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Formal diagram coefficient-to-observable adoption — Examples

1 · Prerequisites

2 · Summary

The companion page specializes the formal pair-production coefficient to massless particles, displays the scalar identical-particle factor and the extra assumption needed for exponential mean and half-life formulas, and evaluates the minimal Dirac spin coefficient in a uniform magnetic field. These are conditional model calculations. The spin coefficient is compared with a separately defined orbital coefficient; no full Landau spectrum, radiative anomaly, apparatus, or measurement is claimed.

3 · Logical flowchart

4 · Definitions, postulates, theorems and proofs

None yet.

5 · Examples, experiments and counterexamples

ExampleConstruction: AI-generatedVerification: AI-generatedverified 2026-10-15 (gpt-6-luna, gpt-6.1-sol, and delegated Codex review/repair agents; see completed run evidence)Open item page →

Massless formal annihilation angular contrast

Physical scope

A massless specialization of the adopted formal one-photon tree coefficient. It compares two angular coefficients and integrates their formal coefficient over the sphere; it is not a measured event ratio or exact continuum QED cross section.

Statement

Use the massless m=M=0 case of the formal tree theorem Formal tree scattering and scalar-decay coefficients, including its stated ACω hypothesis, with s>0. Explicitly take incoming p1,p2 and outgoing k1,k2 on the positive massless shell, so each (E,q) has E=∣q∣>0, with p1+p2=k1+k2=P and h(P,P)=s>0. Use the theorem's proper orthochronous center-of-momentum chart ΛP=(s,0); θ is the Euclidean angle between the nonzero spatial parts of Λp1 and Λk1. The differential coefficient at θ=0 is twice its value at θ=π/2; integrating over the full sphere gives σcoeff=4πα2(ℏc)23s. All three quantities are formal coefficients in the adopted map, not event counts or exact measured cross sections.

Facts & Assumptions

Given: s>0, m=M=0, the theorem's Countable Choice condition, the positive-shell/common-total and center-of-momentum angle data in the Statement, and the coefficient conventions of Formal tree scattering and scalar-decay coefficients and Formal diagram coefficient-to-observable adoption.

[F1]

Formal tree scattering and scalar-decay coefficients: the differential coefficient is α2(ℏc)2βμ[3−βe2−βμ2+βe2βμ2cos⁡2θ]/(4sβe) and the total coefficient is its full-sphere integral.

[F2]

QFT example units, metric, gauge, and pairing conventions: α is dimensionless, [ℏc]=J m, and [s]=J2.

[A1]

Formal diagram coefficient-to-observable adoption: the selected tree result is a leading formal coefficient with no exact continuum or empirical identification.

Example

The angular contrast is a simple consequence of the massless tree angular polynomial.

Verification

1.1givenF1F2algebra

Setting βe=βμ=1 in [F1] gives dσcoeffdΩ=α2(ℏc)24s(1+cos⁡2θ). Thus its values at 0 and π/2 are respectively α2(ℏc)2/(2s) and α2(ℏc)2/(4s), and their ratio is 2. The numerator has unit J2m2 and s has unit J2, so each coefficient has area unit m2.

2.1step 1.1F1A1algebra∎

Integrating the same density uses ∫S2dΩ=4π and ∫S2cos⁡2θ dΩ=4π/3, so σcoeff=α2(ℏc)24s(4π+4π3)=4πα2(ℏc)23s. The adopted reading [A1] introduces no count or measurement record.

ExampleConstruction: AI-generatedVerification: AI-generatedverified 2026-10-15 (gpt-6-luna, gpt-6.1-sol, and delegated Codex review/repair agents; see completed run evidence)Open item page →

Scalar symmetry factor and conditional lifetime model

Physical scope

A massless-daughter scalar formal coefficient example. It explicitly adds an exponential survival model before deriving a mean and half-life; the formal rate coefficient by itself implies neither time law.

Statement

Assume Countable Choice, ACω The Axiom of Countable Choice (ACω), as required by the cited phase-space map and the Borel restriction of Lebesgue measure.

Let s>0, dimensionless λ∈R, parent energy M0>0, and GE∈C∖{0} in joules. For scattering, take the incoming p1,p2 and outgoing k1,k2 on the positive massless scalar shell, each (E,q) having E=∣q∣>0, with common total p1+p2=k1+k2=P, h(P,P)=s>0, and evaluate the coefficient in a proper orthochronous center-of-momentum chart ΛP=(s,0) as in the phase-space supplier. For decay, take massless positive-shell daughters summing to the rest parent P0=(M0,0). With these data the identical final-state quartic total coefficient is σcoeffidentical=λ2(ℏc)232πs, and the distinguishable-final coefficient is twice this value. The identical-daughter decay-rate coefficient is Γcoeff=∣GE∣232πℏM0[s−1]. Set Γ:=Γcoeff>0. For the lifetime calculation only, let (Ξ,F,P) be a probability space in the sense of Probability measures and probability spaces: F is a sigma-algebra on Ξ, and P is a countably additive measure with P(Ξ)=1. Let B([0,∞)) be the sigma-algebra generated by sets U∩[0,∞) for open U⊆R, as in The Borel sigma-algebra of a topological space. Let T:Ξ→[0,∞) be a parent lifetime measured in seconds and measurable in the explicit sense that T−1(B)∈F for every B∈B([0,∞)). Define its law by μT(B):=P(T−1(B)) on those Borel sets. Let ℓ denote one-dimensional Lebesgue measure from Lebesgue measurable sets, the family L(Rn), and the restricted set function λn, restricted to B([0,∞)); this restriction is a measure by Assuming countable choice, every Borel subset of Rn is Lebesgue measurable under the stated Countable Choice assumption. Separately assume the exponential lifetime model, defined by μT(B)=∫BΓe−Γt dℓ(t)for every B∈B([0,∞)). It gives Psurv(t):=P(T−1((t,∞)))=e−Γt for t≥0. Define the mean lifetime as E[T]:=∫[0,∞)t dμT(t), and define the half-life t1/2 by Psurv(t1/2)=1/2. Then the mean lifetime is 1/Γ and the half-life is ln⁡2/Γ. The exponential law is not a consequence of the formal coefficient calculation.

Facts & Assumptions

Given: Countable Choice The Axiom of Countable Choice (ACω); the positive-shell scattering and decay data in the Statement, and the scalar amplitude conventions and coefficient maps of Scalar symmetry factors and decay coefficient units, Complete two-body phase space and coefficient flux map, and Formal diagram coefficient-to-observable adoption.

[F1]

Scalar symmetry factors and decay coefficient units: for identical equal-mass scalars the full-sphere quartic coefficient is λ2(ℏc)2/(32πs); distinguishable final particles give twice this value. The identical-daughter rate coefficient is ∣GE∣21−4ms2/M02/(32πℏM0).

[F2]

QFT example units, metric, gauge, and pairing conventions: [ℏ]=J s and [ℏc]=J m; s is in J2.

[F3]

Probability measures and probability spaces: a probability space is a triple (Ξ,F,P) where F is a sigma-algebra on Ξ and P is a countably additive measure with P(Ξ)=1.

[F4]

The Borel sigma-algebra of a topological space: the Borel sigma-algebra of a topological space is generated by its open sets.

[F5]

Lebesgue measurable sets, the family L(Rn), and the restricted set function λn: one-dimensional Lebesgue measure is the restriction of Lebesgue outer measure to the Lebesgue sigma-algebra.

[F6]

Assuming countable choice, every Borel subset of Rn is Lebesgue measurable: under Countable Choice, every Borel subset of R is Lebesgue measurable, so ℓ denotes its restriction to the stated Borel sigma-algebra.

[A1]

Formal diagram coefficient-to-observable adoption: formal coefficients are adopted leading readings only; no survival law follows from the rate map.

[A2]

For the lifetime calculation only, assume the exponential probability law for T defined in the Statement, with Γ=Γcoeff. This assumption is not part of [A1] or the formal coefficient maps.

Example

The massless special case exposes both the full-sphere identical-particle factor and the distinction between a rate coefficient and a decay law.

Verification

1.1givenF1F2algebra

Set the daughter rest energy to zero in [F1]. The square-root threshold factor becomes 1, so the identical total coefficient is λ2(ℏc)2/(32πs) and the distinguishable total is twice that. The cross-section unit is (J m)2/J2=m2. For the same massless daughter specialization, [F1] gives Γcoeff=∣GE∣232πℏM0. Its unit is J2/(J s J)=s−1, so it is a rate coefficient. Since GE≠0, ℏ>0, and M0>0, this coefficient is strictly positive.

2.1step 1.1F3F4F5F6A1A2algebra∎

By [A2], μT(B)=∫BΓe−Γt dℓ(t) for Borel B⊆[0,∞). Taking B=[0,∞) gives total mass 1, and the mean is E[T]=∫0∞tΓe−Γt dt=[−te−Γt]0∞+∫0∞e−Γt dt=1Γ, by integration by parts; te−Γt→0 since Γ>0. The survival function is continuous and strictly decreasing from 1 to 0, so the defining equation for t1/2 has a unique solution; solving e−Γt1/2=1/2 gives t1/2=ln⁡2/Γ. These formulas use [A2], not the formal rate coefficient alone; no experiment or detector record is specified.

ExampleConstruction: AI-generatedVerification: AI-generatedverified 2026-10-15 (gpt-6-luna, gpt-6.1-sol, and delegated Codex review/repair agents; see completed run evidence)Open item page →

Minimal Dirac spin and orbital coefficient comparison

Physical scope

A uniform-field evaluation of the minimal Dirac spin coefficient and its comparison with a separately defined ideal orbital cyclotron coefficient. It is not a full Landau spectrum, a radiative anomaly calculation, or an experimental prediction.

Statement

Take q=−e with e>0, m>0, and a constant field B=B0z^ with B0>0. It is realized by the smooth SI potential A(x,y,z)=B02(−y,x,0),ϕ=0, for which ∇×A=B0z^, where z^=(0,0,1). Under the Countable Choice and adopted-action hypotheses of Minimal Dirac magnetic benchmark from the adopted action, the formal spin term is −(q/m)S⋅B=(e/m)SzB0. Since Σz=diag⁡(1,−1,1,−1), its two spin eigenvalue coefficients are ΔE↑,↓=±eℏB02m,ΔEgap=eℏB0m. Define the comparison orbital coefficient by ωc,orb:=eB0/m and νc,orb:=ωc,orb/(2π). The cyclic coefficient frequency of the spin gap is νs,coeff:=ΔEgap2πℏ=eB02πm=νc,orb. This is a comparison of formal minimal coefficients. It is not the full Landau spectrum, a radiative correction, a prediction of zero measured anomaly, or a laboratory measurement.

Facts & Assumptions

Given: q=−e≠0, m>0, B0>0, the displayed smooth pure-magnetic potential, and the theorem's Countable Choice and adopted-action hypotheses and conditional minimal Dirac coefficient in Minimal Dirac magnetic benchmark from the adopted action.

[F1]

Minimal Dirac magnetic benchmark from the adopted action: the spin term is −(q/m)S⋅B with S=ℏΣ/2 and its matching convention gives gs=2 at the minimal coefficient level.

[F2]

QFT example units, metric, gauge, and pairing conventions: e is in coulombs, ℏ in J s, m in kilograms, and B0 in tesla.

[F3]

Example observable types and scoped meanings: an adopted coefficient is not a source-reported empirical estimate; empirical uncertainty and conditions would need to accompany a measurement claim.

[A1]

The comparison coefficient is defined as ωc,orb:=eB0/m and νc,orb:=ωc,orb/(2π). This conventional orbital coefficient is supplied for comparison; no orbit equation is derived here.

Example

The uniform field makes the spin eigenvalues and the formal coefficient comparison explicit.

Verification

1.1givenF1algebra

Direct differentiation gives ∇×B02(−y,x,0)=B0z^, so the potential is smooth and satisfies the field hypothesis of [F1]. From [F1] and q=−e, the spin coefficient is +(e/m)SzB0. The explicit diagonal matrix Σz has eigenvalues +1 and −1, so Sz has eigenvalues +ℏ/2 and −ℏ/2. This gives the two stated shifts and their difference eℏB0/m.

2.1step 1.1F2F3A1algebra∎

Dividing that positive gap by 2πℏ yields νs,coeff=eB0/(2πm), equal to νc,orb by [A1]. The unit of eB0/m is s−1 because [T]=kg/(C s); the energy gap has unit joules. The equality is among model coefficients and uses no observation or statistical inference.

Sources