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✓ 14 results · all verified · 11 also independently AI-judged
Every result on this page is machine-checked by a proof checker and read in full and owner-audited; the judge is an additional, independent cross-model AI review of the proofs. The 3 not AI-judged were verified by owner audit (typically over a confirmed judge false positive), not failures.

Rare event importance sampling and multilevel splitting

1 · Prerequisites

2 · Summary

This page separates rare-event proposal quality from the validity of a particular estimator. It defines bounded-relative-error and logarithmic-efficiency criteria, proves the event-conditioned zero-variance benchmark and the exact performance of a Gaussian exponential tilt, and states what independent cross-entropy fitting can guarantee conditional on a successful pilot and admissible production proposal. It also records a positive-probability pilot failure example.

For nested events, the page defines conditional level laws and proves the probability factorization. Independent fixed-level splitting has exact moments and an explicit work convention. The full-resampling SIR construction uses invariant mutations and proves normalizer unbiasedness. A separate martingale argument proves an absolute (L+1)/(4N) mean-square bound for bounded potentials. A two-state counterexample refutes the proposed sharper bound based only on squared conditional future means; the asymptotic SMC CLT variance result does not repair that formula. A separate finite-particle relative MSE bound uses actual conditional event-weight second moments under the random predictive laws, includes the initial sampling factor, and asserts no uniform-in-rarity efficiency without bounds on those additional constants.

A finite-budget stopped-status kernel distinguishes a truncated crossing event from an exact-hitting oracle. Its event normalizer and truncation error are proved, as is a total-variation perturbation bound for finite Feynman–Kac horizons. No continuous-grid error rate is asserted without a separate regularity or missed-crossing estimate.

3 · Logical flowchart

4 · Definitions, theorems and proofs

DefinitionDefinition: Literature-sourcedProof: Not applicableOpen item page →

Rare-event efficiency and work criteria

Definition

Let (Pλ,Aλ)λ∈Λ be a family of probability measures and measurable events with pλ=Pλ(Aλ)>0 and pλ→0 along the stated rare-event limit. An estimator p^λ is unbiased with finite variance when E[p^λ]=pλ and Var⁡(p^λ)<∞. Its relative error is RE⁡(p^λ)=Var⁡(p^λ)pλ. It has bounded relative error if these relative errors remain bounded for all sufficiently rare indices. For such an unbiased estimator family, it is logarithmically efficient if p^λ≥0, its second moment is finite and positive, and lim⁡λlog⁡E[p^λ2]log⁡(pλ2)=1. Among nonnegative unbiased estimator families, logarithmic efficiency is a weaker asymptotic property than bounded relative error; the definitions impose no implication between an algorithm's efficiency and its proposal-fitting success.

For a specified cost model, let Wλ be the expected work of one estimator replication. Record both its variance and its variance-work product WλVar⁡(p^λ); for relative precision, record WλVar⁡(p^λ)/pλ2. These quantities depend on the cost model. Comparing algorithms requires the same declared work convention.

For a single event A under a probability measure P, put p=P(A)>0. If P has density f with respect to μ, the zero-variance event proposal is the probability density q∗(x)=1A(x)f(x)p. It is a formal benchmark because its normalizing constant is the unknown event probability p. Ordinary importance-sampling estimators and their weighted-second-moment condition are defined in Ordinary importance sampling and Ordinary importance sampling has finite variance and a CLT under a weighted second moment.

LemmaStatement: Literature-sourcedProof: AI-generatedjudge pass (gpt-6-luna)Open item page →

Standard-normal Mills bounds and logarithmic tail asymptotics

Statement

Let ϕ(x)=(2π)−1/2e−x2/2 be the standard-normal density and Φˉ(x)=∫x∞ϕ(t) dt. For every x>0, xx2+1ϕ(x)≤Φˉ(x)≤ϕ(x)x. Consequently Φˉ(x)∼ϕ(x)/x and log⁡Φˉ(x)∼−x2/2 as x→∞.

Facts & Assumptions

Given: The standard-normal density ϕ from Standard normal and normal laws, x>0, and the tail integral in the Statement.

[F1]

Standard normal and normal laws: N(0,1) has density ϕ(t)=e−t2/2/2π with total mass one.

[A1]

The Axiom of Choice: AC is assumed only because the cited standard-normal definition uses it through its normalization suppliers.

Proof

1.1F1A1givenalgebra

Since ϕ′(t)=−tϕ(t), for t≥x>0 we have ϕ(t)≤tϕ(t)/x. Integrating and using ∫x∞tϕ(t) dt=ϕ(x), obtained by integrating −ϕ′, gives Φˉ(x)≤ϕ(x)/x.

2.1F1step 1.1givenalgebra

Integration by parts on [x,R], followed by R→∞, gives Φˉ(x)=ϕ(x)x−∫x∞ϕ(t)t2 dt. The remainder is at most Φˉ(x)/x2, hence Φˉ(x)(1+x−2)≥ϕ(x)/x, which is the stated lower bound.

3.1step 1.1step 2.1algebra∎

Dividing the two bounds by ϕ(x)/x>0 traps the ratio Φˉ(x)/(ϕ(x)/x) between x2/(x2+1) and 1, so it tends to 1. Taking logarithms gives log⁡Φˉ(x)=−x2/2−log⁡x−12log⁡(2π)+o(1); division by −x2/2 yields the asserted logarithmic limit.

AlgorithmAlgorithm: Literature-sourcedProof: Not applicableprecheck pendingjudge pass (gpt-6-luna)Open item page →

Independent-pilot cross-entropy proposal fitting and production

Definition

Let (X,X,μ) be a measure space, let A∈X, and let the target probability measure P have a pointwise finite measurable density f:X→[0,∞) with respect to μ, so P(B)=∫Bf dμ. Let {qθ:θ∈Θ} be pointwise finite probability densities with respect to μ, and write Qθ(dx)=qθ(x)μ(dx), where Θ⊂Rd is a finite nonempty set equipped with lexicographic order. For each θ∈Θ, supply an exact admissibility checker C(A,f,qθ) that returns admissible if and only if P∣A≪Qθ and the contribution

wθ(x)={1A(x)f(x)/qθ(x),qθ(x)>0,0,qθ(x)=0

is integrable under Qθ, where P∣A(B):=P(B∩A) for measurable B. Supply an initial parameter θ0∈Θ, a pilot size m≥1, and a production size n≥1.

  1. Draw an IID pilot Y1,…,Ym∼qθ0.
  2. If no Yj lies in A, return pilot-no-hit.
  3. For every θ∈Θ, compute sθ(y)={log⁡qθ(y),y∈A,0,y∉A,S(θ)=∑j=1msθ(Yj), with log⁡0=−∞. Pointwise finiteness rules out +∞, and the piecewise score avoids the undefined product 0⋅(−∞). If all scores equal −∞, return no-finite-maximizer. Otherwise choose the lexicographically least maximizer θ^ among the finite scores and freeze it.
  4. Evaluate C(A,f,qθ^). If it returns inadmissible, return inadmissible-production-proposal. Otherwise draw an IID production sample X1,…,Xn∼qθ^, independent of the pilot conditional on θ^, and return the ordinary importance-sampling estimate p^CE=1n∑i=1nwθ^(Xi) using the piecewise-defined contribution wθ^ above.

The finite candidate set makes the score comparisons and tie rule deterministic. The supplied exact checker is an input oracle; the procedure does not infer support or integrability from a pilot fit. If its check fails, no production estimate or unbiasedness or finite-variance claim is returned.

DefinitionDefinition: Literature-sourcedProof: Not applicablejudge pass (gpt-6-luna)Open item page →

Nested rare-event levels and conditional laws

Definition

Let (Ω,F,P) be a probability space as in Probability measures and probability spaces. A finite nested event sequence of length L≥1 is a sequence of measurable sets Ω=A0⊇A1⊇⋯⊇AL=A such that P(Aℓ)>0 for 0≤ℓ≤L. Its conditional level probabilities and level laws are pℓ=P(Aℓ)P(Aℓ−1)∈(0,1],πℓ(B)=P(B∩Aℓ)P(Aℓ)(B∈F). The target probability is p=P(AL). Independence across levels means that the complete sample arrays used at distinct levels are mutually independent; correct marginal laws alone do not imply this condition.

DefinitionDefinition: Literature-sourcedProof: Not applicablejudge pass (gpt-6-luna)Open item page →

Finite-budget stopped-event kernel with a cemetery outcome

Definition

Let (E,E) be a standard Borel space, M a probability kernel on it, and T,R∈E disjoint target and return sets. Write S=E∖(T∪R) and let C={hit,return,∂} have the discrete sigma-algebra; ∂ is the cemetery outcome meaning the budget expired before either set was reached.

For budget m=0, define κ0(x,⋅)={δhit,x∈T,δreturn,x∈R,δ∂,x∈S. For m≥0, define the finite-budget stopped-status kernel recursively by κm+1(x,⋅)={δhit,x∈T,δreturn,x∈R,∫Eκm(y,⋅) M(x,dy),x∈S. Thus a target hit at the initial state counts at budget zero; each additional budget unit permits one more transition. The exact-hitting status kernel, when used, is the limit law of these statuses and treats nontermination as ∂; it is an exact sampler for Px(τT<τR) only when the requested event is the finite first hit represented by that limit. The budgeted kernel is distinct from an exact-hitting oracle.

LemmaStatement: AI-adaptedProof: AI-generatedprecheck passjudge pass (gpt-6-luna)Open item page →

A bounded-potential SIR update has a uniform unnormalized variance bound

Statement

Let ν be a probability measure on (E,E), M a probability kernel on E, G,f:E→[0,1] measurable, z∈[0,1], and N≥1. Draw Y1,…,YN IID from the probability law νM. Put a=N−1∑i=1NG(Yi). If a>0, set ηN=∑i=1NG(Yi)δYiNa; if a=0, let ηN be any probability measure. Define the one-step unnormalized estimate ΓN(f)=za ηN(f). Then E[ΓN(f)]=z νM(Gf),Var⁡(ΓN(f))≤z24N. The estimate is the normalizer update za multiplied by the weighted empirical mean of f. The zero-weight fallback does not affect ΓN.

Facts & Assumptions

Given: The probability measure ν, probability kernel M, measurable functions G,f valued in [0,1], z∈[0,1], and N independent proposals from νM.

[F1]

Measure kernel and probability kernel: Integrating a probability measure against a probability kernel defines a probability law νM.

[F2]

Unbiasedness and exact variance of the IID Monte Carlo mean: The mean of an IID sample average is the common mean, and its variance is the common variance divided by N when the variables are square-integrable.

[F3]

Moments, variance, and covariance on a probability space: For square-integrable H, Var⁡(H)=E[H2]−(EH)2.

Proof

1.1givenalgebra

If a>0, then za ηN(f)=zN∑i=1NG(Yi)f(Yi) by the definition of ηN. If a=0, each nonnegative G(Yi)=0, so both sides equal zero for any fallback ηN. Thus the identity holds on every proposal outcome.

2.1F1F2F3step 1.1givenalgebra∎

The variables Hi=G(Yi)f(Yi) are IID and lie in [0,1]. For H=H1, H2≤H, so [F3] gives Var⁡(H)≤EH−(EH)2≤1/4, since u(1−u)≤1/4 for u∈[0,1]. By [F2], the average N−1∑iHi has mean νM(Gf) and variance at most 1/(4N). Multiplication by z and step 1.1 give both claims.

Source notes

The cited rare-event SMC papers motivate the particle update; this exact one-step bound is proved locally from the canonical IID sample-mean moments, including the zero-weight branch.

TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passOpen item page →

The event-conditioned proposal is the zero-variance benchmark

Statement

Let (X,X,μ) be a measure space, let P have density f≥0 with ∫f dμ=1, and let A∈X have p=P(A)>0. For q∗(x)=1A(x)f(x)/p and X∼Q∗ with this density, the ordinary importance-sampling contribution Z=1A(X)f(X)/q∗(X), defined on the Q∗-support, equals p almost surely. Thus the estimator from n≥1 IID Q∗-draws is unbiased and has variance zero. This proposal depends on the unknown p, so it is a benchmark and not a generally available algorithm.

Facts & Assumptions

Given: The probability density f, event A, and p=P(A)>0 in the Statement.

[F1]

Rare-event efficiency and work criteria: The zero-variance event proposal has density q∗(x)=1A(x)f(x)/p.

[F2]

Ordinary importance sampling: Ordinary importance sampling averages the contributions 1A(Xi)f(Xi)/q(Xi) over IID proposal draws where q>0.

Proof

1.1F1givenalgebra

The density q∗ is nonnegative and ∫q∗ dμ=P(A)/p=1, so it defines a proposal probability measure Q∗ supported on {x∈A:f(x)>0} up to a Q∗-null set.

2.1F1F2step 1.1givenalgebra∎

For Q∗-almost every X, we have X∈A and f(X)>0. Substitution of q∗(X)=f(X)/p into [F2] gives Z=p almost surely. Every term in the IID sample average is therefore the same constant p; its expectation is p and its variance is zero.

TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passOpen item page →

Gaussian tail tilting is logarithmically efficient but not bounded-relative-error

Statement

Assume AC. Let P=N(0,1), Aa=[a,∞), pa=P(Aa)=Φˉ(a), and Qa=N(a,1), for a>0. Let Za=1Aa(X) dP/dQa(X) for X∼Qa, and let p^a,n be the average of n IID copies. Then EQa[Za]=pa,EQa[Za2]=ea2Φˉ(2a). As a→∞, p^a,n is logarithmically efficient, while its one-sample relative error grows asymptotically as (π/2)1/4a. In particular this tilt is not bounded-relative-error.

Facts & Assumptions

Given: The standard-normal density and tail, the event Aa, the proposal Qa, and a>0.

[A1]

The Axiom of Choice: AC is inherited through Standard normal and normal laws; no further choice is used.

[F1]

Standard normal and normal laws: N(0,1) has density ϕ(x)=e−x2/2/2π, and N(a,1) is its translate by a.

[F2]

Standard-normal Mills bounds and logarithmic tail asymptotics: Φˉ(x)∼ϕ(x)/x and log⁡Φˉ(x)∼−x2/2 for x→∞.

[F3]

Rare-event efficiency and work criteria: Relative error is Var⁡(Za)/pa, and logarithmic efficiency is determined by log⁡E[Za2]/log⁡(pa2).

[F4]

Ordinary importance sampling is unbiased: Under the event-support and integrability hypotheses, the ordinary importance-sampling mean equals pa.

[F5]

Ordinary importance sampling has finite variance and a CLT under a weighted second moment: A finite weighted second moment gives Var⁡(Za)=E[Za2]−pa2.

[F6]

Unbiasedness and exact variance of the IID Monte Carlo mean: For n IID square-integrable contributions, the sample mean has mean pa and variance Var⁡(Za)/n.

Proof

1.1A1F1F4givenalgebra

For every x∈R, the density ratio is ϕ(x)/ϕ(x−a)=exp⁡(−ax+a2/2). The proposal has positive density on Aa, and 0≤Za≤e−a2/2 on Aa, so the event-support and integrability hypotheses of [F4] hold. Hence EQaZa=pa.

1.2F1givenalgebra

Direct integration gives EQaZa2=∫a∞e−2ax+a2ϕ(x−a) dx. With y=x−a, the integrand becomes e−2ay−a2ϕ(y)=ea2ϕ(y+2a); the integral is ea2Φˉ(2a), which is finite for every a>0.

2.1F2F3F6step 1.2givenalgebra

For the average of n≥1 IID contributions, [F6] gives E[p^a,n2]=pa2+E[Za2]−pa2n,pa2≤E[p^a,n2]≤pa2+E[Za2]. By [F2], log⁡pa2=−a2+o(a2) and log⁡E[Za2]=a2+log⁡Φˉ(2a)=−a2+o(a2). Therefore also log⁡(pa2+E[Za2])=−a2+o(a2). The two bounds squeeze log⁡E[p^a,n2]=−a2+o(a2), while 2log⁡pa=−a2+o(a2). By [F3], the logarithmic-efficiency ratio tends to 1.

3.1F2F4F5step 1.2algebra∎

Mills' equivalent in [F2] yields EZa2pa2∼ea2ϕ(2a)/(2a)(ϕ(a)/a)2=π/2 a. Using [F4] and [F5], RE⁡(p^a,1)2=EZa2/pa2−1∼π/2 a; taking square roots gives the stated divergence.

TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-6-luna)Open item page →

Independent cross-entropy production is conditionally unbiased

Statement

Use Independent-pilot cross-entropy proposal fitting and production. Let G=σ(Y1,…,Ym) and let H∈G be the event that the pilot succeeds and the algorithm's exact admissibility checker accepts the selected parameter θ^. On H, the checker guarantees P∣A≪Qθ^ and integrability under Qθ^ of the piecewise contribution wθ^ defined in the algorithm. Define p~CE to equal the returned production estimate on H and zero off H. Then

E[p~CE∣G]=1HP(A)almost surely.

In particular, the production estimate is conditionally unbiased almost surely on the successful, admissible pilot event. This gives no probability-of-success, proposal-optimization, finite-variance, logarithmic-efficiency, or total-work guarantee.

Facts & Assumptions

Given: The pilot sigma-algebra G, the successful and admissible event H, the frozen parameter θ^, the independent production sample, and the support and integrability conditions for wθ^ certified by the algorithm's checker.

[F1]

Independent-pilot cross-entropy proposal fitting and production: After a successful pilot the selected θ^ is frozen, and the production sample is IID from Qθ^, independent of the pilot conditional on that parameter.

[F2]

Ordinary importance sampling is unbiased: For a fixed proposal with support on the target event and an integrable weighted contribution, the ordinary importance-sampling mean equals the target expectation.

Proof

1.1F1given

The pilot outcome space need not be finite. For each θ∈Θ, the score S(θ) is G-measurable, and Θ is finite. Therefore the success event, the exact-checker acceptance event, and the lexicographically least maximizing selector θ^ on success are G-measurable. Partition H into the finitely many events Hθ=H∩{θ^=θ}. Conditional independence of the production sample from the pilot given θ^, as specified in [F1], means that on each Hθ its conditional law given G is IID Qθ.

2.1F2step 1.1givenalgebra∎

On each Hθ, the checker gives the support and integrability hypotheses for [F2]. That theorem gives conditional expectation P(A) for each production contribution given G, and linearity gives the same conditional expectation for their average. Since the finitely many Hθ partition H and p~CE=0 off H, this proves E[p~CE∣G]=1HP(A) almost surely.

LemmaStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-6-luna)Open item page →

Nested-event probabilities factor into conditional levels

Statement

For the nested event levels of Nested rare-event levels and conditional laws, P(AL)=∏ℓ=1Lpℓ.

Facts & Assumptions

Given: A nested sequence A0=Ω⊇A1⊇⋯⊇AL with all prefix probabilities positive.

[F1]

Nested rare-event levels and conditional laws: pℓ=P(Aℓ)/P(Aℓ−1) and P(A0)=1.

Proof

1.1F1givenalgebra

The definition gives P(Aℓ)=pℓP(Aℓ−1) for every 1≤ℓ≤L.

2.1F1step 1.1algebra∎

Applying these identities successively from ℓ=1 to L yields P(AL)=P(A0)∏ℓ=1Lpℓ=∏ℓ=1Lpℓ, since P(A0)=1.

AlgorithmAlgorithm: Literature-sourcedProof: Not applicableprecheck pendingjudge pass (gpt-6-luna)Open item page →

Independent fixed-level splitting

Definition

Input the nested levels and exact conditional samplers for πℓ−1 from Nested rare-event levels and conditional laws, a particle count N≥1, and a declared per-draw work cost cℓ>0 for each level. If any conditional sampler is unavailable, return conditional-sampler-unavailable.

For each level ℓ=1,…,L, independently of every other level, draw Xℓ,1,…,Xℓ,N IID from πℓ−1. Set p^ℓ=N−1∑i=1N1Aℓ(Xℓ,i),p^=∏ℓ=1Lp^ℓ. Return p^, the level counts, total draw work W=N∑ℓ=1Lcℓ, and status success if all level counts are positive or zero-level-estimate otherwise. The zero estimate is not a proof that P(AL)=0.

The procedure is an ideal independent-level baseline. It does not assert that a branching or Markov mutation method produces independent exact conditional draws.

AlgorithmAlgorithm: Literature-sourcedProof: Not applicableprecheck pendingjudge pass (gpt-6-luna)Open item page →

Full-resampling fixed-level SIR splitting with invariant mutations

Definition

Input the nested levels of Nested rare-event levels and conditional laws on a standard Borel state space (Ω,F), a particle count N≥1, and probability kernels Kℓ for 1≤ℓ<L. Each mutation kernel must satisfy Kℓ(x,Aℓ)=1(x∈Aℓ),πℓKℓ=πℓ. If a required kernel is unavailable or violates its declared conditions, return mutation-kernel-unavailable.

Apply the canonical full-resampling sequential importance-resampling procedure of Sequential importance resampling for Feynman–Kac path targets to the following finite Feynman–Kac model: initial law P, initial potential G0≡1, identity transition M1, event potential G1=1A1, and, for 2≤ℓ≤L, transition Mℓ=Kℓ−1 and potential Gℓ=1Aℓ. Use multinomial full resampling at every selection and proposal kernels equal to the target transitions, so each Radon–Nikodym correction is one.

Return the SIR normalizer estimate p^ and the full particle output. If any incremental average event weight is zero, report status zero-particle-prefix and p^=0, as in the canonical SIR procedure. This status does not assert that the target probability is zero. The exact conditional level sampler is not inferred from the existence of an invariant kernel; kernel accessibility is an input requirement.

LemmaStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-6-luna)Open item page →

Finite-budget stopped-kernel measurability and event normalizer

Statement

Assume AC. Under the hypotheses of Finite-budget stopped-event kernel with a cemetery outcome, every κm is a measurable probability kernel from E to C. For an initial probability law μ, let pm=∫Eκm(x,{hit}) μ(dx). Then pm=Pμ(τT<τR, τT≤m). In the one-step Feynman–Kac model with initial law μ, transition κm, initial potential 1, and terminal potential 1{hit}, the normalizer is exactly pm. The limit lim⁡m→∞pm=Pμ(τT<τR) is the exact-hitting normalizer; an exact simulator with finite expected work requires a separate termination-cost bound.

Facts & Assumptions

Given: A measurable state space, probability kernel M, disjoint measurable target and return sets T,R, and the finite-budget kernels from Finite-budget stopped-event kernel with a cemetery outcome.

[A1]

The Axiom of Choice: AC is inherited through the path-law construction used by the finite-horizon supplier.

[F1]

Finite-budget stopped-event kernel with a cemetery outcome: κ0 assigns hit, return, or cemetery according to the current state; κm+1 fixes terminal states and otherwise integrates κm after one M-transition.

[F2]

Measurability of integration against a kernel: Integrating a nonnegative measurable section against a probability kernel gives a measurable function of the source state.

[F3]

Ionescu-Tulcea construction of a Markov chain: Finite-prefix path laws have the prescribed iterated-kernel probabilities.

[F4]

Feynman–Kac path targets and normalizers: A finite-horizon Feynman–Kac normalizer is the integral of the product of its potentials against the ordered path law.

Proof

1.1F1given

For m=0, the three status probabilities are the indicators of the disjoint partition T,R,S; they are measurable and sum to one. Thus κ0 is a probability kernel.

1.2F1F3giveninduction

At m=0 the hit status occurs exactly when X0∈T. For m+1, points in T or R stop immediately, while from S the first M-transition is followed by the budget-m rule. The finite-prefix law [F3] and induction therefore identify κm(x,{hit}) with Px(τT<τR,τT≤m); integrating against μ gives pm.

2.1F1F2step 1.1given

Suppose κm is a probability kernel. For each c∈C, the function y↦κm(y,{c}) is measurable. By [F2], its M(x,⋅)-integral is measurable in x. On T and R the next status is the corresponding point mass; on S the three integrals sum to ∫1 M(x,dy)=1. Hence κm+1 is a probability kernel, and induction proves the first claim.

3.1A1F3F4step 1.2given∎

In the one-step Feynman–Kac model, the product of potentials is 1{hit}; [F4] therefore gives normalizer ∫1{hit} d(μκm)=pm. The success events by budgets m increase to {τT<τR}; countable additivity gives the limit identity.

LemmaStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-6-luna)Open item page →

Truncation and total-variation errors for stopped crossings

Statement

Assume AC. In the stopped-event setup of Finite-budget stopped-event kernel with a cemetery outcome, with (E,E) standard Borel and initial probability law μ, let p=Pμ(τT<τR) and let pm be the finite-budget normalizer of Finite-budget stopped-kernel measurability and event normalizer. Then 0≤p−pm=Pμ(τT<τR,τT>m)≤Pμ(τT∧τR>m). Thus the finite-budget stopped normalizer estimates the truncated event; a rate for its bias requires a tail bound for the stopping time. Separately, assume AC and let both finite-horizon Feynman–Kac models have the same finite horizon H∈N0, the same standard Borel state spaces (Xj,Xj) for 0≤j≤H, the same initial law μ0, and the same potentials Gj:Xj→[0,1] for 0≤j≤H. Let their transition kernels be Mj,M~j:Xj−1⇝Xj for 1≤j≤H, and suppose

sup⁡x∥Mj(x,⋅)−M~j(x,⋅)∥TV≤ϵj,ϵj≥0,

where ∥ν−ν′∥TV=sup⁡B∣ν(B)−ν′(B)∣. If ZHM and ZHM~ are the normalizers in the common Feynman–Kac setup of Feynman–Kac path targets and normalizers, then ∣ZHM−ZHM~∣≤∑j=1Hϵj. If a grid-detected crossing event Ah is contained in a continuous-time target event A, its probability bias is exactly P(A∖Ah); no grid-error rate follows without a separate path regularity or crossing-probability bound.

Facts & Assumptions

Given: AC, the standard Borel stopped-event model and its finite-budget probability, and two common finite-horizon Feynman–Kac models with identical initial law, state spaces, and potentials, differing only in transition kernels by the stated total-variation bounds.

[F1]

Finite-budget stopped-event kernel with a cemetery outcome: ∂ is the budget-censored outcome and κm records success only when the target is hit before return by time m.

[F2]

Measure kernel and probability kernel: A probability kernel has probability-measure rows and measurable evaluations.

[F3]

Probability measures and probability spaces: Probability measures have total mass one and are countably additive.

[F4]

Finite-budget stopped-kernel measurability and event normalizer: The finite-budget hit probability is pm=Pμ(τT<τR,τT≤m).

[F5]

Measurability of integration against a kernel: Integrating a bounded measurable function against a kernel gives a measurable function of the source state.

[F6]

Feynman–Kac path targets and normalizers: AC and a finite sequence of standard Borel state spaces, one initial law, and the ordered transition kernels and potentials define each finite-horizon Feynman–Kac normalizer.

Proof

1.1F1F3F4given

By [F4], pm=Pμ(τT<τR,τT≤m). The events increase to {τT<τR}, and the omitted part at budget m is {τT<τR,τT>m}⊆{τT∧τR>m}. Countable additivity [F3] gives the displayed difference and tail bound.

1.2F2F3F5F6givenalgebra

Replace the transition kernels one at a time and telescope the difference of the two normalizers. For the term replacing Mj, the earlier kernels and potentials define a finite measure of mass at most one, because the initial law is a probability and every potential lies in [0,1]. The remaining kernel-potential composition is a measurable function gj with 0≤gj≤1, measurable by [F5] and kernel composition. By the layer-cake identity gj(y)=∫011{gj(y)>t} dt, the total-variation definition bounds ∣Mjgj(x)−M~jgj(x)∣≤ϵj for every x. Integrating against that finite measure bounds the telescoping term by ϵj; summing yields ∑jϵj.

2.1F3givenalgebra∎

If Ah⊆A, then P(A)−P(Ah)=P(A∖Ah) by finite additivity on disjoint measurable sets. A bound on this value requires an additional estimate for the missed-crossing event; continuity of a path alone does not supply a uniform grid-rate without quantitative regularity.

TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-6-luna)Open item page →

Independent splitting estimator moments and work

Statement

Run Independent fixed-level splitting on the nested levels of Nested rare-event levels and conditional laws with N≥1 draws per level. Then E[p^]=p,Var⁡(p^)p2=∏ℓ=1L(1+1−pℓNpℓ)−1,W=N∑ℓ=1Lcℓ. In absolute error, Var⁡(p^)≤(1+14N)L−1. For fixed L, the right side is O(L/N), uniformly in the rarity of p; the relative-variance formula has factors 1/pℓ and gives no uniform relative-efficiency claim.

Facts & Assumptions

Given: Nested events and conditional laws, independent exact conditional samples at every level, N≥1, and per-draw costs cℓ>0.

[F1]

Nested rare-event levels and conditional laws: pℓ=P(Aℓ)/P(Aℓ−1)>0 and p=P(AL).

[F2]

Nested-event probabilities factor into conditional levels: p=∏ℓ=1Lpℓ.

[F3]

Independent fixed-level splitting: p^=∏ℓ=1Lp^ℓ, with p^ℓ the level-ℓ mean of N indicators sampled from πℓ−1; the level arrays are independent and W=N∑ℓcℓ.

[F4]

Unbiasedness and exact variance of the IID Monte Carlo mean: The mean of N IID Bernoulli-pℓ indicators has expectation pℓ and variance pℓ(1−pℓ)/N.

Proof

1.1F1F3F4given

Under πℓ−1, the indicator 1Aℓ is Bernoulli with success probability P(Aℓ)/P(Aℓ−1)=pℓ. Thus [F4] gives Ep^ℓ=pℓ and Ep^ℓ2=pℓ2+pℓ(1−pℓ)/N at each level.

2.1F2F3step 1.1algebra

The level arrays are independent by [F3], so Ep^=∏ℓpℓ=p by [F2], and Ep^2=∏ℓ[pℓ2+pℓ(1−pℓ)/N]. Subtracting p2=∏ℓpℓ2 gives the displayed variance and, after division by p2>0, the relative-variance formula. The work equality is the LN declared draws weighted by their level costs in [F3].

3.1step 2.1algebra

Put aℓ=pℓ2 and vℓ=pℓ(1−pℓ)/N. Then 0≤aℓ≤1 and 0≤vℓ≤1/(4N). By step 2.1 and finite product expansion, Var⁡(p^)=∏ℓ=1L(aℓ+vℓ)−∏ℓ=1Laℓ=∑∅≠S⊆{1,…,L}(∏ℓ∈Svℓ)(∏j∉Saj)≤∑∅≠S⊆{1,…,L}(14N)∣S∣=(1+14N)L−1.

4.1step 2.1step 3.1algebra∎

For fixed L, expansion of the finite binomial gives (1+1/(4N))L−1≤L4N(1+1/(4N))L−1=O(L/N). The relative formula in step 2.1 still contains (1−pℓ)/(Npℓ), so this absolute bound does not give a rarity-uniform relative bound.

TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-6-luna)Open item page →

Fixed-level full-resampling SIR splitting is unbiased

Statement

Assume AC. Use the full-resampling SIR model in Full-resampling fixed-level SIR splitting with invariant mutations with N≥1, positive level probabilities, and each Kℓ supported on Aℓ and invariant for πℓ=P( ⋅∣Aℓ). Then every prefix Feynman–Kac normalizer is Zℓ=P(Aℓ), and the product normalizer estimate p^ is unbiased: E[p^]=P(AL). This conclusion asserts no finite-N variance bound, accuracy guarantee, or uniform-in-rarity efficiency.

Facts & Assumptions

Given: The nested events, positive level probabilities, mutation kernels, full multinomial resampling, and finite particle count in Full-resampling fixed-level SIR splitting with invariant mutations.

[A1]

The Axiom of Choice: AC is inherited through the Feynman–Kac path-law and SIR unbiasedness suppliers.

[F1]

Nested rare-event levels and conditional laws: πℓ=P( ⋅∣Aℓ) and pℓ=P(Aℓ)/P(Aℓ−1)>0.

[F2]

Full-resampling fixed-level SIR splitting with invariant mutations: G1=1A1, M1 is the identity, and Gℓ+1=1Aℓ+1 follows mutation Kℓ.

[F3]

Feynman–Kac path measures satisfy the forward recursion: The next normalizer is obtained by integrating the next potential against the preceding normalized target and its transition kernel.

[F4]

The sequential particle estimator is unbiased for Feynman–Kac path integrals: Full-resampling SIR estimates each nonnegative Feynman–Kac normalizer without bias when every prefix normalizer is finite and positive.

Proof

1.1A1F1F2given

The initial law is P, G0≡1, and M1 is the identity. Therefore the first weighted normalizer is Z1=P(A1), and the normalized state law after the event potential is π1.

2.1F1F3step 1.1giveninduction

Suppose the normalized law after level ℓ is πℓ and Zℓ=P(Aℓ). The mutation Kℓ preserves πℓ, so [F3] gives Zℓ+1=Zℓ∫1Aℓ+1 dπℓ=P(Aℓ)pℓ+1=P(Aℓ+1). The normalized next law is P( ⋅∣Aℓ+1)=πℓ+1; induction proves all prefix normalizers are finite and positive.

3.1A1F2F4step 2.1given∎

Apply [F4] to the SIR model with all prefix normalizers from step 2.1 and the nonnegative terminal test 1. It yields E[p^]=ZL=P(AL). The conclusion is only unbiasedness; no second moment was estimated.

TheoremStatement: AI-adaptedProof: AI-generatedprecheck passjudge pass (gpt-6-luna)Open item page →

Fixed-level SIR has an absolute O(L/N) mean-square bound

Statement

Assume AC. Use the full-resampling fixed-level SIR model of Full-resampling fixed-level SIR splitting with invariant mutations on nested levels A0⊇⋯⊇AL, with N≥1 particles and positive finite prefixes Zp=P(Ap)>0. Its event potentials satisfy 0≤Gp≤1. Then E[p^]=P(AL),E[(p^−P(AL))2]=Var⁡(p^)≤L+14N. The bound is an absolute mean-square error bound for fixed L; it is not a relative-efficiency claim.

Facts & Assumptions

Given: The nested event model, L≥1, N≥1, full multinomial resampling, transitions Mp, and indicator potentials Gp=1Ap in Full-resampling fixed-level SIR splitting with invariant mutations.

[A1]

The Axiom of Choice: AC is inherited through the canonical Feynman–Kac, SIR, and conditional-variance suppliers.

[F1]

Nested rare-event levels and conditional laws: Zp=P(Ap)∈(0,1] for each prefix, and the target is P(AL).

[F2]

Full-resampling fixed-level SIR splitting with invariant mutations: The particle normalizer is multiplied at step p by the empirical mean of Gp; full multinomial resampling followed by Mp supplies conditionally independent proposals from the current weighted empirical law followed by Mp.

[F3]

A bounded-potential SIR update has a uniform unnormalized variance bound: Given z∈[0,1], a probability law ν, transition Mp, potential Gp∈[0,1], and test f∈[0,1], the unnormalized update has conditional mean zνMp(Gpf) and conditional variance at most z2/(4N).

[F4]

Fixed-level full-resampling SIR splitting is unbiased: Under positive prefixes and full resampling, E[p^]=ZL=P(AL).

[F5]

Feynman–Kac path targets and normalizers: The finite-horizon normalizer is the integral of the ordered product of potentials against the initial law and transition kernels.

[F6]

Unbiasedness and exact variance of the IID Monte Carlo mean: The mean of N IID square-integrable variables has variance equal to the common variance divided by N.

[F7]

Conditional variance decomposition: For square-integrable X, Var⁡(X)=E[Var⁡(X∣G)]+Var⁡(E[X∣G]).

[F8]

Moments, variance, and covariance on a probability space: Variance is the expectation of the centered square.

Proof

1.1A1F1F4given

By [F4], the estimate is unbiased for ZL=P(AL), so its mean-square error equals its variance.

1.2F1F2F5giveninduction

Set QL≡1, and recursively Qp−1=Mp(GpQp) for p=L,…,1. Since Mp is a probability kernel and 0≤Gp≤1, backward induction gives 0≤Qp≤1. By [F5], ZL=P(AL)=∫Q0 dP.

2.1A1F2F3step 1.2givenalgebra

Let ΓpN=Z^pηpN be the unnormalized weighted empirical measure after level p, and put Up=ΓpN(Qp). Conditional on the particle history through level p−1, [F2] gives IID proposals from ηp−1NMp; applying [F3] with z=Z^p−1, ν=ηp−1N, and f=Qp yields E[Up∣Fp−1]=Z^p−1ηp−1N(Mp(GpQp))=Up−1,Var⁡(Up∣Fp−1)≤Z^p−1 24N≤14N. Here the final inequality holds because Z^p−1 is a product of averages of potentials in [0,1].

3.1A1F2F6F7F8step 2.1giveninduction

The initial particles are IID from P, so U0=N−1∑i=1NQ0(X0i). Since Q02≤Q0, [F8] gives Var⁡(Q0(X0))≤EQ0−(EQ0)2≤1/4; [F6] then gives Var⁡(U0)≤1/(4N). Iterating [F7] with the conditional mean identity from step 2.1 gives Var⁡(UL)=Var⁡(U0)+∑p=1LE[Var⁡(Up∣Fp−1)]≤L+14N.

4.1F4step 1.1step 3.1algebra∎

Since QL≡1, UL=ΓLN(1)=Z^L=p^. Step 1.1 and step 3.1 prove both assertions. The constant does not involve P(AL), so no lower bound on the event probability is needed for this absolute error bound.

Boundary notes

The bound uses indicator potentials in [0,1], full multinomial resampling, and positive finite prefixes. It does not bound relative error or a family with unbounded numbers of levels.

Source notes

The cited SMC paper treats related nonasymptotic variance bounds with additional domination assumptions. The absolute (L+1)/(4N) estimate here is proved locally from the one-step lemma and bounded-potential backward recursion; the citation is context, not a claim that the source states this exact bound.

TheoremStatement: AI-adaptedProof: AI-generatedjudge pass (gpt-6-luna)Open item page →

Conditional event second moments give a finite-particle SIR relative MSE bound

Statement

Assume AC. Use the full-multinomial-resampling event model of Full-resampling fixed-level SIR splitting with invariant mutations with L≥1, N≥1 and positive prefix normalizers. Put Z=ZL=P(AL)>0, define qL=1 and qp−1=Mp(Gpqp) for 1≤p≤L, and let ηpN denote the weighted empirical state law after selection at level p. Suppose deterministic finite constants B0,…,BL≥1 satisfy P(q02)≤B0Z2 and, almost surely on {Z^p−1>0}, ηp−1NMp[(Gpqp)2]≤Bp{ηp−1NMp(Gpqp)}2,1≤p≤L. Then E[(Z^L−Z)2]≤Z2{∏p=0L(1+Bp−1N)−1}. If B0=1 and Bp≤B for 1≤p≤L, this is at most Z2[(1+(B−1)/N)L−1]. The conditions involve actual conditional event second moments under random empirical predictive laws. Bounds on squared conditional future means under the deterministic target laws alone do not imply them.

Facts & Assumptions

Given: The full-resampling event model, finite constants and conditional bounds in the Statement.

[A1]

The Axiom of Choice is inherited through the general SIR and conditional-expectation suppliers.

[F1]

Full-resampling fixed-level SIR splitting with invariant mutations and A bounded-potential SIR update has a uniform unnormalized variance bound give conditionally IID next proposals from ηp−1NMp and the identity Z^pηpN(f)=Z^p−1N−1∑iGp(Xpi)f(Xpi), including zero weights.

[F2]

Full-resampling fixed-level SIR splitting with invariant mutations specifies initial law P, initial potential G0=1, probability transitions Mp, and indicator potentials Gp.

[F3]

Unbiasedness and exact variance of the IID Monte Carlo mean gives variance of a mean as common variance divided by N. Moments, variance, and covariance on a probability space gives EH2=Var⁡(H)+(EH)2; Conditional variance decomposition supplies conditional second-moment decomposition.

[F4]

Fixed-level full-resampling SIR splitting is unbiased gives ZL=P(AL)=Z and EZ^L=Z.

Proof

1.1givenA1F1F2F3F4algebrainduction

Put Up=Z^pηpN(qp) for 0≤p≤L, and write αp=1+(Bp−1)/N. Backward induction in the defining recursion gives 0≤qp≤1; expanding its finite ordered integrals gives P(q0)=ZL=Z by [F2] and [F4]. The initial particles are IID from P, Z^0=1 and G0=1, so U0=N−1∑iq0(X0i) has mean Z and second moment Z2+[P(q02)−Z2]/N≤α0Z2. All Up lie in [0,1] by [F2], so all following conditional second moments exist.

1.2givenF1F2F3algebra

Conditional on the particle history Fp−1, put z=Z^p−1, a=ηp−1NMp(Gpqp) and b=ηp−1NMp[(Gpqp)2]. By [F1] and [F3], E[Up2∣Fp−1]=z2[a2+(b−a2)/N]. On z>0, the hypothesis b≤Bpa2 bounds this by αpz2a2=αpUp−12, using qp−1=Mp(Gpqp). If a=0 this same calculation gives zero, without division by a. If z=0, the zero-normalizer branch makes Up=Up−1=0, so the inequality also holds without a hypothesis on the fallback empirical law.

2.1step 1.1step 1.2F3F4algebrainduction∎

Taking expectations in step 1.2 and iterating over p=1,…,L yields EUL2≤∏p=1Lαp EU02≤Z2∏p=0Lαp. Since qL=1, UL=Z^L. Its mean is Z by [F4], so subtracting Z2 proves the claimed MSE bound. If B0=1 then α0=1; if every remaining Bp≤B, each remaining factor is at most 1+(B−1)/N, giving the specialization.

Source notes

The stated bound is proved here from the explicit conditional moment hypotheses, not attributed to the cited paper as an identical theorem. No new source reading is asserted. The cited nonasymptotic particle analysis is source context; its separate domination hypotheses are not inferred from these conditions.

CounterexampleConstruction: AI-generatedVerification: AI-generatedprecheck passOpen item page →

Conditional future means alone do not bound finite-particle SIR error

Statement refuted

The following proposed implication is false as stated. For every finite-level full-resampling SIR event model with positive finite prefix normalizers, define Qp,L1(xp)=E ⁣[∏j=p+1LGj(Xj)∣Xp=xp],hp,L=Qp,L1ZL/Zp,ηp=the normalized level-p law. If ∫hp,L2 dηp≤B for all p<L, the asserted finite-particle bound is E[(Z^L−ZL)2]≤ZL2[(1+B−1N)L−1].

Facts & Assumptions

Given: The two-state probability space Ω={0,1} with uniform law P; A0=A1=Ω, A2={0}; L=2; and N≥1.

[A1]

The Axiom of Choice: AC is inherited through the general SIR supplier; the finite model and its calculations require no additional choice.

[F1]

Nested rare-event levels and conditional laws: pℓ=P(Aℓ)/P(Aℓ−1) and πℓ=P( ⋅∣Aℓ).

[F2]

Full-resampling fixed-level SIR splitting with invariant mutations: The SIR potentials are event indicators, the level-one mutation is K1, and the estimator is the product of average incremental weights under full multinomial resampling.

[F3]

Sequential importance resampling for Feynman–Kac path targets: With proposal kernels equal to target transitions, incremental Radon–Nikodym weights are one; the normalizer update multiplies the previous estimate by the sample mean of the next potential.

Counterexample

1.1A1F1F2given

Here p1=1, p2=1/2, Z0=Z1=1, Z2=1/2, and η0=η1=P. Use M1 equal to the identity and choose the level-one mutation K1(x,⋅)=P(⋅). This refresh kernel is supported on A1=Ω and leaves π1=P invariant, so it satisfies the contract's mutation hypotheses.

1.2F1F2givenalgebra

For p=0, the future event probability Q0,21(x0) is 1/2 for every state because the refresh is independent of x0; for p=1, Q1,21(x1)=K11A2(x1)=1/2 for every state. Both normalizers Z2/Zp equal 1/2. Thus h0,2=h1,2=1, each ηp-second moment is 1, and B=1 satisfies the stated condition.

2.1F2F3step 1.1algebra

Since G1≡1, the first resampling weights are equal. The refresh mutation ignores the resampled ancestors, so X21,…,X2N are IID with law P. By [F3], Z^2=N−1∑i=1N1{X2i=0}, hence E[(Z^2−Z2)2]=Var⁡(Z^2)=1/(4N).

3.1step 2.1step 1.2algebra∎

With B=1, the proposed right-hand side is Z22[(1+(B−1)/N)2−1]=0, contradicting the strictly positive error 1/(4N) in step 2.1. Therefore the proposed implication is false.

RemarkRemark: Literature-sourcedProof: Not applicablejudge pass (gpt-6-luna)Open item page →

Finite-particle SIR absolute and relative error scope

Remarks

Assuming AC, under positive prefixes and full multinomial resampling, Fixed-level SIR has an absolute O(L/N) mean-square bound proves the absolute bound E[(p^−P(AL))2]≤(L+1)/(4N) for event potentials 0≤Gℓ≤1. This does not control relative error uniformly in rarity, because relative error divides by P(AL) (equivalently, relative variance divides by P(AL)2). The published Time-uniform SMC asymptotic variance under uniform weight and operator bounds concerns fixed-horizon CLT variances and does not establish a finite-particle bound. Cérou–Del Moral–Guyader's Theorem 1.5 is a distinct finite-particle result with additional potential-ratio and iterated-kernel domination hypotheses.

5 · Examples, counterexamples and false statements

None yet.

Sources