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Yee FDTD and transient Maxwell finite elements

1 · Prerequisites

2 · Summary

This page defines real transient Maxwell fields with uniformly positive material tensors, source continuity, periodic or PEC boundaries, and transmission conventions for aligned material interfaces. Its Yee branch specifies oriented cochains, Hodge masses, leapfrog rows, exact incidence identities, constraint propagation, and the strict spectral CFL condition. The Cartesian Fourier calculation gives the exact finite-grid eigenvalue and distinguishes the strict stability region from its repeated-root endpoint. The consistency and error estimates are explicitly limited to smooth homogeneous periodic data; no Taylor estimate is extended across jumps or an unspecified boundary stencil.

The edge finite element branch defines the conforming Nedelec/RT0 semidiscretization, its finite-dimensional ODE and energy identity, and the curl-energy Ritz map. For the stated smooth mesh-aligned PEC data, canonical edge and face interpolation supplies the approximation rate. The full degree-two and degree-three cochain projections give divergence-compatible magnetic initialization without imposing a zero normal boundary trace; the initialization error is orthogonal to discrete curls in the magnetic weighted inner product. These local interfaces and the time-independent Ritz map yield the stated semidiscrete error estimate.

The incidence maps are summarized by the following diagram. The vertices, edges, faces, and cells are oriented primal cells; the arrows are the corresponding signed coboundary matrices. The two zero composites express boundary-of-boundary cancellation, proved algebraically in the incidence lemma. For the PEC convention, electric edges and volume-charge vertices are restricted as defined in the cochain item while all magnetic face fluxes, including boundary-normal fluxes, remain represented; no separate boundary surface-charge cochain is claimed. The diagram records the maps and their dimensions; no proof relies on a geometric picture.

\mathbb{R}^{N_v} \arrow[r,"G"] & \mathbb{R}^{N_e} \arrow[r,"C"] & \mathbb{R}^{N_f} \arrow[r,"D"] & \mathbb{R}^{N_c}

3 · Logical flowchart

4 · Definitions, theorems and proofs

LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passOpen item page →

Stokes identity on a rectangular Yee face

Statement

Let F={(x0,y,z):y0≤y≤y1, z0≤z≤z1} be an oriented rectangle with normal ex, and let E be a C1 vector field near F. Orient ∂F by the outward-normal-first convention. Then ∫∂FE⋅t ds=∫F(curl⁡E)⋅ex dS=∫y0y1∫z0z1(∂yEz−∂zEy)(x0,y,z) dz dy. The identities for normals ey and ez follow by cyclic permutation of coordinates. Reversing a face orientation reverses both integrals.

Facts & Assumptions

Given: The rectangle and orientation above, a C1 vector field E, and the one-dimensional fundamental theorem of calculus.

[F1]

For a continuously differentiable scalar function on a closed interval, the integral of its derivative is its endpoint difference. (If f:[a,b]→Rm is differentiable with integrable f′ then ∫abf′=f(b)−f(a); and a bounded derivative makes f Lipschitz)

[F2]

Every continuous real function on a closed nondegenerate rectangle is Riemann integrable. (Every continuous function on a closed nondegenerate rectangle in Rm is Riemann integrable)

[F3]

For a Riemann-integrable function on a product of nondegenerate rectangles, each order in which all sections are Riemann integrable has an ordinary iterated integral equal to the product integral. (Riemann--Fubini on product rectangles, with lower and upper section integrals and content-zero exceptional sections)

Proof

1.1F1givenalgebra

If y0=y1 or z0=z1, the four parameterized boundary sides consist of zero-length sides and two coincident sides traversed in opposite directions; their integrals sum to zero. The flux over this zero-area parameterized rectangle and the displayed iterated integral are also zero. This proves the degenerate cases, with the boundary integral interpreted as that four-side sum. For the remaining steps assume y0<y1 and z0<z1. With the stated orientation, the four boundary contributions are ∫y0y1Ey(x0,y,z0) dy, ∫z0z1Ez(x0,y1,z) dz, −∫y0y1Ey(x0,y,z1) dy, and −∫z0z1Ez(x0,y0,z) dz. Apply [F1] to the two differences to rewrite their sum as −∫y0y1∫z0z1∂zEy dz dy+∫z0z1∫y0y1∂yEz dy dz.

2.1F2F3step 1.1algebra

The two integrands ∂yEz and ∂zEy are continuous on the compact rectangle, so each is Riemann integrable by [F2], as is every one-dimensional section, since it too is continuous. Riemann–Fubini [F3] identifies each double integral with either order of its iterated integral. Thus the ∂yEz term in step 1.1 can be written in the same dy-then-dz order as the other term.

3.1step 1.1step 2.1algebra∎

Combining the two terms from step 1.1 using the ordering justified in step 2.1 gives ∫y0y1∫z0z1(∂yEz−∂zEy) dz dy, exactly the x-component of the curl flux. Cyclic relabeling gives the other coordinate faces; reversing the orientation changes the sign of every boundary and flux term.

DefinitionDefinition: Literature-sourcedProof: Not applicablejudge pass (gpt-6-luna)Open item page →

Transient Maxwell system with piecewise materials and boundary conditions

Definition

Let Ω⊂R3 be a bounded Lipschitz polyhedron, or a periodic rectangular cell. The real electric field is E(t,x)∈R3 and the magnetic flux density is B(t,x)∈R3; the magnetic intensity is H=μ−1B. Let ϵ(x) and μ(x) be measurable, time-independent, symmetric matrix fields for which there are constants 0<ϵ0≤ϵ1 and 0<μ0≤μ1 with ϵ0∣v∣2≤vTϵ(x)v≤ϵ1∣v∣2,μ0∣v∣2≤vTμ(x)v≤μ1∣v∣2 for almost every x and every v∈R3. A conductivity tensor σ(x), when present, is measurable, symmetric, and positive semidefinite. The coefficients may jump across finitely many Lipschitz material interfaces. No derivative of a coefficient is part of the model.

In each material region the constitutive fields satisfy ∂t(ϵE)=curl⁡(μ−1B)−Jsrc−σE,∂tB+curl⁡E=0. Here Jsrc is the impressed free-current density, while σE is the conductive current. Electric charge ρ is constrained by div⁡(ϵE)=ρ and the total-current continuity equation ∂tρ+div⁡(Jsrc+σE)=0; the magnetic constraint is div⁡B=0. These equalities are distributional. In the lossless branch set σ=0.

The boundary choice is one of the following. A periodic boundary identifies opposite traces of the rectangular cell. A perfect electric conductor (PEC) boundary imposes zero tangential trace n×E=0 on ∂Ω. At a material interface with no singular surface charge or current, the weak equations are understood with the transmission conditions [n×E]=0, [n⋅B]=0, [n×(μ−1B)]=0, and [n⋅(ϵE)]=0, where [q] is the trace from one side minus the trace from the other. The interface conditions are part of the model convention; no smooth Taylor expansion across a coefficient jump is asserted.

For PEC, the weak Ampere equation is (ϵEt,v)L2−(μ−1B,curl⁡v)L2=−(Jsrc+σE,v)L2 for every v∈H0(curl⁡;Ω) as defined in Zero tangential trace H(curl) space; the periodic branch uses periodic H(curl⁡) test fields. Faraday’s equation remains Bt+curl⁡E=0 in distributions. These weak forms define the test-space and boundary convention used by the edge finite element method.

The weighted field norms are ∥E∥ϵ2=∫ΩETϵE dx and ∥B∥μ−12=∫ΩBTμ−1B dx. The uniform coefficient bounds make them equivalent to the ordinary L2 norms. All later smooth-error claims require smoothness separately on each mesh-aligned material region.

DefinitionDefinition: Literature-sourcedProof: Not applicableOpen item page →

Oriented Maxwell cochains, masses, and the Yee grid

Definition

Let K be a finite oriented three-dimensional cell complex with vertex, edge, face, and volume cochains. An edge cochain records oriented electric line integrals, a face cochain records oriented magnetic fluxes, and a vertex cochain records electric charge. Write Nv,Ne,Nf,Nc for the retained vertex, edge, face, and cell counts. On a periodic cell, identify opposite cells with orientation preserved and let G,C,D be the full vertex-to-edge gradient, edge-to-face curl, and face-to-cell divergence incidence matrices, each the transpose of its signed oriented boundary matrix. For a PEC closure, “interior” means not in the boundary subcomplex. Keep only interior electric edges as unknowns and only interior vertices as volume-charge locations, but keep all face fluxes, including boundary-normal magnetic fluxes, and all cells. This closure has no separate boundary surface-charge cochain. Define G and C by restricting the absolute vertex-edge and edge-face incidence matrices to those rows and columns. This mixed closure imposes zero tangential electric edge cochains on the boundary while allowing a fixed normal magnetic flux on boundary faces. In both cases, G∈RNe×Nv, C∈RNf×Ne, and D∈RNc×Nf satisfy CG=0 and DC=0.

The electric, magnetic, and conductive material matrices are real symmetric matrices Me∈RNe×Ne, Mb∈RNf×Nf, and S∈RNe×Ne, respectively. The first two are positive definite and represent the discrete weighted inner products induced by ϵ and μ−1; S is positive semidefinite and represents conductivity. Write ⟨e1,e2⟩Me=e1TMee2, ⟨b1,b2⟩Mb=b1TMbb2, and ∥e∥Me2=⟨e,e⟩Me, ∥b∥Mb2=⟨b,b⟩Mb. In a homogeneous isotropic periodic Cartesian grid with spacings hx,hy,hz and cell volume V=hxhyhz, the diagonal entries for an x-edge and an x-normal face are ϵV/hx2=ϵhyhz/hx and μ−1hx/(hyhz); the y and z entries are obtained by cyclic permutation. These values are dual-volume Hodge weights for line-integral and face-flux cochains. A compatible PEC closure uses the corresponding truncated dual volumes for free electric edges, while the magnetic mass includes boundary faces; the resulting matrices remain positive definite. The discrete constraints are −GTMeen=ρn on interior vertices and Dbn−1/2=0 on all cells.

The minus sign in the electric constraint is essential: an edge oriented from tail to head has incidence entries −1,+1, so −GT is the outgoing-flux divergence. Thus ρ represents physical electric charge with the sign of div⁡(ϵE) in Transient Maxwell system with piecewise materials and boundary conditions.

For current cochains jn+1/2 and charge rows ρn, the discrete continuity condition means ρn+1−ρn−Δt GT(jn+1/2+Sen+1+en2)=0. For PEC this is the interior-vertex volume-charge relation; this closure has no separate boundary surface-charge/current cochain.

The cochain identities CG=0 and DC=0 are not imposed as an extra numerical approximation: they follow from oriented boundary-of-boundary cancellation, including the PEC row and column restrictions, as proved in Incidence curl has zero discrete divergence and gradient curl ↗. No cell geometry picture is used as a proof.

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Incidence curl has zero discrete divergence and gradient curl

Statement

For the incidence matrices G,C,D of Oriented Maxwell cochains, masses, and the Yee grid, one has CG=0 and DC=0. The conclusion holds for the full periodic complex and for the PEC mixed closure defined there.

Facts & Assumptions

Given: A finite oriented cell complex and the PEC mixed-or-periodic boundary convention in Oriented Maxwell cochains, masses, and the Yee grid.

[F1]

Before the PEC restriction, G,C,D are the transposes of the oriented boundary maps on vertices, edges, faces, and volumes. The PEC mixed closure retains only interior electric edges and interior vertices but all faces and cells. (Oriented Maxwell cochains, masses, and the Yee grid)

[F2]

For an oriented cell complex, the cellular boundary matrix is its signed incidence matrix and consecutive cellular boundaries compose to zero. (Cellular boundary is the incidence degree matrix, The cellular boundary squares to zero)

Proof

1.1F1F2algebra

Let ∂k be the absolute oriented cellular boundary from degree k to degree k−1. By [F2], ∂1∂2=0. Since Gˉ=∂1T and Cˉ=∂2T, transposition gives CˉGˉ=(∂1∂2)T=0. For a polygonal face this is the telescoping sum of endpoint differences around its boundary, including a triangular or rectangular Yee face.

1.2F1F2algebra

Similarly [F2] gives ∂2∂3=0, hence DˉCˉ=(∂2∂3)T=0. For a tetrahedral or cubical volume, each edge in the boundary of its oriented boundary has two occurrences with opposite induced signs. The cellular identity covers arbitrary cell attachments as well, so this argument does not restrict the claim to tetrahedra.

2.1F1step 1.1step 1.2algebra∎

Periodic identification identifies faces with the prescribed orientation, so the quotient cell structure retains oriented boundary-of-boundary cancellation. For PEC, let Gˉ,Cˉ,Dˉ be the absolute incidence matrices and let Pe select interior edges and Pv select interior vertices. The matrices are G=PeGˉPv, C=CˉPeT, and D=Dˉ. An interior vertex is incident to no boundary edge, so PeTPeGˉPv=GˉPv. Hence CG=CˉGˉPv=0, while DC=DˉCˉPeT=0. This retains boundary-face magnetic cochains although boundary electric edge values are fixed.

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The midpoint-conductivity Yee electric solve is well defined

Statement

Let Me be the positive definite electric mass matrix, let S be the positive semidefinite conductivity matrix, and let Δt>0. Then Me+(Δt/2)S is symmetric positive definite, hence invertible. Thus each midpoint-conductivity Yee electric row has a unique solution.

Facts & Assumptions

Given: The material matrices and time-step convention of Oriented Maxwell cochains, masses, and the Yee grid.

[F1]

Me is symmetric positive definite and S is symmetric positive semidefinite. (Oriented Maxwell cochains, masses, and the Yee grid)

Proof

1.1F1givenalgebra

The matrix Me+(Δt/2)S is symmetric because both summands are symmetric. For each nonzero x, its quadratic form is xTMex+(Δt/2)xTSx>0+0=0, using Δt>0 and the two definiteness hypotheses. Hence it is positive definite.

2.1step 1.1algebra∎

A positive definite square matrix has trivial kernel: if (Me+(Δt/2)S)x=0, then its quadratic form at x is zero and step 1.1 forces x=0. A linear map from a finite-dimensional space to itself with trivial kernel is bijective, so the solve exists uniquely for every right-hand side.

DefinitionDefinition: Literature-sourcedProof: Not applicableOpen item page →

Edge-face Maxwell finite element semidiscretization

Definition

Let Ω be a bounded contractible Lipschitz polyhedron with a finite matching affine tetrahedral mesh Th, and use the real lowest-order spaces Wh0,Nh1,Nh2,Nh3 defined in Lowest-order Whitney and Nedelec de Rham spaces. The electric trial field is Eh(t)∈Nh1∩H0(curl⁡;Ω); the magnetic flux field is Bh(t)∈Nh2, with no imposed zero normal trace on Bh. PEC means the closure-defined zero tangential subspace from Zero tangential trace H(curl) space. Periodic analogues use the periodic cell complex. Countable Choice is inherited from the H(div) and affine Piola space definitions in the suppliers; the finite matrix operations below use no additional choice.

Put Vh:=Nh1∩H0(curl⁡;Ω). Choose an edge basis {ϕi}i=1Ne of the electric trial space Vh and a face basis {ψa}a=1Nf of Nh2, so Ne=dim⁡Vh and Nf=dim⁡Nh2. Define the symmetric mass matrices (Me)ij=∫ΩϕjTϵϕi dx,(Mb)ab=∫ΩψbTμ−1ψa dx. They are positive definite by the coefficient bounds in Transient Maxwell system with piecewise materials and boundary conditions and linear independence of the finite element bases. Let C and D be the coefficient matrices, in these chosen bases, of the restricted map curl⁡:Vh→Nh2 and of div⁡:Nh2→Nh3. The moment-commuting supplier gives DC=0 on the full spaces, hence also after restriction to Vh. Set ji(t)=∫ΩJsrc(t)⋅ϕi dx, with Jsrc∈C([0,T];L2(Ω;R3)). The lossless, conductivity-free semidiscretization with this source is Mee˙−CTMbb=−j,b˙+Ce=0. The coefficient ODE is defined for arbitrary initial coefficients. To represent the magnetic constraint of the Maxwell model, require Db(0)=0: the Faraday row and DC=0 give Db˙=−DCe=0, so Db(t)=Db(0) and compatible data remain divergence-free. An incompatible initial divergence is preserved, not corrected by this ODE. This is a spatial Galerkin system only; no time integrator is included. The cochain convention and weak material-interface formulation come from the declared spaces and Transient Maxwell system with piecewise materials and boundary conditions. Smooth interpolation and a uniformly bounded commuting projection are separate prerequisites for the later error estimate and are not asserted by this definition.

AlgorithmAlgorithm: Literature-sourcedProof: Not applicableOpen item page →

Lossless or midpoint-conductive Yee leapfrog update

Definition

Choose a finite complex and boundary closure as in Oriented Maxwell cochains, masses, and the Yee grid, step size Δt>0, initial e0∈RNe and b−1/2∈RNf, and source rows jn+1/2∈RNe. The output is a sequence en at integer times and bn+1/2 at half-integer times. For each n≥0, perform the ordered instructions

  1. Update the face flux by bn+1/2=bn−1/2−Δt Cen.

  2. Solve the electric row (Me+Δt2S)en+1=(Me−Δt2S)en+Δt CTMbbn+1/2−Δt jn+1/2.

For S=0 this is the lossless Yee leapfrog scheme. For S⪰0, the midpoint term is the specified trapezoidal treatment of conductivity. The row is well defined for every input because its matrix is invertible by The midpoint-conductivity Yee electric solve is well defined. This procedure makes no stability claim; the lossless stability condition is proved separately.

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Existence and uniqueness for the finite-dimensional Maxwell ODE

Statement

Assume the Countable Choice branch inherited from Edge-face Maxwell finite element semidiscretization. Let T≥0. For any finite matching mesh, initial edge and face coefficients (e0,b0), and continuous load vector j:[0,T]→RNe, the source-driven semidiscrete Maxwell system Mee˙−CTMbb=−j(t),b˙+Ce=0,(e(0),b(0))=(e0,b0) has one and only one global C1 solution on [0,T] when T>0, with domain-relative one-sided endpoint derivatives. When T=0, there is exactly one map with the prescribed initial value; it extends locally to the same coefficient ODE with the load held constant at j(0), and any two such continuations agree on their common interval containing zero. No derivative or IVP solution on the singleton itself is asserted. The construction and uniqueness argument use finite-dimensional linear algebra and the matrix-ODE supplier; no choice axiom stronger than the inherited Countable Choice branch is used.

Facts & Assumptions

Given: The real FE matrices and curl map from the semidiscretization, initial coefficients, and a continuous load vector on [0,T], T≥0.

[A1]

Countable Choice is inherited from the H(div⁡)/Piola space definitions used to form the FE spaces; the local ODE argument makes no further choice. (The Axiom of Countable Choice (ACω), Edge-face Maxwell finite element semidiscretization)

[F1]

For a continuous matrix field C(t) on a nondegenerate compact interval, the matrix IVP Y′=C(t)Y, Y(t0)=Y0, has a unique global solution, with domain-relative endpoint derivatives. On a singleton the prescribed initial value determines only a map, with a unique local continuation for the constant coefficient field. (Linear matrix ODEs have unique global solutions on a fixed interval)

[F2]

Me is invertible, and the semidiscrete rows are e˙=Me−1CTMbb−Me−1j(t) and b˙=−Ce. (Edge-face Maxwell finite element semidiscretization)

Proof

1.1A1F2givenconstruct

Put x=(e,b)∈RN, N=Ne+Nf, and A=(0Me−1CTMb−C0), f(t)=(−Me−1j(t),0). By [F2], x′=Ax+f(t). Form the continuous (N+1)×(N+1) matrix A(t)=(Af(t)00) and the initial matrix Y0 whose last column is (x0,1)T and whose other columns are zero.

2.1F1step 1.1algebra

If T=0, the prescribed initial coefficients determine the unique singleton map. Hold j constant at j(0) and use the matrix A of step 1.1 on [−1,1]. By [F1] it has a unique matrix solution there through Y0 at zero. Its last column has last entry one and its top block solves the constant-load coefficient ODE, giving the asserted continuation. Uniqueness on any common interval containing zero follows by applying [F1] to each compact subinterval joining zero to a point of overlap. No singleton derivative is taken.

3.1F1step 1.1algebra∎

Now assume T>0. By [F1], Y′=A(t)Y, Y(0)=Y0 has a unique global solution. Its last column (x(t),s(t))T satisfies s′(t)=0 and s(0)=1, so s(t)=1, while the top block satisfies x′=Ax+f(t) and x(0)=x0. Thus it gives a global solution of the Maxwell coefficient system. Any two such coefficient solutions yield two matrix solutions with the same last-column initial data; uniqueness in [F1] forces their last columns to agree.

DefinitionDefinition: Literature-sourcedProof: Not applicableOpen item page →

Maxwell curl-energy Ritz projection

Definition

Assume Countable Choice in the inherited edge/face finite-element space branch. Let V=H0(curl⁡;Ω) with the PEC convention in Edge-face Maxwell finite element semidiscretization, and let Vh=Nh1∩H0(curl⁡;Ω). Define m(u,v)=∫ΩvTϵu dx,a(u,v)=∫Ω(curl⁡v)Tμ−1curl⁡u dx,a+(u,v)=m(u,v)+a(u,v). For u∈V, the Maxwell curl-energy Ritz projection Rhu∈Vh is the solution of a+(Rhu,vh)=a+(u,vh)(vh∈Vh). Its finite-dimensional well-definedness, orthogonality, and best-approximation property are supplied by Well-definedness and best approximation of the Maxwell Ritz map ↗.

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Smooth lowest-order Nedelec and RT0 interpolation estimate

Statement

Assume Countable Choice only in the H(div)/Piola space branch inherited from the suppliers below. Let Th be a finite matching affine tetrahedral mesh of a bounded polyhedron, with shape-regularity constant σ and h=max⁡KhK. Assume material interfaces are mesh-aligned. Let u,v be piecewise C1 on cell closures, with curl⁡u, div⁡v also piecewise C1, and with matching tangential traces of u and matching normal traces of v. The canonical edge and face moment interpolants Ih1,Ih2 are those in Whitney edge, face, and cell moments commute with grad, curl, and div. Then ∥u−Ih1u∥L2(Ω)+∥curl⁡(u−Ih1u)∥L2(Ω)+∥v−Ih2v∥L2(Ω)+∥div⁡(v−Ih2v)∥L2(Ω)≤Cσh∣Ω∣1/2max⁡K∈Th(∥∇u∥L∞(K)+∥∇curl⁡u∥L∞(K)+∥∇v∥L∞(K)+∥∇div⁡v∥L∞(K)). The constant depends only on reference-element basis norms and σ. This estimate is only for the canonical smooth-input interpolants; it makes no boundedness claim on all of H(curl⁡) or H(div⁡).

Facts & Assumptions

Given: A finite matching shape-regular affine tetrahedral mesh, the real lowest-order Nedelec and RT0 local spaces, and piecewise smooth fields with the stated trace compatibility.

[A1]

Countable Choice means every countable family of nonempty sets has a choice function. It is inherited from the affine Piola and H(div) definitions; no stronger Choice axiom is used. (The Axiom of Countable Choice (ACω))

[F1]

The local spaces are the span of the six Whitney edge fields ϕij=λi∇λj−λj∇λi and RT0(K)={a+cx:a∈R3,c∈R}. (Lowest-order Whitney and Nedelec de Rham spaces)

[F2]

The six oriented edge circulations are unisolvent and the local edge space is {a+b×x:a,b∈R3}, so it contains every constant vector field. (Lowest-order Nedelec edge circulation unisolvence)

[F3]

For smooth inputs the moment interpolants are globally conforming and commute cellwise with gradient, curl, and divergence; in particular curl⁡Ih1u=Ih2curl⁡u and div⁡Ih2v=Ih3div⁡v. (Whitney edge, face, and cell moments commute with grad, curl, and div)

[F4]

Covariant and contravariant affine Piola maps preserve oriented edge and face moments, with pushforwards A−Tu^ and (det⁡A)−1Av^. (Affine Piola maps commute with differential operators and preserve moments)

[F5]

Shape regularity gives ∥AK∥≤CσhK, ∥AK−1∥≤CσhK−1, and cσhK3≤∣K∣≤CσhK3. (Matching affine simplicial meshes and shape regularity)

Proof

1.1A1F1F4F5givenalgebra

On a fixed reference tetrahedron, each canonical basis function has finite L2 norm. Under the covariant Piola map, [F4] and [F5] give ∥ϕK,e∥L2(K)≤CσhK−1hK3/2=CσhK1/2 for each edge basis function. Under the contravariant Piola map they give ∥ψK,F∥L2(K)≤CσhK−3hKhK3/2=CσhK−1/2 for each unit-face-flux RT0 basis function.

1.2F3givenalgebra

By [F3], div⁡IK2v=IK3div⁡v, and IK3 is the cell average because its defining degree of freedom is the cell integral. Thus ∣div⁡v(x)−IK3div⁡v∣≤hK∥∇div⁡v∥L∞(K) throughout K, and ∥div⁡(v−IK2v)∥L2(K)≤ChK5/2∥∇div⁡v∥L∞(K).

2.1A1F1F2step 1.1givenalgebra

Fix K and xK∈K, and put uK=u(xK), a constant vector in the local Nedelec space by [F2]. For each of its six edges, the mean-value bound gives ∣∫e(u−uK)⋅t ds∣≤hK2∥∇u∥L∞(K). By edge-moment unisolvence [F2], IK1(u−uK) is the sum of these six coefficients times the corresponding basis functions. Step 1.1 and ∥u−uK∥L2(K)≤ChK5/2∥∇u∥∞ therefore yield ∥u−IK1u∥L2(K)≤CσhK5/2∥∇u∥L∞(K).

2.2A1F1F3step 1.1givenalgebra

Set q=curl⁡u and qK=q(xK), a constant RT0 field. By the curl commuting identity [F3], curl⁡IK1u=IK2q. Each face-flux coefficient of q−qK is at most ChK3∥∇q∥L∞(K); multiplying the four coefficients by the RT0 basis bounds in step 1.1 and adding ∥q−qK∥L2(K) gives ∥curl⁡(u−IK1u)∥L2(K)≤CσhK5/2∥∇curl⁡u∥L∞(K).

2.3A1F1F3step 1.1givenalgebra

For v, set vK=v(xK), again a constant in RT0. Each of the four face-flux coefficients of v−vK is bounded by ChK3∥∇v∥L∞(K). The RT0 basis scaling in step 1.1 and ∥v−vK∥L2(K)≤ChK5/2∥∇v∥∞ give ∥v−IK2v∥L2(K)≤CσhK5/2∥∇v∥L∞(K).

3.1F3F5step 2.1step 2.2step 2.3step 1.2algebra∎

Square and sum the four local bounds. By [F5], hK5≤Cσh2∣K∣; the cell interiors are disjoint and sum to Ω. Taking square roots gives the displayed global estimate with the maximum cell derivative bound and the factor ∣Ω∣1/2. The matching traces and the conformity part of [F3] assemble the interpolants globally.

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Compatible discrete charge and magnetic divergence propagate

Statement

For the Yee update in Lossless or midpoint-conductive Yee leapfrog update, suppose the initial rows satisfy −GTMee0=ρ0 and Db−1/2=0. If the source and charge rows satisfy ρn+1−ρn−Δt GT(jn+1/2+Sen+1+en2)=0 at every step, then −GTMeen=ρn and Dbn−1/2=0 for every later step. This is exact constraint propagation; it does not assert stability for a time step violating the CFL condition.

Facts & Assumptions

Given: A finite incidence complex, the Yee rows, initial charge and magnetic constraints, and the discrete continuity equation above.

[F1]

The Yee magnetic row is bn+1/2=bn−1/2−Δt Cen and its electric row is Me(en+1−en)/Δt+S(en+1+en)/2=CTMbbn+1/2−jn+1/2. (Lossless or midpoint-conductive Yee leapfrog update)

[F2]

The incidence maps satisfy CG=0 and DC=0 for the selected periodic or PEC-relative complex. (Incidence curl has zero discrete divergence and gradient curl)

[F3]

Discrete charge continuity is the displayed update for ρ and total current j+S(en+1+en)/2. (Oriented Maxwell cochains, masses, and the Yee grid)

Proof

1.1givenF1F2induction

Apply D to the magnetic row in [F1]. Then Dbn+1/2=Dbn−1/2−Δt DCen=Dbn−1/2 by [F2]. Starting from Db−1/2=0, induction gives Dbn−1/2=0 at every half step.

2.1givenF1F2F3algebra∎

Apply −GT to the electric row in [F1]. Since GTCT=(CG)T=0, this gives −GTMeen+1+GTMeen=ΔtGT(jn+1/2+S(en+1+en)/2). By [F3], the right side equals ρn+1−ρn. Thus the physical-charge residual −GTMeen−ρn is constant in n and is initially zero, so it remains zero.

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Strict spectral CFL positivity and Yee modified energy

Statement

Set K=CTMbC. If the retained electric cochain space is zero-dimensional, define λmax⁡:=0; otherwise set λmax⁡:=max⁡e≠0eTKeeTMee. For a lossless, source-free update from Lossless or midpoint-conductive Yee leapfrog update, define En:=12(en)TMeen+12(bn−1/2)TMbbn+1/2,bcn:=bn−1/2+bn+1/22. Then En is independent of n, and En≥12(1−Δt2λmax⁡4)∥en∥Me2+12∥bcn∥Mb2. Consequently, the actual strict spectral condition Δt2λmax⁡<4 makes this modified energy positive on admissible staggered states and controls the electric field and the centered magnetic field. When λmax⁡>0, at equality the energy loses coercivity and a maximal mode has a repeated root −1; above equality a mode grows exponentially. If λmax⁡=0, the strict condition is automatic for every Δt>0 and neither endpoint case occurs.

Facts & Assumptions

Given: Δt>0, a finite Yee complex, symmetric positive definite Me,Mb, no source, and S=0.

[F1]

The mass matrices are symmetric positive definite, and K=CTMbC is the curl-curl matrix. (Oriented Maxwell cochains, masses, and the Yee grid)

[F2]

The lossless rows are bn+1/2=bn−1/2−ΔtCen and Me(en+1−en)=ΔtCTMbbn+1/2. (Lossless or midpoint-conductive Yee leapfrog update)

Proof

1.1F1F2givenalgebra

If Ne=0, the electric cochain is necessarily zero and C is the zero map from the zero space. The Faraday row in [F2] makes bn+1/2=bn−1/2 at every step, while the electric row is an equality in the zero space. Thus bcn=bn+1/2 is constant and En=12∥bcn∥Mb2. With the stated convention λmax⁡=0, this proves conservation, the lower bound, and positivity on the remaining magnetic state for every Δt>0; there is no positive-eigenvalue endpoint case. For the rest of the proof assume Ne>0. The quotient defining λmax⁡ is continuous on the compact set {e:eTMee=1}, so the maximum exists and is finite. Also eTKe=(Ce)TMb(Ce)≥0, hence λmax⁡≥0. From the first row of [F2], bn−1/2=bcn+ΔtCen/2 and bn+1/2=bcn−ΔtCen/2. Expanding their Mb inner product gives En=12∥en∥Me2+12∥bcn∥Mb2−Δt28∥Cen∥Mb2.

1.2F2algebra

Using [F2], the electric-energy increment is 12∥en+1∥Me2−12∥en∥Me2=(en+1+en2)TMe(en+1−en)=Δt(en+1+en2)TCTMbbn+1/2. The magnetic cross-energy increment is 12(bn+1/2)TMb(bn+3/2−bn−1/2)=−Δt(en+1+en2)TCTMbbn+1/2, by applying the Faraday row at times n and n+1. The two increments cancel, proving conservation.

2.1step 1.1F1F2algebra

By the definition of λmax⁡, ∥Cen∥Mb2=(en)TKen≤λmax⁡∥en∥Me2. Substitution into step 1.1 gives the stated lower bound. When Δt2λmax⁡<4, its electric coefficient is positive. If an admissible staggered state has zero energy, the bound forces en=0 and bcn=0; the Faraday row in [F2] then gives bn+1/2=bn−1/2, so bcn=bn−1/2=bn+1/2=0. Thus the energy is positive definite on update states.

3.1F1F2algebra∎

Subtract the electric row in [F2] at indices n and n−1, then use the magnetic row to replace bn+1/2−bn−1/2; this gives Me(en+1−2en+en−1)+Δt2Ken=0. If Δt2λmax⁡=4, a maximizing vector v satisfies Kv=λmax⁡Mev by the constrained Rayleigh-quotient maximum. Thus en=qnv obeys qn+1−2qn+qn−1+Δt2λmax⁡qn=0, whose characteristic polynomial is (r+1)2. Hence qn=(−1)n(a+bn) is a solution and grows linearly when b≠0. It is compatible with the full first-order rows by setting bn+1/2=(qn+1−qn)Cv/(Δtλmax⁡): the Ampere row follows from Kv=λmax⁡Mev, and the Faraday row follows from the scalar recurrence. For Δt2λmax⁡>4, the same recurrence has real reciprocal roots, one with modulus greater than one. This proves the endpoint caveat and instability above it.

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Second-order consistency of the homogeneous periodic Yee scheme

Statement

Let a periodic rectangular cell be discretized by a uniform Cartesian Yee grid with spacings hx,hy,hz, h=max⁡jhj, and constant scalar coefficients ϵ,μ>0. Let (E,B) be a source-free smooth periodic Maxwell solution on [0,T], with the spatial derivatives of E through total order four, ∂t4E, and ∂t3B bounded. Sample E(tn) by exact oriented edge line integrals e∗n and B(tn+1/2) by exact oriented face fluxes b∗n+1/2. Define rhn=Mee∗n+1−2e∗n+e∗n−1Δt2+CTMbCe∗n,shn=b∗n+1/2−b∗n−1/2+Δt Ce∗n. With the homogeneous diagonal Hodge weights of Oriented Maxwell cochains, masses, and the Yee grid, there is a constant CT independent of the cell counts such that, whenever Δt≤tn≤T−Δt, ∥rhn∥Me−1≤CT(h2+Δt2),∥shn∥Mb≤CTΔt3. Here ∥r∥Me−12=rTMe−1r. This is a smooth homogeneous periodic consistency result; it asserts no Taylor estimate across coefficient jumps or a PEC boundary closure.

Facts & Assumptions

Given: A homogeneous periodic Cartesian grid, exact edge and face samples of a smooth source-free Maxwell solution, and the lossless Yee rows.

[F1]

The periodic Cartesian masses use edge weights ϵhyhz/hx and face weights μ−1hx/(hyhz), cyclically. (Oriented Maxwell cochains, masses, and the Yee grid)

[F2]

The homogeneous lossless Yee rows use the incidence curl at integer electric and half-integer magnetic times. (Lossless or midpoint-conductive Yee leapfrog update)

[F3]

The continuous equations imply ϵEtt+μ−1curl⁡curl⁡E=0 and Bt=−curl⁡E. (Transient Maxwell system with piecewise materials and boundary conditions)

[F4]

On each axis-parallel rectangular face, exact edge circulation equals the exact curl flux. (Stokes identity on a rectangular Yee face)

Proof

1.1F1givenalgebra

Let ux=ex/hx denote the line average of the x component on an x-edge; define uy,uz cyclically. For values on the corresponding staggered locations, define δiδjf(r) by the four-corner formula [f(r+hi2ei+hj2ej)−f(r+hi2ei−hj2ej)−f(r−hi2ei+hj2ej)+f(r−hi2ei−hj2ej)]/(hihj). Expanding the four signed face incidences around an x-edge and inserting [F1] gives the normalized electric operator hx−1(Me−1CTMbCe)x=c2(−δy2ux−δz2ux+δxδyuy+δxδzuz),c2=(ϵμ)−1, where δj2f=(f(x+hjej)−2f(x)+f(x−hjej))/hj2 and δiδj is the corresponding centered staggered mixed difference. The y and z components follow by the same cyclic incidence expansion.

1.2F1F2F3F4algebra

For every face, the exact circulation cochain Ce∗n equals the face flux of curl⁡E(tn) by [F4]. Taylor’s formula in time around tn gives ∫tn−Δt/2tn+Δt/2 ⁣ ⁣ ⁣∫Fcurl⁡E(t)⋅n dS dt=Δt∫Fcurl⁡E(tn)⋅n dS+O(∣F∣Δt3∥∂t2curl⁡E∥∞). Faraday’s equation in [F3] identifies the left side with −∫F(B(tn+Δt/2)−B(tn−Δt/2))⋅n dS. Thus each face entry of shn is bounded by C∣F∣Δt3 times the derivative bound. The face weights in [F1] turn the sum of their squared entries into at most CTΔt6 times the fixed box volume, so ∥shn∥Mb≤CTΔt3≤CT′Δt2 on the stated time range.

2.1F1F3step 1.1algebra

Taylor’s formula with integral remainder gives δj2f=∂j2f+O(hj2∥∂j4f∥∞) and δiδjf=∂i∂jf+O((hi2+hj2)∥D4f∥∞). Averaging along the edge changes the midpoint value of each needed derivative by at most O(h2) by the same symmetric Taylor estimate. Therefore the stencil in step 1.1 differs from curl⁡curl⁡E by at most Ch2 pointwise. The centered time second difference of the exact edge integrals differs from the edge integral of Ett by at most CΔt2 times the stated fourth time-derivative bound. The continuous equation [F3] cancels the leading terms. For an x-edge, the resulting electric covector entry is bounded by Cϵhyhz(h2+Δt2), with cyclic area factors for the other orientations. Summing squared entries with the reciprocal edge masses in [F1] contributes a factor proportional to hxhyhz per edge, so ∥rhn∥Me−1≤CT(h2+Δt2), since the dual cell volumes sum to the fixed box volume.

3.1step 2.1step 1.2algebra∎

The electric bound from step 2.1 and the separate face bound from step 1.2 give the two asserted residual estimates.

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Semidiscrete edge-face Maxwell energy conservation

Statement

Assume Countable Choice only as inherited from the real H(div⁡)/Piola finite-element space interfaces in Edge-face Maxwell finite element semidiscretization. For the lossless source-free semidiscretization Mee˙−CTMbb=0,b˙+Ce=0, the weighted energy Hh(t)=12∥e(t)∥Me2+12∥b(t)∥Mb2 is constant in time. The local matrix calculation uses no further choice principle.

Facts & Assumptions

Given: The finite-dimensional semidiscrete fields, symmetric positive definite matrices, and the source-free equations above.

[A1]

The Countable Choice Axiom is the principle that every countable family of nonempty sets has a choice function; it is included only because the imported FE-space and Piola definitions declare it. (The Axiom of Countable Choice (ACω))

[F1]

Me,Mb are symmetric positive definite and the semidiscrete equations are Mee˙=CTMbb and Mbb˙=−MbCe. (Edge-face Maxwell finite element semidiscretization)

Proof

1.1A1F1algebra

On a singleton time interval the energy is constant immediately; assume henceforth that the time interval is nondegenerate. In the declared Countable Choice branch [A1], the FE bases and matrices in [F1] are fixed finite objects; the calculation below makes no selection. Differentiating the electric part gives ddt12eTMee=eTMee˙=eTCTMbb.

2.1F1step 1.1algebra∎

Differentiating the magnetic part gives ddt12bTMbb=bTMbb˙=−bTMbCe=−eTCTMbb, because the scalar transpose equals itself. The two derivatives cancel, so Hh′(t)=0 throughout the interval of existence.

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Well-definedness and best approximation of the Maxwell Ritz map

Statement

In the Countable Choice branch of Maxwell curl-energy Ritz projection, the equation defining Rhu has a unique solution for each u∈V. Moreover, with ∥v∥a+2=a+(v,v), ∥u−Rhu∥a+≤inf⁡vh∈Vh∥u−vh∥a+.

Facts & Assumptions

Given: The finite-dimensional real edge space and symmetric form a+ from Maxwell curl-energy Ritz projection, with uniformly positive definite ϵ and μ−1.

[A1]

Countable Choice is inherited from the H(div) and affine Piola definitions that supply the FE spaces; the local linear-algebra argument below uses only the given finite space. (The Axiom of Countable Choice (ACω), Maxwell curl-energy Ritz projection)

[F1]

The mass form m and curl form a are symmetric, and their sum satisfies a+(v,v)≥c(∥v∥L22+∥curl⁡v∥L22) for some c>0. (Maxwell curl-energy Ritz projection)

Proof

1.1A1F1givenalgebra

By [F1], the Gram matrix of a+ in any basis of the finite-dimensional Vh is symmetric positive definite. Hence its kernel is zero and it is invertible, so the linear system defining Rhu has exactly one solution.

1.2F1givenalgebra

Subtracting the defining equation from itself gives a+(u−Rhu,vh)=0 for every vh∈Vh.

2.1A1F1step 1.2algebra∎

For arbitrary wh∈Vh, write u−wh=(u−Rhu)+(Rhu−wh). The second summand lies in Vh, so [step 1.2] makes the cross term zero in the a+ inner product. Thus ∥u−wh∥a+2=∥u−Rhu∥a+2+∥Rhu−wh∥a+2≥∥u−Rhu∥a+2. Taking the infimum proves the claim.

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Cartesian Yee symbol, numerical dispersion, and grid CFL bound

Statement

Consider a homogeneous isotropic periodic Yee grid with ϵ,μ>0, wave speed c=(ϵμ)−1/2, spacings hx,hy,hz, and Nx,Ny,Nz cells. Its allowed wave angles are θj=2πmj/Nj. On a mode with wave vector kj=θj/hj, the transverse curl-curl eigenvalue is λ(θ)=c2∑j∈{x,y,z}4hj2sin⁡2(θj2), and the lossless Yee leapfrog dispersion relation is sin⁡2(ωΔt2)=c2Δt2∑j∈{x,y,z}sin⁡2(θj/2)hj2. The exact finite-grid strict condition is Δt2max⁡θλ(θ)<4, as in Strict spectral CFL positivity and Yee modified energy. The rectangular sufficient bound is Δt<1chx−2+hy−2+hz−2; it is exact when every Nj is even. For a cubic grid this bound is Δt<h/(c3). Odd cell counts may have a smaller finite-grid maximum, so the finite-grid eigenvalue is the exact criterion.

Facts & Assumptions

Given: A homogeneous isotropic periodic Cartesian Yee grid and a lossless, source-free leapfrog update.

[F1]

Edge cochains are oriented line integrals, face cochains are oriented fluxes, and the homogeneous Cartesian Hodge weights are the stated diagonal dual-volume weights. (Oriented Maxwell cochains, masses, and the Yee grid)

[F2]

The positive-energy criterion is the strict generalized spectral condition Δt2λmax⁡<4. (Strict spectral CFL positivity and Yee modified energy)

[F3]

The Yee rows use the half-step magnetic update and integer-step electric update. (Lossless or midpoint-conductive Yee leapfrog update)

Proof

1.1F1algebra

On a periodic Fourier mode, a forward edge difference in direction j has multiplier eiθj−1=2ieiθj/2sin⁡(θj/2). The half-cell phase in the edge and face cochain locations is removed by a unitary diagonal change of Fourier basis, so the scaled directional symbol is idj with dj=2sin⁡(θj/2)/hj. The Cartesian curl symbol is therefore id×.

2.1F1step 1.1algebra

The cross-product matrix d× is real skew-symmetric. The identity −(d×)2=∣d∣2I−ddT follows by expanding the vector triple product. Thus the curl-curl symbol is zero on the longitudinal vector d and equals ∣d∣2 on its two-dimensional orthogonal complement. The Hodge weights in [F1] scale this eigenvalue by c2, giving the stated λ(θ).

3.1F3step 2.1algebra

For a transverse mode en=qnv with this eigenvalue, subtracting the electric row in [F3] at consecutive time indices and using its magnetic row gives qn+1−2qn+qn−1+Δt2λ(θ)qn=0. Substitution of qn=e−iωnΔt yields 4sin⁡2(ωΔt/2)=Δt2λ(θ), which is the displayed dispersion relation.

4.1F1F2step 3.1algebra∎

Since 0≤sin⁡2(θj/2)≤1, λ(θ)≤4c2(hx−2+hy−2+hz−2). When every Nj is even, the allowed tuple θ=(π,π,π) attains equality; otherwise the exact maximum is the maximum over the finite allowed tuples. Applying [F2] gives the rectangular strict bound and its cubic specialization, while preserving the finite-grid endpoint distinction.

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Finite-time Yee error for smooth homogeneous periodic Maxwell fields

Statement

Assume the hypotheses and residual bounds of Second-order consistency of the homogeneous periodic Yee scheme on [0,T]. Write δttun=(un+1−2un+un−1)/Δt2. Let ehn,bhn+1/2 be a lossless, source-free periodic Yee solution, with S=0 and jn+1/2=0 at every step, and let e∗n,b∗n+1/2 be the exact samples. Set wn=ehn−e∗n and zn+1/2=bhn+1/2−b∗n+1/2. Suppose the initial electric rows are compatible with the Yee equations and satisfy ∥w0∥Me+∥Cw0∥Mb+∥w1∥Me+∥Cw1∥Mb+∥w1−w0Δt∥Me+∥z1/2∥Mb≤C0(h2+Δt2). Let λmax⁡ be the largest generalized curl-curl eigenvalue in Strict spectral CFL positivity and Yee modified energy. If the strict spectral margin obeys γ:=1−Δt2λmax⁡/4≥γ0>0, then for every integer n≥0 with tn+1≤T, ∥ehn−e∗n∥Me+∥bhn+1/2−b∗n+1/2∥Mb+∥C(ehn−e∗n)∥Mb≤C(h2+Δt2), where C is independent of the grid counts and time step. The statement is for the smooth homogeneous periodic branch and compatible starts; it makes no Taylor error claim across material jumps or an unspecified PEC boundary stencil.

Facts & Assumptions

Given: A homogeneous periodic grid, exact smooth source-free Maxwell samples, the lossless source-free Yee rows, a strict CFL margin, and the stated initial-error bound.

[F1]

With S=0 and jn+1/2=0 at every step, eliminating the magnetic half-step from the Yee rows gives the electric recurrence Meδtten+CTMbCen=0 and the Faraday half-step row. (Lossless or midpoint-conductive Yee leapfrog update)

[F2]

The generalized Rayleigh maximum λmax⁡ gives ∥Cv∥Mb2≤λmax⁡∥v∥Me2 for every electric cochain v. The strict spectral margin is 1−Δt2λmax⁡/4. (Strict spectral CFL positivity and Yee modified energy)

[F3]

Exact samples satisfy ∥rhn∥Me−1≤CT(h2+Δt2) and the unscaled Faraday-row residual satisfies ∥shn∥Mb≤CTΔt3. (Second-order consistency of the homogeneous periodic Yee scheme)

[F4]

Me is positive definite, and ∥r∥Me−12=rTMe−1r is the dual norm to ∥⋅∥Me. (Oriented Maxwell cochains, masses, and the Yee grid)

Proof

1.1F1F3algebra

Subtract the exact-sample equations with residuals from the numerical rows. With K=CTMbC, this gives Meδttwn+Kwn=−rhn,zn+1/2−zn−1/2=−Δt Cwn−shn. The sign convention for shn is the one in the consistency statement.

1.2F2givenalgebra

Put Vn=(wn+1−wn)/Δt, wˉn=(wn+1+wn)/2, and En+1/2=12∥Vn∥Me2+12⟨Cwn+1,Cwn⟩Mb. Expanding about Cwˉn gives En+1/2=12∥Vn∥Me2+12∥Cwˉn∥Mb2−Δt28∥CVn∥Mb2. The generalized Rayleigh bound in [F2] yields En+1/2≥γ02∥Vn∥Me2+12∥Cwˉn∥Mb2. The initial assumptions therefore give E1/2≥0 and E1/2≤C(h2+Δt2).

2.1F4step 1.1algebra

The kinetic-energy increment is Δt⟨(Vn+Vn−1)/2,Meδttwn⟩, and the curl-potential increment is Δt⟨(Vn+Vn−1)/2,Kwn⟩. Substituting step 1.1 gives En+1/2−En−1/2=−Δt⟨Vn+Vn−12,rhn⟩. By [F4] and Cauchy–Schwarz, the absolute value is at most Δt∥rhn∥Me−1(∥Vn∥Me+∥Vn−1∥Me)/2.

3.1F2F3step 1.2step 2.1algebra

Coercivity in step 1.2 bounds both velocities by the square roots of their adjacent energies times 2/γ0. Factoring the difference of squares and summing (with the zero-energy case obtained by continuity, or by first replacing each square root by E+δ and letting δ↓0) gives max⁡n(∥Vn∥Me+∥Cwˉn∥Mb)≤C(E1/2+∑nΔt∥rhn∥Me−1)≤CT(h2+Δt2). The sum has at most T/Δt terms, so [F3] gives the final inequality.

4.1F2givenstep 1.2step 3.1algebra

Since wn=w0+Δt∑m<nVm, the initial bound and step 3.1 imply max⁡n∥wn∥Me≤CT(h2+Δt2). For n≥1, Cwn=Cwˉn−1+ΔtCVn−1/2 and Δt∥CVn−1∥Mb≤Δtλmax⁡∥Vn−1∥Me≤2∥Vn−1∥Me by the strict CFL condition. Thus the same order holds for ∥Cwn∥Mb for n≥1; the n=0 curl bound is part of the initial assumptions.

5.1F3givenstep 1.1step 4.1algebra∎

Summing the second equation in step 1.1 from the controlled start z1/2 gives ∥zn+1/2∥Mb≤∥z1/2∥Mb+Δt∑m=1n∥Cwm∥Mb+∑m=1n∥shm∥Mb. The curl sum is bounded by Tmax⁡m∥Cwm∥Mb, and the residual sum is at most (T/Δt)CTΔt3=CTTΔt2 by [F3]. The initial bound and step 4.1 therefore bound both terms by CT(h2+Δt2). Combining the electric, curl and magnetic bounds proves the claim.

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Midpoint conductivity dissipates the Yee discrete energy

Statement

For the midpoint-conductive update of Lossless or midpoint-conductive Yee leapfrog update, define the same staggered cross-energy as in Strict spectral CFL positivity and Yee modified energy. Then for every step En+1−En=−Δt(en+1+en2)Tjn+1/2−Δt(en+1+en2)TS(en+1+en2). With zero impressed current, this algebraic energy is nonincreasing because S⪰0. Under the strict spectral CFL hypothesis of Strict spectral CFL positivity and Yee modified energy it is also positive on admissible update states. Dissipation is asserted for this specified midpoint treatment, not for an arbitrary conductivity discretization.

Facts & Assumptions

Given: Δt>0, symmetric positive definite Me,Mb, symmetric positive semidefinite S, the midpoint conductivity row, and the stated cross-energy.

[F1]

The electric row contains S(en+1+en)/2 and the magnetic row is Faraday leapfrog. (Lossless or midpoint-conductive Yee leapfrog update)

[F2]
[F3]

Under the strict spectral CFL bound the cross-energy is positive on admissible states. (Strict spectral CFL positivity and Yee modified energy)

Proof

1.1F1algebra

Put eˉn=(en+1+en)/2. The electric quadratic-energy increment is 12∥en+1∥Me2−12∥en∥Me2=(eˉn)TMe(en+1−en). By [F1], this is Δt(eˉn)TCTMbbn+1/2−Δt(eˉn)Tjn+1/2−Δt(eˉn)TSeˉn.

2.1F1step 1.1algebra

The magnetic cross-energy increment is 12(bn+1/2)TMb(bn+3/2−bn−1/2). Applying the magnetic row in [F1] at n and n+1 gives bn+3/2−bn−1/2=−ΔtC(en+1+en)=−2ΔtCeˉn. Therefore the magnetic increment is −Δt(eˉn)TCTMbbn+1/2 and cancels the electric curl work in step 1.1. The remaining terms are exactly the claimed balance.

3.1F2F3step 2.1algebra∎

If jn+1/2=0, the balance and [F2] imply En+1≤En. When the strict CFL condition also holds, [F3] shows these nonnegative values control the admissible electric and centered magnetic state.

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Compatible magnetic initial projection for the Maxwell edge method

Statement

Assume the contractible Lipschitz domain and shape-regular mesh-family hypotheses of Uniformly bounded commuting projection for lowest-order Nedelec spaces, with matching affine tetrahedra and the PEC edge space of Edge-face Maxwell finite element semidiscretization. Assume Countable Choice as in that projection interface. Let B0∈H(div⁡;Ω) be piecewise smooth, have matching normal traces, and satisfy div⁡B0=0. For the approximation bound below, assume all material and field smoothness interfaces are mesh-aligned, with B0 and div⁡B0 piecewise C1 on cell closures and bounded cellwise first derivatives as in Smooth lowest-order Nedelec and RT0 interpolation estimate. Let πh2 be the degree-two cochain projection in that interface, let Xh=range⁡C⊂Nh2, and let PXh be orthogonal projection onto Xh for (u,v)μ−1=∫ΩuTμ−1v dx. Define Bh0=πh2B0+PXh(B0−πh2B0). Then Bh0∈Nh2, DBh0=0, and (Bh0−B0,curl⁡vh)μ−1=0(vh∈Vh),∥Bh0−B0∥μ−1≤Ch MB, where Vh=Nh1∩H0(curl⁡;Ω) and MB is the maximum of the piecewise first-derivative bounds for B0 and div⁡B0 used by the smooth interpolation estimate. The error constant is uniform over the shape-regular family when the commuting projection norms are uniformly bounded.

Facts & Assumptions

Given: The finite element spaces, curl matrix C, divergence matrix D, positive magnetic inner product, and the declared Countable Choice branch.

[A1]

Countable Choice is the only choice axiom required by the current bounded commuting projection interface; this proof makes no stronger choice assumption. (The Axiom of Countable Choice (ACω))

[F1]

The degree-two and degree-three operators πh2,πh3 are projections onto Nh2,Nh3, are uniformly bounded on their de Rham graph spaces, and satisfy div⁡πh2=πh3div⁡. (Uniformly bounded commuting projection for lowest-order Nedelec spaces)

[F2]

The oriented moment matrices represent curl⁡:Vh→Nh2 and div⁡:Nh2→Nh3, with DC=0. (Edge-face Maxwell finite element semidiscretization, Whitney edge, face, and cell moments commute with grad, curl, and div)

[F3]

Under the stated mesh alignment and cellwise C1 bounds, for B0 with matching normal traces, the canonical face interpolant Ih2B0 lies in Nh2 and has ∥B0−Ih2B0∥H(div⁡)≤ChMB. (Smooth lowest-order Nedelec and RT0 interpolation estimate)

Proof

1.1A1givenconstructalgebra

The subspace Xh is finite dimensional. In a basis of Xh, its μ−1 Gram matrix is symmetric positive definite, so the normal equations have one solution for each B0−πh2B0; this defines PXh. Its value lies in Xh⊂Nh2, and the definition of orthogonal projection gives Bh0−B0=−(I−PXh)(B0−πh2B0)⊥μ−1Xh. Orthogonal decomposition yields ∥Bh0−B0∥μ−1≤∥B0−πh2B0∥μ−1.

2.1F1F3step 1.1algebra

Since Ih2B0∈Nh2 and πh2 is a projection, πh2Ih2B0=Ih2B0. Thus B0−πh2B0=(I−πh2)(B0−Ih2B0). Uniform boundedness of πh2 on H(div⁡), norm equivalence from the coefficient bounds, and [F3] imply ∥B0−πh2B0∥μ−1≤ChMB. Combining with step 1.1 gives the asserted approximation estimate.

3.1F1F2givenstep 1.1algebra∎

The projection identity and [F1] give Dπh2B0=πh3(div⁡B0)=0. Every element of Xh is a discrete curl, so [F2] gives DPXh(B0−πh2B0)=0. Adding the two terms proves DBh0=0.

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Smooth PEC edge finite element Maxwell error from compatible projections

Statement

Fix T≥0. Let Ω be a bounded contractible Lipschitz polyhedron with a shape-regular family of matching affine tetrahedral meshes, maximum diameter h→0, and mesh-aligned material interfaces. Let ϵ,μ be time-independent symmetric uniformly positive definite bounded coefficients. In the lossless branch σ=0, let (E,B) be a PEC solution of Transient Maxwell system with piecewise materials and boundary conditions with Jsrc∈C1([0,T];L2(Ω)3), satisfying the stated current continuity and magnetic divergence constraints. Assume E,Et,Ett are piecewise C1 in space, their curls are piecewise C1, and their tangential traces match across interior mesh faces and vanish on the exterior PEC boundary; assume B(0) is piecewise C1 with matching normal traces and div⁡B(0)=0. These bounds are uniform in time on [0,T].

Take the semidiscrete solution of Edge-face Maxwell finite element semidiscretization with exact load moments, initialize Eh(0)=RhE(0) using the Maxwell Ritz map of Maxwell curl-energy Ritz projection, and initialize Bh(0)=Bh0 by Compatible magnetic initial projection for the Maxwell edge method. Write θh(t)=Eh(t)−RhE(t). The Countable Choice assumption required by that projection interface is in force. Then the semidiscrete solution exists uniquely (at T=0, as the initialized singleton map with the unique constant-load local continuation, without a derivative assertion on the singleton) and sup⁡0≤t≤T(∥Eh(t)−E(t)∥L2(Ω)+∥curl⁡(Eh(t)−E(t))∥L2(Ω)+∥Bh(t)−B(t)∥L2(Ω))≤CTh. The constant depends on T, the coefficient bounds, the shape-regularity and projection bounds, and the stated piecewise smooth norms, but not on h. The initial magnetic projection preserves the discrete divergence constraint, and its error Bh0−B(0) is μ−1-orthogonal to all discrete curls. The result is a PEC semidiscrete estimate for smooth mesh-aligned data; it does not claim a rate across unresolved jumps or for nonsmooth fields.

Facts & Assumptions

Given: A shape-regular PEC tetrahedral family, time-independent uniformly positive coefficients, a smooth compatible Maxwell solution and source, the edge-face semidiscrete equations, and the stated initial projections.

[A1]

Countable Choice is the only choice axiom required by the bounded commuting projection interface; the proof makes no stronger choice assumption. (The Axiom of Countable Choice (ACω))

[F1]

For T>0, the finite-dimensional source-driven Maxwell ODE has a unique global C1 solution for continuous load moments. For T=0, it has a unique initialized singleton map with a unique local continuation when the load is held constant. (Existence and uniqueness for the finite-dimensional Maxwell ODE)

[F2]

The exact weak PEC equations are m(Et,v)−(μ−1B,curl⁡v)=−(Jsrc,v) and Bt+curl⁡E=0; the semidiscrete equations are their edge-face Galerkin rows. (Transient Maxwell system with piecewise materials and boundary conditions, Edge-face Maxwell finite element semidiscretization)

[F3]

The time-independent symmetric form a+(u,v)=m(u,v)+a(u,v) defines Rh; it is orthogonal and best approximating in its graph norm. (Maxwell curl-energy Ritz projection, Well-definedness and best approximation of the Maxwell Ritz map)

[F4]

For the stated piecewise smooth fields, the canonical lowest-order edge interpolant gives a uniform O(h) approximation in the L2 and curl norms. (Smooth lowest-order Nedelec and RT0 interpolation estimate)

[F5]

The initial magnetic field Bh0 has div⁡Bh0=0, is μ−1-orthogonal to every discrete curl after subtracting B(0), and satisfies ∥Bh0−B(0)∥μ−1≤Ch. (Compatible magnetic initial projection for the Maxwell edge method)

[F6]

The electric and magnetic weighted L2 norms are equivalent to ordinary L2 under the uniform coefficient bounds. (Transient Maxwell system with piecewise materials and boundary conditions)

[F7]

The relative degree-one Whitney space with zero boundary edge moments is exactly Nh1∩H0(curl⁡;Ω), and boundary tangential polynomial traces are determined by the boundary edge moments. (Averaged pullback Whitney moments and uniform near identity, Whitney edge, face, and cell moments commute with grad, curl, and div)

[F8]

Compactly supported smooth vector tests are dense in real L2; dominated convergence passes uniformly dominated difference quotients under scalar integrals. A real or finite-dimensional differentiable function with bounded derivative is Lipschitz, by the mean-value bound. (Smooth compactly supported functions of an open set are dense in L2, Dominated convergence, If f:[a,b]→Rm is differentiable with integrable f′ then ∫abf′=f(b)−f(a); and a bounded derivative makes f Lipschitz)

[F9]

H0(curl⁡;Ω) is a closed subspace of H(curl⁡;Ω), by its definition as a graph-norm closure. (Zero tangential trace H(curl) space)

Proof

1.1A1F1F3F4F5F6F7F8F9givenalgebra

If T=0, [F1] supplies the unique initialized map; Ritz best approximation [F3] and interpolation [F4] give the electric and curl error at zero, and [F5] gives the magnetic error and divergence compatibility. Norm equivalence [F6] proves the stated estimate on the singleton. Hence assume T>0. We first justify the closure and time derivatives; Et,Ett denote the classical time derivatives. For each u=E(t),Et(t),Ett(t), zero boundary tangential trace makes the boundary edge moments of Ih1u zero, so [F7] gives Ih1u∈Vh. By [F4], Ih1u→u in H(curl⁡) as h→0, and [F9] gives u∈H0(curl⁡). Uniform bounds on Ett give L2-Lipschitz continuity of Et by the pointwise mean-value bound [F8]. For a compact smooth vector test ψ, dominated differentiation gives ddt(curl⁡Et,ψ)=ddt(Et,curl⁡ψ)=(Ett,curl⁡ψ)=(curl⁡Ett,ψ). The uniform bound on curl⁡Ett and [F8], followed by L2 density, therefore give ∥curl⁡Et(t)−curl⁡Et(s)∥2≤K∣t−s∣. The same test identities for E show E is graph-norm C1 with derivative Et: subtract the value of Et(s) from its difference quotient and use the just-proved Lipschitz bound, first in test pairings and then by density. Difference quotients of Et are uniformly graph bounded; their L2 parts converge to Ett by dominated convergence, and their curls converge distributionally to curl⁡Ett. Density and uniform boundedness upgrade the latter to weak L2 convergence. Consequently every bounded graph-linear functional of Et is differentiable with derivative its value on Ett. In particular the finite Ritz Gram equations give (RhE)t=RhEt and (RhE)tt=RhEtt, with a bounded second derivative; continuity of Ett in the graph norm is unnecessary.

1.2A1F2F3F4F5F7givenalgebra

The initialization gives θh(0)=0. Test the semidiscrete Ampere row at t=0 and subtract the exact weak row. By the curl orthogonality in [F5], (μ−1(Bh0−B(0)),curl⁡vh)=0 for every vh, so E˙h(0) is the ϵ-orthogonal projection of Et(0) onto Vh. The zero tangential boundary trace gives zero boundary edge moments for Ih1Et(0); [F7] therefore places this interpolant in Vh. Its best-approximation error is at most ∥Et(0)−Ih1Et(0)∥ϵ≤Ch by [F4]. Also ∥RhEt(0)−Et(0)∥ϵ≤Ch by [F3,F4]. Hence ∥θ˙h(0)∥ϵ≤Ch.

2.1F1F2step 1.1givenalgebra

Differentiate the exact weak Ampere equation in [F2] and use Bt=−curl⁡E. Since μ is time-independent, this gives, for every v∈H0(curl⁡;Ω), (ϵEtt,v)+(μ−1curl⁡E,curl⁡v)=−(∂tJsrc,v). Differentiating the finite-dimensional Ampere row and using b˙+Ce=0 gives the identical Galerkin equation for Eh: (ϵE¨h,vh)+(μ−1curl⁡Eh,curl⁡vh)=−(∂tJsrc,vh). The solution exists by [F1]; the exact time pairings are differentiable by step 1.1, and the discrete differentiation is valid because Jsrc is C1.

3.1F3F4F7step 1.1step 2.1algebra

Let Rh be fixed in time and put θh=Eh−RhE. Step 1.1 justifies (RhE)tt=RhEtt for its time-independent Gram matrix. Subtract the two equations in step 2.1 and use Ritz orthogonality [F3], namely a(E−RhE,vh)=−m(E−RhE,vh). For every vh∈Vh this yields m(θ¨h,vh)+a(θh,vh)=m((I−Rh)(Ett−E),vh). The zero tangential boundary trace gives zero boundary edge moments for Ih1(Ett−E), so [F7] places this interpolant in Vh. Best approximation [F3] and the canonical estimate [F4] then show uniformly in time that ∥(I−Rh)(Ett−E)∥ϵ≤Ch.

4.1F4F8step 1.1step 3.1step 1.2algebra

Define Qh(t)=12(∥θ˙h(t)∥ϵ2+∥curl⁡θh(t)∥μ−12). Test the equation in step 3.1 with vh=θ˙h. Symmetry gives Qh′(t)=m((I−Rh)(Ett−E),θ˙h),∣Qh′(t)∣≤∥(I−Rh)(Ett−E)∥ϵ2Qh(t). For δ>0, the derivative of Qh+δ has absolute value at most Ch/2 by step 3.1. The scalar mean-value bound [F8], the initial estimate in step 1.2 and then δ↓0 give Qh(t)≤Ch on [0,T]. The finite-dimensional mean-value bound and θh(0)=0 also give sup⁡t∥θh(t)∥ϵ≤Tsup⁡t∥θ˙h(t)∥ϵ≤Ch.

5.1F3F4step 4.1algebra

By step 4.1, θh is O(h) in the electric L2 norm and its curl norm. The Ritz best-approximation estimate [F3] and interpolation estimate [F4] give ∥RhE−E∥L2+∥curl⁡(RhE−E)∥L2≤Ch. The triangle inequality therefore gives the asserted electric and curl error bound.

6.1F2F5F6step 5.1algebra∎

Subtract the exact Faraday equation from the semidiscrete magnetic row and integrate in time: Bh(t)−B(t)=Bh0−B(0)−∫0tcurl⁡(Eh(s)−E(s)) ds. The initial difference is O(h) by [F5], and the curl error is O(h) uniformly by step 5.1, so the magnetic L2 error is at most Ch+TCh. Also DBh(t)=DBh0−∫0tDCeh(s) ds=0 by [F5] and the discrete identity DC=0 in [F2]. Norm equivalence [F6] completes the result.

5 · Examples, counterexamples and false statements

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