Alphabeta Math
Pipeline-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

✓ 2 results · all verified · 2 also independently AI-judged
Every result on this page is machine-checked by a proof checker and read in full and owner-audited; the judge is an additional, independent cross-model AI review of the proofs; all 2 also cleared it.

Exotic Smooth Structures and Milnor Spheres — Examples

1 · Prerequisites

2 · Summary

These examples instantiate the constructions of exotic-smooth-structures-and-milnor-spheres in the two families used throughout the page. The Gysin computation for (h,j)=(2,−1) exhibits the integral homology of S7, the bounding disk bundle W2,−1 has middle form [1] and signature 1, the standard seven-sphere is the (1,0) quaternionic Hopf sphere bundle with λ=0, and the two manifolds M1,0 and M2,−1 are homeomorphic to S7 with distinct congruence invariants; the final counterexample records that homeomorphism type does not determine smooth structure in dimension seven.

3 · Logical flowchart

4 · Definitions, theorems and proofs

None yet.

5 · Examples, counterexamples and false statements

ExampleConstruction: Literature-sourcedVerification: Literature-sourcedprecheck passjudge pass (gpt-6.1-sol)Open item page →

The standard seven-sphere as the (1,0) quaternionic Hopf sphere bundle

Example

Assume the Axiom of Choice. The (1,0) Milnor sphere bundle is diffeomorphic to the standard S7, and its disk filling has q=4, σ=1 and λ=0(mod7).

Facts & Assumptions

[F1]

The quaternionic clutching is upper-to-lower (a,v)+∼(a,av)− for (h,j)=(1,0) (The Milnor sphere and disk bundles Mh,j and Wh,j).

[F3]

The filling-independent invariant is λ=2q−σ(mod7) (The Milnor lambda invariant is well defined modulo seven).

Verification

Given: AC and the sphere S7={(q0,q1)∈H2:∣q0∣2+∣q1∣2=1}, with the projection onto right quaternionic lines.

1.1F1givenconstruct

On the base chart q0≠0, put z=q1q0−1 and write (q0,q1)=(1,z)λ/1+∣z∣2, with unit λ=q0/∣q0∣. On q1≠0, put w=q0q1−1=z−1 and write (q0,q1)=(w,1)λ′/1+∣w∣2, with λ′=q1/∣q1∣. These formulas and their inverses are smooth. The base is the one-point compactification of H; replacing the second coordinate w by wˉ gives the usual stereographic transition z↦z/∣z∣2, hence its smooth structure is that of S4. On the equator ∣z∣=1 set a=z; the fibre transition is λ′=aλ, since quaternionic multiplication has the displayed order. Thus the two hemisphere product charts of S7 glue by precisely [F1], giving M1,0≅S7.

2.1step 1.1F2F3algebra∎

By [F2], q(W1,0)=4 and σ(W1,0)=1. Therefore [F3] gives λ(M1,0)=2⋅4−1=7≡0(mod7), agreeing with the standard sphere's disk filling.

ExampleConstruction: Literature-sourcedVerification: Literature-sourcedjudge pass (gpt-6.1-sol)Open item page →

The Gysin sequence for M2,−1

Example

Assume the Axiom of Choice. For (h,j)=(2,−1) the Euler class of ξ2,−1 is e=(2−1)u=u by the class formula (Euler and first Pontryagin classes of ξh,j). The integral Gysin sequence of the oriented S3-bundle S3→M2,−1→S4 is ⋯→Hk−4(S4;Z)→⌣uHk(S4;Z)→Hk(M2,−1;Z)→Hk−3(S4;Z)→⋯ , and outside degrees 0 and 4 the base cohomology vanishes. The only nonempty multiplication map is H0(S4)=Z→⌣uH4(S4)=Z, multiplication by 1, which is an isomorphism; exactness therefore forces H0(M2,−1;Z)=H7(M2,−1;Z)=Z and Hk(M2,−1;Z)=0 for 1≤k≤6. Transferring to homology by the universal coefficient theorem and finite generation gives Hk(M2,−1;Z)=Hk(S7;Z) for every k, which is exactly the statement verified by the homology-seven-sphere theorem (Euler number ±1 implies the Milnor sphere bundle is a homology seven-sphere).

ExampleConstruction: Literature-sourcedVerification: Literature-sourcedjudge pass (gpt-6.1-sol)Open item page →

The middle form of the bounding disk bundle W2,−1

Example

Assume the Axiom of Choice. For (h,j)=(2,−1) the disk bundle W=W2,−1=D(ξ2,−1) has Euler number ε=h+j=1 and k=h−j=3. The middle form of Middle form and signature of the Milnor disk bundle is generated by the zero section S4⊆W, whose normal bundle is ξ2,−1 with Euler number 1; hence the one-by-one matrix of the form is [1] and the boundary signature is σ(W2,−1)=1. The normalized Thom evaluation ⟨U⌣x,[W,M]⟩=1 gives the same sign in the rank-one computation.

ExampleConstruction: Literature-sourcedVerification: Literature-sourcedjudge pass (gpt-6.1-sol)Open item page →

Two Milnor spheres with distinct congruence invariants

Example

Assume the Axiom of Choice and countable choice. For (h,j)=(1,0) we have h+j=1 and k=h−j=1, so λ(M1,0)=(h−j)2−1=1−1=0(mod7), while for (h,j)=(2,−1) we have h+j=1 and k=h−j=3, so λ(M2,−1)=(h−j)2−1=9−1=8≡1(mod7). The displayed values follow from The Milnor sphere M2,−1 is homeomorphic but not diffeomorphic to S7. Both manifolds are homeomorphic to S7 by The Milnor homotopy seven-spheres are homeomorphic to S7, and the invariant is preserved under orientation-preserving diffeomorphism and negated under orientation reversal by The Milnor lambda invariant is well defined modulo seven, so no diffeomorphism between them exists in either orientation. Thus M1,0 and M2,−1 are two closed smooth seven-manifolds with distinct congruence invariants.

CounterexampleConstruction: Literature-sourcedVerification: Literature-sourcedprecheck passjudge pass (gpt-6.1-sol)Open item page →

Homeomorphism type does not determine smooth structure in dimension seven

Statement refuted

False claim: two closed smooth seven-manifolds that are homeomorphic have diffeomorphic smooth structures; equivalently, the homeomorphism type of a closed seven-manifold determines its smooth structure up to diffeomorphism.

Counterexample

Given: The Axiom of Choice and countable choice, the standard sphere S7 with its standard smooth structure, and the Milnor sphere bundle M2,−1 with (h,j)=(2,−1).

1.1given

By The Milnor sphere M2,−1 is homeomorphic but not diffeomorphic to S7 the manifold M2,−1 is homeomorphic to S7.

2.1step 1.1given

The same theorem gives λ(M2,−1)≡(2−(−1))2−1=8≡1(mod7), while λ(S7)=0 because the standard sphere bounds the disk D8 with q=σ=0, and the invariant is negated by orientation reversal so its zero value is fixed by reversal.

3.1step 2.1

If the two closed smooth seven-manifolds were diffeomorphic with either orientation, the invariant of step 2.1 would agree, since an orientation-preserving diffeomorphism preserves λ and an orientation-reversing one sends λ(S7)=0 to −λ(S7)=0; the values 1 and 0 differ modulo seven, so no such diffeomorphism exists.

4.1step 3.1∎

Therefore S7 and M2,−1 are homeomorphic closed smooth seven-manifolds with non-diffeomorphic smooth structures, which refutes the statement.

Sources