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Finite reversible stochastic rate model and thermal coupling

1 · Prerequisites

2 · Summary

This page defines a finite reversible continuous-time rate model and separately adopts two restricted thermal couplings: a one-dimensional inertial velocity Langevin bath and a finite-state bath with a specified symmetric field-dependent rate rule. The mathematical theorems derive the finite-chain construction, spectral gap, relative-information decay, time averages, rate response and OU displacement variance from their stated inputs.

Physical theorems on the page are conditional predictions of those adopted models. They preserve the SI dimensions and the finite-state or scalar-OU regime; they assert no measured rates, material calibration, experimental observation or universal transport law.

3 · Logical flowchart

4 · Definitions, postulates, theorems and proofs

DefinitionDefinition: Literature-sourcedProof: Not applicablejudge pass (gpt-6-luna)Open item page →

Finite reversible stochastic rate model

Definition

Assume the Axiom of Choice The Axiom of Choice. A finite reversible stochastic rate model consists of an integer r≥2, the finite state set E={1,…,r}, real energy parameters ea∈R, an inverse-energy parameter β>0, and finite transition rates wab≥0 for distinct a,b∈E. When physical units are assigned, ea is measured in joules, β in joules−1, and wab in seconds−1; this mathematical definition does not assert a physical realization. Define

Z:=∑a∈Ee−βea,πa:=Z−1e−βea.

Then Z is finite and positive, and π is a strictly positive probability vector. Require wab>0 exactly when wba>0, require the undirected graph with edge {a,b} whenever wab>0 to be connected, and impose detailed balance πawab=πbwba. Define the row generator Q by Qab=wab for a≠b and Qaa=−qa, where qa:=∑b≠awab. Since r≥2 and the graph is connected, every qa>0. Thus (Qf)a=∑b≠awab(fb−fa) for a column observable f, and a row probability vector evolves by p′=pQ.

For any observable f:E→R, write π(f):=∑a∈Eπafa. For f,g:E→R, define ⟨f,g⟩π:=∑a∈Eπafaga. Since E is finite and every πa>0, all real functions on E belong to this finite-dimensional real inner-product space, denoted L2(E,π); equality in it is pointwise equality.

The associated jump-chain construction waits an exponential time of rate qa in state a and then selects state b≠a with probability wab/qa, using fresh independent random choices at successive jumps. Here an exponential time of rate q>0 has survival probability Pr⁡(τ>t)=e−qt for t≥0. The Ionescu–Tulcea construction Ionescu-Tulcea construction of a Markov chain supplies the countable random sequence under the stated Choice assumption. The theorem on this page proves nonexplosion, identifies the transition semigroup, and establishes the positive reversible spectral gap. This is a finite mathematical rate model, not a derivation of rates from Hamiltonian mechanics.

PostulateStatement: Literature-sourcedProof: Not applicablejudge pass (gpt-6-luna)Open item page →

Adopted inertial velocity Langevin bath

Physical scope

One scalar component of a nonrelativistic particle's position and inertial velocity along a fixed spatial axis of one inertial frame, understood as the fixed adapted affine chart of the adopted Newtonian spacetime, with constant positive mass, damping rate and bath temperature, additive Brownian forcing, the stated stationary Gaussian preparation, and a prescribed continuous external force. This is an adopted model, not a universal bath law or an experimental report.

Postulate

Assume the Axiom of Choice The Axiom of Choice, the filtered Brownian probability-space convention of Ornstein–Uhlenbeck integral equation, and the adopted Newtonian spacetime and frame assumptions of Inertial frames, stationary observers and the adopted Galilean transformations between frames. Fix one inertial frame Γ=(o,u,(e1,e2,e3)) of that postulate: it is a fixed global adapted affine chart, with o∈A, u∈V, τ(u)=1, and a fixed positively oriented g-orthonormal basis (e1,e2,e3) of the spatial displacement space K=ker⁡τ. Its chart map assigns each event p∈A the unique coordinates (tΓ(p),xΓ(p)) satisfying p=o+tΓ(p)u+∑i=13xΓ,i(p)ei. Let X=(Xt)t≥0 be the scalar position-coordinate process in this chart, measured in metres, whose value is the signed first spatial coordinate along the fixed axis e1. The model tracks only X; it does not specify a full particle worldline or assert a law for either of the other spatial coordinates. Let X0 be an F0-measurable real-valued random variable. On a measurable event Ω∗∈F with P(Ω∗)=1, assume t↦Xt(ω) is continuously differentiable and define the velocity coordinate Vt(ω):=dXt(ω)/dt there, measured in metres per second. Thus Xt=X0+∫0tVs ds on Ω∗; values on the null complement do not affect the stochastic conclusions.

Take a primitive particle mass m>0 in kilograms, a primitive constant bath temperature Tb>0 in kelvins, and the primitive SI Boltzmann constant kB>0 in joules per kelvin. The positive damping rate γ is a primitive model parameter in seconds−1; the positive noise amplitude σ is derived as the square root of 2γkBTb/m and has units metres seconds−3/2. Let Bt be standard scalar Brownian motion with B0=0, variance t in seconds, and future increments independent of the present filtration. Prepare an F0-measurable V0∼N(0,kBTb/m) independently of future Brownian increments. The force F:[0,∞)→R is a prescribed deterministic locally continuous input in newtons. Adopt

Vt=V0−γ∫0tVs ds+1m∫0tF(s) ds+σBt,σ2=2γkBTbm.

The displayed integral equation is the definition of the stochastic differential notation dVt=−γVt dt+F(t) dt/m+σ dBt. Brownian increments have units seconds1/2, so every term in the equation for Vt has units metres seconds−1. When F=0, the preparation is the stationary OU Gaussian law because its variance is σ2/(2γ)=kBTb/m; the cited mathematical supplier establishes the specified OU model properties. The thermal noise normalization, Gaussian preparation, constant damping, and deterministic force coupling are adopted assumptions. No measurement, material calibration, nonlinear response, or microscopic derivation of this bath is asserted.

PostulateStatement: Literature-sourcedProof: Not applicablejudge pass (gpt-6-luna)Open item page →

Adopted finite reversible bath rates and field coupling

Physical scope

A prescribed connected finite-state rate network at one fixed positive temperature, initialized in its Gibbs stationary law for the equilibrium-response branch, with the explicitly selected symmetric exponential field coupling. No microscopic Hamiltonian reduction, rate calibration, or unique bath prefactor is asserted.

Postulate

Use the finite state set, energies ea, rates wab, Gibbs weights πa, and row generator Q defined in Finite reversible stochastic rate model. Assign the state energies the physical meaning of coarse-state energies in joules. Use the primitive SI Boltzmann constant kB in joules per kelvin from Adopted inertial velocity Langevin bath, and set β=(kBTb)−1 in joules−1 for the positive bath-temperature parameter Tb in kelvins. Adopt the baseline transition rates wab in seconds−1 and the initial law p0=π for the equilibrium-response branch. These choices define a finite phenomenological thermal rate model; they do not say that a real material has these rates.

Fix a finite time horizon tf>0. For a fixed state observable B:E→R with units denoted [B], a dimensionless control amplitude ϵ, and a continuous field h:[0,tf]→R with units joules per [B], adopt the controlled rates

wabϵ(t)=wabexp⁡ ⁣(βϵh(t)2(Bb−Ba)),a≠b.

Their units remain seconds−1 because the exponent is dimensionless. This is one explicit symmetric allocation of the field-dependent rate factor. For constant h and each positive-rate edge (wab>0, equivalently wba>0), the rate ratio obeys

wabϵwbaϵ=exp⁡ ⁣(−β[(eb−ϵhBb)−(ea−ϵhBa)]),

so the Gibbs weights of the shifted energies ea−ϵhBa satisfy detailed balance by direct multiplication on every positive-rate edge. For an absent edge, both controlled rates remain zero, so the detailed-balance product identity holds there as well; no rate ratio is defined there. A rate ratio alone leaves state-pair prefactors undetermined; the symmetric splitting above is an additional modeling choice and is the specific perturbation analyzed in the consuming theorem. No experiment or empirical rate estimate is asserted.

TheoremStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-6-luna)Open item page →

Nonexplosive finite continuous-time chain and reversible spectral gap

Statement

Assume the Axiom of Choice The Axiom of Choice and let E,π,w,Q be the finite model data of Finite reversible stochastic rate model, with ∣E∣=r≥2. For every initial probability row vector p0, there exists a time-homogeneous continuous-time Markov chain Xt on E, t≥0, with no finite accumulation of jumps, transition matrix Pt=etQ, and law pt=p0Pt. The detailed-balance law π is stationary. On the real inner-product space L2(E,π), Q is self-adjoint and has an orthonormal eigenbasis ϕ0=1,ϕ1,…,ϕr−1 with eigenvalues 0,−λ1,…,−λr−1, where every λj>0. Thus the spectral gap λ∗:=min⁡jλj is positive and Pt converges exponentially to projection onto constants.

Here a finite-state continuous-time Markov chain means a process with piecewise-constant paths whose conditional transition matrix over an interval of length t is Pt, independent of the starting time. For initial law π, the chain has a two-sided stationary extension Xt, t∈R, whose finite-dimensional laws at t1<⋯<tn are πa1∏i=1n−1Pti+1−ti(ai,ai+1). Its sample paths are locally piecewise constant with finitely many jumps on every bounded time interval.

Facts & Assumptions

Given: The Axiom of Choice and the rate model of Finite reversible stochastic rate model.

[A1]

The Axiom of Choice: every family of nonempty sets has a choice function.

[F1]

Finite reversible stochastic rate model: E is finite; π(f)=∑aπafa and ⟨f,g⟩π=∑aπafaga; qa=∑b≠awab; the row generator has Qab=wab for a≠b and Qaa=−qa; the positive-rate graph is connected; and πawab=πbwba.

[F2]

Ionescu-Tulcea construction of a Markov chain: under Choice, an initial probability law and a sequence of probability kernels determine a unique probability law on the countable product with the prescribed finite-prefix laws.

[F3]

Real spectral theorem: a self-adjoint endomorphism of a finite-dimensional real inner product space has an orthonormal eigenbasis: a self-adjoint endomorphism of a finite-dimensional real inner-product space has an orthonormal eigenbasis.

Proof

Given: [A1] and [F1]–[F3].

1.1A1F1F2constructalgebra

Set Λ>max⁡aqa and K:=I+Q/Λ. Every off-diagonal entry of K is nonnegative, Kaa=1−qa/Λ>0, and each row sums to one, so K is a transition matrix. The balance relation in [F1] gives πaKab=πbKba for all a,b. Use [F2] with state space E×(0,1), initial state distributed as p0 with an independent uniform mark, and transition kernel K(a,b) du′ from (a,u) to (b,u′). Write Yn for the state coordinate and Un for the uniform mark; the sequence Yn has transitions K, and the marks Un are independent uniforms independent of the state sequence. The holding intervals τn:=−log⁡Un/Λ are independent exponentials of rate Λ.

2.1A1F2step 1.1algebra

For every n, Pr⁡(τn≥1/Λ)=e−1. For each fixed m, independence gives probability (1−e−1)N that none of τm,…,τm+N−1 reaches 1/Λ; this tends to zero. A countable union over m shows that infinitely many holding intervals are at least 1/Λ, almost surely. Therefore Sn:=∑j=0n−1τj→∞. For each t≥0, there is a unique N(t) with SN(t)≤t<SN(t)+1; set Xt:=YN(t). Thus the constructed path is piecewise constant and has only finitely many transition attempts on each bounded interval. This proves nonexplosion.

3.1F1step 1.1step 2.1algebra

The sum of k≥1 independent rate-Λ exponential holding times has density Λksk−1e−Λs/(k−1)!, as follows by induction using convolution. Integrating this density against the survival e−Λ(t−s) of the next holding time gives Pr⁡(N(t)=k)=e−Λt(Λt)k/k!; for k=0 it is e−Λt. Starting from state a, each uniformized attempt stays at a with probability Kaa=1−qa/Λ. Since N(t) is Poisson and independent of the K-chain, the probability of no state change by time t is ∑k≥0e−Λt(Λt)kKaak/k!=e−qat. At the first attempt that changes state, the destination b≠a has conditional probability Kab/(1−Kaa)=wab/qa. Thus the actual holding time and jump destination have exactly the law stated in the Definition. The exponential holding times are memoryless and independent of the K-chain, so after any time the remaining clock and future transitions have the same laws from the current state; conditioning on N(t) therefore yields the time-homogeneous transition matrix Pt=e−Λt∑k=0∞(Λt)kKk/k!=etQ because Q=Λ(K−I). The finite-matrix series converges absolutely, differentiates termwise, and satisfies Pt′=PtQ and P0=I. Each term is stochastic, hence Pt is stochastic. For each state b, detailed balance gives (πQ)b=∑a≠bπawab−πbqb=πb∑a≠bwba−πb∑a≠bwba=0; therefore πPt=π.

4.1F1F3step 3.1algebra

For f,g∈L2(E,π), detailed balance gives ⟨f,Qg⟩π=⟨Qf,g⟩π. Pairing the two directed terms for each edge gives −⟨f,Qf⟩π=12∑a∈E∑b≠aπawab(fb−fa)2≥0. Equality holds only when fa=fb along every positive-rate edge; connectedness in [F1] then makes f constant. Thus the zero eigenspace is exactly the constants. By [F3], Q has a real orthonormal eigenbasis; nonpositivity and the one-dimensional kernel imply all other eigenvalues are −λj with λj>0. Expanding in this basis gives Ptf=π(f)1+∑j=1r−1e−λjt⟨f,ϕj⟩πϕj, proving the positive gap and exponential convergence.

5.1A1F1F2step 2.1step 3.1∎

Apply [F2] on ((E×(0,1))2) with initial state whose two E coordinates are equal with law π and whose two marks U0+,U0− are independent uniforms. From a state pair (a+,a−), use the product kernel K(a+,b+)K(a−,b−) du′+du′−; this makes the two K-chains conditionally independent given their shared initial state and gives independent uniform marks at every step. Denote the state coordinates by Yn±, set τn±:=−log⁡Un±/Λ, S0±:=0, and Sn±:=∑j=0n−1τj±. For s≥0, let N±(s) be the unique index with SN±(s)±≤s<SN±(s)+1± and put Zs±:=YN±(s)±. Step 2.1 applied to each clock sequence ensures these indices exist for every finite s. Put Xt=Zt+ for t≥0 and Xt=Z−t− for t<0. For times entirely on the nonnegative half, the Markov-chain law has the stated product form. For negative times t1<⋯<tk<0, append the time 0 with state c=X0. In the forward parameter s=−t, the ordered states are c,ak,…,a1, so their joint probability is πcP−tk(c,ak)∏i=1k−1Pti+1−ti(ai+1,ai). Applying πaPu(a,b)=πbPu(b,a) first to the factor from 0 to tk and then successively to the remaining factors gives πa1∏i=1k−1Pti+1−ti(ai,ai+1)P−tk(ak,c). Summing over c gives the negative-time marginal; k=1 is included by the empty-product convention. If a list also has nonnegative times, conditional independence of the halves given X0=c multiplies this negative-side factor by Ptk+1(c,ak+1)∏i=k+1n−1Pti+1−ti(ai,ai+1). For adjacent times tk<0≤tk+1 around zero, summing over c joins the two factors because ∑cP−tk(ak,c)Ptk+1(c,ak+1)=Ptk+1−tk(ak,ak+1), by the semigroup law. Thus in every case the joint probability is πa1∏i=1n−1Pti+1−ti(ai,ai+1), which depends only on time differences. For each a∈E, the set {(s,ω):Zs±(ω)=a} equals ⋃n≥0{(s,ω):Sn±(ω)≤s<Sn+1±(ω), Yn±(ω)=a}; every set in this union is product-measurable because Sn± and Yn± are measurable. Since E is finite, both half-processes are jointly measurable, and composing the negative half with t↦−t and gluing on the measurable half-lines preserves joint measurability. Step 2.1 gives finitely many jumps on every bounded interval on both halves, so the glued process has the stated local path property.

TheoremStatement: Literature-sourcedProof: AI-adaptedOpen item page →

Exact OU velocity response, diffusion and Gaussian scaling

Statement

Assume the Axiom of Choice The Axiom of Choice and the Brownian probability-space hypotheses in Ornstein–Uhlenbeck integral equation. Let γ,m,Θ,kB>0, σ>0, and σ2=2γkBΘ/m. Here these are real mathematical parameters; a separate physics postulate assigns their physical units and interpretation. Let V0:Ω→R be F0-measurable, satisfy V0∼N(0,kBΘ/m) and be independent of future Brownian increments. For any locally continuous deterministic input u:[0,∞)→R, and every finite tf>0, the equation restricted to [0,tf] Vt=V0−γ∫0tVs ds+1m∫0tu(s) ds+σBt,0≤t≤tf, has a unique continuous solution; these unique finite-horizon solutions agree on overlapping intervals and define one solution for all t≥0. Its mean is EVt=1m∫0te−γ(t−s)u(s) ds. For u=0, V is a stationary centered Gaussian process on [0,∞) with covariance E[VsVt]=vΘe−γ∣t−s∣,vΘ:=kBΘ/m. Define Yt:=∫0tVs ds and D:=vΘ/γ. Then Var⁡(Yt)=2vΘ(tγ−1−e−γtγ2),lim⁡t→∞Var⁡(Yt)2t=D. For every deterministic input, the centered displacement Yt−EYt is Gaussian with the variance above; consequently (Yt−EYt)/t converges in distribution to N(0,2D). For constant input u(s)=u0, lim⁡t→∞E[Vt]/u0=χ:=1/(mγ) when u0≠0, and D=χkBΘ.

Facts & Assumptions

Given: The Axiom of Choice, the OU integral equation definition, the published OU solution theorem, positive scalar parameters, and an F0-measurable stationary Gaussian initial state independent of future Brownian increments.

[A1]

The Axiom of Choice: every family of nonempty sets has a choice function.

[F1]

Ornstein–Uhlenbeck integral equation: an OU solution is a continuous adapted process satisfying the stated integral equation with an F0-measurable initial variable and Brownian increments independent of the present filtration.

[F2]

Ornstein–Uhlenbeck equation, transition law, and fluctuations: under Choice and its Brownian and initial-data hypotheses, the OU solution exists uniquely; a centered Gaussian initial law with variance V=σ2/(2γ) gives a stationary Gaussian process with covariance Ve−γ∣τ∣.

Proof

Given: [A1], [F1]–[F2], m,γ,Θ,kB>0, σ2=2γkBΘ/m, and an F0-measurable real random variable V0∼N(0,kBΘ/m) independent of future Brownian increments.

1.1A1F1F2constructalgebra

Let V0 be the unforced OU solution from [F2], satisfying the integral equation in [F1]. Define the deterministic function g(t):=1m∫0te−γ(t−s)u(s) ds. Differentiation under this finite integral gives g(0)=0 and g′(t)=−γg(t)+u(t)/m, hence g(t)=−γ∫0tg(s) ds+1m∫0tu(s) ds. Adding this identity to the unforced equation shows that the continuous adapted process Vt:=Vt0+g(t) satisfies Vt=V0−γ∫0tVs ds+1m∫0tu(s) ds+σBt, the forced equation in the Statement. If two forced solutions have the same initial state and Brownian path, their difference z satisfies z(t)=−γ∫0tz(s) ds; with H(t)=∫0t∣z(s)∣ ds, one has H′(t)≤γH(t) and H(0)=0. Thus (e−γtH(t))′≤0, so H=0 and z=0. Uniqueness makes the finite-horizon solutions agree on overlaps; gluing along integer horizons gives the solution for all t≥0 on a common probability-one event.

2.1F2step 1.1algebra

Since V0 is centered and g is deterministic, EVt=g(t), giving the claimed mean. The parameter relation gives σ2/(2γ)=kBΘ/m=vΘ, so [F2] gives stationarity, Gaussianity and the displayed covariance for the unforced solution.

3.1F2step 2.1algebra

For a uniform partition of [0,t], the Riemann sums Sn=(t/n)∑j=0n−1Vjt/n converge almost surely to Yt because V has continuous paths. Each Sn is centered Gaussian under u=0. By the covariance in step 2.1, its variance is a Riemann sum converging to ∫0t∫0tvΘe−γ∣s−r∣ ds dr=2vΘ∫0t(t−a)e−γa da=2vΘ(tγ−1−e−γtγ2). Hence the Gaussian characteristic functions of Sn converge to that of the centered normal with this variance. For each real ξ, almost-sure convergence and ∣eiξSn∣=1 let bounded convergence give EeiξSn→EeiξYt. Therefore Yt has the stated Gaussian law and variance. Adding the deterministic g to velocity changes only the mean of its integral, not this variance.

4.1step 3.1step 1.1algebra∎

Dividing the variance formula in step 3.1 by 2t and letting t→∞ gives D=vΘ/γ. The centered displacement has Gaussian variance 2Dt−2vΘ(1−e−γt)/γ2; after division by t this tends to 2D, proving the distributional limit. For constant u0, step 1.1 gives EVt=u0(1−e−γt)/(mγ), so χ=1/(mγ) and D=(kBΘ/m)/γ=χkBΘ.

Physics theoremStatement: Literature-sourcedProof: AI-adaptedOpen item page →

Conditional Langevin Green–Kubo and Einstein relation

Physical scope

Conditional one-dimensional prediction for the specified stationary inertial velocity Langevin model with constant mass, damping, temperature and additive noise. It does not assert the Einstein relation for nonlinear dynamics, arbitrary baths, general mechanical systems, or measured material coefficients.

Statement

Assume the adopted velocity bath Adopted inertial velocity Langevin bath on t≥0 and the Axiom of Choice The Axiom of Choice. Let Xt=X0+∫0tVs ds be the position coordinate in that model, and prepare V0 in its specified stationary Gaussian law. For zero external force, define the stationary velocity covariance by CVV(τ):=E[(Vs−EVs)(Vs+τ−EVs+τ)],s≥max⁡(0,−τ). Stationarity makes it independent of s, and the model gives CVV(τ)=kBTbme−γ∣τ∣. For a deterministic force applied at time s≤t, the linear response kernel is RVF(t−s)=1me−γ(t−s)=1kBTbCVV(t−s). Here RVF is defined by the exact mean-response formula E[Vt]=∫0tRVF(t−s)F(s) ds for deterministic forcing from the stated zero-mean stationary preparation; its units are kg−1. The constant-force mobility below is a distinct steady-response coefficient. The diffusion coefficient defined by centered displacement variance satisfies the Green–Kubo identity D:=lim⁡t→∞Var⁡(Xt−X0)2t=kBTbmγin m2 s−1. More precisely, D=∫0∞CVV(τ) dτ. The constant-force mobility μ:=lim⁡t→∞E[Vt]F0=1mγin s kg−1 for constant F0≠0. Hence D=μkBTb. The centered displacement divided by t converges in distribution to N(0,2D). These are conditional model deductions, not observed transport data or a universal law for arbitrary systems.

Facts & Assumptions

Given: The adopted one-dimensional Langevin equation and stationary preparation, Choice, and the exact mathematical OU velocity-response theorem.

[A1]

Adopted inertial velocity Langevin bath: m>0 is in kilograms, Tb>0 in kelvins, kB in joules per kelvin, γ>0 in seconds−1, σ2=2γkBTb/m, and the stationary initial velocity has variance kBTb/m.

[A2]

The Axiom of Choice: every family of nonempty sets has a choice function, as required by the Brownian and Itô suppliers.

[F1]

Exact OU velocity response, diffusion and Gaussian scaling: under σ2=2γkBΘ/m and V0∼N(0,kBΘ/m), the OU covariance is (kBΘ/m)e−γ∣τ∣, the integrated displacement variance has limit D=kBΘ/(mγ), and the constant-input response coefficient is 1/(mγ).

Proof

Given: [A1]–[A2] and [F1].

1.1A1algebra

Substituting σ2=2γkBTb/m from [A1] into the stationary variance V=σ2/(2γ) gives V=kBTb/m. Its units are J/kg=m2 s−2, the square of a velocity.

2.1A2F1step 1.1algebra

Apply [F1] with Θ=Tb and input u=F. Its covariance and response formulas give CVV(τ)=(kBTb/m)e−γ∣τ∣ and RVF(t−s)=m−1e−γ(t−s). Since (kBTb)−1CVV(t−s)=m−1e−γ(t−s), the claimed equilibrium response relation follows.

2.2A2F1A1step 1.1algebra

The same substitution in the displacement-variance limit of [F1] gives D=kBTb/(mγ). The covariance in the Statement gives ∫0∞CVV(τ) dτ=(kBTb/m)∫0∞e−γτ dτ=kBTb/(mγ)=D, the Green–Kubo identity for this model. Its constant-input response gives μ=1/(mγ), so D=μkBTb. The unit of μ is (m s−1)/N=s kg−1, and multiplication by kBTb in joules gives m2 s−1.

3.1A2F1A1step 2.2∎

The centered-displacement distributional limit in [F1] gives [Xt−X0−E(Xt−X0)]/t⇒N(0,2D). Every conclusion is conditional on [A1]; no observed value or empirical certainty is inferred.

RemarkRemark: AI-adaptedProof: Not applicableOpen item page →

Scope of the selected finite stochastic and kinetic models

Physical scope

Records the boundaries of the selected smooth periodic mean-field, finite angular-reflection, and finite reversible-rate formulations. It asserts no empirical applicability, microscopic rate derivation, hydrodynamic limit, or generic Hamiltonian ergodicity.

Remarks

The selected mean-field definition Smooth periodic finite-N and scaled mean-field phase data fixes a smooth periodic pair force and 1/N interaction scaling. The collision definition Cutoff elastic-reflection collision measure and gain fixes a homogeneous finite normalized angular reflection measure. The finite-rate definition Finite reversible stochastic rate model fixes a connected finite state graph and reversible rates. These formulations provide the precise regimes used by the results on this page.

No result here derives the finite-state rates from deterministic particle mechanics, proves a limit from particle dynamics to continuum fluid equations, or shows that long-time averages equal invariant-measure averages for a general Hamiltonian system. Such conclusions require their own stated microscopic model, limiting assumptions and mathematical proof. The Langevin model here is exactly Adopted inertial velocity Langevin bath: a scalar velocity process with positive constant mass, damping rate and bath temperature, additive Brownian forcing, the adopted thermal noise normalization, stationary Gaussian initial velocity, and prescribed deterministic continuous force, satisfying its displayed integral equation. The physical rate and Langevin models in this pair are adopted assumptions; their theorems are conditional predictions, and this pair contains no reported observations or empirical inference.

TheoremStatement: Literature-sourcedProof: AI-adaptedOpen item page →

Finite-rate fluctuation response and Green–Kubo inverse

Statement

Assume the Axiom of Choice The Axiom of Choice, countable choice The Axiom of Countable Choice (ACω), and the rate model E,π,w,Q of Finite reversible stochastic rate model. Let Xt be the stationary two-sided chain of Nonexplosive finite continuous-time chain and reversible spectral gap, with transition semigroup Pt=etQ. For any real observables A,B:E→R, write Ac=A−π(A) and Bc=B−π(B), and define CBA(t):=⟨Bc,PtAc⟩π,t≥0. Define Cov⁡π(A,B):=π(AB)−π(A)π(B), where AB is pointwise multiplication. For any finite horizon tf>0, let h:[0,tf]→R be continuous and let ϵ be dimensionless. For 0≤t≤tf, prescribe rates wabϵ(t)=wabexp⁡ ⁣(βϵh(t)2(Bb−Ba)),a≠b, with negative row sums on the diagonal, and let pϵ(0)=π evolve by the resulting finite forward equation. For 0≤t≤tf, the derivative of the observable mean at ϵ=0 is ∂∂ϵ∑apaϵ(t)Aa∣ϵ=0=∫0th(s)RAB(t−s) ds,RAB(u)=−β dduCBA(u). For a constant field h, define the normalized perturbed Gibbs vector by πaϵ:=πaeβϵhBa∑c∈EπceβϵhBc. It is stationary and its static susceptibility is βh Cov⁡π(A,B).

For any bounded vector observable G:E→Rd, set Gc=G−π(G) and Cij(s):=⟨(Gc)i,Ps(Gc)j⟩π. These correlations are absolutely integrable. The Green–Kubo covariance limit is lim⁡T→∞Cov⁡π(∫0TG(Xs) ds)2T=D,Dij=∫0∞Cij(s) ds=⟨(Gc)i,(−Q)−1(Gc)j⟩π, where (−Q)−1 is the inverse on the mean-zero subspace and D is positive semidefinite.

Facts & Assumptions

Given: Choice, countable choice, and the connected finite reversible rate model.

[A1]

The Axiom of Choice: every family of nonempty sets has a choice function.

[A2]

The Axiom of Countable Choice (ACω): for every sequence of nonempty sets (Xn)n∈N, there is a choice function selecting one member of each Xn.

[F1]

Finite reversible stochastic rate model: π(f)=∑aπafa and ⟨f,g⟩π=∑aπafaga; Qab=wab for a≠b, Qaa=−∑b≠awab, π is a positive probability vector, the positive-rate graph is connected, and πawab=πbwba.

[F2]

Nonexplosive finite continuous-time chain and reversible spectral gap: Pt=etQ is stochastic; Q is self-adjoint on L2(E,π) with a one-dimensional constant kernel and a positive gap; from initial law π there is a jointly measurable two-sided stationary chain.

[F3]

Green–Kubo covariance limit under absolute integrability: for a jointly measurable, centered, second-order stationary process on a two-sided time axis with absolutely integrable covariances, the covariance of its time integral divided by 2T converges to the symmetrized integrated covariance matrix, which is positive semidefinite.

Proof

Given: [A1]–[A2] and [F1]–[F3].

1.1A1A2F1F2F3algebra

By [F2], choose an orthonormal eigenbasis of Q with ϕ0=1 and Qϕj=−λjϕj for j≥1, where λj>0. For centered A,B, expand Ac=∑j≥1ajϕj and Bc=∑j≥1bjϕj. Then CBA(t)=∑j=1r−1bjaje−λjt and ∫0∞CBA(t) dt=∑j=1r−1ajbj/λj=⟨Bc,(−Q)−1Ac⟩π. The sum is finite, so the correlation is absolutely integrable. Applying the same expansion to each component of Gc gives Dij=∑j′=1r−1gi,j′gj,j′/λj′, a symmetric positive-semidefinite matrix. The two-sided stationary chain in [F2] has bounded, jointly measurable Gc(Xt); its covariance is absolutely integrable by this expansion, so [F3] gives the stated covariance limit and agrees with this matrix.

2.1A1F1F2step 1.1constructalgebra

For a finite time interval, the controlled off-diagonal rate matrix has the uniform expansion Qϵ(t)=Q+ϵh(t)K+O(ϵ2), where Kab=β2wab(Bb−Ba) for a≠b and each diagonal entry makes its row sum zero. The remainder is uniform because E is finite and h is bounded. The finite forward equation p′=pQϵ(t) has a unique solution: its Picard series converges uniformly, since the nth iterated integral is bounded by Mntfn/n! when ∥Qϵ(t)∥≤M. Since E is finite, h is bounded, and the exponential factors are bounded uniformly for t∈[0,tf] and ∣ϵ∣≤1, choose one Λ larger than every controlled exit rate on this set. Then Qϵ(t)+ΛI has nonnegative entries; after r(t)=eΛtpϵ(t), its Picard series has nonnegative terms, so pϵ(t)≥0 for all such ϵ. The row sums of Qϵ are zero, hence total mass remains one. Subtracting the unperturbed equation and using πQ=0 gives pϵ−π=O(ϵ) on [0,tf] by successive substitution in the bounded linear integral equation. Put yϵ=(pϵ−π)/ϵ; then yϵ(t)=∫0tyϵ(s)Q ds+∫0tpϵ(s)(Qϵ(s)−Q)/ϵ ds. The second integrand converges uniformly to πh(s)K, since pϵ→π uniformly and (Qϵ−Q)/ϵ→hK uniformly. Subtracting the limiting integral equation bounds ∥yϵ−q∥ by a term tending uniformly to zero plus M∫0t∥yϵ−q∥,ds; successive substitution bounds this difference by the forcing error times eMtf. Thus q=∂ϵpϵ∣0 exists and satisfies q′=qQ+hπK, q(0)=0. Variation of constants, verified by differentiation, gives q(t)=∫0th(s)πKPt−s ds.

3.1F1F2step 2.1algebra

For each state b, detailed balance in [F1] and the definition of K give (πK)b=β2∑a≠bπawab(Bb−Ba)−β2πb∑c≠bwbc(Bc−Bb)=−βπb(QB)b. Indeed, replacing πawab by πbwba makes the first sum the negative of the second before its prefactor is applied. Thus q(t)A=∫0th(s)(πK)Pt−sA ds=−β∫0th(s)⟨QBc,Pt−sAc⟩π ds. Self-adjointness of Q and Pu′=QPu imply CBA′(u)=⟨QBc,PuAc⟩π, proving the response formula.

4.1F1step 1.1algebra∎

For constant h, put Zϵ:=∑c∈EπceβϵhBc>0 and πaϵ=Zϵ−1πaeβϵhBa. Multiplying this by wabϵ gives a common edge factor proportional to πawabeβϵh(Ba+Bb)/2, symmetric in a,b by detailed balance. Hence πϵ is stationary. Differentiating its finite normalization sum at ϵ=0 gives ∂ϵ∑aπaϵAa∣0=βh(π(AB)−π(A)π(B)), the stated static susceptibility.

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Markov relative entropy decay and almost-sure time averages

Statement

Assume the Axiom of Choice The Axiom of Choice, countable choice The Axiom of Countable Choice (ACω), and the model E,π,w,Q of Finite reversible stochastic rate model. For any initial probability vector p0, let pt=p0Pt, where Pt=etQ is supplied by Nonexplosive finite continuous-time chain and reversible spectral gap, and define the dimensionless relative information D(pt∥π):=∑a∈Epa(t)log⁡pa(t)πa,0log⁡0:=0. For every t>0, pa(t)>0 for all states and ddtD(pt∥π)=−12∑a∈E∑b≠aπawab(rb(t)−ra(t))(log⁡rb(t)−log⁡ra(t))≤0,ra(t):=pa(t)πa. At a positive time the derivative vanishes exactly when pt=π, and D(pt∥π)→0 as t→∞.

For every bounded observable A:E→R and every initial law, the actual continuous-time average satisfies 1T∫0TA(Xs) ds⟶π(A)almost surely as T→∞. Under stationary preparation, with Ac=A−π(A) and spectral gap λ∗ from Nonexplosive finite continuous-time chain and reversible spectral gap, Var⁡π ⁣(1T∫0TA(Xs) ds)≤2∥Ac∥L2(π)2λ∗T.

Facts & Assumptions

Given: Choice, countable choice, the connected finite reversible rate model, and its stationary semigroup.

[A1]

The Axiom of Choice: every family of nonempty sets has a choice function.

[A2]

The Axiom of Countable Choice (ACω): every countable sequence of nonempty sets has a choice function.

[F1]

Finite reversible stochastic rate model: the finite rates obey πawab=πbwba, the positive-rate graph is connected, and Q is the row generator with off-diagonal entries wab.

[F2]

Nonexplosive finite continuous-time chain and reversible spectral gap: Pt=etQ, the only zero eigenfunctions of Q are constants, the nonzero eigenvalues are −λj with λj>0, and for initial law π there is a jointly measurable stationary process on R.

[F3]

Green–Kubo covariance limit under absolute integrability: for a jointly measurable, centered, second-order stationary process with absolutely integrable covariance, the variance of its time integral is the double-integral covariance formula and its covariance divided by 2T tends to the integrated covariance.

Proof

Given: [A1]–[A2] and [F1]–[F3].

1.1A1F1F2algebra

Choose Λ>max⁡aqa and set K=I+Q/Λ. By [F1], K is stochastic with positive diagonal, and for any distinct a,b a positive-rate path of length k gives Kabk>0; for a=b take k=0. By [F2], Pt=etQ=e−Λt∑n≥0(Λt)nKn/n!. Every summand is nonnegative and the term for this k is strictly positive, so Pt(a,b)>0 for every t>0. Hence pt(b)=∑ap0(a)Pt(a,b)>0.

1.2A1A2F2F3algebra

The eigenbasis in [F2] gives, for centered Ac=∑j≥1ajϕj, CA(s):=Eπ[Ac(X0)Ac(Xs)]=⟨Ac,PsAc⟩π=∑j≥1aj2e−λjs for s≥0. Thus CA(s)≥0 and ∫0∞CA(s) ds=∑j≥1aj2/λj≤∥Ac∥L2(π)2/λ∗. The process Ac(Xs) is centered, jointly measurable and second-order stationary; the spectral sum makes its covariance absolutely integrable. By [F3] the variance of its time integral is the double-integral covariance formula. Dividing by T2 and bounding T−s≤T proves the stated variance bound.

2.1F1step 1.1algebra

For t>0, differentiate the finite sum defining D; the mass derivative ∑apa′(t) is zero, so D′(t)=∑apa′(t)log⁡ra(t)=∑a∑b≠apa(t)wab(log⁡rb(t)−log⁡ra(t)). Use pa=πara and pair the directed (a,b) and (b,a) terms with the symmetric conductance πawab=πbwba. This gives the displayed negative half-sum. For positive x,y, (x−y)(log⁡x−log⁡y)≥0, with equality only at x=y, since log⁡x−log⁡y=∫yxdu/u. Connectedness forces all ra equal when the sum vanishes; normalization then gives ra=1 and pt=π.

2.2F2step 1.2algebra

Fix a reference time t∗>0 and put Tn=n2t∗. For every ε>0, the pointwise inequality 1{∣Y∣>ε}≤Y2/ε2 applied to Y=Tn−1∫0TnAc(Xs) ds, together with step 1.2, gives ∑n=1∞Pr⁡π(∣Y∣>ε)≤2∥Ac∥L2(π)2λ∗ε2t∗∑n=1∞n−2<∞. For each N, the probability that one of these events occurs for some n≥N is at most the corresponding tail sum, which tends to zero. Thus only finitely many occur almost surely. Applying this argument to ε=1/k for each positive integer k proves convergence to zero along Tn, almost surely.

3.1A1F1F2step 2.2algebra

Let M=max⁡a∈E∣Ac(a)∣. For Tn≤T≤Tn+1, ∣T−1∫0TAc(Xs)ds−Tn−1∫0TnAc(Xs)ds∣≤2M(Tn+1−Tn)/Tn→0. Hence the time averages converge to zero for stationary initial law. For any future-path event H and state a, let μa(H) be its probability under the common transition kernels started from a. Then Pr⁡p0(H)=∑ap0(a)μa(H)=Eπ[(p0(X0)/π(X0))1H], so the forward path law from p0 has density p0(X0)/π(X0) relative to the stationary path law. This density is bounded because E is finite and every πa>0. Every stationary null event, including failure of the almost-sure limit, is therefore null for every initial preparation. Adding π(A) proves the claimed limit.

4.1F2step 2.1∎

Exponential convergence in [F2] gives pt→π entrywise. The function x↦xlog⁡(x/πa) extends continuously to x=0 by value zero, so the finite sum D(pt∥π) tends to zero. Combined with step 2.1 this proves all the relative-information claims.

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Exact all-preparations coarse Markov criterion

Statement

Assume the Axiom of Choice The Axiom of Choice and the finite rate chain of Finite reversible stochastic rate model with transition semigroup supplied by Nonexplosive finite continuous-time chain and reversible spectral gap. Let C={C1,…,Ck} be a partition of E, meaning k≥1, each Ci is nonempty, the blocks are pairwise disjoint, and their union is E. For a∈Ci and j≠i, set q(a,Cj):=∑b∈Cjwab. The projected process Xˉt=i when Xt∈Ci has one time-homogeneous Markov generator valid for every initial microscopic probability law if and only if q(a,Cj) is independent of a∈Ci for every i and j≠i. Under this condition, the coarse generator has off-diagonal entries qˉij=q(a,Cj) for any a∈Ci and diagonal entries qˉii=−∑j≠iqˉij. Its stationary weights πˉi=∑a∈Ciπa satisfy detailed balance.

Facts & Assumptions

Given: The Axiom of Choice, a finite rate model, and its nonexplosive Markov semigroup.

[A1]

The Axiom of Choice: every family of nonempty sets has a choice function.

[F1]

Finite reversible stochastic rate model: Qab=wab for a≠b, Qaa=−∑b≠awab, and πawab=πbwba.

[F2]

Nonexplosive finite continuous-time chain and reversible spectral gap: the chain is nonexplosive and has transition semigroup Pt=etQ with forward equation p′=pQ.

Proof

Given: [A1], [F1]–[F2], and the partition C.

1.1F1F2constructalgebra

Let H be the subspace of functions on E that are constant on each block. For f(a)=fˉi when a∈Ci, (Qf)(a)=∑j≠iq(a,Cj)(fˉj−fˉi) for a∈Ci. If the block-rate sums are constant within each Ci, this value is independent of the chosen a∈Ci. Thus Q maps H into itself, and its restriction is the matrix Qˉ in the Statement. Every power Qn preserves H, so the matrix series Pt=etQ does too; for any block Cj, Pt1Cj is constant on each block and defines Pˉt=etQˉ.

2.1A1F1F2step 1.1algebra

Conditional on the full microscopic history through time t, the Markov property gives Pr⁡(Xˉt+s=j∣FtX)=(Ps1Cj)(Xt)=(Pˉs)Xˉt,j. The right side depends only on the current block. Taking conditional expectation with respect to the coarser history proves that Xˉ is a time-homogeneous Markov chain for every microscopic initial law. Moreover, πˉiqˉij=∑a∈Ci∑b∈Cjπawab=∑a∈Ci∑b∈Cjπbwba=πˉjqˉji, so its stationary block weights satisfy detailed balance.

3.1A1F1F2algebra∎

Conversely, assume one time-homogeneous block generator applies for every microscopic initial law. Start once from a point mass at a∈Ci and once at a′∈Ci. For j≠i, the finite matrix expansion ehQ=I+hQ+O(h2) gives Pr⁡a(Xˉh=j)=hq(a,Cj)+O(h2) and Pr⁡a′(Xˉh=j)=hq(a′,Cj)+O(h2). Both probabilities must use the same coarse transition entry from block i to block j. Divide by h>0 and let h↓0; then q(a,Cj)=q(a′,Cj). This holds for each block pair, proving necessity and the equivalence.

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Conditional finite-state equilibration and fluctuation response

Physical scope

Conditional predictions of the specified connected finite-state thermal rate model, including relative-information relaxation from any initial law, equilibrium linear response for its chosen field-dependent rates, and long-time averages of bounded state observables. Rate values and material applicability require separate physical calibration; no observations or empirical rate estimates are included.

Statement

Assume the adopted finite thermal rate model Adopted finite reversible bath rates and field coupling, including its finite energy states, detailed-balance rates, temperature parameter and stationary Gibbs preparation for the response branch. For any initial microscopic probability law, the model's dimensionless relative information D(pt∥π) is nonincreasing and tends to zero, and every bounded state observable has an almost-sure time average equal to its Gibbs mean. For real state observables A,B:E→R, any finite horizon tf>0, and a continuous field h:[0,tf]→R, the equilibrium-response branch with the postulated symmetric field-dependent rates has, for 0≤t≤tf, first-order response δ⟨A(t)⟩=∫0th(s)[−β dduCBA(u)∣u=t−s]ds, where δ⟨A(t)⟩:=∂ϵ∑apaϵ(t)Aa∣ϵ=0, pϵ(0)=π, and pϵ solves the finite forward equation for the postulated controlled rates. The correlation is CBA(u)=⟨(B−π(B)),Pu(A−π(A))⟩π. For a constant field amplitude g (in joules per unit of B), define the normalized perturbed equilibrium vector by πag:=πaeβgBa∑c∈EπceβgBc and define its susceptibility per unit field by χAB:=∂gπg(A)∣g=0. Then χAB=β Cov⁡π(A,B) and, when g=ϵh for constant h, the derivative with respect to dimensionless ϵ is hχAB. Here πg(A):=∑aπagAa and Cov⁡π(A,B):=π(AB)−π(A)π(B). If physical units are assigned to A and B, write them as [A] and [B]: CBA has units [A][B], while βh dCBA/du has units [A] per second, so the time integral and the derivative with respect to dimensionless ϵ have units [A]. These are conditional predictions of this finite stochastic model. They concern its dimensionless relative-information functional and state observables; no experimental observation, calibrated rate, material-specific claim or universal thermodynamic law is asserted.

Facts & Assumptions

Given: The adopted finite rate model, the full and countable choice assumptions, and the local finite-chain theorems.

[A1]

Adopted finite reversible bath rates and field coupling: the model adopts p0=π, β=(kBTb)−1, baseline reversible rates, and the specified symmetric exponential control law.

[A2]

The Axiom of Choice: every family of nonempty sets has a choice function.

[A3]

The Axiom of Countable Choice (ACω): every countable sequence of nonempty sets has a choice function.

[F1]

Finite reversible stochastic rate model: the finite energies, positive Gibbs vector, connected bidirectional rate graph and row generator are explicitly defined.

[F2]

Markov relative entropy decay and almost-sure time averages: the relative-information derivative, convergence to π, almost-sure time averages from every initial law, and stationary variance bound hold for this generator.

[F3]

Finite-rate fluctuation response and Green–Kubo inverse: under the stated symmetric exponential rate perturbation, the finite forward equation has the derived equilibrium response kernel and static susceptibility.

Proof

Given: [A1]–[A3] and [F1]–[F3].

1.1A1A2A3F1F2F3algebra

By [A1] and [F1], the adopted physical model supplies the exact finite state set, energy vector, inverse-temperature factor β, connected rate graph and detailed-balance law used in [F2] and [F3]. The Choice assumptions [A2]–[A3] are the mathematical hypotheses inherited by those two suppliers.

2.1A1F2step 1.1

Apply [F2] to the unforced generator. It gives nonincrease and convergence of D(pt∥π) for every initial law and almost-sure convergence of every bounded-observable time average. These are consequences of the stipulated finite chain and its conditional probability law.

3.1A1F3step 1.1∎

In the equilibrium-response branch, [A1] fixes p0=π and the controlled rates exactly in the form assumed by [F3]. Therefore [F3] gives the stated correlation response and static susceptibility. The source's rate-ratio condition alone does not fix the adopted prefactors; the derivation uses the additional symmetric splitting in [A1]. The conclusions are conditional on that adopted model; no empirical observation or material-specific inference is involved.

5 · Examples, experiments and counterexamples

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