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Categorical Braid Actions and Decategorification

1 · Prerequisites

2 · Summary

This page builds the Khovanov–Seidel categorical braid action for the type A algebras Am and compares it with the unreduced Burau representation. It starts with the topological layer: curves on the marked disk, minimal intersection, the half-weighted geometric intersection number I with its flow extension, the basic arcs and vertical curves with their normal form, the standard nested twists, and the bigraded intersection number Ibigr on the free abelian cover of the projectivized tangent bundle. On the algebraic side the path ideal J with J3=0 controls the finite graded projectives, so every one of them is a finite sum of shifted vertex projectives and the graded Grothendieck group G(Am) is free on their classes.

The category Cm of bounded complexes of finite graded projectives carries the twist complexes Ri=[Ui→Am] and their inverses; the page proves that they are mutually inverse, satisfy far commutativity, and satisfy the three-term braid relation, so every braid word gives an endofunctor and the assignment is a weak action in the source's sense, with no coherence claimed. The decategorification sends the twist classes to the unreduced Burau matrices after one explicit invertible change of basis C and the identification q=t, while the bigraded Hom groups of the action recover the bigraded arc intersections; specializing at q1=q2=1 gives twice the ordinary intersection number, and the two-iterate detection lemma makes the categorical action faithful. The final five-strand kernel lemma supplies an explicit nontrivial braid acting trivially in the Burau representation, so the categorical action is faithful precisely while its decategorification is not. The Axiom of Choice is declared for the braid-to-mapping-class dictionary and for the supplied representative-independence and isotopy invariance of ordinary and bigraded intersection numbers.

3 · Logical flowchart

4 · Definitions, theorems and proofs

DefinitionDefinition: Literature-sourcedProof: Not applicableOpen item page →

Curves and geometric intersection numbers on the marked disk

Definition

Let D:={ z∈C:∣z∣≤1 },∂D:={ z∈C:∣z∣=1 },D∘:=D∖∂D, the closed unit disk with its subspace topology from C≅R2 (Euclidean spheres and closed balls as subspaces of Rn, Subspace topology: the traces of the open sets, its closed sets and its bases, the continuity of the inclusion, and the characteristic property of a map into a subspace), and fix once and for all a set Δ⊂D∘ of m+1≥2 marked points with the induced topology. Fix also an orientation of D, namely the standard one. Write G:=π0Diff⁡(D,∂D;Δ) for the boundary-fixed mapping class group of the punctured disk of Boundary-fixed mapping class group of a punctured disk, in its smooth version, whose elements are isotopy classes of diffeomorphisms of D fixing ∂D pointwise and permuting Δ setwise. The cited item defines the homeomorphism version; the smooth configuration-space comparison used here is Khovanov–Seidel, Section 3b, equation (3.1), printed p. 19.

Curves. A curve in (D,Δ) is a subset c⊆D of one of the following two kinds.

  1. A simple closed curve c⊂D∘∖Δ which is essential, that is, not contractible in D∘∖Δ; it is the image of an embedding S1↪D∘∖Δ (Smooth embeddings).
  2. An arc: the image of an embedding γ ⁣:[0,1]→D (Intervals of R: the nine order-convex forms, nondegeneracy, and length, Smooth embeddings) which is transverse to ∂D, meets the boundary and the marked set exactly in its endpoints, γ−1(∂D∪Δ)={0,1}, and whose interior lies in D∘∖Δ. The unoriented image is the curve; a curve may meet Δ in one or both of its endpoints, may meet ∂D in one or both of them, and may have both endpoints in Δ, both on ∂D, or one of each. Arcs are thus embedded smooth submanifolds with boundary of D (Embedded smooth submanifolds with boundary).

Curves are unoriented: c and its image under any orientation-reversing reparametrization are the same curve. Two curves c0,c1 are isotopic, written c0≃c1, when one can be deformed into the other by an isotopy in Diff⁡(D,∂D;Δ); endpoints on ∂D may not move during an isotopy. Isotopy of curves is the orbit relation for the identity component of Diff⁡(D,∂D;Δ). The full mapping class group G acts on these isotopy classes and may carry one class to a different class.

Minimal intersection. Let c0,c1 be curves. They are in minimal intersection when (i) they intersect transversally, (ii) c0∩c1∩∂D=∅, and (iii) the following disk formulation of the bigon condition holds: for any two points z−≠z+ of c0∩c1 that do not both lie in Δ, and arcs α0⊆c0, α1⊆c1 with endpoints z−,z+ and α0∩α1={z−,z+}, the open Jordan disk K enclosed by α0∪α1 contains a marked point. Other portions of the curves may lie in K; it need not be a component of D∖(c0∪c1). Thus a transverse interior crossing contributing a removable bigon is forbidden, and a pair of arcs with common endpoints in Δ is allowed to bound a marked-free disk only when the two arcs share both endpoints.

Existence of minimal representatives. Given curves c0,c1 with c0∩c1∩∂D=∅ there is a curve c1′≃c1 in minimal intersection with c0: first perturb c1 into transverse position with distinct endpoint germs, giving finitely many intersections. If the disk condition fails, an innermost marked-free bigon can be removed by pushing c1 across it, with support near the bigon and fixing the marked points and the boundary (the bigon removal of Khovanov–Seidel, Section 3a); as each such move decreases the finite number ∣c0∩c1∣ of intersection points, the process terminates. In the case c0∩c1∩∂D≠∅ one first applies the flow extension below.

Choice scope for geometric intersection numbers. Assume AC (The Axiom of Choice) for the representative-independence, isotopy invariance and auxiliary-choice independence of I supplied by Geometric intersection numbers are isotopy invariants ↗. That supplier retains AC for its topological relative-arc inputs. The definitions of the marked disk, curves, isotopy and minimal intersection, and the finite perturbation and bigon-removal construction above do not invoke that input.

The geometric intersection number. Under this assumption, let c0,c1 be curves with c0∩c1∩∂D=∅, and choose a minimal-intersection representative c1′≃c1 of c1. The geometric intersection number is the half-integer I(c0,c1):=∣(c0∩c1′)∖Δ∣+12 ∣c0∩c1′∩Δ∣,I(c0,c1)∈12Z, except in the exceptional case that c0,c1 are simple closed curves with c0≃c1, where one sets I(c0,c1):=2. Interior intersection points count once and common marked endpoints count one half, so that in particular I(bi,bi)=1 for an arc bi joining two marked points. Isotopic arcs have the same endpoint set, since an isotopy fixes every marked point and every boundary point. The number is independent of the chosen representative c1′: this is proved in Geometric intersection numbers are isotopy invariants ↗, together with the invariance of I under isotopies of both arguments. The value is finite because two curves in minimal intersection meet in finitely many points after a small perturbation, the arcs involved being compact.

The flow extension. The definition above requires c0∩c1∩∂D=∅. For the source's I on arbitrary pairs one fixes a nonvanishing smooth vector field on ∂D which is positively oriented with respect to the fixed orientation, extends it to a smooth vector field Z on D which vanishes on Δ, and lets (ft) be the flow of Z. For t>0 small enough that the endpoints of c0 on ∂D are moved along ∂D past no endpoint of c1, set I(c0,c1):=I(c0+,c1),c0+:=ft(c0). This extension is independent of the auxiliary choices by the isotopy invariance proved in Geometric intersection numbers are isotopy invariants ↗; it depends on the orientation of D and is not symmetric, since it removes the common boundary endpoints of c0 with c1 by pushing c0 off them.

Standing conventions. Under the stated AC hypothesis, throughout this page I always denotes this half-integer valued function of isotopy classes of curves, with the exceptional value 2 for isotopic simple closed curves, and with the flow extension whenever a pair meets on ∂D. The basic arcs b0,…,bm fixed in Basic arcs, admissible curves and the standard normal form form a chain: b0 joins a fixed boundary point to the first marked point, and bi for 1≤i≤m joins the (i−1)st marked point to the ith marked point, and all values I(bj,c) quoted on this page are computed in that fixed picture, whose data are fixed there once and for all.

DefinitionDefinition: Literature-sourcedProof: Not applicablejudge pass (gpt-6.1-sol)Open item page →

The graded Grothendieck group of A_m

Definition

Fix m≥1, let Am be the Khovanov–Seidel type A algebra, and let Cm=Kb(proj⁡grAm) be the bounded homotopy category of finite graded projective left Am-modules of The bounded projective homotopy category C_m and the two shifts, with its distinguished triangles and its homological shift [1]. The graded Grothendieck group of Am is the triangulated Grothendieck group G(Am):=K0(Cm)=K0tri(Kb(proj⁡grAm)) of Grothendieck group of an essentially small triangulated category applied to the small coded presentation of The triangulated K_0 of the Khovanov–Seidel projective category: the free abelian group on the set of isomorphism classes of objects of Cm modulo the subgroup generated by the relations [Y]=[X]+[Z] for every distinguished triangle X→Y→Z→X[1] of Cm. Write [X] for the class of X.

Class rules. The definition is the triangulated one, so:

  • the cone triangle X⊕Y→Y→X[1]→X[1]⊕Y[1] of a biproduct gives [X⊕Y]=[X]+[Y];
  • the rotated triangle X→0→X[1]→X[1] gives [X[1]]=−[X], the statement of Homological and internal shifts on K_0(C_m);
  • the internal shift {1}, which is an exact automorphism of Cm distinct from [1], makes G(Am) into a module over Z[q,q−1] with [X{r}]=qr[X], again by Homological and internal shifts on K_0(C_m).

The two shifts are never identified: [1] is homological and contributes a sign −1, {1} is internal and contributes a unit q.

Comparison with perfect complexes. The composite Θ ⁣:Cm=Kb(proj⁡grAm)⟶Db(Am-mod) of inclusion and localization is exact, full, faithful and essentially surjective by The bounded projective comparison for the derived category; the graded clause of Triangle K0 of perfect complexes equals split K0 of finite projectives identifies the target's triangulated Grothendieck group with K0split of the finite graded projectives. Consequently G(Am) is canonically isomorphic to the Grothendieck group of the graded perfect complexes of Perfect complexes over a ring and its graded version on the bounded projective model, and [X] corresponds to the Euler characteristic ∑n(−1)n[Pn] of any bounded finite graded projective complex representing X.

Scope and warnings. This is emphatically the triangulated K0 of projective complexes and not the short-exact G0 of the abelian category of all finitely generated graded Am-modules, and no identification of the two is claimed; G0 may a priori be a quotient of G(Am). No structure theorem for finite-dimensional algebras over a field is applied to the integral algebra Am. The freeness of G(Am) on the shifted vertex-projective classes is not asserted here: it is the content of The graded Grothendieck group is free on the vertex-projective classes, which uses the classification of finite graded projectives and the comparison above.

Notation used below. Since the internal shift is an automorphism, write qr[Pi]:=[Pi{r}], so that G(Am) is generated as a Z[q,q−1]-module by the classes of the vertex projectives P0,…,Pm; the next lemma on this page shows these generate freely.

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The complex of a braid word

Definition

Fix m≥1 and let Ri,Ri−1 be the twist complexes of The twist complexes R_i and R_i^{-1}, built from βi,γi of The Khovanov–Seidel bimodule maps β_i and γ_i and acting on Cm=Kb(proj⁡grAm). Fix a word σ=τ1τ2⋯τk,τℓ∈{σi±1:1≤i≤m}, in the Artin generators and their inverses, and put Rσi:=Ri,Rσi−1:=Ri−1,R1:=Am, the last being the diagonal bimodule Am concentrated in homological degree 0. The complex of the word σ is the iterated signed totalization Rσ:=Rτ1⊗AmRτ2⊗Am⋯⊗AmRτk of Signed totalization of graded A_m-bimodule actions, and Rσ also denotes the endofunctor Rσ ⁣:Cm→Cm,M↦Rσ⊗AmM.

Claims. (i) Rσ is a bounded complex of graded (Am,Am)-bimodules each of whose terms is finitely generated graded projective as a left Am-module and as a right Am-module; (ii) consequently the functor Rσ⊗Am− is an exact additive endofunctor of Cm carrying distinguished triangles to distinguished triangles and agreeing with the derived tensor product through the identity replacements, by Bounded two-sided projective bimodule complexes act on C_m. These two claims are verified below. The definition fixes the complex attached to the chosen word; that different words for the same braid give isomorphic functors is the content of the weak action theorem below and is not asserted here.

Facts & Assumptions

Given: An integer m≥1, the algebra Am, the twist complexes Ri,Ri−1 of Cm-bimodules, a word σ=τ1⋯τk in σi±1, and the class P of bounded complexes of graded (Am,Am)-bimodules whose every term is finitely generated graded projective as a left Am-module and as a right Am-module.

[L1]

A graded left Am-module is finite graded projective exactly when it is a degree-zero direct summand of a finite direct sum of internal shifts Am{r1}⊕⋯⊕Am{rn}; the same characterization holds for graded right Am-modules with the shifts acting on the other side; a direct summand of a projective object is projective, and a finite direct sum of finite graded projectives is finite graded projective (Finite graded projectives are finite shifted-free summands, A direct summand of a projective is projective).

[L2]

For an (Am,Am)-bimodule M and an integer r there is a canonical degree-zero isomorphism of graded (Am,Am)-bimodules M⊗AmAm{r}≅M{r} and, symmetrically, Am{r}⊗AmN≅N{r} for a graded left Am-module N, both given on elementary tensors by multiplication (Graded associativity, units, and internal-shift tensor isomorphisms).

[L3]

The signed totalization (R⊗AmS)n=⨁p+q=nRp⊗AmSq of two bounded complexes of graded bimodules is a bounded complex of graded bimodules with d(r⊗s)=dRr⊗s+(−1)pr⊗dSs; the construction is functorial and associative up to canonical degree-zero isomorphism (Signed totalization of graded A_m-bimodule actions).

[L4]

Ri and Ri−1 are bounded complexes of graded (Am,Am)-bimodules with degree-zero differentials, and every term of either is finitely generated graded projective on the left and on the right (The twist complexes R_i and R_i^{-1}).

[L5]

For a bounded complex R of graded (Am,Am)-bimodules whose every term is finitely generated graded projective as a left and as a right Am-module, the functor R⊗Am− is a well-defined additive exact endofunctor of Cm sending distinguished triangles to distinguished triangles, and it agrees with the derived tensor product through the identity replacements (Bounded two-sided projective bimodule complexes act on C_m).

Proof

technique · direct
1.1L1L2

Tensor products of two-sided finite graded projectives are again two-sided finite graded projectives. Let M,N be graded (Am,Am)-bimodules finite graded projective on each side. To prove left projectivity, split N as a left module by degree-zero left Am-linear maps i:N→⨁jAm{rj} and p:⨁jAm{rj}→N with pi=1. The maps 1M⊗i and 1M⊗p are well-defined over Am and left Am-linear for the action on M; they exhibit M⊗AmN as a left-module summand of ⨁jM{rj} by [L2]. Thus it is finite graded projective on the left by [L1]. To prove right projectivity, split M as a right module and apply −⊗AmN; the resulting right-linear maps exhibit the tensor product as a summand of finitely many shifts of the right-projective module N. No splitting is assumed bimodule-linear, and each is tensored on its valid balanced side.

2.1step 1.1L3

The totalization of two complexes in P lies in P, and is bounded. Let R,S∈P. Every term of R⊗AmS is a finite direct sum of modules Rp⊗AmSq with p+q=n; each summand is two-sided finite graded projective by step 1.1, and a finite direct sum of such is again such by [L1]. By [L3] the totalization is a complex of graded bimodules, and it is bounded because only finitely many pairs (p,q) with p+q=n occur and R,S each have finitely many nonzero terms.

3.1step 2.1L3L4

The claim for k≤1, and the induction step. For k=0 the complex R1=Am is a single copy of the diagonal bimodule in degree 0, which is finite graded projective on both sides, so R1∈P. For k=1 the factors are Ri or Ri−1, which lie in P by [L4]; and in general, if Rτ1⊗⋯⊗Rτℓ∈P then tensoring with the next factor, which lies in P by [L4], stays in P by step 2.1; hence by induction on k the complex Rσ lies in P for every word. Associativity of the iterated totalization up to canonical isomorphism, which is what makes the notation Rτ1⊗⋯⊗Rτk unambiguous, is part of [L3].

4.1step 3.1L5

The functor properties. By step 3.1 the complex Rσ satisfies the hypothesis of [L5], so Rσ⊗Am− is a well-defined additive endofunctor of Cm, exact for the triangulations and carrying distinguished triangles to distinguished triangles, and it agrees with the derived tensor product through the identity replacements.

5.1step 3.1step 4.1∎

Conclusion and scope. The complex Rσ attached to a word σ is a bounded complex of graded (Am,Am)-bimodules with two-sided finite graded projective terms by step 3.1, and its action on Cm is an exact triangulated endofunctor agreeing with derived tensor by step 4.1. The construction depends on the chosen word: nothing here compares Rσ for different words representing the same braid, and no choice principle is used, the tensor products and shifts being explicit and finite.

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The Khovanov-Seidel path ideal

Definition

Fix m≥1 and let Am be the Khovanov–Seidel type A algebra of Khovanov–Seidel type A algebra, with its internal grading deg⁡ei=0,deg⁡(i∣i+1)=0,deg⁡(i+1∣i)=1 on vertices and arrows, extended to paths additively, and with vertex idempotents e0,…,em and unit 1=e0+⋯+em. Let J⊆Am be the two-sided ideal generated by the classes of all arrows (i∣i±1) (The ideal generated by a subset and principal ideals); it is the smallest two-sided ideal containing every arrow, and it is computed in the proof below.

Claims. J is homogeneous for the internal degree; J is spanned as a Z-module by the classes of all paths of length at least one, and J2 is spanned by the returns (i∣i−1∣i), so that J3=0; and the quotient ring of The quotient ring R/I with (r+I)(s+I)=rs+I satisfies Am/J≅Zm+1 through the vertex idempotents, the isomorphism sending the class of ei to the i-th standard basis vector. In particular the quotient module Am/J≅Zm+1 is concentrated on the vertex idempotents.

Facts & Assumptions

Given: An integer m≥1, the graded algebra Am with vertex idempotents e0,…,em, arrows (i∣i±1) and returns (i∣i−1∣i), and the two-sided ideal J generated by the arrows.

[L1]

The algebra Am has the Z-basis of 4m+1 classes e0,…,em, (0∣1),…,(m−1∣m), (1∣0),…,(m∣m−1), (1∣0∣1),…,(m∣m−1∣m); multiplication is left-to-right concatenation of paths, defined when the endpoint of the first equals the start of the second and zero otherwise; the relations make (i∣i−1∣i)=(i∣i+1∣i) for 0<i<m and make every path of length at least three vanish in Am; the vertices are mutually orthogonal idempotents with sum 1 (The 4m+1 path basis, Khovanov–Seidel type A algebra).

[L2]

An element of Am is homogeneous when it is a Z-linear combination of basis paths of one degree; each vertex and each up-arrow has degree 0, each down-arrow and each return has degree 1, and the product of homogeneous elements is homogeneous of the sum of the degrees (Khovanov–Seidel type A algebra).

[L3]

J is the intersection of all two-sided ideals of Am containing all arrows; it contains every arrow, is closed under addition and under left and right multiplication by elements of Am, and is generated by homogeneous elements (The ideal generated by a subset and principal ideals).

[L4]

The elements of Am/J are additive cosets, with [x]+[y]=[x+y] and [x][y]=[xy] (The quotient ring R/I with (r+I)(s+I)=rs+I); hence its projection π(x)=[x] preserves addition and multiplication, and [1] is its unit.

Proof

technique · direct
1.1L1L2L3

J is spanned by the paths of length at least one, and is homogeneous. Write B≥1 for the set of basis elements of [L1] that are arrows or returns, and P≥1 for the Z-span of all paths of length at least one. Every generator of J lies in P≥1, and P≥1 is closed under left and right multiplication by Am: the product of a path of length at least one with any path is either 0 or a concatenation of length at least one, and multiplication is bilinear; hence J⊆P≥1 by minimality of the generated ideal. Conversely every path of length at least one is a product of arrows, hence lies in J because a product of arrows belongs to J and J is closed under multiplication; so P≥1⊆J, and P≥1=J. Every basis element of B≥1 is homogeneous by [L2], so J, the span of the basis elements of B≥1, is homogeneous: it is the direct sum of its intersections with the homogeneous components of Am.

2.1step 1.1L1

J2 is spanned by the returns, and J3=0. By step 1.1 it suffices to compute products of two basis elements of B≥1 and of three such elements. A concatenation of two paths of length at least one has length at least two, and by [L1] the only nonzero classes of length at least two in Am are the returns (i∣i−1∣i) for 1≤i≤m (equal to (i∣i+1∣i) only for i<m), each of which is a product (i∣i−1)(i−1∣i) of two arrows; hence J2 is spanned by the returns. A concatenation of three paths of length at least one is a path of length at least three, which vanishes in Am by [L1], so J3=0.

3.1step 2.1L1L4

The quotient is Zm+1. The assignment ψ0(ei):=ui for the standard basis vectors u0,…,um of Zm+1 and ψ0(b):=0 for every non-vertex basis element b of [L1] is a unital ring homomorphism: on the multiplication table of [L1] one checks that a product of two basis elements, when nonzero, is either a vertex (and the product of the corresponding idempotents is δijei, matching uiuj=δijui) or a non-vertex basis path (whose image and whose factors' product of images are both 0 unless both factors are vertices), and paths of length at least three vanish on both sides; bilinearity extends the check to Am. Since ψ0 kills every arrow, it kills J, define ψ([x]):=ψ0(x). This is well defined: if [x]=[y], then x−y∈J and ψ0(x)−ψ0(y)=ψ0(x−y)=0. The coset formulas [L4] show that ψ preserves addition and multiplication and sends [1] to 1, so it is a unital ring homomorphism with ψπ=ψ0. Let φ:Zm+1→Am/J, φ(a0,…,am):=∑iai[ei], where [ei]=π(ei); the classes [ei] are orthogonal idempotents with ∑i[ei]=1 because π is a unital ring homomorphism, so φ is a unital ring homomorphism, and ψφ=id since ψ([ei])=ui. Conversely φψ([b])=[b] for every basis element b of [L1]: for a vertex this is immediate, and for a non-vertex element both sides are 0 because b∈J by step 1.1; hence φψ=idAm/J and Am/J≅Zm+1.

4.1step 1.1step 2.1step 3.1∎

Conclusion. The ideal J generated by the arrows is homogeneous and consists of the paths of length at least one, its square is spanned by the returns and its cube vanishes, and the quotient is Zm+1 on the vertex idempotents, all by steps 1.1–3.1. No choice principle is used.

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Weak action of a group on a category

Definition

Let G be a group with unit 1 (Left group actions, transitive actions, and faithful actions) and Q a category (Category, object, morphism, domain, codomain, identity, composition, and hom-collection). A weak action of G on Q is a choice of a functor Fg ⁣:Q→Q(g∈G) for every element of G (Covariant functor, identity functor, composite functor, and contravariant functor) such that

  1. F1 is the identity functor of Q, and
  2. for all f,g∈G the functors Ffg and FfFg are isomorphic, that is, there exists a natural isomorphism between them (Natural isomorphism).

No isomorphisms Ffg≅FfFg are chosen, they are not required to be compatible with the associativity of G, and no pentagon is imposed: the definition records only that such isomorphisms exist. This is Definition 2.6 of the source, stated there for a group and a category with the same comments.

Normalized coherent actions. In the identity-unit normalization, the action is coherent, or a genuine 2-action, when isomorphisms μf,g ⁣:FfFg⟶Ffg(f,g∈G) are chosen so that μ1,g=idFg, μf,1=idFf and the two composites FfFgFh→ μf,gFh FfgFh→ μfg,h Ffgh,FfFgFh→ Ffμg,h FfFgh→ μf,gh Ffgh agree, the associativity (pentagon) condition. This is the normalized special case of a strong monoidal action. In the general definition, the unit constraint is a chosen natural isomorphism u:F1⇒Id⁡Q; when F1=Id⁡Q, the unit triangles read μf,1=Ffu and μ1,g=uFg, and need not be identity maps. No strictification to the normalized case is asserted. A coherent action with F1=Id⁡Q is in particular a weak action after forgetting its chosen compositors. For a general coherent action with only u:F1⇒Id⁡Q, first replace the identity component of the functor assignment by Id⁡Q; the unit isomorphism and the compositors then supply the pairwise isomorphisms required by the weak definition. This replacement asserts no strictification of the coherence data.

Standing convention. The whole page uses "weak" in the sense of this definition and never silently substitutes a coherent action: whenever a compositor or pentagon argument would be needed, the weakness of the available data is stated.

Terminology. The functors Fg are the components of the weak action, the assignment g↦Fg is its functor assignment, and a weak action is determined by the functor assignment with its prescribed identity component together with the existence of the pairwise isomorphisms in condition 2. We do not distinguish two weak actions that are naturally isomorphic componentwise.

Remarks

Arbitrarily chosen pairwise isomorphisms of a weak action need not satisfy coherence: the companion-page counterexample Weak actions do not supply pentagon coherence data ↗ exhibits a weak action with chosen pairwise isomorphisms violating the pentagon. That example also admits identity compositors satisfying coherence, so it does not assert that no coherent choice exists.

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Far commutativity of the generator complexes

Statement

Fix m≥1 and let Ri and Ri−1 be the twist complexes of graded (Am,Am)-bimodules of The twist complexes R_i and R_i^{-1}, with Ri=[Ui→βiAm] having Ui in homological degree −1 and Am in degree 0. If ∣i−j∣>1 then there is an isomorphism of complexes of graded (Am,Am)-bimodules Ri⊗AmRj  ≅  Rj⊗AmRi, and consequently an isomorphism of endofunctors of Cm RiRj  ≅  RjRi.

Facts & Assumptions

Given: An integer m≥1, indices i,j with ∣i−j∣>1, the two-term complexes Ri=[Ui→βiAm], Rj=[Uj→βjAm] with Ui,Uj in homological degree −1 and the diagonal bimodule Am in degree 0 in both, and the totalization of Signed totalization of graded A_m-bimodule actions.

[L1]

Ui=Pi⊗ZiP and βi:Ui→Am is the degree-zero bimodule map with βi(ei⊗ei)=ei; both Ri and Rj are bounded complexes of graded (Am,Am)-bimodules with degree-zero differentials, the differential of Ri being βi (The twist complexes R_i and R_i^{-1}, The Khovanov–Seidel bimodule maps β_i and γ_i).

[L2]

If ∣i−j∣>1 then Ui⊗AmUj=0 as a graded (Am,Am)-bimodule (Corner computations: the U_i satisfy the Temperley-Lieb relations).

[L3]

For bounded complexes R,S of graded (Am,Am)-bimodules the totalization has (R⊗AmS)n=⨁p+q=nRp⊗AmSq with d(r⊗s)=dRr⊗s+(−1)pr⊗dSs; it is a bounded complex, functorial in both variables, and its terms carry the bimodule structure inherited from the two factors (Signed totalization of graded A_m-bimodule actions).

[L4]

For every graded (Am,Am)-bimodule M the tensor-unit maps Am⊗AmM→M, a⊗m↦am, and M⊗AmAm→M, m⊗a↦ma, are degree-zero isomorphisms of graded bimodules (Graded associativity, units, and internal-shift tensor isomorphisms).

[L5]

A bounded complex of graded (Am,Am)-bimodules with two-sided finite graded projective terms acts on Cm by an exact triangulated endofunctor, and an isomorphism of such complexes induces a natural isomorphism of the associated functors (Bounded two-sided projective bimodule complexes act on C_m).

Proof

technique · direct
1.1L1L2L3L4

The two totalizations are the same complex with the two factors interchanged. By [L3] the degree −2 term of Ri⊗AmRj is Ui⊗AmUj, which is 0 by [L2]; its degree −1 term is (Ui⊗AmAm)⊕(Am⊗AmUj) and its degree 0 term is Am⊗AmAm, with nothing else. Using the unit isomorphisms of [L4] to identify Ui⊗AmAm≅Ui, Am⊗AmUj≅Uj and Am⊗AmAm≅Am, the differential of [L3] reads (u,v)↦βi(u)+βj(v): on u⊗1 the Koszul sign multiplies the zero second summand only, and on 1⊗v the first summand is zero and the sign is (−1)0=1. Hence Ri⊗AmRj is isomorphic to the two-term complex Cij=[Ui⊕Uj→ (βi,βj) Am] with Ui⊕Uj in degree −1. Symmetrically Rj⊗AmRi≅Cji=[Uj⊕Ui→(βj,βi)Am].

2.1step 1.1L1

The flip is a chain isomorphism. The flip s:Ui⊕Uj→Uj⊕Ui, s(u,v):=(v,u), is a degree-zero isomorphism of graded bimodules; together with the identity of Am it defines a degree-zero isomorphism of graded bimodule complexes Cij→Cji. It commutes with the differentials because (βj,βi)∘s=(βi(u)+βj(v)) on (u,v) equals the composite s after (βi,βj), the target being Am in both cases and no sign entering the degree-zero component.

3.1step 1.1step 2.1

Conclusion for the complexes. The composite of the identifications of step 1.1 with the flip of step 2.1 is an isomorphism of complexes of graded (Am,Am)-bimodules Ri⊗AmRj≅Rj⊗AmRi.

4.1step 3.1L5

Conclusion for the functors. Both Ri⊗AmRj and Rj⊗AmRi are bounded complexes with two-sided finite graded projective terms, since the terms Am, Ui⊕Uj, Uj⊕Ui are finite graded projective on both sides; by [L5] the isomorphism of step 3.1 induces a natural isomorphism of the endofunctors M↦(Ri⊗AmRj)⊗AmM and M↦(Rj⊗AmRi)⊗AmM of Cm. Composing with the canonical associativity identifications (Ri⊗AmRj)⊗AmM≅Ri⊗Am(Rj⊗AmM) and (Rj⊗AmRi)⊗AmM≅Rj⊗Am(Ri⊗AmM) gives the asserted natural isomorphism RiRj≅RjRi.

5.1step 3.1step 4.1L1∎

Conclusion. For ∣i−j∣>1 the vanishing Ui⊗AmUj=0 collapses both tensor complexes to the two-term complexes Cij, Cji, the flip identifies them, and the induced natural isomorphism of functors is RiRj≅RjRi, both sides being the two-term complexes of [L1]. No choice principle is used.

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The generator complexes are mutually inverse

Statement

Fix m≥1 and let Ri=[Ui→βiAm] and Ri−1=[Am→γiUi{−1}] be the positive and negative twist complexes of The twist complexes R_i and R_i^{-1}, with Ui in homological degree −1 and Am in degree 0 in the first complex and Am in degree 0 and Ui{−1} in degree 1 in the second. Then for every 1≤i≤m there are homotopy equivalences of complexes of graded (Am,Am)-bimodules Ri⊗AmRi−1  ≃  Am  ≃  Ri−1⊗AmRi, where Am denotes the diagonal bimodule concentrated in homological degree 0; they become isomorphisms in Cm and induce isomorphisms of endofunctors RiRi−1≅Id⁡Cm≅Ri−1Ri. In particular Ri−1 is a two-sided inverse of Ri on Cm, and both are equivalences of Cm.

Facts & Assumptions

Given: An integer m≥1, the algebra Am with corner bases, the bimodules Ui=Pi⊗ZiP and maps βi,γi, and the complexes Ri,Ri−1 with the totalization of Signed totalization of graded A_m-bimodule actions.

[L1]

βi(ei⊗ei)=ei and γi(1)=wi with wi=(i−1∣i)⊗(i∣i−1)+(i+1∣i)⊗(i∣i+1)+(i)⊗(i∣i−1∣i)+(i∣i−1∣i)⊗(i), the term (i+1∣i)⊗(i∣i+1) being omitted for i=m; both are degree-zero maps of graded (Am,Am)-bimodules (The Khovanov–Seidel bimodule maps β_i and γ_i).

[L2]

Ri=[Ui→βiAm] and Ri−1=[Am→γiUi{−1}] are bounded complexes of graded (Am,Am)-bimodules with degree-zero differentials whose terms are finitely generated graded projective on both sides; their actions on Cm are exact endofunctors agreeing with derived tensor (The twist complexes R_i and R_i^{-1}, Bounded two-sided projective bimodule complexes act on C_m).

[L3]

The corner eiAmei has Z-basis ei in degree 0 and the return (i∣i−1∣i) in degree 1, and eiAmei±1 is free of rank one on the arrow (i∣i±1) whenever the neighboring index lies in {0,…,m}; every path of length at least three is zero in Am and (i∣i−1∣i)=(i∣i+1∣i) when i<m (The 4m+1 path basis).

[L4]

iP⊗AmPi≅eiAmei as graded abelian groups under y⊗x↦yx, and the balanced tensor is associative and unital, with M⊗AmAm≅M and Am⊗AmN≅N naturally in the graded variables (Graded associativity, units, and internal-shift tensor isomorphisms, The two-sided projective bimodules U_i and their tensor functors).

[L5]

The totalization (R⊗AmS)n=⨁p+q=nRp⊗AmSq of two bounded complexes of graded bimodules is a bounded complex with d(r⊗s)=dRr⊗s+(−1)pr⊗dSs, its square-zero condition holding automatically, and it is functorial and associative up to canonical degree-zero isomorphism (Signed totalization of graded A_m-bimodule actions).

[L6]

If a two-term cochain complex in an additive category has terms U,V in adjacent degrees and differential φ:U→V an isomorphism, then it is contractible, with contracting homotopy φ−1 in the upper degree (Gaussian elimination splits a contractible two-term complex, An invertible cochain differential block and its candidate reduction, Complexes, homotopies and contractibility in an additive category).

Proof

technique · direct
1.1L3L4L5

The middle corner and the module Q. By [L3] and the tensor-unit and associativity isomorphisms of [L4] the graded abelian group Q:=iP⊗AmPi is free with basis u1=ei⊗ei in degree 0 and u2=(i∣i−1∣i)⊗ei in degree 1, so that Q=Zu1⊕Zu2; by [L5] and [L4] the terms of the totalization N:=Ri⊗AmRi−1 are N−1≅Ui, N0≅Am⊕(Pi⊗ZQ⊗ZiP{−1}) and N1≅Ui{−1}.

2.1L5step 1.1L1

The two maps of the source's square. Define the Am-bimodule maps τ ⁣:Ui→Pi⊗ZQ⊗ZiP{−1} and δ ⁣:Pi⊗ZQ⊗ZiP{−1}→Ui{−1} by τ(x⊗y):=x⊗u1⊗(i∣i−1∣i)y+x⊗u2⊗y, δ(x⊗u1⊗y):=x⊗y and δ(x⊗u2⊗y):=x(i∣i−1∣i)⊗y; both are bilinear because multiplication is, and both are degree zero: in the shifted middle object the u1 and u2 components have degrees deg⁡x+deg⁡y−1 and deg⁡x+deg⁡y, respectively, matching the degrees of their images x⊗y and x(i∣i−1∣i)⊗y in Ui{−1}. Each summand in τ(x⊗y) has degree deg⁡x+deg⁡y; the natural balanced identification gives differentials (βi,−τ) and (γi,δ). Negating the middle Pi⊗Q⊗iP{−1} coordinate gives the source’s signed chart, in which the differentials read ∂−1=βi+τ, ∂−1(u)=(βi(u),τ(u)), and ∂0=(γi,−δ), ∂0(a,z)=γi(a)−δ(z), the source's anticommutative square of Section 2 with the sign on δ, and ∂0∂−1=0 is the automatic square-zero condition of the totalization [L5].

3.1step 2.1

The splitting of N0. Let ξ(a) be the image of γi(a)=∑jxj⊗yj under x⊗y↦x⊗u1⊗y, so that δξ(a)=∑jxj⊗yj=γi(a) because δ removes the middle u1; write W:=Pi⊗ZZu1⊗ZiP{−1} for the u1-component and define Ψ(a,w,u):=(a+βi(u), ξ(a)+w+τ(u)). The map Ψ ⁣:Am⊕W⊕Ui→N0 is an isomorphism of graded bimodules: its inverse sends (a′,z) to u:=τ2−1(z2), a:=a′−βi(u), w:=z1−ξ1(a)−τ1(u), where z=z1+z2 decomposes along the u1- and u2-components, τ2 denotes the injective u2-component x⊗y↦x⊗u2⊗y of τ, and the subscript 1 denotes the u1-component; these four maps are well defined and degree zero. Consequently N0 is the direct sum of ∂−1(Ui)={(βi(u),τ(u))}, the graph T00:={(a,ξ(a)):a∈Am} and the u1-component T10:={(0,w):w∈W}, while N−1=Ui and N1=Ui{−1}.

4.1step 2.1step 3.1

N splits as a direct sum of three subcomplexes. Put T−1:=[Ui→∂−1∂−1(Ui)], T0:={(a,ξ(a)):a∈Am} concentrated in degree 0, and T1:=[W→−δUi{−1}], with differentials the restrictions of ∂−1 and ∂0; these are subcomplexes of N because ∂0∂−1=0 on Ui by step 2.1, ∂0(a,ξ(a))=γi(a)−δξ(a)=0 by step 3.1 and ∂0(0,w)=−δ(w), and by the direct sum decomposition of step 3.1 the objects of N are the degreewise direct sums Nj=T−1j⊕T0j⊕T1j. Hence N=T−1⊕T0⊕T1 as complexes of graded bimodules, and a↦(a,ξ(a)) identifies T0 with the diagonal bimodule Am concentrated in degree 0.

5.1L6step 4.1

The two outer summands are contractible. The restriction ∂−1:Ui→∂−1(Ui) is surjective by construction and injective because τ is injective (its u2-component τ2 alone is already injective, as observed in step 3.1); hence it is an isomorphism, and T−1 is a two-term complex with invertible differential, contractible by [L6]. The restriction −δ:W→Ui{−1} is an isomorphism, with inverse x⊗y↦−x⊗u1⊗y, so T1 is contractible by [L6] as well.

6.1L2step 4.1step 5.1

The first homotopy equivalence. By steps 4.1 and 5.1 the complex N is the direct sum of T0≅Am with two contractible complexes; a finite direct sum of contractible complexes is contractible, the contracting homotopy of a biproduct being the biproduct of the given homotopies, so the projection N→T0≅Am and the inclusion T0→N are inverse homotopy equivalences. This proves Ri⊗AmRi−1≃Am, and since the action of a complex with two-sided finite graded projective terms on Cm is well defined on homotopy classes [L2], these maps induce natural isomorphisms RiRi−1≅Id⁡Cm.

7.1L5L1L3L4L6step 3.1step 6.1algebra

The opposite order. Write ci=(i∣i−1∣i). The middle corner in N′=Ri−1⊗AmRi is again Q=iP⊗AmPi, not the oppositely typed tensor Pi⊗AmiP. Its terms are Ui in degree −1, Am⊕(Pi⊗Q⊗iP{−1}) in degree 0, and Ui{−1} in degree 1. Define τ′(x⊗y)=xci⊗u1⊗y+x⊗u2⊗y, δ′(x⊗u1⊗y)=x⊗y,δ′(x⊗u2⊗y)=x⊗ciy. These formulas are obtained by inserting γi on the left and multiplying on the right in the tensor totalization; in particular ∂′−1=(βi,τ′) and ∂′0=(γi,−δ′). They are bimodule-linear and homogeneous, and their composite is zero by [L5]. The u2-component of τ′ is the identity under its shift identification, while δ′ is the identity from the u1-component to Ui{−1}. With ξ′ given by inserting u1 in γi(a), one has δ′ξ′=γi. Hence the same explicit coordinate map Ψ′(a,w,u)=(a+βi(u),ξ′(a)+w+τ′(u)) and its componentwise inverse from step 3.1 split N′ into its diagonal Am and two identity-pivot pairs. Their inverse differentials are the contracting homotopies, proving Ri−1⊗AmRi≃Am. Applying the action as in step 6.1 gives the opposite functor identity.

8.1step 6.1step 7.1∎

Conclusion. The complexes Ri and Ri−1 are mutually inverse up to the homotopy equivalences of steps 6.1 and 7.1, hence are inverse isomorphisms in Cm and induce two-sided inverse functor isomorphisms on Cm; in particular both are equivalences of Cm. No choice principle is used, all the identifications being explicit finite formulas.

DefinitionDefinition: Literature-sourcedProof: Not applicableOpen item page →

Basic arcs, admissible curves and the standard normal form

Definition

Let (D,Δ) be the marked disk of Curves and geometric intersection numbers on the marked disk with m+1≥2 marked points, and let G=π0Diff⁡(D,∂D;Δ) be its boundary-fixed mapping class group (Boundary-fixed mapping class group of a punctured disk). Write D:=Diff⁡(D,∂D;Δ) for the actual diffeomorphism group, so G=π0(D). Actual curve images below use members of D, and mapping classes act on curve-isotopy classes. All curves below are curves in (D,Δ) in the sense of that definition.

Basic sets. Fix the boundary endpoint d of the standard drawn chain of source Figure 2, and label its marked points q0,…,qm along that chain. The standard basic arcs are b0 from d to q0 and bi from qi−1 to qi for 1≤i≤m. Their interiors are pairwise disjoint and avoid Δ∪∂D; consecutive arcs meet only at their common marked endpoint, and all other arcs are disjoint. A basic set of curves is an actual image of this fixed chain under a member of D. The marked labels are transported with it. Under AC, the preferred identification of the Artin-presentation group Bm+1 with G sends σi to the half twist about bi, 1≤i≤m. Presentation completeness is supplied by The Artin presentation is complete for geometric braids; the geometric-to-topological comparison is Braid group as boundary-fixed punctured-disk mapping classes. For the smooth group G used here, use the smooth configuration-space comparison and generator convention of Khovanov–Seidel, Section 3b, equation (3.1) and Figure 6, printed pp. 19–20 (The Axiom of Choice, The elementary geometric half twist, its support disc, and its opposite). Admissible curves. A curve c is admissible if c=f(bi) for some f∈D and some i, that is, if it lies in the D-orbit of the actual basic set. The endpoints of an admissible curve lie in Δ∪(b0∩∂D), and conversely every arc with such endpoints is admissible; G acts on the set of isotopy classes of admissible curves.

Vertical curves and normal form. Fix arcs d0,…,dm as in Figure 11, pairwise disjoint embedded arcs dividing D into regions D0,D1,…,Dm+1 in that order, chosen so that dk meets the spine in the prescribed way of the standard picture. An admissible curve c is in normal form if it has minimal intersection with every dk. Every admissible curve can be isotoped into normal form, and the normal form is unique up to isotopy preserving each dk setwise and fixing the marked points and ∂D (the source's Lemma 3.15); consequently the combinatorial data below are invariants of the isotopy class of c.

Crossings, segments, strings. For an admissible curve c in normal form put cr⁡(c):=c∩(d0∪⋯∪dm), the set of crossings of c; a crossing lying on dk is a k-crossing. The connected components of c∩Dk are the segments of c; a segment is essential when both its endpoints are crossings, and inessential otherwise (it then ends at a point of Δ∪∂D). The connected components of c∩(Dk∪Dk+1), for 0≤k≤m with Dm+1 interpreted as the region across dm in the standard picture, are the k-strings of c; write st⁡(c,k) for their set. By the uniqueness of normal form, the number and relative position of the segments and of the strings are invariants of c.

String types. Up to isotopy of Dk∪Dk+1 fixing the boundary arcs and the marked points, each k-string belongs to one of the following families or exceptional types. For 1≤k<m there are five infinite families Iu, IIu, IIu′, IIIu, IIIu′(u∈Z) and five exceptional types IV,IV′,V,V′,VI (Figures 15-16); the type Iu+1 is obtained from Iu by applying the half twist about bk, and likewise for the other families. For k=m the list consists of the two families IIu,IIIu and the two exceptional types V,VI (Figure 17), and for k=0 of the five exceptional types VII,VIII,IX,X,XI (Figure 18). The members u=0 of the families and the exceptional types are the drawn models of those figures; each type is an isotopy class of arcs in Dk∪Dk+1 with the prescribed endpoints on dk−1,dk,dk+1 and Δ∪∂D.

Segments types. A segment of c∩Dk for 1≤k≤m is, up to the analogous isotopy, of one of the six types labelled 1,1′,2,2′,3,3′ of Figure 12; for k=m+1 there are the two types analogous to 2 and 3 (Figure 13), and for k=0 the single type of Figure 14. The essential segments are precisely those of type 1,1′,2,2′; the basic curves b0,…,bm themselves have no essential segments.

The nested twists. Fix the pairwise disjoint nested curves l0,…,lm−1 of Figure 7. The disk bounded by lj contains exactly the suffix of marked points {qj,…,qm}. Choose a small closed annular neighbourhood of lj, disjoint from all marks and from the other support annuli; among the basic arcs it meets only bj, in one transverse crossing. Let τj be a positive Dehn twist supported in that annulus. Its class lies in G, the classes commute by disjoint support, and the chosen representative fixes every bk with k≠j. They generate the standard twist subgroup used in the detector lemma below. Standing convention. All the data above — the basic set b0,…,bm, the vertical curves d0,…,dm, the regions D0,…,Dm+1 and the nested curves l0,…,lm−1 — are fixed once and for all in the standard picture, and every statement invoking them names this fixed picture. When a statement is applied to an arbitrary basic set, it is transported by an actual diffeomorphism in D carrying the standard basic set to the given one; the transport is part of the statement.

DefinitionDefinition: Literature-sourcedProof: Not applicableOpen item page →

Faithful weak action

Definition

Let (Fg)g∈G be a weak action of a group G on a category Q in the sense of Weak action of a group on a category, with unit 1 of G (Left group actions, transitive actions, and faithful actions). The action is faithful if for every g≠1 the functor Fg is not isomorphic to the identity functor of Q, that is, there is no natural isomorphism Fg≅Id⁡Q of functors Q→Q (Natural isomorphism).

Equivalently, the action is faithful when the functor assignment g↦Fg is injective up to natural isomorphism: if Fg≅Fh then g=h, since Fg≅Fh is equivalent to Fh−1g≅Fh−1Fg≅Id⁡Q by the weak action property and the definition, so that h−1g=1 for a faithful action.

Remarks

Remarks on the notion.

  • Faithfulness is a property of the functor assignment g↦Fg itself, not of an induced action on any invariant of Q. In particular a group element may act nontrivially on Q while inducing the identity on a Grothendieck group or another functorial invariant; the pair of this definition with Equal actions on K_0 do not imply isomorphic derived autoequivalences ↗ records exactly that contrast.
  • Because the components of a weak action are compared only through the existence of natural isomorphisms Ffg≅FfFg, faithfulness is a property of the weak action and not of an underlying coherent 2-action: nothing in the definition refers to the compositors μf,g of a coherent action, and the notion is well defined for a bare functor assignment.
  • The source states this definition for the action of the braid group on Cm and proves faithfulness in Corollary 1.2; the definition here is the general one used on this page, of which that statement is the instance The Khovanov-Seidel weak braid action is faithful.
DefinitionDefinition: Literature-sourcedProof: Not applicableOpen item page →

The Z^2 cover of the projectivized tangent bundle and bigraded curves

Definition

The braid action is used only through the mapping class group. Assume the Axiom of Choice (The Axiom of Choice), used here only to pass between braid classes and boundary-fixed mapping classes of the punctured disk, so that the braid group acts on bigraded curves through G=π0Diff⁡(D,∂D;Δ) via Artin presentation completeness The Artin presentation is complete for geometric braids and the smooth configuration-space comparison of Khovanov–Seidel, Section 3b, equation (3.1), printed p. 19. The corresponding topological comparison uses Braid group as boundary-fixed punctured-disk mapping classes and AC. Everything else in this definition — the cover, its deck group and the preferred lifts — is produced by the covering-space classification and the lifting criterion and is choice-free.

Let (D,Δ) be the marked disk of Curves and geometric intersection numbers on the marked disk, and let D∖Δ⊆C carry its subspace topology. Write P:=P(T(D∖Δ)) for the real projectivization of the tangent bundle, the space of tangent lines Tzc of curves at unmarked points; the embedding D⊂C trivializes TD, so P is identified with (C∗/R×)×(D∖Δ) and is a smooth manifold of real dimension 3 with boundary. Fix once and for all a polynomial h∈C[z] with simple zeros exactly at the points of Δ (for instance h(z)=∏a∈Δ(z−a)), and define δP ⁣:P⟶(C∗/R>0)×(C∗/R>0),δP(ζ,z):=(h(z)−2ζ2, −h(z)). This is well defined: ζ is a class modulo real scalars, so ζ2 is a class modulo positive real scalars and h(z)−2ζ2 likewise, and both coordinates are nonzero because ζ≠0 and h(z)≠0 on D∖Δ.

The cover. Let exp⁡ ⁣:R2⟶(C∗/R>0)2,exp⁡(ξ1,ξ2):=(e2πiξ1,e2πiξ2), the universal covering of the two-torus (C∗/R>0)2; it is a regular covering with deck group Z2 acting by translation (Covering maps, evenly covered neighbourhoods, fibres, sheets, and trivial coverings, Deck transformations and the deck-transformation group of a covering, Connected covering spaces are classified by conjugacy classes of fundamental-group subgroups). Define P~:={(x,p)∈R2×P:exp⁡(x)=δP(p)} with the subspace topology and the projection π~(x,p):=p. Then π~:P~→P is a covering map with deck group Z2 acting by χ(r1,r2)(x,p):=(x+(r1,r2), p), the pullback of the universal covering along δP. This is the source's Z2-cover of P.

Bigradings and bigraded curves. For a curve c (unoriented, as in Curves and geometric intersection numbers on the marked disk) the canonical section is sc ⁣:c∖Δ⟶P,sc(z):=Tzc. It is well defined because a curve meets Δ in at most its two endpoints, so Tzc exists for every z∈c∖Δ, and it is continuous. A bigrading of c is a continuous lift c~ ⁣:c∖Δ⟶P~,π~∘c~=sc, of the canonical section. Pairs (c,c~) consisting of a curve and a bigrading are bigraded curves; we often write c~ in place of (c,c~). A curve need not admit a bigrading — the obstruction for simple closed curves is computed by the source — and precisely the arcs admit bigradings. An arc with its marked endpoints removed is contractible, so its tangent section lifts. A simple closed curve enclosing k≥1 marked points has tangent-section monodromy ±(2−2k,k)≠0: the tangent makes one full turn and h winds k times, so the two coordinates of δP wind 2−2k and k. Hence its tangent section cannot lift (Khovanov--Seidel, Lemma 3.12, printed p. 24). The bigradings of any fixed arc form a Z2-torsor by uniqueness of path lifting, and are acted on by the deck group χ: χ(r1,r2)c~:=χ(r1,r2)∘c~.

The diffeomorphism and mapping-class actions. Let D:=Diff⁡(D,∂D;Δ) be the actual orientation-preserving diffeomorphism group; its component group is the mapping class group G used in the marked-disk Definition. For f∈D, the derivative induces P→P, [v]↦[Df(v)]. It preserves the monodromy homomorphism: a fibre loop maps to a fibre loop of degree one, and a positively oriented puncture loop maps to the corresponding loop about the permuted puncture. No extra fibre winding occurs because Df:D→GL+(2,R) is defined on the whole disk, so its restriction to any loop in D is null-homotopic. The monodromy images of a fibre generator and a puncture generator are (1,0) and (−2,1); they generate Z2, so the pullback cover is connected and its deck group is exactly Z2.

There is a unique deck-equivariant preferred lift f~ fixing every point of the fibre over one chosen boundary tangent line Tz∂D. This base tangent line is fixed by the derivative, so the lifting criterion gives the based lift (Lifting criterion for maps from path-connected locally path-connected spaces), and monodromy preservation makes it deck-equivariant. Along the connected boundary tangent section the derivative is the identity; lifting its paths shows that f~ fixes every fibre over every Tw∂D. Uniqueness of based lifts (Two lifts from a connected space that agree at one point agree everywhere) gives fg~=f~g~. The action on bigraded curves is parametrization-aware: the bigrading of f(c) at f(z) is f~(c~(z)). An isotopy of actual diffeomorphisms lifts from the identity by homotopy lifting (Existence and uniqueness of homotopy lifts through a covering map) and hence carries bigraded curves through bigraded isotopies; therefore the action on bigraded isotopy classes descends to G=π0(D). Isotopy. A bigraded isotopy between bigraded curves (c~0,c~1) is an isotopy ct of curves, together with a continuous family of lifts c~t through bigraded curves; the deck action and the D-action take bigraded isotopy classes to bigraded isotopy classes. Two bigraded curves are isotopic when such a family exists, and isotopy relates only bigradings of curves in the same curve-isotopy class.

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Finite graded projectives are sums of shifted vertex projectives

Statement

Fix m≥1 and let Am be the Khovanov–Seidel type A algebra with vertex projectives Pi=Amei, 0≤i≤m (Finite graded A_m-modules, internal shifts and the vertex projectives, The vertex modules S_i and their prime quotients). Every finitely generated graded projective left Am-module P is isomorphic, as a graded module, to a finite direct sum P≅⨁i=0m ⨁r∈ZPi{r}⊕ai,r of internal shifts of the vertex projectives, with multiplicities ai,r∈N zero for all but finitely many pairs (i,r); the multiplicities are uniquely determined by P. Equivalently, the shifted modules Pi{r} are the indecomposable objects, and their classes [Pi{r}], 0≤i≤m, r∈Z, form a free abelian basis of the split Grothendieck group of finite graded projectives, with no relations among distinct pairs.

Facts & Assumptions

Given: An integer m≥1, the algebra Am with vertex idempotents ei, its path ideal J generated by the arrows, the vertex projectives Pi=Amei with internal shift {r}, and a finitely generated graded projective left Am-module P.

[L1]

J is homogeneous, J3=0, J is spanned by the paths of length at least one, and the quotient satisfies Am/J≅Zm+1 with the classes of the vertex idempotents as basis (The Khovanov-Seidel path ideal).

[L2]

A graded left Am-module is finite graded projective exactly when it is a degree-zero direct summand of a finite direct sum of internal shifts of the regular module, P⊕Q≅Am{r1}⊕⋯⊕Am{rn}, with degree-zero inclusion and projection (Finite graded projectives are finite shifted-free summands).

[L3]

Every submodule of a finite free Z-module is free, hence torsion-free and finitely generated if the ambient module is; a graded subgroup of a graded free abelian group that is a direct summand is again a graded free abelian group, and it has a homogeneous Z-basis (A submodule of a free module of finite rank over a PID is free of no larger rank).

[L4]

Am=⨁i=0mPi as a left module, Pi{r} is the shift with (Pi{r})d=(Pi)d−r, the shift is an automorphism of the category, and a direct summand of a projective object is projective; a direct summand of a finitely generated module is finitely generated (Finite graded A_m-modules, internal shifts and the vertex projectives, A direct summand of a projective is projective).

[L5]

Am has the Z-basis of 4m+1 classes of vertices, arrows and returns, so Am/J kills exactly the non-vertex basis paths and the vertices e0,…,em are pairwise orthogonal idempotents with sum 1 (The 4m+1 path basis, The Khovanov-Seidel path ideal).

Proof

technique · direct
1.1L1L2L3

P/JP is a finite free graded abelian group. By [L2] there is a degree-zero isomorphism P⊕Q≅F:=Am{r1}⊕⋯⊕Am{rn} for some finitely generated graded projective Q. Applying (Am/J)⊗Am−=Zm+1⊗Am− degreewise gives a degree-zero isomorphism of graded Zm+1-modules P/JP⊕Q/JQ≅F/JF≅(Zm+1){r1}⊕⋯⊕(Zm+1){rn}; in particular P/JP is a direct summand, as a graded abelian group, of the finite free graded abelian group F/JF whose homogeneous components are finite free Z-modules. By [L3] each graded component (P/JP)d is a finitely generated torsion-free, hence free, Z-module, and P/JP has a homogeneous Z-basis.

2.1step 1.1L1L5

The vertex decomposition of P/JP. Since J acts as 0 on P/JP, the latter is a graded module over Am/J≅⨁iZei: the projections ei are orthogonal idempotents with sum 1 [L5], so as a graded abelian group P/JP=⨁iei(P/JP), and a homogeneous basis of P/JP is the disjoint union of homogeneous bases of the graded free abelian groups ei(P/JP). Write ai,r for the rank of the degree-r part (ei(P/JP))r of the i-th summand; the ai,r are the multiplicities of the Cartesian basis of [L3] and are zero for all but finitely many (i,r).

3.1step 2.1L1L4L5

A surjection from the proposed direct sum. Choose, for every i and r, a homogeneous Z-basis {[xi,r,s]}s=1ai,r of the degree-r part of ei(P/JP) and lift each xi,r,s to a homogeneous element x^i,r,s∈P of degree r that lies in eiP; since P=⨁ieiP this is possible component by component. The lifts assemble into a degree-zero Am-linear map φ ⁣:F′:=⨁i,rPi{r}⊕ai,r→P with φ(ei⊗1r,s)=x^i,r,s, the map on a summand being aei↦ax^i,r,s. This is well defined because x^i,r,s=eix^i,r,s, so aei=0 implies ax^i,r,s=0. Reducing modulo J gives the isomorphism F′/JF′→P/JP determined by the chosen bases, because Pi/JPi≅Z is concentrated at the vertex i and J kills the generators; hence φ is surjective by the nilpotent Nakayama argument: if C:=coker⁡φ then C=JC, so C=J3C=0 because J3=0.

3.2step 2.1L1L5

Uniqueness of the multiplicities. Suppose ⨁i,rPi{r}ai,r≅⨁i,rPi{r}bi,r, and reduce modulo J: since Pi/JPi≅Z placed at internal degree 0 with the vertex i acting by 1, an isomorphism of the direct sums induces, for every i and r, an isomorphism of graded abelian groups between the degree-r parts of the i-th vertex components, which are the free abelian groups of ranks ai,r and bi,r; hence ai,r=bi,r.

4.1step 3.1L1L4

The surjection splits, and is an isomorphism. The module P is projective, so the surjection φ splits: there is a degree-zero Am-linear ψ:P→F′ with φψ=idP, and then F′≅P⊕K with K:=ker⁡φ a direct summand of F′, hence finitely generated graded projective by [L4]. Applying (Am/J)⊗Am− to F′≅P⊕K and comparing with the isomorphism F′/JF′≅P/JP of step 3.1 gives K/JK=0, so K=JK=J2K=J3K=0; hence φ is injective and therefore an isomorphism F′≅P.

5.1step 4.1step 3.2∎

Conclusion. Every finitely generated graded projective P is isomorphic to ⨁i,rPi{r}⊕ai,r by step 4.1, the multiplicities are finite in number by step 2.1 and unique by step 3.2. Equivalently, the comparison with the split Grothendieck group sends the class of such a sum to the finite sum ∑ai,r[Pi{r}], so the classes [Pi{r}] are linearly independent over Z by step 3.2, and each Pi is indecomposable: for i=0 its endomorphism ring is e0Ame0=Ze0, whose only idempotents are 0,1. For 1≤i≤m the corner is eiAmei=Zei⊕Z(i∣i−1∣i) with (i∣i−1∣i)2=0, an idempotent a+br satisfies a2=a and b(2a−1)=0 in Z, so only a=b=0 and a=1,b=0 occur, and a decomposition Pi=X⊕Y would give a nontrivial idempotent. No choice principle is used: all bases are finite and chosen explicitly from the finitely many graded pieces.

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Geometric intersection numbers are isotopy invariants

Statement

Assume AC, used in the relative-isotopy input where homotopic arcs are replaced by isotopic ones through Homotopic simple proper arcs in the punctured disk are isotopic relative to their endpoints. For curves c0,c1 in (D,Δ) (Curves and geometric intersection numbers on the marked disk) the number I(c0,c1) does not depend on the chosen minimal-intersection representative c1′ of c1, and if ci′ is isotopic to ci for i=0,1 then I(c0′,c1′)=I(c0,c1). Consequently I is an invariant of isotopy classes of curves, and it is computed in the source's picture as well as in any curve system obtained from it by an ambient isotopy.

Facts & Assumptions

Given: The marked disk (D,Δ), the isotopy relation ≃ of Curves and geometric intersection numbers on the marked disk, its minimal-intersection condition, the half-weight formula for I with the exceptional value 2 for isotopic simple closed curves and the flow extension for pairs meeting on ∂D, and curves c0,c1.

[L1]

For curves with c0∩c1∩∂D=∅ the number I(c0,c1) is defined as ∣(c0∩c1′)∖Δ∣+12∣c0∩c1′∩Δ∣ for any minimal-intersection representative c1′ of c1, with the exceptional value 2 when c0,c1 are simple closed curves with c0≃c1; for pairs meeting on ∂D it is defined after pushing c0 by a small positive boundary flow (Curves and geometric intersection numbers on the marked disk).

[L2]

Assume AC. Simple proper arcs in the punctured disk with the same endpoints that are homotopic relative to endpoints are isotopic relative to endpoints as unoriented arc images (Homotopic simple proper arcs in the punctured disk are isotopic relative to their endpoints).

[L3]

Assume AC. Let N be a finite family of pairwise disjoint simple arcs in D with endpoints on ∂D and interiors avoiding the marked points, and let T be a simple arc with endpoints in Δ∪∂D. Then T is isotopic relative to endpoints to an arc meeting every member of N minimally, and T is isotopic relative to endpoints to an arc disjoint from N if and only if some minimal-position representative is disjoint from N (Minimal-position representatives and the arc bigon criterion).

[L4]

The relative minimal-position comparison is Khovanov–Seidel Lemma 3.2: if c1′,c1′′ are isotopic, both minimal with c0, and not isotopic to c0, a boundary-fixed ambient isotopy preserving Δ and c0 setwise carries one to the other. Lemma 3.3 says that an isotopic minimal pair is either closed or has all endpoints marked, and is carried, relative to c0, to one of the two configurations of Figure 5. For a two-marked-endpoint arc each configuration has precisely the two common marked endpoints. These are the source's relative comparison lemmas, not a claim that arbitrary isotopies preserve a fixed intersection set (Khovanov–Seidel, printed pp. 18–19).

[L5]

Simultaneous transport by a boundary-fixed diffeomorphism preserving Δ bijects intersection sets, preserves their marked subsets, and carries bigons and minimal positions to bigons and minimal positions. An identity-component isotopy gives isotopic transported curves (Boundary-fixed mapping class group of a punctured disk, Curves and geometric intersection numbers on the marked disk).

Proof

technique · direct
1.1L1L4

The exceptional cases. Suppose the pair has no common boundary endpoint and c0≃c1. For closed curves the prescribed value is 2. For arcs, isotopy preserves their endpoint set, so both endpoints must lie in Δ. Each relative minimal model in [L4] has just those two common marked endpoints, giving I=1. These values depend only on the isotopy classes.

2.1L2L3L4L5step 1.1

Other minimal representatives give the same count. Suppose c0≄c1 and let c1′,c1′′ be minimal representatives of c1 relative to c0. The relative comparison [L4] gives an ambient isotopy preserving c0 setwise and carrying c1′ to c1′′. Its endpoint map bijects intersections with c0 and preserves Δ, so the ordinary and marked intersection counts agree. With step 1.1 this proves representative independence away from boundary intersections. The AC-dependent arc inputs [L2] and [L3] retain their hypotheses; the stronger relative comparison is the source lemma [L4].

3.1L1L5step 1.1step 2.1

Isotopy invariance away from boundary intersections. An endpoint map F of an identity-component ambient isotopy carrying c0 to c0′ carries a minimal representative c1′ to a minimal representative of the same class of c1. Simultaneous transport preserves both counts. If the pair is isotopic and closed, both values instead equal the prescribed 2; otherwise the weighted formula applies. Hence I(c0′,c1)=I(c0,c1) by step 2.1. Representative independence gives invariance in the second argument as well.

4.1L1L5step 3.1

The boundary push is independent of its small positive choice. Interpolate between the two positive boundary fields and their extensions by convex combination, and between sufficiently small positive flow times; write gs for the resulting endpoint diffeomorphisms. Compactness of the parameter interval allows a common small-time bound, so each boundary endpoint of gs(c0) stays in one complementary interval of ∂D∖c1. Larger allowed times can first be decreased within those intervals. Choose a boundary isotopy hs, starting at the identity and fixing the endpoints of c1, which carries these moving endpoints back to those of g0(c0). Extend hs to Hs in a thin collar preserving c1 setwise and missing Δ: in collar coordinates straightening the endpoint germs of c1 to radial segments, extend the boundary velocity tangentially along these segments, with a cutoff. Then as:=Hsgs(c0) is a smooth isotopy of embedded arcs with fixed endpoints. It extends to a boundary-fixed ambient isotopy fixing Δ: extend the velocity along the moving arc over tubular charts with cutoffs; it vanishes at fixed endpoints, and transversality at boundary endpoints allows the extension to vanish on the boundary. Thus step 3.1 gives I(a0,c1)=I(a1,c1). Simultaneous transport by H1, which preserves c1, bijects intersections and marked subsets and preserves the Jordan-disk condition; therefore I(g1(c0),c1)=I(a1,c1)=I(g0(c0),c1). The comparison is between isotopy classes before minimization; no isotopy preserving c1 is asserted between the arbitrary pushed arcs themselves.

5.1L5step 3.1step 4.1

Invariance with the boundary convention. A boundary-fixed endpoint map F transports a positive field Z to F∗Z and conjugates their flows, so simultaneous transport identifies I(ft(c0),c1) with I(Fft(c0),F(c1)). Step 4.1 permits the transported push for F(c0). Since the pushed pair has disjoint boundary endpoints and F(c1)≃c1, step 3.1 identifies the latter count with the pushed count for (F(c0),c1). This proves invariance in the first argument. For an isotopy in the second argument, use the same fixed push of c0; its boundary endpoints are disjoint from the fixed endpoints of every curve in that isotopy, so step 3.1 applies directly.

6.1step 1.1step 2.1step 3.1step 5.1∎

Conclusion. The ordinary weighted formula, the exceptional closed value, and the positive-boundary extension all define numbers independent of minimal representatives and invariant under the stated isotopies. The AC-dependent arc inputs retain the hypothesis in the Statement; the finite counts and explicit collar comparison require no additional choice.

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The three-term braid relation

Statement

Fix m≥1, let Ri,Ri+1 be the positive twist complexes of The twist complexes R_i and R_i^{-1}, and use the balanced totalization of Signed totalization of graded A_m-bimodule actions. For 1≤i≤m−1 there is a homotopy equivalence of complexes of graded (Am,Am)-bimodules Ri⊗AmRi+1⊗AmRi  ≃  Ri+1⊗AmRi⊗AmRi+1, hence an isomorphism of endofunctors of Cm RiRi+1Ri≅Ri+1RiRi+1. Together with the far-commutativity lemma Far commutativity of the generator complexes and the inverse-pair lemma The generator complexes are mutually inverse, this is the braid relation for the generators of the action.

Facts & Assumptions

Given: An integer m≥1, an index 1≤i≤m−1, the twist complexes Ri,Ri+1 with the bimodules Ui,Ui+1 and the maps β,γ of The Khovanov–Seidel bimodule maps β_i and γ_i, and the balanced tensor and corner identifications of Graded associativity, units, and internal-shift tensor isomorphisms.

[L1]

Ri=[Ui→βiAm] and Ri−1=[Am→γiUi{−1}] are bounded complexes of graded (Am,Am)-bimodules with degree-zero differentials and two-sided finite graded projective terms (The twist complexes R_i and R_i^{-1}).

[L2]

Ri⊗AmRi−1≃Am≃Ri−1⊗AmRi, and more precisely the proof of that statement exhibits Ri⊗AmRi−1≅T−1⊕Am⊕T1 with T−1,T1 two-term complexes with invertible differentials; the same holds with i replaced by i+1 (The generator complexes are mutually inverse).

[L3]

The balanced tensor of graded bimodules is associative and unital, and the totalization of tensor products of bounded complexes is a bounded complex functorial in each variable, compatible with these identifications (Graded associativity, units, and internal-shift tensor isomorphisms, Signed totalization of graded A_m-bimodule actions).

[L4]

A two-term complex with invertible differential is contractible, and splitting off a contractible direct summand does not change the homotopy type (Gaussian elimination splits a contractible two-term complex).

[L5]

Corner computations: jP⊗AmPk≅ejAmek; for the pair (j,k)=(i+1,i) this is Z(i+1∣i) with (i+1∣i) of degree 1, for (j,k)=(i,i+1) it is Z(i∣i+1) with (i∣i+1) of degree 0, and it vanishes for ∣j−k∣>1 (Graded associativity, units, and internal-shift tensor isomorphisms, The 4m+1 path basis).

Proof

technique · direct
1.1L2

The two relations are equivalent. Assume first RiRi+1Ri≅Ri+1RiRi+1, that is, an isomorphism in the homotopy category of tensor complexes. Composing on the right with Ri−1 and using the inverse-pair lemma [L2] to cancel RiRi−1≃Am at the two ends of both sides gives RiRi+1≃Ri+1RiRi+1Ri−1; composing on the left with Ri+1−1 and cancelling Ri+1−1Ri+1≃Am gives Ri+1−1RiRi+1≃RiRi+1Ri−1. Conversely the same two cancellations applied to this isomorphism recover the braid relation. Hence it suffices to prove the displayed symmetric relation, which is the symmetric relation displayed in the source's proof.

2.1step 1.1L2L3L4L5

Normal form of the left-hand side. By [L3] and the definition of the cone, tensoring the two-term complex Ri=[Ui→Am] with the complex Ri+1 inside the triple tensor exhibits Ri+1−1RiRi+1 as the cone of the chain map g ⁣:Ri+1−1⊗AmUi⊗AmRi+1→Ri+1−1⊗AmRi+1 induced by βi, with all identifications canonical. The target splits as Am⊕(acyclic) by [L2] applied at i+1, and splitting off the contractible summand [L4] leaves the cone of the induced map to Am. Using the corner computations [L5] one obtains the isomorphisms of complexes Ri+1−1⊗AmPi≅[Pi→(i∣i+1)Pi+1] and iP⊗AmRi+1≅[i+1P→(i∣i+1)iP], with Pi, respectively iP, placed in degree 0; these are the two displays in the source's proof. Tensoring the left (Am,Z) and right (Z,Am) complexes over Z and using [L5] for the outer corners eiAmei and ei+1Amei+1 gives the four-term complex C=[0→Pi⊗Zi+1P→∂−1(Pi⊗ZiP)⊕(Pi+1⊗Zi+1P)→∂0Pi+1⊗ZiP→0] with terms in homological degrees −1,0,1, together with a chain map e ⁣:C→Am concentrated in degree 0, so that the left-hand side of step 1.1 is homotopy equivalent to the cone of e.

3.1L1L3L5step 2.1algebra

The normal complex and its chain map. Put a=(i∣i+1), a degree-zero forward arrow. In the complex C of step 2.1 the differentials, after the indicated corner identifications, are ∂−1(x⊗y)=(x⊗ay, xa⊗y),∂0(u,v)=ℓa(u)−ra(v), where ℓa(x⊗y)=xa⊗y on Ui and ra(x′⊗y′)=x′⊗ay′ on Ui+1. All path endpoints match these modules, and the two products in ∂0∂−1 cancel. A degree-zero map e:Ui⊕Ui+1→Am is determined by e(ei⊗ei)=a1ei and e(ei+1⊗ei+1)=a2ei+1, since the degree-zero corner ejAmej is Zej. Evaluating e∂−1 on ei⊗ei+1 gives (a1+a2)a, so the chain-map condition is a1+a2=0.

4.1L1L2L5step 3.1algebra

Why the coefficient is a unit. The cone of e is an invertible bimodule complex by [L2], with explicit inverse homotopies that remain valid after reduction modulo any prime p. Over k=Fp, the degree-zero centre of Am⊗k is k: commuting with the vertex idempotents removes every off-diagonal forward-arrow term, and a diagonal element ∑jbjej commutes with each nonzero adjacent arrow only if bj=bj+1. Thus the degree-zero endomorphism ring of the unit bimodule complex is k, with no nontrivial idempotent. Tensoring with an invertible object is an equivalence of the homotopy category, so it transports the endomorphism ring of the cone to that of the unit; the cone cannot split into two nonzero homotopy summands. If p divides a1, then a2=−a1 also vanishes modulo p and the cone is Am⊗k⊕Ck[1]. The second summand is nonzero in the homotopy category: tensor Ck on both outer sides with (Am/J)⊗k, where J is the arrow ideal. Its arrow differentials become zero and its nonzero vertex tensor terms remain nonzero. An additive tensor functor preserves a contracting homotopy, so this zero-differential complex proves that Ck was not contractible. This contradicts the preceding indecomposability. Hence no prime divides a1, so a1=±1; if a1=0, any prime gives the same contradiction. Changing the sign of the target Am if necessary yields a1=1, a2=−1. This is the precise connected-algebra argument behind the source's characteristic-p normalization, rather than a false assertion about all equivalences of categories.

5.1L1L2L3L4L5step 1.1step 2.1step 3.1step 4.1algebra

The second conjugate. For RiRi+1Ri−1, the two corner complexes are [Pi→Pi+1] in degrees −1,0 and [i+1P→iP] in degrees 0,1, with the same forward-arrow maps. Their tensor over Z has the same terms as C. Its initial differential has signs (−,+) and its final differential signs (+,+); the degreewise sign maps 1, diag⁡(−1,1) and −1 identify it with the C of step 3.1. The target inverse-pair complex again cancels to Am, giving the cone of a degree-zero map f:C→Am. Its values are b1ei,b2ei+1, the chain condition gives b1+b2=0, and step 4.1 applies to this invertible conjugate as well, so after the target sign normalization b1=1,b2=−1. Consequently f=e on both cyclic summands and hence everywhere. The two cones are isomorphic, and the inverse cancellations of step 1.1 give the full triple braid relation.

6.1step 5.1L3∎

Conclusion. The two triple tensor complexes are homotopy equivalent, so in the homotopy category Cm the three-term braid relation holds; passing to the induced functors gives RiRi+1Ri≅Ri+1RiRi+1. The identifications used are canonical, and no choice principle is used.

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Local indices and bigraded intersection numbers

Definition

Assume AC (The Axiom of Choice) for the supplied representative-independence and isotopy-invariance assertions for I used in (B1) and the proof below. The local-index construction and finite Laurent sums require no additional choice.

Work in the situation of The Z^2 cover of the projectivized tangent bundle and bigraded curves: (D,Δ) is the marked disk, P the projectivized tangent bundle and π~ ⁣:P~→P the Z2-cover with deck action χ. Let c~0,c~1 be bigraded curves meeting transversally at a point z∈D∘∖∂D; z may or may not lie in Δ.

The local index. Fix a small circle l⊂D∖Δ around z and an embedded arc α ⁣:[0,1]→l moving clockwise around l with α−1(c0)={0} and α−1(c1)={1}, and choose a smooth path π ⁣:[0,1]⟶P,π(t)∈Pα(t), over α from Tα(0)c0 to Tα(1)c1 which is never tangent to α, that is, π(t)≠Tα(t)l for all t. Lift π to a path π~ ⁣:[0,1]→P~ with π~(0)=c~0(α(0)); then necessarily c~1(α(1))=χ(μ1,μ2)π~(1) for a unique (μ1,μ2)∈Z2. The local index is μbigr(c~0,c~1;z):=(μ1,μ2)∈Z2. It is independent of the choices of l, of the admissible α, of the path π and of the chosen lift, by the proof below.

The bigraded intersection number. Let c~0,c~1 be bigraded curves with c0∩c1∩∂D=∅. Choose a curve c1′≃c1 in minimal intersection with c0; by the free deck action on bigraded isotopy classes (Khovanov--Seidel, Lemma 3.13, printed p. 24), there is a unique bigrading c~1′ of c1′ with c~1′≃c~1 (the deck group acts freely on bigradings of a fixed curve, and a fixed bigrading transported along an isotopy determines the resulting bigraded isotopy class). Put Ibigr(c~0,c~1):=(1+q1−1q2) ⁣ ⁣∑z∈(c0∩c1′)∖Δ ⁣ ⁣q1μ1(z)q2μ2(z)+ ⁣ ⁣∑z∈c0∩c1′∩Δ ⁣ ⁣q1μ1(z)q2μ2(z)∈Z[q1±1,q2±1], where (μ1(z),μ2(z))=μbigr(c~0,c~1′;z) and the coefficients lie in the two-variable Laurent polynomial ring The Laurent polynomial ring as the principal localisation of Z[t] at t (iterated once; its monomials q1r1q2r2, r1,r2∈Z, are units). The number Ibigr is a Laurent polynomial: the intersection c0∩c1′ is finite and the sum is finite. For curves with c0∩c1∩∂D≠∅ the number is extended by the positive boundary flow: take the flow (ft) of the boundary vector field, lift it to a flow (f~t) on P~ with f~0=id, and set Ibigr(c~0,c~1):=Ibigr(f~t(c~0),c~1)(t>0 small).

Properties. The following hold, and the first four are proved below.

  • (B1) Setting q1=q2=1 and dividing by two recovers the ordinary geometric intersection number: Ibigr(c~0,c~1)∣q1=q2=1=2I(c0,c1) (Curves and geometric intersection numbers on the marked disk).
  • (B2) Ibigr(f~(c~0),f~(c~1))=Ibigr(c~0,c~1) for every actual f∈D=Diff⁡(D,∂D;Δ), with f~ the preferred lift; equivalently this holds for the induced mapping-class action on bigraded isotopy classes.
  • (B3) Ibigr(c~0,χ(r1,r2)c~1)=q1r1q2r2Ibigr(c~0,c~1) and Ibigr(χ(−r1,−r2)c~0,c~1)=q1r1q2r2Ibigr(c~0,c~1).
  • (B4) If c0∩c1∩∂D=∅ and Ibigr(c~0,c~1)=∑ar1,r2q1r1q2r2, then Ibigr(c~1,c~0)=∑ar1,r2q1−r1q21−r2.
  • Ibigr is independent of the choices of c1′ and c~1′ and is an invariant of the isotopy classes of (c~0,c~1).

Facts & Assumptions

Given: AC and the marked disk (D,Δ), the projectivized tangent bundle P, the Z2-cover π~ ⁣:P~→P with deck action χ, bigraded curves c~0,c~1 transverse at z, and the local model of the annulus around z.

[L1]

P~→P is a covering with deck group Z2 acting by χ, and a bigrading of a curve is a continuous lift of the canonical section; the deck action and the preferred lifts f~ of actual diffeomorphisms in D act on bigraded curves (The Z^2 cover of the projectivized tangent bundle and bigraded curves).

[L2]

Under AC, I(c0,c1) is independent of the minimal representative and is an isotopy invariant of curves, with the half-weight convention at marked endpoints and the positive flow extension (Curves and geometric intersection numbers on the marked disk, Geometric intersection numbers are isotopy invariants).

[L3]

Z[q1±1,q2±1] is the Laurent polynomial ring in two variables, obtained by iterating the one-variable construction; its monomials are units and finite Laurent coefficient sequences are unique, and qiqi−1=1 gives the unit identities (The Laurent polynomial ring as the principal localisation of Z[t] at t).

[L4]

The tangent lines Tα(0)c0 and Tα(1)c1 are defined at the endpoints of α; the fibre Pα(t) is a circle, the path π is transverse to the circle-valued family Tα(t)l, and a lift of π exists with any prescribed initial point because π~ is a covering (The Z^2 cover of the projectivized tangent bundle and bigraded curves).

[L5]

Khovanov–Seidel Lemmas 3.2 and 3.3 (printed pp. 18–19) give relative comparison of nonisotopic minimal pairs and the two minimal models for isotopic arcs. Lemma 3.13 (printed p. 24) gives freeness of the deck action on bigraded isotopy classes. The type-VI entry of Lemma 3.20 (printed p. 32) is 1+q2 for the zero-shift basic arc. These exact literature inputs concern the smooth marked-disk conventions of this item (source URL in references).

Proof

technique · direct
1.1L1L4

The local index is well defined. For a fixed clockwise arc α, trivialize the projective tangent bundle along α so that its circle tangent line is a fixed forbidden point of RP1. The allowed fibre is RP1∖{point}≅R, so any two admissible paths with the prescribed endpoint tangent lines are homotopic through admissible paths relative to endpoints. Homotopy lifting then gives the same lifted endpoint and index. Shrinking the small circle and straightening the two curve germs yields homotopic data, so the index is independent of these choices. At a marked endpoint there is one clockwise sector. At an unmarked crossing there are two sectors; in the straight-line model a half-turn identifies them and acts trivially on projective tangent lines. Their base-path comparison is contained in an unmarked disk and their fibre paths agree, so they have identical monodromy after transporting the curve bigradings through the disk. Thus the two admissible sectors give the same index. These are the local models of Khovanov--Seidel printed p. 25, Figure 10.

1.2L1L3

Properties (B3) and (B4). For (B3), replacing c~1 by χ(r1,r2)c~1 adds (r1,r2) to the endpoint of the lifted path, so by the definition of the local index and the deck action each μbigr(c~0,c~1;z) is replaced by μbigr(c~0,c~1;z)+(r1,r2), and the displayed sum is multiplied by q1r1q2r2 by [L3]; the second identity is the same computation with the roles of the two arguments exchanged. For (B4), assume minimal intersection and let z be an intersection point; exchanging the two arguments reverses the direction of the arc α around l, so the local indices satisfy μbigr(c~1,c~0;z)=(1,0)−μbigr(c~0,c~1;z) when z∉Δ and (0,1)−μbigr(c~0,c~1;z) when z∈Δ, since reversing the direction adds the deck element corresponding to one full turn of the tangent line along the small circle, which is (1,0) in the interior case and (0,1) at a marked point; the interior contribution of z to Ibigr(c~0,c~1) is (1+q1−1q2)q1aq2b with (a,b)=μbigr(c~0,c~1;z), while the contribution of the same point to Ibigr(c~1,c~0) is (1+q1−1q2)q11−aq2−b=q11−aq2−b+q1−aq21−b, which is the sum of the two monomials obtained from the contributions of the original summand by applying the transformation F(q1,q2)↦q2F(q1−1,q2−1); summing over the finitely many points (and treating marked endpoints the same way without the (1+q1−1q2) factor) gives the stated reversal rule.

2.1L1L2L3L5step 1.1step 1.2

B1, B2 and independence of minimal representatives. Bigraded curves are arcs, by the obstruction computation in [L1]; there is no bigraded simple-closed-curve exceptional case. Setting q1=q2=1 makes each unmarked contribution 2 and each marked-endpoint contribution 1, so [L2] gives B1. For nonisotopic arcs, the relative minimal-position comparison of [L5] supplies an isotopy fixing c0 setwise between minimal representatives. Lift that isotopy; its returned bigrading on c0 equals the original by the free deck action on isotopy classes ([L5]), so it transports every local index unchanged. For isotopic arcs with no common boundary endpoint, both endpoints are marked; the isotopic-minimal-position statement of [L5] (Figure 5) reduces to the two small push-offs of the same arc. For a small self push-off with the transported bigrading, the two marked-end indices are (0,0) and (0,1). To compute them, straighten the arc near an endpoint q and write h(z)=(z−q)a(z) with a nonvanishing on the small disk. In the clockwise sector the radial tangent and z−q rotate together, so the first coordinate h(z)−2ζ2 has zero winding. At one endpoint the clockwise comparison is the short sector, giving index (0,0); at the other it differs from the bigrading transport by one clockwise full turn, giving endpoint index (0,1) because μ compares the curve lift to the path lift. The other push-off exchanges the two ends. Thus a relative deck shift (r1,r2) gives total contribution q1r1q2r2(1+q2). This also satisfies the reversal identity of step 1.2 and agrees with the source type-VI table in [L5]. Thus the two choices agree. This proves independence and bigraded isotopy invariance. For B2, an orientation-preserving diffeomorphism maps the small circle and clockwise sector to admissible local data after deformation; its deck-equivariant lift sends the endpoint relation defining the index to the identical relation, and preserves marked/unmarked points and minimal intersection. Hence it preserves each summand. The boundary-flow extension is compatible with these arguments: two sufficiently small positive pushes are joined by a flow interval with no endpoint passing, and transporting a field by a boundary-fixed diffeomorphism preserves its positive direction. Its lift starts at the identity, so no deck ambiguity occurs.

3.1L2step 1.1step 1.2step 2.1∎

Conclusion. The local index and the bigraded intersection number are well defined functions of the choices of bigradings and their isotopy classes, with the properties (B1)–(B4), and the definition is meaningful for all bigraded curves; AC is inherited through [L2] for ordinary intersection invariance; the local-index and finite-sum calculations require no additional choice.

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Existence and rigidity of bigradings

Statement

Let (D,Δ) be the marked disk and π~ ⁣:P~→P the Z2-cover of The Z^2 cover of the projectivized tangent bundle and bigraded curves with deck action χ. A curve c in (D,Δ) (Curves and geometric intersection numbers on the marked disk) admits a bigrading if and only if c is not a simple closed curve; when it does, any two bigradings of c differ by a unique element of the deck group Z2. Moreover, the Z2-action on isotopy classes of bigraded curves is free: a bigraded curve is never isotopic to χ(r1,r2)c~ with (r1,r2)≠0. Consequently a bigrading of a non-closed curve is unique up to the deck action, and an isotopy of curves lifts uniquely to an isotopy of bigraded curves once one bigrading is fixed, whenever the lifted bigradings exist throughout the isotopy.

Facts & Assumptions

Given: The marked disk (D,Δ), the pullback covering π~ of the universal covering of (C∗/R>0)2 along δP, with deck group Z2 acting by χ, and a curve c with canonical section sc.

[L1]

A bigrading of c is a continuous lift of sc to P~; the deck group acts on bigradings by composition with χ, and bigraded isotopy is isotopy through pairs (The Z^2 cover of the projectivized tangent bundle and bigraded curves).

[L2]

A map from a path-connected, locally path-connected space lifts through a covering with a prescribed initial point exactly when its induced fundamental-group image lies in that of the covering; homotopies lift uniquely from an initial lift (Lifting criterion for maps from path-connected locally path-connected spaces, Existence and uniqueness of homotopy lifts through a covering map). In this particular pullback, a lift is a continuous real-coordinate lift x of δPsc, and χ(r) sends x to x+r. Thus each fibre is a free transitive Z2-set: this follows from the explicit translation formula, not from a freeness assertion for arbitrary deck groups (The Z^2 cover of the projectivized tangent bundle and bigraded curves).

[L3]

A curve is either an embedded arc with interior in D∘∖Δ, or an essential simple closed curve in D∘∖Δ; an arc with its endpoints in Δ removed is a contractible interval, possibly closed or half-open at boundary endpoints, and the complement of the marked points in a simple closed curve is connected (Curves and geometric intersection numbers on the marked disk).

[L4]

The covering P~ is classified by the cohomology class whose value on a small positively oriented loop λz around a marked point is (−2,1) and whose value on the class of a full turn of the tangent line over a point is (1,0); an essential simple closed curve in the punctured disk bounds a topological disk in D containing k≥1 marked points, and its class pairs with the covering class as ±(2−2k,k)≠(0,0) (The Z^2 cover of the projectivized tangent bundle and bigraded curves).

Proof

technique · direct
1.1L1L2L3

Non-closed curves admit bigradings. If c is an arc, c∖Δ is a contractible interval [L3], hence path-connected and locally path-connected with trivial fundamental group. Choose any point over sc(z0); the subgroup condition in [L2] is then automatic, and the lifting criterion gives a continuous lift of sc, which is a bigrading.

1.2L2L4

Simple closed curves do not admit bigradings. By Jordan's theorem an essential simple closed curve encloses k≥1 marks. The two circle coordinates of δPsc have winding ±(2−2k,k) by [L4]. A continuous real-coordinate lift around c would return to its initial value, forcing both windings to be zero, contrary to k≥1. Hence no bigrading exists.

1.3L1L2L3

Uniqueness up to the deck action. Suppose c admits bigradings c~ and c~′. Both are lifts of the same section sc over the connected base c∖Δ [L3], so c~′(z)=χ(δ(z))c~(z) for a continuous function δ ⁣:c∖Δ→Z2; since Z2 is discrete this function is locally constant, and since c∖Δ is connected it is constant, say δ≡(r1,r2). Thus c~′=χ(r1,r2)c~, and (r1,r2) is unique because χ acts freely on each fibre.

1.4L1L2L3L4

Freeness on isotopy classes. Parametrize the given bigraded isotopy by smooth embedded arcs γt:[0,1]→D, choosing the parametrizations so that γ1=γ0; this is possible by interpolating the increasing reparametrization of the returned arc. The base and tangent-line traces at each unmarked parameter value are therefore closed loops. If the arc has a boundary endpoint, that endpoint is fixed, and its tangent line stays transverse to the boundary throughout the isotopy. Its projective tangent trace lies in RP1 minus the boundary tangent line, a contractible interval; its base trace is constant. Hence its cover monodromy is zero. If both endpoints are distinct marks q0,q1, the loops κs(t)=γt(s) for 0<s<1 are freely homotopic as s varies, and thus have the same winding about every mark. Near q0 all windings except the one about q0 vanish, while near q1 all except the one about q1 vanish. Comparing these tuples shows that every winding is zero. For small s>0, κs(t)−q0=sγt′(0)+o(s) uniformly in t, so the nonzero vector loop γt′(0) also has winding zero; the tangent-line trace at γt(s) converges to its projectivization, and thus has zero fibre winding. The two coordinates of the covering monodromy in [L4] are consequently zero. The deck shift is constant along the connected arc, so in both endpoint cases (r1,r2)=0. This is the endpoint comparison of Khovanov--Seidel Lemma bigrading-isotopy, printed p. 24, with the tangent contribution made explicit.

2.1L2step 1.1step 1.2step 1.3step 1.4∎

Conclusion and isotopy lifting. Steps 1.1 and 1.2 give the existence criterion, step 1.3 gives uniqueness up to a unique deck element, and step 1.4 gives freeness on isotopy classes. Parametrize an arc isotopy by a fixed interval with its marked ends removed. Its tangent sections give a homotopy into P, which lifts uniquely from a prescribed initial bigrading by [L2]; interpreting the lifted map on each moving arc gives the required bigraded isotopy. No choice principle is used.

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The graded Grothendieck group is free on the vertex-projective classes

Statement

Let G(Am)=K0(Cm) be the graded Grothendieck group of The graded Grothendieck group of A_m. Then G(Am) is a free Z[q,q−1]-module with basis [P0],[P1],…,[Pm]. Equivalently, the comparison isomorphism K0(Cm)≅K0split(proj⁡grAm) sends the class [X] of a bounded complex X of finite graded projectives to its Euler class ∑n(−1)n[Xn], the split Grothendieck group is free abelian on the classes [Pi{r}], and the internal-shift rule [Pi{r}]=qr[Pi] identifies it with ⨁i=0mZ[q,q−1] [Pi].

Facts & Assumptions

Given: An integer m≥1, the category Cm=Kb(proj⁡grAm) with its triangulation and the equivalence Θ:Cm→Db(Am-mod), the graded Grothendieck group G(Am)=K0(Cm), and the split Grothendieck group of the finite graded projectives.

[L1]

G(Am)=K0tri(Cm) is the free abelian group on the isomorphism classes of Cm modulo the triangle relations [Y]=[X]+[Z], with [X⊕Y]=[X]+[Y], [X[1]]=−[X] and a Z[q,q−1]-module structure with [X{r}]=qr[X] (The graded Grothendieck group of A_m, Homological and internal shifts on K_0(C_m)).

[L2]

Θ:Cm→Db(Am-mod) is exact, full, faithful and essentially surjective; every bounded complex of finitely generated graded Am-modules is isomorphic in Db(Am-mod) to the image of an object of Cm, so every such complex is perfect, and Θ induces an isomorphism K0(Cm)≅K0tri(Dperf(Am)) (The bounded projective comparison for the derived category, The bounded projective homotopy category C_m and the two shifts).

[L3]

For any unital ring the degree-zero inclusion of finitely generated projectives induces an isomorphism K0split(Proj⁡fg)→K0tri(Dperf) whose inverse sends a perfect object represented by a bounded finite-projective complex P to ∑n(−1)n[Pn]; the same holds in the graded setting with degree-zero maps (Triangle K0 of perfect complexes equals split K0 of finite projectives).

[L4]

Every finitely generated graded projective left Am-module is isomorphic to a finite direct sum ⨁i,rPi{r}⊕ai,r with unique multiplicities, and the classes [Pi{r}] are linearly independent in the split Grothendieck group of the additive category of finite graded projectives (Finite graded projectives are sums of shifted vertex projectives, Split Grothendieck group of an additive category).

Proof

technique · direct
1.1L1L2L3

K0(Cm) is the split Grothendieck group of finite graded projectives. By [L2] the functor Θ is an exact equivalence onto the perfect objects, so it induces a bijection on isomorphism classes preserving cones and shifts and hence an isomorphism of abelian groups K0(Cm)→K0tri(Dperf(Am)); by [L3] this group is identified with K0split(proj⁡grAm) through the Euler class ∑n(−1)n[Xn]. Composition gives the displayed comparison isomorphism.

1.2L4

Freeness of the split group. By [L4] every finite graded projective is a finite direct sum of shifts of the Pi with unique multiplicities, so the split Grothendieck group is free abelian with basis the classes [Pi{r}], 0≤i≤m, r∈Z; there are no relations among distinct pairs by uniqueness.

2.1step 1.2L1

The Z[q,q−1]-action on the basis. The internal shift is an automorphism of Cm commuting with Θ, so its induced operator q on K0(Cm) is invertible and qr[Pi]=[Pi{r}] by [L1]; hence the free abelian group ⨁i,rZ[Pi{r}] acquires the Z[q,q−1]-module structure of ⨁i=0mZ[q,q−1][Pi], with the q-action shifting the basis.

3.1step 1.1step 1.2step 2.1∎

Conclusion. G(Am) is a free Z[q,q−1]-module with basis [P0],…,[Pm], and the Euler-class comparison identifies it with the split Grothendieck group of finite graded projectives; the freeness uses the explicit classification of finite graded projectives and no finite-dimensional-field-algebra structure theorem. No choice principle is used.

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String types and their contributions to geometric intersection numbers

Statement

Assume AC (The Axiom of Choice) for the supplied well-definedness and isotopy invariance of geometric intersection numbers.

Let c be an admissible curve in normal form with respect to a basic system and the vertical curves, and fix 0≤k≤m (Basic arcs, admissible curves and the standard normal form). Then the ordinary geometric intersection number I(bk,c) is the sum, over the k-strings of c, of the following contributions:

  • for k>0: a k-string of type I, II, II′ or VI contributes 1; one of type III or III′ contributes 1/2; all other types contribute 0;
  • for k=0: the types VII,VIII,IX,X,XI contribute 0,1,1/2,1,1/2 respectively.

For an integer-indexed family with k>0, applying the half twist about bk to a string type u shifts the type index by one, u↦u+1, so together with the base contributions the table determines I(bk,c) completely.

Facts & Assumptions

Given: The standard picture with the basic arcs b0,…,bm, vertical curves d0,…,dm, their regions D0,…,Dm+1, and the finite list of segment and string types of Basic arcs, admissible curves and the standard normal form; an admissible curve c in normal form and an index k. For k>0, let tk denote the half twist about bk; the nested Dehn twists τj are different maps.

[A1]

AC is inherited from the representative-independence and isotopy-invariance supplier in [L2] (The Axiom of Choice); the local counting uses only finitely many string models.

[L1]

The k-strings of c are the connected components of c∩(Dk∪Dk+1), their types are the isotopy classes of Figures 15-18, and, for k>0, the k-strings of c correspond bijectively to those of tk(c) after normalizing inside Dk∪Dk+1 (Khovanov–Seidel, Proposition 3.17, printed p. 29) (Basic arcs, admissible curves and the standard normal form).

[L2]

Under AC, I is independent of minimal representatives and invariant under the specified isotopies. The arc bk lies in Dk∪Dk+1 and crosses only dk; for k>0 both endpoints are marked, while b0 has one boundary endpoint, for which the positive-push convention applies. Every intersection with bk is assigned to the corresponding k-string (Curves and geometric intersection numbers on the marked disk, Geometric intersection numbers are isotopy invariants).

[L3]

The types and their drawn models are fixed: for k>0 one has the families Iu,IIu,IIu′,IIIu,IIIu′ and the exceptional types IV,IV′,V,V′,VI; for k=m the families IIu,IIIu and the exceptional types V,VI; for k=0 the five exceptional types VII,VIII,IX,X,XI; in the integer-indexed families for k>0, the type u+1 is obtained from the type u by the half twist about bk (Basic arcs, admissible curves and the standard normal form).

Proof

technique · direct
1.1A1L1L2L3

Reduction to the string models. The fixed basic arc bk is contained in Dk∪Dk+1, with its unique dividing-arc crossing on dk. Use the source's relative minimal-position construction, fixing all di for i≠k SETWISE: remove innermost removable bigons within the two-region union, allowing the string ends to slide along its dividing boundary. The resulting model realizes the source lower bound for every string simultaneously (KS proof of the string-contribution lemma, printed pp. 29–31). For k=0, make the prescribed small positive boundary push first; its cyclic endpoint order is unchanged during this local comparison. The weighted intersection count of the resulting minimal model is consequently the sum of the individual model counts, not an alleged additivity of I under arbitrary isotopies.

2.1step 1.1L2L3

The contributions of the individual types. For each of the finite types, the source's Figures 15-18 exhibit the string and its position relative to bk, and the count is a finite local computation: a type I, II or II′ string crosses bk once, while type VI is the basic arc itself and its minimal push-off has two common marked endpoints, a type III or III′ string has exactly one marked endpoint in common with bk and no interior crossing, and the types IV,IV′,V,V′ are disjoint from bk; correspondingly the contributions are 1, 1/2 and 0 by the half-weight convention. For k=0 the five exceptional types give the listed values 0,1,1/2,1,1/2. Each case is a local picture: the explicit isotopy of step 1.1 attains the displayed lower bound because it removes all other intersections with bk.

3.1step 2.1L1L2L3

The shift of the index. For k>0 and an integer-indexed family, [L1] says the half twist tk maps the set of k-strings of c bijectively onto those of tk(c) and maps the type u to the type u+1 by definition of the families [L3]; the contribution table is therefore indexed by the integer u with the fixed base values of step 2.1, and tk fixes bk setwise. Simultaneous transport preserves the weighted intersection count, so I(bk,tk(c))=I(bk,c); hence the base values apply to every integer u, positive or negative. Summing these values and the exceptional contributions determines I(bk,c).

4.1A1step 1.1step 2.1step 3.1∎

Conclusion. I(bk,c) is the sum of the contributions of its k-strings as displayed, and the type shift by the half twist is u↦u+1; AC is inherited only for the supplied well-definedness and isotopy invariance of I, while the counts are finite checks in the fixed standard picture.

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The standard twists commute and fix the complementary basic arcs

Statement

In the standard picture of the basic arcs b0,…,bm and the nested curves l0,…,lm−1 of Basic arcs, admissible curves and the standard normal form, let τj be the positive Dehn twist about lj and let G be the boundary-fixed mapping class group. Then the twists commute, [τi,τj]=1in G for all i,j, and τj(bk)≃bkfor all k≠j. Consequently τj induces the identity on every bk with k≠j, and for any integers e0,…,em−1 and any j one has (∏i=0m−1τiei)(bj)≃τjej(bj).

Facts & Assumptions

Given: The fixed standard picture with basic arcs b0,…,bm, nested curves l0,…,lm−1, their classes [τj]∈G, and the isotopy relation of Basic arcs, admissible curves and the standard normal form.

[L1]

The standard lj bounds the disk containing precisely {qj,…,qm}, and their small supporting annuli are pairwise disjoint, contain no marks and meet only bj among the basic arcs (Basic arcs, admissible curves and the standard normal form).

[L2]

A curve disjoint from the support of a diffeomorphism is fixed pointwise. Thus a curve with such a representative is fixed up to isotopy, since diffeomorphisms transport isotopies (Curves and geometric intersection numbers on the marked disk).

[L3]

Dehn twists about disjoint simple closed curves commute: the two twists have disjointly supported representatives, and the composites τiτj and τjτi agree pointwise because each twist acts as the identity on the support of the other (Boundary-fixed mapping class group of a punctured disk, Curves and geometric intersection numbers on the marked disk).

Proof

technique · direct
1.1L1L3

Commutation. Choose representatives Ti,Tj of τi,τj supported in closed annular neighbourhoods of li,lj; since li∩lj=∅ and the annuli can be chosen disjoint and contained in D∘∖Δ [L1], the composites TiTj and TjTi agree: on the support of Ti the map Tj is the identity, and conversely. Hence [τi,τj]=1 in G for all i,j, including i=j.

1.2L1L2

The twists fix the complementary arcs. If k≠j, the fixed basic arc bk is disjoint from the chosen supporting annulus of τj by [L1]: for k<j it lies outside the enclosed suffix disk, and for k>j it lies inside that disk away from its boundary. Thus the chosen representative is the identity on bk, and τj(bk)≃bk.

2.1step 1.1step 1.2

The composite clause. Let e0,…,em−1∈Z and fix j. For i≠j the twist τi fixes bj up to isotopy by step 1.2; by induction on the number of factors and the commutation of step 1.1, (∏i≠jτiei)(bj)≃bj and the factors can be moved past τjej with the identities τiτj=τjτi; hence (∏iτiei)(bj)≃τjej(bj).

3.1step 1.1step 1.2step 2.1∎

Conclusion. The nested twists commute, fix the complementary basic arcs, and their composites act on bj through τjej alone. No choice principle is used; all incidences are finite checks in the fixed standard picture.

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The Khovanov-Seidel complexes give a weak derived braid action

Statement

Fix m≥1 and let Cm=Kb(proj⁡grAm) be the bounded homotopy category of finite graded projective left Am-modules. Choose a signed word t(β) representing each β∈Bm+1, with t(1) the empty word, and let Gβ=Rt(β) be its complex from The complex of a braid word. Define F1=Id⁡Cm and Fβ=Gβ⊗Am− for β≠1. Then the assignment β⟼Fβ defines a weak action of the braid group Bm+1 (The braid group by Artin presentation) on Cm in the sense of Weak action of a group on a category:

  1. F1=Id⁡Cm exactly;
  2. every Fβ is an equivalence of Cm, and
  3. for all β,γ∈Bm+1 the functors Fβγ and FβFγ are naturally isomorphic.

Explicitly, for any two words presenting the same element, a chosen finite sequence of defining relation moves gives an explicit homotopy equivalence between their complexes, so the action is well defined up to isomorphism by the presentation of Bm+1. No independence of that chosen sequence is asserted. No coherence of the isomorphisms is claimed: the action is weak and is not asserted to be a genuine 2-action.

Facts & Assumptions

Given: An integer m≥1, the generators σ1,…,σm and defining relations of the presented braid group Bm+1, the word complexes Rσ of The complex of a braid word and their functors on Cm.

[L1]

For every word σ the complex Rσ is a bounded complex of graded (Am,Am)-bimodules with two-sided finite graded projective terms, and its action Rσ⊗Am− is an exact triangulated endofunctor of Cm agreeing with the derived tensor product (The complex of a braid word).

[L2]

RiRi−1≃Id⁡Cm≃Ri−1Ri for every i (The generator complexes are mutually inverse).

[L3]

RiRj≅RjRi for ∣i−j∣>1 (Far commutativity of the generator complexes).

[L4]

RiRi+1Ri≅Ri+1RiRi+1 for 1≤i≤m−1 (The three-term braid relation).

[L5]

Bm+1 is presented by the generators σ1,…,σm subject to the relations σiσi−1=1=σi−1σi, σiσj=σjσi for ∣i−j∣>1 and σiσi+1σi=σi+1σiσi+1; consequently a group homomorphism or an assignment on words satisfying these relations up to the appropriate equivalences is well defined on the presented group, and any two words for the same element are related by a finite sequence of insertions and deletions of these relators (The braid group by Artin presentation, Group presentation by generators and relations, Von Dyck's theorem: maps of generators that satisfy the relators extend uniquely from a presented group).

[L6]

The empty tensor product is the diagonal bimodule Am concentrated in degree 0, and Am⊗AmM≅M naturally, so R1≃Id⁡Cm (The complex of a braid word, Signed totalization of graded A_m-bimodule actions).

Proof

technique · direct
1.1L1L2L6

Every Fβ is an equivalence. For β≠1, [L1] makes Gβ⊗Am− an endofunctor of Cm, and the generator inverse relations of [L2], applied factor by factor with tensor associativity, identify its composites with the functor of the literal reversed inverse word as the identity; the empty-word functor is canonically the identity by [L6]. Thus Fβ is an equivalence with inverse the functor of that literal inverse word, up to the canonical unit identification. For β=1 the claim holds by the definition F1=Id⁡.

1.2L2L3L4

The defining relations hold up to natural isomorphism. The inverse-cancellation relation is [L2], far commutativity is [L3], and the three-term Artin relation is [L4]; for each of these the two functors are respectively naturally isomorphic, and the isomorphisms are compatible with concatenation of words because both sides are computed by the same balanced tensor product of the word complexes [L1].

2.1step 1.2L1L5L6

Well-definedness on braid words. Let σ=τ1⋯τk be a word and let σ′ be obtained from it by one of the elementary moves of [L5]: inserting or deleting σi±1σi∓1, commuting two far-apart letters, or replacing σiσi+1σi by σi+1σiσi+1. Each move replaces Rσ by a naturally isomorphic functor by step 1.2, since the tensor product identifies the segments of the word and the isomorphisms compose; by induction on the number of moves, any two words presenting the same element of Bm+1 yield naturally isomorphic functors. Hence the assignment β↦Fβ is well defined up to natural isomorphism on the presented group, with F1 represented by the identity functor rather than merely by an isomorphic empty-word functor.

3.1step 2.1L1L6

The weak-action axioms. By definition F1=Id⁡Cm. If β,γ≠1, concatenating their chosen words gives Gβ⊗AmGγ≃Gβγ up to the natural isomorphism of step 2.1; tensoring with an input complex gives FβFγ≅Fβγ, using [L6] when βγ=1. If one of β,γ is 1, the corresponding composite is identified with the other functor by the canonical tensor unit isomorphism (and is literally composition with Id⁡ on the functor side). Thus the weak-action unit and pairwise-isomorphism conditions hold. No compositors satisfying a pentagon are produced or claimed.

4.1step 1.1step 2.1step 3.1∎

Conclusion. The functors Fβ define a weak action of Bm+1 on Cm: the assignment is well defined up to natural isomorphism on words for the same braid (step 2.1), every value is an equivalence (step 1.1), and the identity functor is assigned exactly to 1 with the pairwise isomorphisms supplied in step 3.1. No coherence upgrade is claimed.

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The complex of an admissible bigraded curve

Definition

Fix the normalized bigradings d~i,b~i of Bigraded string types and their contributions to I^{bigr}. Let c~ be an admissible bigraded curve in normal form with respect to the fixed basic set and vertical curves (Basic arcs, admissible curves and the standard normal form), with crossing set cr⁡(c~) and local index (x1,x2):=μbigr(d~x0,c~;x)∈Z2 at each crossing x; here x0 denotes the index of the vertical curve dx0 containing x, so that x∈dx0, and for a crossing of the underlying curve c the local index of the bigrading is interpreted through the identification of the crossings of c~ with those of c (Local indices and bigraded intersection numbers). Put P(x):=Px0[−x1]{x2}∈Cm,L(c~):=⨁x∈cr⁡(c~)P(x), the direct sum of shifted vertex projectives indexed by the crossings, where Px0=Amex0 is the vertex projective of Finite graded A_m-modules, internal shifts and the vertex projectives and the two shifts are the homological shift [−x1] and the internal shift {x2}.

The differential. For crossings x,y which are the two endpoints of an essential segment of c and satisfy y1=x1+1, define the component ∂yx ⁣:P(x)⟶P(y) by the following rules, right multiplication meaning the left Am-linear map Amei→Amej, u↦ua, for a∈eiAmej:

  1. if x0=y0 (in which case x2=y2+1), then ∂yx is the right multiplication by the return (x0∣x0−1∣x0) when x0>0, and is the zero map when x0=0 (the return (0∣1∣0) vanishes);
  2. if x0=y0±1, then ∂yx is the right multiplication by the arrow (x0∣y0), which is (x0∣x0−1) or (x0∣x0+1);
  3. otherwise ∂yx:=0.

Put ∂:=∑x,y∂yx. For a bigraded k-string g~ of c~ the same formulas applied to the crossings and essential segments of g define an object L(g~) with its differential, and the underlying graded module of L(g~) is an abelian subgroup of L(c~).

Claims. (L(c~),∂) is a bounded complex of finitely generated graded projective left Am-modules with a differential that is degree zero for the internal grading, hence an object of Cm=Kb(proj⁡grAm); the object is bounded because there are finitely many crossings; and the deck action translates into the shift rule L(χ(r1,r2)c~)≅L(c~)[−r1]{r2} by the degreewise sign identification described in the proof. These claims are proved below.

Facts & Assumptions

Given: An admissible bigraded curve c~ in normal form with finitely many crossings x=(x0;x1,x2), its essential segments classified by the six types of Figure 12 and the endpoint types of Figures 13-14, and the vertex projectives Pi=Amei with these typed right multiplication maps.

[L1]

The crossing set is finite, each essential segment has two crossings as endpoints, and for every essential segment with endpoints x,y one has y1=x1±1; the segment types 1,1′,2,2′ are the essential ones and the tables of Figures 12-14, in the normalization of Bigraded string types and their contributions to I^{bigr}, record the internal indices at their endpoints: for a segment whose endpoints satisfy y1=x1+1 one has either x0=y0 and x2=y2+1, or x0=y0±1 (Basic arcs, admissible curves and the standard normal form, Local indices and bigraded intersection numbers).

[L2]

For x0>0, (x0∣x0−1∣x0) is the return at x0, of internal degree 1, and (x0∣y0) is either the ascending arrow (x0∣x0+1) of internal degree 0 or the descending arrow (x0∣x0−1) of internal degree 1; the product of two arrow classes is zero whenever it is defined as a path of length two other than a return, the return at vertex 0 is zero, and every path of length at least three vanishes in Am (The 4m+1 path basis).

[L3]

Pi=Amei is a finitely generated graded projective left Am-module, right multiplication by a homogeneous element a∈Am is a degree-zero map Pi{r}→Pj{r−deg⁡a} when a lies in eiAmej, the homological shift and the internal shift act as displayed, and Cm is the homotopy category of bounded complexes of such modules (Finite graded A_m-modules, internal shifts and the vertex projectives).

[L4]

The deck action adds (r1,r2) to the local indices of all crossings: χ(r1,r2) replaces (x1,x2) by (x1+r1,x2+r2) for every crossing x (Local indices and bigraded intersection numbers, The Z^2 cover of the projectivized tangent bundle and bigraded curves).

Proof

technique · direct
1.1L1L2

The composites of two differential components vanish. Let x,y,z be crossings with ∂yx≠0≠∂zy, so that y1=x1+1, z1=y1+1 and the pairs (x,y), (y,z) are endpoints of essential segments; the composite is right multiplication by the concatenation of the two path labels. If either label is a return, its length is at least three, so it vanishes by [L2]. If both labels are arrows and x0≠z0, they form a monotone length-two path, which also vanishes. The remaining case would have x0=z0=y0±1. Both segments would then lie in the same region between these adjacent dividing curves and approach y from the same side of dy0. This contradicts transversality at the crossing y, where the two branches of the embedded curve lie on opposite sides of dy0. Thus no such consecutive arrow return occurs, and every composite is zero. Summing the components gives ∂2=0.

1.2L1L3L4

The shift rule. Under χ(r1,r2) the local index of each crossing x becomes (x1+r1,x2+r2) by [L4], and the crossing data (which crossings are joined by essential segments, and the segment types) are unchanged because the deck action changes only the bigrading, not the underlying curve or its normal form; the source retains the same path entries, while the homological shift [−r1] multiplies the target differential by (−1)r1. Map the summand indexed by x by (−1)r1x1 times the identity. For a nonzero entry x→y one has y1=x1+1, so the target differential followed by the source sign agrees with the target sign followed by the source differential. These invertible sign maps give the claimed chain isomorphism. An identity on every summand would fail for odd r1.

2.1step 1.1L1L3

The differential is degree zero and the terms are finite graded projective. For a component given by right multiplication by a path a∈ex0Amey0 of internal degree δ, an element of underlying degree d has source shifted degree d+x2 and target shifted degree d+δ+y2. The segment tables in [L1] give δ=x2−y2: a return has δ=1, an ascending arrow has δ=0, and a descending arrow has δ=1. Thus both degrees agree. The map is left Am-linear because (bu)a=b(ua), and its image lies in Amey0 because a=ex0aey0; no right-module structure on Amex0 is assumed. Homological degree rises from x1 to y1=x1+1. Each term is a shifted finite graded vertex projective, and there are finitely many crossings; together with step 1.1 this gives a bounded complex of the required bidegree.

3.1step 1.1step 2.1step 1.2∎

Conclusion. (L(c~),∂) is a bounded complex of finite graded projectives with a degree-zero differential, so it defines an object of Cm, and the deck action acts by the shift [−r1]{r2}. No choice principle is used; the verifications are finite checks over the segment types.

LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passOpen item page →

The standard nested twists generate a free abelian subgroup

Statement

The subgroup ⟨[τ0],…,[τm−1]⟩ of G=π0Diff⁡(D,∂D;Δ) generated by the classes of the standard nested twists is free abelian of rank m; equivalently, if ∏j=0m−1τjej is isotopic to the identity in G, then e0=⋯=em−1=0.

Facts & Assumptions

Given: The fixed nested picture of Basic arcs, admissible curves and the standard normal form, the twists τj about lj and their classes in G, and an exponent vector (e0,…,em−1)∈Zm.

[L1]

The twists commute, [τi,τj]=1, and τj fixes every basic arc bk with k≠j up to isotopy (The standard twists commute and fix the complementary basic arcs).

[L2]

In the standard picture, lj encloses the suffix {qj,…,qm} and a positive Dehn twist can be represented by the endpoint of an unmarked disk isotopy rotating the enclosed disk through one full turn, interpolated to the identity across its supporting annulus (Basic arcs, admissible curves and the standard normal form). These endpoints fix every marked point.

[L3]

A closed nonzero-vector path has an integer winding, obtained by normalizing it to the unit circle. This integer is invariant under homotopy and additive under concatenation; one positive turn has winding 1 (The trigonometric loops give π1({(x,y):x2+y2=1},(1,0))≅Z). Reversing the twist convention changes all computed signs together and does not affect the argument.

Proof

technique · direct
1.1L2L3

Pair windings detect the twist exponents. For 0≤k<m, follow the pair (qk,qm) during an unmarked isotopy from the identity to τj, and take the winding of their nonzero difference. In the standard circular model of [L2], if j≤k both points are inside the rotating disk and their difference makes one full turn, giving 1. If j>k, only qm moves, and its path lies in a disk not containing qk, so the difference loop has winding zero. Concatenation gives pair winding ∑j=0kej for the standard unmarked isotopy to ∏jτjej; negative exponents reverse the corresponding paths.

2.1L3step 1.1

A relation has zero pair windings. Suppose that product is isotopic to the identity relative to the boundary and the marked set. Append that marked isotopy to the unmarked isotopy in step 1.1; the marks are constant on the appended part, so it does not change the pair windings. This produces a loop ft in the group of boundary-fixed homeomorphisms of the unmarked unit disk. It contracts by the explicit Alexander formula As(f)(x)=sf(x/s) for ∣x∣≤s, As(f)(x)=x for ∣x∣≥s, and A0(f)=id. The two formulas agree on ∣x∣=s because f fixes the boundary; each As(f) is a homeomorphism, and continuity at s=0 follows from ∣As(f)(x)−x∣≤2s. Applying this contraction to the loop ft gives a homotopy of each pair's nonzero difference loop to the constant loop. Thus every winding from step 1.1 is zero.

3.1step 1.1step 2.1algebra

The triangular equations force all exponents to vanish. For k=0 the zero-winding equation is e0=0. For each 1≤k<m, subtract the equation for k−1 from that for k to obtain ek=0. Hence the only relation among the commuting twists is the trivial exponent vector.

4.1L1step 3.1∎

Conclusion. Commutation [L1] defines a surjective homomorphism Zm onto the generated subgroup, and step 3.1 proves it is injective. Thus that subgroup is free abelian of rank m, including m=1, when the single pair winding detects τ0. The proof uses explicit isotopies and finitely many windings and requires no choice axiom.

LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passOpen item page →

The preferred lift of a half twist shifts the bigrading by chi(-1,1)

Statement

Let c be a curve joining two marked points, τ the half twist along c (the elementary geometric half twist of The elementary geometric half twist, its support disc, and its opposite, supported in a regular neighbourhood of c), and τ~ its preferred lift to the cover P~ of The Z^2 cover of the projectivized tangent bundle and bigraded curves. Then τ~(c~)=χ(−1,1)c~ for every bigrading c~ of c. For the following bigraded intersection-number consequence, assume AC (The Axiom of Choice) as inherited from its well-definedness suppliers. In particular, for 1≤k≤m and a basic arc of Basic arcs, admissible curves and the standard normal form b~k and its preferred half-twisted image one has Ibigr(b~k,τ~k(c~))=(q1−1q2) Ibigr(b~k,c~), the factor responsible for the shift u↦u+1 in the string tables.

Facts & Assumptions

Given: A curve c joining two marked points, its half twist τ with preferred lift τ~, a bigrading c~, and the cover π~:P~→P classified by the cohomology class C with C([RP1×point])=(1,0) and C([point×λz])=(−2,1).

[A1]

AC is inherited for the bigraded intersection-number invariance used in [L3] (The Axiom of Choice); the deck-element computation for the actual half twist uses only the specified cover and lift.

[L1]

τ preserves c and reverses its orientation; τ~ is the unique lift acting trivially on the fibres over the tangent lines of ∂D (The Z^2 cover of the projectivized tangent bundle and bigraded curves, Curves and geometric intersection numbers on the marked disk).

[L2]

A curve joining two marked points has a bigrading, and any two bigradings of it differ by a unique deck element; equivalently, isotopy classes of bigraded curves are acted on freely by Z2 (Existence and rigidity of bigradings).

[L3]

Under AC for the supplied intersection-number invariance, the deck action changes local indices by translation, and the transformation rules of Ibigr are Ibigr(f~(c~0),f~(c~1))=Ibigr(c~0,c~1) for an actual boundary-fixed diffeomorphism f (or its induced action on bigraded isotopy classes) and Ibigr(c~0,χ(r1,r2)c~1)=q1r1q2r2Ibigr(c~0,c~1) (Local indices and bigraded intersection numbers).

Proof

technique · direct
1.1L1L2

The deck element exists and is unique. Since τ(c)=c, the preferred lift sends the bigrading c~ of c to a bigrading τ~(c~) of the same curve c; by [L2] there is a unique (r1,r2)∈Z2 with τ~(c~)=χ(r1,r2)c~, and it is independent of the chosen bigrading because the deck group is abelian and acts freely. The whole content of the lemma is the computation of (r1,r2).

1.2L1

The test loop in P and its class. Use the standard rotational half-twist representative along c, conjugated from a round support disk; its midpoint is its unique fixed point on c, its derivative there is −I, and it is the identity near ∂D. Choose the standard embedded path β:[0,1]→D∖Δ from the boundary to that midpoint, as in source Figure 9, with nonzero endpoint tangents. Let π ⁣:[0,2]→P be the closed path π(t):=Rβ′(t)  (0≤t≤1),π(t):=Dτ(Rβ′(2−t))  (1≤t≤2), where Rv denotes the tangent line spanned by v; the two halves match at t=1 because Dτ=−I at the midpoint fixes every projective tangent line, and the endpoint lines at the boundary match because τ is the identity nearby, and π is a loop in P. For this standard path, the source's Figure 9 computation gives [π]=−[RP1×point]−[point×λz] for one endpoint z of c; this is the literature calculation in Khovanov--Seidel Lemma half-twist, printed pp. 24--25. Transport by the support-disk coordinates preserves its value under the covering class because all positive puncture loops have monodromy (−2,1).

2.1step 1.1step 1.2

The value of the deck element. By the definition of the local index and the preferred lift, the deck element (r1,r2) comparing τ~(c~) with c~ is obtained by evaluating the classifying class C on the loop of tangent lines swept by the preferred lift of τ along c, which is the class [π] of step 1.2; hence (r1,r2)=−C([π])=C([RP1×point])+C([point×λz])=(1,0)+(−2,1)=(−1,1). This proves the main formula.

3.1A1step 2.1L3∎

The consequence for the string tables. The half twist τk along bk is the preferred lift acting on bigraded curves, so by [L3] and the main formula Ibigr(b~k,τ~k(c~))=Ibigr(τ~k−1b~k,c~)=Ibigr(χ(1,−1)b~k,c~)=(q1−1q2)Ibigr(b~k,c~), where the first equality uses the invariance of Ibigr under the preferred lifts and the second uses that τ~k−1 acts on b~k by χ(1,−1) by the main formula applied at index k. Applied to a k-string, this is the factor (q1−1q2)u of the source's table. For other representatives of the same half-twist class, the same identities hold on bigraded isotopy classes by the homotopy-lifting and freeness suppliers. AC is inherited for the supplied bigraded intersection-number invariance in this consequence.

LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passOpen item page →

Bigraded string types and their contributions to I^{bigr}

Statement

Assume AC (The Axiom of Choice) for the supplied well-definedness and isotopy invariance of ordinary and bigraded intersection numbers.

Fix bigradings b~k,d~k of the basic arcs and vertical curves normalized by Ibigr(d~k,b~k)=1+q1−1q2,Ibigr(b~k,b~k+1)=1(0≤k≤m in the first equation, 0≤k<m in the second), which determine the bigradings uniquely up to an overall shift χ(r1,r2). For every admissible bigraded curve c~ in normal form the bigraded intersection number Ibigr(b~k,c~) is computed by summing the contributions of the bigraded k-strings of c~ according to the following table: for k>0, I0(0,0)↦q1+q2,II0(0,0)↦q1+q2,II0′(0,0)↦1+q1q2−1,III0(0,0)↦q2,III0′(0,0)↦1, the exceptional types IV,IV′,V,V′ all contribute 0, and VI(0,0) contributes 1+q2; a general type Iu(r1,r2) (and likewise for the other families) contributes the value of its u=0 member multiplied by q1r1q2r2(q1−1q2)u; for k=0 the zero-parameter types VII(0,0),VIII(0,0),IX(0,0),X(0,0),XI(0,0) contribute 0, q1q2−1+1, 1, q1q2−1+1, 1 respectively; a type with parameters (r1,r2) has this value multiplied by q1r1q2r2. In particular, VI(r1,r2) means χ(r1,r2)b~k and XI(r1,r2) means χ(r1,r2)b~0, as in the source’s printed p. 32.

Facts & Assumptions

Given: AC, the fixed standard picture, the normalized bigradings b~k,d~k, a bigraded curve c~ in normal form, and the type tables of Figures 15-18 together with the local index decorations of Figures 12-14.

[A1]

AC is inherited for the representative-independence and isotopy-invariance assertions used in [L2] and [L3] (The Axiom of Choice); the normalization of the fixed arcs and the finite local-index computations require no additional choice.

[L1]

In the standard picture dk crosses bk once in the interior and adjacent basic arcs share one marked endpoint (Basic arcs, admissible curves and the standard normal form). Bigradings of these arcs exist and differ by unique deck elements (Existence and rigidity of bigradings).

[L2]

Under AC, ordinary intersection weights add over the k-strings in their minimal models (String types and their contributions to geometric intersection numbers). In such a model, each unmarked intersection contributes (1+q1−1q2)q1μ1q2μ2 and each marked endpoint contributes q1μ1q2μ2 (Local indices and bigraded intersection numbers). The relative minimal-position construction fixing the other dividing arcs is the one in Khovanov–Seidel's proof of Lemma 3.18, printed pp. 29–31.

[L3]

For k>0, the preferred half-twist lift satisfies t~k(b~k)=χ(−1,1)b~k, only asserting a deck shift for its supporting arc (The preferred lift of a half twist shifts the bigrading by chi(-1,1)). Under AC for the supplied bigraded intersection-number invariance, simultaneous transport preserves local indices, while shifting the second bigrading by χ(r1,r2), or the first by χ(−r1,−r2), multiplies each contribution by q1r1q2r2 (Local indices and bigraded intersection numbers).

[L4]

The k-string Iu+1(r1,r2) is obtained from Iu(r1,r2) by applying the half twist about bk; the same holds for the other families, and the exceptional types are fixed or shifted according to Figure 15 (Basic arcs, admissible curves and the standard normal form).

Proof

technique · direct
1.1L1L2L3

Normalization. Each dk,bk pair has one interior crossing, so its bigraded value is a monomial times 1+q1−1q2; each defined adjacent pair bk,bk+1 has one common marked endpoint, so its value is a monomial. Choose the bigrading of b0, then successively shift bk+1 to make each adjacent monomial 1, and finally shift each dk to make its crossing monomial 1. Deck freeness makes these relative shifts unique. All simultaneous shifts of both families cancel in the relative indices and preserve these equations; hence the only ambiguity is a common overall shift. A shift of c~ alone multiplies its contributions by the stated monomial. At q1=q2=1 the normalizations are 2=2I(dk,bk) and 1=2I(bk,bk+1), consistent with the ordinary half weights.

1.2L2L4

The tables at the base parameters. Put each string into the relative minimal model used in the ordinary contribution lemma. The clockwise local-index paths in the decorated Figures 12–18 give, for k>0, an interior index (1,0) for I0,II0, an interior index (1,−1) for II0′, and a marked-end index (0,1) for III0 and (0,0) for III0′. The types IV,IV′,V,V′ are disjoint from bk. Multiplying interior monomials by 1+q1−1q2 gives q1+q2,q1+q2,1+q1q2−1; the single marked-end monomials give q2,1. For VI(0,0)=b~k, a minimal self push-off has marked-end indices (0,0),(0,1), hence value 1+q2. For k=0, the positive boundary push gives no intersection for VII, an interior index (1,−1) for VIII,X, and a marked-end index (0,0) for IX,XI, yielding 0,1+q1q2−1,1,1+q1q2−1,1. These are the local-index readings in the source’s bigraded string table; the ordinary relative minimal-position construction assigns each intersection to its string and realizes all model counts simultaneously.

2.1step 1.2L3L4

The family index and deck parameters. Write C(b~k,g~) for the local contribution of a bigraded k-string. Transporting its local-index paths by the preferred half twist and using [L3] gives C(b~k,t~kg~)=C(t~k−1b~k,g~)=C(χ(1,−1)b~k,g~)=(q1−1q2)C(b~k,g~). Normalization after twisting preserves these local contributions. By [L4], an integer-indexed type with index u is the u-th preferred half-twist iterate of its zero-index member; iteration gives (q1−1q2)u, also for negative u by inverting the monomial. The deck parameters add q1r1q2r2 by [L3]. Thus every indexed family has the claimed factor, including the shorter list for k=m. Exceptional types and k=0 types have only the deck factor. This uses the shift of the fixed bk, not a deck-shift assertion about g~.

3.1A1step 1.1step 1.2step 2.1∎

Conclusion. The bigraded intersection number Ibigr(b~k,c~) is the sum over the bigraded k-strings of the contributions of the table, and the two normalizing equations determine the two families of bigradings up to an overall deck shift. AC is inherited for the supplied intersection-number invariance; the normalization and finite table calculations require no additional choice.

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The basic arcs detect the identity braid

Statement

Assume AC for the supplied well-definedness and isotopy invariance of geometric intersection numbers, including the normal-form contribution table, and to move between the boundary-fixed mapping class f and its braid class (the Artin-to-smooth dictionary of Basic arcs, admissible curves and the standard normal form, including presentation completeness; the topological comparison is Braid group as boundary-fixed punctured-disk mapping classes). Let b0,…,bm be a basic set of curves in (D,Δ) and let f∈G be a boundary-fixed mapping class. If I(bj,f(bk))=I(bj,f2(bk))=I(bj,bk)for all 0≤j,k≤m, then [f]=1 in G. Both iterates are required: the hypothesis on f alone only forces f to act on the basic arcs as a product of the standard twists, and the second iterate together with the freeness of the twist subgroup is what kills the exponents.

Facts & Assumptions

Given: The standard picture with basic arcs b0,…,bm, nested curves l0,…,lm−1 and twists τj, and a boundary-fixed mapping class f whose intersection table with the basic arcs is the identity table for both f and f2.

[L1]

The action of G on isotopy classes of admissible curves preserves the ordinary intersection number I; the hypotheses of the statement are invariant under replacing the basic set by a G-translate, and the conclusion [f]=1 is conjugation invariant, so it suffices to prove the statement in the standard picture (Basic arcs, admissible curves and the standard normal form, Geometric intersection numbers are isotopy invariants).

[L2]

If g∈G satisfies g(bk)≃bk for all k, then [g]=1: the source's Lemma 3.4 isotopes g to a representative fixing the spine b0∪⋯∪bm pointwise and applies the disk mapping-class theorem, and the endpoint bookkeeping uses that the bk meet only consecutively (Basic arcs, admissible curves and the standard normal form).

[L3]

If c is an admissible curve with I(bj,c)=I(bj,bk) for all j, then, in the standard picture, c≃b0 or τ0−1(b0) when k=0, c≃bk or τk±1(bk) when 1≤k<m, and c≃bm when k=m; the proof is the source's Lemma 3.5, a finite read-off from the intersection tables of the normal form (String types and their contributions to geometric intersection numbers).

[L4]

The twists τj commute, τj fixes bk up to isotopy for k≠j, and the subgroup generated by their classes is free abelian of rank m (The standard twists commute and fix the complementary basic arcs, The standard nested twists generate a free abelian subgroup).

Proof

technique · direct
1.1L1L2

A preliminary identification. Suppose g∈G satisfies g(bk)≃bk for all k. Then [g]=1 by [L2], and in particular g(bk) is isotopic to bk for every k and the intersection table of g with the basic set is the identity table.

1.2L3

The intersection table determines the action on the basic curves. Let c be admissible and suppose I(bj,c)=I(bj,bk) for all j. For k<m, [L3] gives c≃τkν(bk) for an integer ν∈{−1,0,1}, with ν≤0 when k=0; for k=m, it gives c≃bm directly. Consequently, applying this to c=f(bk) for each k separately, there are integers ν0∈{−1,0} and ν1,…,νm−1∈{−1,0,1} with f(bk)≃τkνk(bk)(0≤k≤m−1),f(bm)≃bm.

2.1step 1.1step 1.2L4

An explicit model for f. Let g:=τ0ν0τ1ν1⋯τm−1νm−1∈G. Since the twists commute and τj fixes the complementary basic arcs by [L4], one has g(bk)≃τkνk(bk) for k≤m−1 and g(bm)≃bm; comparing with step 1.2, f(bk)≃g(bk) for every k. Applying step 1.1 to g−1f, which fixes each bk up to isotopy, gives [f]=[g].

3.1step 2.1L4

The same for the square, and comparison of exponents. Applying the same argument to f2, whose intersection table with the basic set is also the identity table by hypothesis, produces integers μ0∈{−1,0} and μ1,…,μm−1∈{−1,0,1} with f2≃τ0μ0⋯τm−1μm−1. Since [f]=[g], one has [f2]=[g]2=∏jτj2νj, and therefore ∏j=0m−1τj2νj−μj≃1.

4.1step 3.1L4

Freeness kills the exponents. By the freeness of the twist subgroup [L4], the relation ∏jτj2νj−μj≃1 forces 2νj=μj for every j. Since each μj lies in {−1,0,1} and each 2νj is even, the only possibility is νj=μj=0 for all j; hence [f]=[g]=1, as required.

5.1L1L3step 4.1∎

Conclusion. The identity intersection table for f and f2 forces [f]=1. AC is inherited through the braid/mapping-class dictionary and the supplied well-definedness and isotopy invariance of geometric intersection numbers used in [L1] and [L3]; the local counts and exponent bookkeeping are finite.

LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passOpen item page →

The curve complex is a complex and is invariant under normal-form moves

Statement

Let c~,c~′ be admissible bigraded curves that are isotopic and both in normal form with respect to the fixed vertical curves (Basic arcs, admissible curves and the standard normal form), and let L(c~),L(c~′) be the complexes of The complex of an admissible bigraded curve. Then L(c~)≅L(c~′)in Cm. More precisely, L(c~) is a complex and the relative isotopy between two normal-form representatives identifies their crossings, essential-segment types and local indices. The resulting permutation of identically shifted projective summands is an explicit chain isomorphism, with the inverse crossing correspondence as inverse; its mapping cone has an explicit contracting homotopy. Stretching or folding the drawn presentation of this same indexed complex changes only its presentation. A half twist is a braid action, not an isotopy move asserted to preserve L. The shift rule L(χ(r1,r2)c~)≅L(c~)[−r1]{r2} is compatible with these identifications.

Facts & Assumptions

Given: Two isotopic admissible bigraded curves in normal form for the fixed dividing curves, with their indexed projective summands and essential-segment differentials.

[L1]

The current definition constructs a bounded complex by assigning P(x)=Px0[−x1]{x2} to each crossing, and path multiplication to the essential segments. Its square-zero verification excludes a consecutive arrow return by transversality, and its deck shift is [−r1]{r2} (The complex of an admissible bigraded curve).

[L2]

Two isotopic normal-form admissible curves are carried to each other by an ambient isotopy preserving each dividing curve SETWISE; thus the isotopy transports their crossing and segment incidences (Basic arcs, admissible curves and the standard normal form). This is the normal-form uniqueness statement of KS, not a half-twist move.

[L3]

Bigrading transport through an isotopy is unique. An isotopy loop of an arc does not insert a deck shift; hence isotopic BIGRADED representatives have identical transported local indices, rather than indices known only up to an arbitrary shift (Existence and rigidity of bigradings).

[L4]

An invertible chain map is a homotopy equivalence, and a complex whose identity is dh+hd is contractible (Complexes, homotopies and contractibility in an additive category).

Proof

technique · direct
1.1L1

The complex and shift. The square-zero verification is [L1], already proved for the actual essential-segment/path rules of the current definition. A deck shift changes each crossing index by (r1,r2), so every summand changes by [−r1]{r2}. The source keeps its path entries, while the homological shift changes their sign by (−1)r1; the supplier’s sign map (−1)r1x1 on the summand indexed by x gives the stated chain isomorphism.

1.2L1L2L3

The crossing correspondence. Use [L2] to transport c~ to c~′, preserving the dividing curves setwise. A crossing with di moves along di and retains its index i, its two local indices by [L3], and the types and orientations of its incident essential segments. Thus its source and target summands are the identical shifted projective. Define Φ on that summand to be the identity into the summand indexed by the transported crossing; define Ψ by the inverse correspondence. Every differential entry is multiplication by the same path before and after transport, so Φd=d′Φ, Ψd′=dΨ, and ΨΦ=id, ΦΨ=id. No arbitrary overall deck shift is introduced for isotopic bigraded representatives.

2.1L4step 1.2algebra

Explicit cone contraction. In the degree-increasing convention the mapping cone of Φ is L(c~′)n⊕L(c~)n+1 with differential D(y,x)=(d′y+Φx,−dx). Define h(y,x)=(0,Ψy). Then Dh+hD=(y,−dΨy+Ψd′y+x)=(y,x) by the chain-map identity. Hence the cone is contractible, and in particular the two complexes are isomorphic in Cm; the displayed maps are stronger than merely homotopy inverses.

3.1step 1.1step 1.2step 2.1∎

Presentations and conclusion. Stretching the curve drawing, grouping the indexed summands into columns, and folding arrows into a complex leave precisely the same summands and differential entries, so their comparisons are the corresponding reindexing chain isomorphisms of step 1.2. Inessential end segments carry no pair of crossing modules and are omitted in the construction, not cancelled through a fabricated identity pivot. Half twists have their separate generator action. The isotopy isomorphism and deck-shift rule therefore prove the full claimed invariance and compatibility without additional choice.

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Curve complexes intertwine the braid generators

Statement

Assume AC, used only for the induction over braid words, which reads a braid as a boundary-fixed mapping class acting on bigraded curves (Basic arcs, admissible curves and the standard normal form, with its Artin completeness and smooth comparison); each local intertwining isomorphism is a finite computation. For every 1≤k≤m and every admissible bigraded curve c~ there is an isomorphism in Cm Rk⊗AmL(c~)≅L(τ~kc~), where τ~k is the preferred lift of the half twist along bk acting on bigraded curves; the inverse-generator analogue Rk−1⊗AmL(c~)≅L(τ~k−1c~) holds as well. Consequently, for every braid σ presented by a word, RσL(c~)≅L(σc~)and, for c~=b~j,RσPj≅L(σb~j), the last isomorphism using L(b~j)≅Pj for the normalized bigradings of the basic arcs.

Facts & Assumptions

Given: The complex L(c~) of an admissible bigraded curve, the twist complex Rk=[Uk→Am], the half twist τk along bk and its preferred lift τ~k, and a braid word σ.

[L1]

L(c~) is a bounded complex of finite graded projectives, the assignment c~↦L(c~) is invariant under normal-form moves and the deck action acts by shifts (The complex of an admissible bigraded curve, The curve complex is a complex and is invariant under normal-form moves).

[L2]

The functors Uk(−)=Uk⊗Am− satisfy Uk(Pj)≅Pk⊕Pk{1} for j=k, Uk(Pk+1)≅Pk, Uk(Pk−1)≅Pk{1}, and Uk(Pj)=0 for ∣j−k∣>1; these are the corner computations behind the Temperley–Lieb relations (Corner computations: the U_i satisfy the Temperley-Lieb relations).

[L3]

For a bigraded k-string g~ of c~, the inclusion of graded modules L(g~)⊆L(c~) is a direct summand in each degree, and the functor Uk applied to it gives an inclusion of complexes UkL(g~)⊆UkL(c~) whenever the crossings of g support the differential components (Signed totalization of graded A_m-bimodule actions, The complex of an admissible bigraded curve).

[L4]

The half twist τk acts on bigraded curves by the preferred lift τ~k, and the normal form of τ~kc~ is obtained from that of c~ by the local moves of Proposition 3.17, which change each k-string to its half-twisted form and leave the rest fixed (Basic arcs, admissible curves and the standard normal form, The elementary geometric half twist, its support disc, and its opposite).

[L5]

Rk⊗AmL is the cone of the map UkL→L induced by βk, and belongs to Cm for every L∈Cm (The twist complexes R_i and R_i^{-1}, Signed totalization of graded A_m-bimodule actions).

[L6]

For a word σ=τ1⋯τk the complex Rσ is the iterated tensor product of the factors Ri±1, and its functor is the composite (The complex of a braid word).

[L7]

The positive and negative generator complexes are two-sided inverse up to bimodule homotopy, and their tensor functors preserve those homotopies (The generator complexes are mutually inverse).

[F1]

Literature input. Khovanov–Seidel Proposition 4.4, Cases 1–5 (printed pp. 38–44) gives the string comparisons relative to the complement ∇; printed pp. 38–40 explain how the local homotopies extend. For type II0, equations (4.7)–(4.8) and the map on printed p. 43 give (x,y,z,w)↦(x,−y−z(k−1∣k),z,−w), together with negation of the attached right tail. The source URL and exact section are in references.

Proof

technique · direct
1.1L2L3

Decomposition into k-strings. Let c~ be an admissible bigraded curve in normal form and fix k. The direct sum decomposition of the graded module L(c~) into its summands P(x) over crossings restricts, over the subsets of crossings lying in a single k-string g~, to a direct sum decomposition L(c~)=⨁g~∈st⁡(c~,k)L(g~)⊕(crossings with ∣x0−k∣>1). Applying Uk, all summands P(x) with ∣x0−k∣>1 die by [L2], and for a composable pair of crossings in different k-strings the induced map Uk∂yx is zero: either one of the two crossings has ∣x0−k∣>1, or both lie on dk±1 and the differential is right multiplication by (x0∣k∣x0), which Uk kills [L2]; hence UkL(c~)≅⨁g~UkL(g~) as complexes.

2.1step 1.1L1L2L4L5F1

The local intertwiners. For each of the finitely many types of bigraded k-strings the source's case-by-case computation (the local lemmas and Cases 1-5 of the proof) writes RkL(g~) as L(τ~kg~) plus contractible two-term summands with explicit contracting homotopies: for a string g~ of type VI this is the computation RkPk≃Pk[1]{1}; for the types IV,IV′,V,V′ the summand UkL(g~) is acyclic; for the types I,II,II′,III,III′ the complex UkL(g~) splits off acyclic complexes and the central folding is isomorphic to L(τ~kg~) after the indicated sign isomorphisms, as displayed in the source comparisons [F1]. Those comparisons are relative to the outside complement ∇. In particular, the type-II0 comparison sends (x,y,z,w) to (x,−y−z(k−1∣k),z,−w) and negates the entire attached right tail (printed p. 43); it is not simply an identity on all outside summands. Composing these relative homotopy equivalences string by string, and step 1.1 gives RkL(c~)≅L(τ~kc~).

3.1step 2.1L7

The inverse-generator analogue. Apply step 2.1 to τ~k−1c~: it gives RkL(τ~k−1c~)≅L(c~). Tensor with Rk−1 and use Rk−1Rk≅Id⁡ from [L7]. Thus L(τ~k−1c~)≅Rk−1L(c~). No additional inverse case computation is needed.

4.1step 2.1step 3.1L6

Induction over braid words. Let σ be a word. By [L6] the functor Rσ is the composite of the factors; inducting over the length of the word using steps 2.1 and 3.1 (and the composition of the induced natural isomorphisms) gives RσL(c~)≅L(σc~) for the action of the braid on bigraded curves through the preferred lifts, which is well defined by the braid/mapping-class dictionary and uses AC exactly there. Applying this to c~=b~j and using that the basic arc has no essential segments, so that L(b~j) is a single summand Pbj=Pj for the normalized bigradings, gives RσPj≅L(σb~j).

5.1step 4.1∎

Conclusion. The generator complexes intertwine the half-twist action on bigraded curves, and consequently the braid-word complexes intertwine the braid action; the last isomorphism identifies RσPj with the complex of the twisted basic arc. The local computations are finite and AC is used only in the final word induction.

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Decategorification is the unreduced Burau action

Statement

Each X∈Cm has a class [X]∈G(Am) (The graded Grothendieck group of A_m), and the class [Rσ⊗Am−] depends only on σ∈Bm+1 by The Khovanov-Seidel complexes give a weak derived braid action, so the braid action induces a representation of Bm+1 by Z[q,q−1]-linear maps on G(Am). On the basis [P0],…,[Pm] of The graded Grothendieck group is free on the vertex-projective classes the generators act by [Ri][Pi]=−q[Pi],[Ri][Pi+1]=[Pi+1]−[Pi],[Ri][Pi−1]=[Pi−1]−q[Pi],[Ri][Pj]=[Pj](∣i−j∣>1), with the terms [Pi+1], respectively [Pi−1], omitted when the index leaves {0,…,m}. Moreover, let C be the (m+1)×(m+1) matrix over Z[q,q−1] with Cr,r=Cr,r+1=(−q)m−r(0≤r≤m−1),Cm,m=1, all other entries zero. Then C is invertible and C [Ri] C−1=Bi∣t=q(1≤i≤m), where B1,…,Bm are the unreduced Burau matrices of The unreduced Burau matrices in their column-vector convention with parameter t. Consequently, after the explicit change of basis C and the parameter identification q=t, the decategorified action is exactly the unreduced Burau representation of Bm+1; no identification is left implicit, and the comparison uses the same generator indexing and word order as the Burau matrices.

Facts & Assumptions

Given: An integer m≥1, the free Z[q,q−1]-module G(Am) with basis [P0],…,[Pm], the twist complexes Ri, the functors Ui, and the unreduced Burau matrices Bi with parameter t.

[L1]

[Ri]=[Am]−[Ui]: the twist complex is the cone of βi:Ui→Am between complexes concentrated in degree 0, its class in K0 is [Am]−[Ui] by the triangle relation [Am]=[Ui]+[Ri], and [Am]=[P0]+⋯+[Pm] (The twist complexes R_i and R_i^{-1}, The triangulated K_0 of the Khovanov–Seidel projective category, Homological and internal shifts on K_0(C_m)).

[L2]

Ui⊗AmPj≅Pi⊗ZeiAmej with the corner bases eiAmei=Zei⊕Z(i∣i−1∣i) in degrees 0,1, eiAmei+1=Z(i∣i+1) in degree 0, eiAmei−1=Z(i∣i−1) in degree 1, and eiAmej=0 for ∣i−j∣>1 (Corner computations: the U_i satisfy the Temperley-Lieb relations, The 4m+1 path basis).

[L3]

G(Am) is free over Z[q,q−1] with basis [P0],…,[Pm], and the class map is additive over direct sums with [X{r}]=qr[X] (The graded Grothendieck group is free on the vertex-projective classes, Homological and internal shifts on K_0(C_m)).

[L4]

The unreduced Burau matrices act on column vectors by the identity except for the block Bi=(1−tt10) at rows and columns i−1,i, and satisfy the Artin relations (The unreduced Burau matrices).

Proof

technique · direct
1.1L1L2L3

The class of the twist. By [L1] the operator [Ri] on G(Am) is Id⁡−[Ui], where [Ui] is induced by the exact functor Ui, and the class of [Ui] is computed on the basis by [L2]: [Ui][Pi]=[Pi]+q[Pi], [Ui][Pi+1]=[Pi], [Ui][Pi−1]=q[Pi] and [Ui][Pj]=0 for ∣i−j∣>1, where the degrees of the corner generators turn the tensor shifts into the powers of q by [L3].

1.2L3

The matrix C is invertible. C is upper triangular, with diagonal entries (−q)m,(−q)m−1,…,(−q),1, all units of Z[q,q−1]; hence det⁡C=(−q)m+(m−1)+⋯+1 is a unit and C∈GLm+1(Z[q,q−1]).

2.1step 1.1L3

The displayed action. Subtracting the four formulas of step 1.1 from [Pj] gives the four displayed rules: [Ri][Pi]=[Pi]−[Pi]−q[Pi]=−q[Pi], [Ri][Pi+1]=[Pi+1]−[Pi], [Ri][Pi−1]=[Pi−1]−q[Pi], and [Ri][Pj]=[Pj] for ∣i−j∣>1; indices outside {0,…,m} do not occur. Hence the representation is well defined on the whole basis.

2.2step 1.2L2L4

The intertwining identity. Write Ai for the matrix of [Ri] and U for the matrix of [Ui] in the basis [P0],…,[Pm], so that Ai=I−U by step 1.1; the columns of U are Uei=(1+q)ei, Uei+1=ei, Uei−1=qei and Uej=0 otherwise. Decompose C=D(I+N), where D is the diagonal matrix with entries dr=(−q)m−r for r<m and dm=1, and N is the matrix with ones on the superdiagonal and zeros elsewhere, so that Nej=ej−1; then (I+N)−1=I−N+N2−⋯+(−1)mNm and the j-th column of (I+N)−1 is ∑k≥0(−1)kej−k. Compute (I+N)U(I+N)−1 column by column. In column i the alternating sum of the U-images is (1+q)ei−qei=ei, and applying (I+N) gives ei+ei−1. In column i−1 only Uei−1=qei survives, and applying (I+N) gives q(ei+ei−1). In every other column the finitely many nonzero contributions Uei+1,Uei,Uei−1 occur with consecutive alternating signs and cancel to 0. Hence (I+N)U(I+N)−1 has columns ei+ei−1 at i, q(ei+ei−1) at i−1 and 0 elsewhere. Conjugating by the diagonal D multiplies each entry (r,j) by drdj−1, so CUC−1 has entries 1 at (i,i), −q at (i−1,i), −1 at (i,i−1) and q at (i−1,i−1), and 0 elsewhere; that is, CUC−1=I−Bi with Bi the unreduced Burau matrix at t=q, whose block at rows and columns i−1,i is (1−qq10) [L4]. Hence CAiC−1=I−CUC−1=Bi.

3.1step 2.1step 2.2∎

Conclusion. The decategorified action of the generators is the displayed four-case action, and the single invertible matrix C, independent of i, conjugates every generator to the unreduced Burau matrix at t=q; since both sides are representations of the presented group Bm+1 [L4], the change of basis C and the parameter identification q=t identify the whole representation with the unreduced Burau representation, with the same indexing and word order. The action on the reduced quotient is not claimed here. No choice principle is used beyond the inputs already recorded.

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Homs compute bigraded arc intersections

Statement

Assume AC, inherited from the representative-independence and isotopy invariance of intersection numbers (Local indices and bigraded intersection numbers) and used to interpret σ∈Bm+1 as a boundary-fixed mapping class acting on bigraded curves (Basic arcs, admissible curves and the standard normal form, with its Artin completeness and smooth comparison); the graded Hom and Poincaré-polynomial computation is finite. For all σ,τ∈Bm+1, all s1,s2∈Z and all 0≤k,j≤m the abelian group Hom⁡Cm(RτPk, RσPj[s1]{−s2}) is free, and its Poincaré polynomial satisfies ∑s1,s2rk⁡Hom⁡Cm(RτPk,RσPj[s1]{−s2})q1s1q2s2=Ibigr(f~τ(b~k),f~σ(b~j)), where f~σ is the preferred lift of the boundary-fixed mapping class representing σ under the isomorphism Bm+1≅G, acting on the normalized bigradings of the basic arcs. In particular, specializing q1=q2=1 gives Ibigr(…)∣q1=q2=1=2 I(⋅,⋅), so the ranks at q1=q2=1 recover twice the ordinary geometric intersection numbers of the source's curves.

Facts & Assumptions

Given: AC, the braid group action on bigraded curves by preferred lifts, the complexes Rσ acting on Cm, the normalized bigradings of the basic arcs, and the complex L(c~) of an admissible bigraded curve.

[L1]

RσPj≅L(σb~j) for normalized bigradings of the basic arcs, and Rσ is an equivalence of Cm with inverse Rσ−1 (Curve complexes intertwine the braid generators, The Khovanov-Seidel complexes give a weak derived braid action).

[L2]

L(c~) is a bounded complex of finite graded projectives and its homotopy type depends only on the isotopy class of c~; the deck action acts by shifts L(χ(r1,r2)c~)≅L(c~)[−r1]{r2} (The curve complex is a complex and is invariant under normal-form moves, The complex of an admissible bigraded curve).

[L3]

For chain complexes over an abelian category the homotopy classes of chain maps are the degree-zero homology of the Hom complex: Hom⁡K(C,D)≅H0(Hom⁡‾(C,D)), and the bigraded Hom groups of Cm are the degree-zero homology of the bigraded Hom complex (Hom in the homotopy category is zero-degree homology of the Hom complex).

[L4]

Under AC, Ibigr is invariant under the preferred lifts: Ibigr(f~(c~0),f~(c~1))=Ibigr(c~0,c~1), and it is a sum of the contributions of the k-strings, with the table of Bigraded string types and their contributions to I^{bigr} (Local indices and bigraded intersection numbers).

[L5]

The graded maps Pk=Amek→Pj=Amej are right multiplication by paths in ekAmej. The finite path basis gives zero when ∣k−j∣>1, one arrow for adjacent vertices, the vertex and degree-one return for k=j>0, and only the vertex for k=j=0. Thus adjacent and internally shifted self Homs must not be discarded (Finite graded A_m-modules, internal shifts and the vertex projectives, The 4m+1 path basis).

[L6]

Bigradings of non-closed curves exist and are unique up to the deck action, and b~j is a basic arc (Existence and rigidity of bigradings, Basic arcs, admissible curves and the standard normal form).

[F1]

Literature input. KS Lemma 4.10 proves the string decomposition of shifted Homs: the only surviving projectives have ∣x0−k∣≤1, and the differential components joining different k-strings induce zero on Hom⁡(Pk,−). Lemmas 4.11–4.12 prove that each string Hom group is free, with the base Poincaré tables equal to the complete bigraded contribution tables, and the parameters multiply them by q1r1q2r2(q1−1q2)u for the integer-indexed families. Their proof first removes deck shifts and integer twists and only then computes the base diagrams. For type VI(0,0), one has L(b~k)=Pk; its self-Hom has the vertex in bidegree (0,0) and the return in bidegree (0,1), both with homological shift zero. Thus its polynomial is 1+q2, agreeing directly with the source tables and the self-intersection computation of [L4]. This is a stated literature input; we do not infer free homology merely from free chains (KS full proof, printed pp. 45–47).

Proof

technique · source-supported direct reduction
1.1L1L4L6

Reduction to the first untwisted arc. Apply the inverse equivalence Rτ−1 to both arguments of each shifted Hom. The weak action identifies the second image with Rτ−1σPj. Apply the corresponding inverse preferred lift to both geometric arcs; [L4] gives the same reduction of their intersection polynomial. It therefore suffices to compare Hom⁡(Pk,L(c~)[s1]{−s2}) and Ibigr(b~k,c~), with c~=f~τ−1σb~j by [L1], a bigraded basic-arc image.

1.2L2L3L5F1

The correct string decomposition. Compute these groups as homology of the Hom complex by [L3]. The corner basis [L5] kills summands farther than one vertex from k, while retaining adjacent arrows and the self return. For different k-strings the remaining connecting differential acts by a length-three product or a forbidden return at the exterior vertex, hence is zero, as the source string-splitting calculation in [F1] proves. Thus for every pair of shifts the Hom group is the finite direct sum of the string Hom groups.

1.3L2L3L4F1

Base diagrams, integer twists and freeness. The source local theorem [F1] computes the BASE diagrams, then extends by deck shifts and integer half twists. For example its I0 Hom complex reduces to 0→Z{1}→0Z→0, giving q1+q2 and free groups. The four exceptional zero-contribution types have acyclic Hom complexes; the other base types give the full table of [L4], with type VI checked directly in [F1]. The source's parameter reduction multiplies the table by the stated monomial, without claiming an arbitrary winding string has at most three terms. Crucially [F1] asserts freeness of the actual string HOMOLOGY groups; that property is not inferred from the chain groups alone.

2.1step 1.1step 1.2step 1.3L4F1

The polynomial and all shifts. Summing the string polynomials of step 1.3 gives Ibigr(b~k,c~) by [L4], while step 1.2 identifies each coefficient with the rank of the corresponding shifted Hom group. A finite direct sum of the free string Hom groups is free. Step 1.1 now returns the original σ,τ and both geometric images, proving the claimed full Poincaré formula and freeness for every shift.

3.1step 2.1L4∎

Specialization and conclusion. Property (B1) of [L4] evaluates the polynomial at q1=q2=1 as twice the ordinary intersection number. The equivalence reduction, correctly retained corner Homs, exact source string theorem and coefficient-wise freeness prove all claimed conclusions. AC is inherited through the braid/mapping-class dictionary and the supplied representative-independence and isotopy invariance of intersection numbers; the finite string groups add no choice requirement.

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The Khovanov-Seidel weak braid action is faithful

Statement

Assume AC, inherited from the braid-to-mapping-class dictionary used in the Hom theorem and the detector, and from the supplied representative-independence and isotopy invariance of intersection numbers. For every m≥1 the weak action of Bm+1 on Cm given by the complexes Rσ (The Khovanov-Seidel complexes give a weak derived braid action) is faithful (Faithful weak action): if Rσ≅Id⁡Cm for a braid σ, then σ=1. Equivalently, no nontrivial braid acts by the identity functor, although nontrivial braids may act trivially on the Grothendieck group G(Am).

Facts & Assumptions

Given: AC, the weak braid action by the complexes Rσ on Cm, the basic arcs b0,…,bm with their normalized bigradings, and a braid σ∈Bm+1 with Rσ≅Id⁡Cm.

[L1]

For all σ,τ and all j,k,s1,s2 the Hom groups Hom⁡Cm(RτPk,RσPj[s1]{−s2}) are free with Poincaré polynomial Ibigr(f~τb~k,f~σb~j) (Homs compute bigraded arc intersections).

[L2]

If f∈G satisfies I(bj,f(bk))=I(bj,f2(bk))=I(bj,bk) for all j,k, then [f]=1 in G (The basic arcs detect the identity braid).

[L3]

Under AC, the preferred lifts give the action of Bm+1 on bigraded curves, and Ibigr(c~0,c~1)∣q1=q2=1=2I(c0,c1), so equality of the bigraded numbers specializes to equality of the ordinary intersection numbers (Local indices and bigraded intersection numbers).

[L4]

Under the isomorphism Bm+1≅G=π0Diff⁡(D,∂D;Δ) a braid σ corresponds to a boundary-fixed mapping class fσ well defined up to isotopy, and σ=1 iff [fσ]=1 (Basic arcs, admissible curves and the standard normal form, whose dictionary includes Artin-presentation completeness and the smooth comparison).

Proof

technique · direct
1.1L1

The Hom-table of Rσ is the identity table. Suppose Rσ≅Id⁡Cm. Then for all j,k and all shifts s1,s2 the induced isomorphism gives Hom⁡Cm(Pk,RσPj[s1]{−s2})≅Hom⁡Cm(Pk,Pj[s1]{−s2}). By the Hom theorem [L1] applied with τ=1 on the left and σ=1 on the right, taking Poincaré polynomials gives Ibigr(b~k,σb~j)=Ibigr(b~k,b~j)for all j,k.

2.1step 1.1L1

The same for the square. The weak-action relation Rσ2≅RσRσ gives Rσ2≅Id⁡Cm as well; hence the same argument yields Ibigr(b~k,σ2b~j)=Ibigr(b~k,b~j)for all j,k.

3.1step 1.1step 2.1L3L4

Specialization to the ordinary intersection table. Setting q1=q2=1 in the identities of steps 1.1 and 2.1 and using [L3] gives I(bk,fσ(bj))=I(bk,bj),I(bk,fσ2(bj))=I(bk,bj)for all j,k, where fσ is the boundary-fixed mapping class of σ [L4].

4.1step 3.1L2L4

The detector concludes. The two families of equalities of step 3.1 are exactly the hypotheses of the detector lemma [L2] for f=fσ; hence [fσ]=1 in G, and by [L4] σ=1 in Bm+1. This proves faithfulness.

5.1step 4.1L1L2L3∎

Conclusion. No nontrivial braid acts by the identity functor: the identity of the Hom tables forces the identity of the mapping class, by the two-iterate hypothesis of the detector. The contrast with the Grothendieck group is displayed by the decategorification proposition and the companion counterexample. AC is inherited through the Hom theorem and the detector, which use Bm+1≅G, and through the supplied representative-independence and isotopy invariance of intersection numbers in [L3].

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A nontrivial five-strand braid lies in the Burau kernel

Statement

Assume AC, inherited from the topological definition of the Burau representations and from the reduced/unreduced same-kernel transfer. There exists a nontrivial element of B5 that acts trivially in the unreduced Burau representation ρ5mat of The unreduced Burau matrices. Explicitly, let α,β be the two embedded arcs on the five-punctured disk displayed in Figure 3 of the source, using the standard Artin labels fixed by its straightening words on p. 403, with α joining the marked points q2 and q4 and β joining the boundary basepoint p0 to the marked point q3, and put ψ:=[Tα,Tβ]=Tα−1Tβ−1TαTβ, the commutator of the clockwise half Dehn twist Tα about the boundary of a regular neighbourhood of α (whose induced permutation exchanges q2 and q4) with the full boundary-arc twist Tβ about the boundary of a regular neighbourhood of β∪∂D. Then ψ≠1 in B5 and ρ5mat(ψ)=I5. This is the explicit kernel element used by the counterexample on the companion page; it is not an instance of Δ2k. The boundary-arc twist uses the boundary-relative convention of Bigelow, Section 2; changing its representative by a central boundary full twist leaves this commutator unchanged.

Facts & Assumptions

Given: AC; the five-punctured disk (D,Δ5) with boundary basepoint p0; the oriented embedded arcs α,β of Bigelow's Figure 3; the half twist Tα and the full twist Tβ specified in the Statement; the commutator ψ=Tα−1Tβ−1TαTβ; and Λ1=Z[t±1].

[L1]

Write si=σi−1 for clockwise generators, since the positive geometric half twists of The elementary geometric half twist, its support disc, and its opposite are anticlockwise. Bigelow's printed p. 403 gives the words P=s3−1s2s12s2s43s3s2,Q=s4−1s3s2s1−2s2s12s22s1s45,R=s4s3s2s12s2s3s4. In the Figure 3 coordinates, P straightens α to the arc between q4,q5 and Q straightens β to the boundary arc ending at q5; hence its kernel witness is [P−1s4P,Q−1RQ]. We use these exact words to check the twist argument below, rather than assuming that the source's abbreviated digon check proves nontriviality.

[L2]

Put Si=ρ5mat(si)=Bi−1. Its nonidentity block is (01t−11−t−1). For a word V in the si±1, let M(V) be the ordered product of these blocks or their inverses. This is its unreduced Burau action (The unreduced Burau matrices, The unreduced Burau matrices satisfy the Artin relations).

[L3]

The Artin representation η:B5→Aut⁡(F5) is a homomorphism. In the clockwise convention its substitutions are η(si)(xi)=xi+1,η(si)(xi+1)=xi+1−1xixi+1; its inverse sends xi to xixi+1xi−1 and xi+1 to xi, fixing the other basis letters. Products compose with the rightmost letter first. Free reduction has unique normal forms (Artin automorphisms of the free group, The Artin representation on a free group, Reduced words form the free group on an alphabet). To prove that a braid is nontrivial it suffices that its image is nontrivial; no faithfulness theorem is needed.

[L4]

The topological reduced action is the action on H1(X~;Z) for the infinite cyclic cover of The Burau infinite cyclic cover. It agrees with the invariant reduced submodule of the matrix action, and the reduced and unreduced integral representations have the same kernel (The topological and matrix Burau representations agree, The reduced and unreduced Burau representations have the same kernel). A boundary full twist Δ2 acts on this homology by t5 (Bigelow, printed p. 400).

[L5]

Twists are boundary-fixed braid mapping classes, and twists supported on disjoint regular neighbourhoods commute (Boundary-fixed mapping class group of a punctured disk, The braid group by Artin presentation, The elementary geometric half twist, its support disc, and its opposite). Homotopic simple proper arcs are isotopic relative to their endpoints (Homotopic simple proper arcs in the punctured disk are isotopic relative to their endpoints); their geometric intersection number has the meaning in Curves and geometric intersection numbers on the marked disk. The half twist Tα exchanges q2,q4, so its induced permutation is an involution. The braid itself has infinite order: on the subgroup preserving these two punctures, forgetting the other strands sends its powers to powers of a generator of B2≅Z.

[L6]

For lifts of the oriented arcs to the cyclic cover, the lifted intersection polynomial is J(α,β)=∑k(tkα~,β~)tk, where the parentheses denote algebraic intersection. Changing lifts multiplies J by a power of t. Bigelow, Definition 1.3 and Section 3, records the crossing signs and all fifty terms; the exponents are determined by the total winding about punctures between crossings.

Proof

technique · direct
1.1L1L5

Fix the Figure 3 witness and the conventions. Set a=P−1s4P and b=Q−1RQ. The puncture permutation of P sends (1,2,3,4,5) to (1,5,2,4,3), and Q sends it to (2,1,5,4,3). Thus P−1s4P exchanges q2,q4 and Q−1RQ uses the boundary arc ending at q3. This fixes the Figure 3 labeling; The source's general arc criterion labels an arbitrary test arc's endpoints q1,q2; applying that criterion to these words requires a relabeling. By [L1] these are the source's half twist and boundary-arc twist; in particular ψ=[a,b] is the displayed geometric commutator. An ambiguity by a boundary full twist in b has no effect on [a,b], since a boundary twist is supported in a collar and each boundary-fixed mapping class has a representative that is the identity on a smaller collar, making the two supports disjoint. Every subsequent calculation uses si=σi−1, the source's clockwise convention, and ordinary left actions.

1.2L2algebra

The two block calculations. Let u0=−e4+t−1e5 and v0=e4∗−e5∗, so S4=I+u0v0. Multiplying the eight blocks of R gives M(R)=(t−10001−t−10t−1001−t−100t−101−t−1000t−11−t−1t−4−t−5t−3−t−4t−2−t−3t−1−t−21−t−1+t−5). Put u=M(P)−1u0 and v=v0M(P). The ten blocks of P give u=(t3−t2, t−2t2+2t3−t4+t5, t3−t2, −t2, t−1−1+t−t2)T, v=(t−2−t−3, −t−5+t−4−t−3, t−5−2t−4+2t−3−2t−2+t−1, t−4−t−3+2t−2−2t−1+1, t−3−t−2+t−1−1). Thus M(a)=I+uv. These computations use only the displayed two-by-two blocks; in particular they take place over the integral Laurent ring.

1.3L6algebra

The source's lifted intersection calculation. Normalize lifts so the first crossing along β contributes +t0. Upward crossings are positive and downward crossings negative. When successive crossing subarcs bound a disk containing k punctures, the exponent changes by k with the sign of the orientation around that disk. In the fifty-term calculation on Bigelow's printed p. 403, the positive terms at exponents −3,−2,−1,0,1,2,3,4,5 have respective multiplicities (1,2,3,4,5,4,3,2,1), and the negative terms have exactly the same multiplicities. Therefore every coefficient cancels and J(α,β)=0, independently of the choice of lifts. The explicit matrix calculation below verifies the resulting commuting twist action in the frozen convention.

2.1L2step 1.2algebra

The intersection cancellation in matrix coordinates. Put y=M(Q)u and z=vM(Q)−1. Multiplication by the sixteen blocks of Q gives the four scalar identities y5=0, y1+ty2+t2y3+t3y4=0, z5=0, and z1+z2+z3+z4=0. These can be checked without forming any full matrix: a positive letter si changes a column pair (ci,ci+1) to (ci+1,t−1ci+(1−t−1)ci+1) and a row pair (di,di+1) to (t−1di+1,di+(1−t−1)di+1); a negative letter uses the inverse pair operations. For columns apply the word from right to left, and for rows from left to right. With those four identities, the displayed matrix M(R) gives M(R)y=t−1y and zM(R)=t−1z: its fifth column pairs to zero with z, and its fifth row pairs to zero with y. Consequently M(b)u=t−1u and vM(b)=t−1v. Hence M(b)(I+uv)=M(b)+t−1uv=(I+uv)M(b), proving ρ5mat(ψ)=I5. This explicitly checks the boundary-arc case of the source's intersection/twist argument.

2.2L3step 1.1algebra

The geometric twists do not commute. Conjugate by P, so the two twists become s4 and w=PQ−1RQP−1. Compute their actions on x1 using [L3]. Successively applying P−1,Q,R,Q−1,P and then s4 gives freely reduced lengths 13,83,185,1993,14095,19199. The reduced word η(w)(x1) begins x5−1x3−1x5−1, while η(s4w)(x1) begins x5−1x4−1x5. The full substitutions and reductions, including the two different prefixes, are given by the finite certificate below. Since s4 fixes x1, η(ws4)(x1)=η(w)(x1); the two different reduced prefixes show η(s4w)≠η(ws4). Thus s4w≠ws4, and after conjugating back, ab≠ba and ψ≠1.

3.1L5step 2.2

Why Figure 3 has essential intersection. If α could be homotoped off β relative to endpoints, the proper-arc homotopy/isotopy identification in [L5] would allow disjoint representatives. Their regular neighbourhoods, including the boundary collar in the boundary-arc construction, could then be chosen disjoint, so their supported twists would commute. This contradicts step 2.2. Thus the Figure 3 arcs cannot be homotoped apart. This gives a local proof of the geometric conclusion, including the boundary-arc case, through their explicit actions rather than the source's abbreviated digon argument. The induced permutation of Tα is the involution in [L5], and the half twist itself is not an order-two braid.

4.1L4step 2.1step 2.2algebra∎

Conclusion and exclusion of boundary full twists. Steps 2.1 and 2.2 prove the claimed nontrivial kernel element. By [L4] its reduced action is also the identity. If ψ=Δ2k, that reduced action would be t5kI4, so t5k=1 in Z[t±1] and k=0; this contradicts ψ≠1. The statement retains AC through its topological suppliers; the explicit matrix and reduced-word computations are finite and require no choice.

Remarks

Here is the complete finite free-word certificate for step 2.2. A signed integer j denotes xj and −j denotes xj−1; signed braid integers refer to sj. The stack cancels adjacent inverse letters, and therefore returns the unique free-group reduced word. No truncation of an intermediate word occurs. The displayed assertions follow by these explicit substitutions.

P = [-3, 2, 1, 1, 2, 4, 4, 4, 3, 2]
Q = [-4, 3, 2, -1, -1, 2, 1, 1, 2, 2, 1, 4, 4, 4, 4, 4]
R = [4, 3, 2, 1, 1, 2, 3, 4]

def inverse(word):
    return [-j for j in reversed(word)]

def reduce(word):
    stack = []
    for j in word:
        if stack and stack[-1] == -j:
            stack.pop()
        else:
            stack.append(j)
    return stack

def substitute(word, braid_letter):
    i = abs(braid_letter)
    if braid_letter > 0:
        images = {i: [i+1], i+1: [-i-1, i, i+1]}
    else:
        images = {i: [i, i+1, -i], i+1: [i]}
    expanded = []
    for j in word:
        image = images.get(abs(j), [abs(j)])
        expanded.extend(image if j > 0 else inverse(image))
    return reduce(expanded)

def act(braid_word, word):
    for j in reversed(braid_word):
        word = substitute(word, j)
    return word

word = [1]
for factor, length in zip(
    [inverse(P), Q, R, inverse(Q), P], [13, 83, 185, 1993, 14095]
):
    word = act(factor, word)
    assert len(word) == length
assert word[:3] == [-5, -3, -5]
other = act([4], word)
assert len(other) == 19199 and other[:3] == [-5, -4, 5]
assert act([4], [1]) == [1]

5 · Examples, counterexamples and false statements

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