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✓ 20 results · all verified · 18 also independently AI-judged
Every result on this page is machine-checked by a proof checker and read in full and owner-audited; the judge is an additional, independent cross-model AI review of the proofs. The 2 not AI-judged were verified by owner audit (typically over a confirmed judge false positive), not failures.

Bergman and Szegő Kernels

1 · Prerequisites

2 · Summary

This page develops Bergman spaces, their reproducing kernels and invariant metrics, together with the surface-measure Hardy and Szegő construction on regular smooth domains.

3 · Logical flowchart

4 · Definitions, theorems and proofs

DefinitionDefinition: AI-adaptedProof: AI-generatedprecheck passjudge pass (gpt-6.1-sol)audited 2026-10-08Open item page →

The Hardy boundary space, Szegő projection and Szegő kernel on a smoothly bounded domain

Facts & Assumptions

[F1]

Under The Axiom of Countable Choice (ACω), complex L2(μ) with the pairing ⟨f,g⟩=∫fg‾ dμ is a Hilbert space, with the pairing linear in its first variable and conjugate symmetric (The complex L2 pairing on equivalence classes, L2 with the integral pairing is a Hilbert space).

[F2]

Under The Axiom of Countable Choice (ACω), every closed linear subspace of a Hilbert space has an orthogonal projection, determined by the unique orthogonal decomposition (Orthogonal decomposition by a closed subspace, The Hilbert orthogonal projection onto a closed subspace).

[F3]

Under The Axiom of Countable Choice (ACω), every bounded linear functional on a Hilbert space has a unique Riesz representer, with f(x)=⟨x,y⟩ in the first-variable-linear convention (Riesz representation for Hilbert spaces).

Definition

Assume the Axiom of Countable Choice ACω (The Axiom of Countable Choice (ACω)). Let m≥1, let Ω⊂Cm be a nonempty bounded connected open set with C1 boundary (Bounded C1 domains and their outward normals), let dS be its boundary surface measure (Surface integration on compact C1 hypersurfaces), and fix a normalization σ=c dS with c>0. Give L2(∂Ω,σ;C) the first-variable-linear pairing from The complex L2 pairing on equivalence classes. For f∈O(Ω)∩C(Ω‾), its boundary trace tr⁡σf:=[f∣∂Ω] is an L2 class because ∂Ω is compact and σ is finite. Set

T(Ω,σ):={tr⁡σf:f∈O(Ω)∩C(Ω‾)},H2(∂Ω,σ):=T(Ω,σ)‾ L2(σ).

The space T(Ω,σ) is linear, and H2(∂Ω,σ) is a closed linear subspace of the Hilbert space L2(∂Ω,σ;C) by [F1]. The Szegő projection is the orthogonal projection

Pσ:L2(∂Ω,σ;C)⟶H2(∂Ω,σ),

which exists by [F2].

Call (Ω,σ) Szegő-regular if, for every w∈Ω, the rule tr⁡σf↦f(w) is well-defined and bounded on T(Ω,σ) in the L2 norm, and its unique continuous extension Ew:H2(∂Ω,σ)→C has the property that z↦Ez(h) is holomorphic on Ω for every h∈H2(∂Ω,σ). Boundedness and density make each Ew unique. By [F3], there is a unique Sw∈H2(∂Ω,σ) such that

Ew(h)=⟨h,Sw⟩L2(σ)(h∈H2(∂Ω,σ)).

For a Szegő-regular pair define its Szegő kernel by Sσ(z,w):=Ez(Sw). Then Ew(h)=⟨h,Sw⟩ is the reproducing identity, Sσ(z,w)=⟨Sw,Sz⟩, and conjugate symmetry of the inner product gives Sσ(w,z)=Sσ(z,w)‾. The regularity condition makes the kernel holomorphic in z; conjugate symmetry makes it antiholomorphic in w. The ACω assumption is used through the Hilbert-space, projection and Riesz suppliers in [F1]–[F3]; no stronger choice principle is asserted. No Szegő construction is claimed for boundaries that are not C1 hypersurfaces, including the polydisc when m≥2.

Proof

technique · direct

Given: ACω, the bounded C1 domain Ω, the finite measure σ, and the spaces T(Ω,σ) and H2(∂Ω,σ) just defined.

1.1F1

The space T(Ω,σ) is linear, so its closure H2(∂Ω,σ) is a closed linear subspace of L2(∂Ω,σ;C). By [F1] the ambient space is a Hilbert space with the stated pairing; therefore the closed subspace is itself a Hilbert space.

2.1step 1.1F2

The orthogonal-decomposition theorem in [F2] gives each g∈L2(∂Ω,σ;C) a unique H2 component, and The Hilbert orthogonal projection onto a closed subspace defines Pσ to be that component.

2.2step 1.1F3given

For a Szegő-regular pair each Ew is a bounded linear functional on the Hilbert space H2 from step 1.1, so [F3] gives its unique representing vector Sw and the stated reproducing identity.

3.1step 2.2F1algebra∎

The definition gives Sσ(z,w)=Ez(Sw)=⟨Sw,Sz⟩; conjugate symmetry of the pairing in [F1] gives Sσ(w,z)=Sσ(z,w)‾. The regularity condition makes z↦Sσ(z,w) holomorphic, and this symmetry makes w↦Sσ(z,w) antiholomorphic.

LemmaStatement: AI-adaptedProof: AI-generatedprecheck passjudge pass (gpt-6.1-sol)audited 2026-10-08Open item page →

The mean-value L2 bound for holomorphic functions on a polydisc

Facts & Assumptions

[A1]

The Axiom of Countable Choice ACω is the principle defined by The Axiom of Countable Choice (ACω). It is the only choice assumption below; the polar-measure and product-Lebesgue suppliers used here state it explicitly.

[F1]

If g is holomorphic on D(b,R) and 0<s<R, then g(b)=(2π)−1∫02πg(b+seiθ) dθ (A holomorphic function equals its average on every circle inside a larger concentric holomorphy disc).

[F2]

The chart surface measure of S1 agrees with its polar surface measure; under the angular chart ω=eiθ its density is dθ, so σ(S1)=2π (Surface integration on compact C1 hypersurfaces, Agreement with the existing polar sphere measure).

[F3]

For every nonnegative Borel h on R2, polar coordinates give ∫h dλ2=∫0∞∫S1h(sω)s dσ(ω) ds (The polar surface set function on the unit sphere, Polar coordinates decompose Lebesgue measure into r^{n-1} dr d sigma).

[F4]

Lebesgue measure is translation invariant on measurable sets (Lebesgue outer measure, Lebesgue measurability and Lebesgue measure are unchanged by translation).

[F5]

Every nonnegative measurable function is the increasing limit of nonnegative simple functions, and increasing limits pass through the Lebesgue integral; thus the setwise translation invariance in [F4] extends from indicators and simple functions to nonnegative Borel integrals (Every nonnegative measurable function admits an explicit increasing sequence of simple approximations, Monotone convergence for the integral).

[F6]

Borel sets in a finite Euclidean product are product-measurable; Tonelli permits iterated integration of nonnegative product-measurable functions, and the finite product of planar Lebesgue measures agrees with Euclidean Lebesgue measure under R2m≅(R2)m (The Borel product of R^m and R^n is the Borel sigma-algebra of R^{m+n}, Tonelli's theorem for nonnegative measurable functions on a sigma-finite product, On Borel subsets of R^{m+n}, the product lambda_m times lambda_n agrees with lambda_{m+n}).

[F7]

A holomorphic function is continuous, hence ∣f∣2 is Borel (A holomorphic function of several variables is continuous and separately holomorphic); the one-variable case is also supplied by Complex differentiability at a point implies continuity there.

[F8]

Restricting the complex linear derivative in the definition of holomorphy to a coordinate line shows that every coordinate slice of a holomorphic function is holomorphic (Holomorphic functions on an open subset of Cm).

[F9]

A polydisc is the product of its coordinate discs, and Cm is identified with R2m with the corresponding Lebesgue convention (Balls, polydiscs and the distinguished boundary in Cm, Complex m-space and its real coordinate dictionary).

Statement

Assume ACω (The Axiom of Countable Choice (ACω)). Let m≥1, let Ω⊆Cm be open, let a∈Ω, and let r=(r0,…,rm−1) be a polyradius with each rk>0 such that Δ‾r(a)⊆Ω. If f is holomorphic on Ω, then

∣f(a)∣2≤1λ2m(Δr(a))∫Δr(a)∣f∣2 dλ2m,λ2m(Δr(a))=πm∏k<mrk2,

where λ2m is Lebesgue measure under Cm≅R2m. In particular, for a common radius r the coefficient is (πr2)−m.

Proof

technique · direct

Given: ACω, m≥1, the open set Ω, the point a, the positive polyradius r, and the holomorphic function f from the statement.

1.1F1algebra

For a one-variable holomorphic g on D(b,ρ) and each 0<s<ρ, [F1] gives the circular mean of g as g(b). Expanding the nonnegative integral of ∣g(b+seiθ)−g(b)∣2 and using that mean identity yields ∣g(b)∣2≤(2π)−1∫02π∣g(b+seiθ)∣2 dθ.

2.1step 1.1F2F3F4F5F7A1algebra

By [F2], the angular measure in step 1.1 is the polar surface measure with total mass 2π. The function h(x)=∣g(b+x)∣2 for x∈D(0,ρ) and h(x)=0 otherwise is nonnegative Borel by [F7]. Apply [F3] to h, using translation invariance [F4]–[F5]. Integrating the circle inequality in step 1.1 against 2s ds/ρ2 for 0<s<ρ gives ∣g(b)∣2≤1πρ2∫D(b,ρ)∣g(z)∣2 dλ2(z); the same polar formula applied to the indicator of the disc gives λ2(D(b,ρ))=πρ2.

3.1step 2.1F6F9A1

Let Dk=D(ak,rk). By [F6] and [F9], the measure of their product is the product of their planar measures, so step 2.1 gives λ2m(Δr(a))=∏k<mπrk2.

4.1step 2.1step 3.1F6F7F8F9A1given∎

For 0≤k≤m, let Ik be the integral of ∣f(z0,…,zk−1,ak,…,am−1)∣2 over D0×⋯×Dk−1 with product planar measure, with I0=∣f(a)∣2. For each fixed tuple of the first k coordinates, [F8] shows that the resulting one-variable slice is holomorphic on D(ak,rk). The estimate of step 2.1 applies to that slice; integrating over the preceding discs and using [F6] gives Ik≤(πrk2)−1Ik+1. Iterating for k=0,…,m−1 and using [F6], [F7] and [F9] to identify Im with the integral in the statement gives ∣f(a)∣2≤(∏k<mπrk2)−1∫Δr(a)∣f∣2 dλ2m. Step 3.1 identifies the coefficient with 1/λ2m(Δr(a)), completing the proof.

LemmaStatement: AI-adaptedProof: AI-generatedprecheck passjudge pass (gpt-6.1-sol)audited 2026-10-08Open item page →

The complex Hessian of a C2 function dominates that of a minorant at a common minimum

Facts & Assumptions

Given: An integer m≥1, an open set U⊆Cm, real-valued functions u,v∈C2(U), a point a∈U, a neighbourhood V⊆U of a on which u≥v, and u(a)=v(a).

[F1]

The identification of Cm with R2m transports open sets and real coordinate regularity, and C2 means all ordered real coordinate derivatives through order two exist and are continuous (Complex m-space and its real coordinate dictionary, Ck maps and multi-index derivative notation in Euclidean space).

[F2]

For a real C2 function on a real open set, its real Hessian quadratic form is nonpositive at an interior local maximum (The Hessian is negative semidefinite at an interior local maximum).

[F3]

The Wirtinger operators are ∂zk=12(∂xk−i∂yk) and ∂zˉk=12(∂xk+i∂yk) (Wirtinger operators in Cm).

[F4]

If a map has continuous coordinate partial derivatives on a neighbourhood, it is totally differentiable there, and the ordinary chain rule for total derivatives applies (If all partial derivatives exist on a neighbourhood and are continuous at a point, then the map is totally differentiable there with Jacobian derivative, The chain rule for total derivatives: D(g∘f)(a)=Dg(f(a))∘Df(a)). Applied to an affine complex line and to the first coordinate derivatives of a real C2 function, it gives the line-composition derivative formulas used below.

[F5]

The real coordinate mixed partial derivatives of a C2 function commute (Clairaut--Schwarz theorem for continuous second partial derivatives).

[F6]

The Levi form is Lu(a;X)=∑j,k=1muzjzˉk(a)XjXk‾, with the one-based indices of The Levi form and strict plurisubharmonicity.

Statement

Let m≥1, let U⊆Cm be open, let u,v∈C2(U,R), and let a∈U. If u≥v on a neighbourhood of a and u(a)=v(a), then for every X∈Cm

∑j,k=1m∂2u∂zj∂z‾k(a)XjXk‾ ≥ ∑j,k=1m∂2v∂zj∂z‾k(a)XjXk‾.

Here C2 is interpreted in the real coordinates of Complex m-space and its real coordinate dictionary, and the one-based complex-coordinate aliases and Wirtinger derivatives are those of The Levi form and strict plurisubharmonicity.

Proof

technique · direct

Given: m,U,u,v,a as in the statement and an arbitrary X∈Cm.

1.1F1F4givenalgebra

Put w=u−v. If X=0, both sides of the claimed inequality are zero. Otherwise, since U is open, the affine map λ↦a+λX maps a sufficiently small disc about 0 into U. On a possibly smaller such disc, Φ(λ):=w(a+λX) is real C2 by [F4], is nonnegative, and satisfies Φ(0)=0; hence 0 is a local minimum of Φ.

2.1F2step 1.1given

The function −Φ is real C2 and has a local maximum at 0. Apply [F2] in the real coordinates λ=s+it. Its Hessian quadratic form is nonpositive on each coordinate vector, so Φss(0)≥0 and Φtt(0)≥0. Therefore Φss(0)+Φtt(0)≥0.

3.1F3F4F5F6step 2.1algebragiven∎

Write Xj=αj+iβj. By the definitions in [F3] and the chain rule in [F4], ∂λˉΦ(λ)=∑kXk‾(∂zˉkw)(a+λX) and therefore ∂λ∂λˉΦ(0)=∑j,kXjXk‾ ∂zj∂zˉkw(a). Also, the one-variable Wirtinger formulas give 4∂λ∂λˉΦ=Φss+Φtt+i(Φst−Φts)=Φss+Φtt by [F5]. Thus [F6] and step 2.1 imply 4(Lu(a;X)−Lv(a;X))=Φss(0)+Φtt(0)≥0, which is the required inequality for this arbitrary X.

LemmaStatement: AI-adaptedProof: AI-generatedprecheck passjudge pass (gpt-6.1-sol)audited 2026-10-08Open item page →

Weighted monomial integrals and monomial norms for the disc, ball and polydisc

Facts & Assumptions

Given: An integer m≥1, the Axiom of Countable Choice ACω, and a multi-index α=(α0,…,αm−1)∈Nm. Write α!:=∏j<mαj!, ∣α∣:=∑j<mαj, and zα:=∏j<mzjαj using the conventions of Ck maps and multi-index derivative notation in Euclidean space and Integer powers in the complex field.

For d≥1, β∈Nd and t∈N, write Id(β,t):=∫Bd∣zβ∣2(1−∣z∣2)t dλ2d(z).

[A1]

The only choice principle assumed is ACω (The Axiom of Countable Choice (ACω)). It is required by the polar-coordinate, chart/polar surface, sigma-finiteness and product-Lebesgue suppliers below; no full Axiom of Choice or arbitrary-index selection is used.

[F1]

The complex-real identification and Euclidean norm are those of Complex m-space and its real coordinate dictionary, and the open unit ball Bm and open unit polydisc Dm are those of Balls, polydiscs and the distinguished boundary in Cm.

[F2]

For every nonnegative Borel function on Rn, polar coordinates give ∫f dλn=∫0∞∫Sn−1f(rω)rn−1 dσ(ω) dr (The polar surface set function on the unit sphere, Polar coordinates decompose Lebesgue measure into r^{n-1} dr d sigma).

[F3]

On each angular chart X(θ)=(cos⁡θ,sin⁡θ) of S1, the derivative has norm 1, so the surface density is 1; summing a partition of unity over one full turn gives chart surface measure ∫02π1 dθ=2π. The chart surface measure equals the polar measure σ (Surface integration on compact C1 hypersurfaces, Agreement with the existing polar sphere measure).

[F4]

For p,q>0, the Euler Beta integral is B(p,q)=∫01tp−1(1−t)q−1 dt and converges (Euler's real Beta integral, Euler's Beta integral converges exactly for two positive parameters); change of variables is valid on the improper interval after compact truncation (Change of variable in an improper integral).

[F5]

The Beta-Gamma identity is B(p,q)=Γ(p)Γ(q)/Γ(p+q), and Γ(n+1)=n! for every n∈N (The real Beta--Gamma identity, Γ(n+1)=n! for every natural number n, The factorial n! and the falling factorial nk‾, defined by recursion in N).

[F6]

Nonnegative product-measurable functions satisfy Tonelli's iterated-integral identity on sigma-finite measure spaces; under ACω, product Lebesgue measure agrees with Euclidean Lebesgue measure on Borel sets, and equality of these measures gives equality of nonnegative integrals by simple approximation and monotone convergence (Tonelli's theorem for nonnegative measurable functions on a sigma-finite product, The Borel product of R^m and R^n is the Borel sigma-algebra of R^{m+n}, On Borel subsets of R^{m+n}, the product lambda_m times lambda_n agrees with lambda_{m+n}, Lebesgue measure is sigma-finite, and every metrically bounded subset of Rn has finite outer measure, Every nonnegative measurable function admits an explicit increasing sequence of simple approximations, Monotone convergence for the integral).

[F7]

In real coordinates the displayed integrands are nonnegative polynomials times indicators of open balls or polydiscs. Finite sums and products of coordinate polynomials are continuous by the Ck algebra theorem; the preimage criterion makes continuous maps Borel measurable, and products of measurable functions remain measurable (Ck Euclidean maps and diffeomorphisms, Ck Euclidean maps are closed under componentwise algebra and composition, The Borel sigma-algebra of a topological space, A measurable function between measurable spaces, A continuous map has Borel preimages of Borel sets, Arithmetic and lattice operations preserve measurability whenever they are defined, Balls, polydiscs and the distinguished boundary in Cm).

[F8]
[F10]

Induction on the positive integer dimension is valid (The principle of mathematical induction).

[F9]

Multi-indices, their factorials and lengths, and complex nonnegative integer powers have the conventions used in the statement (Ck maps and multi-index derivative notation in Euclidean space, The factorial n! and the falling factorial nk‾, defined by recursion in N, Integer powers in the complex field).

Statement

Assume ACω (The Axiom of Countable Choice (ACω)). Let m≥1, and let λ2m be Lebesgue measure under Cm≅R2m. For every α∈Nm and every integer s≥0,

∫Bm∣zα∣2(1−∣z∣2)s dλ2m(z)=πmα! s!(m+s+∣α∣)!.

In particular,

∫Bm∣zα∣2 dλ2m(z)=πmα!(m+∣α∣)!,λ2m(Bm)=πmm!.

For the unit polydisc and the one-dimensional disc,

∫Dm∣zα∣2 dλ2m(z)=πm∏j<m(αj+1),λ2m(Dm)=πm,

and for every integer k≥0,

∫D∣z∣2k dλ2(z)=πk+1.

Proof

technique · direct, using a one-variable polar integral and induction by slicing the ball

Given: m≥1, ACω, and α∈Nm; the indices in zα use the zero-based convention in [F1] and [F9].

1.1A1F2F3F7given

For integers k,s≥0 and ρ>0, let Jk,s(ρ):=∫∣w∣<ρ∣w∣2k(ρ2−∣w∣2)s dλ2(w). The integrand extended by zero outside the disc is nonnegative Borel by [F7]. By [F2] and [F3], Jk,s(ρ)=2π∫0ρr2k+1(ρ2−r2)s dr.

2.1F4step 1.1givenalgebra

The substitution t=(r/ρ)2 is increasing from (0,ρ) onto (0,1) and has r dr=ρ2dt/2. Thus [F4] gives Jk,s(ρ)=πρ2(k+s+1)B(k+1,s+1).

3.1F5step 2.1givenalgebra

By [F5], B(k+1,s+1)=Γ(k+1)Γ(s+1)/Γ(k+s+2)=k!s!/(k+s+1)!. Hence Jk,s(ρ)=πρ2(k+s+1)k!s!/(k+s+1)!.

4.1F1F9step 3.1given

In dimension m=1, writing α=(k) and taking ρ=1 in step 3.1 gives I1((k),s)=πk!s!/(k+s+1)!, the asserted formula.

4.2A1F1F6F7F8F9step 3.1given

Fix m≥2 and assume the ball formula in dimension m−1 for all multi-indices and nonnegative integer weights. Write α=(α′,k) and slice Bm⊆Cm−1×C at z′∈Bm−1; its last-coordinate slice is ∣w∣<ρ(z′), where ρ(z′)=(1−∣z′∣2)1/2>0 by [F8]. For z′∉Bm−1 the slice is empty. By Tonelli, product-Lebesgue agreement, and step 3.1, Im(α,s)=πk!s!(k+s+1)!Im−1(α′,k+s+1).

4.3A1F1F6F7F9step 3.1given

The unit polydisc is the product of m unit discs and ∣zα∣2=∏j<m∣zj∣2αj. Repeated application of Tonelli and product-Lebesgue agreement, followed by step 3.1 with s=0 and ρ=1 in each coordinate, gives ∫Dm∣zα∣2 dλ2m=∏j<mπ/(αj+1)=πm/∏j<m(αj+1).

5.1F9F10step 4.1step 4.2givenalgebradischarge-induction

Substitution of the induction hypothesis into step 4.2 gives Im(α,s)=πk!s!(k+s+1)!⋅πm−1α′!(k+s+1)!(m+s+k+∣α′∣)!=πmα!s!(m+s+∣α∣)!, since α!=α′!k! and ∣α∣=∣α′∣+k. The base case step 4.1 and this induction step prove the weighted ball formula in every positive dimension by [F10].

6.1F9step 5.1step 4.3given∎

Setting s=0 in the ball formula gives its unweighted monomial integral; setting also α=0 gives λ2m(Bm)=πm/m!. Setting α=0 in step 4.3 gives λ2m(Dm)=πm, and the case m=1, s=0, α=(k) in the ball formula gives the stated disc integral.

LemmaStatement: AI-adaptedProof: AI-generatedprecheck passjudge pass (gpt-6.1-sol)audited 2026-10-08Open item page →

Sup-norm and first-derivative bounds by the L2 norm on compact subsets

Facts & Assumptions

Given: m≥1, the Axiom of Countable Choice ACω, an open set Ω⊆Cm, a nonempty compact set K⊆Ω, and a holomorphic function f∈L2(Ω).

[A1]

The only choice principle is ACω (The Axiom of Countable Choice (ACω)). It is used through the local mean-value lemma and the complex L2 Hilbert-space supplier; no full Axiom of Choice or sequence-selection principle is used.

[F1]

Read Cm as R2m with its Euclidean metric and norm (Complex m-space and its real coordinate dictionary).

[F2]

Open and closed polydiscs and balls have the coordinatewise definitions of Balls, polydiscs and the distinguished boundary in Cm.

[F3]

For a holomorphic g on an open set containing a closed polydisc Δ‾r(a), the local mean-value lemma gives ∣g(a)∣≤(πm∏j<mrj2)−1/2∥g∥L2(Δr(a)) (The mean-value L2 bound for holomorphic functions on a polydisc).

[F4]

If g is holomorphic on Δρ(a), rj<ρj, and M=sup⁡Γr(a)∣g∣, then ∣∂zαg(a)∣≤α!M∏j<mrj−αj (Cauchy estimates for mixed derivatives on a polydisc).

[F5]
[F6]

Multi-index notation and ∂0f=f use the convention of Ck maps and multi-index derivative notation in Euclidean space.

[F7]

Under ACω, complex L2(Ω) with its quotient norm is a Hilbert space, so the norm satisfies the triangle inequality and convergence implies the Cauchy property (L2 with the integral pairing is a Hilbert space, Complex Lp classes and Euclidean test-function conventions).

[F8]

If 0≤g≤h are measurable, then ∫g≤∫h (Monotonicity and nonnegative homogeneity of the nonnegative integral).

[F12]

Every Euclidean closed ball of positive radius in R2m is compact (For n≥1, every Euclidean closed ball and every Euclidean sphere of positive radius is compact).

[F14]

A locally uniform limit of holomorphic functions is holomorphic with locally uniform convergence of every complex derivative (Locally uniform limits of holomorphic functions are holomorphic, with locally uniform convergence of all derivatives).

[F15]

For nonnegative measurable functions, Fatou's lemma gives ∫lim inf⁡gn≤lim inf⁡∫gn (Fatou's lemma).

[F16]

Sums and scalar multiples of holomorphic functions are holomorphic (Sums, products and nonvanishing quotients of holomorphic functions are holomorphic).

Statement

Assume ACω (The Axiom of Countable Choice (ACω)). Let m≥1, let Ω⊆Cm be open, and let K⊆Ω be nonempty and compact. There are finite constants CK and CK,α for every multi-index α with ∣α∣≤1 such that every holomorphic f∈L2(Ω) satisfies

sup⁡z∈K∣f(z)∣≤CK∥f∥L2(Ω),sup⁡z∈K∣∂zαf(z)∣≤CK,α∥f∥L2(Ω).

Moreover, if a sequence of holomorphic L2(Ω) functions (fn) converges in L2(Ω) to an equivalence class g, then g has a holomorphic representative F and fn→F, ∂zαfn→∂zαF uniformly on K for every ∣α∣≤1.

Proof

technique · direct, combining a local mean-value estimate with polydisc Cauchy estimates

Given: m,Ω,K,f as in the statement.

1.1F1F9F10F11given

If Ωc=∅, set δ=1. Otherwise put q(z)=d(z,Ωc). By [F9] this is continuous, and for each z∈K openness gives an εz>0 with B(z,εz)⊆Ω, so q(z)≥εz>0. The minimum d0=min⁡z∈Kq(z) is positive by [F11]; set δ=min⁡{1,d0}. In either case, B‾(z,δ/2)⊆Ω for every z∈K. Let r=δ/(4m)>0.

2.1A1F1F2F3F7F8step 1.1given

For z∈K the closed polydisc Δ‾2r(z) is contained in B‾(z,δ/2), since each coordinate difference is at most 2r and 2mr=δ/2. If ζ∈Γr(z), each coordinate of a point in Δ‾r(ζ) differs from z by at most 2r as well, so Δ‾r(ζ)⊆B‾(z,δ/2). Thus these closed polydiscs lie in Ω. For each such ζ, the local mean bound [F3], monotonicity [F8], and the L2 norm definition in [F7] give ∣f(ζ)∣2≤(πr2)−m∫Δr(ζ)∣f∣2≤(πr2)−m∥f∥L2(Ω)2, so sup⁡ζ∈Γr(z)∣f(ζ)∣≤(πr2)−m/2∥f∥L2(Ω).

3.1F2F4F6step 2.1given

Since f is holomorphic on Δ2r(z) and r<2r, apply [F4] with outer polyradius 2r and inner polyradius r. For every ∣α∣≤1 this gives ∣∂zαf(z)∣≤α!r−∣α∣(πr2)−m/2∥f∥L2(Ω). This includes α=0, where ∂z0f=f by [F6].

4.1step 3.1givenalgebra

Taking CK=(πr2)−m/2 and CK,α=α!r−∣α∣(πr2)−m/2 in step 3.1 proves both compact estimates.

5.1A1F1F7F10F12F13F16step 4.1given

Now let (fn) converge in L2(Ω) to g. By [F7] it is Cauchy in that norm. For every nonempty compact K′⊆Ω, applying the first estimate of step 4.1 to the holomorphic L2 difference fn−fk (holomorphic by [F16]) shows that (fn) is uniformly Cauchy on K′. Every point of Ω has an open ball neighborhood contained in Ω by [F10]; its concentric closed ball of half the radius is compact by [F12]. Completeness of C in [F13] therefore gives a pointwise limit F on Ω, and letting k→∞ in the uniform Cauchy bound shows fn→F uniformly on every compact subset of Ω.

6.1F6F14step 5.1

The convergence in step 5.1 is locally uniform, so [F14] implies that F is holomorphic and that ∂zαfn→∂zαF locally uniformly for every multi-index α. In particular this convergence is uniform on the compact set K for ∣α∣≤1.

7.1A1F5F7F15step 5.1step 6.1given∎

To identify the L2 limit, fix ε>0 and choose N so that ∥fn−fk∥L2(Ω)<ε whenever n,k≥N, using convergence to g and [F7]. For fixed n≥N, fk(z)→F(z) pointwise; the functions are measurable since fn and the holomorphic F are continuous by [F5]. Fatou's lemma [F15] applied to ∣fn−fk∣2 gives ∥fn−F∥L2(Ω)2≤lim inf⁡k→∞∥fn−fk∥L2(Ω)2≤ε2. Thus fn−F∈L2(Ω), and the vector-space property in [F7] gives F∈L2(Ω); the same estimate for all n≥N proves fn→F in L2(Ω). Uniqueness of limits in the norm metric gives [F]=g.

LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-6.1-sol)audited 2026-10-08Open item page →

The disc trace space is the Hardy boundary space and the Szegő family reproduces H2

Facts & Assumptions

[A1]

The only choice principle is the Axiom of Countable Choice ACω (The Axiom of Countable Choice (ACω)). The Hardy boundary theorem, Hardy-space and torus conventions, L2 Hilbert structure, and Riesz/Szegő construction below are used under this hypothesis; no full Axiom of Choice or arbitrary-index selection is used.

[F1]

The unit circle is parametrized by ζ=e2πit, normalized Haar measure is dm=dt, and m(T)=1 (The one-dimensional torus and its normalized Haar integral).

[F2]

Hp(D) is defined by the supremum of the radial Lp means; in particular H2(D) is a normed complex vector space and H2(D)⊆H1(D) (Analytic Hardy spaces on the unit disc, Radial p-means of a holomorphic function are nondecreasing).

[F3]

For f∈H2(D), the Fatou boundary theorem gives f∗∈L2(T,m), ∥fr−f∗∥2→0 as r↑1, and ∥f∗∥2=∥f∥H2 (Fatou's boundary theorem for analytic Hardy spaces).

[F4]

For f∈H1(D), its boundary function satisfies the Cauchy representation f(w)=12πi∮Tf∗(ζ)ζ−w dζ=∫Tf∗(ζ)1−wζ‾ dm(ζ) (Cauchy representation of an H1 function from its boundary values).

[F5]

L2(T,m) with ⟨g,h⟩=∫gh‾ dm is a complex Hilbert space, the pairing is linear in its first variable, and it satisfies Cauchy–Schwarz (L2 with the integral pairing is a Hilbert space).

[F6]

The Hardy boundary space in the Szegő definition is the L2 closure of traces from O(D)∩C(D‾) (The Hardy boundary space, Szegő projection and Szegő kernel on a smoothly bounded domain).

[F7]

Every bounded linear functional on a complex Hilbert space has a unique representing vector y with L(x)=⟨x,y⟩ under the first-variable-linear convention (Riesz representation for Hilbert spaces).

[F8]

A function on an open subset of C is holomorphic when it is complex differentiable at each point (Complex differentiability at a point, the complex derivative, holomorphic functions, and entire functions).

[F9]

Complex differentiability implies continuity (Complex differentiability at a point implies continuity there).

[F10]

Conjugation is involutive and zz‾=∣z∣2, so ∣z‾∣=∣z∣; modulus is multiplicative and subadditive, hence the reverse triangle inequality follows (Conjugation is an involutive real-field automorphism, zz‾=∣z∣2, and modulus is definite, multiplicative, and subadditive).

[F12]

A continuous real-valued function on a nonempty compact metric space is bounded and attains its maximum (A continuous real-valued function on a nonempty compact metric space is bounded and attains a greatest and a least value).

[F16]

For nonnegative measurable functions, ∫lim inf⁡gn dm≤lim inf⁡∫gn dm (Fatou's lemma).

[F17]

Szegő regularity means that trace evaluation is well defined and bounded on the generating trace space, and its continuous extension is holomorphic in the interior variable (The Hardy boundary space, Szegő projection and Szegő kernel on a smoothly bounded domain).

[F18]

For a Szegő-regular pair, the Szegő kernel is defined by Sσ(z,w):=Ez(Sw), where Sw is the Riesz representer of Ew (The Hardy boundary space, Szegő projection and Szegő kernel on a smoothly bounded domain, Riesz representation for Hilbert spaces).

Statement

Assume ACω (The Axiom of Countable Choice (ACω)). Let D⊂C be the unit disc and let m be normalized Haar measure on T=∂D. Write H2(∂D,m) for the boundary space in The Hardy boundary space, Szegő projection and Szegő kernel on a smoothly bounded domain, with its first-variable-linear L2 pairing.

  • The traces of functions holomorphic on a neighbourhood of D‾ are dense in H2(∂D,m), and the boundary-value range {f∗:f∈H2(D)} is closed in L2(T,m). The map f↦f∗ is an isometric isomorphism H2(D)→H2(∂D,m).

  • For every w∈D, the evaluation f↦f(w) is bounded on H2(D), and the function Sw(ζ):=1/(1−w‾ζ) belongs to H2(∂D,m). For all f∈H2(D), f(w)=∫Tf∗(ζ)Sw(ζ)‾ dm(ζ),∣f(w)∣≤∥f∥H21−∣w∣. Consequently (D,m) is Szegő-regular and its two-variable Szegő kernel is S(z,w)=1/(1−zw‾).

Proof

technique · direct, using radial convergence, the $H^1$ Cauchy representation, and a local closed-range argument

Given: ACω, D, normalized Haar measure m, and the analytic and boundary Hardy spaces just defined.

1.1A1F2F3F4given

For every f∈H2(D), [F3] gives f∗∈L2 and ∥f∗∥2=∥f∥H2; boundary limits are linear, so f↦f∗ is a linear isometry. If f∗=0, then f∈H1 by [F2] and [F4] gives f(w)=0 for every w∈D, proving injectivity.

1.2A1F3F8F9given

Fix f∈H2(D) and 0<r<1. The dilate gr(z):=f(rz) is holomorphic on {∣z∣<1/r}: for z there, its difference quotient tends to rf′(rz) by [F8]. It is continuous on a neighbourhood of D‾ by [F9], and its boundary trace is f(rζ). By [F3], these traces converge to f∗ in L2 as r↑1, so the neighbourhood-holomorphic traces are dense in the boundary-value range.

1.3A1F2F3F6F10F11F12given

Let G∈O(D)∩C(D‾), the generating class in [F6]. By [F11] and [F12], ∣G∣ is bounded on D‾, hence every radial L2 mean of G is bounded and G∈H2(D) by [F2]. Continuity on D‾ makes its radial boundary limit equal to G∣T at every point, so [F3] identifies its trace with G∗ in L2. Thus every generating trace in [F6] belongs to the boundary-value range.

2.1A1F1F2F3F4F5F10step 1.1given

Let hn=fn∗ be a sequence in the boundary-value range converging in L2 to h. The preimage fn is unique by step 1.1, so this sequence is well defined; [F3] applied to differences shows (fn) is Cauchy in H2. For fixed z∈D, [F4] applies to fn−fk∈H1. With ηz(ζ):=1/(1−zζ‾), [F1] and [F10] give ∣ηz(ζ)∣≤(1−∣z∣)−1 and ∥ηz∥2≤(1−∣z∣)−1. Cauchy–Schwarz in [F5] therefore yields ∣fn(z)−fk(z)∣≤∥fn∗−fk∗∥21−∣z∣.

3.1F14F15step 2.1given

By [F14], fn(z) has a limit F(z) for each z∈D. Given z0∈D, choose ρ with ∣z0∣<ρ<1; the estimate of step 2.1, uniformly for ∣z∣<ρ, makes fn uniformly Cauchy on that neighbourhood. Hence fn→F locally uniformly, and [F15] makes F holomorphic.

4.1F2F16step 2.1step 3.1given

The Cauchy sequence (fn) is bounded in H2. For every 0≤r<1, pointwise convergence on rT and [F16] give ∫T∣F(rζ)∣2 dm(ζ)≤lim inf⁡n→∞∫T∣fn(rζ)∣2 dm(ζ)≤sup⁡n∥fn∥H22, so F∈H2. Given ε>0, choose N with ∥fn−fk∥H2<ε for n,k≥N. For fixed n≥N and each r, another application of [F16] as k→∞ gives ∫T∣fn(rζ)−F(rζ)∣2 dm(ζ)≤ε2. Taking the supremum over r proves fn→F in H2.

5.1F3F5step 4.1given

By [F3] applied to fn−F, its boundary traces converge in L2 to F∗. Since fn∗→h as well and L2 limits are unique, h=F∗. This proves that the boundary-value range is closed.

6.1A1F6step 1.1step 1.2step 1.3step 5.1

The neighbourhood-holomorphic traces in step 1.2 lie in the generating trace space of [F6], and step 1.3 shows every generator lies in the boundary-value range. Step 1.2 gives density of the smaller trace space in that range, and step 5.1 proves the range is closed. Therefore the closure defining H2(∂D,m) equals the boundary-value range; step 1.1 makes f↦f∗ an isometric isomorphism onto it.

7.1A1F1F2F3F4F5F10F13step 1.3step 6.1

Fix w∈D. If w=0, sw(z)=1; if w≠0, choose R=(1+1/∣w∣)/2, so 1<R<1/∣w∣ and ∣w‾z∣<∣w∣R=(1+∣w∣)/2<1 for ∣z∣<R, hence 1−w‾z≠0 by [F10]. Thus sw(z):=1/(1−w‾z) is holomorphic on a neighbourhood of D‾ by [F13]. Step 1.3 identifies its trace Sw(ζ)=sw(ζ) with sw∗ in the boundary-value range, and step 6.1 puts it in the boundary space. For ζ∈T, [F1] and [F10] give ∣1−w‾ζ∣≥1−∣w∣, so ∣Sw(ζ)∣≤(1−∣w∣)−1, hence ∥Sw∥2≤(1−∣w∣)−1. For f∈H2⊆H1, [F4] gives f(w)=⟨f∗,Sw⟩; [F5] and [F3] then give the stated bounded-evaluation estimate and reproducing identity.

8.1A1F5F6F7F17F18step 1.3step 5.1step 6.1step 7.1given∎

For every generating trace tr⁡G from [F6], step 1.3 gives G∈H2 and G∗=G∣T, so step 7.1 shows G(w)=⟨tr⁡G,Sw⟩. Thus trace evaluation is well defined and bounded on the generating space, and Ew(h):=⟨h,Sw⟩ is its continuous extension to the closure, as required by [F17]. By step 6.1 every h in that closure is f∗ for a unique f∈H2; step 7.1 gives Ez(h)=f(z), which is holomorphic in z. In particular Sw=sw∗, so Ez(Sw)=sw(z). The boundary range is closed by step 5.1 in the Hilbert space [F5], hence it is a Hilbert space; [F7] and [F18] identify Sw as the unique representer used in the kernel definition. Therefore S(z,w)=Ez(Sw)=sw(z)=11−zw‾, proving Szegő regularity and the claimed normalization.

LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-6.1-sol)audited 2026-10-08Open item page →

Monomial integrals on the sphere and orthonormality on the distinguished torus

Facts & Assumptions

[A1]

The only choice principle assumed is the Axiom of Countable Choice ACω (The Axiom of Countable Choice (ACω)). It is carried through the polar-coordinate, polar-surface, previous ball-integral, normalized-torus and linear-change-of-variables suppliers; no full Axiom of Choice or arbitrary-index selection is used.

[F1]

Under Cm≅R2m, the unit ball and the unit sphere are the Euclidean ball and sphere for the norm ∣z∣2=∑j<m∣zj∣2 (Complex m-space and its real coordinate dictionary, Balls, polydiscs and the distinguished boundary in Cm).

[F2]

For a nonnegative Borel function F on Rn, polar coordinates give ∫RnF(x) dλn(x)=∫0∞rn−1∫Sn−1F(rω) dσ(ω) dr (Polar coordinates decompose Lebesgue measure into r^{n-1} dr d sigma).

[F3]

The polar surface measure is σ(E)=2mλ2m({rω:ω∈E, 0<r≤1}) for Borel E⊆S2m−1; the polar-coordinate theorem makes it a finite Borel measure (The polar surface set function on the unit sphere, Polar coordinates decompose Lebesgue measure into r^{n-1} dr d sigma).

[F4]

For α∈Nm, the preceding ball-integral lemma proves that ∣zα∣21Bm is nonnegative Borel and gives ∫Bm∣zα∣2 dλ2m(z)=πmα!(m+∣α∣)!,λ2m(Bm)=πmm! (Weighted monomial integrals and monomial norms for the disc, ball and polydisc).

[F5]

mTm is the product of the normalized Haar probabilities on the circle and has total mass one (The one-dimensional torus and its normalized Haar integral).

[F6]

Multi-indices have α∈Nm, ∣α∣=∑j<mαj, and zα=∏j<mzjαj; complex powers are defined recursively for natural exponents (Ck maps and multi-index derivative notation in Euclidean space, Integer powers in the complex field).

[F9]

Multiplication of one complex coordinate by η=a+ib acts on its real coordinate pair by (a−bba), whose determinant is a2+b2=∣η∣2 (Complex m-space and its real coordinate dictionary, Real and imaginary parts, complex conjugation, and modulus).

[F11]

A measurable measure-preserving self-map preserves integrals of integrable complex functions (Measure-preserving transformations and systems, Integral invariance under measure-preserving maps).

[F13]

Translation of any one coordinate preserves the product normalized Haar measure on Tm (The one-dimensional torus and its normalized Haar integral).

[F14]

The pointwise product of measurable functions is measurable (Arithmetic and lattice operations preserve measurability whenever they are defined).

Statement

Assume ACω (The Axiom of Countable Choice (ACω)). Let m≥1, let σ be the polar surface measure on S2m−1⊆Cm≅R2m, and set σ1:=σ/σ(S2m−1). For all multi-indices α,β∈Nm,

∫S2m−1ζαζβ‾ dσ1=δαβ(m−1)! α!(m−1+∣α∣)!,∫S2m−1∣ζα∣2 dσ=2πmα!(m−1+∣α∣)!,

where δαβ=1 if α=β and 0 otherwise. On the distinguished torus Tm with product normalized Haar measure mTm,

∫Tmζαζβ‾ dmTm=δαβ.

Proof

technique · direct, using polar decomposition for the diagonal moments and coordinate rotations for orthogonality

Given: ACω, m≥1, the polar surface measure σ, and α,β∈Nm.

1.1A1F1F2F3F4F12given

Apply [F2] to the indicator of the open, hence Borel, unit ball. For 0<r<1 every rω lies in Bm, while for r>1 none does, so λ2m(Bm)=∫01r2m−1 dr σ(S2m−1)=σ(S2m−1)2m. By [F4], σ(S2m−1)=2mπm/m!=2πm/(m−1)!, which is finite and positive, so σ1 is well defined.

1.2A1F3F9F10F11F12given

Fix j<m and a unit complex number η∈C with ∣η∣=1, and let Rj,η multiply the jth complex coordinate by η and fix the others. It maps the unit sphere to itself; its real matrix is the identity except for the jth block in [F9], whose determinant is ∣η∣2=1. Since Rj,η and its inverse are continuous, both Rj,ηE and Rj,η−1E are Borel for Borel E⊆S2m−1 by [F12]. The conical set in [F3] is carried onto the cone for Rj,ηE, so [F10] gives σ(Rj,ηE)=σ(E); applying this equality to Rj,η−1E gives σ(Rj,η−1E)=σ(E). Thus the continuous map is measure preserving, and [F11] makes the integrals of the bounded monomial products in [F12] invariant.

2.1A1F2F4F6F12F14step 1.1given

For a fixed α, set Mα:=∫S2m−1∣ωα∣2 dσ. The integrand ∣zα∣21Bm is nonnegative Borel by [F12] and [F14]; since ∣(rω)α∣2=r2∣α∣∣ωα∣2, [F2] and [F4] give πmα!(m+∣α∣)!=∫01r2m−1+2∣α∣ dr Mα=Mα2(m+∣α∣). Hence Mα=2πmα!/(m−1+∣α∣)!, and division by the total mass in step 1.1 gives the normalized diagonal moment.

2.2A1F6F7F8F11F12step 1.1step 1.2given

Suppose α≠β and choose j<m with a:=αj≠b:=βj. Let d:=∣a−b∣>0 and η:=eiπ/d, so [F7] gives ∣η∣=1 and ηd=−1. By the recursive powers in [F6], induction and commutativity give ηaη‾ b=−1: if a>b, factor (ηη‾)bηa−b=ηd; if b>a, factor (ηη‾)aη‾ b−a=ηd‾. Under Rj,η the integrand ζαζβ‾ is multiplied by this scalar. Integral invariance from step 1.2 therefore makes its integral equal to its negative, so it is zero. The integrand is integrable by [F12] and finiteness in step 1.1.

3.1A1F5F6F7F8F11F12F13step 2.2given

On Tm, the normalized product Haar measure is invariant under translation of any one coordinate by [F13]. For α≠β, choose j,a,b,d,η as in step 2.2 and translate that coordinate by the torus element represented by 1/(2d), which multiplies it by η=eiπ/d. The integrand is multiplied by ηaη‾ b=−1 by the same power calculation, so integral invariance [F11] makes the integral zero. If α=β, the integrand is identically one and [F5] gives total measure one; hence the integral is one.

4.1step 2.1step 2.2step 3.1∎

Step 2.1 gives the unnormalized and normalized sphere diagonal moments; step 2.2 gives the off-diagonal sphere moments; step 3.1 gives all distinguished-torus moments. Together these are exactly the three displayed formulas.

DefinitionDefinition: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-6.1-sol)audited 2026-10-08Open item page →

The Bergman space A2(Ω) and the Bergman kernel

Definition

Assume the Axiom of Countable Choice ACω (The Axiom of Countable Choice (ACω)), let m≥1, and let Ω⊆Cm be a nonempty open set. Read Cm as R2m through Complex m-space and its real coordinate dictionary. Give Ω the trace of the Lebesgue sigma-algebra and the restricted measure λΩ induced by λ2m, namely λΩ(E):=λ2m(E) for E∈L(R2m)∣Ω; write L2(Ω) for the resulting complex L2 space.

Let A2(Ω) be the holomorphic functions f on Ω with ∫Ω∣f∣2 dλΩ<∞, and let A2(Ω):={[f]L2(Ω):f∈A2(Ω)}. The argument below shows that each such class has a unique holomorphic representative and that A2(Ω) is a closed complex linear subspace of L2(Ω). Give it the inherited inner product ⟨[f],[g]⟩:=∫Ωfg‾ dλΩ, which is linear in the first variable. Thus A2(Ω) is a Hilbert space.

For each w∈Ω, evaluation Ew([f])=f(w) is a bounded linear functional on A2(Ω). Riesz representation gives a unique kw∈A2(Ω) such that f(w)=⟨[f],kw⟩(f∈A2(Ω)). The Bergman kernel is KΩ(z,w):=kw(z),z,w∈Ω, where kw(z) means evaluation of the unique holomorphic representative of kw. In particular kz=KΩ(⋅,z) and the displayed Riesz identity is the reproducing property. For Ω=Cm, A2(Ω)={0} and KΩ≡0; no positivity of KΩ is asserted for general unbounded Ω.

Facts & Assumptions

[A1]

The only choice principle is ACω; it is used by the Lebesgue, complex L2, Bergman mean/evaluation, and Riesz suppliers, and to select an approximating sequence in the closedness argument. No full Axiom of Choice is used (The Axiom of Countable Choice (ACω)).

[F2]

Holomorphic functions on Ω are continuous; their restrictions are Borel measurable on the subspace Ω, and the subspace Borel sigma-algebra is the trace of the ambient Borel sigma-algebra, hence is contained in the trace Lebesgue sigma-algebra (Holomorphic functions on an open subset of Cm, Holomorphic functions of several variables are smooth and their complex derivatives are holomorphic, The Borel sigma-algebra of a subspace is the trace of the ambient Borel sigma-algebra, Assuming countable choice, every Borel subset of Rn is Lebesgue measurable).

[F3]

Complex linear combinations of holomorphic functions are holomorphic (Sums, products and nonvanishing quotients of holomorphic functions are holomorphic).

[F4]

With the pairing ∫fg‾ dλΩ, complex L2(Ω) is a Hilbert space under ACω; the pairing is linear in its first variable and induces the quotient L2 norm (The complex L2 pairing on equivalence classes, Complex Lp classes and Euclidean test-function conventions, L2 with the integral pairing is a Hilbert space).

[F5]

On each nonempty compact K⊆Ω, point evaluation is bounded by sup⁡K∣f∣≤CK∥f∥L2(Ω) (Sup-norm and first-derivative bounds by the L2 norm on compact subsets).

[F6]

An L2 limit class of holomorphic L2 functions has a holomorphic representative (Sup-norm and first-derivative bounds by the L2 norm on compact subsets).

[F7]

For a holomorphic f on a polydisc with closure in Ω, ∣f(a)∣2≤1πm∏j<mrj2∫Δr(a)∣f∣2 dλ2m, where Δr(a) is the polydisc of positive radii (Balls, polydiscs and the distinguished boundary in Cm, The mean-value L2 bound for holomorphic functions on a polydisc).

[F8]

Every bounded linear functional on a complex Hilbert space has a unique Riesz representer y with F(x)=⟨x,y⟩ (Riesz representation for Hilbert spaces).

Proof

technique · direct, using the preceding compact evaluation and mean-value estimates

Given: ACω, m≥1, a nonempty open Ω⊆Cm, and the Lebesgue measure and function-space conventions above.

1.1F2F3F4F5given

By [F2], every holomorphic function is measurable for λΩ, so the definition of A2(Ω) is meaningful. If f,g∈A2(Ω) determine the same L2 class, then h=f−g is holomorphic by [F3] and has ∥h∥L2(Ω)=0 by [F4]. For each w∈Ω, the singleton {w} is compact, so [F5] gives ∣h(w)∣≤C{w}∥h∥L2(Ω)=0. Thus f=g on Ω, proving uniqueness of the holomorphic representative and well-definedness of evaluation.

1.2A1F1F4F7given

If Ω=Cm, then for every a∈Cm and every R>0, [F7] gives ∣f(a)∣2≤(πR2)−m∫ΔR(a)∣f∣2 dλ2m≤(πR2)−m∥f∥L2(Cm)2. Letting R→∞ and using m≥1 gives f(a)=0 for every a, so A2(Cm)={0}.

2.1A1F3F4F6step 1.1given

The image A2(Ω) is a complex linear subspace by [F3] and [F4]. To prove it is closed, let g lie in its L2 closure. For each n≥1, the set of A2 classes within distance 1/n of g is nonempty; [A1] selects a sequence of such classes, and step 1.1 gives each a unique holomorphic representative fn. Then fn→g in L2(Ω), so [F6] supplies a holomorphic representative F of g. Since g∈L2(Ω), this representative belongs to A2(Ω), and g∈A2(Ω). Hence the image is closed.

3.1A1F3F4F5F8step 1.1step 2.1given

The closed subspace A2(Ω) of the Hilbert space in [F4] is complete: each Cauchy sequence in it converges in L2(Ω) and its limit lies in A2(Ω) by step 2.1. For fixed w∈Ω, evaluation is well-defined by step 1.1, complex-linear by [F3], and bounded by [F5] with K={w}. Applying [F8] gives a unique kw∈A2(Ω) such that f(w)=⟨[f],kw⟩ for every f∈A2(Ω).

4.1step 1.1step 1.2step 3.1∎

Define KΩ(z,w)=kw(z) using the unique holomorphic representative from step 1.1. Then kz=KΩ(⋅,z) and the identity in step 3.1 is exactly the reproducing property. If Ω=Cm, step 1.2 gives A2(Cm)={0}, so every evaluation functional and its unique Riesz representer vanish; hence KCm≡0.

TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-6.1-sol)audited 2026-10-08Open item page →

A2(Ω) is closed, and the Bergman kernel is the sum over any complete orthonormal system

Statement

Assume ACω (The Axiom of Countable Choice (ACω)), let m≥1, and let Ω⊆Cm be a nonempty open set. The Bergman space A2(Ω) of The Bergman space A2(Ω) and the Bergman kernel is a closed complex linear subspace of L2(Ω).

Let (ej)j∈J be any complete orthonormal system of A2(Ω), when one exists. For arbitrary J, interpret each sum as the net of finite subsum values ordered by inclusion. Then for all z,w∈Ω, KΩ(z,w)=∑j∈Jej(z)ej(w)‾. For every pair of nonempty compact sets K,L⊆Ω and every ε>0, there is a finite F0⊆J such that for every finite G⊆J∖F0, sup⁡(z,w)∈K×L∑j∈G∣ej(z)ej(w)‾∣<ε. Thus the series converges absolutely and uniformly on compact subsets of Ω×Ω with its Euclidean product metric and is independent of the chosen complete orthonormal system; an empty compact set gives a vacuous uniform-convergence claim. The kernel is holomorphic in z, antiholomorphic in w, and KΩ(w,z)=KΩ(z,w)‾.

Facts & Assumptions

[A1]

The only choice principle is ACω. It is inherited through the preceding Bergman-space closure argument, the arbitrary-index Fourier expansion, and Riesz representation; this proof uses no full Axiom of Choice (The Axiom of Countable Choice (ACω)).

[F1]

A2(Ω) is a closed complex Hilbert subspace of L2(Ω) for the first-variable-linear integral pairing (The Bergman space A2(Ω) and the Bergman kernel).

[F2]

For every nonempty compact K⊆Ω, point evaluation and all first complex partials are bounded by constants times the L2 norm (Sup-norm and first-derivative bounds by the L2 norm on compact subsets).

[F3]

For a complete orthonormal family (ej)j∈J in a Hilbert space, the finite-subset Fourier net converges in norm to each vector (Fourier expansion in a Hilbert space).

[F4]

For a finite orthonormal projection PF, both PF and the residual I−PF are contractions by Pythagoras; for finite G⊆J∖F, PGx=PG(I−PF)x (Orthonormal families, complete orthonormal systems and Hilbert bases, Pythagoras and finite orthogonal sums).

[F5]

For finite scalar lists, Cauchy–Schwarz bounds the sum of products by the product of the ℓ2 norms (Square-summable families on an arbitrary index set and the space ℓ2(I)).

[F6]

For holomorphic f, Df(a)h=∑j<m(∂zjf(a))hj; holomorphic functions are continuous and finite linear combinations remain holomorphic (A holomorphic function of several variables is continuous and separately holomorphic, Sums, products and nonvanishing quotients of holomorphic functions are holomorphic).

[F8]

A continuous differentiable curve in the Banach space C whose derivative has norm at most M varies by at most M times the parameter distance; C is Banach for its usual modulus norm (Banach space, The complex plane is complete, and convergence is equivalent to convergence of real and imaginary parts, Mean value inequality for a differentiable Banach-valued curve).

[F10]

Every at most countable infinite set is in bijection with N; finite support is handled by a finite sum (Finite, countably infinite, countable, uncountable).

[F11]

A locally uniform limit of holomorphic functions on an open set is holomorphic (Locally uniform limits of holomorphic functions are holomorphic, with locally uniform convergence of all derivatives).

[F12]

Riesz representation is isometric: the representing vector has norm equal to the functional norm (Riesz representation for Hilbert spaces); the Hilbert pairing is conjugate symmetric (Real and complex inner-product spaces and their induced length).

[F13]

A compact metric space has a finite subcover for every open cover, and a compact subset is compact in the restricted metric (Open cover, subcover, compact metric space, and compact subset of a metric space).

[F14]

With the Euclidean product metric d((z,w),(z′,w′))=(∥z−z′∥2+∥w−w′∥2)1/2, each coordinate projection is 1-Lipschitz. Hence the coordinate projections of a compact subset are compact and contain it in their product (Complex m-space and its real coordinate dictionary, A continuous image of a compact space is compact; a continuous real-valued map on a nonempty compact space attains a maximum and a minimum; and a continuous bijection from a compact space to a Hausdorff space is a homeomorphism).

[F15]

Each evaluation Ew is bounded and has a unique Riesz representer kw with f(w)=⟨f,kw⟩, and KΩ(z,w)=kw(z) (The Bergman space A2(Ω) and the Bergman kernel).

[F16]

The coefficient support of each vector for a complete orthonormal family is at most countable (Fourier expansion in a Hilbert space).

[F17]

For an arbitrary index set, a scalar sum is the limit of its finite-subset net (Square-summable families on an arbitrary index set and the space ℓ2(I)).

Proof

technique · direct, using Fourier projections, compact evaluation estimates, and Riesz representation

Given: ACω, m≥1, a nonempty open Ω⊆Cm, and a complete orthonormal system (ej)j∈J of A2(Ω).

1.1A1F1given

The closedness assertion is the closed-subspace conclusion already proved in The Bergman space A2(Ω) and the Bergman kernel; the inner product and pointwise representatives are those fixed there.

1.2A1F2F3F12F15given

Fix w∈Ω and let PFkw:=∑j∈F⟨kw,ej⟩ej for finite F⊆J. By [F3], PFkw→kw in A2(Ω). For each j, the reproducing identity in [F15] and conjugate symmetry [F12] give ⟨kw,ej⟩=ej(w)‾, so PFkw(z)=∑j∈Fej(z)ej(w)‾. For every nonempty compact K⊆Ω, the compact evaluation bound [F2] gives sup⁡z∈K∣PFkw(z)−KΩ(z,w)∣≤CK∥PFkw−kw∥L2(Ω)→0; the empty case is vacuous.

1.3A1F2F5F6F7F8F9F12F15

Fix w0∈Ω. By [F9] choose r>0 with B(w0,r)⊆Ω, and put Q=B‾(w0,r/2), a compact subset of Ω. For w,w′∈B(w0,r/4) the segment γ(t)=w+t(w′−w), 0≤t≤1, stays in Q by the triangle inequality. Write ϵℓ for the multi-index with a 1 in coordinate ℓ and zeros elsewhere. For f∈A2(Ω) with ∥f∥2≤1, [F7] gives ddtf(γ(t))=∑ℓ<m∂zℓf(γ(t))(wℓ′−wℓ); by [F2] and finite Cauchy–Schwarz [F5], its modulus is at most MQ∥w′−w∥, where MQ=(∑ℓ<mCQ,ϵℓ2)1/2. The curve is continuous by [F6], so [F8] yields ∣f(w′)−f(w)∣≤MQ∥w′−w∥. Taking the supremum over the unit ball of A2 proves ∥Ew′−Ew∥≤MQ∥w′−w∥; by the isometry in [F12], ∥kw′−kw∥2≤MQ∥w′−w∥. Thus w↦kw is locally Lipschitz and continuous.

2.1F3F4F9F13step 1.3given

If C is a compact subset of A2(Ω) in its norm metric, the net (PFx) converges to x uniformly for x∈C; the empty case is vacuous. For ε>0, the norm balls of radius ε/3 centered at points of C are open by the triangle inequality and form a cover in that metric, so [F13] gives a finite subcover with centers x1,…,xN. For each center choose a finite Fi with ∥PFxi−xi∥<ε/3 whenever F⊇Fi, using [F3]. For F0=⋃iFi and F⊇F0, contraction of I−PF from [F4] gives sup⁡x∈C∥PFx−x∥<2ε/3. By [F9] and step 1.3, k(K) and k(L) are compact for compact K,L⊆Ω, so this uniform convergence applies to both section families.

2.2A1F2F3F6F10F11F16step 1.2

Fix w∈Ω. By [F16], the support of (⟨kw,ej⟩)j∈J is at most countable; if it is finite the expansion is finite, and otherwise [F10] enumerates it by a sequence. The corresponding finite partial sums converge to kw in norm by [F3] and uniformly on every compact subset in the variable z by [F2]. Each partial sum is holomorphic in z by [F6], so [F11] makes z↦KΩ(z,w) holomorphic.

3.1F2F4F5F9F14F17step 1.2step 2.1

Let SF(z,w):=∑j∈Fej(z)ej(w)‾=PFkw(z) as in step 1.2. Step 2.1 and [F2] show SF→KΩ uniformly on each K×L with K,L⊆Ω compact. For ε>0, apply step 2.1 to the compact sets k(K) and k(L) with tolerance ε, and take the union F0 of the resulting finite index sets. For every finite G⊆J∖F0, finite Cauchy–Schwarz [F5] and the orthogonal projections [F4], with F=F0, give ∑j∈G∣ej(z)ej(w)‾∣≤∥PGkz∥2∥PGkw∥2≤∥kz−PF0kz∥2∥kw−PF0kw∥2<ε uniformly on K×L. Thus the series converges absolutely and uniformly there. Any compact subset of Ω×Ω is contained in the product of its compact coordinate projections by [F14], so the convergence holds on every such compact subset.

4.1F12F15step 3.1step 2.2∎

For z,w∈Ω, KΩ(z,w)=⟨kw,kz⟩ by the reproducing identity [F15], so conjugate symmetry [F12] gives KΩ(w,z)=KΩ(z,w)‾. Thus the kernel is antiholomorphic in w as well as holomorphic in z by step 2.2. Since step 3.1 identifies every complete orthonormal system's sum with the kernel defined in [F15], the expansion is basis-independent.

LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-10-08Open item page →

Monomials form complete orthogonal systems of the Bergman spaces of the disc, the ball and the polydisc

Statement

Assume ACω (The Axiom of Countable Choice (ACω)) and let m≥1. For k≥0 and α∈Nm, the monomials in each of A2(D), A2(Bm) and A2(Dm) are pairwise orthogonal. Their squared norms are, respectively, ∥zk∥A2(D)2=πk+1,∥zα∥A2(Bm)2=πmα!(m+∣α∣)!,∥zα∥A2(Dm)2=πm∏j<m(αj+1). Thus the normalized monomials form complete orthonormal systems in all three Bergman spaces. Equivalently, for each of these domains Ω, a function f∈A2(Ω) orthogonal to every monomial is identically zero.

Facts & Assumptions

[A1]

The only choice principle is ACω: it enters through the Bergman Hilbert structure, monomial norms, real-linear change of variables for rotations, Borel-to-Lebesgue measurability, and the Hilbert-space completeness criterion; no full Axiom of Choice is used (The Axiom of Countable Choice (ACω)).

[F1]

The Bergman definition identifies A2 with holomorphic L2 classes, gives the first-variable-linear integral pairing, and provides their unique holomorphic representatives (The Bergman space A2(Ω) and the Bergman kernel).

[F2]

The monomial square norms on the disc, ball and polydisc are the formulas in the statement; they are positive and finite (Weighted monomial integrals and monomial norms for the disc, ball and polydisc).

[F3]

Each coordinate projection is holomorphic since its increment at a in direction h is hj; finite products of holomorphic functions are holomorphic and holomorphic functions are continuous (Holomorphic functions on an open subset of Cm, Sums, products and nonvanishing quotients of holomorphic functions are holomorphic, A holomorphic function of several variables is continuous and separately holomorphic).

[F4]

On every polydisc centered at 0 whose closure lies in the domain, the Taylor series of a holomorphic function converges absolutely and uniformly on each smaller closed polydisc (A continuous separately holomorphic function is the sum of an absolutely convergent power series with Cauchy-integral coefficients on every smaller polydisc).

[F5]

The Taylor coefficients at 0 are independent of which such centered polydisc is used (The coefficients of a convergent multi-indexed power series are its derivative coefficients, hence unique).

[F7]

Multiplication of one coordinate by η=a+ib acts on its real coordinate pair by (a−bba), whose determinant is ∣η∣2; all other real coordinates are fixed, so the full determinant is also ∣η∣2. If ∣η∣=1, the rotation preserves each of the three domains and its dilates. Applying the linear change-of-variables theorem to the inverse rotation shows that every restricted map is measurable and measure preserving (Complex m-space and its real coordinate dictionary, Real and imaginary parts, complex conjugation, and modulus, Measure-preserving transformations and systems, A linear map T of Rn sends Lebesgue measurable sets to Lebesgue measurable sets, with λn(T[E])=∣det⁡T∣ λn(E) when T is invertible and T[E] Lebesgue null when it is not).

[F8]

Integrals of integrable complex functions are invariant under a measure-preserving map (Integral invariance under measure-preserving maps).

[F10]

A pointwise almost-everywhere limit dominated by one integrable nonnegative function has convergent complex integrals (Dominated convergence).

[F11]

For u,v∈L2(Ω), the product uv‾ is integrable and ∫∣uv‾∣≤∥u∥2∥v∥2 (Cauchy–Schwarz: ∣⟨x,y⟩∣≤∥x∥ ∥y∥, with equality exactly for dependent pairs).

[F13]

The nonnegative integral is monotone; in particular λ(tΩ)≤λ(Ω)<∞ (Monotonicity and nonnegative homogeneity of the nonnegative integral, Weighted monomial integrals and monomial norms for the disc, ball and polydisc).

[F14]

An orthonormal family in a Hilbert space is complete exactly when its orthogonal complement is {0} (Orthonormal families, complete orthonormal systems and Hilbert bases, Parseval equivalences for an orthonormal family).

[F15]

The integral of a finite sum of integrable complex functions is the corresponding finite sum of their integrals (The Lebesgue integral is linear on L1(μ)).

[F16]

If u,v are continuous complex functions, then uv‾ is continuous: near any point a, ∣u(x)v(x)‾−u(a)v(a)‾∣≤∣u(x)∣ ∣v(x)−v(a)∣+∣v(a)∣ ∣u(x)−u(a)∣, and continuity of u bounds it locally; conjugation preserves modulus (Conjugation is an involutive real-field automorphism, zz‾=∣z∣2, and modulus is definite, multiplicative, and subadditive).

[F17]

Under ACω, L2(Ω) is Hilbert and the preceding theorem makes A2(Ω) a closed subspace, hence a Hilbert space (The Bergman space A2(Ω) and the Bergman kernel, A2(Ω) is closed, and the Bergman kernel is the sum over any complete orthonormal system).

Proof

technique · direct, using monomial moments, coordinate rotations, and Taylor coefficients

Given: ACω, one of Ω=D, Bm or Dm (with m=1 in the disc case), and f∈A2(Ω) when testing completeness.

1.1A1F1F2F3given

The preceding monomial-integral lemma gives the three squared-norm formulas in the statement. Every value is positive and finite, so each monomial belongs to the corresponding Bergman space and can be normalized.

1.2A1F1F2F6F7F8F11given

Let α≠β and choose j<m with d0:=βj−αj≠0. Set d=∣d0∣ and η=eiπ/d. The coordinate rotation T(z)j=ηzj, fixing the other coordinates, maps Ω and every tΩ onto themselves and preserves Lebesgue measure by [F7]. For g(z)=zβzα‾, one has g(Tz)=ηβjη‾αjg(z)=ηd0g(z)=−g(z): if d0>0 the factor is ηd=−1, and if d0<0 it is η−d=ηd‾=−1. Invariance [F8] gives I:=∫Ωg=∫Ωg∘T=−I, so I=0 in C. Integrability follows from [F2] and [F11]; therefore ⟨zβ,zα⟩=0. Hence distinct monomials are orthogonal, and the normalized family is orthonormal.

1.3F3F4F5F9given

Fix 0<t<1 and set Kt=tΩ‾. By [F9], Kt is compact and contained in Ω. For each a∈Kt, choose a positive polyradius ρ with Δ‾ρ(0)⊂Ω and ∣aj∣<ρj for all j<m: if Ω=D, take ∣a∣<ρ<1; if Ω=Bm, take ρj>∣aj∣ with ∑j<mρj2<1; and if Ω=Dm, take ∣aj∣<ρj<1. These choices exist since a∈tΩ‾ and t<1. Choose s<ρ and 0<θ<1 with ∣aj∣<θsj for every j<m, possible because there are finitely many strict coordinate inequalities. Holomorphy gives the continuity and separate holomorphy required by [F4]. Define the box partial sums SN(z)=∑α∈{0,…,N}mcαzα. By [F4], these sums converge uniformly on each closed polydisc strictly inside Δρ(0), including Δ‾θs(0). If two admissible radii are used, restrict both expansions to a smaller common centered polydisc and apply [F5]; hence their coefficient families agree. The family of all such open polydiscs Δθs(0) covers Kt, without selecting one for each point. By A subset of a metric space is open in the subspace metric exactly when it is the trace of an open set of the ambient space, and it is compact as a metric space in its own right exactly when every family of open subsets of the ambient space covering it, indexed or not, has finitely many members covering it, this ambient open cover has a finite subcover; a common cutoff for its finitely many uniform convergences shows that these same box partial sums converge uniformly to f on Kt.

2.1A1F1F2F3F8F9F10F11F12F13F15F16step 1.2step 1.3

Fix 0<t<1 and a multi-index γ. The box partial sums SN from step 1.3 converge uniformly on Kt, so they are uniformly bounded there by a finite Mt. Since ∣zγ∣≤1 on Ω and λ(tΩ)<∞ by [F13], the measurable functions 1tΩSNzγ‾ are dominated by the integrable function Mt1tΩ; measurability follows from [F3], [F12] and [F16], and dominated convergence [F10] permits passing their integrals to the limit. For every N≥max⁡jγj, finite-sum linearity [F15] and the rotation argument of step 1.2 give ∫tΩSN(z)zγ‾ dλ2m(z)=cγ∫tΩ∣zγ∣2 dλ2m(z), since every off-diagonal monomial moment vanishes on tΩ by that same rotation argument. Taking the limit yields ∫tΩf(z)zγ‾ dλ2m(z)=cγ∫tΩ∣zγ∣2 dλ2m(z).

3.1A1F1F2F3F10F11F12F16step 2.1given

Suppose f is orthogonal to every monomial. Let tn=1−1/(n+2), so tn↑1 and tnΩ increases to Ω. For each γ, the functions 1tnΩfzγ‾ converge pointwise to fzγ‾ and are dominated by ∣fzγ‾∣, which is integrable by [F11]; measurability follows from [F3], [F12] and [F16]. Also 1tnΩ∣zγ∣2 converges to ∣zγ∣2 and is dominated by it, which is integrable by [F2]; its measurability follows by the same facts. Applying [F10] to both sequences and using step 2.1 gives 0=⟨f,zγ⟩=cγ∥zγ∥22. The norm in [F2] is positive, so cγ=0 for every γ.

4.1F1step 1.3step 3.1given

Step 1.3 supplies the Taylor expansion on each Kt, and the dilates tnΩ exhaust Ω. Since all coefficients vanish by step 3.1, this expansion gives f=0 at every point of Ω. Thus the only element of A2(Ω) orthogonal to every monomial is 0.

5.1A1F1F11F14F17step 1.2step 4.1∎

Step 1.2 makes the normalized monomials an orthonormal family, and step 4.1 makes its orthogonal complement zero. By [F17] the Bergman space is Hilbert, so the zero-complement-to-completeness direction of [F14] shows that this family is complete. Conversely, if the family is complete, every vector orthogonal to its members is orthogonal to their dense linear span and hence, by Cauchy–Schwarz [F11], to itself; it must then be zero. Thus both directions of the stated equivalence hold, and the norm formulas and completeness establish all three asserted complete orthonormal systems.

TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-6.1-sol)audited 2026-10-08Open item page →

Reproducing property, Bergman projection and the extremal characterization

Statement

Assume ACω (The Axiom of Countable Choice (ACω)), let m≥1, and let Ω⊆Cm be a nonempty open set. Write kw=KΩ(⋅,w) for the Riesz section at w∈Ω, and let P:L2(Ω)→A2(Ω) be the Hilbert orthogonal projection. Then for every w∈Ω:

  1. For every f∈A2(Ω), f(w)=⟨f,kw⟩=∫Ωf(z)KΩ(z,w)‾ dλΩ(z).
  2. For every f∈L2(Ω), Pf(w)=⟨f,kw⟩=∫Ωf(z)KΩ(z,w)‾ dλΩ(z); P is linear, self-adjoint and contractive, and Pf=f for f∈A2(Ω).
  3. KΩ(w,w)=∥kw∥22=sup⁡{∣f(w)∣2:f∈A2(Ω),∥f∥2≤1} and ∣f(w)∣2≤KΩ(w,w)∥f∥22 for every f∈A2(Ω). If kw≠0, the maximizers in the supremum are exactly λkw/∥kw∥2 with ∣λ∣=1; if kw=0, every member of the closed unit ball attains the supremum, which is 0.

Facts & Assumptions

[A1]

The only choice principle is ACω, inherited through the Bergman Hilbert-space structure and the orthogonal-decomposition and projection suppliers; no full Axiom of Choice is used (The Axiom of Countable Choice (ACω)).

[F1]

A2(Ω) is a closed complex linear subspace of the Hilbert space L2(Ω), with the first-variable-linear integral pairing and unique holomorphic representatives (The Bergman space A2(Ω) and the Bergman kernel, A2(Ω) is closed, and the Bergman kernel is the sum over any complete orthonormal system).

[F2]

For a closed subspace M of a Hilbert space, each x has a unique decomposition x=PMx+(x−PMx) with PMx∈M and x−PMx∈M⊥; PM is the Hilbert orthogonal projection and is the identity on M (Orthogonal decomposition by a closed subspace, The Hilbert orthogonal projection onto a closed subspace).

[F3]

The Hilbert orthogonal projection is linear, self-adjoint and contractive (Hilbert projections are linear, self-adjoint and contractive).

[F4]

Evaluation at w has unique Riesz representer kw∈A2(Ω), f(w)=⟨f,kw⟩, and KΩ(z,w)=kw(z) (The Bergman space A2(Ω) and the Bergman kernel).

[F5]

Cauchy–Schwarz gives ∣⟨f,kw⟩∣≤∥f∥2∥kw∥2, with equality exactly when the pair is linearly dependent (Cauchy–Schwarz: ∣⟨x,y⟩∣≤∥x∥ ∥y∥, with equality exactly for dependent pairs).

Proof

technique · direct, using the Riesz representation and orthogonal projection

Given: ACω, a nonempty open Ω⊆Cm, its Bergman space A2(Ω), and w∈Ω.

1.1A1F1F4given

By [F4], evaluation at w is represented by kw=KΩ(⋅,w), so for each f∈A2(Ω), f(w)=⟨f,kw⟩=∫Ωf(z)kw(z)‾ dλΩ(z). The definition KΩ(z,w)=kw(z) gives the stated reproducing integral.

1.2A1F1F2F3given

By [F1], A2(Ω) is a closed subspace of L2(Ω), so [F2] defines its unique orthogonal projection P. The projection lemma [F3] gives linearity, self-adjointness and contractivity; [F2] also gives Pf=f for f∈A2(Ω).

2.1A1F1F2F4step 1.1step 1.2given

For f∈L2(Ω), [F2] gives f−Pf∈A2(Ω)⊥ and kw∈A2(Ω) by [F4]. Hence ⟨f−Pf,kw⟩=0. Applying step 1.1 to Pf∈A2(Ω) and using linearity in the first variable, Pf(w)=⟨Pf,kw⟩=⟨f,kw⟩; expanding kw(z) as KΩ(z,w) gives the displayed integral.

3.1A1F1F4F5step 1.1given∎

Applying step 1.1 to kw gives KΩ(w,w)=kw(w)=⟨kw,kw⟩=∥kw∥22. For any f∈A2(Ω), [F4] and [F5] imply ∣f(w)∣2≤∥f∥22∥kw∥22, so the supremum over the unit ball is at most ∥kw∥22. If kw≠0, the unit vector kw/∥kw∥2 attains this bound. Any other maximizer must give equality in [F5], hence is linearly dependent on kw; its norm must be 1, so it is exactly λkw/∥kw∥2 with ∣λ∣=1. If kw=0, step 1.1 gives f(w)=0 for every f∈A2(Ω), so the supremum is 0 and every function in the unit ball attains it.

LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-10-08Open item page →

Polynomial traces, monomial basis and bounded evaluation for the ball Hardy space

Statement

Assume the Axiom of Countable Choice ACω (The Axiom of Countable Choice (ACω)), let m≥1, let Bm={z∈Cm:∣z∣<1}, let S=∂Bm, and give S the normalized polar surface measure σ=σ1 of Monomial integrals on the sphere and orthonormality on the distinguished torus. Let H2(S,σ) be the closure of the traces of O(Bm)∩C(Bm‾) in L2(S,σ), as in The Hardy boundary space, Szegő projection and Szegő kernel on a smoothly bounded domain.

  1. If g is holomorphic on an open neighbourhood of Bm‾, its Taylor polynomials at 0 converge uniformly to g on Bm‾. More generally, polynomial traces are dense in the trace subspace and hence H2(S,σ) is the closure of the polynomial traces.

  2. For α∈Nm, ∥ζα∥L2(S,σ)2=wα:=(m−1)! α!(m−1+∣α∣)!>0. The normalized monomials eα(ζ)=ζα/wα form a complete orthonormal system of H2(S,σ).

  3. For each 0<r<1, set Cr:=(∑k=0∞(m−1+k)!(m−1)! k! r2k)1/2<∞. Then every polynomial p satisfies sup⁡∣z∣≤r∣p(z)∣≤Cr∥tr⁡σp∥L2(S,σ).

  4. Every h∈H2(S,σ) has a unique holomorphic extension h~ to Bm. It is the locally uniform limit of any sequence (fn)⊂O(Bm)∩C(Bm‾) whose traces converge to h in L2(S,σ). For every f∈O(Bm)∩C(Bm‾), sup⁡∣z∣≤r∣f(z)∣≤Cr∥tr⁡σf∥2; thus trace evaluation is well-defined and bounded, and each extended evaluation has a unique Riesz representer in H2(S,σ). In particular, (Bm,σ) is Szegő-regular.

Facts & Assumptions

[A1]

The only choice principle used is ACω (The Axiom of Countable Choice (ACω)). It selects countably many polynomial approximants or trace generators; the Hilbert-space and surface-measure conventions in The Hardy boundary space, Szegő projection and Szegő kernel on a smoothly bounded domain and its suppliers also assume only ACω. No full Axiom of Choice is used.

[F1]

Under Cm≅R2m, ∣z∣2=∑j<m∣zj∣2, the open unit ball is bounded and convex, and its closure is the closed Euclidean unit ball (Balls, polydiscs and the distinguished boundary in Cm, Complex m-space and its real coordinate dictionary). Its closure is compact (For n≥1, every Euclidean closed ball and every Euclidean sphere of positive radius is compact).

[F2]

The unit ball is path-connected by the segments t↦tz, and hence connected (Paths, path-connected spaces and path components, Every path-connected space is connected, and every path component lies inside a component). It is a nonempty bounded domain with C1 boundary in the convention of Bounded C1 domains and their outward normals. Indeed, put n=2m and take x0∈S in real coordinates; since ∣x0∣=1, some coordinate x0,i is nonzero, and after the rigid change of coordinates that moves slot i to the last position and, when x0,i<0, reflects that coordinate, one has x0=(y0,z0) with z0=∣x0,i∣>0 and ∣y0∣2+z02=1. The polynomial F(y,z)=1−∣y∣2−z2 has continuous partial derivatives ∂yjF=−2yj and ∂zF=−2z (For a natural n≥1 the function x↦xn is differentiable everywhere with derivative ι(n) x n−1; for n=0 it is the constant 1, with derivative 0; for a natural n≥1 the function x↦x−n is differentiable at every x≠0 with derivative −ι(n) x−n−1; consequently every polynomial function is differentiable at every real, with the derivative computed term by term, If all partial derivatives exist on a neighbourhood and are continuous at a point, then the map is totally differentiable there with Jacobian derivative), so it is C1, and ∂zF(x0)=−2z0≠0; the implicit function theorem (The Euclidean implicit function theorem with derivative formula) therefore supplies neighbourhoods P of y0 and Q of z0, with Q⊆(0,∞) after shrinking, and a unique C1 function φ:P→Q with F(y,z)=0  ⟺  z=φ(y) for (y,z)∈P×Q. Since ∂zF=−2z<0 on Q, the map z↦F(y,z) is strictly decreasing on Q for each y∈P, so F(y,z)>0  ⟺  z<φ(y) there; because ∣y∣2+z2<1  ⟺  F(y,z)>0, this gives Bm∩(P×Q)={(y,z)∈P×Q:z<φ(y)}, that is, locally exactly the subgraph of the C1 function φ, whose graph {z=φ(y)} is locally the sphere. The chart surface measure on S equals polar surface measure (Surface integration on compact C1 hypersurfaces, Agreement with the existing polar sphere measure); the sphere moment formula gives 0<σ(S)<∞ and σ(S)=1 after normalization (Monomial integrals on the sphere and orthonormality on the distinguished torus). Thus this normalization is c dS for c=1/σpolar(S)>0, as required in The Hardy boundary space, Szegő projection and Szegő kernel on a smoothly bounded domain.

[F3]

The trace subspace and Hardy space are T={tr⁡σf:f∈O(Bm)∩C(Bm‾)} and H2=T‾L2(σ); the pairing is ⟨f,g⟩=∫Sfg‾ dσ, linear in its first variable (The Hardy boundary space, Szegő projection and Szegő kernel on a smoothly bounded domain, The complex L2 pairing on equivalence classes). Under ACω, this L2 space is Hilbert (L2 with the integral pairing is a Hilbert space).

[F4]

For all α,β∈Nm, the sphere monomial moments are ∫Sζαζβ‾ dσ=δαβ(m−1)!α!/(m−1+∣α∣)! (Monomial integrals on the sphere and orthonormality on the distinguished torus). Multi-index notation has ∣α∣=∑j<mαj, α!=∏j<mαj!, and zα=∏j<mzjαj (Ck maps and multi-index derivative notation in Euclidean space, The factorial n! and the falling factorial nk‾, defined by recursion in N).

[F6]

A one-variable holomorphic function has its Taylor expansion on every centered disc contained in its domain, and if its modulus is at most M on the circle of radius R, its k-th Taylor coefficient has modulus at most M/Rk (A holomorphic function equals its Taylor series throughout the largest centred disc in its domain, Cauchy's inequalities bound the Taylor coefficients by the circle supremum).

[F7]

The closed Euclidean ball is compact; every ambient open cover of a compact subset has a finite subcover by A subset of a metric space is open in the subspace metric exactly when it is the trace of an open set of the ambient space, and it is compact as a metric space in its own right exactly when every family of open subsets of the ambient space covering it, indexed or not, has finitely many members covering it, and metric balls are open in the Euclidean metric topology (For n≥1, every Euclidean closed ball and every Euclidean sphere of positive radius is compact, Open cover, subcover, compact metric space, and compact subset of a metric space, Metric space: d(x,y)=0 iff x=y, symmetry, and the triangle inequality; pseudometric and ultrametric, The metric topology: a set is open when every one of its points has a ball around it inside the set; closed means open complement, Open ball, closed ball and sphere in a metric space, Arbitrary unions and finite intersections of open sets are open, open balls are open and closed balls are closed, Complex m-space and its real coordinate dictionary). A continuous real-valued function on a nonempty compact metric space has a finite maximum (A continuous real-valued function on a nonempty compact metric space is bounded and attains a greatest and a least value). The Euclidean norm is continuous (The finite and reverse triangle inequalities for a norm; and for n≥1 every norm N on Rn satisfies N(x)≤C∥x∥1 and is Lipschitz, hence continuous, for d2), a continuous function on the compact closed ball is uniformly continuous (Heine-Cantor: a continuous map from a compact metric space to any metric space is uniformly continuous), and complex modulus is subadditive, which implies ∣∣u∣−∣v∣∣≤∣u−v∣ (Conjugation is an involutive real-field automorphism, zz‾=∣z∣2, and modulus is definite, multiplicative, and subadditive).

[F8]

For a finite coefficient family, Cauchy–Schwarz bounds the absolute value of its scalar product by the product of the two Euclidean norms (Cauchy–Schwarz: ∣⟨x,y⟩∣≤∥x∥ ∥y∥, with equality exactly for dependent pairs). For k≥0, ∑∣α∣=k(k!/α!)xα=(∑j<mxj)k (The multinomial coefficient equals n!/∏i<mki!, and (x0+⋯+xm−1)n=∑ι ⁣(nk)∏i<mxiki in R).

[F9]

The natural powers rk are defined recursively, and the series ∑k≥0((m−1+k)!/((m−1)!k!))r2k converges for 0<r<1 by the ratio test: its successive-term ratio is r2(m+k)/(k+1)→r2<1 (Integer powers am, Ratio test: lim sup⁡∣ak+1/ak∣<1 gives absolute convergence and hence convergence, and lim inf⁡∣ak+1/ak∣>1 gives divergence). The geometric series with ratio 1/R<1 converges (For ∣r∣<1, ∑k≥0rk=1/(1−r), and for ∣r∣≥1 the series diverges).

[F10]

A locally uniform limit of holomorphic functions on an open set is holomorphic there (Locally uniform limits of holomorphic functions are holomorphic, with locally uniform convergence of all derivatives).

[F11]

Each bounded linear functional on a complex Hilbert space has a unique Riesz representer; in the first-variable-linear convention E(h)=⟨h,S⟩ (Riesz representation for Hilbert spaces). The complete orthonormal-system condition means that the closed linear span is the whole Hilbert space (Orthonormal families, complete orthonormal systems and Hilbert bases).

Proof

technique · direct, using radial dilations, homogeneous Taylor polynomials, and the sphere moments

Given: ACω, m≥1, the unit ball Bm, its sphere S, and normalized polar surface measure σ.

1.1A1F1F2given

The segment from 0 to each z∈Bm stays in Bm, so [F2] puts Bm in the domain class of The Hardy boundary space, Szegő projection and Szegő kernel on a smoothly bounded domain. By [F2], its normalized polar surface measure is an allowed positive multiple of chart surface measure.

1.2F1F7given

Let g be holomorphic on an open neighbourhood U of Bm‾. Consider the family of metric balls B(a,ε) with a∈Bm‾, ε>0, and B‾(a,2ε)⊂U. It covers Bm‾: openness supplies such a radius at each point, and the family is defined by this property, so no uncountable choice of radii is made. The ambient-cover implication of A subset of a metric space is open in the subspace metric exactly when it is the trace of an open set of the ambient space, and it is compact as a metric space in its own right exactly when every family of open subsets of the ambient space covering it, indexed or not, has finitely many members covering it gives a finite subcover B(ai,εi), and let δ=min⁡iεi>0. If ∣y∣≤1+δ, put x=y/(1+δ), so ∣x∣≤1 and ∣y−x∣≤δ. Choose an index i whose covering ball contains x; then ∣y−ai∣<δ+εi≤2εi, hence y∈U. Therefore B‾(0,1+δ)⊂U.

1.3F5F7given

Fix R with 1<R<1+δ. Continuity of g and the modulus inequality in [F7] make ∣g∣ continuous on the compact closed ball of radius R; let MR=max⁡∣u∣≤R∣g(u)∣<∞. For each ∣z∣≤1, the function ϕz(t)=g(tz) is holomorphic on ∣t∣<1+δ: if z≠0, complex differentiability of g gives ϕz(t+h)−ϕz(t)=Dg(tz)(hz)+o(∣h∣ ∣z∣), and for z=0 it is constant.

2.1F5F6F9step 1.3

The local power series of g at 0 is ∑αcαuα. For each fixed ∣z∣≤1 and sufficiently small ∣t∣, absolute convergence lets us group g(tz)=∑k≥0Pk(z)tk, where Pk(z)=∑∣α∣=kcαzα. Uniqueness of power-series coefficients identifies Pk(z) as the k-th Taylor coefficient of ϕz. The one-variable Cauchy estimate [F6], applied on ∣t∣=R, gives ∣Pk(z)∣≤MR/Rk, uniformly for ∣z∣≤1. Thus sup⁡∣z∣≤1∣∑k>NPk(z)∣≤MR∑k>NR−k→0; the Taylor polynomials ∑k=0NPk converge uniformly to g on the closed ball.

3.1A1F3F7step 2.1

Let f∈O(Bm)∩C(Bm‾). For 0<ρ<1, fρ(z)=f(ρz) is holomorphic on the neighbourhood ρ−1Bm of the closed unit ball. Uniform continuity of f on that compact ball gives fρ→f uniformly there as ρ↑1. For each positive integer n, choose ρn close enough to 1 that ∥fρn−f∥C(Bm‾)<1/(2n), then use step 2.1 to choose a polynomial pn with ∥pn−fρn∥C(Bm‾)<1/(2n). The countable selection is allowed by [A1], and ∥pn−f∥C<1/n. Since σ(S)=1, uniform convergence implies tr⁡σpn→tr⁡σf in L2(S,σ). Hence polynomial traces are dense in T, and by the definition of H2 in [F3] their closure is all of H2(S,σ).

4.1F4F11step 3.1given

By [F4], distinct monomial traces are orthogonal and ∥ζα∥22=wα>0. Thus eα=ζα/wα is an orthonormal family. Its finite linear span is exactly the polynomial traces, dense by step 3.1; the definition in [F11] therefore makes it a complete orthonormal system. In particular the zero multi-index has norm squared w0=1, and for m=1 every monomial has norm squared 1.

5.1F4F8F9step 4.1

If F=∅, then p=0 and the bound is immediate. Otherwise write p(z)=∑α∈Fcαzα for a finite set F. Orthogonality in [F4] gives ∥tr⁡σp∥22=∑α∈F∣cα∣2wα. Cauchy–Schwarz and [F8] give, for ∣z∣≤r, ∣p(z)∣2≤∥tr⁡σp∥22∑α∈F∣zα∣2wα≤∥tr⁡σp∥22∑k=0∞(m−1+k)!(m−1)! k!r2k. Indeed, the degree-k part of the full sum is (m−1+k)!(m−1)!k!(∑j<m∣zj∣2)k, by the multinomial identity. When m=1, this coefficient is 1 for every k and the series is ∑k≥0r2k. The final series converges by [F9], proving the claimed bound with the displayed Cr.

6.1F2F3step 3.1step 5.1

If f∈O(Bm)∩C(Bm‾), choose the uniform polynomial approximants from step 3.1. For each ∣z∣≤r, step 5.1 bounds ∣pn(z)∣ by Cr∥tr⁡σpn∥2. Uniform convergence gives pn(z)→f(z), and L2 convergence gives ∥tr⁡σpn∥2→∥tr⁡σf∥2. Taking the limit pointwise and then the supremum over ∣z∣≤r proves sup⁡∣z∣≤r∣f(z)∣≤Cr∥tr⁡σf∥2. If two trace generators determine the same L2 class, apply this bound to their difference for every r<1; their holomorphic functions agree throughout Bm. Thus trace evaluation is well-defined, and for any w∈Bm, choose ∣w∣<r<1 to get ∣f(w)∣≤Cr∥tr⁡σf∥2.

7.1A1F3F7F10step 6.1

Given h∈H2(S,σ), [F3] and [A1] give a sequence fn∈O(Bm)∩C(Bm‾) whose traces converge to h in L2. If a compact K⊂Bm is nonempty, the norm attains a maximum s<1 on K by [F7]; choose s<r<1, so K⊂rBm. For empty K the convergence assertion is automatic. Step 6.1 applied to fn−fj then shows that (fn) is uniformly Cauchy on K. Its limit h~ is holomorphic by [F10], independent of the approximating sequence by the same estimate, and agrees with every trace generator by applying it to the constant sequence at that generator. Hence it is the unique extension represented by the convergent sequence. Passing the bound in step 6.1 to the limit gives ∣h~(w)∣≤Cr∥h∥2 whenever ∣w∣<r<1. At each w, this limit extends the well-defined bounded linear trace evaluation from step 6.1; the extension is linear because the trace subspace is dense and linearity passes to limits.

8.1A1F3F11step 7.1∎

The Hilbert-space and pairing assumptions for H2(S,σ) are [F3]. The Riesz theorem [F11] therefore supplies a unique Sw∈H2(S,σ) with Ew(h)=⟨h,Sw⟩ for every h∈H2(S,σ). Step 7.1 makes w↦Ew(h) holomorphic, so the pair (Bm,σ) is Szegő-regular by The Hardy boundary space, Szegő projection and Szegő kernel on a smoothly bounded domain.

LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-6.1-sol)audited 2026-10-08Open item page →

Smoothness of the Bergman kernel and positivity of its diagonal on bounded domains

Statement

Assume the Axiom of Countable Choice ACω (The Axiom of Countable Choice (ACω)). Let m≥1 and let Ω⊆Cm be a nonempty open set. Then KΩ∈C∞(Ω×Ω) and z↦KΩ(z,z) is C∞ on Ω. If Ω is bounded, its Lebesgue measure satisfies 0<λΩ(Ω)<∞, and for every z∈Ω,

KΩ(z,z)≥1λΩ(Ω)>0.

In particular, on a bounded domain z↦log⁡KΩ(z,z) is C∞.

Facts & Assumptions

[A1]

The only choice principle assumed is ACω (The Axiom of Countable Choice (ACω)). It is inherited through the Bergman Hilbert-space and Riesz setup, and is used by the Borel and Euclidean-ball measure suppliers below; no full Axiom of Choice is used.

[F1]

Under ACω, A2(Ω) is a closed complex Hilbert subspace of L2(Ω) with the first-variable-linear pairing. Point evaluation has Riesz section kw=KΩ(⋅,w) and reproduces evaluation. The definition also gives A2(Cm)={0} and KCm≡0, so no positivity is asserted for every unbounded open set (The Bergman space A2(Ω) and the Bergman kernel, The complex L2 pairing on equivalence classes, L2 with the integral pairing is a Hilbert space).

[F2]

The definition KΩ(z,w)=kw(z) makes z↦KΩ(z,w) holomorphic. Reproduction gives KΩ(z,w)=⟨kw,kz⟩, so conjugate symmetry of the first-variable-linear L2 pairing gives KΩ(w,z)=KΩ(z,w)‾; hence the kernel is antiholomorphic in w (The Bergman space A2(Ω) and the Bergman kernel, The complex L2 pairing on equivalence classes, L2 with the integral pairing is a Hilbert space).

[F3]

On every nonempty compact K⊆Ω, sup⁡K∣f∣≤CK∥f∥2. The diagonal extremal identity is KΩ(w,w)=∥kw∥22=sup⁡∥f∥2≤1∣f(w)∣2 (Sup-norm and first-derivative bounds by the L2 norm on compact subsets, Reproducing property, Bergman projection and the extremal characterization).

[F4]

The first-variable-linear Hilbert pairing satisfies ∣⟨f,g⟩∣≤∥f∥2∥g∥2 (Cauchy–Schwarz: ∣⟨x,y⟩∣≤∥x∥ ∥y∥, with equality exactly for dependent pairs).

[F5]

A separately holomorphic, locally bounded function on an open subset of Cn is jointly holomorphic there (Locally bounded and separately holomorphic implies holomorphic).

[F6]

A holomorphic function on an open subset of complex Euclidean space is C∞ in the underlying real coordinates (Holomorphic functions of several variables are smooth and their complex derivatives are holomorphic).

[F7]

Complex conjugation is a real-linear coordinate map, and finite-order smooth maps are closed under composition (Real and imaginary parts, complex conjugation, and modulus, Ck Euclidean maps and diffeomorphisms, Ck Euclidean maps are closed under componentwise algebra and composition).

[F9]

For x>0, log⁡′(x)=1/x and log⁡ is continuous. For each integer n≥1, ddxx−n=−nx−n−1; products and quotients of continuous functions are continuous where their denominators are nonzero (The natural logarithm as the inverse of the exponential function, The natural logarithm has derivative 1/x and equals the integral from 1 to x of 1/t, Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm, Integer powers am, For a natural n≥1 the function x↦xn is differentiable everywhere with derivative ι(n) x n−1; for n=0 it is the constant 1, with derivative 0; for a natural n≥1 the function x↦x−n is differentiable at every x≠0 with derivative −ι(n) x−n−1; consequently every polynomial function is differentiable at every real, with the derivative computed term by term, Sums, scalar multiples, products, absolute values, maxima, minima and quotients with nonvanishing denominator of continuous functions are continuous, as are constants, the identity and every polynomial function, Sums, scalar multiples, products and quotients: (f+g)′(c)=f′(c)+g′(c), (αf)′(c)=αf′(c), (fg)′(c)=f′(c)g(c)+f(c)g′(c), and (f/g)′(c)=(f′(c)g(c)−f(c)g′(c))/g(c)2 when g(c)≠0). A real function is C∞ when all iterated coordinate partial derivatives of every finite order exist and are continuous (Ck maps and multi-index derivative notation in Euclidean space).

Proof

technique · direct, using the Riesz sections, compact evaluation bounds and the constant-function extremal witness

Given: ACω, m≥1, a nonempty open Ω⊆Cm, its Bergman space A2(Ω), and its Bergman kernel KΩ.

1.1A1F1F2given

For each w∈Ω, KΩ(z,w)=kw(z) is holomorphic in z by [F1, F2]. Reproducing evaluation at z on kw gives KΩ(z,w)=⟨kw,kz⟩. Conjugate symmetry then gives KΩ(w,z)=⟨kz,kw⟩=KΩ(z,w)‾. Thus KΩ is antiholomorphic in w, and F(z,η):=KΩ(z,η‾) is separately holomorphic on Ω×Ω∗, where Ω∗:={η:η‾∈Ω}.

1.2A1F1F8given

Suppose Ω is bounded. Choose a∈Ω; openness gives r>0 with B(a,r)⊆Ω. Boundedness supplies c∈Cm and R0>0 with Ω⊆B(c,R0). The Euclidean triangle inequality then gives Ω⊆B(0,∥c∥+R0+1). By [F8], Ω is measurable and 0<λ(B(a,r))≤λΩ(Ω)≤λ(B(0,∥c∥+R0+1))<∞. Hence 0<λΩ(Ω)<∞.

2.1A1F3F4F8step 1.1

Let K,L⊆Ω be nonempty compact sets. The evaluation estimate [F3] and the diagonal extremal identity [F3] give KΩ(z,z)≤CK2 for z∈K and KΩ(w,w)≤CL2 for w∈L. Since KΩ(z,w)=⟨kw,kz⟩, Cauchy–Schwarz [F4] gives ∣KΩ(z,w)∣≤CKCL on K×L. Around any z0,w0∈Ω choose closed Euclidean ball neighborhoods K,L contained in Ω; they are compact by [F8]. This proves that F is locally bounded on Ω×Ω∗.

2.2A1F1F3step 1.2

Suppose Ω is bounded. For z∈Ω let f0:=λΩ(Ω)−1/2 be the constant function. By step 1.2 it lies in A2(Ω) and has norm one. The extremal identity [F3] gives KΩ(z,z)≥∣f0(z)∣2=1/λΩ(Ω)>0.

3.1F5F7F8step 1.1step 2.1

The set Ω∗ is open because complex conjugation is a Euclidean isometry, so Ω×Ω∗ is an open subset of C2m. By [F5], the separately holomorphic, locally bounded function F is jointly holomorphic.

4.1F6F7step 3.1

By [F6], F is C∞ in real coordinates. The map (z,w)↦(z,w‾) and the diagonal map z↦(z,z) are real-linear coordinate maps, hence smooth; [F7] makes their compositions with F smooth. Therefore KΩ(z,w)=F(z,w‾) is C∞ on Ω×Ω, and z↦KΩ(z,z) is C∞ on Ω.

5.1F7F9step 4.1step 2.2

Let D(z):=KΩ(z,z). On a bounded Ω, steps 4.1 and 2.2 give D∈C∞(Ω) with D>0. Set ℓ(x):=log⁡x for x>0. By [F9], ℓ′(x)=x−1, and induction using the negative-power derivative in [F9] gives ℓ(n)(x)=(−1)n−1(n−1)!x−n for every n≥1. These derivatives are continuous on (0,∞) by [F9], and ℓ itself is continuous there; hence ℓ∈C∞((0,∞)). The composition theorem [F7] now gives log⁡KΩ(z,z)=ℓ(D(z))∈C∞(Ω).

6.1step 2.1step 4.1step 1.2step 2.2step 5.1∎

Steps 2.1 and 4.1 establish joint C∞ smoothness and the smooth diagonal for every nonempty open Ω; steps 1.2, 2.2 and 5.1 establish the positive diagonal bound and smooth logarithmic potential whenever Ω is bounded. These are the two claims.

TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-6.1-sol)audited 2026-10-08Open item page →

Transformation law of the Bergman kernel under a biholomorphism

Statement

Assume the Axiom of Countable Choice ACω (The Axiom of Countable Choice (ACω)). Let m≥1, let Ω,Ω′⊆Cm be domains, and let F:Ω→Ω′ be a biholomorphism. Write JF(z):=det⁡CDF(z). Then JF(z)≠0 for every z∈Ω, and

KΩ(z,w)=JF(z) KΩ′(F(z),F(w)) JF(w)‾(z,w∈Ω).

The pullback UF:A2(Ω′)→A2(Ω), defined on the unique holomorphic representatives by UFg:=(g∘F)JF, is a unitary isomorphism (a surjective linear isometry), with

UF∗KΩ(⋅,z)=JF(z)‾KΩ′(⋅,F(z)).

Facts & Assumptions

[A1]

The only choice principle assumed is ACω (The Axiom of Countable Choice (ACω)). Under it, the Bergman spaces are Hilbert spaces of unique holomorphic representatives with first-variable-linear inner products, Riesz sections, and reproducing kernels; the real change-of-variables supplier and Hilbert-adjoint definition also use only ACω (The Bergman space A2(Ω) and the Bergman kernel, Reproducing property, Bergman projection and the extremal characterization, A C^1 diffeomorphism satisfies the change-of-variables formula for L^1 functions, The Hilbert-space adjoint of a bounded operator).

[F1]

A biholomorphism and its inverse are holomorphic maps. Their components are holomorphic scalar functions, hence smooth in real coordinates, so under Cm≅R2m both are real C1 maps and F is a C1 diffeomorphism (Biholomorphic maps between open sets in Cm, A map into Cn is holomorphic exactly when each of its components is, Holomorphic functions of several variables are smooth and their complex derivatives are holomorphic, Ck Euclidean maps and diffeomorphisms, Complex m-space and its real coordinate dictionary).

[F2]

The entries of the complex Jacobian matrix are the component derivatives ∂zkFj, which are holomorphic; its determinant is a finite sum of products of these entries, so JF is holomorphic. Composition of holomorphic maps is holomorphic (Holomorphic maps Cm→Cn and the complex Jacobian matrix, A map into Cn is holomorphic exactly when each of its components is, Holomorphic functions of several variables are smooth and their complex derivatives are holomorphic, Sums, products and nonvanishing quotients of holomorphic functions are holomorphic, The composite of holomorphic maps is holomorphic and its complex Jacobian is the product).

[F3]

The complex Jacobian determinant is multiplicative under composition. Applying this to F−1∘F=id⁡ gives JF−1(F(z))JF(z)=1, hence JF(z)≠0 (The complex Jacobian determinant of a composite of equidimensional holomorphic maps is the product).

[F4]

For a C-linear map with complex determinant J, the real determinant under Cm≅R2m is ∣J∣2 (The real Jacobian determinant of a complex-linear automorphism is the squared modulus of its complex determinant).

[F5]

For the real C1 diffeomorphism underlying F, Lebesgue change of variables gives ∫Ω′q(ζ) dλ2m(ζ)=∫Ωq(F(z))∣det⁡RDF(z)∣ dλ2m(z) for every complex q∈L1(Ω′). The Bergman measures are restrictions of this Lebesgue measure (A C^1 diffeomorphism satisfies the change-of-variables formula for L^1 functions, The Bergman space A2(Ω) and the Bergman kernel, Complex m-space and its real coordinate dictionary).

[F6]

The Bergman section kz=KΩ(⋅,z) satisfies f(z)=⟨f,kz⟩; the pairing is linear in its first variable (The Bergman space A2(Ω) and the Bergman kernel, Reproducing property, Bergman projection and the extremal characterization).

[F7]

For a bounded linear operator T:H→K between Hilbert spaces, its adjoint is characterized by ⟨Tx,y⟩K=⟨x,T∗y⟩H. An isometry is bounded with bound 1 (The Hilbert-space adjoint of a bounded operator, A bounded linear operator between normed spaces).

[F8]

If g,h∈A2(Ω′), then gh‾∈L1(Ω′) by Cauchy–Schwarz (Cauchy–Schwarz: ∣⟨x,y⟩∣≤∥x∥ ∥y∥, with equality exactly for dependent pairs).

Proof

technique · direct, using the weighted pullback and the reproducing property

Given: ACω, domains Ω,Ω′⊆Cm, and a biholomorphism F:Ω→Ω′.

1.1A1F1given

By [F1], F and F−1 are smooth as real maps under the Euclidean identification, so F is a real C1 diffeomorphism between the corresponding open subsets of R2m.

1.2F3given

Applying [F3] to F−1∘F=id⁡Ω gives JF−1(F(z))JF(z)=1 for every z∈Ω. Thus JF(z)≠0.

2.1A1F2F4F5F8step 1.1given

By [F2], JF is holomorphic, and the chain rule makes g∘F holomorphic for g∈A2(Ω′); hence (g∘F)JF is holomorphic. Applying [F4] and [F5] to ∣g∣2∈L1(Ω′) gives ∫Ω∣(g∘F)(z)JF(z)∣2 dλ2m(z)=∫Ω′∣g(ζ)∣2 dλ2m(ζ)<∞, so UFg∈A2(Ω) and ∥UFg∥2=∥g∥2. For g,h∈A2(Ω′), [F8] gives gh‾∈L1(Ω′), and [F4]–[F5] yield ⟨UFg,UFh⟩Ω=∫Ωg(F(z))h(F(z))‾∣JF(z)∣2 dλ2m(z)=∫Ω′g(ζ)h(ζ)‾ dλ2m(ζ)=⟨g,h⟩Ω′. Pointwise linearity makes UF a linear isometry preserving the inner product.

3.1A1F3F6F7step 1.2step 2.1given

Apply step 2.1 to F−1 as well. For each h∈A2(Ω), g:=(h∘F−1)JF−1 lies in A2(Ω′), and [F3] gives UFg=h. Thus UF is onto with inverse UF−1, so it is a unitary isomorphism. For every y∈A2(Ω), inner-product preservation and surjectivity give ⟨UFg,y⟩Ω=⟨g,UF−1y⟩Ω′ for all g; by [F7], UF∗=UF−1. Finally, for z∈Ω and g∈A2(Ω′), [F6] gives ⟨g,UF∗kz⟩Ω′=⟨UFg,kz⟩Ω=(UFg)(z)=JF(z)g(F(z))=⟨g,JF(z)‾kF(z)′⟩Ω′, where kη′:=KΩ′(⋅,η). Nondegeneracy of the inner product yields UF∗kz=JF(z)‾kF(z)′.

4.1F6step 3.1∎

Since UFUF∗=id⁡, step 3.1 gives kw=UFUF∗kw=JF(w)‾ UFkF(w)′. Evaluating the unique holomorphic representatives at z gives KΩ(z,w)=JF(w)‾JF(z)KΩ′(F(z),F(w)), the asserted transformation law.

DefinitionDefinition: Literature-sourcedProof: Not applicablejudge pass (gpt-6.1-sol)audited 2026-10-08Open item page →

The Bergman metric form on a bounded domain

Definition

Assume the Axiom of Countable Choice ACω (The Axiom of Countable Choice (ACω)), let m≥1, and let Ω⊆Cm be a bounded domain, meaning a nonempty connected open set. Use the first-variable-linear Bergman kernel KΩ of The Bergman space A2(Ω) and the Bergman kernel. By Smoothness of the Bergman kernel and positivity of its diagonal on bounded domains, uΩ(z):=log⁡KΩ(z,z) is a real-valued C∞ function on Ω.

Using the one-based coordinate aliases for the library's zero-based coordinates from The Levi form and strict plurisubharmonicity, define the Bergman metric form at z∈Ω by the Hermitian form gΩ(z)(X,Y):=∑j,k=1m∂2uΩ∂zj∂z‾k(z)XjYk‾,X,Y∈Cm. Because uΩ is real-valued and C2, expanding the Wirtinger operators and commuting real mixed partials gives gjkˉ‾=gkjˉ (Wirtinger operators in Cm, Clairaut--Schwarz theorem for continuous second partial derivatives), so this form is Hermitian. Its associated quadratic form is BΩ2(z;X):=gΩ(z)(X,X), the Levi form of uΩ at z; write its matrix as gΩ(z)=(gjkˉ(z)). The pair (Ω,gΩ) is the Bergman (pseudo-)metric. This definition does not assert positive definiteness; the separate positivity theorem on this page proves it for bounded domains.

Remarks

The ACω assumption is inherited through the Bergman Hilbert-space/Riesz construction and its smoothness/positive-diagonal supplier. The definition itself makes no additional selections and uses no full Axiom of Choice.

LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck pendingjudge pass (gpt-6.1-sol)audited 2026-10-08Open item page →

The multinomial theorem for finitely many complex variables

Statement

Let m,n∈N, let W(n,m) and (nα) be as in The multinomial coefficient (nk0,…,km−1) as the number of ordered partitions of an n-set into blocks of prescribed sizes, and let z0,…,zm−1∈C. Write ιC:N→C for the canonical natural of The canonical natural ι(n)=n⋅1F of a field. Then

(∑i<mzi)n=∑α∈W(n,m)ιC ⁣((nα))∏i<mziαi.

For every α∈W(n,m), the same coefficient satisfies ιC ⁣((nα))∏i<mιC(αi!)=ιC(n!). The sum on the right is the finite sum in the additive commutative monoid of C; the statement includes m=0 and n=0.

Facts & Assumptions

[F2]

For x,y∈C and j∈N, (x+y)j=∑k≤jιC ⁣((jk))xkyj−k (The binomial theorem over the complex field).

[F4]
[F5]

Multiplication in N cancels a common nonzero factor (Cancellation for multiplication by a nonzero factor).

[F6]

The canonical natural ιC is defined by ιC(0)=0 and ιC(j+1)=ιC(j)+1; complex integer powers use z0=1 and zj+1=zjz (The canonical natural ι(n)=n⋅1F of a field, Integer powers in the complex field).

[F8]

The natural operations satisfy a+0=a, a+(j+1)=(a+j)+1, a⋅0=0, and a⋅(j+1)=a⋅j+a (Addition of natural numbers, Multiplication of natural numbers).

[F9]

Complex field arithmetic is associative and distributive, and integer powers of nonzero elements obey the usual exponent laws (C=R[x]/(x2+1) is a field, every element is uniquely a+bi, and every nonzero element has inverse (a−bi)/(a2+b2), Laws of integer exponents).

[F10]

Induction on N is valid (The principle of mathematical induction).

Proof

technique · induction on the number of variables, with the complex binomial theorem in the inductive step

Given: Naturals m,n, the finite index set W(n,m), and complex numbers zi for i<m.

1.1F3F6F7F8F9F10given

The canonical natural preserves addition and multiplication in C. For fixed a∈N, induction [F10] on b proves ιC(a+b)=ιC(a)+ιC(b): the base case uses a+0=a, and the successor case uses a+(b+1)=(a+b)+1 and the recursion in [F6]. A second induction on b proves ιC(ab)=ιC(a)ιC(b): at b=0 both sides are 0, and at the successor use a(b+1)=ab+a, the first identity, and distributivity in [F9]. Also ιC(1)=1. Applying [F3] and the multiplicative property just proved successively along the finite product recursion [F7] gives the coefficient identity in the statement.

1.2F1F6given

For m=0, the left side is 0n. If n=0, both sides equal 1: the right side has the single empty tuple, coefficient (00)=1, and empty product 1. If n≥1, the right side is an empty sum and the left side is 0; this proves the formula in dimension zero.

1.3ih

Fix m and assume the formula holds for this dimension for every exponent j∈N and every m-tuple of complex numbers.

2.1F2F7step 1.3given

Let z0,…,zm∈C, put S=∑i<mzi, and fix n∈N. The complex binomial theorem [F2], followed by the induction hypothesis [step 1.3] for each j≤n, expands (S+zm)n as the finite double sum over 0≤j≤n and β∈W(j,m) whose summand is ιC ⁣((nj))ιC ⁣((jβ))(∏i<mziβi)zm n−j.

3.1F1F3F4F5F6F7F9step 1.1step 2.1

For every pair (j,β) in step 2.1, let α=(β0,…,βm−1,n−j)∈W(n,m+1). This is a bijection from the pair index set to W(n,m+1): its inverse takes the first m coordinates as β and their natural sum as j. Put P=(∏i<mβi!)(n−j)!. By [F3], (nα)P=n!; also [F3] gives (jβ)∏i<mβi!=j!, so (nj)(jβ)P=(nj) j! (n−j)!=n!. The factor P is nonzero, since (nα)P=n!≠0 by [F4]; hence [F5] gives (nα)=(nj)(jβ). Step 1.1 carries this identity to the canonical naturals in C, and the power laws [F6], [F9] identify the accompanying monomial with ∏i<m+1ziαi.

4.1F1F3F6F7F10step 1.1step 1.2step 1.3step 2.1step 3.1discharge-induction∎

Reindex the finite double sum of step 2.1 along the bijection in step 3.1. Its coefficients and monomials become exactly those in the asserted formula for m+1 variables. The base case step 1.2 and this inductive step prove the statement for every m by [F7] and induction. If all variables are zero and n>0, every α∈W(n,m) has a positive coordinate, so every monomial on the right vanishes; if n=0, step 1.2 checks 00=1. For m=1, the sole index is (n) and its multinomial coefficient is 1 by the coloring definition, so the formula reduces to z0n=z0n.

TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-6.1-sol)audited 2026-10-08Open item page →

Bergman kernels of the disc, ball and polydisc, and Szegő kernels of the disc and ball

Statement

Assume the Axiom of Countable Choice ACω (The Axiom of Countable Choice (ACω)), let m≥1, and use Lebesgue measure on Cm≅R2m with the first-variable-linear pairing. Write ⟨z,w⟩:=∑j<mzjwj‾ for the standard Hermitian inner product. Then

KD(z,w)=1π(1−zw‾)2,KDm(z,w)=1πm∏j<m1(1−zjwj‾)2,KBm(z,w)=m!πm(1−⟨z,w⟩)m+1.

Let μT be normalized Haar measure on T=∂D, and let σm be normalized polar surface measure on S2m−1=∂Bm. The pairs (D,μT) and (Bm,σm) are Szegő-regular, with kernels

SD(z,w)=11−zw‾,SBm(z,w)=1(1−⟨z,w⟩)m.

Each displayed Bergman kernel reproduces the corresponding A2 space and is the unique such kernel. Each displayed Szegő kernel reproduces the corresponding boundary Hardy space and is its unique Riesz kernel. No smooth-boundary Szegő construction is asserted for the polydisc.

Facts & Assumptions

[A1]

The only choice axiom assumed is ACω (The Axiom of Countable Choice (ACω)). It supplies the Bergman and Hardy Hilbert/Riesz constructions and the Hilbert Fourier expansion used below; no full Axiom of Choice is used.

[F1]

The normalized monomials form complete orthonormal systems in A2(D), A2(Bm), and A2(Dm), with squared norms π/(k+1), πmα!/(m+∣α∣)!, and πm/∏j<m(αj+1), respectively (Monomials form complete orthogonal systems of the Bergman spaces of the disc, the ball and the polydisc).

[F2]

For a complete orthonormal system (eα) of a Bergman space, its kernel is ∑αeα(z)eα(w)‾; the sum converges absolutely and uniformly on compact subsets (A2(Ω) is closed, and the Bergman kernel is the sum over any complete orthonormal system).

[F3]

The Cauchy product of two absolutely convergent complex series is absolutely convergent, with sum the product of the sums (The Cauchy product of two absolutely convergent complex series converges absolutely to the product of their sums).

[F4]

For a real r with 0≤r<1, ∑k≥0rk=1/(1−r) (For ∣r∣<1, ∑k≥0rk=1/(1−r), and for ∣r∣≥1 the series diverges).

[F5]

Conjugation is multiplicative, ∣xy∣=∣x∣∣y∣, ∣1∣=1, and ∣t∣=0 exactly when t=0 (Conjugation is an involutive real-field automorphism, zz‾=∣z∣2, and modulus is definite, multiplicative, and subadditive).

[F6]

Complex series are limits of their finite partial sums, and absolute convergence is defined by the real modulus series (Complex series, absolute convergence, complex power series, and radius of convergence, Series, partial sums, convergence and the sum, divergence, and the tail series). An absolutely convergent complex series converges (Every absolutely convergent complex series converges, and rearrangements preserve its sum).

[F9]

The Euclidean norm on Cm is ∥z∥=(∑j<m∣zj∣2)1/2, and its balls are the stated unit balls (Complex m-space and its real coordinate dictionary, Balls, polydiscs and the distinguished boundary in Cm).

[F10]

The complex multinomial expansion holds for every m,n∈N (The multinomial theorem for finitely many complex variables).

[F11]

For every α∈W(n,m), ιC((nα))∏i<mιC(αi!)=ιC(n!) (The multinomial theorem for finitely many complex variables).

[F12]

The disc Hardy pair is Szegő-regular and has kernel 1/(1−zw‾) under normalized Haar measure (The disc trace space is the Hardy boundary space and the Szegő family reproduces H2).

[F13]

The ball Hardy pair is Szegő-regular; extended evaluation is bounded and has a unique Riesz representer (Polynomial traces, monomial basis and bounded evaluation for the ball Hardy space).

[F14]

The normalized ball boundary monomials form a complete orthonormal system with squared norms wα=(m−1)!α!/(m−1+∣α∣)! (Polynomial traces, monomial basis and bounded evaluation for the ball Hardy space).

[F15]

A complete orthonormal family has a norm-convergent Fourier expansion by the net of finite-subset sums (Fourier expansion in a Hilbert space).

[F18]

On a Szegő-regular pair, each extended evaluation has a unique Riesz representer and the Szegő kernel is defined from those representers (The Hardy boundary space, Szegő projection and Szegő kernel on a smoothly bounded domain).

[F19]

The Bergman kernel reproduces evaluation on A2(Ω) (Reproducing property, Bergman projection and the extremal characterization).

[F20]

Each point evaluation on A2(Ω) has a unique Riesz representer, whose holomorphic representative defines the Bergman kernel (The Bergman space A2(Ω) and the Bergman kernel).

[F23]

Induction on the natural numbers is valid (The principle of mathematical induction).

[F24]

Natural powers are recursively defined; (ab)k=akbk, and conjugation of a natural power is the corresponding power of the conjugate (Integer powers in the complex field, Laws of integer exponents, with the last identity following by induction from the recursion and [F5]).

Proof

technique · direct, using complete monomial systems and the binomial series

Given: ACω, the unit disc, unit ball and unit polydisc, and the normalized boundary measures.

1.1F5F8F9given

The series parameters lie in the unit disc. If z,w∈D, or if z,w∈Dm, then ∣zw‾∣<1 or ∣zjwj‾∣<1 coordinatewise. If z,w∈Bm, [F8] gives ∣⟨z,w⟩∣≤∥z∥∥w∥<1 by [F9]. Thus every denominator below is nonzero.

1.2A1F12F18

The disc pair with normalized Haar measure is Szegő-regular and has kernel 1/(1−zw‾) by [F12]. The Szegő definition [F18] makes each kernel section the unique Riesz representer of its extended evaluation, so this is the unique disc Szegő kernel.

2.1F4F5F6F7F21F24step 1.1given

Fix a complex t with ∣t∣<1. By induction from the power recursion [F24] and modulus multiplicativity [F5], ∣tk∣=∣t∣k for every k. The real geometric series for ∣t∣ converges by [F4], so ∑k≥0tk is absolutely convergent and converges by [F6], say to G(t). The finite identity (1−t)∑k=0Ntk=1−tN+1 follows by telescoping in the field [F21]; [F7] gives ∣t∣N+1→0, hence tN+1→0. Since ∣t∣<1=∣1∣, t≠1; taking limits gives G(t)=1/(1−t).

3.1F3F16F21F23step 2.1given

For every integer q≥1, define Bq(t):=∑k≥0(q+k−1q−1)tk. Step 2.1 is the base q=1. If Bq(t) is absolutely convergent with sum (1−t)−q, its Cauchy product with ∑j≥0tj is absolutely convergent and has sum (1−t)−(q+1) by [F3]. The coefficient of tk in this product is ∑j=0k(q+j−1q−1). Set i=q+j−1; the hockey-stick identity [F16] sums (iq−1) from i=0 to q+k−1, and [F16] makes each omitted term with i<q−1 zero. Thus the coefficient is (q+kq). By [F21] this natural identity also holds for the coefficients embedded in C. Thus the product is exactly Bq+1(t), proving the identity for every q≥1 by induction [F23].

4.1A1F1F2F3F6F22F23F24step 3.1

On the disc, the normalized monomials from [F1] give KD(z,w)=π−1∑k≥0(k+1)(zw‾)k=π−1B2(zw‾), which is the stated formula by step 3.1. On the polydisc, [F2] gives the monomial expansion. Its finite degree shells are cofinal among finite subsets by [F22], so the shell sums have the same limit as the kernel expansion. Repeated Cauchy products [F3] show that the degree-k shell sum is the degree-k coefficient in the product of the m absolutely convergent series π−1B2(zjwj‾); hence summing the shells gives their product.

4.2A1F1F2F10F11F17F21F22F24step 3.1

For z,w∈Bm, put t=⟨z,w⟩. The Bergman expansion [F2] and ball monomial norms [F1] give KBm(z,w)=π−m∑α∈Nm(m+∣α∣)!α!zαwα‾. The degree shells are finite and cofinal by [F22], so their partial sums converge to this kernel. In the shell ∣α∣=k, the multinomial expansion [F10] applied to xj=zjwj‾ gives ∑∣α∣=kιC((kα))zαwα‾=tk, using [F24] for powers and conjugation. Also [F11] gives ιC((kα))∏j<mιC(αj!)=ιC(k!), while [F17] gives ιC((m+km))ιC(m!)ιC(k!)=ιC((m+k)!) after [F21] identifies the real and complex canonical naturals. The factorial denominator is positive by [F17, F21], so division gives (m+k)!/α!=m!(m+km)(kα) in the corresponding real scalars. The degree-k block is therefore m!πm(m+km)tk. Step 3.1 sums these blocks to the stated formula.

4.3A1F10F11F13F14F15F17F18F21F22F24step 3.1

Let Sw be the ball Szegő Riesz representer from [F13], and let eα(ζ)=ζα/wα be its complete orthonormal boundary monomials by [F14]. By [F15], Sw=∑α⟨Sw,eα⟩eα. For any finite subset of indices, the first-variable-linear reproducing identity gives ⟨eα,Sw⟩=eα(w) and hence ⟨Sw,eα⟩=eα(w)‾. The finite degree shells are cofinal by [F22]; applying the bounded evaluation at z from [F13] to the Fourier sums over those shells gives SBm(z,w)=∑k≥0∑∣α∣=kzαwα‾/wα. For each shell, [F10] applied to xj=zjwj‾ gives ∑∣α∣=kιC((kα))zαwα‾=⟨z,w⟩k, using [F24] for powers and conjugation. Since wα=(m−1)!α!/(m−1+k)!, [F11] gives ιC((kα))∏j<mιC(αj!)=ιC(k!), and [F17] gives ιC((m+k−1m−1))ιC((m−1)!)ιC(k!)=ιC((m−1+k)!) after [F21] identifies canonical natural scalars. The factorial denominator is positive by [F17, F21], so division gives the degree-k block (m+k−1m−1)⟨z,w⟩k. Step 3.1 with q=m sums these blocks to (1−⟨z,w⟩)−m. The Szegő definition [F18] gives uniqueness of this Riesz kernel.

5.1F2F19F20step 1.2step 4.1step 4.2step 4.3∎

The basis expansions in steps 4.1 and 4.2 are the Bergman Riesz kernels by [F2], so [F19] supplies their reproducing identities; uniqueness follows from the Bergman-space Riesz definition [F20]. Steps 1.2 and 4.3 establish the two Szegő reproducing kernels and uniqueness. Setting either kernel variable to 0 in the displayed formulas (equivalently, retaining only the degree-zero monomial term) gives KD(0,w)=1/π, KDm(0,w)=1/πm, KBm(0,w)=m!/πm, and both stated Szegő values 1. When m=1, B1=D and D1=D, and the corresponding formulas agree. The polydisc appears only in the Bergman product formula, so no boundary regularity is claimed for it.

TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-6.1-sol)audited 2026-10-08Open item page →

The Bergman metric is positive definite on bounded domains and biholomorphically invariant

Statement

Assume the Axiom of Countable Choice ACω (The Axiom of Countable Choice (ACω)) and let m≥1. Let Ω⊆Cm be a bounded domain with Bergman kernel KΩ, Bergman metric form gΩ, and quadratic form BΩ2(z;X)=gΩ(z)(X,X) as in The Bergman metric form on a bounded domain, and use the one-based coordinate aliases of The Levi form and strict plurisubharmonicity.

  1. For every z∈Ω and every X∈Cm∖{0}, BΩ2(z;X)=1KΩ(z,z)sup⁡{∣∂Xf(z)∣2: f∈A2(Ω), ∥f∥L2≤1, f(z)=0}, where ∂Xf=∑j=1mXj∂f∂zj. The supremum is finite, positive, and attained. In particular BΩ2(z;X)>0, so the Hermitian form gΩ(z) is positive definite.

  2. If F:Ω→Ω′ is a biholomorphism of bounded domains, then for all z∈Ω and all X,Y∈Cm, gΩ(z)(X,Y)=gΩ′(F(z))(DF(z)X, DF(z)Y). Equivalently, BΩ2(z;X)=BΩ′2(F(z);DF(z)X) for every X.

Facts & Assumptions

[A1]

The only choice principle assumed is ACω (The Axiom of Countable Choice (ACω)): it enters through the Bergman Hilbert/Riesz structure and the orthogonal projection. No full Axiom of Choice is used.

[F1]

For a nonempty open Ω⊆Cm, A2(Ω) is a closed complex Hilbert subspace of L2(Ω) for the first-variable-linear pairing, each class has a unique holomorphic representative, point evaluation has a unique Riesz section kw=KΩ(⋅,w) with f(w)=⟨f,kw⟩, and KΩ(z,w)=⟨kw,kz⟩=KΩ(w,z)‾ (The Bergman space A2(Ω) and the Bergman kernel, A2(Ω) is closed, and the Bergman kernel is the sum over any complete orthonormal system).

[F2]

For a bounded domain Ω, KΩ∈C∞(Ω×Ω), the diagonal is smooth with KΩ(z,z)≥1/λΩ(Ω)>0, and KΩ is holomorphic in its first and antiholomorphic in its second variable (Smoothness of the Bergman kernel and positivity of its diagonal on bounded domains, A2(Ω) is closed, and the Bergman kernel is the sum over any complete orthonormal system).

[F3]

For every nonempty compact K⊆Ω there are finite constants with sup⁡K∣f∣≤CK∥f∥2 and sup⁡K∣∂zαf∣≤CK,α∥f∥2 for every multi-index ∣α∣≤1 (Sup-norm and first-derivative bounds by the L2 norm on compact subsets).

[F4]

Every bounded linear functional on a real or complex Hilbert space has a unique representing vector, isometrically; in the first-variable-linear convention f(x)=⟨x,y⟩ (Riesz representation for Hilbert spaces).

[F5]

A closed linear subspace M of a Hilbert space satisfies H=M⊕M⊥ uniquely, and the orthogonal projection onto M is defined by that decomposition (Orthogonal decomposition by a closed subspace, The Hilbert orthogonal projection onto a closed subspace).

[F6]

Cauchy–Schwarz: ∣⟨x,y⟩∣≤∥x∥∥y∥, with equality exactly for linearly dependent pairs (Cauchy–Schwarz: ∣⟨x,y⟩∣≤∥x∥ ∥y∥, with equality exactly for dependent pairs).

[F7]

If real C2 functions satisfy u≥v near a with u(a)=v(a), then Lu(a;X)≥Lv(a;X) for every X (The complex Hessian of a C2 function dominates that of a minorant at a common minimum).

[F8]

The Bergman metric form is the Levi form of uΩ=log⁡KΩ(z,z), and BΩ2(z;X)=LuΩ(z;X)=∑j,k=1m∂2uΩ∂zj∂z‾k(z)XjXk‾ for the one-based coordinate aliases (The Bergman metric form on a bounded domain, The Levi form and strict plurisubharmonicity).

[F9]

Wirtinger operators are ∂zj=12(∂xj−i∂yj), ∂z‾j=12(∂xj+i∂yj), for holomorphic functions the real-coordinate derivative identities in [F12] give ∂z‾jf=0, real mixed partials commute by Clairaut--Schwarz theorem for continuous second partial derivatives, log⁡′(x)=1/x for x>0 by The natural logarithm has derivative 1/x and equals the integral from 1 to x of 1/t, and the product and chain rules hold for these first-order operators (Wirtinger operators in Cm, Complex m-space and its real coordinate dictionary, Ck maps and multi-index derivative notation in Euclidean space, The chain rule for total derivatives: D(g∘f)(a)=Dg(f(a))∘Df(a)).

[F11]

A biholomorphism F:Ω→Ω′ satisfies KΩ(z,w)=JF(z)KΩ′(F(z),F(w))JF(w)‾ with JF=det⁡CDF≠0, and UFg=(g∘F)JF is a unitary isomorphism A2(Ω′)→A2(Ω) (Transformation law of the Bergman kernel under a biholomorphism).

[F12]

A holomorphic function on an open set is of class Cn in the real coordinates for every natural n, hence smooth (Holomorphic functions of several variables are smooth and their complex derivatives are holomorphic).

[F13]

The complex plane is complete, hence Banach for its modulus norm. A continuous differentiable complex-valued curve whose derivative is bounded by C changes by at most C times the parameter distance (The complex plane is complete, and convergence is equivalent to convergence of real and imaginary parts, Mean value inequality for a differentiable Banach-valued curve).

Proof

technique · direct, using the reduced Riesz kernel of the subspace $\{f(z)=0\}$ and a second-order comparison with $\log K_\Omega$

Given: ACω, the bounded domain Ω, a point z∈Ω, and a direction X∈Cm.

1.1A1F1F2F3F4F5

Put M:=KΩ(z,z). By [F2], M>0, so kz≠0 and the subspace H′:={f∈A2(Ω):f(z)=0}={f:⟨f,kz⟩=0}=(Ckz)⊥ is closed; by [F5], A2(Ω)=Ckz⊕H′. By [F3] with the singleton K={ζ} the evaluation εζ(f):=f(ζ) is bounded on A2(Ω) and hence on H′ for every ζ∈Ω; [F4] gives a unique hζ∈H′ with f(ζ)=⟨f,hζ⟩ for all f∈H′. Define E(ζ):=∥hζ∥22.

1.2F1F2F5F6algebra

By [F5] the projection of kζ onto H′ is hζ=kζ−⟨kζ,kz⟩Mkz, and ⟨kζ,kz⟩=KΩ(z,ζ) by [F1]. Hence, pointwise in η, hζ(η)=KΩ(η,ζ)−KΩ(z,ζ)MKΩ(η,z), and reproducing on hζ gives E(ζ)=∥hζ∥22=KΩ(ζ,ζ)−∣KΩ(z,ζ)∣2M. By [F2] the function E is C∞ on Ω; by [F6] it satisfies E(ζ)≥0 with E(z)=0, and E(ζ)>0 for ζ≠z, since then some coordinate satisfies ζj≠zj and the bounded function η↦ηj−zj lies in H′ with nonzero value at ζ.

1.3F2F8F9algebra

Compute the Levi form of E. Write D(ζ):=KΩ(ζ,ζ) and A(ζ):=KΩ(ζ,z), so that E=D−∣A∣2M, D(z)=A(z)=M and ∣A(z)∣2=M2, and D is C∞ near z. Set aj:=∂jA(z) and cjk:=∂j∂k‾D(z). Since KΩ is holomorphic in the first and antiholomorphic in the second variable [F2, F9], the Wirtinger derivatives ∂ζ‾KΩ and ∂ηKΩ vanish identically, and the product and chain rules give ∂jD(z)=aj, ∂k‾D(z)=ak‾, ∂j∣A∣2(z)=ajM, ∂k‾∣A∣2(z)=Mak‾, and ∂j∂k‾∣A∣2(z)=ajak‾; consequently ∂jE(z)=∂j‾E(z)=0, ∂j∂kE(z)=∂j‾∂k‾E(z)=0, and ∂j∂k‾E(z)=cjk−ajak‾M. Since D(z)=M>0, the same rules applied to log⁡D give ∂j∂k‾log⁡D(z)=cjkM−ajak‾M2, so M ∂j∂k‾log⁡D(z)=∂j∂k‾E(z); summing against XjXk‾ and using [F8] yields LE(z;X)=M Llog⁡D(z;X)=M BΩ2(z;X).

2.1A1F5F6F7F8F12step 1.2

Let f∈H′ with ∥f∥2≤1. By [F6] and the reproducing identity of step 1.1, ∣f(ζ)∣2=∣⟨f,hζ⟩∣2≤∥f∥22E(ζ)≤E(ζ) for every ζ∈Ω, with equality at ζ=z. Both E and ∣f∣2 are C2: E was shown C∞ in step 1.2, and f is holomorphic, hence smooth in the real coordinates by [F12]. So [F7] gives LE(z;X)≥L∣f∣2(z;X)=∣∂Xf(z)∣2; hence sup⁡{∣∂Xf(z)∣2:f∈H′,∥f∥2≤1}≤LE(z;X).

2.2F2F9F13step 1.2step 1.3

Fix X≠0 and δ>0 such that z+τX∈Ω for real ∣τ∣<δ. Set H(τ,σ):=hz+τX(z+σX). The explicit formula in step 1.2 makes H smooth, with H(τ,0)=H(0,σ)=0. Differentiating that formula gives ∂τ∂σH(0,0)=∑j,kXjXk‾(cjk−ajak‾/M)=b, where b:=LE(z;X) by step 1.3. Put R(τ,σ):=H(τ,σ)−bτσ. For every ε>0, continuity makes ∣∂τ∂σR∣<ε on a small rectangle about (0,0). Since ∂σR(0,σ)=0 and R(τ,0)=0, applying [F13] first to τ↦∂σR(τ,σ) and then to σ↦R(τ,σ) yields ∣R(τ,σ)∣≤ε∣τσ∣. Thus H(τ,σ)/(τσ)→b as both nonzero real parameters tend to 0, and in particular E(z+τX)/τ2=H(τ,τ)/τ2→b.

3.1A1F4F8step 2.1step 1.3

Assume X≠0. The function f0(η):=⟨η−z,X⟩=∑j=1m(ηj−zj)Xj‾ is holomorphic on Ω and bounded there because Ω is bounded, so f0∈H′; also ∂Xf0(z)=∑j=1mXjXj‾=∣X∣2. Applying step 2.1 to f0/∥f0∥2 gives LE(z;X)≥∣X∣4/∥f0∥22>0 for X≠0. Hence by step 1.3, BΩ2(z;X)=LE(z;X)/M>0: the quadratic form of gΩ(z) is positive on every nonzero vector, so the Hermitian form is positive definite.

4.1A1F1F4F5F6F10step 1.1step 3.1step 2.2

For real τ≠0 put gτ:=hz+τX/τ∈H′. Reproduction gives ⟨gτ,gσ⟩=H(τ,σ)/(τσ), so step 2.2 implies ∥gτ−gσ∥22→0 as τ,σ→0. Choose, for example, τn=δ/(n+2). The closed subspace H′ is complete by [F1, F5], so gτn→g∈H′; the same Cauchy estimate gives gτ→g for all real τ→0. By step 2.2, ∥g∥22=b. For every f∈H′, continuity of the pairing and holomorphic differentiability give ⟨f,g⟩=lim⁡τ→0f(z+τX)/τ=∂Xf(z). Hence g represents the derivative functional, and Cauchy–Schwarz gives sup⁡f∈H′,∥f∥2≤1∣∂Xf(z)∣2=∥g∥22=b, attained at g/∥g∥2 because b>0 by step 3.1.

5.1step 2.1step 1.3step 3.1step 4.1

Combining steps 1.3, 2.1 and 4.1 yields sup⁡{∣∂Xf(z)∣2:f∈A2(Ω),∥f∥2≤1,f(z)=0}=LE(z;X)=KΩ(z,z)BΩ2(z;X), which is the displayed formula, with the supremum attained; step 3.1 gives its strict positivity for X≠0. This proves the two assertions of part 1.

6.1A1F8F10F11step 5.1

For part 2, let F:Ω→Ω′ be a biholomorphism, J:=JF=det⁡CDF, and let UFg=(g∘F)J be the unitary isomorphism of [F11], so that UF maps the closed unit ball of A2(Ω′) onto that of A2(Ω) and {g:g(F(z))=0} onto H′={f:f(z)=0} (because J(z)≠0). If f=UFg, then the product rule and [F10] give ∂Xf(z)=J(z) ∂DF(z)Xg(F(z))+g(F(z)) ∂XJ(z), and for f∈H′ the second term vanishes; hence the supremum identity of part 1 applied on both domains, together with the diagonal kernel law KΩ(z,z)=∣J(z)∣2KΩ′(F(z),F(z)) from [F11], gives KΩ(z,z)BΩ2(z;X)=∣J(z)∣2KΩ′(F(z),F(z))BΩ′2(F(z);DF(z)X). Since KΩ(z,z)>0 and ∣J(z)∣2KΩ′(F(z),F(z))=KΩ(z,z), dividing by the positive number KΩ(z,z) yields BΩ2(z;X)=BΩ′2(F(z);DF(z)X) for every nonzero X; when X=0, both quadratic forms are zero by definition.

7.1F10step 6.1∎

The quadratic forms of the Hermitian forms agree under the complex-linear map DF(z). For all X,Y, applying step 6.1 to the four directions X+Y,X−Y,X+iY,X−iY and using complex linearity of DF(z) plus the polarization identity g(X,Y)=14(q(X+Y)−q(X−Y)+iq(X+iY)−iq(X−iY)) for the quadratic form q(Z)=g(Z,Z) gives gΩ(z)(X,Y)=gΩ′(F(z))(DF(z)X,DF(z)Y).

Remarks

The supremum in part 1 is taken over all of A2(Ω) with the single constraint f(z)=0; since f(z)=⟨f,kz⟩, this is exactly the closed subspace H′ of the proof. In the orthonormal-system proof of the source, the reduced kernel of H′ plays the role of the element g of step 4.1. The constant hidden in the formula is carried by KΩ(z,z); the Bergman metric is normalized so that on the disc at the origin one obtains BD2(0;X)=2∣X∣2.

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The determinant quotient det⁡gΩ/KΩ is a biholomorphic invariant

Statement

Assume the Axiom of Countable Choice ACω (The Axiom of Countable Choice (ACω)). Let Ω,Ω′⊆Cm be bounded domains, let F:Ω→Ω′ be a biholomorphism with complex Jacobian DF(z), and let gΩ(z) be the matrix of the Bergman metric form in the one-based coordinate aliases of The Levi form and strict plurisubharmonicity. Then, for every z∈Ω,

det⁡gΩ(z)=∣det⁡DF(z)∣2det⁡gΩ′(F(z)),KΩ(z,z)=∣det⁡DF(z)∣2KΩ′(F(z),F(z)),

and consequently

det⁡gΩ(z)KΩ(z,z)=det⁡gΩ′(F(z))KΩ′(F(z),F(z))(z∈Ω).

If each quotient is constant on its domain, then the two constants are equal. (For m≥2 these quotients are the invariants that distinguish the ball metric from the polydisc metric, but constancy is not claimed here.)

Facts & Assumptions

[A1]

The only choice assumption is ACω (The Axiom of Countable Choice (ACω)), inherited through the Bergman metric, kernel and transformation suppliers; no full Axiom of Choice is used.

[F1]

The Bergman metric form of a bounded domain is the Hermitian form gΩ(z)(X,Y)=∑j,k=1m(gΩ)jkˉ(z)XjYk‾ with matrix (gΩ)jkˉ(z), and BΩ2(z;X)=gΩ(z)(X,X) (The Bergman metric form on a bounded domain, The Levi form and strict plurisubharmonicity).

[F2]

A biholomorphism F:Ω→Ω′ of bounded domains satisfies gΩ(z)(X,Y)=gΩ′(F(z))(DF(z)X,DF(z)Y) for all z,X,Y (The Bergman metric is positive definite on bounded domains and biholomorphically invariant).

[F3]

A biholomorphism F satisfies KΩ(z,w)=JF(z)KΩ′(F(z),F(w))JF(w)‾ with JF=det⁡DF≠0; in particular the diagonal kernel law KΩ(z,z)=∣det⁡DF(z)∣2KΩ′(F(z),F(z)) holds (Transformation law of the Bergman kernel under a biholomorphism).

[F4]

On a bounded domain, KΩ(z,z)>0 for every z (Smoothness of the Bergman kernel and positivity of its diagonal on bounded domains).

[F5]

For A∈Mn(R) over a commutative ring, det⁡(A)=∑σ∈Snsgn⁡(σ)∏i<naσ(i),i, and transposition leaves the determinant unchanged; the determinant is multiplicative: det⁡(AB)=det⁡Adet⁡B (For n≥1, the determinant over a commutative ring by the Leibniz formula, and ∣det⁡A∣ for a real matrix, Finite rectangular matrices over a commutative ring, their entries, rows and columns, For every square matrix over a commutative ring, det⁡(AT)=det⁡(A), For same-sized finite square matrices over a commutative ring, det⁡(AB)=det⁡(A)det⁡(B)).

[F6]

Complex conjugation is a field automorphism of C fixing the rationals, so it commutes with finite sums and products of complex numbers (Conjugation is an involutive real-field automorphism, zz‾=∣z∣2, and modulus is definite, multiplicative, and subadditive).

Proof

technique · direct, comparing Hermitian matrices by their quadratic forms and taking determinants

Given: ACω, bounded domains Ω,Ω′, a biholomorphism F, a point z∈Ω, and J:=DF(z).

1.1A1F1F2F7algebra

Put G:=gΩ′(F(z)) and H:=gΩ(z), with entries Glm and Hjk in the one-based aliases. By [F1] and [F2], for all X,Y∈Cm, ∑j,kHjkXjYk‾=∑l,mGlm(JX)l(JY)m‾=∑j,k(∑l,mJmk‾GlmJlj)XjYk‾. Since the Hermitian form is determined by its coefficients, Hjk=∑l,mJmk‾GlmJlj, which is the (j,k) entry of JTGJ‾ because (JTGJ‾)jk=∑l,mJljGlmJmk‾ by [F7]; in matrix notation gΩ(z)=JTgΩ′(F(z))J‾.

1.2F5F6algebra

Conjugation is a field automorphism of C [F6] applied entrywise to the Leibniz sum of [F5] gives det⁡(J‾)=det⁡J‾; since transposition leaves determinants unchanged [F5], det⁡(J‾T)=det⁡J‾.

2.1F3F5step 1.1step 1.2

Taking determinants in the matrix identity of step 1.1 and using multiplicativity and transposition invariance [F5] gives det⁡gΩ(z)=det⁡(J)det⁡gΩ′(F(z))det⁡(J‾)=det⁡J det⁡gΩ′(F(z)) det⁡J‾=∣det⁡J∣2det⁡gΩ′(F(z)), the first displayed identity. The second displayed identity is the diagonal kernel law of [F3] with J=DF(z), whose determinant is nonzero.

3.1F3F4step 2.1∎

By [F4] the diagonal values KΩ(z,z) and KΩ′(F(z),F(z)) are positive, and ∣det⁡DF(z)∣2>0 by [F3]; dividing the two identities of step 2.1 by each other and cancelling the common positive factor ∣det⁡DF(z)∣2 gives the displayed identity of the quotients for every z∈Ω. If each quotient is constant on its domain, evaluating the identity at any z shows the two constants are equal.

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Determinants and kernel quotients of the model Bergman metrics

Statement

Assume the Axiom of Countable Choice ACω (The Axiom of Countable Choice (ACω)), let m≥1, and use the one-based coordinate aliases of The Bergman metric form on a bounded domain. For the unit ball and the unit polydisc in Cm,

det⁡gBm(z)=(m+1)m(1−∣z∣2)m+1,det⁡gDm(z)=2m∏j=1m1(1−∣zj∣2)2.

Consequently the invariant quotients are the constants

det⁡gBmKBm=(m+1)mπmm!,det⁡gDmKDm=2mπm,

and these constants are distinct for every m≥2.

Facts & Assumptions

[A1]

The only choice assumption is ACω (The Axiom of Countable Choice (ACω)), inherited through the Bergman metric, kernel and determinant suppliers; no full Axiom of Choice is used.

[F1]

The model kernels are KBm(z,z)=m!πm(1−∣z∣2)m+1 and KDm(z,z)=1πm∏j=1m1(1−∣zj∣2)2 (Bergman kernels of the disc, ball and polydisc, and Szegő kernels of the disc and ball).

[F2]

The Bergman metric form is gΩ=∂∂‾log⁡KΩ(z,z), its matrix has entries (gΩ)jkˉ=∂j∂kˉlog⁡KΩ(z,z), and log⁡KΩ(z,z) is real C∞ on a bounded domain (The Bergman metric form on a bounded domain, Smoothness of the Bergman kernel and positivity of its diagonal on bounded domains).

[F4]

Under the complex Euclidean dictionary, ∣z∣2=∑j=1m∣zj∣2=∑j=1mzjzj‾, and ∂z‾kzj‾=δjk for these first-order operators (Complex m-space and its real coordinate dictionary, Wirtinger operators in Cm).

[F5]

For a commutative ring, A∈Mn(R) and columns u,v, det⁡(A+uvT)=det⁡(A)+vTadj⁡(A)u; the adjugate is the transpose of the cofactor matrix, and a diagonal matrix has determinant the product of its diagonal entries (For A∈Mn(R) and columns u,v over a commutative ring, det⁡(A+uvT)=det⁡(A)+vTadj⁡(A)u, Deleted-row-and-column minors, cofactors, the cofactor matrix and the adjugate over a commutative ring, The determinant of a triangular matrix is the product of its diagonal entries).

[F6]

For A=(1−r)Im with 0≤r<1, each diagonal cofactor equals (1−r)m−1, including the empty minor 1 when m=1. If i≠j, deleting row i and column j leaves the original row j present but zero, so its determinant is zero by the Leibniz formula. Thus adj⁡(A)=(1−r)m−1Im (Deleted-row-and-column minors, cofactors, the cofactor matrix and the adjugate over a commutative ring, For n≥1, the determinant over a commutative ring by the Leibniz formula, and ∣det⁡A∣ for a real matrix, The determinant of a triangular matrix is the product of its diagonal entries).

[F7]

The invariant quotient det⁡gΩ/KΩ agrees under biholomorphisms, and diagonal kernel values are positive on bounded domains (The determinant quotient det⁡gΩ/KΩ is a biholomorphic invariant, Smoothness of the Bergman kernel and positivity of its diagonal on bounded domains).

[F8]

Factorials of naturals are positive and m!=∏k=1mk (The factorial n! and the falling factorial nk‾, defined by recursion in N).

[F9]

In the Leibniz determinant formula every term contains exactly m matrix entries, so det⁡(cA)=cmdet⁡A for a complex scalar c (For n≥1, the determinant over a commutative ring by the Leibniz formula, and ∣det⁡A∣ for a real matrix).

Proof

technique · direct differentiation of the explicit model kernels, a rank-one determinant update, and a finite comparison of constants

Given: ACω, m≥1, the unit ball Bm and the unit polydisc Dm with the model kernels of [F1], and z in the respective domain.

1.1A1F1F2F3F4algebra

By [F1], log⁡KBm(z,z)=log⁡m!πm−(m+1)log⁡(1−∣z∣2). Using [F3] and [F4], ∂jlog⁡KBm(z,z)=(m+1)zj‾1−∣z∣2 and hence (gBm)jkˉ(z)=(m+1)(1−∣z∣2)δjk+zj‾zk(1−∣z∣2)2; in matrix form gBm(z)=m+1(1−∣z∣2)2((1−∣z∣2)Im+z‾ zT), where z‾ zT has entries zj‾zk.

1.2F1F2F3F4F5algebra

By [F1], log⁡KDm(z,z)=−mlog⁡π−2∑j=1mlog⁡(1−∣zj∣2). Each summand depends only on its own coordinate, so [F3] and [F4] give (gDm)jkˉ(z)=0 for j≠k and (gDm)jj(z)=2(1−∣zj∣2)2; the matrix is diagonal, and [F5] gives det⁡gDm(z)=2m∏j=1m(1−∣zj∣2)−2, the second displayed determinant.

2.1F5F6F9step 1.1algebra

Put r:=∣z∣2∈[0,1) and A:=(1−r)Im. By [F6], adj⁡(A)=(1−r)m−1Im, so the rank-one update [F5] with u=z‾, v=z gives det⁡((1−r)Im+z‾ zT)=det⁡(A)+zTadj⁡(A)z‾=(1−r)m+(1−r)m−1r=(1−r)m−1. Taking determinants in step 1.1 with [F9] therefore gives det⁡gBm(z)=(m+1)m(1−r)m−1/(1−r)2m=(m+1)m/(1−∣z∣2)m+1, the first displayed determinant.

3.1F1F7step 1.2step 2.1algebra

Dividing by the model kernel diagonals of [F1] cancels the (1−∣z∣2) and coordinate factors and gives det⁡gBm/KBm=(m+1)mπmm! and det⁡gDm/KDm=2mπm; the divisions use the positive diagonal values, and by [F7] the quotients are the biholomorphic invariants of the two domains.

4.1F8step 3.1algebra∎

It remains to compare the two constants. Their quotient is (m+1)m2mm!=∏k=1mm+12k, a product of positive real factors. Pair the factor k with the factor m+1−k; the pair contributes (m+1)24k(m+1−k)≥1, because (m+1)2−4k(m+1−k)=(2k−m−1)2≥0, with strict inequality unless 2k=m+1. If m=2n is even, every one of the n pairs has strict inequality, so the product exceeds 1. If m=2n+1≥3 is odd, the middle factor k=n+1 contributes 1 while the pair k=1 with k=m contributes (m+1)24m>1 for m≥2, so again the product exceeds 1. Hence (m+1)mπmm!>2mπm for every m≥2, and the two invariant constants are distinct.

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Poincaré's theorem: the ball and the polydisc are not biholomorphic for m≥2

Statement

Assume the Axiom of Countable Choice ACω (The Axiom of Countable Choice (ACω)). For every m≥2 the unit ball Bm and the unit polydisc Dm in Cm are not biholomorphic. (For m=1 both are the unit disc.)

Facts & Assumptions

[A1]

The only choice assumption is ACω (The Axiom of Countable Choice (ACω)), inherited through the Bergman metric, kernel and determinant suppliers; no full Axiom of Choice is used.

[F1]

The unit ball and unit polydisc are Bm={z:∑j<m∣zj∣2<1} and Dm={z:∣zj∣<1}; for m=1 both equal the unit disc {∣z∣<1} (Balls, polydiscs and the distinguished boundary in Cm).

[F2]

A biholomorphism F:Ω→Ω′ is a bijective holomorphic map whose inverse is holomorphic, and the determinant quotient satisfies det⁡gΩ(z)KΩ(z,z)=det⁡gΩ′(F(z))KΩ′(F(z),F(z)) for every z∈Ω; if each quotient is constant on its domain, the two constants are equal (Biholomorphic maps between open sets in Cm, The determinant quotient det⁡gΩ/KΩ is a biholomorphic invariant).

[F3]

The model quotients are the constants det⁡gBmKBm=(m+1)mπmm! and det⁡gDmKDm=2mπm, and these constants are distinct for every m≥2 (Determinants and kernel quotients of the model Bergman metrics).

Proof

technique · direct, comparing the biholomorphically invariant quotient of the two model domains

Given: ACω and an integer m≥2.

1.1A1F2F3given

Suppose, for contradiction, that F:Bm→Dm is a biholomorphism. Both domains are bounded, so [F2] applies and gives det⁡gBm(z)KBm(z,z)=det⁡gDm(F(z))KDm(F(z),F(z)) for every z∈Bm. By [F3] the left-hand side is the constant (m+1)mπmm! and the right-hand side the constant 2mπm; hence, by the constant-quotient clause of [F2], the two constants are equal.

2.1F2F3step 1.1

However, [F3] states that (m+1)mπmm!≠2mπm for every m≥2. This contradicts step 1.1, so no biholomorphism Bm→Dm exists; the same argument applies to a biholomorphism in either direction, by symmetry of the biholomorphism relation.

3.1F1given∎

For m=1, [F1] gives B1=D1={∣z∣<1}, so the two domains coincide; this is why the theorem is stated for m≥2 only, and no inequivalence is asserted in dimension one.

5 · Examples, counterexamples and false statements

None yet.

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