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Hamilton–Jacobi and integrability — Examples

1 · Prerequisites

2 · Summary

Worked checks and counterexamples for cm14-hamilton-jacobi-and-integrability. The harmonic model worked through: an explicit complete integral, its characteristic motion, and the action-angle chart with I=∮p dx and period-one frequency 1/T works the harmonic model of The harmonic (linear restoring) model: a declared linear force law with parameter k>0 through the whole page using its declared straight-line generalized-coordinate presentation: the explicit family S is shown to be a complete integral of the model's Hamilton-Jacobi equation wherever sin⁡(ωt)≠0, its characteristic curves are the harmonic motions with β=Sα constant, and the explicit chart (x,p)↦(θ,I) is canonical with H=I/T, I˙=0, θ˙=1/T, the normalization I=∮p dx and the radian chart of the sources. The central example The gravitational two-body model on an elliptic orbit: two simple turning points of the effective potential and Ja′(E)=T/(2π)=μ/κ a3/2 inherits countable choice from its orbit suppliers and verifies, inside the gravitational two-body model of Adopted two-label gravitational model: the inverse-square pair potential with coupling parameters, the empirical mass identification, and the measured value and uncertainty of the Newtonian constant, that the Kepler effective potential has exactly two simple turning points on the elliptic energy window, applies the one-dimensional action-variable theorem The action variable of a two-simple-turning-point family is C1 with derivative T(E)/(2π), the period quadrature over 2π to obtain Ja′(E)=T/(2π), and identifies the radial quadrature with the orbital period T on the unique global relative central-force extension (with model motions restricted to their declared time window), recovering T2=4π2μa3/κ without using any measured constant.

The two counterexamples exhibit the hypotheses that cannot be dropped. The zero-energy level of the harmonic model: a compact connected common level set of a completely integrable datum that is a point, not a torus shows that the zero-energy level of the one-degree-of-freedom harmonic datum in its declared generalized-coordinate presentation is a compact connected common level set that is a single point, not a torus: compactness and connectedness alone do not give the toral conclusion, regularity is indispensable. A free label: a nonempty regular common level set of a completely integrable datum that is noncompact and has no period lattice uses the three-integral free-particle datum (H,p1,p2) on p3>0: each common fibre at (E,c1,c2) with 2mE>c12+c22 is a connected copy of R3 that is noncompact and carries no period at all, so the compactness hypothesis of Compact connected regular fibres of a completely integrable datum of the presentation are Lagrangian tori with a full period lattice is indispensable too. The published mathematical obstruction Period-lattice monodromy obstructs global action–angle coordinates and the refuted global statement Liouville–Arnold gives global action–angle coordinates on the entire manifold record the complementary global failure: local action-angle coordinates need not patch to a single-valued global chart even when all fibres are regular and compact, so no universal torus chart is claimed. Finally, The conjugate time of the harmonic model: the complete integral's mixed derivative is unbounded and the characteristic family refocuses at ωt∈πZ exhibits the local caustic of the oscillator family: the mixed derivative Sxα of the complete integral is unbounded at the conjugate times ωt∈πZ, and the family of model solutions through a fixed event refocuses there, which is why the Hamilton–Jacobi statements of this page are local in time and carry no claim across a caustic.

3 · Logical flowchart

4 · Definitions, postulates, theorems and proofs

None yet.

5 · Examples, experiments and counterexamples

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The harmonic model worked through: an explicit complete integral, its characteristic motion, and the action-angle chart with I=∮p dx and period-one frequency 1/T

Physical scope

A worked instance of the Hamilton-Jacobi and action-angle items inside the declared scalar harmonic model, identified with the generalized-coordinate presentation of the explicit straight-line immersion into a three-dimensional force model: for one label of mass m>0 and spring constant k>0, the explicit family S is a complete integral of the model's Hamilton-Jacobi equation wherever sin⁡(ωt)≠0; its characteristic curves are the harmonic motions with β=Sα constant; and the explicit chart (θ,I) is canonical with H=I/T, I˙=0, θ˙=1/T and I=∮p dx, in the period-one convention, with the radian rescaling recovering the sources' chart. The example asserts no measured value, no claim that a real oscillator realizes the model, and no global extension of S across the conjugate times ωt∈πZ.

Example

Adopt the harmonic model of The harmonic (linear restoring) model: a declared linear force law with parameter k>0: one label of mass m>0 on R with spring constant k>0, force law F(x)=−kx, potential U(x)=12kx2 and no residual force. For the CM12-CM14 presentation interfaces, declare the ambient one-label model on Qamb=R3 with mass operator mI3, time window R, potential Uamb(y)=ky12/2, d=0 and smooth force Famb(y,v)=(−ky1,0,0) (Adopted force model: force maps, the equation of motion, additive composition of force contributions and frame covariance, Potential presentations of a force model, potential and mechanical energy, closed versus exact force fields, local potentials and equipotential level sets, The action functional of a force model with a potential presentation: the mechanical Lagrangian, its chart instance and its dimensions). The generalized-coordinate map X:R→Qamb, X(x)=(x,0,0) is a smooth immersion with length-valued coordinate x, G=DXTmI3DX=m and substituted potential kx2/2 (Generalized-coordinate maps of the model, the substituted Lagrangian, the kinetic metric and generalized forces). Thus its chart Hamiltonian H~ of The Hamiltonian of a hyperregular potential presentation: the Legendre transform of the mechanical Lagrangian, its domain and its dimensions clause (b) is exactly the scalar Hamiltonian below; write it as H. A scalar harmonic motion reconstructs an ambient motion X∘x since the longitudinal equation is mx′′=−kx and both transverse equations are 0=0. Write

ω:=km>0,T:=2πω,

so that U(x)=12mω2x2 and the branch Hamiltonian in the generalized-coordinate chart is

H(x,p)=p22m+mω22x2

(Every potential presentation is hyperregular in its charts, with inverse branch v=M−1p (or G(q)−1p) and the explicit kinetic-plus-potential Hamiltonian, The Hamiltonian of a hyperregular potential presentation: the Legendre transform of the mechanical Lagrangian, its domain and its dimensions), with [H]=μℓ2τ−2 (Dimensions and SI unit conventions of the non-relativistic classical mechanics framework). On the open set

V:={(t,x,α)∈R3:sin⁡(ωt)≠0}

define

S(t,x,α):=mω2[(x2+α2)cot⁡(ωt)−2xα csc⁡(ωt)]. The example checks the following claims of this page on this instance.

  1. (complete integral) S is of class C∞ on V and solves the model's Hamilton-Jacobi equation St+H(x,Sx)=0 on V; the mixed derivative is Sxα=−mω csc⁡(ωt), so S is a complete integral of the model's Hamilton-Jacobi equation at every point of V (The Hamilton-Jacobi equation of a declared potential presentation: the class of action-dimension functions S with St+H(t,q,Sq)=0 in one momentum chart, A complete integral of the model's Hamilton-Jacobi equation: nondegenerate mixed derivative, momentum map and Jacobi constants).

  2. (characteristics) for every (t0,x0,α0)∈V and every real β, the curve x(t)=α0cos⁡(ωt)−βmωsin⁡(ωt) satisfies Sα(t,x(t),α0)=β, and with p(t):=Sx(t,x(t),α0) the pair (x,p) solves x′=Hp, p′=−Hx on every interval on which sin⁡(ωt)≠0; hence x is a motion of the harmonic model with p=mx′ and Sα is constant along it (A complete integral of the model's Hamilton-Jacobi equation produces chart Hamiltonian characteristics, Jacobi constants and local canonical (β,α) labels).

  3. (action-angle chart) the map (θ,I)⟼(x,p)=(Iπmω sin⁡(2πθ), Imωπ cos⁡(2πθ))

    for I>0 and θ∈R/Z is a C∞ parametrization of the punctured phase plane; local real lifts of θ give charts with {x,p}=1 for the presentation's bracket, i.e. a canonical chart of Canonical coordinates and the canonical form of the two-form for a potential presentation: the coordinate expression ω=∑a=1mdθa∧dθm+a with m the chart's half-dimension, and the model's own momentum charts with ωform=dθ∧dI in the period-one convention of Action and angle coordinates, and in it H=h(I)=IT, so that every motion satisfies I˙=0, θ˙=1/T, by the canonical Hamiltonian field of The Hamiltonian field of a phase function for a potential presentation: the unique field Xf with ιXfω=df, and XH=(Hp,−Hx) for the branch Hamiltonian clause (a).

  4. (action normalization) the action coordinate is the period integral I=∮p dx=∫0Tp(t) x′(t) dt along one period of the oscillator motion, in the period-one normalization discussed in the remark of Action-angle coordinates of a completely integrable presentation: period-one angles, action coordinates, H=h(I) and linear motion on the tori.

  5. (radian convention) with θrad:=2πθ and Irad:=I/(2π) the chart becomes x=2Irad/(mω) sin⁡θrad, p=2Iradmω cos⁡θrad with H=ωIrad and θ˙rad=ω, which is the radian chart of the sources (Period-one to radian action-angle rescaling: θrad=2πθ and Irad=I/(2π) preserve ω).

All data m,k are declared model parameters; the example asserts no measured value and no claim about a real oscillator.

Facts & Assumptions

Given: The harmonic model data m>0, k>0, the ambient potential presentation and immersion X just declared, the constants ω,T, the Hamiltonian H, the open set V and the function S displayed above.

[L1]

Model and Hamiltonian (The harmonic (linear restoring) model: a declared linear force law with parameter k>0, The motions of the harmonic model are the sinusoids Acos⁡(ω(t−t0))+Bsin⁡(ω(t−t0)): amplitude and phase, the least period, the conserved energy kR2/2 and the elliptical phase curves, Every potential presentation is hyperregular in its charts, with inverse branch v=M−1p (or G(q)−1p) and the explicit kinetic-plus-potential Hamiltonian, The Hamiltonian of a hyperregular potential presentation: the Legendre transform of the mechanical Lagrangian, its domain and its dimensions, The associated first-order system, motions, maximal motions and the Newtonian flow of a force model, Generalized-coordinate maps of the model, the substituted Lagrangian, the kinetic metric and generalized forces): scalar motions of the model are the solutions of mx′′=−kx, and are exactly the curves x(t)=Acos⁡(ω(t−t0))+Bsin⁡(ω(t−t0)) with reals A,B; the inverse Legendre branch is (x,p)↦p/m, equivalently p=mx′, and the branch Hamiltonian is the displayed H. The least positive period of x is T when (A,B)≠(0,0), by clause 3 of The motions of the harmonic model are the sinusoids Acos⁡(ω(t−t0))+Bsin⁡(ω(t−t0)): amplitude and phase, the least period, the conserved energy kR2/2 and the elliptical phase curves.

[L2]

Calculus (Ck Euclidean maps and diffeomorphisms, Directional derivatives and partial derivatives of a map U⊆Rm→Rn, The Jacobian matrix of partial derivatives and the gradient in the scalar-valued case, The derivatives of sine and cosine are cosine and minus sine, The chain rule, in one line from Carathéodory: if g is differentiable at c and f is differentiable at g(c), then f∘g is differentiable at c with (f∘g)′(c)=f′(g(c)) g′(c), Sums, scalar multiples, products and quotients: (f+g)′(c)=f′(c)+g′(c), (αf)′(c)=αf′(c), (fg)′(c)=f′(c)g(c)+f(c)g′(c), and (f/g)′(c)=(f′(c)g(c)−f(c)g′(c))/g(c)2 when g(c)≠0, Double-angle and quadratic power-reduction identities, The zero sets of sine and cosine and the least positive common period 2 pi, Parity and the Pythagorean identity for sine and cosine, If f:[a,b]→Rm is differentiable with integrable f′ then ∫abf′=f(b)−f(a); and a bounded derivative makes f Lipschitz, The lower and upper Darboux integrals of a bounded f on [a,b] as sup⁡PL(f,P) and inf⁡PU(f,P), Darboux integrability as their equality, and the notation ∫abf, Intervals of R: the nine order-convex forms, nondegeneracy, and length): the derivatives (sin⁡)′=cos⁡, (cos⁡)′=−sin⁡, (cot⁡)′=−csc⁡2, (csc⁡)′=−csc⁡cot⁡ hold wherever the functions are defined; the chain rule and the algebra of derivatives apply; the power-reduction identity cos⁡2u=(1+cos⁡2u)/2 and the Pythagorean identity sin⁡2u+cos⁡2u=1 hold; sin⁡(kπ)=0 for integers k; and a continuous u:[a,b]→R with a primitive W satisfies ∫abu=W(b)−W(a).

[L4]

Characteristics theorem (A complete integral of the model's Hamilton-Jacobi equation produces chart Hamiltonian characteristics, Jacobi constants and local canonical (β,α) labels): a complete integral S produces curves with p=Sx solving the Hamilton equations and with β=Sα constant.

[L5]

Canonical chart and field (Canonical coordinates and the canonical form of the two-form for a potential presentation: the coordinate expression ω=∑a=1mdθa∧dθm+a with m the chart's half-dimension, and the model's own momentum charts, The Hamiltonian field of a phase function for a potential presentation: the unique field Xf with ιXfω=df, and XH=(Hp,−Hx) for the branch Hamiltonian clause (a), Action and angle coordinates, The Euclidean inverse function theorem): a smooth coordinate map with nonzero Jacobian has smooth local inverses. In coordinates (θ,I) with two-form dθ∧dI, the defining equation ιXHωform=dH reads θ˙=HI, I˙=−Hθ. The radian rescaling preserves the two-form and transforms the Hamiltonian as h~(Irad)=h(2πIrad).

Verification

technique · direct; compute the partial derivatives, verify the Hamilton-Jacobi equation and the characteristic equations by substitution, check the Poisson bracket of the explicit chart, and evaluate the period integral
1.1L2L3givenalgebra

Derivatives of S: with c:=cos⁡(ωt) and s:=sin⁡(ωt), [L2] gives Sx=mω(xcot⁡(ωt)−αcsc⁡(ωt)) and St=mω22[−(x2+α2)csc⁡2(ωt)+2xα csc⁡(ωt)cot⁡(ωt)]. Substituting p=Sx into H, St+H(x,Sx)=mω22[−(x2+α2)csc⁡2+2xαcsc⁡cot⁡+(xcot⁡−αcsc⁡)2+x2]=mω22x2(−csc⁡2+cot⁡2+1)=0, because cot⁡2−csc⁡2=−1; and Sxα=−mω csc⁡(ωt)≠0 on V. Hence S is a C∞ complete integral of the model's Hamilton-Jacobi equation at every point of V, which is claim 1. Dimensions: [mωx2]=μτ−1ℓ2=[S].

2.1L1L2L4step 1.1algebra

The characteristic motion: put x(t):=α0cos⁡(ωt)−β(mω)−1sin⁡(ωt) and p(t):=Sx(t,x(t),α0). By [L2], x′(t)=−α0ωsin⁡(ωt)−βm−1cos⁡(ωt) and p(t)m=ω[x(t)cs−α01s]=ω[(α0c−βmωs)cs−α0s]=−ωα0s−βmc=x′(t), using α0(c2−1)/s=−α0s, so p=mx′ and x′=Hp=p/m, and p′(t)=−mω2α0c+βωs=−mω2x(t)=−Hx. For the constants, differentiating the displayed S in α gives Sα(t,x,α)=mω(αcot⁡(ωt)−xcsc⁡(ωt)), so Sα(t,x(t),α0)=mω[α0cot⁡(ωt)−(α0c−βmωs)csc⁡(ωt)]=mωα0(cot⁡−c csc⁡)+β=β, since cot⁡u−cos⁡u csc⁡u=0. Hence the characteristic curve lies on the level set Sα=β, it is a motion of the model with p=mx′ by [L1], and β=Sα is constant along it, which is claim 2.

3.1L2L5step 2.1algebra

The canonical chart: write x=I/(πmω) sin⁡(2πθ) and p=Imω/π cos⁡(2πθ); by [L2], xθpI−xIpθ=cos⁡2(2πθ)+sin⁡2(2πθ)=1, the computation being: xθ=2πI/(πmω)cos⁡, pI=12mω/π I−1/2cos⁡ give xθpI=cos⁡2; and xI=12(πmωI)−1/2sin⁡, pθ=−2πImω/πsin⁡ give xIpθ=−sin⁡2. The energy fixes I=2πH/ω>0, and the normalized pair (xπmω/I,pπ/(Imω)) fixes θ modulo one, so the parametrization is bijective onto the punctured phase plane; the nonzero Jacobian makes its inverse smooth in local angle lifts. Hence {x,p}=1 in the chart, i.e. the coordinates are canonical for the presentation's bracket and ωform=dθ∧dI. Substituting into H, H=p22m+mω22x2=Iω2π(cos⁡2+sin⁡2)=Iω2π=IT=h(I). Writing XH=a∂θ+b∂I, contraction gives a dI−b dθ=dH=T−1dI, so a=1/T, b=0 by [L5]. Hence I˙=0 and θ˙=1/T along the scalar harmonic motions, which is claim 3.

4.1L2step 3.1algebra

The period integral: parametrize the motion of step 3.1 with I>0, θ0=0 by x(t)=Asin⁡(ωt), A:=I/(πmω), so that p(t)=mx′(t)=mAωcos⁡(ωt) and the least positive period is T by [L1]. Then by [L2], ∮p dx=∫0Tp(t)x′(t) dt=mA2ω2∫0Tcos⁡2(ωt) dt=mA2ω2⋅T2=mA2ωπ=I, because cos⁡2(ωt)=(1+cos⁡2ωt)/2, the integral of cos⁡(2ωt) over [0,T] vanishes being an increment of sin⁡(2ωt)/(2ω) at sin⁡(2πk)=0, and mA2ωπ=mIπmωωπ=I. This is claim 4.

4.2L5step 3.1algebra

Radian rescaling: the map [u]↦[2πu] from R/Z to R/(2πZ) is a smooth bijection with smooth inverse [v]↦[v/(2π)], as checked in local real lifts. Thus θrad=2πθ and Irad=I/(2π) satisfy dθrad∧dIrad=(2π)dθ∧dI/(2π)=dθ∧dI and keep the two-form and give H=h(2πIrad)=2πIrad/T=ωIrad and θ˙rad=2πθ˙=2π/T=ω; inverting the rescaling in the chart of step 3.1 gives x=2Irad/(mω)sin⁡θrad and p=2Iradmωcos⁡θrad, the source's chart. This is claim 5.

5.1step 1.1step 2.1step 3.1step 4.1step 4.2∎

Claims 1-5 are verified by steps 1.1, 2.1, 3.1, 4.1 and 4.2 respectively; the example is verified.

Remarks

  • Where the construction breaks. The family S is defined only for sin⁡(ωt)≠0, and the mixed derivative Sxα=−mωcsc⁡(ωt) is unbounded as ωt→πZ; the complete integral is a local object between the conjugate times of the oscillator and is not continued across them. The companion example computes the focusing of the characteristic family at those times.

  • No empirical content. The oscillator data are declared model parameters, and the displayed identities are statements about the model; no measured frequency, amplitude or period is asserted.

ExampleConstruction: AI-adaptedVerification: AI-adaptedprecheck passOpen item page →

The gravitational two-body model on an elliptic orbit: two simple turning points of the effective potential and Ja′(E)=T/(2π)=μ/κ a3/2

Physical scope

Assuming countable choice for the orbit suppliers, A worked instance inside the two-label gravitational model of the framework's force branch: on the unique global central-force extension of an elliptic relative orbit (j=Je3, J>0, E<0, eccentricity 0≤e<1), the Kepler effective potential has exactly two simple turning points on the energy window between its minimum and 0; the one-dimensional action variable of the radial problem is C1 there with derivative T/(2π); and for a noncircular orbit the radial quadrature is the orbital period, so Ja′(E)=T/(2π)=μ/κ a3/2 with T2=4π2μa3/κ. The example uses only the model's declared couplings κ=GNm1gm2g and masses; no measured value of GN and no empirical premise is used, and no real orbit is claimed to obey the model.

Example

Assume ACω (The Axiom of Countable Choice (ACω)), as required by the conic, ellipse and period suppliers.

Adopt the two-label gravitational model of Adopted two-label gravitational model: the inverse-square pair potential with coupling parameters, the empirical mass identification, and the measured value and uncertainty of the Newtonian constant clause (i) inside the central-force model of Adopted central-force model class: static central pair potentials, the reduced one-label problem, the fixed-centre idealization, reading conventions and exclusions: inertial masses m1,m2>0, M=m1+m2, reduced mass μ=m1m2/M, gravitational couplings m1g,m2g>0, κ=GNm1gm2g>0 and the pair potential of Two-body reduction of a static central pair-potential model: the relative coordinate is a central-force trajectory for the reduced mass, the centre of mass moves uniformly, and the reconstruction is a bijection. Let x:I→Q be a motion whose relative coordinate r has constant angular momentum j=Je3 with J>0 and constant energy E<0. Let rˉ:R→R3∖{0} be the unique global central-force extension of r supplied by Completeness and periodicity of the negative-energy Kepler orbit, with T=2πμab/J and T2=4π2μa3/κ clause 1 and Kepler's third law for the gravitational two-label model: the relative period is T=2πμab/J=2πμ/κ a3/2, so T2=4π2a3/(GNM) under the mass identification, and both labels are periodic relative to the centre of mass clause 1. In all subsequent period and quadrature statements, write r:=rˉ, ρ:=∣rˉ∣ and let θ:R→R be its increasing polar-angle lift. Its restriction to the initial interval is the original relative motion; no global physical time window is assumed. Let 0≤e<1, θ0,

p=J2μκ,a=p1−e2,b=a1−e2,T=2πμκ a3/2 be its conic data (The Kepler orbit equation is a conic: u=c(1+ecos⁡(φ−θ0)) with E=(μκ2/2J2)(e2−1), Kepler's third law for the gravitational two-label model: the relative period is T=2πμab/J=2πμ/κ a3/2, so T2=4π2a3/(GNM) under the mass identification, and both labels are periodic relative to the centre of mass). Write

I0:=(−μκ22J2, 0),r∗:=J2μκ=p,Ueff(ρ):=−κρ+J22μρ2(ρ>0) for the effective potential of Reduction of the central problem to the effective one-dimensional potential: μρ′′=−(UJeff)′(ρ), the energy identity, and the converse reconstruction of the planar trajectory from the radial data (its effective potential UJeff). The example verifies:

  1. (two simple turning points) Ueff is of class C∞ on (0,∞), has the unique critical point r∗ with Ueff(r∗)=−μκ2/(2J2), is strictly decreasing on (0,r∗) and strictly increasing on (r∗,∞); hence for every E∈I0 there are exactly two solutions 0<r−(E)<r∗<r+(E) of Ueff(ρ)=E, with (Ueff)′(r−(E))<0<(Ueff)′(r+(E)) and Ueff<E between them, and the datum (J0,Ueff,μ) with J0=(0,∞) satisfies the hypotheses of The action variable of a two-simple-turning-point family is C1 with derivative T(E)/(2π), the period quadrature over 2π on the energy window I0.

  2. (action derivative) consequently the action variable Ja of The one-dimensional action variable of a family of two-turning-point energy levels is of class C1 on I0 with Ja′(E)=Trad(E)2π,Trad(E)=2μ∫r−(E)r+(E)dρE−Ueff(ρ)∈(0,∞).

  3. (quadrature equals the orbital period) for a noncircular orbit 0<e<1 (equivalently E∈I0), the radial coordinate of this global extension solves the one-dimensional problem of clause 1 of Reduction of the central problem to the effective one-dimensional potential: μρ′′=−(UJeff)′(ρ), the energy identity, and the converse reconstruction of the planar trajectory from the radial data with the same energy, and its least positive period is the orbital period T of the conic data; the time quadrature of that problem is Trad(E)=T, so that Ja′(E)=T2π=μκ a3/2,T2=4π2μa3κ.

  4. (sharpness of the hypotheses) for e=0 the two turning points coalesce at the critical point r∗=a and the simple-turning-point hypothesis of the action-variable theorem fails; the value J=0 is outside this example (no two-sided bound radial motion), so both hypotheses of the construction are genuinely used.

The couplings κ and the masses are declared model parameters; no measured value of GN and no empirical premise enters.

Facts & Assumptions

Given: Assume ACω. The gravitational model data m1,m2,κ>0, the motion with j=Je3, J>0, E<0, its unique global relative extension r with ρ=∣r∣ and polar lift θ, the conic data p,e,a,b,T, the effective potential Ueff and the energy window I0.

[L2]

Conic geometry (The Kepler orbit equation is a conic: u=c(1+ecos⁡(φ−θ0)) with E=(μκ2/2J2)(e2−1), Completeness and periodicity of the negative-energy Kepler orbit, with T=2πμab/J and T2=4π2μa3/κ, Kepler's third law for the gravitational two-label model: the relative period is T=2πμab/J=2πμ/κ a3/2, so T2=4π2a3/(GNM) under the mass identification, and both labels are periodic relative to the centre of mass, Polar reduction of a non-radial central-force trajectory: ρ2θ′=J/μ, the effective-potential equation and energy conservation): with e≥0 and θ0 as in the cited conic theorem, ρ(t)=p/(1+ecos⁡(θ(t)−θ0)) and E=μκ22J2(e2−1); consequently e<1 is equivalent to E<0, and for 0<e<1 the radial coordinate is T-periodic, ρ(t+T)=ρ(t) and ρ′(t+T)=ρ′(t), with T=2πμ/κ a3/2=2πμab/J, and the polar angle is a strictly increasing bijection θ:R→R with θ(t+T)=θ(t)+2π.

[L3]

Calculus and integrals (The derivative f′(c)=lim⁡x→cf(x)−f(c)x−c of f:A→R at a point c∈A that is a limit point of A, and differentiability on a set, For a natural n≥1 the function x↦xn is differentiable everywhere with derivative ι(n) x n−1; for n=0 it is the constant 1, with derivative 0; for a natural n≥1 the function x↦x−n is differentiable at every x≠0 with derivative −ι(n) x−n−1; consequently every polynomial function is differentiable at every real, with the derivative computed term by term, Sums, scalar multiples, products and quotients: (f+g)′(c)=f′(c)+g′(c), (αf)′(c)=αf′(c), (fg)′(c)=f′(c)g(c)+f(c)g′(c), and (f/g)′(c)=(f′(c)g(c)−f(c)g′(c))/g(c)2 when g(c)≠0, The chain rule, in one line from Carathéodory: if g is differentiable at c and f is differentiable at g(c), then f∘g is differentiable at c with (f∘g)′(c)=f′(g(c)) g′(c), The mean value theorem, as the case g(x)=x of Cauchy's: for f continuous on [a,b] with a<b and differentiable on (a,b) there is c∈(a,b) with f(b)−f(a)=f′(c)(b−a), Intermediate value theorem, by bisection with a canonical left-half rule: a continuous function on [a,b] takes every value between f(a) and f(b), Continuity of f:A→R at a point of A and on A: the ε-δ condition, its agreement with lim⁡x→cf(x)=f(c) at a limit point, and continuity at an isolated point, Ck Euclidean maps and diffeomorphisms, Derivative of an inverse: if f is continuous and injective on a nondegenerate interval I and differentiable at c∈I with f′(c)≠0, then the inverse g is differentiable at f(c) with g′(f(c))=1/f′(c); and if f′(c)=0 then g is not differentiable at f(c), Substitution: if φ is differentiable on [c,d] with φ′ integrable and f is continuous on an interval containing φ([c,d]), then ∫φ(c)φ(d)f=∫cd(f∘φ) φ′, If f:[a,b]→Rm is differentiable with integrable f′ then ∫abf′=f(b)−f(a); and a bounded derivative makes f Lipschitz, The lower and upper Darboux integrals of a bounded f on [a,b] as sup⁡PL(f,P) and inf⁡PU(f,P), Darboux integrability as their equality, and the notation ∫abf, Intervals of R: the nine order-convex forms, nondegeneracy, and length): sums, quotients with nonzero denominator and powers of class C∞ are C∞; the derivative of ρ↦κ/ρ is −κ/ρ2 and that of ρ↦J2/(2μρ2) is −J2/(μρ3); the mean-value theorem, the intermediate value theorem and the one-variable inverse-function rule hold on intervals; a continuous integrand on a compact interval is Riemann integrable, substitution is available for strictly monotone C1 changes of variables, and ∫cdu′=u(d)−u(c) for a C1 function u on [c,d].

[L4]

Action-variable theorems (The one-dimensional action variable of a family of two-turning-point energy levels, The action variable of a two-simple-turning-point family is C1 with derivative T(E)/(2π), the period quadrature over 2π): for the datum (J0,Ueff,μ) with the two simple turning points a(E)<b(E) on an energy interval (E0,E1) and (Ueff)′(a)<0<(Ueff)′(b), the action variable Ja is C1 and Ja′(E)=T(E)/(2π) with the displayed quadrature T(E).

Verification

Proof technique: direct; compute the effective potential's derivative and signs, produce the two simple roots by the intermediate-value and mean-value theorems, apply the one-dimensional action-variable theorem, and identify the time quadrature with the orbital period.

1.1L3algebra

Derivative and critical point: by [L3], (Ueff)′(ρ)=κρ2−J2μρ3=κρ−J2/μρ3=κ(ρ−r∗)ρ3, which vanishes exactly at ρ=r∗=J2/(μκ) and has the sign of ρ−r∗; and Ueff(r∗)=−κμκ/J2+J2μ2κ2/(2μJ4)=−μκ2/(2J2). Also Ueff(r∗/2)=−2μκ2/J2+2μκ2/J2=0, and for any E∈I0 and R:=r∗+κ/∣E∣ one has Ueff(R)>−κ/R>−∣E∣=E.

2.1L3step 1.1algebra

Monotonicity and the two simple roots: if 0<ρ1<ρ2≤r∗, then by [L3] the mean-value theorem applied to Ueff on [ρ1,ρ2] gives Ueff(ρ2)−Ueff(ρ1)=(Ueff)′(ξ)(ρ2−ρ1)<0; hence Ueff is strictly decreasing on (0,r∗]. Similarly, on r∗≤ρ1<ρ2, the increment is positive, so Ueff is strictly increasing on [r∗,∞). Now fix E∈I0. By step 1.1, Ueff(r∗)<E<0=Ueff(r∗/2); since Ueff is continuous, the intermediate-value theorem gives r−(E)∈(r∗/2,r∗) with Ueff(r−(E))=E, and strict monotonicity makes it unique on (0,r∗]. Likewise Ueff(r∗)<E<Ueff(R) gives a unique r+(E)∈(r∗,R) with Ueff(r+(E))=E, and monotonicity makes the root unique on [r∗,∞). The intermediate values on (r−(E),r+(E)) lie below E because the only point where Ueff could reach E again would be a third root. The roots are simple: (Ueff)′(r−(E))<0<(Ueff)′(r+(E)) because r−(E)<r∗<r+(E) and the sign computation of step 1.1. The assignments E↦r±(E) therefore have the properties required in [L4] on the energy interval I0.

3.1L4step 2.1algebra

Applying the action-variable theorem: by step 2.1 the datum (J0,Ueff,μ) satisfies the hypotheses of [L4] on I0=(E0,E1); hence Ja is C1 on I0 and Ja′(E)=Trad(E)/(2π) with the quadrature Trad(E)=2μ∫r−(E)r+(E)dρ/E−Ueff(ρ)>0, which is claim 2.

4.1L1L2L3step 2.1step 3.1algebra

The quadrature measures one radial cycle: for 0<e<1, choose a periastron time t− of the global extension, and let t+ and t1 be the unique times with polar-angle increments π and 2π from it, respectively. These exist by the increasing bijection of [L2]. The conic formula of [L2] gives endpoint radii r−=p/(1+e), r+=p/(1−e), the roots of step 2.1 by the energy identity of [L1], and places ρ strictly between them on each open leg. Energy then makes ρ′ nonzero there. At periastron ρ′=0 and ρ′′=−(Ueff)′(r−)/μ>0, so continuity makes ρ′>0 immediately afterwards and throughout (t−,t+), since it cannot change sign without vanishing. At apastron ρ′′=−(Ueff)′(r+)/μ<0 gives ρ′<0 on (t+,t1) by the same reasoning. On the increasing leg its inverse t(ρ) is differentiable for r−<ρ<r+, with t′(ρ)=μ/2/E−Ueff(ρ) by [L1] and the inverse rule in [L3]. For 0<δ<(r+−r−)/2, FTC on the interior compact interval gives t(r+−δ)−t(r−+δ)=μ/2∫r−+δr+−δ(E−Ueff(ρ))−1/2 dρ. Letting δ↓0, continuity of the inverse at its endpoint limits gives t+−t− on the left, and the convergent improper integral of step 3.1 gives the limit on the right. On the decreasing leg the same interior calculation with t′(ρ)=−μ/2/E−Ueff(ρ) gives the identical duration t1−t+. Thus t1−t−=Trad(E); no derivative or compact-interval substitution at a turning endpoint is used.

5.1L2step 3.1step 4.1algebra

Least period and the value of the derivative: by [L2] the radial coordinate satisfies ρ(t+T)=ρ(t) with T the orbital period of the conic data. Since θ:R→R is a strictly increasing bijection with θ(t+T)=θ(t)+2π and ρ(t)=p/(1+ecos⁡(θ(t)−θ0)) with 0<e<1, the periastron value r−(E)=p/(1+e) and the apastron value r+(E)=p/(1−e) are attained exactly once in every half-open interval of the form [t0,t0+T). Every positive period must carry a periastron time to another periastron time. The strictly increasing polar angle attains successive periastra at increments of 2π, and θ(t+T)=θ(t)+2π shows their successive times differ by T; hence any positive period is at least T. Since T is a period, it is the least positive radial period. Therefore Trad(E)=T by step 4.1, and Ja′(E)=T2π=μabJ=μκ a3/2, where the last identity uses J=μκa(1−e2) and b=a1−e2: explicitly μab/J=μa21−e2/μκa(1−e2)=μ/κ a3/2. Squaring T=2πμ/κa3/2 returns T2=4π2μa3/κ. This is claim 3.

6.1L2step 2.1step 5.1

Sharpness: if e=0 then r−(E)=r+(E)=a=r∗ and E=Ueff(r∗), the lower endpoint of I0; there is no energy interval containing this circular energy on which two distinct simple turning points exist, so the hypothesis of [L4] fails, in agreement with the circular orbit having a constant radial coordinate and no radial oscillation. The case J=0 has no term J2/(2μρ2) and no critical point with the stated two-sided conservation, so it is outside the example by hypothesis. This is claim 4.

7.1step 1.1step 2.1step 3.1step 4.1step 5.1step 6.1∎

Claims 1-4 are verified by steps 1.1 and 2.1, by step 3.1, by steps 4.1 and 5.1, and by step 6.1 respectively; the example is verified.

Remarks

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The zero-energy level of the harmonic model: a compact connected common level set of a completely integrable datum that is a point, not a torus

Physical scope

A counterexample inside the declared harmonic model of the framework's force branch: the one-degree-of-freedom harmonic datum (H) on the generalized-coordinate phase plane of the explicit straight-line immersion is a completely integrable datum, and its zero common level set is compact, connected and nonempty but consists of the single rest point, so it is not diffeomorphic to a torus; equivalently, the level is a critical level at which the regular-fibre hypotheses of the torus theorem fail. The item asserts no measured value and no claim about any apparatus; it shows that regularity cannot be dropped from the hypotheses.

Statement refuted

In a completely integrable datum of a presentation of the framework's force branch, every nonempty compact connected common level set of the integral map is diffeomorphic to a torus Tn=Rn/Zn.

Facts & Assumptions

Given: The scalar harmonic model of The harmonic (linear restoring) model: a declared linear force law with parameter k>0 with m>0, k>0, [m]=μ, [k]=μτ−2 and length-valued x. To place its phase plane in the presentation class, declare the ambient one-label force model on Qamb=R3, time window R, mass operator mI3, smooth potential Uamb(y)=ky12/2 and d=0, with force Famb(y,v)=(−ky1,0,0) (Adopted force model: force maps, the equation of motion, additive composition of force contributions and frame covariance, Potential presentations of a force model, potential and mechanical energy, closed versus exact force fields, local potentials and equipotential level sets). Choose the smooth immersion X:R→Qamb, X(x)=(x,0,0), of Generalized-coordinate maps of the model, the substituted Lagrangian, the kinetic metric and generalized forces. Its derivative (1,0,0)T is injective, its kinetic metric is G=m, and its substituted potential is kx2/2; thus clause 2 of Every potential presentation is hyperregular in its charts, with inverse branch v=M−1p (or G(q)−1p) and the explicit kinetic-plus-potential Hamiltonian gives the generalized-coordinate phase domain W=R×R and chart Hamiltonian (write it as H) H(x,p)=p2/(2m)+kx2/2, with p=mx′ and [p]=μℓτ−1, [H]=μℓ2τ−2 (The Hamiltonian of a hyperregular potential presentation: the Legendre transform of the mechanical Lagrangian, its domain and its dimensions, The momentum of a potential presentation: the fibre derivative of the mechanical Lagrangian, the Cartesian momentum Mv and generalized momenta, Dimensions and SI unit conventions of the non-relativistic classical mechanics framework). This identifies the scalar model with the substituted equations exactly: x solves mx′′=−kx if and only if X∘x solves my′′=(−ky1,0,0) along this line; the transverse equations are 0=0.

[L1]

Datum and integral map (Completely integrable data of a declared presentation: n smooth phase functions with F1=H, pairwise in involution and independent on the regular locus, First integrals of the model's Hamiltonian and families in involution: the bracket criterion and differential independence, The Hamiltonian field of a phase function for a potential presentation: the unique field Xf with ιXfω=df, and XH=(Hp,−Hx) for the branch Hamiltonian): with ω=k/m>0 so that H(x,p)=(p2+m2ω2x2)/(2m), the single function F1:=H on W0:=W satisfies {H,H}=0 by skew-symmetry of the bracket, is C∞, and has differential dH=(mω2x) dx+(p/m) dp, which vanishes exactly at (0,0); hence F=(H) is a completely integrable datum of the presentation on W0, whose integral map is H itself and whose only critical value is 0. The complement of (0,0) is open and dense, so the independence requirement holds on a dense open subset.

[L3]

The torus theorem's hypotheses (Compact connected regular fibres of a completely integrable datum of the presentation are Lagrangian tori with a full period lattice): the conclusion that a common level set is a torus is asserted there only for a compact connected regular fibre of a regular value, among further hypotheses; the item makes no claim about critical levels.

Counterexample

1.1L1given

By [L1] the datum F=(H) is completely integrable on W0 and H−1(0)={(0,0)}: indeed H(x,p)=0 forces p=0 and x=0 because H is a sum of two squares divided by the positive number 2m. The set H−1(0) is therefore nonempty, compact (a single point) and connected.

1.2L1L3

The point (0,0) is a critical point of H by [L1], so 0 is a critical value and the fibre H−1(0) is a critical (not regular) fibre; the hypothesis of [L3] fails, and the torus conclusion is not available. This already shows that the regular-value hypothesis is needed, but the point of the counterexample is stronger.

2.1L2step 1.1algebra

The fibre is not diffeomorphic to T1: it has exactly one point, while T1 is infinite, and a diffeomorphism is a bijection by [L2]; no bijection exists between a one-point set and an infinite set. Hence the refuted statement fails at the declared model datum.

2.2L1step 1.1algebra

The failure is confined to the critical level: for every E>0 the level H−1(E) is the ellipse {(x,p):p2/(2m)+kx2/2=E}, a one-dimensional compact connected manifold, the phase curve of a nonconstant harmonic motion; the smooth parametrization u↦(2E/ksin⁡(2πu),2mEcos⁡(2πu)) is a diffeomorphism from R/Z to that ellipse. Indeed the Pythagorean identity gives its image, the bijection of t↦(cos⁡t,sin⁡t) is a bijection from [0,2π) onto the real unit circle and the 2π period fix u modulo one and cover the whole ellipse. At each point either the derivative of its x coordinate or of its p coordinate is nonzero, since sine and cosine cannot vanish together. Applying The Euclidean inverse function theorem to that scalar coordinate in a real representative interval gives a smooth local inverse, proving the claimed diffeomorphism. These trigonometric properties are The zero sets of sine and cosine and the least positive common period 2 pi, The derivatives of sine and cosine are cosine and minus sine and Parity and the Pythagorean identity for sine and cosine. Thus the regular fibres have the torus structure, whereas the critical fibre is a point. The refuted claim therefore fails exactly at the critical value.

3.1step 1.1step 1.2step 2.1step 2.2∎

Collecting: the common level set H−1(0) of the completely integrable datum (H) is nonempty, compact and connected but not diffeomorphic to a torus, so the refuted statement is false; the regular values of the same datum do satisfy the torus conclusion, so no claim of Compact connected regular fibres of a completely integrable datum of the presentation are Lagrangian tori with a full period lattice is affected.

Remarks

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A free label: a nonempty regular common level set of a completely integrable datum that is noncompact and has no period lattice

Physical scope

A counterexample in the autonomous zero-force one-label presentation on R6: the smooth three-integral datum F=(H,p1,p2) on p3>0 has connected regular fibres diffeomorphic to R3, hence noncompact. Its commuting R3 action has trivial stabilizer, so no full period lattice exists, and the physical Hamiltonian flow has no nonzero period. This is declared model data, with no measured value or apparatus claim.

Statement refuted

In a completely integrable datum of a presentation of the framework's force branch, every nonempty regular common level set of the integral map is compact, and along it the datum's Hamiltonian flow is periodic with a full lattice of periods.

Facts & Assumptions

[L1]

Datum and fields (Completely integrable data of a declared presentation: n smooth phase functions with F1=H, pairwise in involution and independent on the regular locus, First integrals of the model's Hamiltonian and families in involution: the bracket criterion and differential independence, The Hamiltonian field of a phase function for a potential presentation: the unique field Xf with ιXfω=df, and XH=(Hp,−Hx) for the branch Hamiltonian): on the open phase domain W0={(x,p)∈R6:p3>0} take F=(H,p1,p2). All three functions are smooth and depend only on p, so their pairwise brackets vanish. Their momentum derivatives are the rows p/m, (1,0,0) and (0,1,0), with determinant p3/m>0. Thus the regular locus is all of W0. The fields are XH=(p/m,0), Xp1=(e1,0) and Xp2=(e2,0).

[L2]

Regular fibres: for c1,c2∈R and E>(c12+c22)/(2m) set ρ=2mE−c12−c22>0 and p∗=(c1,c2,ρ). The common fibre of F at (E,c1,c2) is exactly N=R3×{p∗}. It is nonempty, connected and regular at every point, and the projection to x is a smooth diffeomorphism to R3.

[L4]

The torus and lattice conclusion (Compact connected regular fibres of a completely integrable datum of the presentation are Lagrangian tori with a full period lattice clauses 2 and 3): compactness of the fibre is a hypothesis there for the completeness of the restricted fields, for the full period lattice and for the torus identification; the item asserts no conclusion for a noncompact level set.

Counterexample

1.1L1L2given

By [L1], F=(H,p1,p2) is a completely integrable datum with n=3 on the six-dimensional domain W0. By [L2], N=F−1(E,c1,c2) is a nonempty connected regular common fibre.

1.2L1L2algebra

Use fixed SI numerical coordinates for the physical quantities, as in Dimensions and SI unit conventions of the non-relativistic classical mechanics framework. Give the flow parameters the dimensions [a]=τ and [b]=[c]=ℓ: a is the Hamiltonian time parameter, while b,c are position-translation parameters for the momentum integrals. With these units each summand in the displacement has length dimension. On N the commuting fields have the globally defined joint action Ψ(a,b,c)(x,p∗)=(x+ap∗/m+be1+ce2,p∗). In these fixed numerical units the translation matrix has determinant ρ/m>0, so it is transitive and its stabilizer is {0} at every point. There is therefore no full rank-three period lattice. In particular the physical Hamiltonian flow Φt(x,p∗)=(x+tp∗/m,p∗) has no nonzero period since p∗≠0.

2.1L3step 1.1

The continuous coordinate x1 takes every real value on N, at points ((c,0,0),p∗). If N were compact, [L3] would make this coordinate bounded. Thus N is noncompact.

3.1L4step 1.1step 2.1step 1.2∎

The compactness hypothesis in [L4] fails, while connectedness and regularity hold. Thus the qualified torus and action-angle conclusions remain consistent, and the refuted conclusion without compactness fails inside the declared free model.

Remarks

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The conjugate time of the harmonic model: the complete integral's mixed derivative is unbounded and the characteristic family refocuses at ωt∈πZ

Physical scope

A worked warning inside the declared harmonic model of the framework's force branch: the explicit complete integral of the oscillator's Hamilton-Jacobi equation is defined only on the time strips between the conjugate times ωt∈πZ; its mixed derivative Sxα=−mωcsc⁡(ωt) is unbounded as those times are approached; and the characteristic family through a fixed event refocuses there (all members with the same initial position pass through the same point a half-period later), so the map from the family's label to the position degenerates. The example asserts no measured value and no claim about any apparatus; it exhibits why the Hamilton-Jacobi statements of this page are local in time and carry no claim across a caustic.

Example

Adopt the harmonic model of The harmonic (linear restoring) model: a declared linear force law with parameter k>0 as in the companion example. For the CM12-CM14 interfaces, declare an ambient one-label potential presentation on Qamb=R3, time window R, mass operator mI3, potential Uamb(y)=ky12/2 and residual force d=0. Its smooth immersion X:R→Qamb, X(x)=(x,0,0) has mass metric G=DXTmI3DX=m and substituted potential kx2/2 (Generalized-coordinate maps of the model, the substituted Lagrangian, the kinetic metric and generalized forces, Potential presentations of a force model, potential and mechanical energy, closed versus exact force fields, local potentials and equipotential level sets, Adopted force model: force maps, the equation of motion, additive composition of force contributions and frame covariance). The transverse equations are 0=0, so scalar harmonic motions reconstruct ambient motions. The displayed scalar Hamiltonian is the generalized-coordinate chart Hamiltonian of The Hamiltonian of a hyperregular potential presentation: the Legendre transform of the mechanical Lagrangian, its domain and its dimensions clause (b).

Take one label of mass m>0, spring constant k>0, ω=k/m>0, T=2π/ω, branch Hamiltonian H(x,p)=p2/(2m)+mω2x2/2, and the family

S(t,x,α)=mω2[(x2+α2)cot⁡(ωt)−2xα csc⁡(ωt)] on the open strips where sin⁡(ωt)≠0. The example verifies:

  1. (nondegeneracy between conjugate times) the mixed derivative is Sxα(t)=−mωsin⁡(ωt), so S is a complete integral of the model's Hamilton-Jacobi equation at every point of each time strip ωt∈(kπ,(k+1)π), and ∣Sxα(t)∣→+∞ as ωt→kπ for every k∈Z; the family has a pole there and offers no complete integral across it.
  2. (degeneration of the characteristic family) the characteristic curves of S are x(t)=αcos⁡(ωt)−βmωsin⁡(ωt),β=Sα(t,x(t),α),and the derivative of the position with respect to the Jacobi label β at fixed (α,t) is ∂x∂β(t)=−sin⁡(ωt)mω,∂x∂β(t)=1Sxα(t)(sin⁡(ωt)≠0),so it vanishes exactly at the conjugatetimes ωt∈πZ, where the map from the label β to the position degenerates while Sxα is unbounded.
  3. (refocusing of the model's motions) independently, the harmonic motions through a fixed event (t0,x0), labelled by their initial momentum q, x(t;q)=x0cos⁡(ω(t−t0))+qmωsin⁡(ω(t−t0)),all satisfyx(t1;q)=−x0 at the conjugate time t1=t0+π/ω, for every q, and ∂x(t;q)/∂q=0 at t=t1: the family of model solutions through the event refocuses at (t1,−x0), so no label of the family can be recovered from the position there.

All data m,k are declared model parameters and no measured value is asserted.

Facts & Assumptions

Given: The harmonic model data m>0, k>0, the constants ω,T, the Hamiltonian H, the function S on the strips sin⁡(ωt)≠0, and the conjugate time t1=t0+π/ω.

[L2]

Calculus (Ck Euclidean maps and diffeomorphisms, Directional derivatives and partial derivatives of a map U⊆Rm→Rn, The Jacobian matrix of partial derivatives and the gradient in the scalar-valued case, The derivatives of sine and cosine are cosine and minus sine, The chain rule, in one line from Carathéodory: if g is differentiable at c and f is differentiable at g(c), then f∘g is differentiable at c with (f∘g)′(c)=f′(g(c)) g′(c), Sums, scalar multiples, products and quotients: (f+g)′(c)=f′(c)+g′(c), (αf)′(c)=αf′(c), (fg)′(c)=f′(c)g(c)+f(c)g′(c), and (f/g)′(c)=(f′(c)g(c)−f(c)g′(c))/g(c)2 when g(c)≠0, The zero sets of sine and cosine and the least positive common period 2 pi, Parity and the Pythagorean identity for sine and cosine, Derivative of an inverse: if f is continuous and injective on a nondegenerate interval I and differentiable at c∈I with f′(c)≠0, then the inverse g is differentiable at f(c) with g′(f(c))=1/f′(c); and if f′(c)=0 then g is not differentiable at f(c), The derivative f′(c)=lim⁡x→cf(x)−f(c)x−c of f:A→R at a point c∈A that is a limit point of A, and differentiability on a set, Intervals of R: the nine order-convex forms, nondegeneracy, and length): (sin⁡)′=cos⁡, (cos⁡)′=−sin⁡, (cot⁡)′=−csc⁡2, (csc⁡)′=−csc⁡cot⁡; the chain rule and algebra of derivatives apply; sin⁡(kπ)=0 and cos⁡(kπ)=(−1)k for integers k; and the one-variable inverse-function rule holds where the derivative is nonzero.

[L4]

Hamilton equations in one dimension (The Hamiltonian field of a phase function for a potential presentation: the unique field Xf with ιXfω=df, and XH=(Hp,−Hx) for the branch Hamiltonian): for the branch Hamiltonian the field is XH=(Hp,−Hx), so x′=p/m and p′=−mω2x along solutions.

Verification

technique · direct; differentiate the displayed family, evaluate the mixed derivative, solve the characteristics explicitly, and exhibit the refocusing of the model's solutions at the conjugate time
1.1L2L3algebra

Mixed derivative: by [L2], differentiating the displayed S gives Sx=mω(xcot⁡(ωt)−αcsc⁡(ωt)) and hence Sxα=−mωcsc⁡(ωt)=−mω/sin⁡(ωt); this is finite and nonzero exactly when sin⁡(ωt)≠0, and ∣Sxα∣→+∞ as ωt→kπ, k∈Z, because sin⁡(kπ)=0. Direct substitution gives St+H(x,Sx)=mω2x22(1+cot⁡2(ωt)−csc⁡2(ωt))=0 on the strips by [L2]. Thus by [L3], S is a complete integral at every point of the strips and has no finite nondegenerate extension across the conjugate times. This is claim 1.

2.1L1L2L3L4step 1.1algebra

Characteristic curves: by [L3], solving β=Sα(t,x,α)=mω(αcot⁡(ωt)−xcsc⁡(ωt)) for x gives x(t)=αcos⁡(ωt)−βmωsin⁡(ωt), and with p=Sx the pair solves x′=p/m, p′=−mω2x; explicitly x′(t)=−αωsin⁡(ωt)−βm−1cos⁡(ωt) and ∂βx(t)=−sin⁡(ωt)/(mω), which vanishes exactly at ωt∈πZ; moreover (∂βx)(t)=1/Sxα(t) by step 1.1. At those times the label β has no first-order effect on the position, so the map from the Jacobi label to the position degenerates while the mixed derivative is unbounded: this is the conjugate time of the family. This is claim 2.

3.1L1L2step 2.1algebra

Refocusing: by [L1] the curve x(t;q)=x0cos⁡(ω(t−t0))+qm−1ω−1sin⁡(ω(t−t0)) is the motion of the model with x(t0)=x0 and x′(t0)=q/m. At t1=t0+π/ω, [L2] gives cos⁡π=−1 and sin⁡π=0, so x(t1;q)=−x0 for every q, and ∂x(t;q)/∂q=(mω)−1sin⁡(ω(t−t0))=0 at t=t1. Hence every member of the family of model solutions through (t0,x0) passes through the single point (t1,−x0), and the initial-momentum label cannot be recovered from the position at t1; by the inverse-function rule of [L2] this is the same degeneration as in step 2.1. This is claim 3.

4.1step 1.1step 2.1step 3.1∎

Claims 1-3 are steps 1.1, 2.1 and 3.1 respectively; the example is verified.

Remarks

  • The failure is a caustic, not an accident of the chart. The half-period refocusing in step 3.1 shows that the obstruction is invariant: at the conjugate time the endpoint-position map of the family of extremals is not locally invertible, so no smooth complete integral based on that family can satisfy the nondegeneracy det⁡Sqα≠0 across the caustic. The companion scope remark records the same warning for the page.

  • No empirical content. The conjugate time π/ω is a property of the ideal harmonic model; the example asserts no measured period or frequency and no claim about a real oscillator.

Sources