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Power-normalized scattering and passivity

1 · Prerequisites

2 · Summary

3 · Logical flowchart

4 · Definitions, postulates, theorems and proofs

DefinitionDefinition: AI-adaptedProof: Not applicableverified 2026-10-22 (gpt-6.1-sol)Open item page →

Finite propagating-port scattering map

Physical scope

A conditional finite-channel interface for linear, fixed-frequency Maxwell scattering in one stationary material-rest frame. It assumes the listed propagating channels, their flux and reciprocal pairings, and a unique solution map at the chosen real frequency. Evanescent fields may be needed in the exact boundary matching. The definition proves no existence, uniqueness, completeness or empirical realization claim, and an omitted outgoing continuum must be separately counted.

Definition

Fix a real angular frequency ω>0 in s−1 and use the e−iωt convention and SI field units of the fixed-frequency reciprocal-phasor model. Let Ω⊂R3 be a bounded device region with C1 boundary in one stationary material-rest frame. Its continuous phasor coefficient maps are ε,μ:Ω‾→C3×3 in F m−1 and H m−1, respectively. The complex phasor fields E~,H~∈C1(Ω‾;C3) have units V m−1 and A m−1. They satisfy the fixed-frequency Maxwell equations of the reciprocal-phasor data class, with no impressed volume current or charge in Ω. The corresponding real fields are E(x,t)=Re⁡(E~(x)e−iωt) and H(x,t)=Re⁡(H~(x)e−iωt), with period T=2π/ω. Assume ACω as defined by the countable-choice axiom when the reciprocal boundary identity below is used.

An admissible port consists of a bounded connected C1 cross-section Σj in a plane perpendicular to a fixed unit guide axis z^j, together with a uniform lossless straight reference guide extending from that section. The outward normal nj on the port points from Ω into the guide. The reference-guide phasor coefficients and wall conditions are independent of distance along z^j. A propagating channel mode is a pair of C1 complex transverse profiles (ejα,hjα) whose associated source-free phasor fields in the guide solve the fixed-frequency Maxwell equations and have longitudinal factor e±iβαsj with real βα>0 in m−1. The profiles are normalized per unit amplitude in W1/2, so the resulting fields have units V m−1 and A m−1. The plus and minus signs are assigned according to whether energy travels toward or away from Ω. At ω, assume a finite list of N propagating mode channels in total and that this list is complete for the propagating channels represented by the finite interface. Any outgoing radiation continuum or omitted propagating channel is separately recorded as nonnegative outward power Pother. Evanescent modes may be required in the exact near-port matching field, but are not entries of the propagating amplitude vectors; no finite truncation of such matching modes is asserted to be exact.

Let a=(a1,…,aN)T∈CN and b=(b1,…,bN)T∈CN be the incoming and outgoing amplitudes. Choose the mode shapes and amplitude convention so that each coefficient has units W1/2, the Hermitian norm is ∥a∥22=∑α=1N∣aα∣2 in W, and the total time-averaged outward power through the port sections is

Pports=∥b∥22−∥a∥22.

This equality, including the vanishing of cross terms in the real-power pairing, is a port-mode normalization hypothesis. For complex phasor fields the time-averaged Poynting vector is Π=12Re⁡(E~×H~∗) in W m−2, where ∗ denotes componentwise conjugation before the bilinear cross product. This Hermitian power pairing is distinct from the unconjugated Lorentz bilinear pairing.

On the non-port wall Γw, the model prescribes either a smooth PEC condition Eτ(t)=0, giving zero outward wall power, or a passive wall condition with explicitly specified nonnegative cycle-averaged outward power P∂≥0. Here Eτ(t)=E(t)−(n⋅E(t))n and Hτ(t)=H(t)−(n⋅H(t))n are the classical tangential restrictions of the smooth real fields. A smooth impedance wall is one such condition: for a real scalar surface admittance Y≥0 in siemens and Hτ(t)=Y(n×Eτ(t)), its instantaneous outward power density is n⋅(Eτ(t)×Hτ(t))=Y∣Eτ(t)∣2≥0, so its cycle-averaged outward power is nonnegative. For phasor amplitude E~τ, that average is 12Y∣E~τ∣2. This is a smooth-field model assumption; no L2 trace is inferred from membership in H(curl⁡).

The total cycle-averaged outward boundary power is the port contribution ∥b∥22−∥a∥22, plus P∂ and any unlisted outgoing power Pother. No unlisted incoming power is included.

For each a, assume the adopted linear source-free Maxwell boundary problem has a unique time-harmonic solution and a unique outgoing vector b. The model assumes no incoming wave in unlisted channels. By linearity of the phasor equations and uniqueness, the map a↦b is complex-linear: a linear combination of two solutions solves the problem for the same linear combination of their incoming data, and uniqueness identifies its outgoing data. The finite scattering matrix is the unique matrix S(ω)∈CN×N such that b=S(ω)a. The definition assumes this well-posed solution map; it does not prove its existence, uniqueness, modal completeness, or absence of resonances.

For reciprocal use, the incoming and outgoing modal phases are additionally chosen so that for every pair of source-free solutions with incoming vectors a1,a2 and outgoing vectors b1,b2, the Lorentz boundary pairing reduces to

∫∂Ωn⋅(E~1×H~2−E~2×H~1) dS=a1Tb2−b1Ta2.

This is an explicit reciprocal-normalization condition, using the complex-bilinear products of the reciprocal-phasor model and the bounded-C1 reciprocity identity of the Lorentz reciprocity theorem. Power normalization alone does not imply this bilinear pairing for arbitrary complex reference impedances. Rephasing a port is allowed only when the declared reciprocal pairing is preserved.

Port orientation

The arrows show the sign convention for two ports: incoming amplitudes point toward the device and outgoing amplitudes point away. The drawing records orientation only; the flux identities in the definition, not the drawing, determine the proofs.

device¬a1b1a2b2§1§2

Remarks

The rectangular-guide suppliers on the prerequisite page provide mode-profile results only under their stated rectangular, lossless hypotheses; their completeness theorem expressly does not prove an open-end scattering map. The finite channel basis and the unique scattering solution above therefore remain explicit interface assumptions. For an open radiating device, radiation power must be included in Pother; finite-channel unitarity is not concluded while that term is omitted.

Physics theoremStatement: AI-adaptedProof: AI-adaptedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Passivity gives a contractive scattering matrix

Physical scope

A conditional classical Maxwell scattering deduction at one real frequency for the finite port model of emx-port-scattering-channels. The material branches are exactly the homogeneous finite Lorentz oscillator or Drude current closures stated here; fields are smooth and periodic, free-current work is zero, wall power is nonnegative, and all unlisted outgoing power is counted. It is not an existence theorem, does not cover arbitrary passive constitutive laws, and makes no empirical claim.

Statement

Assume ACω. Fix the finite port model at a real angular frequency ω>0 and period T=2π/ω, with bounded C1 device region Ω and scattering matrix S(ω). For every incoming amplitude a∈CN, let E~a,H~a∈C1(Ω‾;C3) be that model's unique phasor solution with outgoing amplitude b=S(ω)a, and set E(x,t)=Re⁡(E~a(x)e−iωt) and H(x,t)=Re⁡(H~a(x)e−iωt). Assume for every such input that these real fields, D,B:Ω‾×R→R3, and the material states are jointly C∞ and T-periodic, satisfy the smooth source-free macroscopic Maxwell equations with ρf=0 and Jf=0, and obey the same one of the following two homogeneous material branches with coefficients independent of the input. The units of E,H,D,B are respectively V m−1, A m−1, C m−2, and T.

For real vectors v,w∈R3, the Euclidean product is v⋅w:=∑r=13vrwr and ∣v∣2:=v⋅v.

The port model uses incoming and outgoing vectors a,b∈CN with amplitude units W1/2; for either vector z, ∥z∥22:=∑α=1N∣zα∣2 is its power in W, and the net outward port power is ∥b∥22−∥a∥22.

Finite Lorentz branch. For a finite M≥1, each Pℓ:Ω‾×R→R3 has units C m−2, D=ε∞E+∑ℓ=1MPℓ, B=μH, and ∂t2Pℓ+γℓ∂tPℓ+ωℓ2Pℓ=aℓE, where ε∞,μ,aℓ,ωℓ>0 and γℓ≥0.

Drude branch. P,V:Ω‾×R→R3 have units C m−2 and A m−2, respectively; D=ε∞E+P, B=μH, ∂tP=V, and ∂tV+γV=aE, where ε∞,μ,a>0 and γ≥0.

The constants have the SI units of the respective adopted closure: ε∞ in F m−1, μ in H m−1, each aℓ or a in F m−1 s−2, and each ωℓ or damping rate in s−1. In the Lorentz branch define the loss-density map ℓ:Ω‾×R→[0,∞) by ℓ=∑ℓ=1M(γℓ/aℓ)∣∂tPℓ∣2; in the Drude branch define it by ℓ=(γ/a)∣V∣2. These have units W m−3. For the solution with the fixed input a, set Pmat(a):=T−1∫0T∫Ωℓ dV dt. Let P∂(a)≥0 be its cycle-averaged outward power at passive physical walls, and let Pother(a)≥0 be all its outgoing radiation or propagating-channel power not represented in b, as defined by the port model. For brevity, in the proof write these three quantities as Pmat, P∂, and Pother. Then

∥a∥22−∥S(ω)a∥22=Pmat(a)+P∂(a)+Pother(a)≥0.

For complex vectors and matrices, an overline denotes componentwise complex conjugation and a superscript T denotes ordinary transpose; set z†:=z‾ T for z∈CN and A†:=A‾ T for A∈CN×N. A matrix is Hermitian when A†=A, and is unitary when A†A=AA†=IN, where IN is the identity matrix on CN.

Consequently S(ω) is contractive: ∥Sa∥2≤∥a∥2 for every a. If Pmat(a)=P∂(a)=Pother(a)=0 for every incoming vector a, then S†S=IN; because the defined map is square, S is unitary. The exact equality and unitarity are conditional deductions of this model, not existence claims about arbitrary scatterers.

Statement references

Facts & Assumptions

Given: ACω; one fixed ω>0 and T=2π/ω; for every input, the real E,H obtained from that finite scattering model's phasor solution; the same stated homogeneous material branch with its positive parameters and nonnegative damping; smooth periodic real fields and material states for every input; zero free current; and nonnegative passive-wall and unlisted-outgoing powers. Fix an arbitrary input a for the calculation below.

[A1]

The Lorentz postulate has constant ε∞,μ,aℓ,ωℓ,γℓ, D=ε∞E+∑Pℓ, and the displayed second-order oscillator equations. Finite Lorentz oscillator closure

[A2]

The Drude postulate has constant ε∞,μ,a,γ, D=ε∞E+P, Pt=V, and Vt+γV=aE. Drude current closure and collisionless limit

[L1]

On the smooth Maxwell branch, curl⁡E=−∂tB and curl⁡H=Jf+∂tD. The macroscopic Maxwell equations in terms of D, H and the free sources

[F1]

For real C1 fields, div⁡(E×H)=H⋅curl⁡E−E⋅curl⁡H. The divergence and curl of a cross product

[F3]

On a bounded C1 device, the integral of the divergence of a real C1 vector field equals its outward boundary flux under ACω. Divergence on a bounded C1 Euclidean domain

[F4]

Fubini's theorem permits exchanging the order of integration for an integrable function on the finite-volume product Ω×[0,T]. Fubini's theorem for L^1 functions on a sigma-finite product

[F5]

The port model defines the outward port flux as ∥b∥22−∥a∥22 and the total outward boundary power as that port flux plus P∂+Pother; it assumes no unlisted incoming channel. Finite propagating-port scattering map

[A3]

Physical wall conditions are either smooth PEC, with zero outward flux, or passive conditions with cycle-averaged outward power P∂≥0. This is an explicit model premise, not a trace theorem. Finite propagating-port scattering map

Proof

technique · derive the local Poynting identity separately for the Lorentz and Drude closures, integrate it over the device and one period, then use the port flux identity and finite-dimensional matrix algebra
1.1givenA1A2L1algebra

In the Lorentz branch set Jtot=Jf+∑ℓ=1M∂tPℓ, and in the Drude branch set Jtot=Jf+V. From [L1] and [A1] or [A2], respectively, the field and constitutive equations give ε∞∂tE=curl⁡H−Jtot and μ∂tH=−curl⁡E.

1.2givenA1F2algebra

In the Lorentz branch, dot the ℓth oscillator equation [A1] with ∂tPℓ/aℓ. Since aℓ>0, the division is valid; the product rule in [F2] gives E⋅∂tPℓ=∂t ⁣((∣∂tPℓ∣2+ωℓ2∣Pℓ∣2)/(2aℓ))+(γℓ/aℓ)∣∂tPℓ∣2. The last term is nonnegative because γℓ≥0.

1.3givenA2F2algebra

In the Drude branch, dot ∂tV+γV=aE from [A2] with V/a. The product rule and a>0 give E⋅V=∂t(∣V∣2/(2a))+(γ/a)∣V∣2, whose last term is nonnegative because γ≥0.

2.1step 1.1F1F2algebra

Define the field energy density uf:Ω‾×R→[0,∞) by uf=(ε∞∣E∣2+μ∣H∣2)/2. Differentiate it componentwise using [F2] and the field equations of step 1.1. This gives ∂tuf=E⋅curl⁡H−E⋅Jtot−H⋅curl⁡E. Applying [F1] yields −div⁡(E×H)−E⋅Jf−∑E⋅∂tPℓ in the Lorentz branch and −div⁡(E×H)−E⋅Jf−E⋅V in the Drude branch.

3.1givenstep 1.2step 1.3step 2.1algebra

Define the total field-plus-material energy density u:Ω‾×R→[0,∞) branchwise: in the Lorentz branch, u:=uf+∑ℓ=1M(∣∂tPℓ∣2+ωℓ2∣Pℓ∣2)/(2aℓ); in the Drude branch, u:=uf+∣V∣2/(2a). All terms are nonnegative, have SI units J m−3, and are jointly smooth and T-periodic under the Statement's hypotheses. Substituting step 1.2 into the Lorentz field balance of step 2.1 cancels every E⋅∂tPℓ term; substituting step 1.3 into its Drude balance cancels E⋅V. Since the given source-free condition has Jf=0, each branch therefore satisfies ∂tu+div⁡(E×H)=−ℓ with exactly the loss density ℓ in the Statement.

4.1givenF3F4step 3.1algebra

Integrate the local identity of step 3.1 over Ω at each time and apply [F3] to E×H. Then integrate in time from 0 to T. The integrand ∂tu is continuous and integrable on the finite product domain, so [F4] permits integration first in time: ∫Ω∫0T∂tu dt dV=∫Ω(u(x,T)−u(x,0)) dV=0 by periodicity. Hence the time-integrated outward boundary flux equals −TPmat.

5.1givenA3F5step 4.1algebra

For the given phasor solution, expand each real part as (z+z‾)/2 in E×H. The terms proportional to e±2iωt have zero average over [0,T], leaving T−1∫0TE×H dt=12Re⁡(E~a×H~a‾). Thus the cycle average in step 4.1 is precisely the phasor power used by [F5]. Divide that step by T and use its total boundary-flux decomposition: the port term is ∥b∥22−∥a∥22, the wall term is P∂≥0 by [A3], and the remaining outgoing term is Pother≥0. Rearrangement gives the power balance for the arbitrary input a. The all-input hypotheses permit this calculation for every incoming vector of the same matrix S(ω).

6.1givenstep 5.1algebra∎

Since each of Pmat,P∂,Pother is nonnegative, step 5.1 gives ∥Sa∥22≤∥a∥22 for every a; taking nonnegative square roots proves contractivity. If all three powers vanish for every a, set K:=IN−S†S. Then K†=K because (S†S)†=S†S, and the power balance gives a†Ka=∥a∥22−∥Sa∥22=0 for every a. Let ej denote the jth coordinate vector of CN. Testing a=ej gives Kjj=0; for j<k, testing a=ej+ek gives 2Re⁡Kjk=0, while testing a=ej+iek gives −2Im⁡Kjk=0. Hence every entry of K is zero, so S†S=IN. The square matrix S is injective, hence surjective by finite-dimensional rank-nullity; therefore S−1=S† and SS†=IN as well. Thus S is unitary.

Physics theoremStatement: AI-adaptedProof: AI-adaptedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Reciprocal port normalization gives symmetric scattering

Physical scope

A conditional fixed-frequency consequence for the reciprocal phasor model on a bounded C1 device with the reciprocal port-pairing convention of emx-port-scattering-model. It uses ordinary transpose for reciprocity and a separate Hermitian power pairing for energy. The symmetric-unitary conclusion requires zero operational net cycle-averaged material transfer, passive-wall outward power, and unlisted outgoing power for every input of the same port map. Smooth periodic finite Lorentz and Drude branches with matching harmonic coefficients and zero branch losses remain explicit sufficient cases. It asserts no time-reversal theorem, local passivity for arbitrary coefficients, existence of a scattering solution, or empirical realization.

Statement

Assume ACω and the finite port model at a fixed real ω>0. Let S(ω)∈CN×N be its unique scattering matrix. Suppose the continuous device phasor coefficient maps ε,μ:Ω‾→C3×3 obey ε(x)T=ε(x) and μ(x)T=μ(x) pointwise, and for every pair of incoming vectors the corresponding source-free scattering solutions lie in C1(Ω‾;C3) and have reciprocal port modes satisfying the exact bilinear pairing stipulated in the model definition. Then

S(ω)T=S(ω).

For A∈CN×N, define its conjugate transpose by A†:=A‾ T, where the overline is componentwise conjugation and a superscript T is ordinary transpose; A is Hermitian when A†=A and unitary when A†A=AA†=IN, with IN the identity on CN. The transpose relation above uses the unconjugated Lorentz pairing; the unitary relation below uses the separate conjugated Hermitian power pairing. No time-reversal claim follows.

For each incoming vector a, define the operational net cycle-averaged material power transferred from the fields in this source-free phasor model by

Pbulk(a):=ω2∫ΩIm⁡(E~†εE~+H~†μH~) dV.

Here v†=v‾ T for a complex column vector, and this power has units W. It is a signed net transfer, not an assumption of local passivity or a definition of a material realization. Let P∂(a) and Pother(a) be the nonnegative outward wall and unlisted-channel powers of the same finite-port model, whose total outward boundary power is ∥Sa∥22−∥a∥22+P∂(a)+Pother(a). Then

∥a∥22−∥Sa∥22=Pbulk(a)+P∂(a)+Pother(a).

Consequently, if all three powers vanish for every incoming vector a∈CN, then S†S=SS†=IN, so S is symmetric and unitary. Pointwise Hermitian ε and μ suffice to make Pbulk(a)=0 for every input, since their quadratic forms are real; Hermitian symmetry is distinct from the ordinary transpose symmetry required for reciprocity. No constitutive branch beyond the stated phasor model is required for this operational zero-power conclusion.

The following full finite-port contraction hypotheses give additional Lorentz and Drude sufficient cases on this same port map. For every incoming vector, its real field maps E,H,D,B:Ω‾×R→R3 and its material-state maps on that domain are jointly C∞ and T-periodic, where T=2π/ω, and satisfy the smooth source-free macroscopic Maxwell equations with ρf=Jf=0.

The material closure is one of these two homogeneous, constant-coefficient branches. In the finite Lorentz branch, choose finite M≥1 and maps Pℓ:Ω‾×R→R3 for 1≤ℓ≤M. They satisfy

D=ε∞E+∑ℓ=1MPℓ,B=μH,∂t2Pℓ+γℓ∂tPℓ+ωℓ2Pℓ=aℓE,

with constant ε∞,μ,aℓ,ωℓ>0 and γℓ≥0. In the Drude branch, take maps P,V:Ω‾×R→R3. They satisfy

D=ε∞E+P,B=μH,∂tP=V,∂tV+γV=aE,

with constant ε∞,μ,a>0 and γ≥0. Their SI units are those specified in the finite-port contraction model.

For each input, require the real fields and material states to have only this frequency: let E~,H~,D~,B~:Ω‾→C3 be their phasor amplitudes with E(x,t)=Re⁡(E~(x)e−iωt), and analogously for H,D,B. In the Lorentz branch also write Pℓ(x,t)=Re⁡(P~ℓ(x)e−iωt) with P~ℓ:Ω‾→C3; in the Drude branch write P,V in the same form with amplitudes P~,V~:Ω‾→C3. Substitution into the closure equations gives

εL(ω)=(ε∞+∑ℓ=1Maℓωℓ2−ω2−iγℓω)I3,εD(ω)=(ε∞−aω2+iγω)I3,

where every Lorentz denominator is required nonzero, I3 is the 3×3 identity, and the magnetic coefficient is μI3 in either branch. Require these harmonic coefficient maps to be the continuous coefficients of this same reciprocal-phasor port model. The matrices are symmetric under ordinary transpose. The branch loss density is ℓ=∑j=1M(γj/aj)∣∂tPj∣2 in the Lorentz branch and ℓ=(γ/a)∣V∣2 in the Drude branch, using the real vector norm ∣v∣2=v⋅v. For the solution with incoming vector a, define Pmat(a):=T−1∫0T∫Ωℓ dV dt, and let P∂(a) and Pother(a) be its nonnegative passive-wall and unlisted-outgoing powers under the finite-port model's bookkeeping. The field, material-state, and parameter units are exactly those specified in that model.

In either harmonic branch, Pbulk(a)=Pmat(a). Thus Pmat(a)=P∂(a)=Pother(a)=0 for every incoming vector a is a sufficient case of the operational zero-power criterion, also supplied by the contraction result. These branch hypotheses are sufficient cases, not restrictions on the general phasor power identity above.

Facts & Assumptions

Given: ACω, a unique finite scattering matrix S, two source-free C1 phasor solutions in the same reciprocal device, and reciprocal incoming/outgoing mode phases satisfying the bilinear pairing in the definition.

[A1]

ACω is the countable-choice axiom required by the bounded-domain reciprocity supplier. The Axiom of Countable Choice (ACω)

[F1]

The reciprocal port convention is ∫∂Ωn⋅(E~1×H~2−E~2×H~1) dS=a1Tb2−b1Ta2; the products are complex-bilinear and contain no conjugation. Finite propagating-port scattering map

[L1]

For C1 phasor solutions on a bounded C1 domain, common continuous coefficients with ordinary transpose symmetry and ACω, the source-free Lorentz boundary pairing is zero. The identity does not assume Hermitian coefficients or losslessness. Reciprocity in reciprocal linear media

[L2]

Under the additional smooth T-periodic, source-free field assumptions, the finite homogeneous Lorentz or Drude closure equations, and the branchwise loss and port bookkeeping stated for the unitary conclusion above, the contraction theorem gives S†S=IN when Pmat(a)=P∂(a)=Pother(a)=0 for every input a. Passivity gives a contractive scattering matrix

[F2]

For real C1 vector fields F,G on an open subset of R3, div⁡(F×G)=G⋅curl⁡F−F⋅curl⁡G. The complex-bilinear version follows by expanding real and imaginary parts. The divergence and curl of a cross product

[F3]

Under ACω, on a bounded C1 domain Ω⊂R3, each real C1(Ω‾) vector field has finite volume-divergence and boundary-flux integrals, and these integrals agree. Divergence on a bounded C1 Euclidean domain

Proof

technique · apply the source-free Lorentz identity to two independently chosen incoming vectors, rewrite its boundary term with the reciprocal port pairing, and test the resulting bilinear matrix identity on coordinate vectors
1.1givenA1L1

Choose arbitrary a1,a2∈CN, and let (E~j,H~j) be their unique source-free scattering solutions. The coefficient transpose equalities and the hypotheses in [L1] imply ∫∂Ωn⋅(E~1×H~2−E~2×H~1) dS=0.

1.2givenA1F1F2F3algebra

For any input a, abbreviate its phasors by e=E~ and h=H~. The source-free equations are curl⁡e=iωμh and curl⁡h=−iωεe. Expanding [F2] into real and imaginary parts and then substituting these equations gives div⁡(e×h‾)=iω(h†μh−e†εe‾). Therefore the real C1 field Π=12Re⁡(e×h‾) satisfies div⁡Π=−ω2Im⁡(h†μh+e†εe). The bounded C1 domain and field regularity required by [F3] are precisely those in the port model. Its finite-integral conclusion applies to this identity and yields ∫∂Ωn⋅Π dS=−Pbulk(a). Substituting the model's outward-power convention proves ∥a∥22−∥Sa∥22=Pbulk(a)+P∂(a)+Pother(a), with no unlisted incoming term.

2.1givenF1step 1.1algebra

Substitute [F1] and bj=Saj into step 1.1. Since (Sa1)T=a1TST, the result is a1T(S−ST)a2=0 for every a1,a2∈CN.

3.1step 2.1algebra

For any coordinate vectors ej,ek, step 2.1 gives ejT(S−ST)ek=Sjk−Skj=0. This holds for every pair j,k, hence every entry of S−ST is zero and ST=S. No complex conjugation is introduced.

4.1givenstep 3.1step 1.2algebra

If these three powers vanish for every a, step 1.2 gives a†Qa=0 for every a, where Q=IN−S†S is Hermitian. Taking a=ej gives Qjj=0. For j≠k, taking a=ej+ek and a=ej+iek gives respectively 2Re⁡Qjk=0 and −2Im⁡Qjk=0, so Q=0. Thus S†S=IN. Its N columns are orthonormal and hence linearly independent; in the N-dimensional space they form a basis. For x=Sy this gives SS†x=SS†Sy=Sy=x, so also SS†=IN. Combining with step 3.1 proves the symmetric-unitary conclusion. For Hermitian coefficients, e†εe‾=e†ε†e=e†εe and likewise for h, so their imaginary parts and Pbulk vanish. No time-reversal conclusion is used.

5.1givenL2step 4.1algebra∎

In the stated Lorentz sufficient case, set dj=ωj2−ω2−iγjω≠0; the harmonic closure gives P~j=aje/dj. Hence Im⁡(e†εLe)=∑jajγjω∣e∣2/∣dj∣2, while the magnetic quadratic form is real. Direct averaging of the real sinusoid gives T−1∫0T∣∂tPj∣2dt=ω2∣P~j∣2/2. Thus its loss density average equals ω2Im⁡(e†εLe). For the Drude case, V~=ae/(γ−iω) gives T−1∫0T∣V∣2dt=a2∣e∣2/[2(γ2+ω2)], and Im⁡(e†εDe)=aγ∣e∣2/[ω(γ2+ω2)]. Multiplication by γ/a gives the same equality with ω/2 times this imaginary part. The formulas remain valid at zero damping, and the Lorentz nonzero-denominator condition is retained. Integrating in space proves Pmat=Pbulk in both branches. Their stipulated smooth periodic fields make these finite integrals legitimate, as also assured by their contraction power balance. Consequently their all-input zero-loss case satisfies step 4.1, consistently with [L2].

5 · Examples, experiments and counterexamples

None yet.

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