and using RTR=I3 gives ω×l+l′=RTτ.

1.2givenL2L7algebra

Let t′=t+b and use [L7]: ω~(t′)=ω(t′−b) and L~c(t′)=QLc(t′−b); differentiating the second identity in t′ by the chain rule [L7] gives L~c′(t′)=QLc′(t′−b)=Qτ(t′−b)=τ~(t′), so the adopted balance holds in the second frame.

2.1step 1.1givenL1algebra

Since l=Iω and I is a constant matrix, l′=Iω′; substituting l=Iω into step 1.1 gives Iω′+ω×Iω=RTτ, which is clause 1 (and the alternative form l′=RTτ−ω×Iω).

2.2step 1.1givenL4L8algebra

Assume τ≡0 and nondegeneracy. From step 1.1, l′=−ω×l=(Iω)×ω=l×(I−1l), the middle equality by antisymmetry [L4] and the last by I−1l=ω from [L8]; similarly ω′=I−1(−ω×Iω)=F(ω), which is clause 4.

3.1step 2.1givenL3L4L5algebra

In the positively oriented principal basis of [L5], the basis matrix Q belongs to SO(3) and the skew/cross correspondence [L3] gives Q(u×v)=(Qu)×(Qv), so the usual cross-product coordinates apply. Any orthonormal principal basis can be given this orientation by negating one eigenvector, without changing eigenvalues or the motion. Iω=∑jIjωjej and the first component of ω×Iω is ω2I3ω3−ω3I2ω2=(I3−I2)ω2ω3, with the cyclic analogues; writing RTτ=∑jτjej, clause 1 reads I1ω1′=(I2−I3)ω2ω3+τ1 and cyclically, which is clause 2.

3.2step 2.1givenL1L4L6algebra

Differentiating Krot=12⟨ω,Iω⟩ with [L6] and using the symmetry of I from [L1] gives Krot′=⟨ω′,Iω⟩=⟨ω,Iω′⟩; substituting Iω′=RTτ−ω×Iω from step 2.1 and using ⟨ω,ω×Iω⟩=0 by [L4] gives Krot′=⟨ω,RTτ⟩, which is clause 3; when τ≡0 this derivative vanishes identically and [L6] makes Krot constant on I0. The identification with the kinetic splitting is clause 3 of Total momentum, kinetic-energy splitting and centre-of-mass angular momentum of a rigid-material motion.

4.1step 1.2step 2.1givenL3L7algebra∎

Applying step 2.1 in the second frame (whose configuration path is (c~,R~) of class C2 by [L7]) gives Iω~′+ω~×Iω~=R~Tτ~ on I0+b; and R~(t′)Tτ~(t′)=R(t′−b)TQTQτ(t′−b)=R(t′−b)Tτ(t′−b) because QTQ=I3 [L3], so the body-frame torque is unchanged; this is clause 5.

Remarks

  • What is a theorem and what is an assumption. The balance Lc′=τ is adopted in Adoption of the external-torque branch of the rigid-material model: declared torque data and the balance of angular momentum about the centre of mass; clauses 1-4 here are its consequences in the body frame and in the torque-free case, and clause 5 records that the formulation is consistent with the framework's frame changes. No clause produces τ from a force system.

  • Where the nondegeneracy is used. Clauses 1-3 and 5 hold for every model of the branch, including degenerate ones; only clause 4 uses the invertibility of I, and the items that invert I on this page state that hypothesis explicitly.

  • The rotational power identity. Clause 3 says that the rate of change of the rotational kinetic energy equals the power ω⋅RTτ developed by the external torque; in the torque-free branch the rotational kinetic energy is a constant of the motion. This is a consequence of the adopted balance, not a separate assumption, and it does not by itself determine the motion.

Physics theoremStatement: AI-adaptedProof: AI-adaptedprecheck passOpen item page →

Torque-free motion of the rigid-material model: conservation of the angular momentum about the centre of mass, the energy-momentum invariants, the principal-axis equations and global existence of the spin dynamics

Physical scope

Conditional statements about a torque-free motion of a nondegenerate rigid-material model of Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope: the angular momentum about the centre of mass is constant in the inertial frame; the scalars C=∥l∥22=∥Lc∥22 and E=12ωTIω=12l⋅I−1l are constants of the motion and E is the rotational kinetic energy; in a principal basis the spin components obey the displayed torque-free equations; and the torque-free spin field is globally solvable in time, so the body angular momentum and the body angular velocity of a torque-free motion are bounded by initial data. The statements are conditional on the adopted zero-torque balance and nondegeneracy, carry the countable-choice assumption used only for the finiteness of the defining integrals, and assert no measurement, no orientation statement and no claim about nature.

Statement

Assume the Axiom of Countable Choice ACω (The Axiom of Countable Choice (ACω)), used only through the integrals of Total momentum, kinetic-energy splitting and centre-of-mass angular momentum of a rigid-material motion. Adopt a model of the rigid-material branch Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope that is nondegenerate in the sense of Inertia matrix, spatial inertia tensor, inertia tensor about a point and moment of inertia about an axis of a rigid-material model clause (a) (no line through the origin carries the whole mass), and use it in the torque-free external-torque branch of Adoption of the external-torque branch of the rigid-material model: declared torque data and the balance of angular momentum about the centre of mass clause (iv): the datum vanishes, so along every motion of the resulting model the adopted balance reads Lc′=0 on the time window I0. Let ω be the body angular velocity, I the body inertia matrix and l:=Iω (Body and spatial angular velocity of a rigid-material motion, and the material velocity field, Inertia matrix, spatial inertia tensor, inertia tensor about a point and moment of inertia about an axis of a rigid-material model). Then:

  1. Conservation of angular momentum. The angular momentum about the centre of mass Lc(t)=R(t)l(t) of Total momentum, kinetic-energy splitting and centre-of-mass angular momentum of a rigid-material motion clause 4 is constant on I0; in particular ∥Lc∥2 is constant.
  2. Energy-momentum invariants and principal components. The scalars C:=⟨l,l⟩=∥Lc∥22,E:=12 ωTIω=12 ⟨l,I−1l⟩ are constant on I0, and l satisfies the torque-free equation l′=l×(I−1l). If (e1,e2,e3) is a positively oriented orthonormal eigenbasis of I with Iej=Ijej and l=∑jljej (Principal axes and principal moments of the inertia data of a rigid-material model, axis moments and extremal values clauses (a)-(b)), then C=∑jlj2,E=∑jlj22Ij, and the component equations are l1′=(1I3−1I2)l2l3,l2′=(1I1−1I3)l1l3,l3′=(1I2−1I1)l1l2.
  3. The energy invariant is the rotational kinetic energy. E equals the rotational term 12ωTIω of the model's kinetic energy in clause 3 of Total momentum, kinetic-energy splitting and centre-of-mass angular momentum of a rigid-material motion; and with Imin⁡:=min⁡jIj>0 one has ∥ω(t)∥22≤2EImin⁡(t∈I0). In particular both l and ω are bounded on I0.
  4. The spin field is globally solvable. The autonomous field F(l)=l×(I−1l) on R3 is locally Lipschitz in the state variable (Local Lipschitz continuity in the state variable, locally uniform in time and parameters), and every solution of l′=F(l) has a unique maximal extension defined on all of R, and that extension satisfies ∥l(t)∥2=∥l(0)∥2 for every t. Consequently the l-path of a torque-free motion is the restriction to I0 of a solution defined on all of R, and its path is contained in the compact level set Λ(C,E):={z∈R3:⟨z,z⟩=C, 12⟨z,I−1z⟩=E}, which is nonempty because it contains the datum at any chosen time of the motion.

The statement is conditional on the adopted model, its nondegeneracy and the zero-torque balance; it asserts no orientation of the body in space, no measured value and no empirical law.

Facts & Assumptions

Given: A nondegenerate model of Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope, its time window I0, one inertial frame, a C2 motion x(t,ρ)=c(t)+R(t)ρ, its body angular velocity ω and body inertia matrix I, the zero-torque datum τ≡0, and the balance Lc′=τ of Adoption of the external-torque branch of the rigid-material model: declared torque data and the balance of angular momentum about the centre of mass clause (iii).

[L2]

The mathematical supplier (Euler's equations Iω′+ω×Iω=RTτ under an adopted torque balance, and the torque-free invariants and principal-axis equations): for a centred mass distribution not supported on any line through the origin, with inertia matrix I, an interval with at least two points, differentiable c, twice differentiable R and the rigid placement x=c+Rρ with body angular velocity ω, the balance hypothesis (Rl)′=τ with τ≡0 implies that l=Iω satisfies l′=l×(I−1l), that t↦⟨l,l⟩ and t↦12⟨l,I−1l⟩=12ωTIω are constant, and that in a positively oriented orthonormal eigenbasis of I with l=∑jljej those constants equal ∑jlj2 and ∑jlj2/(2Ij) and the component equations of clause 2 hold.

[L4]

Principal data: the orthonormal eigenbasis and principal moments, the identity Iω=∑jIjωjej for ω=∑jωjej, and Ij>0 with Imin⁡>0 in the nondegenerate case (Principal axes and principal moments of the inertia data of a rigid-material model, axis moments and extremal values clauses (a)-(b), (d)-(e), Inertia matrix, spatial inertia tensor, inertia tensor about a point and moment of inertia about an axis of a rigid-material model clause (a), The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn).

[L5]

Kinetic splitting: K(t)=12m∥c′(t)∥22+12ω(t)TIω(t) is the model's kinetic energy, so its rotational term is 12ωTIω (Total momentum, kinetic-energy splitting and centre-of-mass angular momentum of a rigid-material motion clause 3).

[L6]

Cross-product and norm algebra: u×v is bilinear and alternating with ∥u×v∥2≤∥u∥2∥v∥2, and u×u=0 (The cross product in R3, The cross product is bilinear, alternating, and orthogonal to both factors, The squared cross-product norm is the Gram determinant of two vectors, The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn).

[L8]

The chain rule for a composition with the affine reparametrisation s↦−s gives (l(−s))′=−l′(−s) (The chain rule for total derivatives: D(g∘f)(a)=Dg(f(a))∘Df(a)). Negating a continuous locally Lipschitz field preserves continuity and its state-Lipschitz constants.

Proof

technique · direct; instantiate the cited mathematical supplier on the model's measure and balance, identify the invariant with the kinetic term, and prove the local Lipschitz bound and the global existence by trapping in a sphere
1.1givenL1L2L3

The hypotheses of [L2] are met: ν is a centred mass distribution with finite second moment by [L1] and is not supported on any line through the origin by the nondegeneracy hypothesis; I0 has at least two points; c is differentiable and R twice differentiable because the configuration path is of class C2; and the balance hypothesis (Rl)′=τ holds with τ≡0 because Rl=Lc by [L1] and Lc′=0 by [L3]. Hence clause 2 of [L2] gives l′=l×(I−1l) and the constancy of C and E, and clause 3 of [L2] gives their principal-basis expressions and the component equations.

1.2givenL1L2L3

By [L3] the continuous function Lc has zero derivative on I0, so it is constant on I0; hence ∥Lc∥2 is constant, and ∥Lc(t)∥22=⟨l(t),l(t)⟩=C by [L1]. This is clause 1.

1.3givenL4L6algebra

The field F(l)=l×(I−1l) is locally Lipschitz in the state variable: by bilinearity and additivity of the cross product [L6], for all x,y∈R3 one has F(x)−F(y)=(x−y)×(I−1x)+y×(I−1(x−y)), so with the bound ∥I−1z∥2≤∥z∥2/Imin⁡ valid in the principal basis [L4] and the norm bound of [L6], ∥F(x)−F(y)∥2≤∥x−y∥2∥I−1x∥2+∥y∥2∥I−1(x−y)∥2≤(∥x∥2+∥y∥2)∥x−y∥2/Imin⁡; on the ball ∥z∥2≤r this is at most 2r∥x−y∥2/Imin⁡, a finite state-Lipschitz constant on every compact cylinder.

2.1step 1.1givenL4L5algebra

Writing ω=∑jωjej in the principal basis of [L4], one has ωTIω=∑jIjωj2≥Imin⁡∑jωj2=Imin⁡∥ω∥22, so ∥ω(t)∥22≤2E/Imin⁡ with E=12ωTIω constant by step 1.1 and Imin⁡>0 by [L4]; together with l=Iω this bounds ∥l∥22=C on I0. The identification of E with the rotational term of the kinetic energy is clause 3 of [L5]. This is clause 3.

2.2step 1.3givenL3L6L7L8

Every solution of l′=F(l) has a unique maximal extension defined on all of R: by [L7] and step 1.3 a unique maximal solution exists through every datum, with open domain (a,b); along it ddt∥l(t)∥22=2⟨l′(t),l(t)⟩=2⟨l(t)×(I−1l(t)),l(t)⟩=0 because the cross product is orthogonal to each factor [L6], so by [L3], applied to this continuous differentiable scalar on (a,b), ∥l(t)∥22≡∥l(t0)∥22 for any datum time t0∈(a,b) and its values over (a,b) lie in the sphere {z:∥z∥2=∥l(t0)∥2}⊆R3, which is closed and bounded and therefore compact by Heine-Borel in Rn: with the Euclidean metric a subset of Rn is compact if and only if it is closed and bounded, and the proof by bisection uses no choice principle; the same holds on the real line. If b<+∞, then near b the solution stays in that compact subset of the state domain, and clause 2 of [L7] extends it past b, contradicting maximality; hence b=+∞. If a>−∞, put z(s):=l(−s) on (−b,−a). By the chain rule [L8], z′(s)=−F(z(s)). The field −F is continuous and locally Lipschitz with the same constants as F, and z stays in the same compact sphere near its finite right endpoint −a. Applying the autonomous compact continuation of [L7] to −F extends z past −a; reflecting this extension back extends l past a, contradicting maximality. Hence a=−∞. Every original solution is a restriction of this unique global maximal solution by the uniqueness assertion of [L7].

3.1step 1.1step 2.2givenL4algebra∎

The l-path of a torque-free motion is a solution of l′=F(l) on I0 by step 1.1, hence by step 2.2 it is the restriction of a solution defined on all of R (uniqueness), its maximal extension satisfies ∥l(t)∥2=∥l(t0)∥2 for any datum time t0 and every t, and it takes values in Λ(C,E), which is compact as the intersection of the closed sphere and the closed level set {z:⟨z,I−1z⟩=2E} and nonempty because it contains l(t0). This is clause 4.

Remarks

  • The scalar invariants. The two invariant functions displayed are C=∥l∥22 and E=12⟨l,I−1l⟩; they need not be functionally independent in every model. For spherical inertia I=αI3 with α>0, one has E=C/(2α). The components lj=Ijωj are coordinates, not additional conserved quantities. The statement proves the displayed invariants and boundedness; it does not parameterize their level sets, compute elliptic functions or claim periodicity.

  • What is not claimed. No orientation statement is made: the conservation of Lc bounds the body-frame data l and ω, but the orientation R(t) itself is not confined by these invariants, and the pages that follow record this distinction explicitly.

  • The countable-choice hypothesis. ACω enters only through [L1] and [L2], which make the defining integrals of the model's inertial quantities finite; the algebraic identities themselves are choice-free once those integrals exist.

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Principal-axis uniform rotations of the torque-free rigid-material model: existence, a fixed spatial direction, the invariants, and the converse classification

Physical scope

Conditional statements about the torque-free branch of a nondegenerate rigid-material model of Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope: for every principal axis ej and every real rate Ω there is a motion whose orientation path is a uniform rotation with constant body angular velocity Ωej; for Ω≠0 the spatial direction R(t)ej of the body-fixed line through c(t) parallel to the reference axis ej is fixed in the inertial frame, so the spatial angular velocity ωs(t)=ΩR(t)ej is constant in that direction while its spatial location may translate with the arbitrary centre-of-mass curve c; the invariants take the values C=Ω2Ij2, E=12Ω2Ij; and conversely, a torque-free motion with constant body angular velocity must spin about a principal axis. The statements carry the countable-choice assumption inherited for finite mass moments and inertial integrals and for the double-cover surjectivity used to choose an initial unit quaternion, assert no measurement, no empirical law and no claim that any apparatus has been observed.

Statement

Assume the Axiom of Countable Choice ACω (The Axiom of Countable Choice (ACω)), carried through Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope clause (i) and Inertia matrix, spatial inertia tensor, inertia tensor about a point and moment of inertia about an axis of a rigid-material model for finite mass moments, through Total momentum, kinetic-energy splitting and centre-of-mass angular momentum of a rigid-material motion and Adoption of the external-torque branch of the rigid-material model: declared torque data and the balance of angular momentum about the centre of mass clause (i) for the finite inertial integrals, and through the double-cover supplier of The quaternion rotation map ρ: conjugation on the imaginary quaternions, the unit sphere S3, and quaternion lifts (its second remark) for the surjectivity used to choose an initial unit quaternion. Adopt a nondegenerate model of the rigid-material branch Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope: a reference mass distribution ν with total mass m, centred reference coordinates and no line through the origin carrying the whole mass (Inertia matrix, spatial inertia tensor, inertia tensor about a point and moment of inertia about an axis of a rigid-material model clause (a)). Fix an orthonormal principal basis (e1,e2,e3) with Iej=Ijej and Ij>0 (Principal axes and principal moments of the inertia data of a rigid-material model, axis moments and extremal values clauses (a) and (d)), use the model in the torque-free branch of Adoption of the external-torque branch of the rigid-material model: declared torque data and the balance of angular momentum about the centre of mass clause (iv), and fix an index j∈{1,2,3} and a rate Ω∈R. Use the model's nondegenerate open time window I0 (Intervals of R: the nine order-convex forms, nondegeneracy, and length and Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope clause (ii)), and fix a time t0∈I0 and an orientation R0∈SO(3). Then:

  1. Existence of the uniform rotation. There is a path R:I0→SO(3) of class C1 with R(t0)=R0 and R(t)TR′(t)=[Ωej]×(t∈I0), that is, with constant body angular velocity ω≡Ωej (Body and spatial angular velocity of a rigid-material motion, and the material velocity field clause (a)).
  2. It is a torque-free motion. For every such path R and every curve c:I0→R3 of class C2, the map x(t,ρ):=c(t)+R(t)ρ is a motion of the torque-free model of the branch: its angular momentum about the centre of mass is Lc(t)=ΩIj R(t)ej, it is constant on I0, and the adopted balance Lc′=0 holds. (Here R is automatically of class C2, because R′=R[Ωej]× is the product of the C1 curve R with a constant matrix, so the configuration path (c,R) has the regularity required of a motion.)
  3. Geometry and invariants. In the motions of clause 2 one has l=Iω=ΩIjej constant, C=∥Lc∥22=Ω2Ij2,E=12ωTIω=12Ω2Ij; if Ω≠0, define the spatial line of the body-fixed axis by ℓj(t):={c(t)+sR(t)ej:s∈R} and its unit direction by nj(t):=R(t)ej. Then nj(t)=Lc/(ΩIj) for every t, so this direction is fixed in the inertial frame and the spatial angular velocity ωs(t):=R(t)ω(t)=Ωnj of Body and spatial angular velocity of a rigid-material motion, and the material velocity field clause (b) is constant; the line ℓj(t) need not be fixed because c is arbitrary. If Ω=0, then R is constant on I0.
  4. Converse classification. Conversely, let a motion of a nondegenerate torque-free model have constant body angular velocity ω≡ω0 on its time window. Then Iω0=λω0 for some λ∈R: either ω0=0 and the orientation path is constant, or ω0≠0 and ω0 lies along a principal axis; in the latter case an orthonormal principal basis can be chosen with one vector ej=ω0/∥ω0∥2 and Ω=∥ω0∥2≠0, and the conclusions of clauses 2 and 3 hold in that adapted basis. It can be made positively oriented by negating a different basis vector. No alignment with the initially fixed basis is asserted when eigenvalues repeat.

The statement is conditional on the adopted model and zero-torque balance; it asserts no force, no measurement and no empirical law, and the existence clause is a statement about the model's kinematic class, not about nature.

Facts & Assumptions

Given: A nondegenerate model of Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope with principal basis (ej) and positive principal moments Ij, the zero-torque datum τ≡0, the balance Lc′=0, and the data j, Ω, I0, t0, R0 of the statement.

[L1]

Model data: Lc(t)=R(t)Iω(t) for every motion, C=∥Lc∥22=⟨l,l⟩ and E=12⟨l,I−1l⟩ are the torque-free invariants, and l′=l×(I−1l) under the zero-torque balance (Total momentum, kinetic-energy splitting and centre-of-mass angular momentum of a rigid-material motion clause 4, Torque-free motion of the rigid-material model: conservation of the angular momentum about the centre of mass, the energy-momentum invariants, the principal-axis equations and global existence of the spin dynamics clauses 1-2).

[L2]

Quaternion lifts: for a continuous ω:I0→R3 and q0∈S3 there is exactly one C1 curve q:I0→S3 with q(t0)=q0 and q′=12q φ(ω(t)); the curve R:=ρ∘q is C1 with values in SO(3) and R′(t)=R(t)Ωω(t), so ω is its body angular velocity (The quaternion lift of a prescribed continuous angular velocity: q′=12q φ(ω(t)) keeps S3 invariant, its rotation path has body angular velocity ω, and the initial value problem has a unique solution on the whole interval clauses 1-2, The quaternion rotation map ρ: conjugation on the imaginary quaternions, the unit sphere S3, and quaternion lifts). The covering map ρ:S3→SO(3) is surjective, every R∈SO(3) having exactly two preimages q and −q, under ACω (The quaternion rotation map ρ: conjugation on the imaginary quaternions, the unit sphere S3, and quaternion lifts second remark).

[L3]

Skew/cross correspondence: Ωωz=[ω]×z=ω×z, and for an SO(3)-valued curve the body angular velocity is the unique ω with RTR′=[ω]× (The skew-matrix/cross-product correspondence [ω]×z=ω×z and its conjugation law R[ω]×RT=[Rω]×, Body and spatial angular velocity of a rigid-material motion, and the material velocity field clause (a), The orthogonal group O(3) and the rotation group SO(3)).

[L4]

Matrix products: (Rl)′=R′l+Rl′ for the C1 curves R:I0→SO(3) and l:I0→R3; R′=R[ω]×; and a continuous curve on an interval with vanishing derivative is constant (Derivative rules for differentiable matrix-valued curves, and skewness of RTR′ for a curve in SO(3), A function continuous on an interval I whose derivative vanishes at every interior point of I is constant on I; consequently two such functions with the same derivative differ by a constant).

[L6]

Torque-free Euler equations: for the zero-torque branch the body angular velocity satisfies Iω′+ω×Iω=0; in particular, if ω is constant, then ω0×Iω0=0 (Euler's equations with torque for the rigid-material model, the rotational power identity, the torque-free reduction and frame covariance clause 1 and clause 4).

Proof

technique · direct; construct the rotation path by the quaternion lift of the constant body angular velocity, verify the zero-torque balance, read off the geometry, and prove the converse from the Euler equations
1.1givenL2L3

By [L2] the covering map ρ is surjective; choose q0∈S3 with ρ(q0)=R0, and let ω:I0→R3 be the constant curve ω(t):=Ωej, which is continuous. Clause 2 of [L2] supplies a C1 curve q:I0→S3 with q(t0)=q0 and q′=12qφ(ω), and clause 1 of [L2] shows that R:=ρ∘q:I0→SO(3) is C1 with R(t0)=R0 and R′(t)=R(t)Ωω(t); by [L3] this is RTR′=[Ωej]×, so the body angular velocity of R is the constant map Ωej by the uniqueness in [L3]. This is clause 1.

2.1step 1.1givenL1L4L5algebra

Let R be a path as in clause 1 and let c:I0→R3 be of class C2. Its body angular velocity is the constant ω≡Ωej by step 1.1, so l=Iω=ΩIjej is constant, and by [L1] Lc=Rl; with [L4], (Rl)′=R′l+Rl′=R[ω]×l+0=R(ω×l)=R(Ω2Ij ej×ej)=0 by [L5]. Moreover R′=R[ω]× is of class C1 because R is and [ω]× is constant, so R is of class C2 by definition of second differentiability and (c,R) is a configuration path of class C2; hence, on the model's time window I0, x(t,ρ)=c(t)+R(t)ρ is a motion of the model by Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope clause (ii). Since Lc is constant, the zero-torque balance Lc′=0 holds and the motion belongs to the torque-free branch; this is clause 2.

3.1step 2.1givenL1L4L5algebra

In the motions of step 2.1, l=ΩIjej and by [L1] and [L5] C=⟨l,l⟩=Ω2Ij2 and E=12⟨l,I−1l⟩=12Ω2Ij. If Ω≠0, then ΩIj≠0 and the identity Lc=ΩIjR(t)ej of step 2.1 gives R(t)ej=Lc/(ΩIj) with Lc constant, so the material axis R(t)ej is fixed in the inertial frame and the motion is the uniform rotation about that direction; if Ω=0, then R′=R[ω]×=R[0]=0, so R is constant by [L4]. This is clause 3.

4.1step 2.1givenL4L5L6algebra∎

For the converse, let a torque-free motion have constant body angular velocity ω≡ω0. By [L6] its body angular velocity satisfies Iω′+ω×Iω=0; with ω′=0 this reads ω0×Iω0=0. If ω0≠0, in the positively oriented principal coordinates, the coordinate formula for the cross product in [L5] makes this the vanishing of all 2×2 minors uivk−ukvi for u=ω0 and v=Iω0. Since ω0≠0, choose k with (ω0)k≠0; then vi=(vk/(ω0)k)(ω0)i for every i, so Iω0=λω0 for λ=vk/(ω0)k∈R and ω0 is an eigenvector of I. Within its eigenspace choose the unit vector ej=ω0/∥ω0∥2. Starting with the original principal vectors in that eigenspace, subtract their projection onto ej, and normalize a nonzero remainder if the eigenspace has dimension greater than one; subtract the projections onto both selected vectors and normalize a nonzero remainder if its dimension is three. Such remainders exist because the original vectors span the eigenspace; linear combinations remain eigenvectors for the same eigenvalue, and the projection subtractions give orthonormality by [L5]. Retain the original orthonormal vectors in the other eigenspaces. This supplies an adapted orthonormal principal basis directly in dimension three. Negating one of the other two basis vectors if necessary makes it positively oriented. In this adapted basis ω0=Ωej, Ω=∥ω0∥2≠0, without a simple-spectrum hypothesis; if ω0=0, then R′=R[0]=0 and R is constant by [L4]. In the nonzero case the path satisfies the identity of clause 1 with rate Ω, so clauses 2 and 3 apply to it. This is clause 4.

Remarks

  • Existence is a kinematic statement. Clause 1 constructs the orientation path; clause 2 then verifies the adopted zero-torque balance for it. Neither clause produces a force or a datum, and the curve c is arbitrary of class C2: the torque balance constrains the orientation path alone, in accordance with the absence of a momentum balance in Adoption of the external-torque branch of the rigid-material model: declared torque data and the balance of angular momentum about the centre of mass clause (vi).

  • Constancy of l and of ω is equivalent. The body inertia matrix I is fixed and invertible, so l=Iω and ω=I−1l show that either vector is constant exactly when the other is. Thus clause 4 also classifies motions with constant body angular momentum. Constancy of the magnitude alone is insufficient: the companion page exhibits a torque-free motion of a symmetric model with constant ∥ω∥2 and nonconstant ω. The classification does not claim that every torque-free motion is a uniform rotation.

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Linearization of the torque-free spin of the rigid-material model at a principal-axis spin: the oscillatory/exponential dichotomy and linear stability

Physical scope

The first-order linearization of the torque-free body-angular-velocity dynamics of a nondegenerate rigid-material model of Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope at a principal-axis spin Ωej, for pairwise distinct principal moments: the total derivative of the spin field, the explicit transverse equations, the sign criterion λj<0 for an extreme axis and λj>0 for the intermediate axis, the bounded oscillatory solutions in the extreme case and the exponentially growing solutions in the intermediate case, and the corresponding linear-stability verdicts in the sense of Invariant sets, orbital stability of an invariant set, and linear stability of an equilibrium. The statement concerns the linearized system only; no nonlinear Lyapunov conclusion is drawn here, and no measurement, damping, friction or empirical value is asserted.

Statement

Adopt a nondegenerate model of the rigid-material branch Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope with pairwise distinct principal moments in a positively oriented principal basis (e1,e2,e3), Iej=Ijej with Ij>0 (Principal axes and principal moments of the inertia data of a rigid-material model, axis moments and extremal values clauses (a) and (d)), and use it in the torque-free branch of Adoption of the external-torque branch of the rigid-material model: declared torque data and the balance of angular momentum about the centre of mass clause (iv). In the body-angular-velocity variable ω the torque-free dynamics is the autonomous field F(ω):=−I−1(ω×Iω),ω∈R3, on R3 (Euler's equations with torque for the rigid-material model, the rotational power identity, the torque-free reduction and frame covariance clause 4), and for every axis j and every Ω≠0 the constant path ωˉ≡Ωej is a solution (Principal-axis uniform rotations of the torque-free rigid-material model: existence, a fixed spatial direction, the invariants, and the converse classification clauses 1-3). Fix such j and Ω, and choose (a,b,j) cyclically: (a,b,j)=(2,3,1), (3,1,2) or (1,2,3). Thus (ea,eb,ej) is positively oriented. Put λj:=Ω2 (Ia−Ij)(Ij−Ib)IaIb≠0,κj:=∣λj∣. Then:

  1. The linearized field. F is totally differentiable at Ωej in the sense of The total (Fréchet) derivative Df(a) as the linear first-order approximation with o(∥h∥2) remainder, with total derivative Aj given on the principal basis by Ajea=Ω(Ij−Ia)Ib eb,Ajeb=Ω(Ib−Ij)Ia ea,Ajej=0, and there is a constant C≥0 with ∥F(Ωej+δ)−Ajδ∥2≤C∥δ∥22 for all δ∈R3.
  2. The linearized system and its dichotomy. Write δ=δaea+δbeb+δjej.
    • If Ij is a largest or smallest principal moment, then λj<0, every solution of the linearized system δ′=Ajδ has a unique maximal extension defined on all of R and bounded on [0,∞), with δa(t)=δa(0)cos⁡(κjt)+Ω(Ib−Ij)Iaκj δb(0)sin⁡(κjt), δb(t)=δb(0)cos⁡(κjt)+Ω(Ij−Ia)Ibκj δa(0)sin⁡(κjt), and δj constant; consequently the spin is linearly stable in the sense of Invariant sets, orbital stability of an invariant set, and linear stability of an equilibrium.
    • If Ij lies strictly between Ia and Ib, then λj>0, the same two formulas hold with cosh⁡ and sinh⁡ in place of cos⁡ and sin⁡ and κj=λj, the linearized system has unbounded solutions (for instance with δb(0)=0 and δa(0)≠0 satisfying δa(0)+Ω(Ib−Ij)Iaκjδb(0)≠0), and the spin is not linearly stable.

The statement is a statement about the linearized system at the spin; the corresponding nonlinear Lyapunov statements are separate items of this page, and no conclusion about the nonlinear stability of the spin is drawn here.

Facts & Assumptions

Given: A nondegenerate model of Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope with pairwise distinct principal moments Ij>0 in the positively oriented principal basis (ej), the zero-torque branch, and the data j, Ω≠0 of the statement.

[L1]

The torque-free spin equation: for the zero-torque branch the body angular velocity satisfies ω′=F(ω) with F(ω)=−I−1(ω×Iω) (Euler's equations with torque for the rigid-material model, the rotational power identity, the torque-free reduction and frame covariance clause 4, Body and spatial angular velocity of a rigid-material motion, and the material velocity field).

[L2]

The mathematical supplier (Linearization of the torque-free Euler system at a principal-axis spin, and the oscillatory/exponential dichotomy): let I1,I2,I3>0 be pairwise distinct, let I be the diagonal map with Iek=Ikek on the standard orthonormal basis and F(ω)=−I−1(ω×Iω); for Ω≠0 the field F is totally differentiable at Ωe3 with total derivative A satisfying (Aδ)1=Ω(I2−I3)δ2/I1, (Aδ)2=Ω(I3−I1)δ1/I2, (Aδ)3=0 and ∥F(Ωe3+δ)−Aδ∥2≤C∥δ∥22 for the explicit constant C=∥I−1∥F∥I∥F; with λ=Ω2(I2−I3)(I3−I1)/(I1I2) the linearized system δ′=Aδ has constant δ3 and solves the transverse pair by cos⁡,sin⁡ when λ<0 (with κ=−λ, bounded solutions) and by cosh⁡,sinh⁡ when λ>0 (with κ=λ, unbounded solutions and the growth criterion of the supplier), and λ<0 exactly when I3 is a largest or smallest moment, λ>0 exactly when it lies strictly between I1 and I2 (The total (Fréchet) derivative Df(a) as the linear first-order approximation with o(∥h∥2) remainder, Intervals of R: the nine order-convex forms, nondegeneracy, and length).

[L3]

Linear stability: for an equilibrium of an autonomous system with total derivative L, the linearized system is y′=Ly, and the equilibrium is linearly stable when every maximal solution of the linearized system is defined for all t≥0 and bounded on [0,∞) (Invariant sets, orbital stability of an invariant set, and linear stability of an equilibrium).

[L4]

The spin is a solution: for every axis j and rate Ω the constant body angular velocity Ωej belongs to a torque-free motion with l=Iω=ΩIjej constant (Principal-axis uniform rotations of the torque-free rigid-material model: existence, a fixed spatial direction, the invariants, and the converse classification clauses 1-3).

[L5]

Principal data: (e1,e2,e3) is a positively oriented orthonormal basis and I is diagonal with positive entries in it, ∥⋅∥2 denoting the Euclidean norm (Principal axes and principal moments of the inertia data of a rigid-material model, axis moments and extremal values clauses (a)-(b) and (d), The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn, The cross product in R3).

[L6]

For Q∈SO(3) the cross product is equivariant, Q(u×v)=(Qu)×(Qv) (The skew-matrix/cross-product correspondence [ω]×z=ω×z and its conjugation law R[ω]×RT=[Rω]× clause 3 and proof step 1.3). An orthonormal principal basis can be made positively oriented by replacing one eigenvector by its negative; the associated eigenvalues are unchanged.

Proof

technique · direct; identify the principal basis with the supplier's standard basis so that the spin axis is third, apply its clauses, and translate the sign criterion and the boundedness conclusion
1.1givenL1L4L5

The spin Ωej is a solution of ω′=F(ω) on every interval with at least two points, because it is the constant body angular velocity of the torque-free motion of [L4] and [L1] is the same equation; with l=Iω=ΩIjej and I−1l=Ωej the right-hand side F(Ωej)=−I−1(Ωej×ΩIjej)=0 vanishes.

1.2givenL2L5L6algebra

Identify R3 with the supplier's R3 of [L2] by the map Q carrying its standard basis to the cyclic basis (ea,eb,ej). By the positive orientation stipulated in [L5], Q∈SO(3), so Q(u×v)=(Qu)×(Qv) ([L6]); then the supplier's diagonal map with entries (Ia,Ib,Ij) is the model's inertia operator I expressed in the principal basis [L5], and the fields F(ω)=−I−1(ω×Iω) correspond. Clause 1 of [L2] applied at the spin about the third basis vector gives the total differentiability of F at Ωej and the derivative Aj of clause 1: the components are (Ajδ)a=Ω(Ib−Ij)δb/Ia, (Ajδ)b=Ω(Ij−Ia)δa/Ib, (Ajδ)j=0, so evaluating at ea and eb gives exactly the stated basis images. The supplier also gives the remainder bound and explicit constant, and clauses 2-3 of [L2] give the transverse formulas, the criterion for the sign of λj=Ω2(Ia−Ij)(Ij−Ib)/(IaIb) and the bounded/unbounded alternatives. The displayed sine/cosine and hyperbolic formulas are defined on all of R, satisfy the linear system, and have the prescribed initial data; the uniqueness assertion in the supplier proof makes every local solution their restriction. This is clause 1 and the case analysis of clause 2 up to the sign criterion.

2.1step 1.2givenL2algebra

The product (Ia−Ij)(Ij−Ib) is positive exactly when Ij lies strictly between Ia and Ib and negative exactly when Ij is larger than both or smaller than both; since Ω2/(IaIb)>0, the criterion of clause 3 of [L2] reads: λj<0 (oscillatory, bounded, the displayed cos⁡,sin⁡ formulas with κj=−λj) exactly for the extreme axes, and λj>0 (the cosh⁡,sinh⁡ formulas with κj=λj, unbounded solutions, the stated growth criterion) exactly for the intermediate axis. This completes clause 2.

3.1step 1.2step 2.1givenL3∎

By [L3] the boundedness of every global maximal solution of the linearized system on [0,∞) in the extreme case is exactly linear stability of the spin, and the existence of an unbounded solution in the intermediate case is the failure of linear stability, since a solution that is unbounded on [0,∞) is not bounded there.

Remarks

  • The linearization variable. The linearization is taken in the body-angular-velocity variable ω; because l=Iω with I a fixed invertible linear map, stability and boundedness statements transfer between the ω- and l-variables up to the fixed constants Imin⁡ and Imax⁡, and the two formulations are equivalent for the linearized system.

  • Linear versus nonlinear. Clause 2 is a statement about the linearized system. Exponential growth of a linearized solution does not by itself prove nonlinear instability, and boundedness of the linearized system does not by itself prove nonlinear Lyapunov stability; the nonlinear statements are proved separately in Nonlinear stability of the torque-free spin of the rigid-material model about an extreme principal axis, and instability about the intermediate axis, with an explicit escape time and the orientation caveat, which uses the conserved quantities rather than the linearization.

  • Distinctness is a real hypothesis. The supplier requires pairwise distinct principal moments and the case analysis uses it; repeated moments change the equilibrium set and are not covered by this statement.

Physics theoremStatement: AI-adaptedProof: AI-adaptedprecheck passOpen item page →

Nonlinear stability of the torque-free spin of the rigid-material model about an extreme principal axis, and instability about the intermediate axis, with an explicit escape time and the orientation caveat

Physical scope

Lyapunov stability and instability of the torque-free spin of a nondegenerate rigid-material model of Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope with pairwise distinct principal moments, stated for the model's motions with time window containing [0,∞): spins about the largest and smallest principal axes are Lyapunov stable in the body angular momentum, with an explicit conserved deviation bound, and spins about the intermediate axis are unstable with an explicit escape time; the escaping perturbation is realised by an actual torque-free motion. The stability is a statement about the body-frame angular momentum and angular velocity only: two motions with the same constant body angular velocity can have orientations differing by a fixed nontrivial rotation at every time, so no orientation stability is asserted. No measurement, damping, dissipation or empirical value is asserted; the countable-choice assumption is inherited for finite mass moments and inertial integrals, and for the double-cover supplier used in the quaternion constructions. The stability and escape calculations for a given positive diagonal inertia matrix introduce no additional choice principle.

Statement

Assume the Axiom of Countable Choice ACω (The Axiom of Countable Choice (ACω)), carried through Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope clause (i) and Inertia matrix, spatial inertia tensor, inertia tensor about a point and moment of inertia about an axis of a rigid-material model for finite mass moments, through Adoption of the external-torque branch of the rigid-material model: declared torque data and the balance of angular momentum about the centre of mass clause (i) and the inertial-integral suppliers of Euler's equations with torque for the rigid-material model, the rotational power identity, the torque-free reduction and frame covariance and Torque-free motion of the rigid-material model: conservation of the angular momentum about the centre of mass, the energy-momentum invariants, the principal-axis equations and global existence of the spin dynamics, and through the double-cover supplier of The quaternion rotation map ρ: conjugation on the imaginary quaternions, the unit sphere S3, and quaternion lifts for the surjectivity used to choose initial unit quaternions. The stability and escape calculations for a given positive diagonal I introduce no additional choice principle. Adopt a nondegenerate model of the rigid-material branch Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope with pairwise distinct principal moments, and label a positively oriented principal basis (e1,e2,e3), Iej=Ijej, so that I1<I2<I3. Use the model in the torque-free branch of Adoption of the external-torque branch of the rigid-material model: declared torque data and the balance of angular momentum about the centre of mass clause (iv). Along any motion write l:=Iω; the torque-free l-path solves l′=l×(I−1l) and is the restriction of a solution defined on all of R (Torque-free motion of the rigid-material model: conservation of the angular momentum about the centre of mass, the energy-momentum invariants, the principal-axis equations and global existence of the spin dynamics clauses 2 and 4). Write I0 for the model's time window. All physical realizations below use paths restricted to I0; clause 3's forward-time realization assumes [0,∞)⊆I0. Let L≠0. Then:

  1. Stability of the extreme-axis spins. For j=1 and j=3 the constant path t↦Lej is Lyapunov stable for the l-system (Equilibria, Lyapunov stability and asymptotic stability of an autonomous first-order system): for every ε>0 there is δ∈(0,ε] such that every maximal solution l with ∥l(0)−Lej∥2<δ is defined for all t≥0 and satisfies ∥l(t)−Lej∥2<ε for all t≥0. Consequently every torque-free motion of a model of the branch whose time window contains [0,∞) and whose datum satisfies ∥l(0)−Lej∥2<δ has, with Ω:=L/Ij, ∥l(t)−Lej∥2<ε,∥ω(t)−Ωej∥2<εImin⁡(t≥0), where Imin⁡=I1.
  2. Explicit deviation bound. For j=1 define on R3 c1:=12(1I1−1I2)>0,D1(l):=12(⟨l,l⟩I1−⟨l,I−1l⟩) ≥0, and for j=3 c3:=12(1I2−1I3)>0,D3(l):=12(⟨l,I−1l⟩−⟨l,l⟩I3) ≥0. Along every solution of l′=l×(I−1l) one has, for all t in its interval, with l(0) evaluated on its unique global extension if the original interval does not contain 0, l2(t)2+l3(t)2≤D1(l(0))c1,l1(t)2+l2(t)2≤D3(l(0))c3.
  3. Instability of the intermediate-axis spin. The spin l0:=Le2 is not Lyapunov stable. More precisely, with a:=1/I1−1/I21/I2−1/I3>0,c0:=a(1I2−1I3)32 ∣L∣>0,δ0:=∣L∣21+a2,ε0:=∣L∣2, if [0,∞)⊆I0, then for every δ>0 there are a torque-free motion of this model on I0, with body angular velocity ω, and a time t≥0 such that ∥l(0)−Le2∥2<δ,∥l(t)−Le2∥2≥ε0, and the escape can be arranged with t≤c0−1log⁡(δ0/η) for any prescribed η∈(0,min⁡{δ0,δ}) whose initial datum lη:=(η, σL2−(1+a2)η2, −σaη), σ:=L/∣L∣, satisfies ∥lη−Le2∥2<δ. Such η exist arbitrarily close to zero, and the datum belongs to the l-system.
  4. Orientation caveat. For j=1 or j=3 and every Ω≠0 there are two torque-free motions of the model, with c≡0, whose body angular velocities are both constantly equal to Ωej and whose orientation paths R1,R2 satisfy R2(t)=R1(t)S for every t and a fixed rotation S≠I3. Consequently clause 1 asserts nothing about the closeness of the orientations of two motions.

The statement is conditional on the adopted model and zero-torque balance; it asserts no force, no damping, no measurement and no empirical law.

Facts & Assumptions

Given: A nondegenerate model of Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope with positively oriented principal basis (ej) and moments I1<I2<I3, positive; the zero-torque branch; the data L≠0 and the auxiliary constants a,c0,δ0,ε0,c1,c3,D1,D3 of the statement.

[L1]

The torque-free system and its invariants: with l=Iω one has l′=l×(I−1l); ⟨l,l⟩ and 12⟨l,I−1l⟩ are constant along solutions; every solution has a unique maximal extension to all of R; and l=Iω with I diagonal positive in the principal basis, so ∥ω∥2≤∥l∥2/Imin⁡ and ∥l∥2≤Imax⁡∥ω∥2 (Torque-free motion of the rigid-material model: conservation of the angular momentum about the centre of mass, the energy-momentum invariants, the principal-axis equations and global existence of the spin dynamics clauses 2-4, Euler's equations with torque for the rigid-material model, the rotational power identity, the torque-free reduction and frame covariance clause 4, Principal axes and principal moments of the inertia data of a rigid-material model, axis moments and extremal values clauses (a) and (d), Inertia matrix, spatial inertia tensor, inertia tensor about a point and moment of inertia about an axis of a rigid-material model).

[L2]

Stability supplier (Lyapunov stability of spin about the largest and smallest principal axes of the torque-free top): for positive reals I1<I2<I3, the diagonal map I and the field F(l)=l×(I−1l) on R3, the equilibria Le1 and Le3, L≠0, are Lyapunov stable in the sense of Equilibria, Lyapunov stability and asymptotic stability of an autonomous first-order system: for j=1,3 and every ε>0 there is δ∈(0,ε] such that every maximal solution with ∥l(0)−Lej∥2<δ is defined for all t≥0 and satisfies ∥l(t)−Lej∥2<ε for all t≥0.

[L3]

Instability supplier (Instability of spin about the intermediate principal axis of the torque-free top): its Statement gives the existential instability and time bound. Its Proof, second through sixth numbered steps, gives the stronger prescribed-datum conclusion used here: in the same setting, Le2 is an equilibrium which is not Lyapunov stable, and with the constants a,c0,δ0 of the statement and ε0=∣L∣/2, for every δ>0 there is a solution l of the l-system with ∥l(0)−Le2∥2<δ and some t≥0 with ∥l(t)−Le2∥2≥ε0; the escape can be arranged at a time t≤c0−1log⁡(δ0/η) from the datum lη of the statement for every 0<η<min⁡{δ0,δ} additionally satisfying ∥lη−Le2∥2<δ; such data exist arbitrarily close to the spin as η↓0.

[L4]

Realisability: for every continuous ω:R→R3 there is a C1 rotation path R:R→SO(3) whose body angular velocity is ω; if ω is C1 then R is of class C2; and for q0∈S3 with ρ(q0)=R0 the path can be chosen with R(t0)=R0, the covering map ρ being surjective with ρ(q1q2)=ρ(q1)ρ(q2) on S3 (The quaternion lift of a prescribed continuous angular velocity: q′=12q φ(ω(t)) keeps S3 invariant, its rotation path has body angular velocity ω, and the initial value problem has a unique solution on the whole interval clauses 1-2, The quaternion rotation map ρ: conjugation on the imaginary quaternions, the unit sphere S3, and quaternion lifts and its second remark).

[L5]

The balance check ingredients: for a C1 curve R:I→SO(3) and a C1 curve l:I→R3 one has (Rl)′=R′l+Rl′, R′=R[ω]×, and [ω]×z=ω×z; the cross product is bilinear and alternating with ω×l=−(l×ω) (Derivative rules for differentiable matrix-valued curves, and skewness of RTR′ for a curve in SO(3), The skew-matrix/cross-product correspondence [ω]×z=ω×z and its conjugation law R[ω]×RT=[Rω]×, The cross product is bilinear, alternating, and orthogonal to both factors, The cross product in R3); and a C2 curve c together with a C2 rotation path forms a motion x=c+Rρ of the model (Configuration, configuration space and orientation of a rigid-material model in an inertial frame, Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope clause (ii)).

[L6]

The spin motions of Principal-axis uniform rotations of the torque-free rigid-material model: existence, a fixed spatial direction, the invariants, and the converse classification clauses 1-3 realise every constant body angular velocity Ωej, j=1,2,3, Ω≠0, as the body angular velocity of a torque-free motion with l=ΩIjej constant, and Lc=ΩIjR(t)ej is constant along it.

[L7]

The orientation construction uses the imaginary quaternion φ(ej) with N(φ(ej))=1 and φ(ej)2=−1, so that r:=φ(ej)∈S3 and rφ(ω)=φ(ω)r for ω=Ωej (The quaternion rotation map ρ: conjugation on the imaginary quaternions, the unit sphere S3, and quaternion lifts, The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn).

Proof

technique · direct; quote the two supplier theorems for the $l$-system, translate to the model's motions through $l=I\omega$, realise the escaping $l$-path as a motion by the quaternion lift and the balance check, and separate the orientation statement from the angular-momentum statement
1.1givenL1L2L5

The positively oriented principal basis has a basis matrix Q∈SO(3); the skew/cross correspondence of [L5] gives Q(u×v)=(Qu)×(Qv), so l↦l×(I−1l) is the supplier's positive diagonal field in those coordinates. Clause 1 of [L2] gives for j=1 and j=3 and every ε>0 a δ∈(0,ε] such that every maximal solution with ∥l(0)−Lej∥2<δ is defined for all t≥0 and satisfies ∥l(t)−Lej∥2<ε; by [L1] a maximal solution is a solution defined on R, so this is exactly the Lyapunov stability of Lej for the l-system, and the equilibrium property F(Lej)=0 holds by the alternation of the cross product in [L5].

1.2givenL1algebra

The functions D1 and D3 of clause 2 are nonnegative, since in the principal basis with l=∑klkek one has D1(l)=12∑k(1/I1−1/Ik)lk2 and D3(l)=12∑k(1/Ik−1/I3)lk2 with all coefficients nonnegative by I1<I2<I3; and 2D1(l)≥(1/I1−1/I2)(l22+l32) and 2D3(l)≥(1/I2−1/I3)(l12+l22) because the remaining coefficients are at least these. By [L1] the two combinations ⟨l,l⟩ and ⟨l,I−1l⟩ are constant along every solution, so D1 and D3 are constant along solutions and the two displayed inequalities of clause 2 follow.

2.1step 1.1givenL1L3algebra

Fix an admissible prescribed η from clause 3. Apply the invariant-branch argument of [L3] with the auxiliary number η0:=(η+δ0)/2, so 0<η<η0<δ0, as required in that supplier's second proof step. That argument starts with exactly l(0)=lη, with C=L2 and E=L2/(2I2); until l1 first reaches δ0, it obtains l3=−σal1, σl2≥3∣L∣/2 and l1′≥c0l1. Its fifth and sixth steps therefore give a first hitting time t≤c0−1log⁡(δ0/η) and ∥l(t)−Le2∥22≥(1+a2)δ02=L2/4. The construction applies to every such η, not only to an existentially chosen perturbation. The additional initial-norm condition gives ∥l(0)−Le2∥2<δ, and lη→Le2 as η↓0 ensures admissible data for every δ>0. This proves the prescribed-datum escape and, since ε0=∣L∣/2>0 is fixed, instability.

2.2step 1.1givenL1

Let a torque-free motion have time window containing [0,∞) and datum with ∥l(0)−Lej∥2<δ, j∈{1,3}, for the δ of step 1.1. Its l-path is a solution of the l-system by [L1], so ∥l(t)−Lej∥2<ε for all t≥0; and since l=Iω with I diagonal with entries I1,I2,I3, the difference l(t)−Lej=I(ω(t)−Ωej) with Ω=L/Ij gives ∥ω(t)−Ωej∥2≤∥l(t)−Lej∥2/Imin⁡<ε/Imin⁡ by [L1]. This completes clause 1.

3.1step 2.1givenL1L4L5

Realise the escaping l-path of step 2.1 as a motion. Let l:R→R3 be the global solution of the l-system with datum l(0)=lη (global by [L1]), and put ω:=I−1l, which is continuous and of class C1 because l solves a locally Lipschitz equation; by [L4] there is a C2 rotation path R:R→SO(3) with body angular velocity ω, with any prescribed initial orientation R(0)=R0∈SO(3) by choosing a preimage q0 of R0. Assume [0,∞)⊆I0 as in clause 3, restrict R and l to I0, and define x:I0×R3→R3 by x(t,ρ):=R(t)ρ with c≡0. This is a motion of the same model by [L5], and its domain includes the escape time. Its body angular velocity is ω, so its l-data are l, and its zero-torque balance holds: with [L5], (Rl)′=R′l+Rl′=R[ω]×l+Rl′=R(ω×l+l′)=0 because l′=l×(I−1l)=l×ω=−ω×l. Hence the motion is a torque-free motion of the branch with l(0)=lη, ∥l(0)−Le2∥2<δ, and ∥l(t)−Le2∥2≥ε0 at the escape time t≤c0−1log⁡(δ0/η) of step 2.1. This is clause 3.

4.1step 2.2givenL4L6L7algebra∎

For clause 4, put ω≡Ωej and let r:=φ(ej)∈S3, so that r φ(ω)=φ(ω) r by [L7] and N(r)=1. By [L4] choose q0∈S3 with ρ(q0)=R0 for a fixed R0∈SO(3), let q:R→S3 be the lift of ω with q(0)=q0, and put q2(t):=q(t)r; then q2 is C1, takes values in S3 because N is multiplicative, and solves q2′=q′r=12qφ(ω)r=12q2φ(ω) by the commutation in [L7], with q2(0)=q0r. Let R1:=ρ∘q and R2:=ρ∘q2; by the homomorphism property in [L4], R2(t)=ρ(q(t))ρ(r)=R1(t)S with S:=ρ(r)∈SO(3), and S≠I3 because ρ(r) acts as the half-turn about the axis ej: Sej=ej and Sea=−ea for a≠j by the conjugation formula and φ(ej)2=−1 in [L7]. Both R1 and R2 have body angular velocity Ωej by [L4] and so, after restriction to I0 and with c≡0, are torque-free motions by clause 2 of Principal-axis uniform rotations of the torque-free rigid-material model: existence, a fixed spatial direction, the invariants, and the converse classification; their orientations differ by the fixed rotation S≠I3 at every time, which is clause 4.

Remarks

  • What is stable. Clauses 1 and 3 are statements about the body-frame angular momentum l=Iω (equivalently, through the fixed invertible I, about the body angular velocity ω). The orientation of the body in the inertial frame is not controlled, as clause 4 makes explicit; the spin phase about the axis is free.

  • Why the intermediate axis is different. The two conserved quantities C=⟨l,l⟩ and E=12⟨l,I−1l⟩ confine the l-path to a compact set, but near Le2 that set is a pair of curves through the equilibrium along which l1 grows exponentially until the transverse components exchange roles; the explicit datum lη and the escape time of clause 3 make the instability effective, and clause 3's realisation shows that it is a statement about motions, not merely about solutions of a differential equation.

  • No dissipation. The torque-free branch has no damping; with a nonzero datum τ, the statements of this item do not apply, and a dissipative torque model would require its own analysis. The result also asserts no empirical value and no claim that any concrete body has been observed to spin stably or unstably.

PostulateStatement: AI-adaptedProof: Not applicableOpen item page →

Adoption of the heavy symmetric top branch: axisymmetric rigid material, a fixed pivot material point, a uniform gravitational field and the balance of angular momentum about the pivot

Physical scope

Adoption of the heavy symmetric top branch of the rigid-material model: a reference mass distribution whose body inertia matrix is diag(A_c,A_c,C_c) about a declared symmetry axis, a material point held fixed at the origin of the inertial frame (the pivot, on the symmetry axis at distance d from the centre of mass, so that the centre of mass lies on the sphere of radius d about the pivot), an ideal pivot mechanism contributing no torque about the pivot in the framework's sense of a frictionless hinge, a uniform gravitational field of magnitude g directed along −e3, and the adopted balance of angular momentum about the pivot. The branch excludes friction and driving torques at the pivot, rolling and sliding contacts, non-axisymmetric bodies and non-uniform fields, and asserts no measured value and no claim that a concrete top or gyroscope realises it.

Postulate

Adopt as physical assumptions of the framework the following heavy symmetric top branch of the rigid-material model, in the setting of Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope.

(i) Setting. A model of the branch carries the data of Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope: a reference mass distribution ν with total mass m>0 and centred reference coordinates, a time window I0, an inertial frame with adapted coordinates (t,x) (Inertial frames, stationary observers and the adopted Galilean transformations between frames), whose origin is chosen at the pivot point of clause (iii), and a motion x(t,ρ)=c(t)+R(t)ρ with configuration path (c,R) of class C2 (Configuration, configuration space and orientation of a rigid-material model in an inertial frame). Assume the Axiom of Countable Choice ACω (The Axiom of Countable Choice (ACω)), used only through the integrals of the model's inertial quantities. Fix once and for all an orthonormal basis (e1,e2,e3) of the reference coordinates.

(ii) Axisymmetry and the declared parameters. The body inertia matrix of the model (Inertia matrix, spatial inertia tensor, inertia tensor about a point and moment of inertia about an axis of a rigid-material model clause (a)) is I=Ac (e1e1T+e2e2T)+Cc e3e3T,Ac>0, Cc>0, so that e3 is the symmetry axis; the numbers Ac, Cc are declared model parameters of dimension μℓ2, read in kilogram metres squared, and are not measured within the framework. The branch also declares a pivot distance d>0 of dimension ℓ and a field strength g>0 of dimension ℓτ−2, read in metres per second squared (Dimensions and SI unit conventions of the non-relativistic classical mechanics framework).

(iii) The pivot constraint. The material point of reference coordinate ρp:=−d e3 is the pivot material point; it lies on the symmetry axis at distance d from the centre of mass. The motions of the branch are those satisfying c(t)+R(t)ρp=0(t∈I0), that is c(t)=d R(t)e3: the pivot material point is held fixed at the origin of the inertial frame for the whole time window, and the centre of mass lies on the sphere of radius d about the origin. The constraint is maintained by a mechanism (a bearing, a hinge or a fine support) whose force system is ideal in the sense adopted for frictionless hinges in Adopted ideal-reaction law for holonomic constraints: the d'Alembert condition, its scope and its limits clause (iii) together with the virtual-work law of its clause (i): the mechanism exerts on the body a force system equivalent to a single force applied at the pivot point, so that its total torque about the origin vanishes. The holonomic-constraint vocabulary of Holonomic-constraint models of the force branch: constraint data, the constrained equation, virtual displacements and the scleronomic/rheonomic distinction — constrained curve families, reaction fields and the declaration that the constraint is maintained by an additional force contribution — is the framework's account for finitely many particle labels; the present model is a continuum, and this clause adopts the analogous idealisation for it. No friction, damping or driving torque at the pivot is asserted; such torques are excluded and would have to be declared as part of a torque datum with their own model.

(iv) The uniform gravitational field. The model declares a uniform gravitational acceleration G:=−g e3 of dimension ℓτ−2: every material point of the body is subject to the external force G dν, that is, the force per unit mass is the constant vector −ge3 (The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn, The cross product in R3 for the spatial vectors). The field is a model idealisation: it asserts neither a particular direction in any absolute sense (the direction e3 is a declared frame direction) nor a measured value of g, and it is not asserted to represent the Earth's or any planet's field. The resultant of this force system and its total torque about a point are computed in the reduction theorem of this page; in particular the resultant is the total weight −mge3 applied at the centre of mass.

(v) The adopted dynamics. Along every motion of the branch adopt the balance of angular momentum about the pivot: with Jp(t):=∫(x(t,ρ)−0)×∂tx(t,ρ) dν(ρ) the angular momentum of the model about the origin, and with τp(t) the total external torque about the origin — the sum of the gravitational torque and of the pivot reaction torque, the latter vanishing by clause (iii) — adopt Jp′(t)=τp(t)(t∈I0). This is an adopted dynamical law of the branch, analogous to but distinct from the balance of Adoption of the external-torque branch of the rigid-material model: declared torque data and the balance of angular momentum about the centre of mass clause (iii) about the centre of mass; it acquires content only together with the kinematic constraint of clause (iii) and the external force system of clause (iv). No equation of motion for the pivot reaction is asserted: the reaction is whatever force the ideal mechanism supplies, and its torque about the origin is zero by clause (iii).

(vi) Scope and exclusions. The branch excludes non-axisymmetric bodies (Ac and Cc are the two transverse and the axial moment and no other inertia data are used), bodies whose mass distribution fails to produce this inertia matrix, non-uniform gravitational fields, friction and driving torques at the pivot, rolling or sliding contacts, impacts, deformable bodies and variable mass, and every relativistic or quantum description. It asserts no force law for the pivot reaction, no conservation law and no measured value of Ac, Cc, m, d or g. Whether the branch is adequate for a given apparatus — a top on a bearing, a gyroscope in a gimbal, a spinning shell — is decided by comparing the model's conditional predictions with reported observations of that apparatus under its stated regime, and agreement is evidence about the combined model and apparatus, not a proof of the idealisation.

(vii) Relation to the other balances. The balance of clause (v) is not claimed to be a consequence of the centre-of-mass balance of Adoption of the external-torque branch of the rigid-material model: declared torque data and the balance of angular momentum about the centre of mass clause (iii), nor conversely; the two are separate adopted laws about different points, and neither is deduced from the framework's particle balances. A model may use both simultaneously, and the reduction theorem of this page uses only clause (v) together with clauses (ii)-(iv).

Physics theoremStatement: AI-adaptedProof: AI-adaptedprecheck passOpen item page →

Reduction of the heavy symmetric top branch: pivotal angular momentum, Euler-angle equations, the two conserved momenta and the one-dimensional θ equation

Physical scope

Conditional deductions inside the heavy symmetric top branch of Adoption of the heavy symmetric top branch: axisymmetric rigid material, a fixed pivot material point, a uniform gravitational field and the balance of angular momentum about the pivot for the rigid-material model of Adoption of the rigid-material model branch: reference mass distribution, rigid placements, orientation and scope: the angular momentum about the pivot equals RI~ω with I~ the inertia about the pivot; the pivot balance gives the body-frame equations; and on any interval on which the orientation is described by the Euler-angle chart with θ∈(0,π) the motion satisfies the heavy-top system with parameters equal to the pivot transverse moment A=Ac+md2, the axial moment C=Cc, the total mass m, the pivot distance d and the field strength g, so the conserved momenta, the reduced energy and the one-dimensional θ equation hold. The statement carries the countable-choice assumption used only for the finiteness of the defining integrals, assumes the chart description as an explicit hypothesis, asserts nothing at the chart's poles, excludes friction and driving torques at the pivot, and asserts no measured value.

Statement

Assume the Axiom of Countable Choice ACω (The Axiom of Countable Choice (ACω)), used only for the finiteness of the defining integrals of the model's inertial quantities. Adopt the heavy symmetric top branch Adoption of the heavy symmetric top branch: axisymmetric rigid material, a fixed pivot material point, a uniform gravitational field and the balance of angular momentum about the pivot with parameters Ac>0, Cc>0, d>0, g>0 and total mass m>0; use the notation of that postulate: the pivot material point ρp=−d e3 is held at the origin, so c(t)=d R(t)e3; the pivot reaction contributes no torque about the origin; and the external gravitational field is G=−ge3 with total torque about the origin τp(t)=−mgd (R(t)e3)×e3. Put A:=Ac+md2>0,C:=Cc>0, the transverse moment of the model about the pivot and its axial moment. Let x(t,ρ)=c(t)+R(t)ρ be a motion of the branch with time window I0, and suppose that there are functions φ,θ,ψ:I0→R of class C2 with θ(I0)⊆(0,π) and R(t)=Θ(φ(t),θ(t),ψ(t))=Rz(φ(t))Ry(θ(t))Rz(ψ(t))(t∈I0), the Euler-angle description of The Euler-angle parametrization and the heavy symmetric top system. Then:

  1. Angular momentum about the pivot. With ω the body angular velocity of the motion and I~:=A (e1e1T+e2e2T)+C e3e3T (the diagonal matrix diag(A,A,C) in the principal basis) one has Jp(t):=∫x(t,ρ)×∂tx(t,ρ) dν(ρ)=R(t) I~ ω(t), and the balance of Adoption of the heavy symmetric top branch: axisymmetric rigid material, a fixed pivot material point, a uniform gravitational field and the balance of angular momentum about the pivot clause (v) reads Jp′=τp with τp(t)=−mgd (R(t)e3)×e3,τp(t)⋅e3=0.
  2. Body-frame pivot equations. With γ(t):=R(t)Te3, I~ ω′+ω×I~ ω=−mgd (e3×γ)on I0, that is, componentwise in the principal basis, Aω1′=(A−C)ω2ω3+mgd γ2,Aω2′=(C−A)ω1ω3−mgd γ1,Cω3′=0. Under the Euler-angle description of the statement, γ=(−sin⁡θcos⁡ψ, sin⁡θsin⁡ψ, cos⁡θ),ω3=ψ′+φ′cos⁡θ.
  3. Reduction to one dimension. Define on I0 b:=C(ψ′+φ′cos⁡θ),a:=A φ′sin⁡2θ+bcos⁡θ. Then b and a are constant on I0; consequently φ′=a−bcos⁡θAsin⁡2θ,ψ′=bC−(a−bcos⁡θ)cos⁡θAsin⁡2θ; the reduced energy E:=12A θ′2+(a−bcos⁡θ)22Asin⁡2θ+b22C+mgdcos⁡θ is constant on I0; and with the effective potential U(θ):=(a−bcos⁡θ)22Asin⁡2θ+b22C+mgdcos⁡θ one has A θ′′=−U′(θ) on I0.
  4. The heavy-top system. Equivalently, (φ,θ,ψ) is a heavy-top trajectory of The Euler-angle parametrization and the heavy symmetric top system with parameters (A,C,m,d,g), and clauses 1-4 of Reduction of the heavy symmetric top system: conserved momenta, one-dimensional θ equation and conserved reduced energy hold for it.

The statement assumes the Euler-angle description as a hypothesis on the interval: no claim is made that every motion of the branch admits such a description, that a description extends across the poles θ∈{0,π} (where the sleeping-top and hanging configurations lie), or that the description is unique. On every subinterval on which a description with θ∈(0,π) exists, the conclusions hold there. The statement asserts no friction or driving torque at the pivot, no measurement and no empirical value.

Facts & Assumptions

Given: The heavy-top branch data Ac,Cc,d,g,m, the derived constants A=Ac+md2 and C=Cc, a motion x(t,ρ)=c(t)+R(t)ρ of the branch with time window I0, and a C2 Euler-angle description (φ,θ,ψ) of R with θ(I0)⊆(0,π).

[L1]

Branch kinematics: the pivot material point ρp=−de3 satisfies c(t)+R(t)ρp=0, so c(t)=d R(t)e3; the pivot reaction contributes no torque about the origin; the gravitational torque about the origin is τp=mc×(−ge3); and the adopted balance is Jp′=τp with Jp=∫x×∂tx dν (Adoption of the heavy symmetric top branch: axisymmetric rigid material, a fixed pivot material point, a uniform gravitational field and the balance of angular momentum about the pivot clauses (iii)-(v), Configuration, configuration space and orientation of a rigid-material model in an inertial frame, Body and spatial angular velocity of a rigid-material motion, and the material velocity field).

[L2]

Inertial identities of the model: P:=∫∂tx dν=mc′, Lc:=∫(x−c)×(∂tx−c′) dν=RIω, and for Jp=∫x×∂tx dν one has Jp=Lc+c×P (Total momentum, kinetic-energy splitting and centre-of-mass angular momentum of a rigid-material motion clauses 2 and 4, The Lebesgue integral is linear on L1(μ), Finiteness of the moments of a bounded finite Borel measure on R3, Mass distributions on R3: total mass, first moment and inertia matrix).

[L4]

Euler-angle kinematics: for R=Θ(φ,θ,ψ) with θ∈(0,π) the body angular velocity is ω=(−φ′sin⁡θcos⁡ψ+θ′sin⁡ψ, φ′sin⁡θsin⁡ψ+θ′cos⁡ψ, ψ′+φ′cos⁡θ) in the standard basis, and ω12+ω22=θ′2+φ′2sin⁡2θ (Angular velocity in Euler angles: ω3=ψ′+φ′cos⁡θ and ω12+ω22=θ′2+φ′2sin⁡2θ); the coordinate rotation matrices satisfy Ry(a)e3=sin⁡a e1+cos⁡a e3 and Rz(b)Te1=cos⁡b e1−sin⁡b e2, Rz(b)Te3=e3 (The coordinate rotation matrices Rz(a) and Ry(a): values in SO(3), composition law, and derivatives); and sin⁡2+cos⁡2=1 (Sine and cosine defined by their real power series, The derivatives of sine and cosine are cosine and minus sine).

[L5]

The heavy-top system: The Euler-angle parametrization and the heavy symmetric top system defines a heavy-top trajectory by the three displayed equations ddt(Aφ′sin⁡2θ+Ccos⁡θ(ψ′+φ′cos⁡θ))=0, ddt(Aθ′)=Aφ′2sin⁡θcos⁡θ−C(ψ′+φ′cos⁡θ)φ′sin⁡θ+mgdsin⁡θ and ddt(C(ψ′+φ′cos⁡θ))=0, and Reduction of the heavy symmetric top system: conserved momenta, one-dimensional θ equation and conserved reduced energy derives from them the conservation of b and a, the formulas for φ′ and ψ′, the constant reduced energy E and the equation Aθ′′=−U′(θ) with the displayed U (Reduction of the heavy symmetric top system: conserved momenta, one-dimensional θ equation and conserved reduced energy clauses 1-4).

[L6]

Calculus and algebra: (Rl)′=R′l+Rl′, R′=R[ω]× and [ω]×z=ω×z for a C1 rotation path (Derivative rules for differentiable matrix-valued curves, and skewness of RTR′ for a curve in SO(3), The skew-matrix/cross-product correspondence [ω]×z=ω×z and its conjugation law R[ω]×RT=[Rω]×, The orthogonal group O(3) and the rotation group SO(3)); the cross product is bilinear and alternating with u×(u×w)=(u⋅w)u−∥u∥22w for unit u (The cross product is bilinear, alternating, and orthogonal to both factors, The cross product in R3, The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn); the chain, product and quotient rules hold for the scalar functions below (The chain rule for total derivatives: D(g∘f)(a)=Dg(f(a))∘Df(a), Sums, scalar multiples, products and quotients: (f+g)′(c)=f′(c)+g′(c), (αf)′(c)=αf′(c), (fg)′(c)=f′(c)g(c)+f(c)g′(c), and (f/g)′(c)=(f′(c)g(c)−f(c)g′(c))/g(c)2 when g(c)≠0, The derivative f′(c)=lim⁡x→cf(x)−f(c)x−c of f:A→R at a point c∈A that is a limit point of A, and differentiability on a set, Intervals of R: the nine order-convex forms, nondegeneracy, and length); and a continuous real function on an interval with vanishing derivative at every interior point is constant (A function continuous on an interval I whose derivative vanishes at every interior point of I is constant on I; consequently two such functions with the same derivative differ by a constant).

Proof

technique · direct; compute the pivotal angular momentum from the model's inertial identities, translate the adopted balance into the body frame, and read the resulting equations in the Euler-angle chart, then invoke the supplier's reduction
1.1givenL1L6

By [L1] the constraint gives c(t)=dR(t)e3, and since R is C1 with R′=R[ω]× by [L6] one has c′=dR′e3=dR[ω]×e3=dR(ω×e3).

1.2givenL4algebra

By [L4], reading the columns of the three factors and using θ(I0)⊆(0,π), the vector γ=RTe3=Rz(ψ)TRy(θ)TRz(φ)Te3=Rz(−ψ)Ry(−θ)e3 equals Rz(−ψ)(−sin⁡θ e1+cos⁡θ e3)=(−sin⁡θcos⁡ψ, sin⁡θsin⁡ψ, cos⁡θ), and ω3=ψ′+φ′cos⁡θ.

2.1step 1.1givenL1L6

By [L1] the gravitational force system of the branch acts as the total force −mge3 applied at the centre of mass, whose torque about the origin is τp=mc×(−ge3); with c=dRe3 from step 1.1 this is τp=−mgd(Re3)×e3, and τp⋅e3=0 because the cross product is orthogonal to its factors by [L6].

3.1step 1.1step 2.1givenL1L2L3L6algebra

By [L2] one has Jp=Lc+c×P=RIω+mc×c′. Substituting c=dRe3 and c′=dR(ω×e3) from step 1.1 and using Ie3=Ce3, Ie1=Ace1, Ie2=Ace2 from [L3] gives mc×c′=md2 (Re3)×R(ω×e3)=md2R(e3×(ω×e3))=md2R(ω−ω3e3) by [L6] and the vector triple product with ∥e3∥2=1, so Jp=R(Iω+md2(ω−ω3e3))=RI~ω with I~=diag(A,A,C) and A=Ac+md2, C=Cc. Hence the balance of [L1] reads Jp′=τp with τp as in step 2.1, completing clause 1.

4.1step 1.2step 2.1step 3.1givenL6algebra

Since R is C1 and ω is C1, the product I~ω is C1 and Jp=RI~ω from step 3.1 gives R(I~ω′+ω×I~ω)=Jp′ by [L6]; with the balance Jp′=τp of step 3.1 and RTR=I3 one gets I~ω′+ω×I~ω=RTτp. By step 2.1 and [L6], RT((Re3)×e3)=e3×(RTe3)=e3×γ with γ of step 1.2, so I~ω′+ω×I~ω=−mgd(e3×γ). Componentwise, (e3×γ)1=−γ2, (e3×γ)2=γ1, (e3×γ)3=0 and (ω×I~ω)1=(C−A)ω2ω3, (ω×I~ω)2=(A−C)ω1ω3, (ω×I~ω)3=0, giving the three displayed equations of clause 2.

5.1step 1.2step 4.1givenL6

The third of the equations of step 4.1 gives Cω3′=0, and C>0, so ω3 is constant on the interval I0 by [L6]; by step 1.2, b=C(ψ′+φ′cos⁡θ)=Cω3 is constant on I0.

6.1step 1.2step 2.1step 3.1step 5.1givenL4L6algebra

By step 3.1 and [L6], ddt(Jp⋅e3)=Jp′⋅e3=τp⋅e3=0 by step 2.1, so Jp⋅e3 is constant on I0; and by steps 3.1 and 1.2, Jp⋅e3=(RI~ω)⋅e3=I~ω⋅γ=A(ω1γ1+ω2γ2)+Cω3γ3. Substituting the components of [L4] and step 1.2 and using sin⁡2ψ+cos⁡2ψ=1 from [L4] gives ω1γ1+ω2γ2=φ′sin⁡2θ and ω3γ3=(ψ′+φ′cos⁡θ)cos⁡θ, so Jp⋅e3=Aφ′sin⁡2θ+bcos⁡θ=a is constant on I0.

6.2step 1.2step 4.1step 5.1givenL4L6algebra

Put n:=sin⁡ψ e1+cos⁡ψ e2, so that n has ∥n∥2=1 and, by [L4] and R′=R[ω]×, the identity θ′=ω⋅n holds. Differentiating θ′ with [L6] gives Aθ′′=A(ω′⋅n)+A(ω⋅n′), where n′=ψ′(cos⁡ψ e1−sin⁡ψ e2); using the first two equations of step 4.1, the components of [L4] and the values ω1cos⁡ψ−ω2sin⁡ψ=−φ′sin⁡θ, ω2sin⁡ψ−ω1cos⁡ψ=φ′sin⁡θ and γ2sin⁡ψ−γ1cos⁡ψ=sin⁡θ of step 1.2, one computes A(ω′⋅n)=(A−C)ω3 φ′sin⁡θ+mgd sin⁡θ and A(ω⋅n′)=−Aφ′ψ′sin⁡θ, hence Aθ′′=(A−C)ω3φ′sin⁡θ+mgdsin⁡θ−Aφ′ψ′sin⁡θ=Aφ′2sin⁡θcos⁡θ−bφ′sin⁡θ+mgdsin⁡θ, the last equality by ω3−ψ′=φ′cos⁡θ from step 1.2 and b=Cω3 from step 5.1.

7.1step 5.1step 6.1step 6.2givenL5∎

The three equations of the definition of [L5] hold: the first is ddt(Aφ′sin⁡2θ+Ccos⁡θ(ψ′+φ′cos⁡θ))=a′=0 by step 6.1, the third is ddt(C(ψ′+φ′cos⁡θ))=b′=0 by step 5.1, and the second is Aθ′′=Aφ′2sin⁡θcos⁡θ−C(ψ′+φ′cos⁡θ)φ′sin⁡θ+mgdsin⁡θ by step 6.2 with C(ψ′+φ′cos⁡θ)=b. Therefore (φ,θ,ψ) is a heavy-top trajectory of [L5] with parameters (A,C,m,d,g), and clauses 1-4 of Reduction of the heavy symmetric top system: conserved momenta, one-dimensional θ equation and conserved reduced energy apply: a and b are constant, φ′ and ψ′ are given by the displayed formulas, the reduced energy E is constant, and Aθ′′=−U′(θ). This proves clauses 3 and 4.

Remarks

  • Where A=Ac+md2 comes from. The transverse moment of the model about the pivot is the transverse moment Ac about the centre of mass shifted by md2; this is why the reduction uses A and the supplier's parameter is identified with the pivot moment, not with Ac. The axial moment is unchanged because the shift is along the symmetry axis.

  • The role of the chart. The Euler-angle description is a hypothesis; the chart is singular at the poles θ=0,π, where the sleeping top and the hanging configuration lie, and the statement says nothing there. The definitions of a, b, E and U depend on the chosen description (the angles are determined only up to the chart's ambiguities), while the physical conclusions of clause 3 are invariants of the motion.

  • No empirical content. Clause 3 is a conditional deduction from the adopted branch; in particular the sleeping-top threshold, the stability of the upright top and the interpretation of precession in any concrete apparatus are not asserted here, and no value of Ac, Cc, m, d or g is measured.

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